Search Results

Search found 6604 results on 265 pages for 'double precision'.

Page 19/265 | < Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >

  • Java Double Array

    - by user1062058
    I'm having trouble setting up and placing values into an array using a text file containing the floating point numbers 2.1 and 4.3 each number is separated by a space - below is the error I'm getting: Exception in thread "main" java.util.NoSuchElementException import java.util.*; import java.io.*; public class DoubleArray { public static void main(String[] args) throws FileNotFoundException { Scanner in = new Scanner(new FileReader("mytestnumbers.txt")); double [] nums = new double[2]; for (int counter=0; counter < 2; counter++) { int index = 0; index++; nums[index] = in.nextDouble(); } } } Thanks, I'm sure this isn't a hard question to answer... I appreciate your time.

    Read the article

  • Preserving NULL values in a Double Variable

    - by Sam
    Hi, I'm working on a vb.net application which imports from an Excel spreadsheet. If rdr.HasRows Then Do While rdr.Read() If rdr.GetValue(0).Equals(System.DBNull.Value) Then Return Nothing Else Return rdr.GetValue(0) End If Loop Else I was using string value to store the double values and when preparing the database statement I'd use this code: If (LastDayAverage = Nothing) Then command.Parameters.AddWithValue("@WF_LAST_DAY_TAG", System.DBNull.Value) Else command.Parameters.AddWithValue("@WF_LAST_DAY_TAG", Convert.ToDecimal(LastDayAverage)) End If I now have some data with quite a few decimal places and the data was put into the string variable in scientific notation, so this seems to be the wrong approach. It didn't seem right using the string variable to begin with. If I use a double or decimal type variable, the blank excel values come across as 0.0. How can I preserve the blank values? Thanks

    Read the article

  • Type casting int into double C++

    - by user1705380
    I am new to programming and this might be an obvious question, though i cannot for life of me figure out why my program is not returning as a double. I am suppose to write a stocks program that takes in shares of stock, whole dollar portion of price and the fraction portion. And the fraction portion is to be inputted as two int values, and include a function definition with 3 int values.The function returns the price as a double. #include <iostream> using namespace std; int price(int, int, int); int main() { int dollars, numerator, denominator, price1, shares; char ans; do { cout<<"Enter the stock price and the number of shares.\n"; cout<<"Enter the price and integers: Dollars, numerator, denominator\n"; cin>>dollars>>numerator>>denominator; cout<<"Enter the number of shares held\n"; cin>>shares; cout<<shares; price1 = price(dollars,numerator,denominator); cout<<" shares of stock with market price of "; cout<< dollars << " " << numerator<<'/'<<denominator<<endl; cout<<"have a value of " << shares * price1<<endl; cout<<"Enter either Y/y to continue"; cin>>ans; }while (ans == 'Y' || ans == 'y'); system("pause"); return 0; } int price(int dollars, int numerator, int denominator) { return dollars + numerator/static_cast<double>(denominator); }

    Read the article

  • C++: Checking for non-numeric input and assigning to a double

    - by Brundle
    Here is the code I have at the moment: char ch; int sum = 0; double values[10]; int i = 0; cin >> ch; while (!isalpha(ch)) { values[i] = ch; sum += values[i]; i++; cin >> ch; } What is happening is that if I enter the value 1, that gets assigned to ch as a char. Now ch is assigning it's value to a double and doing an implicit cast. So it is assigning the ASCII value of '1' to values[i]. I want it to just assign 1 to values[i]. Is there a better way to do this? Or is there something that I'm missing?

    Read the article

  • Double "!!" in Ruby [closed]

    - by Alex Maslakov
    Possible Duplicate: What does !! mean in ruby? Ruby, !! operator (a/k/a the double-bang) Sometimes I see a Ruby code like this def sent? !!@sent_at end It seems to be not logical. Is it necessary to use here double !? As far as I'm concerned, it might be just def sent? @sent_at end UPDATE: then what is the difference between these def sent? !!@sent_at end def sent? @sent_at.nil? end def sent? @sent_at == nil end

    Read the article

  • Making Visual C++ DLL from C++ class

    - by prosseek
    I have the following C++ code to make dll (Visual Studio 2010). class Shape { public: Shape() { nshapes++; } virtual ~Shape() { nshapes--; }; double x, y; void move(double dx, double dy); virtual double area(void) = 0; virtual double perimeter(void) = 0; static int nshapes; }; class __declspec(dllexport) Circle : public Shape { private: double radius; public: Circle(double r) : radius(r) { }; virtual double area(void); virtual double perimeter(void); }; class __declspec(dllexport) Square : public Shape { private: double width; public: Square(double w) : width(w) { }; virtual double area(void); virtual double perimeter(void); }; I have the __declspec, class __declspec(dllexport) Circle I could build a dll with the following command CL.exe /c example.cxx link.exe /OUT:"example.dll" /DLL example.obj When I tried to use the library, Square* square; square->area() I got the error messages. What's wrong or missing? example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall ... Square::area(void)" (?area@Square@@UAENXZ) ADDED Following wengseng's answer, I modified the header file, and for DLL C++ code, I added #define XYZLIBRARY_EXPORT However, I still got errors. example_unittest.obj : error LNK2019: unresolved external symbol "__declspec(dllimport) public: __th iscall Circle::Circle(double)" (__imp_??0Circle@@QAE@N@Z) referenced in function "protected: virtual void __thiscall TestOne::SetUp(void)" (?SetUp@TestOne@@MAEXXZ) example_unittest.obj : error LNK2019: unresolved external symbol "__declspec(dllimport) public: __th iscall Square::Square(double)" (__imp_??0Square@@QAE@N@Z) referenced in function "protected: virtual void __thiscall TestOne::SetUp(void)" (?SetUp@TestOne@@MAEXXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Square::area(void)" (?area@Square@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Square::perimeter(void)" (?perimeter@Square@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Circle::area(void)" (?area@Circle@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Circle::perimeter(void)" (?perimeter@Circle@@UAENXZ)

    Read the article

  • Recording/Reading C doubles in the IEEE 754 interchange format

    - by rampion
    So I'm serializing a C data structure for cross-platform use, and I want to make sure I'm recording my floating point numbers in a cross-platform manner. I had been planning on just doing char * pos; /*...*/ *((double*) pos) = dataStructureInstance->fieldWithOfTypeDouble; pos += sizeof(double); But I wasn't sure that the bytes would be recorded in the char * array in the IEEE 754 interchange format. I've been bitten by cross-platform issues before (endian-ness and whatnot). Is there anything I need to do to a double to get the bytes in interchange format?

    Read the article

  • Java Math.cos() Method Does Not Return 0 When Expected

    - by dimo414
    Using Java on a Windows 7 PC (not sure if that matters) and calling Math.cos() on values that should return 0 (like pi/2) instead returns small values, but small values that, unless I'm misunderstanding, are much greater than 1 ulp off from zero. Math.cos(Math.PI/2) = 6.123233995736766E-17 Math.ulp(Math.cos(Math.PI/2)) = 1.232595164407831E-32 Is this in fact within 1 ulp and I'm simply confused? And would this be an acceptable wrapper method to resolve this minor inaccuracy? public static double cos(double a){ double temp = Math.abs(a % Math.PI); if(temp == Math.PI/2) return 0; return Math.cos(a); }

