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  • Cloning and renaming form elements with jQuery

    - by Micor
    I am looking for an effective way to either clone/rename or re-create address fields to offer ability to submit multiple addresses on the same page. So with form example like this: <div id="addresses"> <div class="address"> <input type="text" name="address[0].street"> <input type="text" name="address[0].city"> <input type="text" name="address[0].zip"> <input type="text" name="address[0].state"> </div> </div> <a href="" id="add_address">Add address form</a> From what I can understand there are two options to do that: Recreate the form field by field and increment the index which is kind of verbose: var index = $(".address").length; $('<`input`>').attr({ name: 'address[' + index + '].street', type: 'text' }).appendTo(...); $('<`input`>').attr({ name: 'address[' + index + '].city', type: 'text' }).appendTo(...); $('<`input`>').attr({ name: 'address[' + index + '].zip', type: 'text' }).appendTo(...); $('<`input`>').attr({ name: 'address[' + index + '].state', type: 'text' }).appendTo(...); Clone Existing layer and replace the name in the clone: $("div.address").clone().appendTo($("#addresses")); Which one do you recommend using in terms of being more efficient and if its #2 can you please suggest how I would go about search and replacing all occurrences of [0] with [1] ([n]). Thank you.

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  • Routing multiple static IPs from ISP at the cable modem?

    - by Jakobud
    I'm taking over IT responsibilities for a previous IT guy. We have a 50mb cable modem connection from Comcast along with 5 static IP addresses: XXX.XXX.XXX.180 XXX.XXX.XXX.181 XXX.XXX.XXX.182 XXX.XXX.XXX.183 XXX.XXX.XXX.184 We are in the process of replacing our firewall machine. Currently the firewall box is the only thing connected to the cable modem. However the cable modem has multiple ethernet ports on it, similarly to a router. I have assembled a new firewall machine and its time to start testing and configuring it. So that means that I also need it plugged into the cable modem (remember it has multiple ethernet ports on it). So now with multiple computer plugged into the cable modem, how does the cable modem know where to route the traffic? If some request on the internet is made to XXX.XXX.XXX.181, which goes to our cable modem, how does the cable modem know which connected computer that traffic is supposed to be sent? Looking at the web interface for the cable modem, there doesn't seem to be anything special setup on it with regards to routing or NATing IP addresses. Is that because when there is only one computer connected to the modem, all traffic is sent to it by default? Now that I am going to (temporarily) have multiple computers plugged into the cable modem, do I need to specify routing or NAT rules on the modem itself? I am going to speak to Comcast about this next, but I figured I'd ask here first just so I can get a better grasp on how this type of thing generally plays out.

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  • Invoice & Invoice lines: How do you store customer address information?

    - by elviejo
    Hi I'm developing an invoicing application. So the general idea is to have two tables: Invoice (ID, Date, CustomerAddress, CustomerState, CustomerCountry, VAT, Total); InvoiceLine (Invoice_ID, ID, Concept, Units, PricePerUnit, Total); As you can see this basic design leads to a lot of repetiton of records where the client will have the same addrres, state and country. So the alternative is to have an address table and then make a relationship Address<-Invoice. However I think that an invoice is immutable document and should be stored just the way it was first made. Sometimes customers change their addresses, or states and if it was coming from an Address catalog that will change all the previously made invoices. So What is your experience? How is the customer address stored in an invoice? In the Invoice table? an Address Table? or something else? Can you provide pointers to a book, article or document where this is discussed in further detail?

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  • What is the best way to route a static controller in Rails?

    - by yuval
    I have a static_controller that is in charge of all the static pages in the site and works as follows in routes.rb: map.connect ':id', :controller => 'static', :action => 'show' I have a static page called about that among other information, has a contact form. I currently have a contacts_controller that is in charge of inserting the contact information to the database. Inside my routes.rb file, I have: map.resources :contacts My contact form (simplified) looks like this: <% form_for @contact do |f| %> <p class="errors"><%= f.error_messages %></p> <p> <%= f.label :first_name %> <%= f.text_field :first_name %> </p> <p class="buttons"><%= f.submit %></p> <% end %> Which in turn submits to the create action of my contacts_controller. My create action looks like this: def create @contact = Contact.new(params[:contact]) if @contact.save flash[:notice] = "Email delivered successfully." end redirect_to "about" end The problem is, is the that when I redirect back to my about page the error_messages for the form get lost (since the error_messages for the form only exist for one request, and that request ends upon redirect). How would I go about preserving the error_messages and still linking the users back to the about static url? Would a session/flash be sufficient (if so, what code would I use to pass error messages) or am I going about this whole thing wrong? Thanks!

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  • How to get function name against function address by reading co-classs'es vtable?

    - by Usman
    Hello, I need to call the co-class function by reading its address from vtable of COM exposed interface methods. I need some generic way to read addresses. Now I need to call the function, which would have specific address(NOT KNOWN) arguments(parameters) which I have collected from TLB, and name as well. How that address corresponds to that function name to which I am going to call. For this I need to traverse vtable which is holding functional addresses, LASTLY need to correspond function address with NAME of that function. This is I dont know. How? More over one function with the same name may appear in vtable(Overloading case). In that case we need to distinguish function names w.r.t their addresses. How to tackle ? Regards Usman

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  • ChannelFactory don't have an address on the endpoint, why?

    - by Maxim
    When I create a new instance of a ChannelFactory: var factory = new ChannelFactory<IMyService>(); and that I create a new channel, I have an exception saying that the address of the Endpoint is null. My configuration inside my web.config is as mentioned and everything is as it is supposed to be (especially the address of the endpoint). If I create a new MyServiceClientBase, it loads all the configuration from my channel factory: var factoryWithClientBase = new MyServiceClientBase().ChannelFactory; Console.WriteLine(factoryWithClientBase.Endpoint.Address); //output the configuration inside the web.config var factoryWithChannelFactory = new ChannelFactory<IMyService>(); Console.WriteLine(factoryWithChannelFactory.Endpoint.Address); //output nothing (null) Why?

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  • Getting the start address of the current process's heap?

    - by beta
    Hey, I am exploring the lower level workings of the system, and was wondering how malloc determines the start address of the heap. Is the heap a constant offset or is there a call of some sort to get the start address? Does the stack effect the start address of the heap? Thanks, Braden McDorman

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  • Usernames are evil. How can I make Restful Authentication only require an email address and password

    - by Koning WWWWWWWWWWWWWWWWWWWWWWW
    As the title says: how can I use the Restful Authentication Plugin with Ruby on Rails. When I want to create a new user, it requires me to set the (wrong-named, confusing field) login (= username), email address and password. However, I want, like Facebook does, to require the user to enter only an email address and password, not a username. People will also login with this email address. Can anyone help me?

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  • String Manipulation: Spliting Delimitted Data

    - by Milli Szabo
    I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 If the data is *Address 1*Address2, split will create two indexes in the array where index 0 will have the value of Address 1 and index 2 will have the value of Address2. Where's the name. Was there a name? Any suggestion?

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  • How to get the actual address of a pointer in C?

    - by Airjoe
    BACKGROUND: I'm writing a single level cache simulator in C for a homework assignment, and I've been given code that I must work from. In our discussions of the cache, we were told that the way a small cache can hold large addresses is by splitting the large address into the position in the cache and an identifying tag. That is, if you had an 8 slot cache but wanted to store something with address larger than 8, you take the 3 (because 2^3=8) rightmost bits and put the data in that position; so if you had address 22 for example, binary 10110, you would take those 3 rightmost bits 110, which is decimal 5, and put it in slot 5 of the cache. You would also store in this position the tag, which is the remaining bits 10. One function, cache_load, takes a single argument, and integer pointer. So effectively, I'm being given this int* addr which is an actual address and points to some value. In order to store this value in the cache, I need to split the addr. However, the compiler doesn't like when I try to work with the pointer directly. So, for example, I try to get the position by doing: npos=addr%num_slots The compiler gets angry and gives me errors. I tried casting to an int, but this actually got me the value that the pointer was pointing to, not the numerical address itself. Any help is appreciated, thanks!

