Search Results

Search found 25600 results on 1024 pages for 'table partitioning'.

Page 19/1024 | < Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >

  • Tool to automatically combine many large pivot table in many large Excel sheet ?

    - by Sim
    Hi all, We have several Excel files that contains large pivot data table with the same structure For example File A Pivot table (Field A, B, C) File B Pivot table (Field A, B, C) We want to combine them into 1 pivot table (A, B, C). Just want to know which ways we can do it ? Manual way : open a new empty sheet, copy and paste the pivot there and create the pivot again Automatic way : is there some tool that did this ? Thanks

    Read the article

  • Why Doesn’t Partition Elimination Work?

    - by Paul White
    Given a partitioned table and a simple SELECT query that compares the partitioning column to a single literal value, why does SQL Server read all the partitions when it seems obvious that only one partition needs to be examined? Sample Data The following script creates a table, partitioned on the char(3) column ‘Div’, and populates it with 100,000 rows of data: USE Sandpit; GO CREATE PARTITION FUNCTION PF ( char (3)) AS RANGE RIGHT FOR VALUES ( '1' , '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9'...(read more)

    Read the article

  • SQL SERVER – Finding Different ColumnName From Almost Identitical Tables

    - by pinaldave
    I have mentioned earlier on this blog that I love social media – Facebook and Twitter. I receive so many interesting questions that sometimes I wonder how come I never faced them in my real life scenario. Well, let us see one of the similar situation. Here is one of the questions which I received on my social media handle. “Pinal, I have a large database. I did not develop this database but I have inherited this database. In our database we have many tables but all the tables are in pairs. We have one archive table and one current table. Now here is interesting situation. For a while due to some reason our organization has stopped paying attention to archive data. We did not archive anything for a while. If this was not enough we  even changed the schema of current table but did not change the corresponding archive table. This is now becoming a huge huge problem. We know for sure that in current table we have added few column but we do not know which ones. Is there any way we can figure out what are the new column added in the current table and does not exist in the archive tables? We cannot use any third party tool. Would you please guide us?” Well here is the interesting example of how we can use sys.column catalogue views and get the details of the newly added column. I have previously written about EXCEPT over here which is very similar to MINUS of Oracle. In following example we are going to create two tables. One of the tables has extra column. In our resultset we will get the name of the extra column as we are comparing the catalogue view of the column name. USE AdventureWorks2012 GO CREATE TABLE ArchiveTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100)); CREATE TABLE CurrentTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100), ExtraCol INT); GO -- Columns in ArchiveTable but not in CurrentTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' GO -- Columns in CurrentTable but not in ArchiveTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' GO DROP TABLE ArchiveTable; DROP TABLE CurrentTable; GO The above query will return us following result. I hope this solves the problems. It is not the most elegant solution ever possible but it works. Here is the puzzle back to you – what native T-SQL solution would you have provided in this situation? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Issues with LVM partition size in Server 13.04

    - by Michael
    I am new to ubuntu and a little confused about how hard drive partitions and LVM works. I remember setting up Ubuntu server 13.04 and telling to to use 1TB of a 3TB server. Well I have maxed that out with blu-ray rips and want the rest of the drive for space. On log-in it says: System load: 2.24 Processes: 179 Usage of /: 88.7% of 912.89GB Users logged in: 0 Memory usage: 6% IP address for p5p1: 192.168.0.100 Swap usage: 0% => / is using 88.7% of 912.89GB lvdisplay outputs: --- Logical volume --- LV Path /dev/DeathStar-vg/root LV Name root VG Name DeathStar-vg LV Write Access read/write LV Creation host, time DeathStar, 2013-05-18 22:21:11 -0400 LV Status available # open 1 LV Size 2.70 TiB Current LE 707789 Segments 2 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 252:0 --- Logical volume --- LV Path /dev/DeathStar-vg/swap_1 LV Name swap_1 VG Name DeathStar-vg LV Write Access read/write LV Creation host, time DeathStar, 2013-05-18 22:21:11 -0400 LV Status available # open 2 LV Size 3.75 GiB Current LE 959 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 252:1 vgdisplay outputs: VG Name DeathStar-vg System ID Format lvm2 Metadata Areas 1 Metadata Sequence No 4 VG Access read/write VG Status resizable MAX LV 0 Cur LV 2 Open LV 2 Max PV 0 Cur PV 1 Act PV 1 VG Size 2.73 TiB PE Size 4.00 MiB Total PE 715335 Alloc PE / Size 708748 / 2.70 TiB Free PE / Size 6587 / 25.73 GiB df outputs: Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/DeathStar--vg-root 957238932 848972636 59634696 94% / none 4 0 4 0% /sys/fs/cgroup udev 1864716 4 1864712 1% /dev tmpfs 374968 1060 373908 1% /run none 5120 4 5116 1% /run/lock none 1874824 148 1874676 1% /run/shm none 102400 24 102376 1% /run/user /dev/sda2 234153 56477 165184 26% /boot And fdisk /dev/sda -l outputs: Disk /dev/sda: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders, total 5860533168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 4294967295 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. I just don't know what to make of all this and am not sure how I can make it use all 2.73TBs. Thanks in advance for any help. EDIT-- Yes I did make changes to the LVM Config, but it didnt do anything. As requested, output of parted -l /dev/sda Model: ATA WDC WD30EFRX-68A (scsi) Disk /dev/sda: 3001GB Sector size (logical/physical): 512B/4096B Partition Table: gpt Number Start End Size File system Name Flags 1 1049kB 2097kB 1049kB bios_grub 2 2097kB 258MB 256MB ext2 3 258MB 3001GB 3000GB lvm Model: ATA WDC WD30EFRX-68A (scsi) Disk /dev/sdb: 3001GB Sector size (logical/physical): 512B/4096B Partition Table: msdos Number Start End Size Type File system Flags Model: Linux device-mapper (linear) (dm) Disk /dev/mapper/DeathStar--vg-swap_1: 4022MB Sector size (logical/physical): 512B/4096B Partition Table: loop Number Start End Size File system Flags 1 0.00B 4022MB 4022MB linux-swap(v1) Model: Linux device-mapper (linear) (dm) Disk /dev/mapper/DeathStar--vg-root: 2969GB Sector size (logical/physical): 512B/4096B Partition Table: loop Number Start End Size File system Flags 1 0.00B 2969GB 2969GB ext4

    Read the article

  • uninstalling and reinstalling 13.04 to a different hard drive

    - by James
    i recently downloaded and installed ubuntu 13.04, the problem is that i deleted windows operating system by mistake so now only have ubuntu to work off of, im trying to uninstall and reinstall ubuntu to a different hard drive as the one it is currently installed on doesnt have sufficient disk space, could someone instruct how to do this, explaining the partitioning part too as im new and dont fully understand it

    Read the article

  • Weird Ubuntu Desktop Boot Partition On External Hard Drive

    - by Magnitus
    I have a Thinkpad with Windows 7. Last time I installed an Ubuntu/Windows dual boot, Windows was never same after and regularly got corrupted so this time, I installed Ubuntu on a separate external hard drive. I took a 500 GB external hard drive and used Windows to shrink the partition on it to 400 GB, freeing 100 GB to install Ubuntu. Then I modified the booting priority of my computer to boot from the external hard drive if present. Then, I installed Ubuntu desktop on the external hard drive using a DVD, picked the most simplistic partitioning scheme I could get away with (didn't go auto as it didn't include the external hard drive as a choice) and voilà. Fast forward some time and I'm trying to refresh my understanding of Linux partitions to install a bunch of servers, so I'm looking at the current partitioning scheme on my external hard drive and find the boot partition puzzling... sda is my integrated hard drive with Windows 7. sdb is my Ubuntu desktop external hard drive. Running parted on sdb, I get this: (parted) print Model: WD My Passport 0740 (scsi) Disk /dev/sdb: 500GB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 1049kB 393GB 393GB primary ntfs boot 2 393GB 500GB 107GB extended 5 393GB 425GB 32.8GB logical linux-swap(v1) 6 425GB 500GB 74.6GB logical ext4 At this point, I'm wondering why the ntfs partition is flagged as "boot" and not my ext4 partition which is the partition that contains / (and by extension, /boot since it's not on its own separate partition). Looking at mtab only confirms what I already know: eric@eric-ThinkPad-W530:~$ sudo cat /etc/mtab /dev/sdb6 / ext4 rw,errors=remount-ro 0 0 proc /proc proc rw,noexec,nosuid,nodev 0 0 sysfs /sys sysfs rw,noexec,nosuid,nodev 0 0 none /sys/fs/cgroup tmpfs rw 0 0 none /sys/fs/fuse/connections fusectl rw 0 0 none /sys/kernel/debug debugfs rw 0 0 none /sys/kernel/security securityfs rw 0 0 udev /dev devtmpfs rw,mode=0755 0 0 devpts /dev/pts devpts rw,noexec,nosuid,gid=5,mode=0620 0 0 tmpfs /run tmpfs rw,noexec,nosuid,size=10%,mode=0755 0 0 none /run/lock tmpfs rw,noexec,nosuid,nodev,size=5242880 0 0 none /run/shm tmpfs rw,nosuid,nodev 0 0 none /run/user tmpfs rw,noexec,nosuid,nodev,size=104857600,mode=0755 0 0 none /sys/fs/pstore pstore rw 0 0 systemd /sys/fs/cgroup/systemd cgroup rw,noexec,nosuid,nodev,none,name=systemd 0 0 gvfsd-fuse /run/user/1000/gvfs fuse.gvfsd-fuse rw,nosuid,nodev,user=eric 0 0 /dev/sdb1 /media/eric/My\040Passport fuseblk rw,nosuid,nodev,allow_other,default_permissions,blksize=4096 0 0 My lack of understanding concerning this is not vital to anything (this is only my development desktop partition), but somehow annoys me. Any insight that could shed some light on this would be welcome.

    Read the article

  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

    Read the article

  • CSS: Labels in table columns

    - by hello
    Hello. BACKGROUND: I would like to have small labels in columns of a table. I'm using some implemented parts of HTML5/CSS3 in my project, and this section specifically is for mobile devices. While both facts are not necessarily relevant, the bottom line is that I don't have to support Internet Explorer or even Firefox for that matter (just WebKit). THE PROBLEM With my current CSS approach, the vertical padding of the cell comes from the <span element (set to display: block with top/bottom margins), which contains the "value" of the column. As a result there's no padding when the <span> is empty or missing (no value) and the label is not in place. The "full" coulmns should give you the idea of where I want the labels to be, even if there's no value, and the <span> is not there. I realize that I could use "non-breaking-space", but I would really like to avoid it. I wonder if any of you have a fix / better way to do this? current code is below. Thank you for any help. <!DOCTYPE html> <html lang="en"> <head> <title>ah</title> <style> body { width: 320px; } /* TABLE */ table { width: 100%; border-collapse: collapse; font-family: arial; } th, td { border: 1px solid #ccc; border-width: 0px 0px 1px 1px; } th:last-child, td:last-child { border-right-width: 1px; } tr:first-child th { border-top-width: 1px; background: #efefef; } /* RELEVANT STUFF */ td { padding: 3px; } td sup { display: block; } td span { display: block; margin: 3px 0px; text-align: center; } </style> </head> <body> <table> <tr> <th colspan="3">something</th> </tr> <tr> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span></span></td><!-- No content, just a label --> </tr> </table> </body> </html>

    Read the article

  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

    Read the article

  • How to Navigate Directly From One Table to Another in Word 2013

    - by Lori Kaufman
    Jumping to a specific page in Word is a common task and easy to do using the Find and Replace dialog box. You can also use this same tab to jump from one table directly to the next table in your document. Your cursor does not have to be in a table to jump to the next table. Put the cursor in any paragraph or table and press F5 or use the Ctrl + G keystroke combination to open the Find and Replace dialog box. The Go To tab is automatically selected. Select Table from the Go to what list and click Next. The next table in your document is selected and the Find and Replace dialog box stays open.    

    Read the article

  • Subquery using derived table in Hibernate HQL

    - by Vladimir
    I have a Hibernate HQL question. I'd like to write a subquery as a derived table (for performance reasons). Is it possible to do that in HQL? Example: FROM Customer WHERE country.id in (SELECT id FROM (SELECT id FROM Country where type='GREEN') derivedTable) (btw, this is just a sample query so don't give advices on rewriting it, is just the derived table concept I'm interested in) Thanks.

    Read the article

  • ExtJS: Adding table inside a dynamically added tab

    - by esskar
    Hi, i'm fairly new to ExtJS. I adopted some examples and added the functionality to add tabs to a tab-control by clicking on some link. so far so good. now i want to load a ExtJS table into on of the new tabs. the items (rows, columns) are defined in a database on the server side. can you give me some hints how to add the table automatically when the tab is created?

    Read the article

  • SQLite3, "ALTER TABLE" and durability

    - by Bill
    I'd like to run some ALTER TABLE statements on a sqlite3 database. What happens if the user kills the process or the power is cut while the ALTER TABLE is running? Will the database be left in a corrupt intermediate state?

    Read the article

  • Table-Valued Parameter in Stored Procedure and the Entity Framework 4.0

    - by Fabio
    Hi there, I have a stored procedure called 'GetPrices' with a Table-Valued Parameter called 'StoreIDs' and I would like to call it from my Entity Framework. But when I try to add the Stored Procedure to the EDM, i get the following error: The function 'GetPrices' has a parameter 'StoreIDs' at parameter index 2 that has a data type 'table type' which is not supported. The function was excluded. Is there any workaround this? Any thoughts? Fabio

    Read the article

  • Flex: How to most effectively tavere a table column

    - by Maik
    I have a table "template" which is used in various "instances". All instances have checkboxes in the second column (for record-delete). What would be the most effective way of traversing the table and check if at least one checkbox is selected (to enable a "delete" button)? Thanks! Maik

    Read the article

  • table with black outer, but grey inner border

    - by Jan-Frederik Carl
    Hello, I want to create a html table with a 1pt black outer border and the same border around every td. Should look like this (only the borders, of course) link text I use <table border="1" style="border-collapse:collapse; border-color:Black; border-style:solid; border-width:1pt"> As a result I get a black outer, but grey inner borders.

    Read the article

  • mysql create table help with unique

    - by Matt
    I'm trying to create a table, and can't figure out how to assign two columns to be unique.. I know how to alter a table thats already created, but how do you do it in the create.. im after a create if not exist col1 TEXT, col2 TEXT, col3 TEXT unique(col1, col2) ^very rough basic but you get the idea

    Read the article

  • [solved] PHP-called hyperlink stopped showing when CSS table implemented

    - by Luke
    EDIT: Solved - was not flutter's tag stripping, should work as advertised. I'm using Flutter (which creates custom fields) in Wordpress to display profile information entered as a Post. Before I implemented the CSS tables the link showed up and was clickable. Now I get nothing returned, even when I try to call the link outside the table. If you know anything about this, here's my code in the index.php file and I remain available for any questions. <?php if (in_category('Profile')) { ?> <table id="mytable" cellspacing="0"> -snip- <tr> <th class="row1" valign="top">Website </td> <td>Link: <a href="<?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?>"> <?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?></a></td> </tr> -snip- </table> Thanks, L Edit: @Josh - there is a foreach looping construct in the table and it is reading and displaying the code correctly, I see what you're getting at now: <tr> <th class="row2" valign="top">Specialities </td> <td class="alt" valign="top"><?php $my_array = get('Expertise'); $output = ""; foreach($my_array as $check) { $output .= "<span>$check</span><br/> "; } echo $output; ?></td> </tr> Edit - @Josh - here's the old code as far as I can remember it, there was no major difference just a <td> tag where there now stands a <th>, there wasn't the class="" and there was no "Link:" and FrWebsite was called Website, but it still didn't work when called Website so I changed to see if that was the error. <tr> <td width="200" valign="top">Website </td> <td><a href="<?php echo get_post_meta($post->ID, 'Website', $single=true) ?>"><?php echo get_post_meta($post->ID, 'Website', $single=true) ?></a></td> </tr>

    Read the article

  • SQLite3 table not accepting INSERT INTO statements. The table is created, and so is the database, but nothing is passed into it

    - by user1460029
    <?php try { //open the database $db = new PDO('sqlite:music.db'); $db->exec("DELETE from Music;"); $db->exec("INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whatd I Say', 'Ray Charles', '1956');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Smells Like Teen Spirit.', 'Nirvana', '1991');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Hey Jude', 'The Beatles', '1968');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Johnny B. Goode', 'Chuck Berry', '1958');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Good Vibrations', 'The Beach Boys', '1966');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Respect', 'Aretha Franklin', '1967');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whats Going On', 'Marvin Gaye', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Imagine', 'John Lennon', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('(I Cant Get No) Satisfaction', 'Rolling Stones', '1965');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Like A Rolling Stone', 'Bob Dylan', '1965');"); //now output the data to a simple html table... //example of specifier --> WHERE First=\'Josh\'; <-- print "<table border=1>"; print "<tr><td>Title</td><td>Author</td><td>Y.O.P.</td></tr>"; $result = $db->query('SELECT * FROM Music '); foreach($result as $row) { print "<td>".$row['Title']."</td>"; print "<td>".$row['Author']."</td>"; print "<td>".$row['ReleaseDate']."</td></tr>"; } print "</table>"; $db = NULL; } catch(PDOException $e) { print 'Exception : '.$e->getMessage(); } ?> I am not sure why nothing is being inserted into the table. The file 'music.db' exists in the right path. For the record, I can only use SQlite3, no SQL allowed. PHP is allowed, so is SQLite3.

    Read the article

  • create a text table with php using fixed width font

    - by Hintswen
    I want to write a PHP script to output some data as a plain-text table using spaces to get the data into columns (just like the Linux top command). I can't use a HTML table as the script output will be saved to disk and viewed in a plain-text editor. Is there anything available that can do this automatically (format the data into columns)?

    Read the article

< Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >