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  • How to add changebar in latex?

    - by Rabarberski
    In Latex, I've created a new command 'changedtext' to mark specifics parts in my document and make it appear blue: \newcommand{\changedtext}[1]{\textcolor{blue}{#1} } Is there any easy way to alter the command to have change bars appear next to the text in the resulting PDF? If not possible, any other suggestion for a visual markup (other than change bars) that would be clear on a black & white printout would be useful as well.

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  • How to get rid of box around linked image

    - by Earlz
    Hello, I know I've solved this problem before, but I can't remember or find the solution, so here I am... In Firefox 3.5 this code causes an undesirable blue border around the image. How do I get rid of this blue border? <a style="text-decoration: none;" href="index.html"> <img src="http://www.google.com/logos/stpatricksday10-hp.gif" /> </a> http://jsbin.com/umuzo3

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  • (Python) Converting a dictionary to a list?

    - by Daria Egelhoff
    So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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  • Displaying bitmaps in relative positions

    - by JonF
    I'd like to put a couple images on a surfaceview. I understand that the screen sizes of android devices can vary, so I don't think I can just use an x y position or I might end up placing it off different screens. Say I want to put two boxes in the center of the screen, a blue one and a red one. The blue one is to the left of the red one. How can I accomplish that while accounting for different screen sizes?

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  • Python: Comparing specific columns in two csv files

    - by coder999
    Say that I have two CSV files (file1 and file2) with contents as shown below: file1: fred,43,Male,"23,45",blue,"1, bedrock avenue" file2: fred,39,Male,"23,45",blue,"1, bedrock avenue" I would like to compare these two CSV records to see if columns 0,2,3,4, and 5 are the same. I don't care about column 1. What's the most pythonic way of doing this? EDIT: Some example code would be appreciated.

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  • Excelsheet query

    - by kunj
    Hi, Please tell me how can I find the last word from any particular cell in excel sheet if cell contains multiple words or instructions. For ex- The below string is in particular cell: C:\Documents and Settings\All Users\Documents\My Pictures\Sample Pictures\Blue hills.jpg My requirement is to search only last word in that cell i.e. Blue hills.jpg Your early response is highly appreciated!!!

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  • Air/Flex concatenating a variable with a property

    - by Deyon
    I have three text boxes on the stage id=red, blue, green same as the keys in my cars Object/Array public function carsToBox():void { var cars:Object={red:"300zx",blue:"Skyline",green:"Supra"}; for(var tempObj:String in cars) { tempObj.text= cars[tempObj];//this trows errors } } So I'm thinking "tempObj.text" would equal red.text but I can't stick "tempObj" with ".text" is there a way this can be done?

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  • iPod Touch (OS 3.0) bluetooth connection to non apple device

    - by Avi
    I need to know if I can programmatically connect my iPod Touch (OS 3.0) to a non apple blue tooth device, Using the Apple iPhone SDK. I know that I can connect to other iPhone using GameKit API, But can I connect to other non apple Bluetooth devices for example an measuring device that send out real time data over blue tooth?

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  • Line up swing components by edges

    - by rasen58
    Is it possible to line up swing components? The components are in separate panels which both use flow layout. These two panels are in another panel which is using a grid layout. As you can see there is a subtle difference and I find it annoying. I know that all of the jlabels [the rectangles in blue/purple all have the same size, so i think it might be because of the '+' and '*', but I'm not sure because the left sides of the first two boxes aren't lined up. the panels JPanel panel2 = new JPanel(new GridLayout(4, 1)); JPanel panel2a = new JPanel(new FlowLayout()); JPanel panel2b = new JPanel(new FlowLayout()); the first two rectangles (purple) add1 = new JLabel("", JLabel.CENTER); add1.setTransferHandler(new TransferHandler("text")); add1.setBorder(b2); add2 = new JLabel("", JLabel.CENTER); add2.setTransferHandler(new TransferHandler("text")); add2.setBorder(b2); the two blue rectangles textFieldA = new JTextField(); textFieldA.setHorizontalAlignment(JTextField.CENTER); textFieldA.setEditable(false); textFieldA.setBorder(new LineBorder(Color.blue)); textFieldM = new JTextField(); textFieldM.setHorizontalAlignment(JTextField.CENTER); textFieldM.setEditable(false); textFieldM.setBorder(new LineBorder(Color.blue)); the + and * opA = new JLabel("+", JLabel.CENTER); opS = new JLabel("*", JLabel.CENTER); Showing that the rectangles are the same size Dimension d = card1.getPreferredSize(); int width = d.width + 100; int height = d.height + 50; add1.setPreferredSize(new Dimension(width, height)); add2.setPreferredSize(new Dimension(width, height)); mult1.setPreferredSize(new Dimension(width, height)); mult2.setPreferredSize(new Dimension(width, height)); textFieldA.setPreferredSize(new Dimension(width, height)); textFieldM.setPreferredSize(new Dimension(width, height)); Adding to the panels panel2a.add(add1); panel2a.add(opA); panel2a.add(add2); panel2a.add(enterA); panel2a.add(textFieldA); panel2c.add(mult1); panel2c.add(opM); panel2c.add(mult2); panel2c.add(enterM); panel2c.add(textFieldM); panel2.add(panel2a); panel2.add(panel2c);

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  • CSS: a:link vs just a (without the :link part)

    - by Rob
    So we're required to use the following order for CSS anchor pseudo-classes a:link { color: red } a:visited { color: blue } a:hover { color: yellow } a:active { color: lime } But my question is why bother with the a:link part? Rather, is there any advantage to the above (other than perhaps clarity) over: a { color:red; } /* notice no :link part */ a:visited { color: blue; } etc.,etc.

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  • HTG Explains: Why Does Rebooting a Computer Fix So Many Problems?

    - by Chris Hoffman
    Ask a geek how to fix a problem you’ve having with your Windows computer and they’ll likely ask “Have you tried rebooting it?” This seems like a flippant response, but rebooting a computer can actually solve many problems. So what’s going on here? Why does resetting a device or restarting a program fix so many problems? And why don’t geeks try to identify and fix problems rather than use the blunt hammer of “reset it”? This Isn’t Just About Windows Bear in mind that this soltion isn’t just limited to Windows computers, but applies to all types of computing devices. You’ll find the advice “try resetting it” applied to wireless routers, iPads, Android phones, and more. This same advice even applies to software — is Firefox acting slow and consuming a lot of memory? Try closing it and reopening it! Some Problems Require a Restart To illustrate why rebooting can fix so many problems, let’s take a look at the ultimate software problem a Windows computer can face: Windows halts, showing a blue screen of death. The blue screen was caused by a low-level error, likely a problem with a hardware driver or a hardware malfunction. Windows reaches a state where it doesn’t know how to recover, so it halts, shows a blue-screen of death, gathers information about the problem, and automatically restarts the computer for you . This restart fixes the blue screen of death. Windows has gotten better at dealing with errors — for example, if your graphics driver crashes, Windows XP would have frozen. In Windows Vista and newer versions of Windows, the Windows desktop will lose its fancy graphical effects for a few moments before regaining them. Behind the scenes, Windows is restarting the malfunctioning graphics driver. But why doesn’t Windows simply fix the problem rather than restarting the driver or the computer itself?  Well, because it can’t — the code has encountered a problem and stopped working completely, so there’s no way for it to continue. By restarting, the code can start from square one and hopefully it won’t encounter the same problem again. Examples of Restarting Fixing Problems While certain problems require a complete restart because the operating system or a hardware driver has stopped working, not every problem does. Some problems may be fixable without a restart, though a restart may be the easiest option. Windows is Slow: Let’s say Windows is running very slowly. It’s possible that a misbehaving program is using 99% CPU and draining the computer’s resources. A geek could head to the task manager and look around, hoping to locate the misbehaving process an end it. If an average user encountered this same problem, they could simply reboot their computer to fix it rather than dig through their running processes. Firefox or Another Program is Using Too Much Memory: In the past, Firefox has been the poster child for memory leaks on average PCs. Over time, Firefox would often consume more and more memory, getting larger and larger and slowing down. Closing Firefox will cause it to relinquish all of its memory. When it starts again, it will start from a clean state without any leaked memory. This doesn’t just apply to Firefox, but applies to any software with memory leaks. Internet or Wi-Fi Network Problems: If you have a problem with your Wi-Fi or Internet connection, the software on your router or modem may have encountered a problem. Resetting the router — just by unplugging it from its power socket and then plugging it back in — is a common solution for connection problems. In all cases, a restart wipes away the current state of the software . Any code that’s stuck in a misbehaving state will be swept away, too. When you restart, the computer or device will bring the system up from scratch, restarting all the software from square one so it will work just as well as it was working before. “Soft Resets” vs. “Hard Resets” In the mobile device world, there are two types of “resets” you can perform. A “soft reset” is simply restarting a device normally — turning it off and then on again. A “hard reset” is resetting its software state back to its factory default state. When you think about it, both types of resets fix problems for a similar reason. For example, let’s say your Windows computer refuses to boot or becomes completely infected with malware. Simply restarting the computer won’t fix the problem, as the problem is with the files on the computer’s hard drive — it has corrupted files or malware that loads at startup on its hard drive. However, reinstalling Windows (performing a “Refresh or Reset your PC” operation in Windows 8 terms) will wipe away everything on the computer’s hard drive, restoring it to its formerly clean state. This is simpler than looking through the computer’s hard drive, trying to identify the exact reason for the problems or trying to ensure you’ve obliterated every last trace of malware. It’s much faster to simply start over from a known-good, clean state instead of trying to locate every possible problem and fix it. Ultimately, the answer is that “resetting a computer wipes away the current state of the software, including any problems that have developed, and allows it to start over from square one.” It’s easier and faster to start from a clean state than identify and fix any problems that may be occurring — in fact, in some cases, it may be impossible to fix problems without beginning from that clean state. Image Credit: Arria Belli on Flickr, DeclanTM on Flickr     

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  • How to replace a div container with javascript

    - by Kovu
    Hi, I must have a little design in javascript. I have a menu with 5 entrys and only 1 HTML-page. So I will have a content-div and enabled and disabled different static content in it, each menu-entry is another content. I tried with 5 divs and disable 4 of them and enable 1, but the element under each other means every div is like a - enabled or not, so the "content" is moving then. Hope its understandable. Here is the code so far: <html><head><title>Des Einsame-Katerchen's kleine Homepage</title> <style type="text/css"> a:link { font-weight:bold; color:blue; text-decoration:none; } a:visited { font-weight:bold; color:blue; text-decoration:none; } a:focus { font-weight:bold; color:blue; text-decoration:none; } a:hover { font-weight:bold; color:blue; text-decoration:line-through; } a:active { font-weight:bold; color:blue; text-decoration:none; } h1:focus { background-color:red; } h1:hover { background-color:silver; } h1:active { background-color:green; } </style> <script> function an(id) { document.getElementById('start').style.visibility = 'hidden'; document.getElementById('start').style.height = '0px'; document.getElementById('me').style.visibility = 'hidden'; document.getElementById('me').style.height = '0px'; document.getElementById('rpg').style.visibility = 'hidden'; document.getElementById('rpg').style.height = '0px'; document.getElementById('musik').style.visibility = 'hidden'; document.getElementById('musik').style.height = '0px'; document.getElementById('screens').style.visibility = 'hidden'; document.getElementById('screens').style.height = '0px'; document.getElementById(id).style.visibility = 'visible'; document.getElementById(id).style.height = '500px'; } </script> </head> <body style=" " > <div style="width=100%; text-align:center; border: 1px red solid; height:40px;"> <div style="float:left; width:100px;"><a href="#" OnClick="an('start')" >Startseite</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('me')" >Über mich</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('rpg')" >RPG-Chars</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('musik')" >Musik</a></div> <div style="float:left; width:150px;"><a href="#" OnClick="an('screens')" >Knuddels-Screens</a></div> </div> <br> <div id="start" style="border:1px red solid; width:500px; height:500px; overflow: visible; " > a </div> <div id="me" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > b </div> <div id="rpg" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > c </div> <div id="musik" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > d </div> <div id="screens" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > e </div> </body>

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  • creating a color coded time chart using colorbar and colormaps in python

    - by Rusty
    I'm trying to make a time tracking chart based on a daily time tracking file that I used. I wrote code that crawls through my files and generates a few lists. endTimes is a list of times that a particular activity ends in minutes going from 0 at midnight the first day of the month to however many minutes are in a month. labels is a list of labels for the times listed in endTimes. It is one shorter than endtimes since the trackers don't have any data about before 0 minute. Most labels are repeats. categories contains every unique value of labels in order of how well I regard that time. I want to create a colorbar or a stack of colorbars (1 for eachday) that will depict how I spend my time for a month and put a color associated with each label. Each value in categories will have a color associated. More blue for more good. More red for more bad. It is already in order for the jet colormap to be right, but I need to get desecrate color values evenly spaced out for each value in categories. Then I figure the next step would be to convert that to a listed colormap to use for the colorbar based on how the labels associated with the categories. I think this is the right way to do it, but I am not sure. I am not sure how to associate the labels with color values. Here is the last part of my code so far. I found one function to make a discrete colormaps. It does, but it isn't what I am looking for and I am not sure what is happening. Thanks for the help! # now I need to develop the graph import numpy as np from matplotlib import pyplot,mpl import matplotlib from scipy import interpolate from scipy import * def contains(thelist,name): # checks if the current list of categories contains the one just read for val in thelist: if val == name: return True return False def getCategories(lastFile): ''' must determine the colors to use I would like to make a gradient so that the better the task, the closer to blue bad labels will recieve colors closer to blue read the last file given for the information on how I feel the order should be then just keep them in the order of how good they are in the tracker use a color range and develop discrete values for each category by evenly spacing them out any time not found should assume to be sleep sleep should be white ''' tracker = open(lastFile+'.txt') # open the last file # find all the categories categories = [] for line in tracker: pos = line.find(':') # does it have a : or a ? if pos==-1: pos=line.find('?') if pos != -1: # ignore if no : or ? name = line[0:pos].strip() # split at the : or ? if contains(categories,name)==False: # if the category is new categories.append(name) # make a new one return categories # find good values in order of last day newlabels=[] for val in getCategories(lastDay): if contains(labels,val): newlabels.append(val) categories=newlabels # convert discrete colormap to listed colormap python for ii,val in enumerate(labels): if contains(categories,val)==False: labels[ii]='sleep' # create a figure fig = pyplot.figure() axes = [] for x in range(endTimes[-1]%(24*60)): ax = fig.add_axes([0.05, 0.65, 0.9, 0.15]) axes.append(ax) # figure out the colors to use # stole this function to make a discrete colormap # http://www.scipy.org/Cookbook/Matplotlib/ColormapTransformations def cmap_discretize(cmap, N): """Return a discrete colormap from the continuous colormap cmap. cmap: colormap instance, eg. cm.jet. N: Number of colors. Example x = resize(arange(100), (5,100)) djet = cmap_discretize(cm.jet, 5) imshow(x, cmap=djet) """ cdict = cmap._segmentdata.copy() # N colors colors_i = np.linspace(0,1.,N) # N+1 indices indices = np.linspace(0,1.,N+1) for key in ('red','green','blue'): # Find the N colors D = np.array(cdict[key]) I = interpolate.interp1d(D[:,0], D[:,1]) colors = I(colors_i) # Place these colors at the correct indices. A = zeros((N+1,3), float) A[:,0] = indices A[1:,1] = colors A[:-1,2] = colors # Create a tuple for the dictionary. L = [] for l in A: L.append(tuple(l)) cdict[key] = tuple(L) # Return colormap object. return matplotlib.colors.LinearSegmentedColormap('colormap',cdict,1024) # jet colormap goes from blue to red (good to bad) cmap = cmap_discretize(mpl.cm.jet, len(categories)) cmap.set_over('0.25') cmap.set_under('0.75') #norm = mpl.colors.Normalize(endTimes,cmap.N) print endTimes print labels # make a color list by matching labels to a picture #norm = mpl.colors.ListedColormap(colorList) cb1 = mpl.colorbar.ColorbarBase(axes[0],cmap=cmap ,orientation='horizontal' ,boundaries=endTimes ,ticks=endTimes ,spacing='proportional') pyplot.show()

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  • Silverlight Cream for January 08, 2011 -- #1023

    - by Dave Campbell
    In this Heavy and yet incomplete Issue: Mike Wolf, Walter Ferrari, Colin Eberhardt, Mathew Charles, Don Burnett, Senthil Kumar, cherylws, Rob Miles, Derik Whittaker, Thomas Martinsen(-2-), Jason Ginchereau, Vishal Nayan, and WindowsPhoneGeek. Above the Fold: Silverlight: "Automatically Showing ToolTips on a Trimmed TextBlock (Silverlight)" Colin Eberhardt WP7: "Windows Phone Blue Book Pdf" Rob Miles Sharepoint/Silverlight: "Discover Sharepoint with Silverlight - Part 1" Walter Ferrari Shoutouts: Dave Isbitski has announced a WP7 Firestarter, check for your local MS office: Announcing the “Light up your Silverlight Applications for Windows 7 Firestarter” From SilverlightCream.com: Leveraging Silverlight in the USA TODAY Windows 7-Based Slate App Mike Wolf has a post up about Cynergy's release of the new USA TODAY software for Windows 7 Slate devices, and gives a great rundown of all the resources, and how specific Silverlight features were used... tons of outstanding external links here! Discover Sharepoint with Silverlight - Part 1 Walter Ferrari has tutorial up at SilverlightShow... looks like the first in a series on Silverlight and Sharepoint... lots of low-level info about the internals and using them. Automatically Showing ToolTips on a Trimmed TextBlock (Silverlight) Colin Eberhardt has a really cool AutoTooltip attached behavior that gives a tooltip of the actual text if text is trimmed ... and has an active demo on the post... very cool. RIA Services Output Caching Mathew Charles digs into a RIA feature that hasn't gotten any blog love: output caching, describing all the ins and outs of improving the performance of your app using caching. Emailing your Files to Box.net Cloud Storage with WP7 Don Burnett details out everything you need to do to get Box.Net and your WP7 setup to talk to each other. Shortcuts keys for Developing on Windows Phone 7 Emulator Senthil Kumar has some good WP7 posts up ... this one is a cheatsheet list of Function-key assignements for the WP7 emulator... another sidebar listint Windows Phone 7 Design Guidelines – Cheat Sheet cherylws has a great Guideline list/Cheat Sheet up for reference while building a WP7 app... this is a great reference... I'm adding it to the Right-hand sidebar of WynApse.com Windows Phone Blue Book Pdf Rob Miles has added another book and color to his collection of both -- Windows Phone Programming in C#, also known as the Windows Phone Blue Book... get a copy from the links he gives, and check out his other free books as well. Navigating to an external URL using the HyperlinkButton Derik Whittaker has a post up discussing the woes (and error messages) of trying to navigate to an external URL with the Hyperlink button in WP7, plus his MVVM-friendly solution that you can download. Set Source on Image from code in Silverlight Thomas Martinsen has a couple posts up... first is this quick one on the code required to set an image source. Show UI element based on authentication Thomas Martinsen's latest is one on a BoolToVisibilityConverter allowing a boolean indicator of Authentication to be used to control the visibility of a button (in the sample) WP7 ReorderListBox improvements: rearrange animations and more Jason Ginchereau has updated his ReorderListBox from last week to add some animations (fading/sliding) during the rearrangement. Navigation in Silverlight Without Using Navigation Framework Vishal Nayan has a post that attracted my attention... Navigation by manipulating RootVisual content... I've been knee-deep in similar code in Prism this week (and why my blogging is off) ... Creating a WP7 Custom Control in 7 Steps WindowsPhoneGeek creates a simple custom control for WP7 before your very eyes in his latest post, focusing on the minimum requirements necessary for writing a Custom Control. Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

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  • Writing a method to 'transform' an immutable object: how should I approach this?

    - by Prog
    (While this question has to do with a concrete coding dilemma, it's mostly about what's the best way to design a function.) I'm writing a method that should take two Color objects, and gradually transform the first Color into the second one, creating an animation. The method will be in a utility class. My problem is that Color is an immutable object. That means that I can't do color.setRGB or color.setBlue inside a loop in the method. What I can do, is instantiate a new Color and return it from the method. But then I won't be able to gradually change the color. So I thought of three possible solutions: 1- The client code includes the method call inside a loop. For example: int duration = 1500; // duration of the animation in milliseconds int steps = 20; // how many 'cycles' the animation will take for(int i=0; i<steps; i++) color = transformColor(color, targetColor, duration, steps); And the method would look like this: Color transformColor(Color original, Color target, int duration, int steps){ int redDiff = target.getRed() - original.getRed(); int redAddition = redDiff / steps; int newRed = original.getRed() + redAddition; // same for green and blue .. Thread.sleep(duration / STEPS); // exception handling omitted return new Color(newRed, newGreen, newBlue); } The disadvantage of this approach is that the client code has to "do part of the method's job" and include a for loop. The method doesn't do it's work entirely on it's own, which I don't like. 2- Make a mutable Color subclass with methods such as setRed, and pass objects of this class into transformColor. Then it could look something like this: void transformColor(MutableColor original, Color target, int duration){ final int STEPS = 20; int redDiff = target.getRed() - original.getRed(); int redAddition = redDiff / steps; int newRed = original.getRed() + redAddition; // same for green and blue .. for(int i=0; i<STEPS; i++){ original.setRed(original.getRed() + redAddition); // same for green and blue .. Thread.sleep(duration / STEPS); // exception handling omitted } } Then the calling code would usually look something like this: // The method will usually transform colors of JComponents JComponent someComponent = ... ; // setting the Color in JComponent to be a MutableColor Color mutableColor = new MutableColor(someComponent.getForeground()); someComponent.setForeground(mutableColor); // later, transforming the Color in the JComponent transformColor((MutableColor)someComponent.getForeground(), new Color(200,100,150), 2000); The disadvantage is - the need to create a new class MutableColor, and also the need to do casting. 3- Pass into the method the actual mutable object that holds the color. Then the method could do object.setColor or similar every iteration of the loop. Two disadvantages: A- Not so elegant. Passing in the object that holds the color just to transform the color feels unnatural. B- While most of the time this method will be used to transform colors inside JComponent objects, other kinds of objects may have colors too. So the method would need to be overloaded to receive other types, or receive Objects and have instanceof checks inside.. Not optimal. Right now I think I like solution #2 the most, than solution #1 and solution #3 the least. However I'd like to hear your opinions and suggestions regarding this.

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  • jQuery plugin for Event Driven Architecture?

    - by leeand00
    Are there any Event Driven Architecture jQuery plugins? Step 1: Subscribing The subscribers subscribe to the event handler in the middle, and pass in a callback method, as well as the name of the event they are listening for... i.e. The two green subscribers will be listening for p0 events. And the blue subscriber will be listening for p1 events. Step 2: The p0 event is fired by another component to the Event Handler A p0 event is fired to the Event Handler The event handler notifies it's subscribers of the event, calling the callback methods they specified when they subscribed in Step 1: Subscribing. Note that the blue subscriber is not notified because it was not listening for p0 events. Step 3: The p1 event is fired a component to the Event Handler The p1 event is fired by another component Just as before except that now the blue subscriber receives the event through its callback and the other two green subscribers do not receive the event. Images by leeand00, on Flickr I can't seem to find one, but my guess is that they just call it something else in Javascript/jquery Also is there a name for this pattern? Because it isn't just a basic publisher/subscriber, it has to be called something else I would think.

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  • Double buffering with C# has negative effect

    - by Roland Illig
    I have written the following simple program, which draws lines on the screen every 100 milliseconds (triggered by timer1). I noticed that the drawing flickers a bit (that is, the window is not always completely blue, but some gray shines through). So my idea was to use double-buffering. But when I did that, it made things even worse. Now the screen was almost always gray, and only occasionally did the blue color come through (demonstrated by timer2, switching the DoubleBuffered property every 2000 milliseconds). What could be an explanation for this? using System; using System.Drawing; using System.Windows.Forms; namespace WindowsFormsApplication1 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void Form1_Paint(object sender, PaintEventArgs e) { Graphics g = CreateGraphics(); Pen pen = new Pen(Color.Blue, 1.0f); Random rnd = new Random(); for (int i = 0; i < Height; i++) g.DrawLine(pen, 0, i, Width, i); } // every 100 ms private void timer1_Tick(object sender, EventArgs e) { Invalidate(); } // every 2000 ms private void timer2_Tick(object sender, EventArgs e) { DoubleBuffered = !DoubleBuffered; this.Text = DoubleBuffered ? "yes" : "no"; } } }

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  • Missing WM_PAINT when hosting a WPF control inside a winforms application.

    - by Boris
    Hi All, Consider the following scenario: 1) Create a winforms application with an empty form. 2) Create a WPF usercontrol in the same project which is just the default control with background changed to blue. <UserControl x:Class="WindowsFormsApplication2.UserControl1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Height="300" Width="300" Background="Blue"> <Grid> </Grid> </UserControl> 3) Build the project 4) Add the control to your form (an ElementHost is added and the control is added inside it). 5) Run the application (everything looks nice) 6) Start Spy++, click find window (Control+F) and move the cursor onto the WPF control (the blue square) Something strange happens, the control gets a WM_ERASEBKGND message but no WM_PAINT message so now it is white. You can resize the form, hide the form behind other windows and the WPF control will not get rendered. There is an image of the scenario here: http://img260.imageshack.us/img260/2296/wmpaint.png This is a simplified example of the situation I have in the actual application. Please tell me what is the best way to resolve this issue such that the WPF control renders itself correctly. I would like a solution that can be incorporated into a large application with many controls on the form. Thank you very much in advance, Boris

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  • How do I display grouped XML data in a Flex pie chart?

    - by mclaughlinj
    I've looked into grouping XML data with GroupingCollections and AdvancedDataGrids, but I can't figure out how to display that data in a chart. Basically, what I want to do is group the data by the category field, which should give me two rows under red, one under blue, and one under green. When inputting this data into the pie chart, it should take up the right amount of space (1/2 for red, 1/4 each for blue and green). I don't need the other_data field, as I'd like to use the group name (category in this case) as the callout. Any suggestions? Sample data: <row> <category>red</category> <other_data>this shouldn't really matter</other_data> </row> <row> <category>blue</category> <other_data>this shouldn't really matter</other_data> </row> <row> <category>red</category> <other_data>this shouldn't really matter</other_data> </row> <row> <category>green</category> <other_data>this shouldn't really matter</other_data> </row>

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  • a selector which has this selector together with a class selector

    - by Woho87
    Here is an analogy of my problem(a selector which has this selector together with a class selector): Let say that I selects all yellow(classes) div elements in a arbitrary HTML document. And I want each to check if the attribute is yes = 1. If the attribute 'yes' equals '1', then I want the child with class 'blue' have the attribute 'no' equals '1'; $('div .yellow').each(function(){ if($(this).attr('yes') == 1){ $(this '.blue:first-child').attr('no', 1);//This line needs to be fixed } }); I know that the line this.getElementsByClassName('blue')[0] fixes this problem. But in my real problem (not this analogy) I want to use addClass and removeClass which only functions with jQuery objects. It is to cumbersome to use other functions than addClass and removeClass. UPDATE: Here is a code snippet from my real problem. I got some problem with "this" in javascript. I want a invited button to have the className visible when I click on it. The button lies within a div element with className 'box'. I know that there are problem with 'this' on the code snippet. But I want the button and not the box to change to visible $('.Box').each(function(){ if($(this).attr('hasButton') != 1){ var invite = document.createElement('div'); invite.className = 'invite invisible'; invite.innerHTML = 'invite'; $(this).attr('hasButton', 1); this.appendChild(invite); invite.addEventListener('mouseover', function(event){ $('.invite', this).removeClass('invisible');//this line is not functioning $('.invite', this).addClass('visible');//neither this }, false); } });

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