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  • Dutch for once: op zoek naar een nieuwe uitdaging!

    - by Dennis Vroegop
    Originally posted on: http://geekswithblogs.net/dvroegop/archive/2013/10/11/dutch-for-once-op-zoek-naar-een-nieuwe-uitdaging.aspxI apologize to my non-dutch speaking readers: this post is about me looking for a new job and since I am based in the Netherlands I will do this in Dutch… Next time I will be technical (and thus in English) again! Het leuke van interim zijn is dat een klus een keer afloopt. Ik heb heel bewust gekozen voor het leven als freelancer: ik wil graag heel veel verschillende mensen en organisaties leren kennen. Dit werk is daar bij uitstek geschikt voor! Immers: bij iedere klus breng ik niet alleen nieuwe ideeën en kennis maar ik leer zelf ook iedere keer ontzettend veel. Die kennis kan ik dan weer gebruiken bij een vervolgklus en op die manier verspreid ik die kennis onder de bedrijven in Nederland. En er is niets leukers dan zien dat wat ik meebreng een organisatie naar een ander niveau brengt! Iedere keer een ander bedrijf zoeken houdt in dat ik iedere keer weg moet gaan bij een organisatie. Het lastige daarvan is het juiste moment te vinden. Van buitenaf gezien is dat lastig in te schatten: wanneer kan ik niets vernieuwends meer bijdragen en is het tijd om verder te gaan? Wanneer is het tijd om te zeggen dat de organisatie alles weet wat ik ze kan bijbrengen? In mijn huidige klus is dat moment nu aangebroken. In de afgelopen elf maanden heb ik dit bedrijf zien veranderen van een kleine maar enthousiaste groep ontwikkelaars naar een professionele organisatie met ruim twee keer zo veel ontwikkelaars. Dat veranderingsproces is erg leerzaam geweest en ik ben dan ook erg blij dat ik die verandering heb kunnen en mogen begeleiden. Van drie teams met ieder vijf of zes ontwikkelaars naar zes teams met zeven tot acht ontwikkelaars per team groeien betekent dat je je ontwikkelproces heel anders moet insteken. Ook houdt dat in dat je je teams anders moet indelen, dat de organisatie zelf anders gemodelleerd moet worden en dat mensen anders met elkaar om moeten gaan. Om dat voor elkaar te krijgen is er door iedereen heel hard gewerkt, is er een aantal fouten gemaakt, is heel veel van die fouten geleerd en is uiteindelijk een vrijwel nieuw bedrijf ontstaan. Het is tijd om dit bedrijf te verlaten. Ik ben benieuwd waar ik hierna terecht kom: ik ben aan het rondkijken naar mogelijkheden. Ik weet wèl: het bedrijf waar ik naar op zoek ben, is een bedrijf dat openstaat voor veranderingen. Veranderingen, maar dan wel met het oog voor het individu; mensen staan immers centraal in de software ontwikkeling! Ik heb er in ieder geval weer zin in!

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  • How do you set max execution time of PHP's CLI component?

    - by cwd
    How do you set max execution time of PHP's CLI component? I have a CLI script that has gone into a infinite loop and I'm not sure how to kill it without restarting. I used quicksilver to launch it, so I can't press control+c at the command line. I tried running ps -A (show all processes) but php is not showing up in that list, so perhaps it has timed out on it's own - but how do you manually set the time limit? I tried to find information about where I should set the max_execution_time setting, I'm used to setting this for the version of PHP that runs with apache, but I have no idea where to set it for the version of PHP that lives in /usr/bin. I did see the follow quote, which does seem to be accurate (see screenshot below), but having an unlimited execution time doesn't seem like a good idea. Keep in mind that for CLI SAPI max_execution_time is hardcoded to 0. So it seems to be changed by ini_set or set_time_limit but it isn't, actually. The only references I've found to this strange decision are deep in bugtracker (http://bugs.php.net/37306) and in php.ini (comments for 'max_execution_time' directive). (via http://php.net/manual/en/function.set-time-limit.php) ini_set('max_execution_time') has no effect. I also tried the same thing and go the same result with set_time_limit(7).

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  • A tale from a Stalker

    - by Peter Larsson
    Today I thought I should write something about a stalker I've got. Don't get me wrong, I have way more fans than stalkers, but this stalker is particular persistent towards me. It all started when I wrote about Relational Division with Sets late last year(http://weblogs.sqlteam.com/peterl/archive/2010/07/02/Proper-Relational-Division-With-Sets.aspx) and no matter what he tried, he didn't get a better performing query than me. But this I didn't click until later into this conversation. He must have saved himself for 9 months before posting to me again. Well... Some days ago I get an email from someone I thought i didn't know. Here is his first email Hi, I want a proper solution for achievement the result. The solution must be standard query, means no using as any native code like TOP clause, also the query should run in SQL Server 2000 (no CTE use). We have a table with consecutive keys (nbr) that is not exact sequence. We need bringing all values related with nearest key in the current key row. See the DDL: CREATE TABLE Nums(nbr INTEGER NOT NULL PRIMARY KEY, val INTEGER NOT NULL); INSERT INTO Nums(nbr, val) VALUES (1, 0),(5, 7),(9, 4); See the Result: pre_nbr     pre_val     nbr         val         nxt_nbr     nxt_val ----------- ----------- ----------- ----------- ----------- ----------- NULL        NULL        1           0           5           7 1           0           5           7           9           4 5           7           9           4           NULL        NULL The goal is suggesting most elegant solution. I would like see your best solution first, after that I will send my best (if not same with yours)   Notice there is no name, no please or nothing polite asking for my help. So, on the top of my head I sent him two solutions, following the rule "Work on SQL Server 2000 and only standard non-native code".     -- Peso 1 SELECT               pre_nbr,                              (                                                           SELECT               x.val                                                           FROM                dbo.Nums AS x                                                           WHERE              x.nbr = d.pre_nbr                              ) AS pre_val,                              d.nbr,                              d.val,                              d.nxt_nbr,                              (                                                           SELECT               x.val                                                           FROM                dbo.Nums AS x                                                           WHERE              x.nbr = d.nxt_nbr                              ) AS nxt_val FROM                (                                                           SELECT               (                                                                                                                     SELECT               MAX(x.nbr) AS nbr                                                                                                                     FROM                dbo.Nums AS x                                                                                                                     WHERE              x.nbr < n.nbr                                                                                        ) AS pre_nbr,                                                                                        n.nbr,                                                                                        n.val,                                                                                        (                                                                                                                     SELECT               MIN(x.nbr) AS nbr                                                                                                                     FROM                dbo.Nums AS x                                                                                                                     WHERE              x.nbr > n.nbr                                                                                        ) AS nxt_nbr                                                           FROM                dbo.Nums AS n                              ) AS d -- Peso 2 CREATE TABLE #Temp                                                         (                                                                                        ID INT IDENTITY(1, 1) PRIMARY KEY,                                                                                        nbr INT,                                                                                        val INT                                                           )   INSERT                                            #Temp                                                           (                                                                                        nbr,                                                                                        val                                                           ) SELECT                                            nbr,                                                           val FROM                                             dbo.Nums ORDER BY         nbr   SELECT                                            pre.nbr AS pre_nbr,                                                           pre.val AS pre_val,                                                           t.nbr,                                                           t.val,                                                           nxt.nbr AS nxt_nbr,                                                           nxt.val AS nxt_val FROM                                             #Temp AS pre RIGHT JOIN      #Temp AS t ON t.ID = pre.ID + 1 LEFT JOIN         #Temp AS nxt ON nxt.ID = t.ID + 1   DROP TABLE    #Temp Notice there are no indexes on #Temp table yet. And here is where the conversation derailed. First I got this response back Now my solutions: --My 1st Slt SELECT T2.*, T1.*, T3.*   FROM Nums AS T1        LEFT JOIN Nums AS T2          ON T2.nbr = (SELECT MAX(nbr)                         FROM Nums                        WHERE nbr < T1.nbr)        LEFT JOIN Nums AS T3          ON T3.nbr = (SELECT MIN(nbr)                         FROM Nums                        WHERE nbr > T1.nbr); --My 2nd Slt SELECT MAX(CASE WHEN N1.nbr > N2.nbr THEN N2.nbr ELSE NULL END) AS pre_nbr,        (SELECT val FROM Nums WHERE nbr = MAX(CASE WHEN N1.nbr > N2.nbr THEN N2.nbr ELSE NULL END)) AS pre_val,        N1.nbr AS cur_nbr, N1.val AS cur_val,        MIN(CASE WHEN N1.nbr < N2.nbr THEN N2.nbr ELSE NULL END) AS nxt_nbr,        (SELECT val FROM Nums WHERE nbr = MIN(CASE WHEN N1.nbr < N2.nbr THEN N2.nbr ELSE NULL END)) AS nxt_val   FROM Nums AS N1,        Nums AS N2  GROUP BY N1.nbr, N1.val;   /* My 1st Slt Table 'Nums'. Scan count 7, logical reads 14 My 2nd Slt Table 'Nums'. Scan count 4, logical reads 23 Peso 1 Table 'Nums'. Scan count 9, logical reads 28 Peso 2 Table '#Temp'. Scan count 0, logical reads 7 Table 'Nums'. Scan count 1, logical reads 2 Table '#Temp'. Scan count 3, logical reads 16 */  To this, I emailed him back asking for a scalability test What if you try with a Nums table with 100,000 rows? His response to that started to get nasty.  I have to say Peso 2 is not acceptable. As I said before the solution must be standard, ORDER BY is not part of standard SELECT. Try this without ORDER BY:  Truncate Table Nums INSERT INTO Nums (nbr, val) VALUES (1, 0),(9,4), (5, 7)  So now we have new rules. No ORDER BY because it's not standard SQL! Of course I asked him  Why do you have that idea? ORDER BY is not standard? To this, his replies went stranger and stranger Standard Select = Set-based (no any cursor) It’s free to know, just refer to Advanced SQL Programming by Celko or mail to him if you accept comments from him. What the stalker probably doesn't know, is that I and Mr Celko occasionally are involved in some conversation and thus we exchange emails. I don't know if this reference to Mr Celko was made to intimidate me either. So I answered him, still polite, this What do you mean? The SELECT itself has a ”cursor under the hood”. Now the stalker gets rude  But however I mean the solution must no containing any order by, top... No problem, I do not like Peso 2, it’s very non-intelligent and elementary. Yes, Peso 2 is elementary but most performing queries are... And now is the time where I started to feel the stalker really wanted to achieve something else, so I wrote to him So what is your goal? Have a query that performs well, or a query that is super-portable? My Peso 2 outperforms any of your code with a factor of 100 when using more than 100,000 rows. While I awaited his answer, I posted him this query Ok, here is another one -- Peso 3 SELECT             MAX(CASE WHEN d = 1 THEN nbr ELSE NULL END) AS pre_nbr,                    MAX(CASE WHEN d = 1 THEN val ELSE NULL END) AS pre_val,                    MAX(CASE WHEN d = 0 THEN nbr ELSE NULL END) AS nbr,                    MAX(CASE WHEN d = 0 THEN val ELSE NULL END) AS val,                    MAX(CASE WHEN d = -1 THEN nbr ELSE NULL END) AS nxt_nbr,                    MAX(CASE WHEN d = -1 THEN val ELSE NULL END) AS nxt_val FROM               (                              SELECT    nbr,                                        val,                                        ROW_NUMBER() OVER (ORDER BY nbr) AS SeqID                              FROM      dbo.Nums                    ) AS s CROSS JOIN         (                              VALUES    (-1),                                        (0),                                        (1)                    ) AS x(d) GROUP BY           SeqID + x.d HAVING             COUNT(*) > 1 And here is the stats Table 'Nums'. Scan count 1, logical reads 2, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. It beats the hell out of your queries…. Now I finally got a response from my stalker and now I also clicked who he was. This is his reponse Why you post my original method with a bit change under you name? I do not like it. See: http://www.sqlservercentral.com/Forums/Topic468501-362-14.aspx ;WITH C AS ( SELECT seq_nbr, k,        DENSE_RANK() OVER(ORDER BY seq_nbr ASC) + k AS grp_fct   FROM [Sample]         CROSS JOIN         (VALUES (-1), (0), (1)         ) AS D(k) ) SELECT MIN(seq_nbr) AS pre_value,        MAX(CASE WHEN k = 0 THEN seq_nbr END) AS current_value,        MAX(seq_nbr) AS next_value   FROM C GROUP BY grp_fct HAVING min(seq_nbr) < max(seq_nbr); These posts: Posted Tuesday, April 12, 2011 10:04 AM Posted Tuesday, April 12, 2011 1:22 PM Why post a solution where will not work in SQL Server 2000? Wait a minute! His own solution is using both a CTE and a ranking function so his query will not work on SQL Server 2000! Bummer... The reference to "Me not like" are my exact words in a previous topic on SQLTeam.com and when I remembered the phrasing, I also knew who he was. See this topic http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=159262 where he writes a query and posts it under my name, as if I wrote it. So I answered him this (less polite). Like I keep track of all topics in the whole world… J So you think you are the only one coming up with this idea? Besides, “M S solution” doesn’t work.   This is the result I get pre_value        current_value                             next_value 1                           1                           5 1                           5                           9 5                           9                           9   And I did nothing like you did here, where you posted a solution which you “thought” I should write http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=159262 So why are you yourself using ranking function when this was not allowed per your original email, and no cte? You use CTE in your link above, which do not work in SQL Server 2000. All this makes no sense to me, other than you are trying your best to once in a lifetime create a better performing query than me? After a few hours I get this email back. I don't fully understand it, but it's probably a language barrier. >>Like I keep track of all topics in the whole world… J So you think you are the only one coming up with this idea?<< You right, but do not think you are the first creator of this.   >>Besides, “M S Solution” doesn’t work. This is the result I get <<   Why you get so unimportant mistake? See this post to correct it: Posted 4/12/2011 8:22:23 PM >> So why are you yourself using ranking function when this was not allowed per your original email, and no cte? You use CTE in your link above, which do not work in SQL Server 2000. <<  Again, why you get some unimportant incompatibility? You offer that solution for current goals not me  >> All this makes no sense to me, other than you are trying your best to once in a lifetime create a better performing query than me? <<  No, I only wanted to know who you will solve it. Now I know you do not have a special solution. No problem. No problem for me either. So I just answered him I am not the first, and you are not the first to come up with this idea. So what is your problem? I am pretty sure other people have come up with the same idea before us. I used this technique all the way back to 2007, see http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=93911 Let's see if he returns...  He did! >> So what is your problem? << Nothing Thanks for all replies; maybe we have some competitions in future, maybe. Also I like you but you do not attend it. Your behavior with me is not friendly. Not any meeting… Regards //Peso

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  • Java Runtime.freeMemory() returning bizarre results when adding more objects

    - by Sotirios Delimanolis
    For whatever reason, I wanted to see how many objects I could create and populate a LinkedList with. I used Runtime.getRuntime().freeMemory() to get the approximation of free memory in my JVM. I wrote this: public static void main(String[] arg) { Scanner kb = new Scanner(System.in); List<Long> mem = new LinkedList<Long>(); while (true) { System.out.println("Max memory: " + Runtime.getRuntime().maxMemory() + ". Available memory: " + Runtime.getRuntime().freeMemory() + " bytes. Press enter to use more."); String s = kb.nextLine(); if (s.equals("m")) for (int i = 0; i < 1000000; i++) { mem.add(new Long((new Random()).nextLong())); } } } If I write in m, the app adds a million Long objects to the list. You would think the more objects (to which we have references, so can't be gc'ed), the less free memory. Running the code: Max memory: 1897725952. Available memory: 127257696 bytes. m Max memory: 1897725952. Available memory: 108426520 bytes. m Max memory: 1897725952. Available memory: 139873296 bytes. m Max memory: 1897725952. Available memory: 210632232 bytes. m Max memory: 1897725952. Available memory: 137268792 bytes. m Max memory: 1897725952. Available memory: 239504784 bytes. m Max memory: 1897725952. Available memory: 169507792 bytes. m Max memory: 1897725952. Available memory: 259686128 bytes. m Max memory: 1897725952. Available memory: 189293488 bytes. m Max memory: 1897725952. Available memory: 387686544 bytes. The available memory fluctuates. How does this happen? Is the GC cleaning up other things (what other things are there on the heap to really clean up?), is the freeMemory() method returning an approximation that's way off? Am I missing something or am I crazy?

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  • OpenCv Error ( unhandeld exeption) after execute

    - by hamza
    Hi , i m using VS2010 i m trting to make a gray image more bright , the code did compile normaly but no change in the seconde picture , and an error message ( undhadled exeception .. .. ) showed up after that the execute is done showed up here is a peace of my code : int main(int argc, _TCHAR* argv[]) { IplImage *img = cvLoadImage("mra.jpg"); if (!img) { printf("Error: Couldn't open the image file.\n"); return 1; } //IplImage* new_image = getlargersize(img); double Min , Max ; Min = Max = 0 ; Max_Min (img , &Min , &Max); cout<<"the max value in the picture is :"<<Min<<" and the minimum value is :"<<Max<<endl ; IplImage* img2 = eclaircir(Min ,Max ,img); cvNamedWindow("Image:", CV_WINDOW_AUTOSIZE); cvNamedWindow("Image2:", CV_WINDOW_AUTOSIZE); cvShowImage("Image2:", img2); cvShowImage("Image:", img); cvWaitKey(0); cvDestroyWindow("Image2:"); cvDestroyWindow("Image:"); cvReleaseImage(&img2); cvReleaseImage(&img); return 0; } void Max_Min(IplImage* temp , double *min , double *max ){ CvScalar pix ; for (int i = 0 ; i < temp->height ; i++){ for (int j = 0 ; j < temp->width ; j++){ pix = cvGet2D(temp , i , j); if ( pix.val[0] >= *max ){ *max = pix.val[0]; } if ( pix.val[0] <= *min){ *min = pix.val[0]; } } } } IplImage* eclaircir (double min , double max , IplImage* image){ double temp = max - min ; CvScalar pix ; for (int i = 0 ; i < image->height ; i++){ for (int j = 0 ; j < image->width ; j++){ pix = cvGet2D(image , i , j); pix.val[0] = ( pix.val[0] - min)*255 ; pix.val[0] = pix.val[0]/temp ; cvSet2D(image , i , j , pix ); } } return image ; } thanks

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  • Linux AMD-FX 8350 temperature monitoring

    - by HyperDevil
    I’m trying to get the CPU temperature for my AMD-FX8350 on Debian Squeeze. I ran sensors-detect and then sensors, but I only get my motherboard sensors (it8720-isa-0228). There are three temperature values there but I assume those are not for the CPU. it8720-isa-0228 Adapter: ISA adapter in0: +1.36 V (min = +0.00 V, max = +4.08 V) in1: +1.50 V (min = +0.00 V, max = +4.08 V) in2: +3.38 V (min = +0.00 V, max = +4.08 V) in3: +2.93 V (min = +0.00 V, max = +4.08 V) in4: +3.07 V (min = +0.00 V, max = +4.08 V) in5: +4.08 V (min = +0.00 V, max = +4.08 V) in6: +4.08 V (min = +0.00 V, max = +4.08 V) in7: +2.93 V (min = +0.00 V, max = +4.08 V) Vbat: +3.01 V fan1: 3375 RPM (min = 10 RPM) fan2: 0 RPM (min = 0 RPM) fan3: 1730 RPM (min = 10 RPM) fan5: 0 RPM (min = 0 RPM) temp1: +27.0°C (low = +127.0°C, high = +127.0°C) sensor = thermistor temp2: +53.0°C (low = +127.0°C, high = +127.0°C) sensor = thermal diode temp3: +65.0°C (low = +127.0°C, high = +90.0°C) sensor = thermal diode cpu0_vid: +0.000 V Is there anything I am missing? I also loaded the K8temp and K10temp modules and ran sensor-detect without any results. I do see this message in dmesg: hwmon-vid: Unknown VRM version of your x86 CPU

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  • How can I test that my hash function is good in terms of max-load?

    - by philcolbourn
    I have read through various papers on the 'Balls and Bins' problem and it seems that if a hash function is working right (ie. it is effectively a random distribution) then the following should/must be true if I hash n values into a hash table with n slots (or bins): Probability that a bin is empty, for large n is 1/e. Expected number of empty bins is n/e. Probability that a bin has k collisions is <= 1/k!. Probability that a bin has at least k collisions is <= (e/k)**k. These look easy to check. But the max-load test (the maximum number of collisions with high probability) is usually stated vaguely. Most texts state that the maximum number of collisions in any bin is O( ln(n) / ln(ln(n)) ). Some say it is 3*ln(n) / ln(ln(n)). Other papers mix ln and log - usually without defining them, or state that log is log base e and then use ln elsewhere. Is ln the log to base e or 2 and is this max-load formula right and how big should n be to run a test? This lecture seems to cover it best, but I am no mathematician. http://pages.cs.wisc.edu/~shuchi/courses/787-F07/scribe-notes/lecture07.pdf BTW, with high probability seems to mean 1 - 1/n.

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  • Exclude specific value from a Min/Max agregate funcion using ICriteria.

    - by sparks
    I have a schedule (Voyages) table like this: ID Arrival Departure OrderIndex 1 01/01/1753 02/10/2009 0 1 02/11/2009 02/15/2009 1 1 02/16/2009 02/19/2009 2 1 02/21/2009 01/01/1753 3 2 01/01/1753 03/01/2009 0 2 03/04/2009 03/07/2009 1 2 03/09/2009 01/01/1753 2 By design i save '01/01/1753' as a default value if the user doesn't fill a the field on the capture screen and for the very first Arrival and the very last Departure which are never provided. Im using Nhibernate and Criteria, and im wondering whats the best way to query this data if i want to know the First departure and last arrival for each voyage in the table. My first thought was a groupby (ID) and then do some Min and Max with the arrival and departure but the `'01/01/1753' VALUE is messing aronud. ... .SetProjection(Projections.ProjectionList() .Add(Projections.GroupProperty("ID"), "ID") .Add(Projections.Min("DepartureDate"), "DepartureDate") .Add(Projections.Max("ArrivalDate"), "ArrivalDate") ) ... So is there a way to skip this value in the Min function comparison (without losing the whole row of data), or there is a better way to do this, maybe utilizing the OrderIndex that always indicate the correct order of the elements, maybe ordering ASC taking the 1st and then Order DESC and taking the 1 st again, but im not quite sure how to do that with criteria syntax.

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  • Mobile detection - Meta tag and max-device-width vs. php user agent?

    - by nimmbl
    Which form of mobile detection should I use and why? <meta name="viewport" content="width=320,initial-scale=1,maximum-scale=1.0,user-scalable=no" /> <link media="only screen and (max-device-width: 480px) and (min-device-width: 320px)" href="css/mobile.css" type= "text/css" rel="stylesheet"> <link media="handheld, only screen and (max-device-width: 319px)" href="css/mobile_simple.css" type="text/css" rel="stylesheet" /> Or include('mobile_device_detect.php'); $mobile = mobile_device_detect(); And why on earth would this: <?php if(strpos($_SERVER['HTTP_USER_AGENT'], 'iPhone') !== false) { ?> <meta name="viewport" content="width=320,initial-scale=1,maximum-scale=1.0,user-scalable=no" /> <link media="screen" href="css/mobile.css" type= "text/css" rel="stylesheet"> <?php } else { ?> <link media="screen" href="css/mobile_simple.css" type= "text/css" rel="stylesheet"> <?php } ?> ignore this css? body { background: -webkit-gradient(linear, left top, left bottom, from(#555), to(#000)); }

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  • Is it possible to achieve MAX(As,Ad) openGL blending?

    - by Jeff B
    I am working on a game where I want to create shadows under a series of sprites on a grid. The shadows are larger than the sprites themselves and the sprites are animated (i.e. move and rotate). I cannot simply render them into the sprite png, or the shadows will overlap adjacent sprites. I also cannot simply put shadows on a lower layer by themselves, because when they overlap, they will create dark bands at their intersection. These sprites are animated, so it is not feasible to render these en masse. Basically, I want the sprites' shadows to blend together such that they max out at a set opacity. Example: I believe this is equivalent to an openGL blending of (Rs,Gs,Bs,Max(As,Ds)), where I don't really care about R,G, and B, as it will always be the same color in src and dst. However, this is not a valid openGL blending mode. Is there an easy way to accomplish this, especially in cocos2d-iphone? I would be able to approximate this by making the shadow sprites opaque, then applying them both to a parent sprite, and making the parent sprite 40% opacity. However, the way cocos2d works, this only sets the opacity of each child to 40%, rather than the combined sprite image, which results in the same stripe.

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  • how to pull and display range (min-max) data for each page in pagination?

    - by Ty W
    I have a table of data that is searchable and sortable, but likely to produce hundreds or thousands of results for broad searches. Assuming the user searches for "foo" and sorts the foos in descending price order I'd like to show a quick-jump select menu like so: <option value="1">Page 1 ($25,000,000 - $1,625,000)</option> <option value="2">Page 2 ($1,600,000 - $1,095,000)</option> <option value="3">Page 3 ($1,095,000 - $815,000)</option> <option value="4">Page 4 ($799,900 - $699,000)</option> ... Is there an efficient way of querying for this information directly from the DB? I've been grabbing all of the matching records and using PHP to calculate the min and max value for each page which seems inefficient and likely to cause scaling problems. The only possible technique I've been able to come up with is some way of having a calculated variable that increments every X records (X records to a page), grouping by that, and selecting MIN/MAX for each page grouping... unfortunately I haven't been able to come up with a way to generate that variable.

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  • convert .htaccess to nginx

    - by Chip Gà Con
    It's me again :( I was trying to install siwapp on my webserver but I couldn't make it work with nginx, here is the .htaccess file content: RewriteCond %{REQUEST_FILENAME} !index.php RewriteRule (.*)\.php$ index.php/$1 RewriteCond $1 !^(index\.php|nhototamsu|assets|cache|xd_receiver\.html|photo|ipanel|automap|xajax_js|files|robots\.txt|favicon\.ico|ione\.ico|(.*)\.xml|ror\.xml|tool|google6afb981101589049\.html|googlec0d38cf2adbc25bc\.html|widget|iradio_admin|services|wsdl) RewriteRule ^(.*)$ index.php/$1 [QSA,L] When I access http://myurl.com/tin-tuc/tuyen-sinh/tu-van/2012/04/25757-phan-van-qua-giua-khoi-a1-va-khoi-a.html ,nginx could display the page correctly, it said: "404 Not Found" (new URL: http://myurl.com/tin-tuc/tuyen-sinh/tu-van/2012/04/25757-phan-van-qua-giua-khoi-a1-va-khoi-a.html)

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  • Reducing Time Complexity in Java

    - by Koeneuze
    Right, this is from an older exam which i'm using to prepare my own exam in january. We are given the following method: public static void Oorspronkelijk() { String bs = "Dit is een boodschap aan de wereld"; int max = -1; char let = '*'; for (int i=0;i<bs.length();i++) { int tel = 1; for (int j=i+1;j<bs.length();j++) { if (bs.charAt(j) == bs.charAt(i)) tel++; } if (tel > max) { max = tel; let = bs.charAt(i); } } System.out.println(max + " keer " + let); } The questions are: what is the output? - Since the code is just an algorithm to determine the most occuring character, the output is "6 keer " (6 times space) What is the time complexity of this code? Fairly sure it's O(n²), unless someone thinks otherwise? Can you reduce the time complexity, and if so, how? Well, you can. I've received some help already and managed to get the following code: public static void Nieuw() { String bs = "Dit is een boodschap aan de wereld"; HashMap<Character, Integer> letters = new HashMap<Character, Integer>(); char max = bs.charAt(0); for (int i=0;i<bs.length();i++) { char let = bs.charAt(i); if(!letters.containsKey(let)) { letters.put(let,0); } int tel = letters.get(let)+1; letters.put(let,tel); if(letters.get(max)<tel) { max = let; } } System.out.println(letters.get(max) + " keer " + max); } However, I'm uncertain of the time complexity of this new code: Is it O(n) because you only use one for-loop, or does the fact we require the use of the HashMap's get methods make it O(n log n) ? And if someone knows an even better way of reducing the time complexity, please do tell! :)

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  • how do i ininitialize a float to it's max/min value?

    - by Faken
    How do i hard code an absolute maximum or minimum value for a float or double? I want to search out the max/min of an array by simply iterating through and catching the largest. There are also positive and negative infinity for floats, should i use those instead? if so, how do i denote that in my code?

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  • how do I initialize a float to its max/min value?

    - by Faken
    How do I hard code an absolute maximum or minimum value for a float or double? I want to search out the max/min of an array by simply iterating through and catching the largest. There are also positive and negative infinity for floats, should I use those instead? If so, how do I denote that in my code?

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