Search Results

Search found 97296 results on 3892 pages for 'standard user'.

Page 189/3892 | < Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >

  • User Control access from code behind problem.

    - by BillTetrault
    I have a user control called adminMenu and I use it in my index.aspx and all is fine, but I need to access a MenuItem in adminMenu and need to change NavigateUrl on the MenuItem. Tried this code with no luck: MenuItem MaintenanceReports = this.adminMenu.FindItem("MaintenanceReports"); Not sure if I should be accessing adminMenu properties from controls code behind, but when I try from controls code behind was not able to access it either, any ideas would be appreciated.

    Read the article

  • manage user permissions in php

    - by user420528
    i am creating a marks management system using php & mysqlwhere the concerned faculty will be able to login and enter the marks of the students. i can go with a simple table but the problem is there are 288 different subjects for which marks must be entered. So creating a mysql table with so many subjects does not look good for me. please suggest me the best way to manage user permissions so that only the corresponding faculty will be able to enter marks

    Read the article

  • Using `g_object_set_data` for passing user name.

    - by PP
    I am using g_object_set_data to set user name with event_box so in call back i can get it with in event_box pointer. g_object_set_data(G_OBJECT(event_box), "user_name", (gpointer)(user_name) ); but problem is that i am setting user_name which is not an pointer allocated string. It is an local string (not allocated on hip) which gets destroyed. So is it necessary to allocated and then use the pointer, i just want to associate one name with this event_box.

    Read the article

  • Checking array of censored words against user submitted content

    - by steve-o
    Hello, I have set up an array of censored words and I want to check that a user submitted comment doesn't contain any of these words. What is the most efficient way of doing this? All I've come up with so far is splitting the string into an array of words and checking it against the array of censored words, but I've a feeling there's a neater way of doing this.

    Read the article

  • Camping: Return user to recent entries, but keep errors

    - by echoback
    Users can view a specific entry in my webapp with a URL. /entry/8, for example. If an entry doesn't exist, "Entry not found" gets appended to @messages and I render an error page. I'd like to redirect the user to /recent, but I can't figure out a good way to keep the error message around to be displayed. There are other actions that need to take place in the Recent controller, so I can't just duplicate the query and render :posts.

    Read the article

  • Aside from a prototype, what is the next best thing to satisfy a user

    - by user1639998
    Aside from a prototype, what is the next best thing to satisfy a user who really wants to know what an application will be like? Choice 1 A process model Choice 2 An interaction diagram Choice 3 A data-flow diagram Choice 4 A class diagram Choice 5 A class-state diagram 2 is my partner's choice 3 is my choice I stick to my colors also he stick to his. which one is better?

    Read the article

  • Stop a user directly accesing a page

    - by James Jeffery
    I have a page called create.php. It receives post variables and sets up accounts. I don't want that page to be accessible by a user. What's the conventional way of achieving this? I think I remember reading something about including a page with a CONSTANT. If the CONSTANT is not present the page has been accessed directly. I think Wordpress also do it.

    Read the article

  • Why can a local root turn into any LDAP user?

    - by Daniel Gollás
    I know this has been asked here before, but I am not satisfied with the answers and don't know if it's ok to revive and hijack an older question. We have workstations that authenticate users on an LDAP server. However, the local root user can su into any LDAP user without needing a password. From my perspective this sounds like a huge security problem that I would hope could be avoided at the server level. I can imagine the following scenario where a user can impersonate another and don't know how to prevent it: UserA has limited permissions, but can log into a company workstation using their LDAP password. They can cat /etc/ldap.conf and figure out the LDAP server's address and can ifconfig to check out their own IP address. (This is just an example of how to get the LDAP address, I don't think that is usually a secret and obscurity is not hard to overcome) UserA takes out their own personal laptop, configures authentication and network interfaces to match the company workstation and plugs in the network cable from the workstation to their laptop, boots and logs in as local root (it's his laptop, so he has local root) As root, they su into any other user on LDAP that may or may not have more permissions (without needing a password!), but at the very least, they can impersonate that user without any problem. The other answers on here say that this is normal UNIX behavior, but it sounds really insecure. Can the impersonated user act as that user on an NFS mount for example? (the laptop even has the same IP address). I know they won't be able to act as root on a remote machine, but they can still be any other user they want! There must be a way to prevent this on the LDAP server level right? Or maybe at the NFS server level? Is there some part of the process that I'm missing that actually prevents this? Thanks!!

    Read the article

  • ASP.NET: aggregating validators in a user control

    - by orsogufo
    I am developing a web application where I would like to perform a set of validations on a certain field (an account name in the specific case). I need to check that the value is not empty, matches a certain pattern and is not already used. I tried to create a UserControl that aggregates a RequiredFieldValidator, a RegexValidator and a CustomValidator, then I created a ControlToValidate property like this: public partial class AccountNameValidator : System.Web.UI.UserControl { public string ControlToValidate { get { return ViewState["ControlToValidate"] as string; } set { ViewState["ControlToValidate"] = value; AccountNameRequiredFieldValidator.ControlToValidate = value; AccountNameRegexValidator.ControlToValidate = value; AccountNameUniqueValidator.ControlToValidate = value; } } } However, if I insert the control on a page and set ControlToValidate to some control ID, when the page loads I get an error that says Unable to find control id 'AccountName' referenced by the 'ControlToValidate' property of 'AccountNameRequiredFieldValidator', which makes me think that the controls inside my UserControl cannot resolve correctly the controls in the parent page. So, I have two questions: 1) Is it possible to have validator controls inside a UserControl validate a control in the parent page? 2) Is it correct and good practice to "aggregate" multiple validator controls in a UserControl? If not, what is the standard way to proceed?

    Read the article

  • Adding to page control collection from inside a user control

    - by Zarigani
    I have an asp.net usercontrol which represents a "popup" dialog. Basically, it's a wrapper for the jQuery UI dialog which can be subclassed to easily make dialogs. As part of this control, I need to inject a div into the page the control is used on, either at the very top or very bottom of the form so that when the popup is instantiated, it's parent is changed to this div. This allows "nested" popups without the child popup being trapped inside the parent popup. The trouble is, I can't find a safe way to inject this div into the page. A usercontrol doesn't have a preinit event, so I can't do it there, and calling Page.Form.Controls.Add(...) in Init, Load or PreRender causes the standard exception "The control collection cannot be modified during DataBind, Init, Load, PreRender or Unload phases." I thought I had found a solution by using... ScriptManager.RegisterClientScriptBlock(Page, Me.GetType, UniqueID + "_Dialog_Div", containerDiv, False) ... which seemed to work well normally, but recently a coworker tried putting an UpdatePanel inside the dialog and now she's getting the error "The script tag registered for type 'ASP.controls_order_viewzips_ascx' and key 'ctl00$ContentBody$OViewZips_Dialog_Div' has invalid characters outside of the script tags: . Only properly formatted script tags can be registered." How are you supposed to add controls to the pages control collection from inside a user control?

    Read the article

  • Designing Mobile SMS text advertising system

    - by Ramraj Edagutti
    Currently, I am working on a product where we have an SMS text advertising system, and using this, we setup advertising campaigns for clients, and later these campaigns are sent to the end users. This is very similar to Google Adwords, but targeted to Mobile users via SMS. Just to give an overview of the system Each Campaign is mapped to an advertiser Campaign has start date and end date Campaign has a filter condition(s) or query to select the target user base from our database (to whom we send Campaigns) Target user base can be fixed, for e.g send campaign to 10000 users Target user base can also be dynamic based on query condition, for e.g send campaign to users who are active and from a particular state, district, town etc. (this way user base will be keep changing on daily basis) Campaign can have multiple campaign messages Each campaign message has start date and end date Each campaign message can have multiple message texts for different locales, for e.g English,Hindi,Telugu etc After creating an advertisement campaign, we run daily night job to provision the target user base for that a particular campaign in a separate table, and another daily job runs on morning times and checks provisioned table for campaigns and targeted users and sends the campaign to users via SMS. Problem is, current UI for creating advertising campaigns is designed in a very technical manner, I mean, normal user or business owner or clients can not use the UI to create a campaign. Below are reasons why the UI is very technical in nature Filter condition(s) or query input filed, takes user ids or mobile numbers or SQL queries. Most of times or almost every time, we use big SQL queries So we end up storing SQL queries in a database for a campaign, later we use this SQL query to fetch targeted user base. For scheduling these campaigns, we have input filed on UI which takes quartz cron expression(s) ( for e.g. send campaign on "0 0 9 1-10 MAR 2012" ), again very technical in nature Normal user or business owner, can not use the UI for creating campaigns for reasons mentioned above, Currently, we ourself (developers) helping clients to setup/create campaigns. we are trying to re-design the UI to make it more user friendly so that any user can go to UI and create an advertisement campaign by himself. I am thinking of re-designing the current UI similar to Google Adwords interface, especially for selecting target users based on user geography like country, state, city etc. I also need to select users based user subscription(s), which might make system even more complex. And also, for campaign scheduling, I am thinking of using weekdays with hours. For example, I will shows Monday to Sunday on UI, and user can select the from hours, to hours etc. Any better ideas or suggestion on how to design UI in very user friendly manner and what design should be followed on server side code (we write backend code on java/jpa/spring/quartz)? And I am looking for ideas or design patterns on how to build SQL queries (using JPA/Hinernate) programmatically on server side, based on varies conditions like based on country, state, town, village, and user subscriptions.

    Read the article

  • PeopleSoft New Design Solves Navigation Problem

    - by Applications User Experience
    Anna Budovsky, User Experience Principal Designer, Applications User Experience In PeopleSoft we strive to improve User Experience on all levels. Simplifying navigation and streamlining access to the most important pages is always an important goal. No one likes to waste time waiting for pages to load and watching a spinning glass going on and on. Those performance-affecting server trips, page-load waits and just-too-many clicks were complained about for a long time. Something had to be done. A few new designs came in PeopleSoft 9.2 helping users to access their everyday work areas easier and faster. For example, Dashboard and Work Center aggregate most accessed information sections on a single page; Related Information allows users to complete transaction-related-research without interrupting a transaction and Secure Search gets users to a specific page directly. Today we’ll talk about the Actions menu. Most PeopleSoft pages are shared between individual products and product lines. It means changing the content on a single page involves Oracle development and quality assurance time for making and testing the changes. In order to streamline the navigation and cut down on accessing PeopleSoft pages one-page-at-a-time, we introduced a new menu design. The new menu allows accessing shared pages without the Oracle development team making any local changes, and it works as an additional one-click-path to specific high-traffic actionable pages. Let’s look at how many steps it took to Change Salary for an employee in HCM 9.1 before: Figure 1. BEFORE: The 6 steps a user would take to Change Salary in PeopleSoft HCM 9.1 In PeopleSoft 9.1 it took 5 steps + page loading time + additional verification time for making sure a correct employee is selected from the table. In PeopleSoft 9.2 it only takes 2 steps. To complete Ad Hoc Change Salary action, the user can start from the HCM Manager's Dashboard, click the Action menu within a table, choose a menu option, and access a correct employee’s details page to take an action. Figure 2. AFTER: The 2 steps a user would take to Change Salary in PeopleSoft HCM 9.2 The new menu is placed on a row level which ensures the user accesses the correct employee’s details page. The Actions menu separates menu options into hierarchical sections which help to scan and access the correct option quickly. The new menu’s small size and its structure enabled users to access high-traffic pages from any page and from any part of the page. No more spinning hourglass, no more multiple pages upload. The flexible design fits anywhere on a page and provides a fast and reliable path to the correct destination within the product. Now users can: Access any target page no matter how far it is buried from the starting point; Reduce navigation and page-load time; Improve productivity and reduce errors. The new menu design is available and widely used in all PeopleSoft 9.2 product lines.

    Read the article

  • Can see samba shares but not access them

    - by nitefrog
    For the life of me I cannot figure this one out. I have samba installed and set up on the ubuntu box and on the Win7 box I CAN SEE all the shares I created. I created two users on ubuntu that map to the users in windows. On ubuntu they are both admins, user A & B on Windows User A is admin and user B is poweruser. User A can see both shares and access them, but user B can see everythin, but only access the homes directory, the other directory throws an error. I have two drives in Ubuntu and this is the smb.config file (I am new to samba): [global] workgroup = WORKGROUP server string = %h server (Samba, Ubuntu) wins support = no dns proxy = yes name resolve order = lmhosts host wins bcast log file = /var/log/samba/log.%m max log size = 1000 syslog = 0 panic action = /usr/share/samba/panic-action %d security = user encrypt passwords = true passdb backend = tdbsam obey pam restrictions = yes unix password sync = yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . pam password change = yes map to guest = bad user ; usershare max shares = 100 usershare allow guests = yes And here is the share section: Both user A & B can access this from windows. No problems. [homes] comment = Home Directories browseable = no writable = yes Both User A & B can see this share, but only user A can access it. User B get an error thrown. [stuff] comment = Unixmen File Server path = /media/data/appinstall/ browseable = yes ;writable = no read only = yes hosts allow = The permission for the media/data/appinstall/ is as follows: appInstall properties: share name: stuff Allow others to create and delete files in this folder is cheeked Guest access (for people without a user account) is checked permissions: Owner: user A Folder Access: Create and delete files File Access: --- Group: user A Folder Access: Create and delete files File Access: --- Others Folder Access: Create and delete files File Access: --- I am at a loss and need to get this work. Any ideas? The goal is to have a setup like this. 3 users on window machines. Each user on the data drive will have their own personal folder where they are the ones that can only access, then another folder where 2 of the users will have read only and one user full access. I had this setup before on windows, but after what happened I am NEVER going back to windows, so Unix here I am to stay! I am really stuck. I am running Ubuntu 11. I could reformat again and put on version 10 if that would make life easier. I have been dealing with this since Wed. 3pm. Thanks.

    Read the article

  • Using C# FindControl to find a user-control in the master page

    - by Jisaak
    So all I want to do is simply find a user control I load based on a drop down selection. I have the user control added but now I'm trying to find the control so I can access a couple properties off of it and I can't find the control for the life of me. I'm actually doing all of this in the master page and there is no code in the default.aspx page itself. Any help would be appreciated. MasterPage.aspx <body> <form id="form1" runat="server"> <div> <asp:ScriptManager runat="server"> </asp:ScriptManager> </div> <asp:UpdatePanel ID="UpdatePanel2" runat="server" UpdateMode="Conditional" ChildrenAsTriggers="false" OnLoad="UpdatePanel2_Load"> <ContentTemplate> <div class="toolbar"> <div class="section"> <asp:DropDownList ID="ddlDesiredPage" runat="server" AutoPostBack="True" EnableViewState="True" OnSelectedIndexChanged="goToSelectedPage"> </asp:DropDownList> &nbsp; <asp:DropDownList ID="ddlDesiredPageSP" runat="server" AutoPostBack="True" EnableViewState="True" OnSelectedIndexChanged="goToSelectedPage"> </asp:DropDownList> <br /> <span class="toolbarText">Select a Page to Edit</span> </div> <div class="options"> <div class="toolbarButton"> <asp:LinkButton ID="lnkSave" CssClass="modal" runat="server" OnClick="lnkSave_Click"><span class="icon" id="saveIcon" title="Save"></span>Save</asp:LinkButton> </div> </div> </div> </ContentTemplate> <Triggers> </Triggers> </asp:UpdatePanel> <div id="contentContainer"> <asp:UpdatePanel ID="UpdatePanel1" runat="server" OnLoad="UpdatePanel1_Load" UpdateMode="Conditional" ChildrenAsTriggers="False"> <ContentTemplate> <asp:ContentPlaceHolder ID="ContentPlaceHolder1" runat="server"> </asp:ContentPlaceHolder> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="lnkHome" EventName="Click" /> <asp:AsyncPostBackTrigger ControlID="rdoTemplate" EventName="SelectedIndexChanged" /> </Triggers> </asp:UpdatePanel> </div> MasterPage.cs protected void goToSelectedPage(object sender, System.EventArgs e) { temp1 ct = this.Page.Master.LoadControl("temp1.ascx") as temp1; ct.ID = "TestMe"; this.UpdatePanel1.ContentTemplateContainer.Controls.Add(ct); } //This is where I CANNOT SEEM TO FIND THE CONTROL //////////////////////////////////////// protected void lnkSave_Click(object sender, System.EventArgs e) { UpdatePanel teest = this.FindControl("UpdatePanel1") as UpdatePanel; Control test2 = teest.ContentTemplateContainer.FindControl("ctl09") as Control; temp1 test3 = test2.FindControl("TestMe") as temp1; string maybe = test3.Col1TopTitle; } Here I don't understand what it's telling me. for "par" I get "ctl09" and I have no idea how I am supposed to find this control. temp1.ascx.cs protected void Page_Load(object sender, EventArgs e) { string ppp = this.ID; string par = this.Parent.ID; }

    Read the article

  • ASP.NET: Button in user control not posting back

    - by Ronnie Overby
    I have a simple user control with this code: <%@ Control Language="C#" AutoEventWireup="true" CodeFile="Pager.ascx.cs" Inherits="Pager" %> <table style="width: 100%;"> <tr> <td runat="server" id="PageControls"> <!-- This button has the problem: --> <asp:Button ID="btnPrevPage" runat="server" Text="&larr;" OnClick="btnPrevPage_Click" /> Page <asp:DropDownList runat="server" ID="ddlPage" AutoPostBack="true" OnSelectedIndexChanged="ddlPage_SelectedIndexChanged" /> of <asp:Label ID="lblTotalPages" runat="server" /> <!-- This button has the problem: --> <asp:Button ID="btnNextPage" runat="server" Text="&rarr;" OnClick="btnNextPage_Click" /> </td> <td align="right" runat="server" id="itemsPerPageControls"> <asp:Literal ID="perPageText1" runat="server" /> <asp:DropDownList ID="ddlItemsPerPage" runat="server" AutoPostBack="true" OnSelectedIndexChanged="ddlItemsPerPage_SelectedIndexChanged" /> <asp:Literal ID="perPageText2" runat="server" /> </td> </tr> </table> As you can see, the 2 buttons are wired to click events, which are defined correctly in the code-behind. Now, here is how I include an instance of the control on my page: <uc:Pager ID="Pager1" runat="server" TotalRecords="100" DisplayItemsPerPage="true" ItemsPerPageChoices="10,25,50,100" ItemsPerPageFormatString="Sessions/Page: {0}" PageSize="25" OnPageChanged="PageChanged" OnPageSizeChanged="PageChanged" /> I noticed though, that the 2 buttons in my user control weren't causing a post back when clicked. The drop down list does cause postback, though. Here is the rendered HTML: <table style="width: 100%;"> <tr> <td id="ctl00_MainContent_Pager1_PageControls" align="left"> <!-- No onclick event! Why? --> <input type="submit" name="ctl00$MainContent$Pager1$btnPrevPage" value="?" id="ctl00_MainContent_Pager1_btnPrevPage" /> Page <select name="ctl00$MainContent$Pager1$ddlPage" onchange="javascript:setTimeout('__doPostBack(\'ctl00$MainContent$Pager1$ddlPage\',\'\')', 0)" id="ctl00_MainContent_Pager1_ddlPage"> <option value="1">1</option> <option selected="selected" value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> </select> of <span id="ctl00_MainContent_Pager1_lblTotalPages">6</span> <!-- No onclick event! Why? --> <input type="submit" name="ctl00$MainContent$Pager1$btnNextPage" value="?" id="ctl00_MainContent_Pager1_btnNextPage" /> </td> <td id="ctl00_MainContent_Pager1_itemsPerPageControls" align="right"> Sessions/Page: <select name="ctl00$MainContent$Pager1$ddlItemsPerPage" onchange="javascript:setTimeout('__doPostBack(\'ctl00$MainContent$Pager1$ddlItemsPerPage\',\'\')', 0)" id="ctl00_MainContent_Pager1_ddlItemsPerPage"> <option value="10">10</option> <option selected="selected" value="25">25</option> <option value="50">50</option> <option value="100">100</option> </select> </td> </tr> </table> And, as you can see, there is no onclick attribute being rendered in the button's input elements. Why not?

    Read the article

  • initializing structs using user-input information

    - by johnny boy
    I am trying to make a program that works with poker (texas holdem) starting hands; each hand has a value from 1 to 169, and i want to be able to input each card and whether they are suited or not, and have those values correspond to a series of structs. Here is the code so far, i cant seem to get it to work (im a beginning programmer). oh and im using visual studio 2005 by the way #include "stdafx.h" #include <iostream> int main() { using namespace std; struct FirstCard { struct SecondCard { int s; //suited int n; //non-suited }; SecondCard s14; SecondCard s13; SecondCard s12; SecondCard s11; SecondCard s10; SecondCard s9; SecondCard s8; SecondCard s7; SecondCard s6; SecondCard s5; SecondCard s4; SecondCard s3; SecondCard s2; }; FirstCard s14; //ace FirstCard s13; //king FirstCard s12; //queen FirstCard s11; //jack FirstCard s10; FirstCard s9; FirstCard s8; FirstCard s7; FirstCard s6; FirstCard s5; FirstCard s4; FirstCard s3; FirstCard s2; s14.s14.n = 169; // these are the values that each combination s13.s13.n = 168; // will evaluate to, would eventually have s12.s12.n = 167; // hand combinations all the way down to 1 s11.s11.n = 166; s14.s13.s = 165; s14.s13.s = 164; s10.s10.n = 163; //10, 10, nonsuited s14.s13.n = 162; s14.s11.s = 161; s13.s12.s = 160;// king, queen, suited s9.s9.n = 159; s14.s10.s = 158; s14.s12.n = 157; s13.s11.s = 156; s8.s8.n = 155; s12.s11.s = 154; s13.s10.s = 153; s14.s9.s = 152; s14.s11.n = 151; cout << "enter first card: " << endl; cin >> somthing?//no idea what to put here, but this would somehow //read out the user input (a number from 2 to 14) //and assign it to the corresponding struct cout << firstcard.secondcard.suited_or_not << endl; //this would change depending //on what the user inputs system("Pause"); }

    Read the article

< Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >