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  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

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  • Get current session /process id from inside a mysql query

    - by Indra Ginanjar
    I'm trying to create a table for pseudo array variable. That looks like CREATE TABLE IF NOT EXISTS `MyArray`.`ArrayTable` ( `ID` INT UNSIGNED NOT NULL COMMENT 'Hash value of SessionID + ArrayName' , `SessionID` INT UNSIGNED NOT NULL , `ArrayName` CHAR(26) NOT NULL COMMENT '32 digit char - 6 digit longest process id (assumtion)' , `Index` INT UNSIGNED NOT NULL , `Value` TEXT NOT NULL , PRIMARY KEY (`ID`, `SessionID`) ) ENGINE = MyISAM; The table is not normalized yet, 'hope this will make it a little simpler to understand :) To avoid collission between client, there should be a differentiator between client session. For that reason i think need to know current session/process id (just like "SHOW PROCESSLIST") but really need to know IN WHICH process the query are?

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  • block write access to table from an application in mysql

    - by hoberion
    Hello, We have a CMS plugin that writes statistics to 1 table, this creates performance issues on the entire platform. We decided to use another statistics plugin which can connect to a different database server (the first plugin couldn't!) however we need parts of the first plugin. I want to lock the statistics table to prevent misusage (not allowed to drop it by the developer) So I was wondering if a lock table could do this or if I can implement some sort of read only table

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  • Adding with PHP to a MySQL database

    - by shinjuo
    I am pretty new to PHP and I am trying to make an inventory database. I have been trying to make it so that a user can enter a card ID and then amount the want to add to the inventory and have it update the inventory. For example someone could type in test and 2342 and it would update test. Here is what I have been trying with no success: add.html <body> <form action="add.php" method="post"> Card ID: <input type="text" name="CardID" /> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> </body> </html> add.php <?php $link = mysql_connect('tulsadir.ipowermysql.com', 'cbouwkamp', '!starman1'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("tdm_inventory", $link); $add = $_POST[Add] mysql_query("UPDATE cardLists SET AmountLeft = '$add' WHERE cardID = 'Test'"); echo "test successful"; mysql_close($link); ?>

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  • MYSQL, Subquery Reference in Union

    - by christian
    Is there any way to reference a subquery in a union? I am trying to do something like the following, and would like to avoid a temporary table, but the subquery will be drawn from a much larger dataset so it makes sense to only do it once.. SELECT * FROM (SELECT * FROM ads WHERE state='FL' AND city='Maitland' AND page='home' ORDER BY RAND()) AS sq WHERE spot = 'full-banner' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'leaderboard' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle1' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle2' LIMIT 1 .... etc,, It's a shame that DISTINCT can't be specified for a single column of a result set.

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  • PHP, MySQL - My own version of SALT (I call salty) - Login Issue

    - by Fabio Anselmo
    Ok I wrote my own version of SALT I call it salty lol don't make fun of me.. Anyway the registration part of my script as follows is working 100% correctly. //generate SALTY my own version of SALT and I likes me salt.. lol function rand_string( $length ) { $chars = "ABCDEFGHIJKLMNOPQRSTUWXYZabcdefghijklmnopqrstuwxyz1234567890"; $size = strlen( $chars ); for( $i = 0; $i < $length; $i++ ) { $str .= $chars[ rand( 0, $size - 1 ) ]; } return $str; } $salty = rand_string( 256 ); //generate my extra salty pw $password = crypt('password'); $hash = $password . $salty; $newpass = $hash; //insert the data in the database include ('../../scripts/dbconnect.php'); //Update db record with my salty pw ;) // TESTED WITH AND WITHOUT SALTY //HENCE $password and $newpass mysql_query("UPDATE `Register` SET `Password` = '$password' WHERE `emailinput` = '$email'"); mysql_close($connect); However my LOGIN script is failing. I have it setup to TEST and echo if its login or not. It always returns FAILED. I entered the DB and changed the crypted salty pw to "TEST" and I got a SUCCESS. So my problem is somewhere in this LOGIN script I assume. Now I am not sure how to implement my $Salty in this. But also be advised that even without SALTY (just using crypt to store my pass) - I was still unable to perform a login successfully. And if you're gonna suggest i use blowfish - note that my webhost doesn't have it supported and i don't know how to install it. here's my login script: if (isset($_POST['formsubmitted'])) { include ('../../scripts/dbconnect.php'); $username = mysql_real_escape_string($_POST['username']); $password = crypt(mysql_real_escape_string($_POST['password'])); $qry = "SELECT ID FROM Register WHERE emailinput='$username' AND Password='$password'"; $result = mysql_query($qry); if(mysql_num_rows($result) > 0) { echo 'SUCCESS'; //START SESSION } else { echo 'FAILED'; //YOU ARE NOT LOGGED IN } } So what's wrong with this login? Why isn't it working just using the crypt/storing only crypt? How can i make it work storing both the crypt and randomly generated SALTY :) ? Ty advance

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  • PHP MySQL Select multiple tables

    - by Jordan Pagaduan
    Is it posibble to select 3 tables at a time in 1 database? Table 1: employee -- employee_id -- first_name -- last_name -- middle_name -- birthdate -- address -- gender -- image -- salary Table 2: logs -- log_id -- full_name -- employee_id -- date -- time -- status Table 2: logout -- log_id -- full_name -- employee_id -- date -- time -- status I wanted to get the value of employee table where $id of selected. Then the $id also get the value of log.time, log.date, logout.time, and logout.date. I already try using UNION but nothing happens.

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  • how to avoid deadlock in mysql

    - by noam
    I have the following query (all tables are innoDB) INSERT INTO busy_machines(machine) SELECT machine FROM all_machines WHERE machine NOT IN (SELECT machine FROM busy_machines) and machine_name!='Main' LIMIT 1 Which causes a deadlock when I run it in threads, obviously because of the inner select, right? The error I get is: (1213, 'Deadlock found when trying to get lock; try restarting transaction') How can I avoid the deadlock? Is there a way to change to query to make it work, or do I need to do something else?

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  • How to 'insert if not exists' in MySQL?

    - by warren
    I started by googling, and found this article which talks about mutex tables. I have a table with ~14 million records. If I want to add more data in the same format, is there a way to ensure the record I want to insert does not already exist without using a pair of queries (ie, one query to check and one to insert is the result set is empty)? Does a unique constraint on a field guarantee the insert will fail if it's already there? It seems that with merely a constraint, when I issue the insert via php, the script croaks.

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  • Fighing system in Php & MYSQL

    - by Gully
    I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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  • MySQL- complex data query in a single statement

    - by yoda
    Hi, Consider the following structure : Ignore the table user_token. Now, imagine that you need to get all the roles related to an user, wich may be through it's related groups or directly related to him. In case the same role appears related to a group and the user directly, the role related to the user will prevail over the role given by the group. Is there any chance this could be done in a single query? Cheers!

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  • how so select similarities in MySQL?

    - by mysqllearner
    Currently, I am doing a search function. Lets say in my database, I have this data: Keyword1 Keyword2 Keyword3 Keysomething Key and the user entered: "Key" as the keyword to search. This is my current query: Q1: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') Basically, I have 2 questions: How do I sort by (order by) similarity. From above example, I should have "Key" as my first result. My current result is: Keyword1, Keyword2, Keyword3, Keysomething and Key My SQL query only search by the "data_string" column, what if I want to seach others column? Do I need to do something like this: Q2: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') OR (data_other LIKE '$key%' OR data_other LIKE '%$key%' OR data_other LIKE '%$key') ... Is there any better/faster query than Q2?

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  • How do i know if a mysql table is using myISAM or InnoDB Engine

    - by kamal
    I want to confirm if the statement below is indeed true: There is no way to specify a storage engine for a certain database, only for single tables, You can, however, specify a storage engine to be used during one session with: SET storage_engine=InnoDB; so you don't have to specify it for each table. How do i confirm, if indeed all the tables are using InnoDB All the tables were using myISAM.

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • Failed to execute stored procedure from the JDBC code using mysql connection

    - by Purushotham
    Hi, I have one database. I executed a stored procedure on it. I wrote some JDBC code to connect to this database. When I am calling this stored procedure from my JDBC code it is throwing SQLException. One interesting thing I found is that I have one user other than root user. This user has all the privileges to this database where the stored procedure is present. When I use the root user I am able to call the stored procedure successfully. But with the other user I am getting SQLexception. I am not able to find why it happens like this. For sure I want this user(other than root) has to call this stored procedure successfully. Thanks in advance.

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  • MySQL "NULL" questions

    - by Camran
    I have a table with several columns. Sometimes some of these column fields may be empty (ie. I won't use them in some cases). My questions: Would it be smart to set them to NULL in phpmyadmin? What does the "NULL" property actually do? Would I gain anything at all by setting them to NULL? Is it possible to use a NULL field the same way even though it is set to null?

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  • mysql add auto increment and a additional key

    - by Lee
    Hey all I am trying to alter a table with adding a new column setting it as auto increment and with a key. The table already has one key and this one will be an addition. The error I get is the following. error : Multiple primary key defined My code is: alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY KEY FIRST; I have also tries wrapping the key name ie alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY (id) KEY FIRST; But still no luck. How can it be done ?

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  • MySQL join problem

    - by snaken
    Whats wrong with this SQL? It should return results but returns nothing SELECT `pid` FROM `products` LEFT JOIN `prods_to_features` ON (`ptf_pid` = `pid`) WHERE (`ptf_id` = '66' OR `ptf_id` = '67') AND (`ptf_id` = '76') Is it not possible to have the 2nd where clause for the table that has been used in the left join?

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