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  • ClassCleanup in MSTest is static, but the build server uses nunit to run the unit tests. How can i a

    - by Kettenbach
    Hi All, MSTest has a [ClassCleanup()] attribute, which needs to be static as far as I can tell. I like to run through after my unit tests have run,and clean up my database. This all works great, however when I go to our build server and use our Nant build script, it seems like the unit tests are run with NUnit. NUnit doesn't seem to like the cleanup method to be static. It therefore ignores my tests in that class. What can I do to remedy this? I prefer to not use [TestCleanUp()] as that is run after each test. Does anyone have any suggestions? I know [TestCleanup()] aids in decoupling, but I really prefer the [ClassCleanup()] in this situation. Here is some example code. ////Use ClassCleanup to run code after all tests have run [ClassCleanup()] public static void MyFacadeTestCleanup() { UpdateCleanup(); } private static void UpdateCleanup() { DbCommand dbCommand; Database db; try { db = DatabaseFactory.CreateDatabase(TestConstants.DB_NAME); int rowsAffected; dbCommand = db.GetSqlStringCommand("DELETE FROM tblA WHERE biID=@biID"); db.AddInParameter(dbCommand, "biID", DbType.Int64, biToDelete); rowsAffected = db.ExecuteNonQuery(dbCommand); Debug.WriteLineIf(rowsAffected == TestConstants.ONE_ROW, string.Format("biId '{0}' was successfully deleted.", biToDelete)); } catch (SqlException ex) { } finally { dbCommand = null; db = null; biDelete = 0; } } Thanks for any pointers and yes i realize I'm not catching anything. I need to get passed this hurdle first. Cheers, ~ck in San Diego

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  • iPhone - How do I find the MAC address of the connected WiFi access point?

    - by Ciaran
    Without using the private APIs, is it possible to programatically determine the MAC address of the access point that the iPhone is connected to? I understand that this should be doable using the core BSD libraries, but we are new to this, so it would be great if someone can point us to some starter code. Note: we're trying to determine the MAC address of the remote device - not the MAC address of the iPhone.

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  • Rewriting Live TCP/IP (Layer 4) (i.e. Socket Layer) Streams

    - by user213060
    I have a simple problem which I'm sure someone here has done before... I want to rewrite Layer 4 TCP/IP streams (Not lower layer individual packets or frames.) Ettercap's etterfilter command lets you perform simple live replacements of Layer 4 TCP/IP streams based on fixed strings or regexes. Example ettercap scripting code: if (ip.proto == TCP && tcp.dst == 80) { if (search(DATA.data, "gzip")) { replace("gzip", " "); msg("whited out gzip\n"); } } if (ip.proto == TCP && tcp.dst == 80) { if (search(DATA.data, "deflate")) { replace("deflate", " "); msg("whited out deflate\n"); } } http://ettercap.sourceforge.net/forum/viewtopic.php?t=2833 I would like to rewrite streams based on my own filter program instead of just simple string replacements. Anyone have an idea of how to do this? Is there anything other than Ettercap that can do live replacement like this, maybe as a plugin to a VPN software or something? I would like to have a configuration similar to ettercap's silent bridged sniffing configuration between two Ethernet interfaces. This way I can silently filter traffic coming from either direction with no NATing problems. Note that my filter is an application that acts as a pipe filter, similar to the design of unix command-line filters: >[eth0] <----------> [my filter] <----------> [eth1]< What I am already aware of, but are not suitable: Tun/Tap - Works at the lower packet layer, I need to work with the higher layer streams. Ettercap - I can't find any way to do replacements other than the restricted capabilities in the example above. Hooking into some VPN software? - I just can't figure out which or exactly how. libnetfilter_queue - Works with lower layer packets, not TCP/IP streams. Again, the rewriting should occur at the transport layer (Layer 4) as it does in this example, instead of a lower layer packet-based approach. Exact code will help immensely! Thanks!