    Read the article

  • F# - Facebook Hacker Cup - Double Squares

    - by Jacob
    I'm working on strengthening my F#-fu and decided to tackle the Facebook Hacker Cup Double Squares problem. I'm having some problems with the run-time and was wondering if anyone could help me figure out why it is so much slower than my C# equivalent. There's a good description from another post; Source: Facebook Hacker Cup Qualification Round 2011 A double-square number is an integer X which can be expressed as the sum of two perfect squares. For example, 10 is a double-square because 10 = 3^2 + 1^2. Given X, how can we determine the number of ways in which it can be written as the sum of two squares? For example, 10 can only be written as 3^2 + 1^2 (we don't count 1^2 + 3^2 as being different). On the other hand, 25 can be written as 5^2 + 0^2 or as 4^2 + 3^2. You need to solve this problem for 0 = X = 2,147,483,647. Examples: 10 = 1 25 = 2 3 = 0 0 = 1 1 = 1 My basic strategy (which I'm open to critique on) is to; Create a dictionary (for memoize) of the input numbers initialzed to 0 Get the largest number (LN) and pass it to count/memo function Get the LN square root as int Calculate squares for all numbers 0 to LN and store in dict Sum squares for non repeat combinations of numbers from 0 to LN If sum is in memo dict, add 1 to memo Finally, output the counts of the original numbers. Here is the F# code (See code changes at bottom) I've written that I believe corresponds to this strategy (Runtime: ~8:10); open System open System.Collections.Generic open System.IO /// Get a sequence of values let rec range min max = seq { for num in [min .. max] do yield num } /// Get a sequence starting from 0 and going to max let rec zeroRange max = range 0 max /// Find the maximum number in a list with a starting accumulator (acc) let rec maxNum acc = function | [] -> acc | p::tail when p > acc -> maxNum p tail | p::tail -> maxNum acc tail /// A helper for finding max that sets the accumulator to 0 let rec findMax nums = maxNum 0 nums /// Build a collection of combinations; ie [1,2,3] = (1,1), (1,2), (1,3), (2,2), (2,3), (3,3) let rec combos range = seq { let count = ref 0 for inner in range do for outer in Seq.skip !count range do yield (inner, outer) count := !count + 1 } let rec squares nums = let dict = new Dictionary<int, int>() for s in nums do dict.[s] <- (s * s) dict /// Counts the number of possible double squares for a given number and keeps track of other counts that are provided in the memo dict. let rec countDoubleSquares (num: int) (memo: Dictionary<int, int>) = // The highest relevent square is the square root because it squared plus 0 squared is the top most possibility let maxSquare = System.Math.Sqrt((float)num) // Our relevant squares are 0 to the highest possible square; note the cast to int which shouldn't hurt. let relSquares = range 0 ((int)maxSquare) // calculate the squares up front; let calcSquares = squares relSquares // Build up our square combinations; ie [1,2,3] = (1,1), (1,2), (1,3), (2,2), (2,3), (3,3) for (sq1, sq2) in combos relSquares do let v = calcSquares.[sq1] + calcSquares.[sq2] // Memoize our relevant results if memo.ContainsKey(v) then memo.[v] <- memo.[v] + 1 // return our count for the num passed in memo.[num] // Read our numbers from file. //let lines = File.ReadAllLines("test2.txt") //let nums = [ for line in Seq.skip 1 lines -> Int32.Parse(line) ] // Optionally, read them from straight array let nums = [1740798996; 1257431873; 2147483643; 602519112; 858320077; 1048039120; 415485223; 874566596; 1022907856; 65; 421330820; 1041493518; 5; 1328649093; 1941554117; 4225; 2082925; 0; 1; 3] // Initialize our memoize dictionary let memo = new Dictionary<int, int>() for num in nums do memo.[num] <- 0 // Get the largest number in our set, all other numbers will be memoized along the way let maxN = findMax nums // Do the memoize let maxCount = countDoubleSquares maxN memo // Output our results. for num in nums do printfn "%i" memo.[num] // Have a little pause for when we debug let line = Console.Read() And here is my version in C# (Runtime: ~1:40: using System; using System.Collections.Generic; using System.Diagnostics; using System.IO; using System.Linq; using System.Text; namespace FBHack_DoubleSquares { public class TestInput { public int NumCases { get; set; } public List<int> Nums { get; set; } public TestInput() { Nums = new List<int>(); } public int MaxNum() { return Nums.Max(); } } class Program { static void Main(string[] args) { // Read input from file. //TestInput input = ReadTestInput("live.txt"); // As example, load straight. TestInput input = new TestInput { NumCases = 20, Nums = new List<int> { 1740798996, 1257431873, 2147483643, 602519112, 858320077, 1048039120, 415485223, 874566596, 1022907856, 65, 421330820, 1041493518, 5, 1328649093, 1941554117, 4225, 2082925, 0, 1, 3, } }; var maxNum = input.MaxNum(); Dictionary<int, int> memo = new Dictionary<int, int>(); foreach (var num in input.Nums) { if (!memo.ContainsKey(num)) memo.Add(num, 0); } DoMemoize(maxNum, memo); StringBuilder sb = new StringBuilder(); foreach (var num in input.Nums) { //Console.WriteLine(memo[num]); sb.AppendLine(memo[num].ToString()); } Console.Write(sb.ToString()); var blah = Console.Read(); //File.WriteAllText("out.txt", sb.ToString()); } private static int DoMemoize(int num, Dictionary<int, int> memo) { var highSquare = (int)Math.Floor(Math.Sqrt(num)); var squares = CreateSquareLookup(highSquare); var relSquares = squares.Keys.ToList(); Debug.WriteLine("Starting - " + num.ToString()); Debug.WriteLine("RelSquares.Count = {0}", relSquares.Count); int sum = 0; var index = 0; foreach (var square in relSquares) { foreach (var inner in relSquares.Skip(index)) { sum = squares[square] + squares[inner]; if (memo.ContainsKey(sum)) memo[sum]++; } index++; } if (memo.ContainsKey(num)) return memo[num]; return 0; } private static TestInput ReadTestInput(string fileName) { var lines = File.ReadAllLines(fileName); var input = new TestInput(); input.NumCases = int.Parse(lines[0]); foreach (var lin in lines.Skip(1)) { input.Nums.Add(int.Parse(lin)); } return input; } public static Dictionary<int, int> CreateSquareLookup(int maxNum) { var dict = new Dictionary<int, int>(); int square; foreach (var num in Enumerable.Range(0, maxNum)) { square = num * num; dict[num] = square; } return dict; } } } Thanks for taking a look. UPDATE Changing the combos function slightly will result in a pretty big performance boost (from 8 min to 3:45): /// Old and Busted... let rec combosOld range = seq { let rangeCache = Seq.cache range let count = ref 0 for inner in rangeCache do for outer in Seq.skip !count rangeCache do yield (inner, outer) count := !count + 1 } /// The New Hotness... let rec combos maxNum = seq { for i in 0..maxNum do for j in i..maxNum do yield i,j }

