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  • one high-end server with one Application Server or multiple Application Servers?

    - by elgcom
    If I have a high-end server, for example with 1T memory and 8x4core CPU... will it bring more performance if I run multiple App Server (on different JVM) rather than just one App Server? On App Server I will run some services (EAR whith message driven beans) which exchange message with each other. btw, has java 64bit now no memory limitation any more? http://java.sun.com/products/hotspot/whitepaper.html#64

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  • How I can get logged in user's info like email id,name,city etc. in Facebook with uId

    - by vaibhavbhalke
    Hi all Can any one help me to get logged in user's info like email id,name,city etc. with the help of Facebook uId . " Long uid = apiClient.getLoggedInUser ();" Users_getInfo is not useful. It returns No of users connected to _User & according that there info gets. If user login successfully using fb connect, Facebook gives us uid. However, I need to match the logged in user with our member's account If that member is not present in DB then want to register him and I'm trying to do that with e-mail(hashed) address and other info.

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  • How to make php-closure compiler output to a predefined file name? (Updated)

    - by Mohammad
    Php-closure compiler (linked to source code) currently writes the compiled code to a md5 encoded filename. How can I make it so it write the compiled code to a predefined name like compiled_code.js? . . I think it has to do with the write() function on Line 164. It gets the filename via the _getCacheFileName() function (Line 272). function _getCacheFileName() { return $this->_cache_dir . $this->_getHash() . ".js"; } I've tried altering it to this: function _getCacheFileName() { //return $this->_cache_dir . $this->_getHash() . ".js"; return 'copiled_code.js'; } without any results. Thanks to all of you in advance!

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  • NonStop ODBC: how the connections (ODBC servers) are assigned to CPUs?

    - by Vladimir Dyuzhev
    We have an ODBC pool running on a NonStop server. The pool is connected to SQL/MX. This pool is used by a few external Java applications, each of which has an JDBC pool connected to ODBC pool (e.g. 14 connections per application). With time (after a few application recycles) we see an imbalance between CPUs -- some have 8 ODBC processes running, some only 5. That leads to CPU time imbalance too. Up to this point we assumed that a CPU is assigned to ODBC process in round-robin fashion. That would maintain the number of ODBC processes more or less equally distributed. It's not the case though. Is there any information on how ODBC pool decided which CPU to choose for every new allocated process? Does it look at CPU load? Available memory? Something else? Sadly, even HP's own people (available to us, that is) couldn't answer those questions with certainty. :-(

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  • Shortest way of determining a name ends with an `s`, `x` or `z`, and then use the `I18n.t` method wi

    - by Koning Baard XIV
    I'm creating a Rails application where users can have a first and last name. Since I'm a perfectionist, the application may not show something like Dennis's profile or Xianx's profile, but rather Dennis' profile and Xianx' profile. I use L18n, so I wanted to ask what is the shortest way of implementing this? This grammar is the same for both English and Dutch, where the application will be translated to. Oh, some important things: I am not afraid of using helpers and the application controller My language files are in Ruby, not YAML Thanks!

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  • Modifying generator.yml views in Symfony

    - by Alex Ciminian
    Hey! I'm currently working on a web app written in Symfony. I'm supposed to add an "export to CSV" feature in the backend/administration part of the app for some modules. In the list view, there should be an "Export" button which should provide the user with a csv file of the elements that are displayed (considering filtering criteria). I've created a method in the actions class of the module that takes a comma separated list of ids and generates the CSV, but I'm not really sure how to add the link to it in the view. The problem is that the view doesn't exist anywhere, it's generated on the fly from the data in the generator.yml configuration file. I've posted the relevant part of the file below. list: display: [=name, indemn, _status, _participants, _approved_, created_at] title: Lista actiuni object_actions: _edit: ~ _delete: ~ filters: [name, county_id, _status_filter, activity_id] fields: name: name: Nume Actiune indemn: name: Îndemn la actiune description: name: Descriere approved_: name: Operatiune created_at: name: Creata la status: name: Status Actiune I'm new to Symfony, so any help would be appreciated :). Thanks, Alex

