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• nHibernate Self Join Mapping

  - by kmoo01

  Hi Guys, This is probably incredibly simple, but I just cant see the wood for the trees at the moment. For brevity, I would like to model a word object, that has related words to it (synonyms), In doing so I could have the following mappings: <class name="Word" table="bs_word"> <id name="Id" column="WordId" type="Int32" unsaved-value="-1"> <generator class="native"> <param name="sequence"></param> </generator> </id> <property name="Key" column="word" type="String" length="50" /> <many-to-one name="SynonymGroup" class="BS.Core.Domain.Synonym, BS.Core" column="SynonymId" lazy="false"/> <class name="Synonym" table="bs_Synonym"> <id name="Id" column="SynonymId" type="Int32" unsaved-value="-1"> <generator class="native"> <param name="sequence"></param> </generator> </id> <property name="Alias" column="Alias" type="String" length="50" /> <bag name="Words" cascade="none" lazy="false" inverse="true"> <key column="SynonymId" /> <one-to-many class="Word" /> </bag> Mapping it like this would mean for a given word, I can access related words (synonyms) like this: word.SynonymGroup.Words However I would like to know if it is possible to map a bag of objects on an instance of a word object...if that makes sense, so I can access the related words like this: word.Words I've tried playing around with the map element, and composite elements, all to no avail - so I was wondering if some kind person could point me in the right direction? ta, kmoo01

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• Iterating through String word at a time in Python

  - by AlgoMan

  I have a string buffer of a huge text file. I have to search a given words/phrases in the string buffer. Whats the efficient way to do it ? I tried using re module matches. But As i have a huge text corpus that i have to search through. This is taking large amount of time. Given a Dictionary of words and Phrases. I iterate through the each file, read that into string , search all the words and phrases in the dictionary and increment the count in the dictionary if the keys are found. One small optimization that we thought was to sort the dictionary of phrases/words with the max number of words to lowest. And then compare each word start position from the string buffer and compare the list of words. If one phrase is found, we don search for the other phrases (as it matched the longest phrase ,which is what we want) Can some one suggest how to go about word by word in the string buffer. (Iterate string buffer word by word) ? Also, Is there any other optimization that can be done on this ?

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• Full Text Search like Google

  - by Eduardo

  I would like to implement full-text-search in my off-line (android) application to search the user generated list of notes. I would like it to behave just like Google (since most people are already used to querying to Google) My initial requirements are: Fast: like Google or as fast as possible, having 100000 documents with 200 hundred words each. Searching for two words should only return documents that contain both words (not just one word) (unless the OR operator is used) Case insensitive (aka: normalization): If I have the word 'Hello' and I search for 'hello' it should match. Diacritical mark insensitive: If I have the word 'así' a search for 'asi' should match. In Spanish, many people, incorrectly, either do not put diacritical marks or fail in correctly putting them. Stop word elimination: To not have a huge index meaningless words like 'and', 'the' or 'for' should not be indexed at all. Dictionary substitution (aka: stem words): Similar words should be indexed as one. For example, instances of 'hungrily' and 'hungry' should be replaced with 'hunger'. Phrase search: If I have the text 'Hello world!' a search of '"world hello"' should not match it but a search of '"hello world"' should match. Search all fields (in multifield documents) if no field specified (not just a default field) Auto-completion in search results while typing to give popular searches. (just like Google Suggest) How may I configure a full-text-search engine to behave as much as possible as Google? (I am mostly interested in Open Source, Java and in particular Lucene)

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• Algorithm complexity question

  - by Itsik

  During a recent job interview, I was asked to give a solution to the following problem: Given a string s (without spaces) and a dictionary, return the words in the dictionary that compose the string. For example, s= peachpie, dic= {peach, pie}, result={peach, pie}. I will ask the the decision variation of this problem: if s can be composed of words in the dictionary return yes, otherwise return no. My solution to this was in backtracking (written in Java) public static boolean words(String s, Set<String> dictionary) { if ("".equals(s)) return true; for (int i=0; i <= s.length(); i++) { String pre = prefix(s,i); // returns s[0..i-1] String suf = suffix(s,i); // returns s[i..s.len] if (dictionary.contains(pre) && words(suf, dictionary)) return true; } return false; } public static void main(String[] args) { Set<String> dic = new HashSet<String>(); dic.add("peach"); dic.add("pie"); dic.add("1"); System.out.println(words("peachpie1", dic)); // true System.out.println(words("peachpie2", dic)); // false } What is the time complexity of this solution? I'm calling recursively in the for loop, but only for the prefix's that are in the dictionary. Any idea's?

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• typeahead.js remote with subset matching

  - by rebelde

  Instead of returning to the server after each additional letter is typed, I want it to only go to the server once, get all matching words, and filter the downloaded data after that. We are having trouble making this work. We are successfully using "remote" to wait until two letters are typed, but we can't get it to stop going to the server as additional letters are typed. Steps: 1. After two letters are typed, retrieve all matching words that start with those two letters. 2. When a third and additional letters are typed, don't go to the server again, just filter from the previous list that was sent. An example: "mo" is typed in. All 100 words that start with "mo" are returned. (Only 10 are shown.) "mor" - now with a third letter, we don't go back to the server. We just find the 20 words that match from within the previous set of words. Can anybody make this work? In real life (using YUI2), we do this and then go back to the server if somebody types in a space after the word. At that point, we know to retrieve additional words. Thanks!

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• Script says Undefined

  - by user1058887

  I have this script that would let the user input a text and it would get translated into something else. It works only when the word has only 1 letter. When there is more than 1 letter it says Undefined. Here is the script : function copyit(theField) { var tempval=eval("document."+theField) tempval.focus() tempval.select() therange=tempval.createTextRange() therange.execCommand("Copy") } function results() { var behavior="form"; var text=document.csrAlpha.csrresult2.value; var ff22=text.toLowerCase(); var Words=new Array ; Words["b"]="Dadada"; Words["bob"]="Robert"; Words["flower"]="Banana"; Words["brad"]="Chair"; var trans=""; var regExp=/[\!@#$%^&*(),=";:\/]/; var stringCheck=regExp.exec(ff22); if(!stringCheck) { if(ff22.length > 0) { for(var i=0;i < ff22.length;i++) { var thisChar=ff22.charAt(i); trans += Words[thisChar] + " "; } } else { trans +="Please write something."; } } else { trans +="You entered invalid characters. Remove them and try again."; } document.csrAlpha.csrresult.value=trans; } Please insert your text below:

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• If statement String trouble

  - by Jeremy Stone

  I'm trying to create a program which takes user input of two words and determines whether or not these words are the same. import java.util.Scanner; public class L7E3 { public static void main(String[] args) { Scanner keyboard = new Scanner(System. in ); String word1, word2; System.out.println("Please enter a word: "); word1 = keyboard.nextLine(); System.out.println("Please enter a word: "); word2 = keyboard.nextLine(); if (word1 == word2) { System.out.println("The words are " + word1 + " and " + word2 + ". These words are the same."); } else { System.out.println("The words are " + word1 + " and " + word2 + ". These words are not the same."); } } } I figured that word1==word2 would have worked to determine whether the two strings were equal, I'm using JGrasp and it goes directly to my else option regardless of input. Am I doing something wrong with strings?

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• Large free block of english non-pronoun text

  - by Tom

  As part of teaching myself python I've written a script which allows a user to play hangman. At the moment, the hangman word to be guessed is simply entered manually at the start of the script's code. I want instead for the script to choose randomly from a large list of english words. This I know how to do - my problem is finding that list of words to work from in the first place. Does anyone know of a source on the net for, say, 1000 common english words where they can be downloaded as a block of text or something similar that I can work with? (My initial thought was grabbing a chunk of a novel from project gutenburg [this project is only for my own amusement and won't be available anywhere else so copyright etc doesn't matter hugely to me btw], but anything like that is likely to contain too many names or non-standard words that wouldn't be suitable for hangman. I need text that only has words legal for use in scrabble, basically). It's a slightly odd question for here I suppose, but actually I thought the answer might be of use not just to me but anyone else working on a project for a wordgame or similar that needs a large seed list of words to work from. Many thanks for any links or suggestions :)

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• How to make Vim spellcheck remember a new word

  - by Halpo

  I'm using gvim for latex editing. I write lots of scientific documents with words that the vim dictionary does not know. When running through spell checking I come across words that I know are spelled correctly, how do I add those words to the dictionary?

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• Take all fields in a database table and put them straight into a text file

  - by DalexL

  I have an database file (mdb) file that contains a dictionary of words. A couple thousand of them. I just need the words (in the order they are already in) put into a text file. Currently they have ID's associated with them (e.g. 1, 2, 3) but I don't need it. I just need the words. What is the best way to do this? Actually, if somebody is able to find a dictionary of English words (something along the lines of a scrabble dictionary) that is free online, I'll accept that too. I just can't seem to find any good ones online.