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  • How can I serve static content with Glassfish embedded?

    - by Andy Fiedler
    I'm trying to setup Glassfish embedded with a WAR project that implements a REST API and then some static Javascript content that calls it. I got the WAR to deploy and the REST API is available with a context root of "/Users". How can I use Glassfish to serve static content with a context root of "/". So for example, if the user requests http://myserver.com/Users/some-REST-call it routes to the WAR application and http://myserver.com/somefile.js serves a static file from some directory? Here's my Main class file so far: public class Main{ public static void main(String[] args) throws Exception { String port = System.getenv("PORT"); port = port != null ? port : "8080"; GlassFishProperties gfProps = new GlassFishProperties(); gfProps.setPort("http-listener", Integer.parseInt(port)); GlassFish glassfish = GlassFishRuntime.bootstrap().newGlassFish(gfProps); glassfish.start(); Deployer deployer = glassfish.getDeployer(); deployer.deploy(new File("target/Users-Rest.war")); } } Thanks a ton for your help!

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  • Is there a nice way of having static generic parameters is Java?

    - by Chris
    Hello, recently I'm writing some functions that I take from Haskell and translate into Java. One of the main problems I have is I cannot easily create a static property with a generic type. Let me explain by a little example... // An interface to implement functions public interface Func<P, R> { public R apply(P p); } // What I want to do... (incorrect in Java) public class ... { public static <T> Func<T, T> identity = new Func<T, T>() { public T apply(T p) { return p; } } } // What I do right now public class ... { private static Func<Object, Object> identity = new Func<Object, Object>() { public Object apply(Object p) { return p; } } @SuppressWarnings("unchecked") public static <T> Func<T, T> getIdentity() { return (Func<T, T>)identity; } } Are there any easier ways to do something like that? What kind of problems might arise if the syntax I used would be valid?

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  • How can I obtain the IP address of my server program?

    - by Dr Dork
    Hello! This question is related to another question I just posted. I'm prepping for a simple work project and am trying to familiarize myself with the basics of socket programming in a Unix dev environment. At this point, I have some basic server side code and client side code setup to communicate. Currently, my client code successfully connects to the server code and the server code sends it a test message, then both quit out. Perfect! That's exactly what I wanted to accomplish. Now I'm playing around with the functions used to obtain info about the two environments (server and client). I'd like to obtain my server program's IP address. Here's the code I currently have to do this, but it's not working... int sockfd; unsigned int len; socklen_t sin_size; char msg[]="test message"; char buf[MAXLEN]; int st, rv; struct addrinfo hints, *serverinfo, *p; struct sockaddr_storage client; char s[INET6_ADDRSTRLEN]; char ip[INET6_ADDRSTRLEN]; //zero struct memset(&hints,0,sizeof(hints)); hints.ai_family = AF_UNSPEC; hints.ai_socktype = SOCK_STREAM; hints.ai_flags = AI_PASSIVE; //get the server info if((rv = getaddrinfo(NULL, SERVERPORT, &hints, &serverinfo ) != 0)){ perror("getaddrinfo"); exit(-1); } // loop through all the results and bind to the first we can for( p = serverinfo; p != NULL; p = p->ai_next) { //Setup the socket if( (sockfd = socket( p->ai_family, p->ai_socktype, p->ai_protocol )) == -1 ) { perror("socket"); continue; } //Associate a socket id with an address to which other processes can connect if(bind(sockfd, p->ai_addr, p->ai_addrlen) == -1){ close(sockfd); perror("bind"); continue; } break; } if( p == NULL ){ perror("Fail to bind"); } inet_ntop(p->ai_family, get_in_addr((struct sockaddr *)p->ai_addr), s, sizeof(s)); printf("Server has TCP Port %s and IP Address %s\n", SERVERPORT, s); and the output for the IP is always empty... server has TCP Port 21412 and IP Address :: any ideas for what I'm missing? thanks in advance for your help! this stuff is really complicated at first.

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  • Can I check if e-mail address is valid?

    - by simple
    How can I implement following logic? User registers with an e-mail address If provided e-mail address is a valid email address Then user account get's activated or if it is a fake email then user account is not activated I doubt that I can catch the - "Delivery failed reply message", right? anyhow how would you suggest to implement the above logic? PS. I will have to find a way no matter what, client wants it =)

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  • Multiple routers, subnets, gateways etc

    - by allentown
    My current setup is: Cable modem dishes out 13 static IP's (/28), a GB switch is plugged into the cable modem, and has access to those 13 static IP's, I have about 6 "servers" in use right now. The cable modem is also a firewall, DHCP server, and 3 port 10/100 switch. I am using it as a firewall, but not currently as a DHCP server. I have plugged into the cable modem, two network cables, one which goes to the WAN port of a Linksys Dual Band Wireless 10/100/1000 router/switch. Into the linksys are a few workstations, a few printers, and some laptops connecting to wifi. I set the Linksys to use take static IP, and enabled DHCP for the workstations, printers, etc in 192.168.1.1/24. The network for the Linksys is mostly self contained, backups go to a SAN, on that network, it all happens through that switch, over GB. But I also get internet access from it as well via the cable modem using one static IP. This all works, however, I can not "see" the static IP machines when I am on the Linksys. I can get to them via ssh and other protocols, and if I want to from "outside", I open holes, like 80, 25, 587, 143, 22, etc. The second wire, from the cable modem/fireall/switch just uplinks to the managed GB switch. What are the pros and cons of this? I do not like giving up the static IP to the Linksys. I basically have a mixed network of public servers, and internal workstations. I want the public servers on public IP's because I do not want to mess with port forwarding and mappings. Is it correct also, that if someone breaches the Linksys wifi, they still would have a hard time getting to the static IP range, just by nature of the network topology? Today, just for a test, I toggled on the DHCP in the firewall/cable modem at 10.1.10.1/24 range, the Linksys is n the 192.168.1.100/24 range. At that point, all the static IP machines still had in and out access, but Linksys was unreachable. The cable modem only has 10/100 ports, so I will not plug anything but the network drop into it, which is 50Mb/10Mb. Which makes me think this could be less than ideal, as transfers from the workstation network to the server network will be bottlenecked at 100Mb when I have 1000Mb available. I may not need to solve that, if isolation is better though. I do not move a lot of data, if any, from Linsys network to server network, so for it to pretend to be remote is ok. Should I approach this any different? I could enable DHCP on the cable modem/firewall, it should still send out the statics to the GB switch, but will also be a DHCP in 10.1.10.1/24 range? I can then plug the Linksys into the GB switch, which is now picking up statics and the 10.1.10.1/24 ranges, tell the Linksys to use 10.1.10.5 or so. Now, do I disable DHCP on the Linksys, and the cable modem/firewall will pass through the statics and 10.0.10.1/24 ranges as well? Or, could I open a second DHCP pool on the Linksys? I guess doing so gives me network isolation again, but it is just the reverse of what I have now. But I get out of the bottleneck, not that the Linksys could ever really touch real GB speeds anyway, but the managed switch certainly can. This is all because 13 statics are not that many. Right now, 6 "servers", the Linksys, a managed switch, a few SSL certs, and I am running out. I do not want to waste a static IP on the managed GB switch, or the Linksys, unless it provides me some type of benefit. Final question, under my current setup, if I am on a workstation, sitting at 192.168.1.109, the Linksys, with GB, and I send a file over ssh to the static IP machine, is that literally leaving the internet, and coming back in, or does it stay local? To me it seems like: Workstation (192.168.1.109) -> Linksys DHCP -> Linksys Static IP -> Cable Modem -> Server ( and it hits the 10/100 ports on the cable modem, slowing me down. But does it round trip the network, leave and come back in, limiting me to the 50/10 internet speeds? *These are all made up numbers, I do not use default router IP's as I will one day add a VPN, and do not want collisions. I need some recommendations, do I want one big network, or two isolated ones. Printers these days need an IP, everything does, I can not get autoconf/bonjour to be reliable on most printers. but I am also not sure I want the "server" side of my operation to be polluted by the workstation side of my operation. Unless there is some magic subetting I have not learned yet, here is what I am thinking: Cable modem 10/100, has 13 static IP, publicly accessible -> Enable DHCP on the cable modem -> Cable modem plugs into managed switch -> Managed switch gets 10.1.10.1 ssh, telnet, https admin management address -> Managed switch sends static IP's to to servers -> Plug Linksys into managed switch, giving it 10.1.10.2 static internally in Linksys admin -> Linksys gets assigned 10.1.10.x as its DHCP sending range -> Local printers, workstations, iPhones etc, connect to this -> ( Do I enable DHCP or disable it on the Linksys, just define a non over lapping range, or create an entirely new DHCP at 10.1.50.0/24, I think I am back isolated again with that method too? ) Thank you for any suggestions. This is the first time I have had to deal with less than a /24, and most are larger than that, but it is just a drop to a cabinet. Otherwise, it's a router, a few repeaters, and soho stuff that is simple, with one IP. I know a few may suggest going all DHCP on the servers, and I may one day, just not now, there has been too much moving of gear for me to be interested in that, and I would want something in the Catalyst series to deal with that.

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  • Can I get my http back in the address bar in Firefox?

    - by Abel
    Since Firefox 7 (or 6?) they silently removed "http" from the address bar. Previously, when you clicked it, "http" showed up again, allowing to easily just change http into https. So far, I found two ways to get it back, but isn't there a setting I can use to have it permanently in vision again, or at least when I click it? Way 1: copy selection and paste it again Way 2: type the whole scheme again in front of the address ...

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  • cannot delete IPv6 default gateway

    - by NulledPointer
    The commands below should be pretty self-explanatory. Please note that the route for which i get failure is obtained by RA and has very less expiry ( e Flag in UDAe). @vm:~$ ip -6 route 2001:4860:4001:800::1002 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1003 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1005 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:803::100e via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 fd00:ffff:ffff:fff1::/64 dev eth1 proto kernel metric 256 expires 2592300sec fe80::/64 dev eth1 proto kernel metric 256 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto kernel metric 1024 expires 1776sec @vm:~$ @vm:~$ @vm:~$ @vm:~$ sudo route -6 delete default gw fe80::20c:29ff:fe87:f9e7 @vm:~$ ip -6 route 2001:4860:4001:800::1002 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1003 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1005 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:803::100e via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 fd00:ffff:ffff:fff1::/64 dev eth1 proto kernel metric 256 expires 2592279sec fe80::/64 dev eth1 proto kernel metric 256 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto kernel metric 1024 expires 1755sec @vm:~$ @vm:~$ @vm:~$ sudo route -6 delete ::/0 gw fe80::20c:29ff:fe87:f9e7 dev eth1 SIOCDELRT: No such process @vm:~$ @vm:~$ @vm:~$ route -n6 Kernel IPv6 routing table Destination Next Hop Flag Met Ref Use If 2001:4860:4001:800::1002/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:800::1003/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:800::1005/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:803::100e/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 fd00:ffff:ffff:fff1::/64 :: UAe 256 0 0 eth1 fe80::/64 :: U 256 0 0 eth1 ::/0 fe80::20c:29ff:fe87:f9e7 UGDAe 1024 0 0 eth1 ::/0 :: !n -1 1 349 lo ::1/128 :: Un 0 1 3 lo fd00:ffff:ffff:fff1:a00:27ff:fe7f:7245/128 :: Un 0 1 0 lo fd00:ffff:ffff:fff1:fce8:ce07:b9ea:389f/128 :: Un 0 1 0 lo fe80::a00:27ff:fe7f:7245/128 :: Un 0 1 0 lo ff00::/8 :: U 256 0 0 eth1 ::/0 :: !n -1 1 349 lo @vm:~$ UPDATE: Another question is whats the use of link local address as the default route?