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  • What happens when you click a button using WebRat under cucumber

    - by Peter Tillemans
    I am trying to login to a Java web application. The login page has the following html : <html> <head><title>Login Page</title></head> <body onload='document.f.j_username.focus();'> <h3>Login with Username and Password</h3> <form name='f' action='/ui/j_spring_security_check' method='POST'> <table> <tr><td>User:</td><td><input type='text' name='j_username' value=''></td></tr> <tr><td>Password:</td><td><input type='password' name='j_password'/></td></tr> <tr> <td><input type='checkbox' name='_spring_security_remember_me'/> </td> <td>Remember me on this computer.</td> </tr> <tr><td colspan='2'><input name="submit" type="submit"/></td></tr> <tr><td colspan='2'><input name="reset" type="reset"/></td></tr> </table> </form> </body> </html> I use the following script: Given /^I am logged in as (.*) with password (.*)$/ do | user, password | visit "http://localhost:8080/ui" click_link "Projects" puts "Response Body:" puts response.body assert_contain "User:" fill_in "j_username", :with => user fill_in "j_password", :with => password puts "Response Body:" puts response.body click_button puts "Response Body:" puts response.body end This gives the following in the log file : [INFO] Response Body: [INFO] <html><head><title>Login Page</title></head><body onload='document.f.j_username.focus();'> [INFO] <h3>Login with Username and Password</h3><form name='f' action='/ui/j_spring_security_check' method='POST'> [INFO] <table> [INFO] <tr><td>User:</td><td><input type='text' name='j_username' value=''></td></tr> [INFO] <tr><td>Password:</td><td><input type='password' name='j_password'/></td></tr> [INFO] <tr><td><input type='checkbox' name='_spring_security_remember_me'/></td><td>Remember me on this computer.</td></tr> [INFO] <tr><td colspan='2'><input name="submit" type="submit"/></td></tr> [INFO] <tr><td colspan='2'><input name="reset" type="reset"/></td></tr> [INFO] </table> [INFO] </form></body></html> [INFO] Response Body: [INFO] <html><head><title>Login Page</title></head><body onload='document.f.j_username.focus();'> [INFO] <h3>Login with Username and Password</h3><form name='f' action='/ui/j_spring_security_check' method='POST'> [INFO] <table> [INFO] <tr><td>User:</td><td><input type='text' name='j_username' value=''></td></tr> [INFO] <tr><td>Password:</td><td><input type='password' name='j_password'/></td></tr> [INFO] <tr><td><input type='checkbox' name='_spring_security_remember_me'/></td><td>Remember me on this computer.</td></tr> [INFO] <tr><td colspan='2'><input name="submit" type="submit"/></td></tr> [INFO] <tr><td colspan='2'><input name="reset" type="reset"/></td></tr> [INFO] </table> [INFO] </form></body></html> [INFO] Response Body: [INFO] [INFO] Given I am logged in as pti with password ptipti # features/step_definitions/authentication_tests.rb:2 So apparently the response.body disappeared after clicking the submit button. I can see from the server log files that the script does not arrive on the Project page. I am new to webrat and quite new to ruby and I am now thoroughly confused. I have no idea why the response.body is gone. I have no idea where I am. I speculated that I had to wait for the page request, but all documentation says that webrat nicely waits till all redirects, pageloads, etc are finished. (At least I think I read that). Besides I find no method to wait for the page in the webrat API. Can someone give some tips on how to proceed with debugging this?

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  • Find element with attribute with minidom

    - by Xster
    Given <field name="frame.time_delta_displayed" showname="Time delta from previous displayed frame: 0.000008000 seconds" size="0" pos="0" show="0.000008000"/> <field name="frame.time_relative" showname="Time since reference or first frame: 0.000008000 seconds" size="0" pos="0" show="0.000008000"/> <field name="frame.number" showname="Frame Number: 2" size="0" pos="0" show="2"/> <field name="frame.pkt_len" showname="Packet Length: 1506 bytes" hide="yes" size="0" pos="0" show="1506"/> <field name="frame.len" showname="Frame Length: 1506 bytes" size="0" pos="0" show="1506"/> <field name="frame.cap_len" showname="Capture Length: 1506 bytes" size="0" pos="0" show="1506"/> <field name="frame.marked" showname="Frame is marked: False" size="0" pos="0" show="0"/> <field name="frame.protocols" showname="Protocols in frame: eth:ip:tcp:http:data" size="0" pos="0" show="eth:ip:tcp:http:data"/> How do I get the field with name="frame.len" right away without iterating through every tag and checking the attributes?

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  • How to add a another value to a key in python

    - by Nanowatt
    First I'm sorry this might be a dumb question but I'm trying to self learn python and I can't find the answer to my question. I want to make a phonebook and I need to add an email to an already existing name. That name has already a phone number attached. I have this first code: phonebook = {} phonebook ['ana'] = '12345' phonebook ['maria']= '23456' , '[email protected]' def add_contact(): name = raw_input ("Please enter a name:") number = raw_input ("Please enter a number:") phonebook[name] = number Then I wanted to add an email to the name "ana" for example: ana: 12345, [email protected]. I created this code but instead of addend a new value (the email), it just changes the old one, removing the number: def add_email(): name = raw_input("Please enter a name:") email = raw_input("Please enter an email:") phonebook[name] = email I tried .append() too but it didn't work. Can you help me? And I'm sorry if the code is bad, I'm just trying to learn and I'm a bit noob yet :)

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  • Possible to load an Enum based on a string name?

    - by Cooter
    OK, I don't think the title says it right... but here goes: I have a class with about 40 Enums in it. i.e: Class Hoohoo { public enum aaa : short { a = 0, b = 3 } public enum bbb : short { a = 0, b = 3 } public enum ccc : short { a = 0, b = 3 } } Now say I have a Dictionary of strings and values, and each string is the name of above mentioned enums: Dictionary<string,short>{"aaa":0,"bbb":3,"ccc":0} I need to change "aaa" into HooBoo.aaa to look up 0. Can't seem to find a way to do this since the enum is static. Otherwise I'll have to write a method for each enum to tie the string to it. I can do that but thats mucho code to write. Thanks, Cooter

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  • How can you name the Dataset's Tables you return in a stored proc ?

    - by Brann
    I've got the following stored procedure Create procedure psfoo () AS select * from tbA select * from tbB I'm then accessing the data this way : Sql Command mySqlCommand = new SqlCommand("psfoo" , DbConnection) DataSet ds = new DataSet(); mySqlCommand.CommandType = CommandType.StoredProcedure; SqlDataAdapter mySqlDataAdapter = new SqlDataAdapter(); mySqlDataAdapter.SelectCommand = mySqlCommand; mySqlDataAdapter.Fill(ds); Now, when I want to access my tables, I have to do this : DataTable datatableA = ds.Tables[0]; DataTable datatableB = ds.Tables[1]; the dataset Tables property also got an accessor by string (instead of int). Is it possible so specify the name of the tables in the SQL code, so that I can instead write this : DataTable datatableA = ds.Tables["NametbA"]; DataTable datatableB = ds.Tables["NametbB"]; I'm using SQL server 2008, if that makes a difference.

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  • Copying one form's values to another form using JQuery

    - by rsturim
    I have a "shipping" form that I want to offer users the ability to copy their input values over to their "billing" form by simply checking a checkbox. I've coded up a solution that works -- but, I'm sort of new to jQuery and wanted some criticism on how I went about achieving this. Is this well done -- any refactorings you'd recommend? Any advice would be much appreciated! The Script <script type="text/javascript"> $(function() { $("#copy").click(function() { if($(this).is(":checked")){ var $allShippingInputs = $(":input:not(input[type=submit])", "form#shipping"); $allShippingInputs.each(function() { var billingInput = "#" + this.name.replace("ship", "bill"); $(billingInput).val($(this).val()); }) //console.log("checked"); } else { $(':input','#billing') .not(':button, :submit, :reset, :hidden') .val('') .removeAttr('checked') .removeAttr('selected'); //console.log("not checked") } }); }); </script> The Form <div> <form action="" method="get" name="shipping" id="shipping"> <fieldset> <legend>Shipping</legend> <ul> <li> <label for="ship_first_name">First Name:</label> <input type="text" name="ship_first_name" id="ship_first_name" value="John" size="" /> </li> <li> <label for="ship_last_name">Last Name:</label> <input type="text" name="ship_last_name" id="ship_last_name" value="Smith" size="" /> </li> <li> <label for="ship_state">State:</label> <select name="ship_state" id="ship_state"> <option value="RI">Rhode Island</option> <option value="VT" selected="selected">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="ship_zip_code">Zip Code</label> <input type="text" name="ship_zip_code" id="ship_zip_code" value="05401" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div> <div> <form action="" method="get" name="billing" id="billing"> <fieldset> <legend>Billing</legend> <ul> <li> <input type="checkbox" name="copy" id="copy" /> <label for="copy">Same of my shipping</label> </li> <li> <label for="bill_first_name">First Name:</label> <input type="text" name="bill_first_name" id="bill_first_name" value="" size="" /> </li> <li> <label for="bill_last_name">Last Name:</label> <input type="text" name="bill_last_name" id="bill_last_name" value="" size="" /> </li> <li> <label for="bill_state">State:</label> <select name="bill_state" id="bill_state"> <option>-- Choose State --</option> <option value="RI">Rhode Island</option> <option value="VT">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="bill_zip_code">Zip Code</label> <input type="text" name="bill_zip_code" id="bill_zip_code" value="" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div>

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  • Is there a name for a language feature that allows assignment/creation?

    - by Alex Mcp
    This is a bit hard for me to articulate, but in PHP you can say something like: $myArray['someindex'] = "my string"; and if there is no index named that, it will create/assign the value, and if there IS an index, it will overwrite the existing value. Compare this to Javascript where today I had to do checks like so: if (!myObject[key]) myObject[key] = "value"; I know this may be a bit of a picky point, but is there a name for the ability of PHP (and many other languages) to do these checks on their own as opposed to the more verbose (read: PITA) method of Javascript?

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  • Getting an 'Microsoft.ACE.OLEDB.12.0' provider is not registered on the local machine error when I tried hosting on Azure Servers

    - by user1864888
    I am hosting a web application which uses OLEDB 12 to read an Excel file, but getting the error "'Microsoft.ACE.OLEDB.12.0' provider is not registered on the local machine". Wonder if I should use lower version of OLEDB or Azure does not support OLEDB services at all. Before rewriting the program, just wanted to see if anyone knows a better alternative. I am using Visual Studio 2010 for my development. Thanks in Advance.

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  • basic SQL atomicity "UPDATE ... SET .. WHERE ..."

    - by elgcom
    I have a rather basic and general question about atomicity of "UPDATE ... SET .. WHERE ..." statement. having a table (without extra constraint), +----------+ | id | name| +----------+ | 1 | a | +----+-----+ now, I would execute following 4 statements "at the same time" (concurrently). UPDATE table SET name='b1' WHERE name='a' UPDATE table SET name='b2' WHERE name='a' UPDATE table SET name='b3' WHERE name='a' UPDATE table SET name='b4' WHERE name='a' is there only one UPDATE statement would be executed with table update? or, is it possible that more than one UPDATE statements can really update the table? should I need extra transaction or lock to let only one UPDATE write values into table? thanks

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  • The type or namespace name 'Oledb' does not exist in the namespace 'System.Data' error on Web Servic

    - by Pankaj Kumar
    Hi everyone... i have a webservice that i want to test by typing the url in the address bar in the web browser localhost:1981/myProject/admin/autocomplete.asmx and when i do this it gives this compilation error CS0234: The type or namespace name 'Oledb' does not exist in the namespace 'System.Data' (are you missing an assembly reference?) i know this is because we added this in our web.config <add namespace="System.Data.Oledb"/> <add namespace ="System.Data"/> in the namespaces section..... when i call this web service through ajax it works but if i try to test it it gives this error. Is there any way to prevent this?

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  • In ASP.NET MVC, why can't I inherit from "MyCustomView" without specifying the full type name?

    - by Seth Petry-Johnson
    In my MVC apps I normally declare a base view type that all of my views inherit from. I get a parser error when I specify Inherits="MyView" in my Page declaration, but not if I specify Inherits="MyApp.Web.Views.MyView". Strangely enough, it also works fine if I specify Inherits="MyView<T> (where T is any valid type). Why can I specify a strongly typed view without the full type name, but not a generic view? My base view class is declared like this: namespace MyApp.Web.Views { public class MyView : MyView<object> { } public class MyView<TModel> : ViewPage<TModel> where TModel : class { } }

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  • Array.BinarySearch does not find item using IComparable

    - by Sir Psycho
    If a binary search requires an array to be sorted before hand, why does the following code work? string[] strings = new[] { "z", "a", "y", "e", "v", "u" }; int pos = Array.BinarySearch(strings, "Y", StringComparer.OrdinalIgnoreCase); Console.WriteLine(pos); And why does this code result return -1? public class Person : IComparable<Person> { public string Name { get; set; } public int Age { get; set; } public int CompareTo(Person other) { return this.Age.CompareTo(other.Age) + this.Name.CompareTo(other.Name); } } var people = new[] { new Person { Age=5,Name="Tom"}, new Person { Age=1,Name="Tom"}, new Person { Age=2,Name="Tom"}, new Person { Age=1,Name="John"}, new Person { Age=1,Name="Bob"}, }; var s = new Person { Age = 1, Name = "Tom" }; // returns -1 Console.WriteLine( Array.BinarySearch(people, s) );

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  • Fatal error: Function name must be a string in.. PHP error

    - by Jonesy
    Hi I have a class called User and a method called insertUser(). function insertUser($first_name, $last_name, $user_name, $password, $email_address, $group_house_id) { $first_name = mysql_real_escape_string($first_name); $last_name = mysql_real_escape_string($last_name); $user_name = mysql_real_escape_string($user_name); $password = mysql_real_escape_string($password); $email_address = mysql_real_escape_string($email_address); $query = "INSERT INTO Users (FirstName,LastName,UserName,Password,EmailAddress, GroupHouseID) VALUES ('$first_name','$last_name','$user_name','$password','$email_address','$group_house_id')"; $mysql_query($query); } And I call it like this: $newUser = new User(); $newUser->insertUser($first_name, $last_name, $user_name, $email, $password, $group_house_id); When I run the code I get this error: Fatal error: Function name must be a string in /Library/WebServer/Documents/ORIOnline/includes/class_lib.php on line 33 Anyone know what I am doing wronly? Also, this is my first attempt at OO PHP. Cheers, Jonesy

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  • Persistence unit is not persistent

    - by etam
    I need persistence unit that creates embedded database which stays persistent after closing EntityManager. This is my PU: <persistence-unit name="hello-jpa" transaction-type="RESOURCE_LOCAL"> <class>hello.jpa.User</class> <properties> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.format_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/> <property name="hibernate.connection.driver_class" value="org.hsqldb.jdbcDriver"/> <property name="hibernate.connection.username" value="sa"/> <property name="hibernate.connection.password" value=""/> <property name="hibernate.connection.url" value="jdbc:hsqldb:target/hsql.db"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> And it deletes data after closing application.

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  • How to use a different assembly name for different configurations?

    - by Mark Ingram
    In Visual Studio 2008 (and others) when creating a .NET or silverlight application if you look at your project properties, it seems like you can only have one assembly name - across all configurations. I would like to compile my application as: MyAppDebug - in debug mode and just MyApp - in release mode Does anyone know if this is possible? Edit: It seems some people are questioning the reasoning behind the question, so I'll explain a little further: I'm working on a Silverlight application which gets automatically uploaded to our test site when I to a "build solution". The trouble is, the test team are now testing the online version, whilst I work on a new one. So, I want to have a url like .\MyApp.html for the regular version that the QA team will test and then .\MyApp.html?version=debug for the current version that I'm working on.

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