    Read the article

  • Simple Physics Simulation in java not working.

    - by Static Void Main
    Dear experts, I wanted to implement ball physics and as i m newbie, i adapt the code in tutorial http://adam21.web.officelive.com/Documents/JavaPhysicsTutorial.pdf . i try to follow that as i much as i can, but i m not able to apply all physical phenomenon in code, can somebody please tell me, where i m mistaken or i m still doing some silly programming mistake. The balls are moving when i m not calling bounce method and i m unable to avail the bounce method and ball are moving towards left side instead of falling/ending on floor**, Can some body recommend me some better way or similar easy compact way to accomplish this task of applying physics on two ball or more balls with interactivity. here is code ; import java.awt.*; public class AdobeBall { protected int radius = 20; protected Color color; // ... Constants final static int DIAMETER = 40; // ... Instance variables private int m_x; // x and y coordinates upper left private int m_y; private double dx = 3.0; // delta x and y private double dy = 6.0; private double m_velocityX; // Pixels to move each time move() is called. private double m_velocityY; private int m_rightBound; // Maximum permissible x, y values. private int m_bottomBound; public AdobeBall(int x, int y, double velocityX, double velocityY, Color color1) { super(); m_x = x; m_y = y; m_velocityX = velocityX; m_velocityY = velocityY; color = color1; } public double getSpeed() { return Math.sqrt((m_x + m_velocityX - m_x) * (m_x + m_velocityX - m_x) + (m_y + m_velocityY - m_y) * (m_y + m_velocityY - m_y)); } public void setSpeed(double speed) { double currentSpeed = Math.sqrt(dx * dx + dy * dy); dx = dx * speed / currentSpeed; dy = dy * speed / currentSpeed; } public void setDirection(double direction) { m_velocityX = (int) (Math.cos(direction) * getSpeed()); m_velocityY = (int) (Math.sin(direction) * getSpeed()); } public double getDirection() { double h = ((m_x + dx - m_x) * (m_x + dx - m_x)) + ((m_y + dy - m_y) * (m_y + dy - m_y)); double a = (m_x + dx - m_x) / h; return a; } // ======================================================== setBounds public void setBounds(int width, int height) { m_rightBound = width - DIAMETER; m_bottomBound = height - DIAMETER; } // ============================================================== move public void move() { double gravAmount = 0.02; double gravDir = 90; // The direction for the gravity to be in. // ... Move the ball at the give velocity. m_x += m_velocityX; m_y += m_velocityY; // ... Bounce the ball off the walls if necessary. if (m_x < 0) { // If at or beyond left side m_x = 0; // Place against edge and m_velocityX = -m_velocityX; } else if (m_x > m_rightBound) { // If at or beyond right side m_x = m_rightBound; // Place against right edge. m_velocityX = -m_velocityX; } if (m_y < 0) { // if we're at top m_y = 0; m_velocityY = -m_velocityY; } else if (m_y > m_bottomBound) { // if we're at bottom m_y = m_bottomBound; m_velocityY = -m_velocityY; } // double speed = Math.sqrt((m_velocityX * m_velocityX) // + (m_velocityY * m_velocityY)); // ...Friction stuff double fricMax = 0.02; // You can use any number, preferably less than 1 double friction = getSpeed(); if (friction > fricMax) friction = fricMax; if (m_velocityX >= 0) { m_velocityX -= friction; } if (m_velocityX <= 0) { m_velocityX += friction; } if (m_velocityY >= 0) { m_velocityY -= friction; } if (m_velocityY <= 0) { m_velocityY += friction; } // ...Gravity stuff m_velocityX += Math.cos(gravDir) * gravAmount; m_velocityY += Math.sin(gravDir) * gravAmount; } public Color getColor() { return color; } public void setColor(Color newColor) { color = newColor; } // ============================================= getDiameter, getX, getY public int getDiameter() { return DIAMETER; } public double getRadius() { return radius; // radius should be a local variable in Ball. } public int getX() { return m_x; } public int getY() { return m_y; } } using adobeBall: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class AdobeBallImplementation implements Runnable { private static final long serialVersionUID = 1L; private volatile boolean Play; private long mFrameDelay; private JFrame frame; private MyKeyListener pit; /** true means mouse was pressed in ball and still in panel. */ private boolean _canDrag = false; private static final int MAX_BALLS = 50; // max number allowed private int currentNumBalls = 2; // number currently active private AdobeBall[] ball = new AdobeBall[MAX_BALLS]; public AdobeBallImplementation(Color ballColor) { frame = new JFrame("simple gaming loop in java"); frame.setSize(400, 400); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pit = new MyKeyListener(); pit.setPreferredSize(new Dimension(400, 400)); frame.setContentPane(pit); ball[0] = new AdobeBall(34, 150, 7, 2, Color.YELLOW); ball[1] = new AdobeBall(50, 50, 5, 3, Color.BLUE); frame.pack(); frame.setVisible(true); frame.setBackground(Color.white); start(); frame.addMouseListener(pit); frame.addMouseMotionListener(pit); } public void start() { Play = true; Thread t = new Thread(this); t.start(); } public void stop() { Play = false; } public void run() { while (Play == true) { // bounce(ball[0],ball[1]); runball(); pit.repaint(); try { Thread.sleep(mFrameDelay); } catch (InterruptedException ie) { stop(); } } } public void drawworld(Graphics g) { for (int i = 0; i < currentNumBalls; i++) { g.setColor(ball[i].getColor()); g.fillOval(ball[i].getX(), ball[i].getY(), 40, 40); } } public double pointDistance (double x1, double y1, double x2, double y2) { return Math.sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)); } public void runball() { while (Play == true) { try { for (int i = 0; i < currentNumBalls; i++) { for (int j = 0; j < currentNumBalls; j++) { if (pointDistance(ball[i].getX(), ball[i].getY(), ball[j].getX(), ball[j].getY()) < ball[i] .getRadius() + ball[j].getRadius() + 2) { // bounce(ball[i],ball[j]); ball[i].setBounds(pit.getWidth(), pit.getHeight()); ball[i].move(); pit.repaint(); } } } try { Thread.sleep(50); } catch (Exception e) { System.exit(0); } } catch (Exception e) { e.printStackTrace(); } } } public static double pointDirection(int x1, int y1, int x2, int y2) { double H = Math.sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)); // The // hypotenuse double x = x2 - x1; // The opposite double y = y2 - y1; // The adjacent double angle = Math.acos(x / H); angle = angle * 57.2960285258; if (y < 0) { angle = 360 - angle; } return angle; } public static void bounce(AdobeBall b1, AdobeBall b2) { if (b2.getSpeed() == 0 && b1.getSpeed() == 0) { // Both balls are stopped. b1.setDirection(pointDirection(b1.getX(), b1.getY(), b2.getX(), b2 .getY())); b2.setDirection(pointDirection(b2.getX(), b2.getY(), b1.getX(), b1 .getY())); b1.setSpeed(1); b2.setSpeed(1); } else if (b2.getSpeed() == 0 && b1.getSpeed() != 0) { // B1 is moving. B2 is stationary. double angle = pointDirection(b1.getX(), b1.getY(), b2.getX(), b2 .getY()); b2.setSpeed(b1.getSpeed()); b2.setDirection(angle); b1.setDirection(angle - 90); } else if (b1.getSpeed() == 0 && b2.getSpeed() != 0) { // B1 is moving. B2 is stationary. double angle = pointDirection(b2.getX(), b2.getY(), b1.getX(), b1 .getY()); b1.setSpeed(b2.getSpeed()); b1.setDirection(angle); b2.setDirection(angle - 90); } else { // Both balls are moving. AdobeBall tmp = b1; double angle = pointDirection(b2.getX(), b2.getY(), b1.getX(), b1 .getY()); double origangle = b1.getDirection(); b1.setDirection(angle + origangle); angle = pointDirection(tmp.getX(), tmp.getY(), b2.getX(), b2.getY()); origangle = b2.getDirection(); b2.setDirection(angle + origangle); } } public static void main(String[] args) { javax.swing.SwingUtilities.invokeLater(new Runnable() { public void run() { new AdobeBallImplementation(Color.red); } }); } } *EDIT:*ok splitting the code using new approach for gravity from this forum: this code also not working the ball is not coming on floor: public void mymove() { m_x += m_velocityX; m_y += m_velocityY; if (m_y + m_bottomBound > 400) { m_velocityY *= -0.981; // setY(400 - m_bottomBound); m_y = 400 - m_bottomBound; } // ... Bounce the ball off the walls if necessary. if (m_x < 0) { // If at or beyond left side m_x = 0; // Place against edge and m_velocityX = -m_velocityX; } else if (m_x > m_rightBound) { // If at or beyond right side m_x = m_rightBound - 20; // Place against right edge. m_velocityX = -m_velocityX; } if (m_y < 0) { // if we're at top m_y = 1; m_velocityY = -m_velocityY; } else if (m_y > m_bottomBound) { // if we're at bottom m_y = m_bottomBound - 20; m_velocityY = -m_velocityY; } } thanks a lot for any correction and help. jibby