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  • How do I set up an IP address on a Linux VM running in VM Player so I can access it from my Windows 7 host?

    - by BradyKelly
    I have just installed an Openbravo appliance on my Windows 7 VM Player host. I am now staring at a command prompt that tells me to go to http://localhost to access the ERP system, but I cannot find any browser on the appliance. I am guessing I should rather follow their advice to configure an IP address for the Linux VM and just access that from a Windows browser on my host. How do I go about this? More specifically, How do I choose a local IP address to assign? How do I set things up so that this IP address is visible to my Windows host? Their help says to assign an DNS, to make the server visible to the internet, but internet visibility per se is not needed. How should I interpret or adapt this help for that? Finally to make the IP address available to the Internet, assign some DNS servers to it: $ echo "nameserver IP_DNS1" /etc/resolv.conf $ echo "nameserver IP_DNS2" /etc/resolv.conf

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  • Website hosted at home pingable from outside, but not browseable from outside [closed]

    - by Richard DesLonde
    I have a simple setup. Server at home has local I.P. 192.168.1.3 IIS is running on the server and the website is up. Windows firewall on the server has an exception rule for port 80 TCP Router has static I.P. XX.XXX.XX.XXX Router is forwarding TCP port 80 to 192.168.1.3 My domain registrar is my DNS host and is pointing to the static I.P. XX.XXX.XX.XXX of the router Here's what I can and can't do. I can browse the website from within my home network either by I.P. or domain name. I can ping the domain and the I.P. from outside the network (from a computer at work). I can't browse the website either by domain name or by I.P. Wierd. Why I can't browse my website?

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  • Linux policy routing - packets not coming back

    - by Bugsik
    i am trying to set up policy routing on my home server. My network looks like this: Host routed VPN gateway Internet link through VPN 192.168.0.35/24 ---> 192.168.0.5/24 ---> 192.168.0.1 DSL router 10.200.2.235/22 .... .... 10.200.0.1 VPN server The traffic from 192.168.0.32/27 should be and is routed through VPN. I wanted to define some routing policies to route some traffic from 192.168.0.5 through VPN as well - for start - from user with uid 2000. Policy routing is done using iptables mark target and ip rule fwmark. The problem: When connecting using user 2000 from 192.168.0.5 tcpdump shows outgoing packets, but nothing comes back. Traffic from 192.168.0.35 works fine (here I am not using fwmark but src policy). Here is my VPN gateway setup: # uname -a Linux placebo 3.2.0-34-generic #53-Ubuntu SMP Thu Nov 15 10:49:02 UTC 2012 i686 i686 i386 GNU/Linux # iptables -V iptables v1.4.12 # ip -V ip utility, iproute2-ss111117 IPtables rules (all policies in table filter are ACCEPT) # iptables -t mangle -nvL Chain PREROUTING (policy ACCEPT 770K packets, 314M bytes) pkts bytes target prot opt in out source destination Chain INPUT (policy ACCEPT 767K packets, 312M bytes) pkts bytes target prot opt in out source destination Chain FORWARD (policy ACCEPT 5520 packets, 1920K bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 782K packets, 901M bytes) pkts bytes target prot opt in out source destination 74 4707 MARK all -- * * 0.0.0.0/0 0.0.0.0/0 owner UID match 2000 MARK set 0x3 Chain POSTROUTING (policy ACCEPT 788K packets, 903M bytes) pkts bytes target prot opt in out source destination # iptables -t nat -nvL Chain PREROUTING (policy ACCEPT 996 packets, 51172 bytes) pkts bytes target prot opt in out source destination Chain INPUT (policy ACCEPT 7 packets, 432 bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 1364 packets, 112K bytes) pkts bytes target prot opt in out source destination Chain POSTROUTING (policy ACCEPT 2302 packets, 160K bytes) pkts bytes target prot opt in out source destination 119 7588 MASQUERADE all -- * vpn 0.0.0.0/0 0.0.0.0/0 Routing: # ip addr show 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue state UNKNOWN link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo inet6 ::1/128 scope host valid_lft forever preferred_lft forever 2: eth0: <BROADCAST,MULTICAST,PROMISC,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast master lan state UNKNOWN qlen 1000 link/ether 00:40:63:f9:c3:8f brd ff:ff:ff:ff:ff:ff valid_lft forever preferred_lft forever 3: lan: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UP link/ether 00:40:63:f9:c3:8f brd ff:ff:ff:ff:ff:ff inet 192.168.0.5/24 brd 192.168.0.255 scope global lan inet6 fe80::240:63ff:fef9:c38f/64 scope link valid_lft forever preferred_lft forever 4: vpn: <POINTOPOINT,MULTICAST,NOARP,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UNKNOWN qlen 100 link/none inet 10.200.2.235/22 brd 10.200.3.255 scope global vpn # ip rule show 0: from all lookup local 32764: from all fwmark 0x3 lookup VPN 32765: from 192.168.0.32/27 lookup VPN 32766: from all lookup main 32767: from all lookup default # ip route show table VPN default via 10.200.0.1 dev vpn 10.200.0.0/22 dev vpn proto kernel scope link src 10.200.2.235 192.168.0.0/24 dev lan proto kernel scope link src 192.168.0.5 # ip route show default via 192.168.0.1 dev lan metric 100 10.200.0.0/22 dev vpn proto kernel scope link src 10.200.2.235 192.168.0.0/24 dev lan proto kernel scope link src 192.168.0.5 TCP dump showing no traffic coming back when connection is made from 192.168.0.5 user 2000 # tcpdump -i vpn tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on vpn, link-type RAW (Raw IP), capture size 65535 bytes ### Traffic from user 2000 on 192.168.0.5 ### 10:19:05.629985 IP 10.200.2.235.37291 > 10.100-78-194.akamai.com.http: Flags [S], seq 2868799562, win 14600, options [mss 1460,sackOK,TS val 6887764 ecr 0,nop,wscale 4], length 0 10:19:21.678001 IP 10.200.2.235.37291 > 10.100-78-194.akamai.com.http: Flags [S], seq 2868799562, win 14600, options [mss 1460,sackOK,TS val 6891776 ecr 0,nop,wscale 4], length 0 ### Traffic from 192.168.0.35 ### 10:23:12.066174 IP 10.200.2.235.49247 > 10.100-78-194.akamai.com.http: Flags [S], seq 2294159276, win 65535, options [mss 1460,nop,wscale 4,nop,nop,TS val 557451322 ecr 0,sackOK,eol], length 0 10:23:12.265640 IP 10.100-78-194.akamai.com.http > 10.200.2.235.49247: Flags [S.], seq 2521908813, ack 2294159277, win 14480, options [mss 1367,sackOK,TS val 388565772 ecr 557451322,nop,wscale 1], length 0 10:23:12.276573 IP 10.200.2.235.49247 > 10.100-78-194.akamai.com.http: Flags [.], ack 1, win 8214, options [nop,nop,TS val 557451534 ecr 388565772], length 0 10:23:12.293030 IP 10.200.2.235.49247 > 10.100-78-194.akamai.com.http: Flags [P.], seq 1:480, ack 1, win 8214, options [nop,nop,TS val 557451552 ecr 388565772], length 479 10:23:12.574773 IP 10.100-78-194.akamai.com.http > 10.200.2.235.49247: Flags [.], ack 480, win 7776, options [nop,nop,TS val 388566081 ecr 557451552], length 0

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