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• Convert Java program to C

  - by imicrothinking

  I need a bit of guidance with writing a C program...a bit of quick background as to my level, I've programmed in Java previously, but this is my first time programming in C, and we've been tasked to translate a word count program from Java to C that consists of the following: Read a file from memory Count the words in the file For each occurrence of a unique word, keep a word counter variable Print out the top ten most frequent words and their corresponding occurrences Here's the source program in Java: package lab0; import java.io.File; import java.io.FileReader; import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; public class WordCount { private ArrayList<WordCountNode> outputlist = null; public WordCount(){ this.outputlist = new ArrayList<WordCountNode>(); } /** * Read the file into memory. * * @param filename name of the file. * @return content of the file. * @throws Exception if the file is too large or other file related exception. */ public char[] readFile(String filename) throws Exception{ char [] result = null; File file = new File(filename); long size = file.length(); if (size > Integer.MAX_VALUE){ throw new Exception("File is too large"); } result = new char[(int)size]; FileReader reader = new FileReader(file); int len, offset = 0, size2read = (int)size; while(size2read > 0){ len = reader.read(result, offset, size2read); if(len == -1) break; size2read -= len; offset += len; } return result; } /** * Make article word by word. * * @param article the content of file to be counted. * @return string contains only letters and "'". */ private enum SPLIT_STATE {IN_WORD, NOT_IN_WORD}; /** * Go through article, find all the words and add to output list * with their count. * * @param article the content of the file to be counted. * @return words in the file and their counts. */ public ArrayList<WordCountNode> countWords(char[] article){ SPLIT_STATE state = SPLIT_STATE.NOT_IN_WORD; if(null == article) return null; char curr_ltr; int curr_start = 0; for(int i = 0; i < article.length; i++){ curr_ltr = Character.toUpperCase( article[i]); if(state == SPLIT_STATE.IN_WORD){ article[i] = curr_ltr; if ((curr_ltr < 'A' || curr_ltr > 'Z') && curr_ltr != '\'') { article[i] = ' '; //printf("\nthe word is %s\n\n",curr_start); if(i - curr_start < 0){ System.out.println("i = " + i + " curr_start = " + curr_start); } addWord(new String(article, curr_start, i-curr_start)); state = SPLIT_STATE.NOT_IN_WORD; } }else{ if (curr_ltr >= 'A' && curr_ltr <= 'Z') { curr_start = i; article[i] = curr_ltr; state = SPLIT_STATE.IN_WORD; } } } return outputlist; } /** * Add the word to output list. */ public void addWord(String word){ int pos = dobsearch(word); if(pos >= outputlist.size()){ outputlist.add(new WordCountNode(1L, word)); }else{ WordCountNode tmp = outputlist.get(pos); if(tmp.getWord().compareTo(word) == 0){ tmp.setCount(tmp.getCount() + 1); }else{ outputlist.add(pos, new WordCountNode(1L, word)); } } } /** * Search the output list and return the position to put word. * @param word is the word to be put into output list. * @return position in the output list to insert the word. */ public int dobsearch(String word){ int cmp, high = outputlist.size(), low = -1, next; // Binary search the array to find the key while (high - low > 1) { next = (high + low) / 2; // all in upper case cmp = word.compareTo((outputlist.get(next)).getWord()); if (cmp == 0) return next; else if (cmp < 0) high = next; else low = next; } return high; } public static void main(String args[]){ // handle input if (args.length == 0){ System.out.println("USAGE: WordCount <filename> [Top # of results to display]\n"); System.exit(1); } String filename = args[0]; int dispnum; try{ dispnum = Integer.parseInt(args[1]); }catch(Exception e){ dispnum = 10; } long start_time = Calendar.getInstance().getTimeInMillis(); WordCount wordcount = new WordCount(); System.out.println("Wordcount: Running..."); // read file char[] input = null; try { input = wordcount.readFile(filename); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); System.exit(1); } // count all word ArrayList<WordCountNode> result = wordcount.countWords(input); long end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordcount: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); System.out.println("wordsort: running ..."); start_time = Calendar.getInstance().getTimeInMillis(); Collections.sort(result); end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordsort: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); Collections.reverse(result); System.out.println("\nresults (TOP "+ dispnum +" from "+ result.size() +"):\n" ); // print out result String str ; for (int i = 0; i < result.size() && i < dispnum; i++){ if(result.get(i).getWord().length() > 15) str = result.get(i).getWord().substring(0, 14); else str = result.get(i).getWord(); System.out.println(str + " - " + result.get(i).getCount()); } } public