    Read the article

  • Double default gateway ubuntu server

    - by Elena
    Hi, I've just installed an Ubuntu server 9.10 on an EEEBox. This is my /etc/network/interfaces # The loopback network interface auto lo iface lo inet loopback auto wlan0 iface wlan0 inet static address 192.168.48.16 netmask 255.255.248.0 wireless-essid mynet auto eth0 iface eth0 inet static address xx.xx.xx.xx netmask 255.255.255.224 gateway xx.xx.yy.yy When I restart /etc/init.d/networking, I can access the eth0 ip address from the internet and I can ping the machines in my wifi network mynet. Everything works fine and I have one default gateway. But after some time if I check again the route I just find two default gateways: one is correct and is the previous one, but the other is the one of the wifi network. I have a quite low signal of mynet where my server is and sometimes the wifi just disconnect and then reconnect again. Then I think that this can be a problem and the dhcp of the wifi net, when reconnecting it also add a default gateway. Any idea on how to resolve this issue?

    Read the article

  • Double default gateway ubuntu server

    - by Elena
    I've just installed an Ubuntu server 9.10 on an EEEBox. This is my /etc/network/interfaces # The loopback network interface auto lo iface lo inet loopback auto wlan0 iface wlan0 inet static address 192.168.48.16 netmask 255.255.248.0 wireless-essid mynet auto eth0 iface eth0 inet static address xx.xx.xx.xx netmask 255.255.255.224 gateway xx.xx.yy.yy When I restart /etc/init.d/networking, I can access the eth0 ip address from the internet and I can ping the machines in my wifi network mynet. Everything works fine and I have one default gateway. But after some time if I check again the route I just find two default gateways: one is correct and is the previous one, but the other is the one of the wifi network. I have a quite low signal of mynet where my server is and sometimes the wifi just disconnect and then reconnect again. Then I think that this can be a problem and the dhcp of the wifi net, when reconnecting it also add a default gateway. Any idea on how to resolve this issue?

    Read the article

  • Double MySQL Running on Mountain Lion

    - by Norris
    After I've done a full restart, my Apache PHP server doesn't connect to Local MySQL ( connecting via 127.0.0.1 because localhost for some reason fails always ). So I did this today: ? ~ mysqladmin shutdown -u root -p Enter password: ? ~ mysqladmin shutdown -u root -p Enter password: mysqladmin: connect to server at 'localhost' failed error: 'Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2)' Check that mysqld is running and that the socket: '/tmp/mysql.sock' exists! Which basically means that I succeeded in shutting down mysql. But as soon as I did - Apache PHP successfully connect to MySQL and my local sites work without a hiccup until the next restart. Here are a few other details: (as you can tell - I've installed MySQL via brew) ? ~ sudo ps aux | grep mysql N 4774 0.0 0.0 2432768 620 s000 S+ 9:53AM 0:00.00 grep mysql N 4772 0.0 2.6 3030168 440688 ?? S 9:51AM 0:00.29 /usr/local/Cellar/mysql/5.6.13/bin/mysqld --basedir=/usr/local/Cellar/mysql/5.6.13 --datadir=/usr/local/var/mysql --plugin-dir=/usr/local/Cellar/mysql/5.6.13/lib/plugin --bind-address=127.0.0.1 --log-error=/usr/local/var/mysql/N.local.err --pid-file=/usr/local/var/mysql/N.local.pid N 4686 0.0 0.0 2433432 1000 ?? S 9:51AM 0:00.01 /bin/sh /usr/local/opt/mysql/bin/mysqld_safe --bind-address=127.0.0.1 N 4362 0.0 2.7 3120276 458728 ?? S 9:47AM 0:00.45 mysqld ? ~ lsof -i | grep mysql mysqld 4362 N 16u IPv6 0x76959e40691f9f93 0t0 TCP *:mysql (LISTEN) This is the weird thing: ? ~ killall -9 mysqld MySQL Is dead! Apache doesn't connect. Then, when I run: ? ~ sudo mysqladmin shutdown -u root -p Enter password: Apache is (again) able to successfully connect to MySQL. As far as I understand this means that I have two mysql servers setup and both of them are trying to start up at the same time, but I don't have the slightest idea on how to fix it. I've tried brew reinstalling but that didn't help. ? ~ which mysqladmin /usr/local/bin/mysqladmin ? ~ whence -p mysql /usr/local/bin/mysql

    Read the article

  • Function keys on Dell laptop work double as OEM keys

    - by Factor Mystic
    I'm working with a new Dell Studio 1555, and the F1-F12 keys at the top of the keyboard are dual function with OEM keys such as volume and screen brightness. The problem is, is that the OEM keys are the default, and you have to press the Fn key to get the F- key to work. For example, this means you have to hit Alt+Fn+F4 to close a window, instead of the regular Alt+F4. This is really annoying. Is there a way to reverse the default functions of the F- keys in Windows? Ideally this is possible without some kind of third party hotkey manager.

    Read the article

  • Exchange 2003 Sending Double E-mails?

    - by Beuy
    Hello there, We have an exchange 2003 single-machine setup that is behaving very oddly. For various users it sends the same e-mail twice (I've checked the logs and each e-mail has a unique mail identifier which confirms that the problem is not the same e-mail being received twice, but it being sent twice) I've done a quick search and found tons of information regarding POP3/IMAP connectors etc, however these Employes are using Outlook 2003/2007 in Cached Mode. The Symantec AntiVirus for Mail is also not causing the issue, it's correctly scanning both e-mails coming through. Any ideas?

    Read the article

  • Double Filter in Excel

    - by Joe
    I'm trying to "stack" filters in excel, so to speak. I want to filter column A to show anything greater than 30 and then I want to filter column B to show the top ten items. When I do this, however, it shows me all rows that fit both criteria (only five records). I want to first fit the criteria for column A and then filter these results to show the top ten items in column B (10 records total). I know that I could just copy the rows from my first filter to a new sheet and then filter the new worksheet, but is there any way to apply both filters so that I don't physically have to delete records this way? Thanks for your help!

    Read the article

  • mdadm raid5 recover double disk failure - with a twist (drive order)

    - by Peter Bos
    Let me acknowledge first off that I have made mistakes, and that I have a backup for most but not all of the data on this RAID. I still have hope of recovering the rest of the data. I don't have the kind of money to take the drives to a recovery expert company. Mistake #0, not having a 100% backup. I know. I have a mdadm RAID5 system of 4x3TB. Drives /dev/sd[b-e], all with one partition /dev/sd[b-e]1. I'm aware that RAID5 on very large drives is risky, yet I did it anyway. Recent events The RAID become degraded after a two drive failure. One drive [/dev/sdc] is really gone, the other [/dev/sde] came back up after a power cycle, but was not automatically re-added to the RAID. So I was left with a 4 device RAID with only 2 active drives [/dev/sdb and /dev/sdd]. Mistake #1, not using dd copies of the drives for restoring the RAID. I did not have the drives or the time. Mistake #2, not making a backup of the superblock and mdadm -E of the remaining drives. Recovery attempt I reassembled the RAID in degraded mode with mdadm --assemble --force /dev/md0, using /dev/sd[bde]1. I could then access my data. I replaced /dev/sdc with a spare; empty; identical drive. I removed the old /dev/sdc1 from the RAID mdadm --fail /dev/md0 /dev/sdc1 Mistake #3, not doing this before replacing the drive I then partitioned the new /dev/sdc and added it to the RAID. mdadm --add /dev/md0 /dev/sdc1 It then began to restore the RAID. ETA 300 mins. I followed the process via /proc/mdstat to 2% and then went to do other stuff. Checking the result Several hours (but less then 300 mins) later, I checked the process. It had stopped due to a read error on /dev/sde1. Here is where the trouble really starts I then removed /dev/sde1 from the RAID and re-added it. I can't remember why I did this; it was late. mdadm --manage /dev/md0 --remove /dev/sde1 mdadm --manage /dev/md0 --add /dev/sde1 However, /dev/sde1 was now marked as spare. So I decided to recreate the whole array using --assume-clean using what I thought was the right order, and with /dev/sdc1 missing. mdadm --create /dev/md0 --assume-clean -l5 -n4 /dev/sdb1 missing /dev/sdd1 /dev/sde1 That worked, but the filesystem was not recognized while trying to mount. (It should have been EXT4). Device order I then checked a recent backup I had of /proc/mdstat, and I found the drive order. md0 : active raid5 sdb1[0] sde1[4] sdd1[2] sdc1[1] 8790402048 blocks super 1.2 level 5, 512k chunk, algorithm 2 [4/4] [UUUU] I then remembered this RAID had suffered a drive loss about a year ago, and recovered from it by replacing the faulty drive with a spare one. That may have scrambled the device order a bit...so there was no drive [3] but only [0],[1],[2], and [4]. I tried to find the drive order with the Permute_array script: https://raid.wiki.kernel.org/index.php/Permute_array.pl but that did not find the right order. Questions I now have two main questions: I screwed up all the superblocks on the drives, but only gave: mdadm --create --assume-clean commands (so I should not have overwritten the data itself on /dev/sd[bde]1. Am I right that in theory the RAID can be restored [assuming for a moment that /dev/sde1 is ok] if I just find the right device order? Is it important that /dev/sde1 be given the device number [4] in the RAID? When I create it with mdadm --create /dev/md0 --assume-clean -l5 -n4 \ /dev/sdb1 missing /dev/sdd1 /dev/sde1 it is assigned the number [3]. I wonder if that is relevant to the calculation of the parity blocks. If it turns out to be important, how can I recreate the array with /dev/sdb1[0] missing[1] /dev/sdd1[2] /dev/sde1[4]? If I could get that to work I could start it in degraded mode and add the new drive /dev/sdc1 and let it resync again. It's OK if you would like to point out to me that this may not have been the best course of action, but you'll find that I realized this. It would be great if anyone has any suggestions.

    Read the article

  • Fixed and dynamic IPs in ISC DHPD lead to double lease

    - by GorillaPatch
    I would like to have a small dynamic adress part and the most clients are assigned a fixed IP adress. My dhcpd.conf looks like this: use-host-decl-names on; authoritative; allow client-updates; ddns-updates on; # Einstellungen fuer DHCP leases default-lease-time 3600; max-lease-time 86400; lease-file-name "/var/lib/dhcpd/dhcpd.leases"; subnet 192.168.11.0 netmask 255.255.255.0 { ddns-updates on; pool { # IP range which will be assigned statically range 192.168.11.1 192.168.11.240; deny all clients; } pool { # small dynamic range range 192.168.11.241 192.168.11.254; # used for temporary devices } } group { host pc1 { hardware ethernet xx:xx:xx:xx:xx:xx; fixed-address 192.168.11.11; } } The motivation for the pool declaration with deny all hosts comes from the ISC DHCPD homepage http://www.isc.org/files/auth.html This will allow hosts to be first added to the network, where they will receive a temporary IP from the 241-254 adress range and then later write an explicit host declaration. Upon next connect it will receive the right configuration. The problem is that I am getting error messages that 192.168.11.13 has a dynamic and a static lease. I am a bit confused as I expected the pool declaration with deny all clients would not count as dynamic. Dynamic and static leases present for 192.168.11.13. Remove host declaration pc1 or remove 192.168.11.13 from the dynamic address pool for 192.168.11.0/24 Is there a way to have the DHCP server send an DHCPNA to clients if they have a host statement and retain this dynamic range?

    Read the article

  • Double VPN Network Authentication

    - by Pyromanci
    I have a project I'm working on and looking for some info. Right now I have a VPN network using Cisco Pix 501's for the vpn clients and a Cisco VPN Concentrator 3000 for the VPN Server. Since the Pix is constantly connected to the vpn, I want to add a extra level of authentication. Meaning when the user on the other end goes to access anything on the VPN they are asked for a username password before the connection is established. I've never done this sort of structure before. So I'm not even sure where to really being or even if my current hardware can do something like this, or if i need to through in some sort of radius/LDAP/Active Directory type server into the mix.

    Read the article

  • File Transfer with a double SSH login.

    - by Harpal
    I'm have trouble transfering files again from my work PC, which is a linux machine to my home windows PC. My work has changed it so I now need to SSH twice before I can access my PC. So I need to: ssh [email protected] password: xxxxx I then need to do it again. ssh computer_name password: xxxxx I've tried accessing directly via my computers IP but to of no avail. Is there a way I can use pscp or file zilla to ssh twice so I can transfer files?

    Read the article

< Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >