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• Validate xsl fo in xslt styleesheet

  - by Biegal

  Hi, i have a little problem with validating xml, xslt in details. I have a xslt stylesheet that, transforms xml data source to xsl:fo document. Something like this: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <xsl:template match="/"> <fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns="http://www.w3.org/1999/xhtml"> <fo:layout-master-set> <fo:simple-page-master margin-top="25mm" margin-bottom="25mm" margin-left="25mm" margin-right="25mm" page-width="210mm" page-height="297mm" master-name="simplePageLayout"> <fo:region-body region-name="xsl-region-body" column-gap="0.25in" /> <fo:region-before region-name="xsl-region-before" display-align="after" extent="0.1mm" padding-top="0pt" padding-left="0.4in" padding-right="0.4in" padding-bottom="0pt" /> <fo:region-after region-name="xsl-region-after" display-align="before" extent="0.4in" padding-top="4pt" padding-left="0.4in" padding-right="0.4in" padding-bottom="0pt" /> </fo:simple-page-master> <fo:page-sequence-master master-name="default-sequence"> <fo:repeatable-page-master-reference master-reference="simplePageLayout" /> </fo:page-sequence-master> </fo:layout-master-set> <fo:page-sequence master-reference="default-sequence"> <fo:flow flow-name="xsl-region-body"> <fo:block font-family="Segoe UI" color="#000000" font-size="9pt" /> </fo:flow> </fo:page-sequence> </fo:root> </xsl:template> What I want to do, is to validate written xsl:fo elements, ignoring xsl tags. Is it posible? For now I use dtd validation (I have xsd schema too) for validating Fo, but it give me an error on each xsl tag. Summary. Is it posiible to validate only fo elements against the schema, ignoring xsl tags, and how should I do it? Maybe a code snnippet in C#, or a hint how to modify documents? Thanks in advance!

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• Adding custom filter in spring framework problem?

  - by user298768

  hello there iam trying to make a custom AuthenticationProcessingFilter to save some user data in the session after successful login here's my filter: Code: package projects.internal; import java.io.IOException; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.security.Authentication; import org.springframework.security.ui.webapp.AuthenticationProcessingFilter; public class MyAuthenticationProcessingFilter extends AuthenticationProcessingFilter { protected void onSuccessfulAuthentication(HttpServletRequest request, HttpServletResponse response, Authentication authResult) throws IOException { super.onSuccessfulAuthentication(request, response, authResult); request.getSession().setAttribute("myValue", "My value is set"); } } and here's my security.xml file Code: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" auto-config="false" entry-point-ref="authenticationProcessingFilterEntryPoint"> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login.jsp" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login.jsp" authentication-failure-url="/p/login_error.jsp" /> <logout /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <jdbc-user-service data-source-ref="dataSource"/> </authentication-provider> </authentication-manager> <beans:bean id="authenticationProcessingFilter" class="projects.internal.MyAuthenticationProcessingFilter"> <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> </beans:bean> <beans:bean id="authenticationProcessingFilterEntryPoint" class="org.springframework.security.ui.webapp.AuthenticationProcessingFilterEntryPoint"> </beans:bean> </beans:beans> it gives an error here: Code: <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> multiple annotation found at this line:cvc-attribute.3 cvc-complex-type.4 cvc-enumeration-vaild what is the problem? thanks in advance

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• Where to put default-servlet-handler in Spring MVC configuration

  - by gigadot

  In my web.xml, the default servlet mapping, i.e. /, is mapped to Spring dispatcher. In my Spring dispatcher configuration, I have DefaultAnnotationHandlerMapping, ControllerClassNameHandlerMapping and AnnotationMethodHandlerAdapter which allows me to map url to controllers either by its class name or its @Requestmapping annotation. However, there are some static resources under the web root which I also want spring dispatcher to serve using default servlet. According to Spring documentation, this can be done using <mvc:default-servlet-handler/> tag. In the configuration below, there are 4 candidate locations that I marked which are possible to insert this tag. Inserting the tag in different location causes the dispatcher to behave differently as following : Case 1 : If I insert it at location 1, the dispatcher will no longer be able to handle mapping by the @RequestMapping and controller class name but it will be serving the static content normally. Cas 2, 3 : It will be able to handle mapping by the @RequestMapping and controller class name as well as serving the static content if other mapping cannot be done successfully. Case 4 : It will not be able to serve the static contents. Therefore, Case 2 and 3 are desirable .According to Spring documentation, this tag configures a handler which precedence order is given to lowest so why the position matters? and Which is the best position to put this tag? <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <context:annotation-config/> <context:component-scan base-package="webapp.controller"/> <!-- Location 1 --> <!-- Enable annotation-based controllers using @Controller annotations --> <bean id="annotationUrlMapping" class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <!-- Location 2 --> <bean id="controllerClassNameHandlerMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/> <!-- Location 3 --> <bean id="annotationMethodHandlerAdapter" class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <!-- Location 4 --> <mvc:default-servlet-handler/> <!-- All views are JSPs loaded from /WEB-INF/jsp --> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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• How can we define more than one table,define columns and write data in xml file ?

  - by Harikrishna

  I am writing my xml file manually. And I am writing that for storing data and retrieving data from that. I have written file like for the table PersonalInfo. <?xml version="1.0" standalone="yes"?> <PersonalInfo> <xs:schema id="PersonalInfo" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> <xs:element name="PersonalInfo" msdata:IsDataSet="true" msdata:UseCurrentLocale="true"> <xs:complexType> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="PesonalInfo."> <xs:complexType> <xs:sequence> <!--Define Column Here....--> <xs:element name="name" type="xs:string" /> <xs:element name="address" type="xs:string" /> </xs:sequence> </xs:complexType> </xs:element> </xs:choice> </xs:complexType> </xs:element> </xs:schema> <!--First Row--> <PersonalInfo.> <name>Harikrishna</name> <address>India</address> </PersonalInfo.> <!--Second Row--> <PersonalInfo.> <name>Jatin</name> <address>India</address> </PersonalInfo.> </PersonalInfo> Please suggest any mistake with writing file here. And now I want define more than table in this file. And here I have to write data for the table like <PersonalInfo.> <name>Harikrishna</name> <address>India</address> </PersonalInfo.> <PersonalInfo.> <name>Jatin</name> <address>India</address> </PersonalInfo.> Is not possible some thing writing data when defining columns EDIT : <xs:element name="name" type="xs:string",Harikrishna,Jatin.... /> <xs:element name="address" type="xs:string",India,India.... /> And how to define more than one table in a single xml file ?

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• XmlDataProvider and XPath bindings don't allow default namespace of XML data?

  - by Andy Dent

  I am struggling to work out how to use default namespaces with XmlDataProvider and XPath bindings. There's an ugly answer using local-name <Binding XPath="*[local-name()='Name']" /> but that is not acceptable to the client who wants this XAML to be highly maintainable. The fallback is to force them to use non-default namespaces in the report XML but that is an undesirable solution. The XML report file looks like the following. It will only work if I remove xmlns="http://www.acme.com/xml/schemas/report so there is no default namespace. <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type='text/xsl' href='PreviewReportImages.xsl'?> <Report xsl:schemaLocation="http://www.acme.com/xml/schemas/report BlahReport.xsd" xmlns:xsl="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.acme.com/xml/schemas/report"> <Service>Muncher</Service> <Analysis> <Date>27 Apr 2010</Date> <Time>0:09</Time> <Authoriser>Service Centre Manager</Authoriser> Which I am presenting in a window with XAML: <Window x:Class="AcmeTest.ReportPreview" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="ReportPreview" Height="300" Width="300" > <Window.Resources> <XmlDataProvider x:Key="Data"/> </Window.Resources> <StackPanel Orientation="Vertical" DataContext="{Binding Source={StaticResource Data}, XPath=Report}"> <TextBlock Text="{Binding XPath=Service}"/> </StackPanel> </Window> with code-behind used to load an XmlDocument into the XmlDataProvider (seems the only way to have loading from a file or object varying at runtime). public partial class ReportPreview : Window { private void InitXmlProvider(XmlDocument doc) { XmlDataProvider xd = (XmlDataProvider)Resources["Data"]; xd.Document = doc; } public ReportPreview(XmlDocument doc) { InitializeComponent(); InitXmlProvider(doc); } public ReportPreview(String reportPath) { InitializeComponent(); var doc = new XmlDocument(); doc.Load(reportPath); InitXmlProvider(doc); } }

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• How do I apply a servlet filter when serving an HTML page directly?

  - by Philippe Beaudoin

  First off, I'm using Google AppEngine and Guice, but I suspect my problem is not related to these. When the user connect to my (GWT) webapp, the URL is a direct html page. For example, in development mode, it is: http://127.0.0.1:8888/Puzzlebazar.html?gwt.codesvr=127.0.0.1:9997. Now, I setup my web.xml in the following way: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>PuzzleBazar</display-name> <!-- Default page to serve --> <welcome-file-list> <welcome-file>Puzzlebazar.html</welcome-file> </welcome-file-list> <filter> <filter-name>guiceFilter</filter-name> <filter-class>com.google.inject.servlet.GuiceFilter</filter-class> </filter> <filter-mapping> <filter-name>guiceFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <!-- This Guice listener hijacks all further filters and servlets. Extra filters and servlets have to be configured in your ServletModule#configureServlets() by calling serve(String).with(Class<? extends HttpServlet>) and filter(String).through(Class<? extends Filter) --> <listener> <listener-class>com.puzzlebazar.server.guice.MyGuiceServletContextListener </listener-class> </listener> </web-app> Since I'm using Guice, I have to configure extra filters in my ServletModule, where I do this: filter("*.html").through( SecurityCookieFilter.class ); But my SecurityCookieFilter.doFilter is never called. I tried things like "*.html*" or <url-pattern>*</url-pattern> but to no avail. Any idea how I should do this?

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• Noob LINQ - reading, filtering XML with XDocument

  - by user316117

  I'm just learning XDocument and LINQ queries. Here's some simple XML (which doesn't look formatted exactly right in this forum in my browser, but you get the idea . . .) <?xml version="1.0" encoding="utf-8"?> <quiz xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.com/name XMLFile2.xsd" title="MyQuiz1"> <q_a> <q_a_num>1</q_a_num> <q_>Here is question 1</q_> <_a>Here is the answer to 1</_a> </q_a> <q_a> <q_a_num>2</q_a_num> <q_>Here is question 2</q_> <_a>Here is the answer to 2</_a> </q_a> </quiz> I can iterate across all elements in my XML file and display their Name, Value, and NodeType in a ListBox like this, no problem: XDocument doc = XDocument.Load(sPath); IEnumerable<XElement> elems = doc.Descendants(); IEnumerable<XElement> elem_list = from elem in elems select elem; foreach (XElement element in elem_list) { String str0 = "Name = " + element.Name.ToString() + ", Value = " + element.Value.ToString() + ", Nodetype = " + element.NodeType.ToString(); System.Windows.Controls.Label strLabel = new System.Windows.Controls.Label(); strLabel.Content = str0; listBox1.Items.Add(strLabel); } ...but now I want to add a "where" clause to my query so that I only select elements with a certain name (e.g., "qa") but my element list comes up empty. I tried . . . IEnumerable<XElement> elem_list = from elem in elems where elem.Name.ToString() == "qa" select elem; Could someone please explain what I'm doing wrong? (and in general are there some good tips for debugging Queries?) Thanks in advance!

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• XSLT generating attributes if source-Element is in parameterfile

  - by Siegfried

  Hi, i got an xml-file with some elements. For some of these is an aqvivalent in a parameter xml-file along with some other elements. I want to add these other elements from parm-file as parameter to output file if element-names are matching. (the Attributes should only be generated if an element "InvoiceHeader" exists in the source-xml. Here is my code... <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:variable name="rpl" select="document('ParamInvoice.xml')"></xsl:variable> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates></xsl:apply-templates> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:if test="$rpl/StoraInvoice/local-name()"> <xsl:call-template name="AttributeErzeugen"> <xsl:with-param name="attr" select="$rpl/StoraInvoice/local-name()"></xsl:with-param> </xsl:call-template> </xsl:if> <xsl:apply-templates></xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template name="AttributeErzeugen"> <xsl:param name="attr"></xsl:param> <xsl:for-each select="$attr"> <xsl:attribute name="{Attibute/@name}"><xsl:value-of select="."></xsl:value- of></xsl:attribute> </xsl:for-each> </xsl:template> </xsl:stylesheet> and here the param-file <?xml version="1.0" encoding="UTF-8"?> <StoraInvoice> <InvoiceHeader> <Attribute name="Fuehrend">YYY</Attribute> <Attribute name="Feld">FFFF</Attribute> <Attribute name="Format">XYZXYZ</Attribute> </InvoiceHeader> </StoraInvoice> Siegfried

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• How do you make a Custom Data Generator for SQL XML DataType.

  - by Keith Sirmons

  Howdy, I am using Visual Studio 2010 and am playing around with the Database Projects. I am creating a DataGenerationPlan to insert data into a simple table, in which one of the column datatypes is XML. Out of the box, the generation plan uses the Regular Expression generator and generates something like this : HGcSv9wa7yM44T9x5oFT4pmBkEmv62lJ7OyAmCnL6yqXC2X.......... I am looking at creating a custom data Generator for this data type and have followed this site for the basics: http://msdn.microsoft.com/en-us/library/aa833244.aspx This example works if I am creating a string datatype and using it for a nvarchar datatype. What do I need to change to hook this Generator to the XML Datatype? Below are my code files. The string property works for nvarchar. The XElement property does not work for the xml datatype, and the RecordXMLDataGenerator is not listed as an option in the Generator column for the generation plan. CustomDataGenerators: using System; using System.Collections.Generic; using System.Linq; using System.Text; using Microsoft.Data.Schema.Tools.DataGenerator; using Microsoft.Data.Schema.Extensibility; using Microsoft.Data.Schema; using Microsoft.Data.Schema.Sql; using System.Xml.Linq; namespace CustomDataGenerators { [DatabaseSchemaProviderCompatibility(typeof(SqlDatabaseSchemaProvider))] public class RecordXMLDataGenerator : Generator { private XElement _RecordData; [Output(Description = "Generates string of XML Data for the Record.", Name = "RecordDataString")] public string RecordDataString { get { return _RecordData.ToString(SaveOptions.None); } } [Output(Description = "Generates XML Data for the Record.", Name = "RecordData")] public XElement RecordData { get { return _RecordData; } } protected override void OnGenerateNextValues() { base.OnGenerateNextValues(); XElement element = new XElement("Root", new XElement("Children1", 1), new XElement("Children6", 6) ); _RecordData = element; } } } XML Extensions File: <?xml version="1.0" encoding="utf-8" ?> <extensions assembly="" version="1" xmlns="urn:Microsoft.Data.Schema.Extensions" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="urn:Microsoft.Data.Schema.Extensions Microsoft.Data.Schema.Extensions.xsd"> <extension type="CustomDataGenerators.RecordXMLDataGenerator" assembly="CustomDataGenerators, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxx" enabled="true"/> </extensions> Table.sql: CREATE TABLE [dbo].[Record] ( id int IDENTITY (1,1) NOT NULL, recordData xml NULL, userId int NULL, test nvarchar(max) NULL, rowver rowversion NULL, CONSTRAINT pk_RecordID PRIMARY KEY (id) )

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• How to add some complex structure in multiple places in an XML file

  - by Guillaume

  I have an XML file which has many section like the one below: <Operations> <Action [some attributes ...]> [some complex content ...] </Action> <Action [some attributes ...]> [some complex content ...] </Action> </Operations> I have to add an <Action/> to every <Operations/>. It seems that an XSLT should be a good solution to this problem: <xsl:template match="Operations/Action[last()]"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> <Action>[some complex content ...]</Action> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> My problem is that the content of my <Action/> contains some xPath expressions. For example: <Action code="p_histo01"> <customScript languageCode="gel"> <gel:script xmlns:core="jelly:core" xmlns:gel="jelly:com.niku.union.gel.GELTagLibrary" xmlns:soap="jelly:com.niku.union.gel.SOAPTagLibrary" xmlns:soap-env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sql="jelly:sql" xmlns:x="jelly:xml" xmlns:xog="http://www.niku.com/xog" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <sql:param value="${gel_stepInstanceId}"/> </gel:script> </customScript> </Action> The ${gel_stepInstanceId} is interpreted by my XSLT but I would like it to be copied as-is. Is that possible? How?

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• Validating against a Schema with JAXB

  - by fwgx

  I've been looking for solutions to this problem for far too long considering how easy it sounds so I've come for some help. I have an XML Schema which I have used with xjc to create my JAXB binding. This works fine when the XML is well formed. Unfortunately it also doesn't complain when the XML is not well formed. I cannot figure out how to do proper full validation against the schema when I try to unmarshall an XML file. I have managed to use a ValidationEventCollector to handle events, which works for XML parsing errors such as mismatched tags but doesn't raise any events when there is a tag that is required but is completely absent. From what I have seen validation can be done againsta schema, but you must know the path to the schema in order to pass it into the setSchema() method. The problem I have is that the path to the schema is stored in the XML header and I can't knwo at run time where the schema is going to be. Which is why it's stored in the XML file: <?xml version="1.0" encoding="utf-8"?> <DDSSettings xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="/a/big/long/path/to/a/schema/file/DDSSettings.xsd"> <Field1>1</Field1> <Field2>-1</Field2> ...etc Every example I see uses setValidating(true), which is now deprecated, so throws an exception. This is the Java code I have so far, which seems to only do XML validation, not schema validation: try { JAXBContext jc = new JAXBContext() { private final JAXBContext jaxbContext = JAXBContext.newInstance("blah"); @Override public Unmarshaller createUnmarshaller() throws JAXBException { Unmarshaller unmarshaller = jaxbContext.createUnmarshaller(); ValidationEventCollector vec = new ValidationEventCollector() { @Override public boolean handleEvent(ValidationEvent event) throws RuntimeException { ValidationEventLocator vel = event.getLocator(); if (event.getSeverity() == event.ERROR || event.getSeverity() == event.FATAL_ERROR) { String error = "XML Validation Exception: " + event.getMessage() + " at row: " + vel.getLineNumber() + " column: " + vel.getColumnNumber(); System.out.println(error); } m_unmarshallingOk = false; return false; } }; unmarshaller.setEventHandler(vec); return unmarshaller; } @Override public Marshaller createMarshaller() throws JAXBException { throw new UnsupportedOperationException("Not supported yet."); } @Override @SuppressWarnings("deprecation") public Validator createValidator() throws JAXBException { throw new UnsupportedOperationException("Not supported yet."); } }; Unmarshaller unmarshaller = jc.createUnmarshaller(); m_ddsSettings = (com.ultra.DDSSettings)unmarshaller.unmarshal(new File(xmlfileName)); } catch (UnmarshalException ex) { Logger.getLogger(UniversalDomainParticipant.class.getName()).log( Level.SEVERE, null, ex); } catch (JAXBException ex) { Logger.getLogger(UniversalDomainParticipant.class.getName()).log( Level.SEVERE, null, ex); } So what is the proper way to do this validation? I was expecting there to be a validate() method on the JAXB generated classes, but I guess that would be too simple for Java.

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• XSLT - make xsl:analyze-string return string instead of sequence of strings?

  - by tohuwawohu

  Is it possible to make xsl:analyze-string return one string instead of a sequence of strings? Background: I'd like to use xsl:analyze-string in a xsl:function that should encapsulate the pattern matching. Ideally, the function should return an xs:string to be used as sort criteria in an xsl:sort element. At the moment, i have to apply string-join() on every result of the function call since xsl:analyze-string returns a sequence of strings, and xsl:sort doesn't accept such a sequence as sort criteria. See line 24 of the stylesheet: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="www.my-personal-namespa.ce" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:output indent="yes" method="xml" /> <xsl:function name="my:sortierung" > <xsl:param name="inputstring" as="xs:string"/> <xsl:analyze-string select="$inputstring" regex="[0-9]+"> <xsl:matching-substring> <xsl:value-of select="format-number(number(.), '00000')" /> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:value-of select="." /> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:function> <xsl:template match="/input"> <result> <xsl:apply-templates select="value" > <xsl:sort select="string-join((my:sortierung(.)), ' ')" /> </xsl:apply-templates> </result> </xsl:template> <xsl:template match="value"> <xsl:copy-of select="." /> </xsl:template> </xsl:stylesheet> with this input: <?xml version="1.0" encoding="UTF-8"?> <input> <value>A 1 b 120</value> <value>A 1 b 1</value> <value>A 1 b 2</value> <value>A 1 b 1a</value> </input> In my example, is there a way to modify the xsl:function to return a xs:string instead of a sequence?

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• Hadoop in a RESTful Java Web Application - Conflicting URI templates

  - by user1231583

  I have a small Java Web Application in which I am using Jersey 1.12 and the Hadoop 1.0.0 JAR file (hadoop-core-1.0.0.jar). When I deploy my application to my JBoss 5.0 server, the log file records the following error: SEVERE: Conflicting URI templates. The URI template / for root resource class org.apache.hadoop.hdfs.server.namenode.web.resources.NamenodeWebHdfsMethods and the URI template / transform to the same regular expression (/.*)? To make sure my code is not the problem, I have created a fresh web application that contains nothing but the Jersey and Hadoop JAR files along with a small stub. My web.xml is as follows: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <servlet> <servlet-name>ServletAdaptor</servlet-name> <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet- class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>ServletAdaptor</servlet-name> <url-pattern>/mytest/*</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app> My simple RESTful stub is as follows: import javax.ws.rs.core.Context; import javax.ws.rs.core.UriInfo; import javax.ws.rs.Path; @Path("/mytest") public class MyRest { @Context private UriInfo context; public MyRest() { } } In my regular application, when I remove the Hadoop JAR files (and the code that is using Hadoop), everything works as I would expect. The deployment is successful and the remaining RESTful services work. I have also tried the Hadoop 1.0.1 JAR files and have had the same problems with the conflicting URL template in the NamenodeWebHdfsMethods class. Any suggestions or tips in solving this problem would be greatly appreciated.

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• Ignore order of elements using xs:extension

  - by Peter Lang

  How can I design my xsd to ignore the sequence of elements? <root> <a/> <b/> </root> <root> <b/> <a/> </root> I need to use extension for code generation reasons, so I tried the following using all: <?xml version="1.0" encoding="UTF-8"?> <xs:schema targetNamespace="http://www.example.com/test" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:t="http://www.example.com/test" > <xs:complexType name="BaseType"> <xs:all> <xs:element name="a" type="xs:string" /> </xs:all> </xs:complexType> <xs:complexType name="ExtendedType"> <xs:complexContent> <xs:extension base="t:BaseType"> <xs:all> <!-- ERROR --> <xs:element name="b" type="xs:string" /> </xs:all> </xs:extension> </xs:complexContent> </xs:complexType> <xs:element name="root" type="t:ExtendedType"></xs:element> </xs:schema> This xsd is not valid though, the following error is reported at <!-- ERROR -->: cos-all-limited.1.2: An all model group must appear in a particle with {min occurs} = {max occurs} = 1, and that particle must be part of a pair which constitutes the {content type} of a complex type definition. Documentation of cos-all-limited.1.2 says: 1.2 the {term} property of a particle with {max occurs}=1 which is part of a pair which constitutes the {content type} of a complex type definition. I don't really understand this (neither xsd nor English native speaker :) ). Am I doing the wrong thing, am I doing the right thing wrong, or is there no way to achieve this? Thanks!

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• XSLT, JSTL e JSF

  - by Paulo S.

  I have a xml file which I want to transform in a jsf code page. To do that I've created a xsl file. xml: <?xml version='1.0' encoding='ISO-8859-1'?> <questionario xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='Schema2.xsd'> <componente nome='input'> <id>input1</id> </componente> <componente nome='input'> <id>input2</id> </componente> </questionario> code: <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/xml" prefix="x" %> <c:set var="xml" value="${questionarioXSLBean.xml}"/> <c:set var="xsl"> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" exclude-result-prefixes="f h"> <xsl:template match="/"> <xsl:for-each select="questionario/componente"> <xsl:if test="attribute::nome = 'input'"> <xsl:variable name="id"> <xsl:value-of select="id" /> </xsl:variable> <h:inputText id="{$id}"/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> </c:set> <x:transform xml="${xml}" xslt="${xsl}" /> The problem is that nothing is shown in my screen because the generated code for <h:inputText id="input1"/> is <h:inputText id="input_1" xmlns:h="http://java.sun.com/jsf/html"/> how can I replace the xmlns:h="http://java.sun.com/jsf/html" or suppress it. Thanks! Update: Let me clarify what I want to do. I want to generate a jsf page dynamically depending on the attributes of a xml file, for instance, 2 input texts, 3 check boxes, etc. To make the transformation to jsf I thought in two approaches, one using jstl and another using xslt. The problem with the former is that I couldn't integrate jstl with jsf code (to set jsf components attributes using jstl variables) and with the last approach, I'm facing the problem described above.I wouldn't like to create components in java (UIComponents). Any suggestions?

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• Wicket and Spring Intergation

  - by Vinothbabu

  I have a wicket contact form, and i receive the form object. Now i need to pass this object to Spring Service. package com.mysticcoders.mysticpaste.web.pages; import org.apache.wicket.markup.html.WebPage; import org.apache.wicket.markup.html.form.Form; import org.apache.wicket.markup.html.form.TextField; import org.apache.wicket.markup.html.panel.FeedbackPanel; import com.mysticcoders.mysticpaste.model.Contact; import org.apache.wicket.model.CompoundPropertyModel; import com.mysticcoders.mysticpaste.services.IContact; public class FormPage extends WebPage { private Contact contact; private IContact icontact; public FormPage() { // Add a FeedbackPanel for displaying our messages FeedbackPanel feedbackPanel = new FeedbackPanel("feedback"); add(feedbackPanel); Form<Object> form = new Form<Object>("contactForm", new CompoundPropertyModel<Object>(contact)) { private static final long serialVersionUID = 1L; protected void onSubmit(Contact contact) { icontact.saveContact(contact); } }; form.add(new TextField<Object>("name")); form.add(new TextField<Object>("email")); form.add(new TextField<Object>("country")); form.add(new TextField<Object>("age")); add(form); // add a simple text field that uses Input's 'text' property. Nothing // can go wrong here } } I am pretty much sure that we need to do something with application-context xml where i may need to wire out. My Application-context.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <bean id="WicketApplication" class="com.mysticcoders.mysticpaste.web.pages.WicketApplication" /> </beans> My Question is simple. What should i do which can make my onSubmit method call the Spring Service? Could someone let me know what needs to modified in my Application-context.xml so that once the form gets submitted, it contacts the Spring Service class.

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• How can I validate XML against an XSD with distinct imports and namespaces?

  - by Pedrolopes

  Hi there!! I am trying to validate a few XML files and I'm failing due to various issues with the XSD definition and the namespaces... This is public info, so no problem sharing data: the main XSD is at http://bioinformatics.ua.pt/euadr/euadr_types.xsd and it imports another XSD at the same location name common_types.xsd, I've validated them in W3C validator, and they passed. The XML <?xml version="1.0"?> <relationship xmlns="http://euadr.biosemantic.erasmusmc.org/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://euadr.biosemantic.erasmusmc.org/ http://bioinformatics.ua.pt/euadr/euadr_types.xsd"> <sourceId> <source>SMILE</source> <code>[S]1(=O)(=O)N(C(</code> </sourceId> <targetId> <source>UP</source> <code>P35354</code> </targetId> <creator>http://cgl.imim.es</creator> <observationDateTime>2010-05-12T19:03:40.097+02:00</observationDateTime> <informationSources> <informationSource> <relationshipType>BINDS</relationshipType> <interaction> <type>pIC50</type> <value>6.55</value> </interaction> <evidence> <type>OBSERVATIONAL</type> <value>1.0</value> </evidence> <databaseIds> <databaseId> <source>PDSP</source> <code> P35354</code> </databaseId> </databaseIds> </informationSource> </informationSources> </relationship> is straightforward and well-formed! I've tested a few online validators, and I'm getting the following error cvc-elt.1: Cannot find the declaration of element 'relationship'. Does anyone has any idea of what the problem is? Is it in the declaration of the namespaces? Of the XSD? Thanks in advance for your help! Cheers!

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• Does Hibernate create tables in the database automatically.

  - by theJava

  http://www.vaannila.com/spring/spring-hibernate-integration-1.html Upon reading this tutorial, they have not mentioned anything over creating tables in the DB. Does the Hibernate handle it automatically by creating tables and fields once i specify them. Here is my beans configuration. <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" /> <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver"/> <property name="url" value="jdbc:mysql://127.0.0.1:3306/spring"/> <property name="username" value="monwwty"/> <property name="password" value="www"/> </bean> <bean id="mySessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="myDataSource" /> <property name="annotatedClasses"> <list> <value>uk.co.vinoth.spring.domain.User</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.hbm2ddl.auto">create</prop> </props> </property> </bean> <bean id="myUserDAO" class="uk.co.vinoth.spring.dao.UserDAOImpl"> <property name="sessionFactory" ref="mySessionFactory"/> </bean> <bean name="/user/*.htm" class="uk.co.vinoth.spring.web.UserController" > <property name="userDAO" ref="myUserDAO" /> </bean> </beans>

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• How to modify my Response.Document XSD for getting author name form Sharepoint

  - by Rohan Patil

  Hi, This is my XSD currently <?xml version="1.0" encoding="Windows-1252"?> <xsd:schema xmlns:tns="urn:Microsoft.Search.Response.Document" attributeFormDefault="unqualified" elementFormDefault="qualified" targetNamespace="urn:Microsoft.Search.Response.Document" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <xsd:import namespace="urn:Microsoft.Search.Response.Document.Document" schemaLocation="Microsoft.Search.Response.Document.Document.xsd" /> <xsd:annotation> <xsd:documentation> </xsd:documentation> <xsd:documentation> Defines a Query Respnose from a Windows SharePoint Services 3.0 Query Service. </xsd:documentation> </xsd:annotation> <!-- - - - - - - - - - - - - - - - - - - - - - - - - - --> <!-- Root Element: Document --> <!-- - - - - - - - - - - - - - - - - - - - - - - - - - --> <xsd:element name="Document"> <xsd:complexType> <xsd:sequence> <xsd:element name="Title" type="xsd:string" minOccurs="0" /> <xsd:element name="Action"> <xsd:complexType> <xsd:sequence> <xsd:element name="LinkUrl"> <xsd:complexType> <xsd:simpleContent> <xsd:extension base="xsd:string"> <xsd:attribute name="size" type="xsd:unsignedByte" use="optional" /> <xsd:attribute name="fileExt" type="xsd:string" use="required" /> </xsd:extension> </xsd:simpleContent> </xsd:complexType> </xsd:element> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="Description" type="xsd:string" minOccurs="0" /> <xsd:element name="Date" type="xsd:dateTime" minOccurs="0" /> <xsd:element xmlns:q1="urn:Microsoft.Search.Response.Document.Document" ref="q1:Properties" minOccurs="0" /> </xsd:sequence> <xsd:attribute name="relevance" type="xsd:unsignedByte" use="optional" /> </xsd:complexType> </xsd:element> </xsd:schema> I want to able to get the author name.. Please help..

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• XML Schema for a .NET type that inherits and implements

  - by John Ruiz

  Hi, Please consider the following three .NET types: I have an interface, an abstract class, and a concrete class. My question is how to write the XML Schema to include the properties from the interface and from the abstract class. public interface IStartable { bool RequiresKey { get; set; } void Start(object key); } public abstract class Vehicle { uint WheelCount { get; set; } } public class Car : Vehicle, IStartable { public bool RequiresKey { get; set; } public string Make { get; set; } publilc string Model { get; set; } public Car() {} public void Start(object key) { // start car with key } } I don't know how to complete this schema: <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="cars" xmlns="cars" xmlns:c="cars"> <!-- How do I get car to have vehicle's wheelcount AND IStartable's RequiresKey? --> <xs:element name="Car" type="c:Car" /> <xs:complexType name="Car"> <xs:complexContent> <xs:extension base="c:Vehicle"> <xs:group ref=c:CarGroup" /> </xs:extension> </xs:complexContent> </xs:complexType> <xs:group name="CarGroup"> <xs:sequence> <xs:element name="Make" type="xs:token" /> <xs:element name="Model" type="xs:token" /> </xs:sequence> </xs:group> <xs:complexType name="Vehicle"> <xs:sequence> <xs:element name="WheelCount" type="xs:unsignedInt" /> </xs:sequence> </xs:complexType> <xs:complexType name="IStartable"> <xs:sequence> <xs:element name="RequiresKey" type="xs:boolean" /> </xs:sequence> </xs:complexType> </xs:schema>

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• NullPointerException using datanucleus-json with S3

  - by Matt

  I'm using datanucleus 3.2.7 from Maven, trying to use the Amazon S3 JPA provider. I can successfully write data into S3, but querying either by using "SELECT u FROM User u" or "SELECT u FROM User u WHERE id = :id" causes a NullPointerException to be thrown. Using the RDBMS provider, everything works perfectly. Is there something I'm doing wrong? Main.java EntityManagerFactory factory = Persistence.createEntityManagerFactory("MyUnit"); EntityManager entityManager = factory.createEntityManager(); Query query = entityManager.createQuery("SELECT u FROM User u", User.class); List<User> users = query.getResultList(); // Null pointer exception here for(User u:users) System.out.println(u); User.java package test; import javax.persistence.*; @Entity @Table(name = "User") public class User { @Id public String id; public String name; public User(String id, String name) { this.id = id; this.name = name; } public String toString() { return id+" : "+name; } } persistence.xml <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="MyUnit"> <class>test.User</class> <exclude-unlisted-classes /> <properties> <properties> <property name="datanucleus.ConnectionURL" value="amazons3:http://s3.amazonaws.com/" /> <property name="datanucleus.ConnectionUserName" value="xxxxx" /> <property name="datanucleus.ConnectionPassword" value="xxxxx" /> <property name="datanucleus.cloud.storage.bucket" value="my-bucket" /> </properties> <property name="datanucleus.autoCreateSchema" value="true" /> </properties> </persistence-unit> </persistence> Exception java.lang.NullPointerException at org.datanucleus.NucleusContext.isClassWithIdentityCacheable(NucleusContext.java:1840) at org.datanucleus.ExecutionContextImpl.getObjectFromLevel2Cache(ExecutionContextImpl.java:5287) at org.datanucleus.ExecutionContextImpl.getObjectFromCache(ExecutionContextImpl.java:5191) at org.datanucleus.ExecutionContextImpl.findObject(ExecutionContextImpl.java:3137) at org.datanucleus.store.json.CloudStoragePersistenceHandler.getObjectsOfCandidateType(CloudStoragePersistenceHandler.java:367) at org.datanucleus.store.json.query.JPQLQuery.performExecute(JPQLQuery.java:94) at org.datanucleus.store.query.Query.executeQuery(Query.java:1786) at org.datanucleus.store.query.Query.executeWithMap(Query.java:1690) at org.datanucleus.api.jpa.JPAQuery.getResultList(JPAQuery.java:194) at test.Main.main(Main.java:16)

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• Getting Started with Maven + Jaxb project + IntellijIdea

  - by Em Ae

  I am complete new to IntellijIdea and i am looking for some step-by-step process to set up a basic project. My project depends on Maven + Jaxb classes so i need a Maven project so that when i compile this project, the JAXB Objects are generated by Maven plugins. Now i started like this I created a blank project say MaJa project Added Maven Module to it Added following settings in POM.XML <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>MaJa</groupId> <artifactId>MaJa</artifactId> <version>1.0</version> <dependencies> <dependency> <groupId>javax.xml.bind</groupId> <artifactId>jaxb-api</artifactId> </dependency> <dependency> <groupId>com.sun.xml.bind</groupId> <artifactId>jaxb-impl</artifactId> <version>2.1</version> </dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>jaxb2-maven-plugin</artifactId> <executions> <execution> <goals> <goal>xjc</goal> </goals> </execution> </executions> <configuration> <schemaDirectory>${basedir}/src/main/resource/api/MaJa</schemaDirectory> <packageName>com.rimt.shopping.api.web.ws.v1.model</packageName> <outputDirectory>${build.directory}</outputDirectory> </configuration> </plugin> </plugins> </build> </project> First of all, is it right settings ? I tried clicking on Make/Compile 'MaJa' from Project Right Click Menu and it didn't do anything. I will be looking forward to yoru replies.

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• Maven2 not compiling source

  - by Grep

  Hi, I am new to Maven2 and have been having an issue with the compiling of the source for a RAR. Maven currently copies all the information located at my sourceDirectory instead of compiling it even though the console states that the source is being compiled. If I navigate to the sourceDirectory I find all my source files with no compiled class files. I have tried changing my outputDirectory to a different location and when I inspect this directory I find that it only copied my source files instead of compiling them. I have added an example of my POM. Any advice would be appreciated and please keep in mind I have only started learning/implementing Maven2 yesterday :) <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <artifactId>MyApp</artifactId> <groupId>.</groupId> <version>4</version> <packaging>rar</packaging> <name>MyApp rar</name> <build> <directory>target\${artifactId}-${version}</directory> <resources> <resource> <directory>..\gen-src</directory> <excludes> <exclude>util.jar</exclude> </excludes> </resource> <resource> <directory>..\domain</directory> </resource> </resources> <sourceDirectory>target\${artifactId}-${version}</sourceDirectory> <plugins> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-rar-plugin</artifactId> <configuration> <workDirectory>target\${artifactId}-${version}\classes</workDirectory> <outputDirectory>target</outputDirectory> <finalName>MyApp${version}</finalName> <raXmlFile>${workDirectory}\META-INF\ra.xml</raXmlFile> </configuration> </plugin> </plugins> </build> </project>

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• How change Castor mapping to remove "xmlns:xsi" and "xsi:type" attributes from element in XML output

  - by Derek Mahar

  How do I change the Castor mapping <?xml version="1.0"?> <!DOCTYPE mapping PUBLIC "-//EXOLAB/Castor Mapping DTD Version 1.0//EN" "http://castor.org/mapping.dtd"> <mapping> <class name="java.util.ArrayList" auto-complete="true"> <map-to xml="ArrayList" /> </class> <class name="com.db.spgit.abstrack.ws.response.UserResponse"> <map-to xml="UserResponse" /> <field name="id" type="java.lang.String"> <bind-xml name="id" node="element" /> </field> <field name="deleted" type="boolean"> <bind-xml name="deleted" node="element" /> </field> <field name="name" type="java.lang.String"> <bind-xml name="name" node="element" /> </field> <field name="typeId" type="java.lang.Integer"> <bind-xml name="typeId" node="element" /> </field> <field name="regionId" type="java.lang.Integer"> <bind-xml name="regionId" node="element" /> </field> <field name="regionName" type="java.lang.String"> <bind-xml name="regionName" node="element" /> </field> </class> </mapping> to suppress the xmlns:xsi and xsi:type attributes in the element of the XML output? For example, instead of the output XML <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="UserResponse"> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> I'd prefer <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> such that the element name implies the xsi:type.

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• using dictionaries with WebServices

  - by umit-alba

  Hi! I tried to pass a dictionary via WebServices. However it is not serializeable. So i wrote an Own Class that makes it serializeable: using System; using System.Net; using System.Windows; using System.Collections.Generic; using System.Xml.Serialization; using System.Xml; using System.Xml.Schema; namespace Platform { public class SaDictionary<TKey, TValue> : Dictionary<TKey, TValue>, IXmlSerializable { #region Constructors public SaDictionary() : base() { } public SaDictionary(IDictionary<TKey, TValue> dictionary) : base(dictionary) { } public SaDictionary(IEqualityComparer<TKey> comparer) : base(comparer) { } public SaDictionary(int capacity) : base(capacity) { } public SaDictionary(IDictionary<TKey, TValue> dictionary, IEqualityComparer<TKey> comparer) : base(dictionary, comparer) { } public SaDictionary(int capacity, IEqualityComparer<TKey> comparer) : base(capacity, comparer) { } //protected SaDictionary(SerializationInfo info, StreamingContext context) // : base(info, context) //{ //} #endregion public XmlSchema GetSchema() { return null; } public void ReadXml(XmlReader reader) { XmlSerializer keySerializer = new XmlSerializer(typeof(TKey)); XmlSerializer valueSerializer = new XmlSerializer(typeof(TValue)); bool wasEmpty = reader.IsEmptyElement; reader.Read(); if (wasEmpty) return; while (reader.NodeType != XmlNodeType.EndElement) { reader.ReadStartElement("item"); reader.ReadStartElement("key"); TKey key = (TKey)keySerializer.Deserialize(reader); reader.ReadEndElement(); //key reader.ReadStartElement("value"); TValue value = (TValue)valueSerializer.Deserialize(reader); reader.ReadEndElement(); //value this.Add(key, value); reader.ReadEndElement(); //item // reader.MoveToContent(); } reader.ReadEndElement(); } public void WriteXml(XmlWriter writer) { XmlSerializer keySerializer = new XmlSerializer(typeof(TKey)); XmlSerializer valueSerializer = new XmlSerializer(typeof(TValue)); foreach (TKey key in this.Keys) { writer.WriteStartElement("item"); writer.WriteStartElement("key"); keySerializer.Serialize(writer, key); writer.WriteEndElement(); //key writer.WriteStartElement("value"); TValue value = this[key]; valueSerializer.Serialize(writer, value); writer.WriteEndElement(); //value writer.WriteEndElement(); //item } } } } However i get an ArrayOfXElement back. Is there a way to cast it back to a Dictionary? greets

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