class WordCountNode implements Comparable{ private String word; private long count; public WordCountNode(long count, String word){ this.count = count; this.word = word; } public String getWord() { return word; } public void setWord(String word) { this.word = word; } public long getCount() { return count; } public void setCount(long count) { this.count = count; } public int compareTo(Object arg0) { // TODO Auto-generated method stub WordCountNode obj = (WordCountNode)arg0; if( count - obj.getCount() < 0) return -1; else if( count - obj.getCount() == 0) return 0; else return 1; } } } Here's my attempt (so far) in C: #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <string.h> // Read in a file FILE *readFile (char filename[]) { FILE *inputFile; inputFile = fopen (filename, "r"); if (inputFile == NULL) { printf ("File could not be opened.\n"); exit (EXIT_FAILURE); } return inputFile; } // Return number of words in an array int wordCount (FILE *filePointer, char filename[]) {//, char *words[]) { // count words int count = 0; char temp; while ((temp = getc(filePointer)) != EOF) { //printf ("%c", temp); if ((temp == ' ' || temp == '\n') && (temp != '\'')) count++; } count += 1; // counting method uses space AFTER last character in word - the last space // of the last character isn't counted - off by one error // close file fclose (filePointer); return count; } // Print out the frequencies of the 10 most frequent words in the console int main (int argc, char *argv[]) { /* Step 1: Read in file and check for errors */ FILE *filePointer; filePointer = readFile (argv[1]); /* Step 2: Do a word count to prep for array size */ int count = wordCount (filePointer, argv[1]); printf ("Number of words is: %i\n", count); /* Step 3: Create a 2D array to store words in the file */ // open file to reset marker to beginning of file filePointer = fopen (argv[1], "r"); // store words in character array (each element in array = consecutive word) char allWords[count][100]; // 100 is an arbitrary size - max length of word int i,j; char temp; for (i = 0; i < count; i++) { for (j = 0; j < 100; j++) { // labels are used with goto statements, not loops in C temp = getc(filePointer); if ((temp == ' ' || temp == '\n' || temp == EOF) && (temp != '\'') ) { allWords[i][j] = '\0'; break; } else { allWords[i][j] = temp; } printf ("%c", allWords[i][j]); } printf ("\n"); } // close file fclose (filePointer); /* Step 4: Use a simple selection sort algorithm to sort 2D char array */ // PStep 1: Compare two char arrays, and if // (a) c1 > c2, return 2 // (b) c1 == c2, return 1 // (c) c1 < c2, return 0 qsort(allWords, count, sizeof(char[][]), pstrcmp); /* int k = 0, l = 0, m = 0; char currentMax, comparedElement; int max; // the largest element in the current 2D array int elementToSort = 0; // elementToSort determines the element to swap with starting from the left // Outer a iterates through number of swaps needed for (k = 0; k < count - 1; k++) { // times of swaps max = k; // max element set to k // Inner b iterates through successive elements to fish out the largest element for (m = k + 1; m < count - k; m++) { currentMax = allWords[k][l]; comparedElement = allWords[m][l]; // Inner c iterates through successive chars to set the max vars to the largest for (l = 0; (currentMax != '\0' || comparedElement != '\0'); l++) { if (currentMax > comparedElement) break; else if (currentMax < comparedElement) { max = m; currentMax = allWords[m][l]; break; } else if (currentMax == comparedElement) continue; } } // After max (count and string) is determined, perform swap with temp variable char swapTemp[1][20]; int y = 0; do { swapTemp[0][y] = allWords[elementToSort][y]; allWords[elementToSort][y] = allWords[max][y]; allWords[max][y] = swapTemp[0][y]; } while (swapTemp[0][y++] != '\0'); elementToSort++; } */ int a, b; for (a = 0; a < count; a++) { for (b = 0; (temp = allWords[a][b]) != '\0'; b++) { printf ("%c", temp); } printf ("\n"); } // Copy rows to different array and print results /* char arrayCopy [count][20]; int ac, ad; char tempa; for (ac = 0; ac < count; ac++) { for (ad = 0; (tempa = allWords[ac][ad]) != '\0'; ad++) { arrayCopy[ac][ad] = tempa; printf("%c", arrayCopy[ac][ad]); } printf("\n"); } */ /* Step 5: Create two additional arrays: (a) One in which each element contains unique words from char array (b) One which holds the count for the corresponding word in the other array */ /* Step 6: Sort the count array in decreasing order, and print the corresponding array element as well as word count in the console */ return 0; } // Perform housekeeping tasks like freeing up memory and closing file I'm really stuck on the selection sort algorithm. I'm currently using 2D arrays to represent strings, and that worked out fine, but when it came to sorting, using three level nested loops didn't seem to work, I tried to use qsort instead, but I don't fully understand that function as well. Constructive feedback and criticism greatly welcome (...and needed)!

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• Difference between a pseudo code and algorithm?

  - by Vamsi Emani

  Technically, Is there a difference between these two words or can we use them interchangeably? Both of them more or less describe the logical sequence of steps that follow in solving a problem. ain't it? SO why do we actually use two such words if they are meant to talk of the same? Or, In case if they aren't synonymous words, What is it that differentiates them? In what contexts are we supposed to use the word pseudo code vs the word algorithm? Thanks.

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• Looking for a non-cryptographic hash function that returns a single character

  - by makerofthings7

  Suppose I have a dictionary of ASCII words stored in uppercase. I also want to save those words into separate files so that the total word count of each file is approximately the same. By simply looking at the word I need to know which file it should be in (if it's there at all). Duplicate words should go into the same file and overwrite the last one. My first attempt at solving this problem is to use .NET's object.GetHashCode() function and .Trim() to get one of the "random" characters that pop up. I asked a similar question here If I only use one character of object.GetHashCode() I would get a hash code character of A..Z or 0..9. However saving the result of GetHashCode to disk is a no-no so I need a substitute. Question: What algorithm (or subset of an algorithm) is appropriate for pigeonholing strings into a single character or range of characters (Like hex 0..F offers 16 chars)? Real world usage: I'll use this answer to modify the Partition key used in Azure Table storage as described here

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• Could multiple uses of the same word in image alt tags hurt SEO?

  - by saratogahiker

  Let's say on an e-commerce site that sells unique pens, on a particular pen's product page, the image of the pen has an alt tag of "unique red-striped pen"... and another product has "unique blue-spotted pen", etc. The key words across all products being "unique" and "pen", which would also be helpful when it comes to SEO. However, if the person just goes to the general "unique pens" category page and sees a list of thumbnail images, each with the words "unique" and "pen" in the alt tag, would that potentially have a negative impact with regards to SEO by having the words too many times?

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• How do I give a jQuery Element a fixed position on the page. In other words absolute positioning of a jQuery element.

  - by Stephanie

  <script type="text/javascript"> $(function() { $('a.StackedSystem').hover(function(e) { var html = '<div id="StackedSysteminfo">'; html += '<div id="StackedSystemTxt"> ETTER utilizes the latest technologies for our booster systems, including PLC-Based controls complete with touch-screen panel user interfaces (HMI). The base package includes the gray scale screen as shown; color screens are also available. The PLC not only provides a cleaner interface but provides additional features like automatic logging and time/date stamping of all alarms and shut-downs. Great for trouble-shooting.'; html += ''; $('body').append(html).children('#info').hide().fadeIn(400); }, function() { $('#StackedSysteminfo').remove(); }); });

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• Oracle Text query parser

  - by Roger Ford

  Oracle Text provides a rich query syntax which enables powerful text searches.However, this syntax isn't intended for use by inexperienced end-users.  If you provide a simple search box in your application, you probably want users to be able to type "Google-like" searches into the box, and have your application convert that into something that Oracle Text understands.For example if your user types "windows nt networking" then you probably want to convert this into something like"windows ACCUM nt ACCUM networking".  But beware - "NT" is a reserved word, and needs to be escaped.  So let's escape all words:"{windows} ACCUM {nt} ACCUM {networking}".  That's fine - until you start introducing wild cards. Then you must escape only non-wildcarded searches:"win% ACCUM {nt} ACCUM {networking}".  There are quite a few other "gotchas" that you might encounter along the way.Then there's the issue of scoring.  Given a query for "oracle text query syntax", it would be nice if we could score a full phrase match higher than a hit where all four words are present but not in a phrase.  And then perhaps lower than that would be a document where three of the four terms are present.  Progressive relaxation helps you with this, but you need to code the "progression" yourself in most cases.To help with this, I've developed a query parser which will take queries in Google-like syntax, and convert them into Oracle Text queries. It's designed to be as flexible as possible, and will generate either simple queries or progressive relaxation queries. The input string will typically just be a string of words, such as "oracle text query syntax" but the grammar does allow for more complex expressions:  word : score will be improved if word exists  +word : word must exist  -word : word CANNOT exist  "phrase words" : words treated as phrase (may be preceded by + or -)  field:(expression) : find expression (which allows +,- and phrase as above) within "field". So for example if I searched for   +"oracle text" query +syntax -ctxcatThen the results would have to contain the phrase "oracle text" and the word syntax. Any documents mentioning ctxcat would be excluded from the results. All the instructions are in the top of the file (see "Downloads" at the bottom of this blog entry).  Please download the file, read the instructions, then try it out by running "parser.pls" in either SQL*Plus or SQL Developer.I am also uploading a test file "test.sql". You can run this and/or modify it to run your own tests or run against your own text index. test.sql is designed to be run from SQL*Plus and may not produce useful output in SQL Developer (or it may, I haven't tried it).I'm putting the code up here for testing and comments. I don't consider it "production ready" at this point, but would welcome feedback.  I'm particularly interested in comments such as "The instructions are unclear - I couldn't figure out how to do XXX" "It didn't work in my environment" (please provide as many details as possible) "We can't use it in our application" (why not?) "It needs to support XXX feature" "It produced an invalid query output when I fed in XXXX" Downloads: parser.pls test.sql

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• Lucene .Net Searching with TermVector

  - by Ashish

  in Lucene.Net,i am creating the document for searching a word and want to display before 10 words and after 10 words.i have used TermVector. Lucene.Net.Documents.Field fldContent = new Lucene.Net.Documents.Field("content", content, Lucene.Net.Documents.Field.Store.YES, Lucene.Net.Documents.Field.Index.TOKENIZED, Lucene.Net.Documents.Field.TermVector.WITH_POSITIONS_OFFSETS); Can anyone help me how to find out the keyword position and extract nearest 15 words. please send some code. Thanks Ashish

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• crossword algorithm....

  - by teddy

  I'm making algorithm like crossword, but i dont know how to design d algorith. for example, there are words like 'car', 'apple' in the dictionary. and the 'app' words is given on the board. and there are letters like 'l' 'e' 'c' 'r'....for making words. so the algorithm work is making correct words which are stored in dictionary. app - lapp- leapp- lecapp- .... - lappe - eappc - ... - appl - apple(correct answer) what is the best solution for this algorithm?

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• Clarification on recaptcha

  - by luckytaxi

  Um so I was in for a little bit of a surprise tonight. I spent a good 20 mins trying to figure out why I was able to submit a form knowing that what I entered into the recaptcha field was invalid. Is it true that you don't need to input the exact words it displays? If it shows me two words and I misspelled one of the words, I still pass validation? Same goes if "hello world" and I input "hell man" it still works.

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• f# iterating over two arrays, using function from a c# library

  - by user343550

  I have a list of words and a list of associated part of speech tags. I want to iterate over both, simultaneously (matched index) using each indexed tuple as input to a .NET function. Is this the best way (it works, but doesn't feel natural to me): let taggingModel = SeqLabeler.loadModel(lthPath + "models\penn_00_18_split_dict.model"); let lemmatizer = new Lemmatizer(lthPath + "v_n_a.txt") let input = "the rain in spain falls on the plain" let words = Preprocessor.tokenizeSentence( input ) let tags = SeqLabeler.tagSentence( taggingModel, words ) let lemmas = Array.map2 (fun x y -> lemmatizer.lookup(x,y)) words tags

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• recaptcha still submits form when one word invalid

  - by luckytaxi

  Um so I was in for a little bit of a surprise tonight. I spent a good 20 mins trying to figure out why I was able to submit a form knowing that what I entered into the recaptcha field was invalid. Is it true that you don't need to input the exact words it displays? If it shows me two words and I misspelled one of the words, I still pass validation? Same goes if "hello world" and I input "hell man" it still works.

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• Sorting a file with 55K rows and varying Columns

  - by Prasad

  Hi I want to find a programmatic solution using C++. I have a 900 files each of 27MB size. (just to inform about the enormity ). Each file has 55K rows and Varying columns. But the header indicates the columns I want to sort the rows in an order w.r.t to a Column Value. I wrote the sorting algorithm for this (definitely my newbie attempts, you may say). This algorithm is working for few numbers, but fails for larger numbers. Here is the code for the same: basic functions I defined to use inside the main code: int getNumberOfColumns(const string& aline) { int ncols=0; istringstream ss(aline); string s1; while(ss>>s1) ncols++; return ncols; } vector<string> getWordsFromSentence(const string& aline) { vector<string>words; istringstream ss(aline); string tstr; while(ss>>tstr) words.push_back(tstr); return words; } bool findColumnName(vector<string> vs, const string& colName) { vector<string>::iterator it = find(vs.begin(), vs.end(), colName); if ( it != vs.end()) return true; else return false; } int getIndexForColumnName(vector<string> vs, const string& colName) { if ( !findColumnName(vs,colName) ) return -1; else { vector<string>::iterator it = find(vs.begin(), vs.end(), colName); return it - vs.begin(); } } ////////// I like the Recurssive functions - I tried to create a recursive function ///here. This worked for small values , say 20 rows. But for 55K - core dumps void sort2D(vector<string>vn, vector<string> &srt, int columnIndex) { vector<double> pVals; for ( int i = 0; i < vn.size(); i++) { vector<string>meancols = getWordsFromSentence(vn[i]); pVals.push_back(stringToDouble(meancols[columnIndex])); } srt.push_back(vn[max_element(pVals.begin(), pVals.end())-pVals.begin()]); if (vn.size() > 1 ) { vn.erase(vn.begin()+(max_element(pVals.begin(), pVals.end())-pVals.begin()) ); vector<string> vn2 = vn; //cout<<srt[srt.size() -1 ]<<endl; sort2D(vn2 , srt, columnIndex); } } Now the main code: for ( int i = 0; i < TissueNames.size() -1; i++) { for ( int j = i+1; j < TissueNames.size(); j++) { //string fname = path+"/gse7307_Female_rma"+TissueNames[i]+"_"+TissueNames[j]+".txt"; //string fname2 = sortpath2+"/gse7307_Female_rma"+TissueNames[i]+"_"+TissueNames[j]+"Sorted.txt"; string fname = path+"/gse7307_Male_rma"+TissueNames[i]+"_"+TissueNames[j]+".txt"; string fname2 = sortpath2+"/gse7307_Male_rma"+TissueNames[i]+"_"+TissueNames[j]+"4Columns.txt"; //vector<string>AllLinesInFile; BioInputStream fin(fname); string aline; getline(fin,aline); replace (aline.begin(), aline.end(), '"',' '); string headerline = aline; vector<string> header = getWordsFromSentence(aline); int pindex = getIndexForColumnName(header,"p-raw"); int xcindex = getIndexForColumnName(header,"xC"); int xeindex = getIndexForColumnName(header,"xE"); int prbindex = getIndexForColumnName(header,"X"); string newheaderline = "X\txC\txE\tp-raw"; BioOutputStream fsrt(fname2); fsrt<<newheaderline<<endl; int newpindex=3; while ( getline(fin, aline) ){ replace (aline.begin(), aline.end(), '"',' '); istringstream ss2(aline); string tstr; ss2>>tstr; tstr = ss2.str().substr(tstr.length()+1); vector<string> words = getWordsFromSentence(tstr); string values = words[prbindex]+"\t"+words[xcindex]+"\t"+words[xeindex]+"\t"+words[pindex]; AllLinesInFile.push_back(values); } vector<string>SortedLines; sort2D(AllLinesInFile, SortedLines,newpindex); for ( int si = 0; si < SortedLines.size(); si++) fsrt<<SortedLines[si]<<endl; cout<<"["<<i<<","<<j<<"] = "<<SortedLines.size()<<endl; } } can some one suggest me a better way of doing this? why it is failing for larger values. ? The primary function of interest for this query is Sort2D function. thanks for the time and patience. prasad.

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• treeview loses data when page is being refreshed in asp.net

  - by Greg

  Hi, I have a treeview and I written a code for his "treeNodePopulate" event: protected void ycActiveTree_TreeNodePopulate(object sender, TreeNodeEventArgs e) { if (Application["idList"] != null && e.Node.Depth == 0) { string[] words = ((String)Application["idList"]).Split(' '); // Yellow Card details TreeNode child = new TreeNode(""); // Go over all the yellow card details and populate the treeview for (int i = 1; i < words.Length; i++) { child.SelectAction = TreeNodeSelectAction.None; // Same yellow card if (words[i] != "*") { // End of details and start of point ip's if (words[i] == "$") { // Add the yellow card node TreeNode yellowCardNode = new TreeNode(child.Text); yellowCardNode.SelectAction = TreeNodeSelectAction.Expand; e.Node.ChildNodes.Add(yellowCardNode); child.Text = ""; } // yellow card details else { child.Text = child.Text + words[i] + " "; } } // End of yellow card else { child.PopulateOnDemand = false; child.SelectAction = TreeNodeSelectAction.None; // Populate the yellow card node e.Node.ChildNodes[e.Node.ChildNodes.Count - 1].ChildNodes.Add(child); TreeNode moveChild = new TreeNode("Move To Reviewed"); moveChild.PopulateOnDemand = false; moveChild.SelectAction = TreeNodeSelectAction.Select; e.Node.ChildNodes[e.Node.ChildNodes.Count - 1].ChildNodes.Add(moveChild); child = new TreeNode(""); } } Application["idList"] = null; } } I want the treenode to get the data from the Application variable and then nullify the Application variable so that the tree will take data from Applcation only if there is something in it (I put data into the application from another page and then redirect to this page) But when I refresh this page the data in the treenode isnt being saved. I mean after the refresh the Application is null so he isnt doing anything. The question is why is the data that I put in the treenode earlier isnt being saved? The "enableViewState" property is set to "true".. Thanks in advance, Greg

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• html editor properties

  - by Ranjana

  i have used the html editor to my page <%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit.HTMLEditor" TagPrefix="cc1" % i have sent the values to the database as txtjobdesc.Content.Tostring(); but if i type just a paragraph in the editor it is displaying the same Description. But if i use any Bullets and Highlighted words it is displaying as words above the bulleted words.how to make it display as a html description pls help me out..

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• Is it possible to shorten my main function in this code?

  - by AjiPorter

  Is it possible for me to shorten my main() by creating a class? If so, what part of my code would most likely be inside the class? Thanks again to those who'll answer. :) #include <iostream> #include <fstream> #include <string> #include <ctime> #include <cstdlib> #define SIZE 20 using namespace std; struct textFile { string word; struct textFile *next; }; textFile *head, *body, *tail, *temp; int main() { ifstream wordFile("WORDS.txt", ios::in); // file object constructor /* stores words in the file into an array */ string words[SIZE]; char pointer; int i; for(i = 0; i < SIZE; i++) { while(wordFile >> pointer) { if(!isalpha(pointer)) { pointer++; break; } words[i] = words[i] + pointer; } } /* stores the words in the array to a randomized linked list */ srand(time(NULL)); int index[SIZE] = {0}; // temporary array of index that will contain randomized indexes of array words int j = 0, ctr; // assigns indexes to array index while(j < SIZE) { i = rand() % SIZE; ctr = 0; for(int k = 0; k < SIZE; k++) { if(!i) break; else if(i == index[k]) { // checks if the random number has previously been stored as index ctr = 1; break; } } if(!ctr) { index[j] = i; // assigns the random number to the current index of array index j++; } } /* makes sure that there are no double zeros on the array */ ctr = 0; for(i = 0; i < SIZE; i++) { if(!index[i]) ctr++; } if(ctr > 1) { int temp[ctr-1]; for(j = 0; j < ctr-1; j++) { for(i = 0; i < SIZE; i++) { if(!index[i]) { int ctr2 = 0; for(int k = 0; k < ctr-1; k++) { if(i == temp[k]) ctr2 = 1; } if(!ctr2) temp[j] = i; } } } j = ctr - 1; while(j > 0) { i = rand() % SIZE; ctr = 0; for(int k = 0; k < SIZE; k++) { if(!i || i == index[k]) { ctr = 1; break; } } if(!ctr) { index[temp[j-1]] = i; j--; } } } head = tail = body = temp = NULL; for(j = 0; j < SIZE; j++) { body = (textFile*) malloc (sizeof(textFile)); body->word = words[index[j]]; if(head == NULL) { head = tail = body; } else { tail->next = body; tail = body; cout << tail->word << endl; } } temp = head; while(temp != NULL) { cout << temp->word << endl; temp = temp->next; } return 0; }

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