Search Results

Search found 52112 results on 2085 pages for 'name length'.

Page 190/2085 | < Previous Page | 186 187 188 189 190 191 192 193 194 195 196 197  | Next Page >

  • odd resharper indentation formatting for opject intializers

    - by bitbonk
    For some strange reason when I have nested object intializers it always gets the last '}' wrong. It is not indented at all as shown in the following example: namespace MyNameSpace { internal static class MyClass { static MyClass() { var bla = new Bla { Name = "Bla" }; bla.Blub = new Blub { Name = "Blub", Blap = new Blap { Name = "Blap", Visible = true }, Blob = new Blob { Name = "Blob" }, Blib = new Blib { Blep = new Heater { Name = "Bleb" }, Id = 1, Blap = new Blap { Name = "Blap" } } // <---- wrong !!! }; } } } Any idea what I can do against it ?

    Read the article

  • Using cascade in NHibernate

    - by Tyler
    I have two classes, call them Monkey and Banana, with a one-to-many bidirectional relationship. Monkey monkey = new Monkey(); Banana banana = new Banana(); monkey.Bananas.Add(banana); banana.Monkey = monkey; hibernateService.Save(banana); When I run that chunk of code, I want both monkey and banana to be persisted. However, it's only persisting both when I explicitly save the monkey and not vice versa. Initially, this made sense since only my Monkey.hbm.xml had a mapping with cascade="all". <set name="Bananas" inverse="true" cascade="all"> <key column="Id"/> <one-to-many class="Banana"/> </set> I figured I just needed to add the following to my Banana.hbm.xml file: <many-to-one name="Monkey" column="Id" cascade="all" /> Unfortunately, this resulted in a Parameter index is out of range error when I tried to run the snippet of code. I investigated this error and found this post, but I still don't see what I'm doing wrong. I have the relationship mapped once on each side as far as I can tell. For full disclosure, here are the two mapping files: Monkey.hbm.xml <class name="Monkey" table="monkies" lazy="true"> <id name="Id"> <generator class="increment" /> </id> <property name="Name" /> <set name="Bananas" inverse="true" cascade="all"> <key column="Id"/> <one-to-many class="Banana"/> </set> </class> Banana.hbm.xml <class name="Banana" table="bananas" lazy="true"> <id name="Id"> <generator class="increment" /> </id> <property name="Name" /> <many-to-one name="Monkey" column="Id" cascade="all" /> </class>

    Read the article

  • Problems with php:(

    - by Marin
    Please help me again! I have problems with this code: <?php $pathThemes = INC_DIR . "themes"; $d = dir($pathThemes); while (false !== ($entry = $d->read())) { $fileInfo = pathinfo($pathThemes . '/' . $entry); if ('php' == $fileInfo['extension']) { include_once($pathThemes . '/' . $entry); $name = $fileInfo['filename']; if (!$GLOBALS['fc_config']['themes'][$name]['name']) { unset($GLOBALS['fc_config']['themes'][$name]); } } } ?> It says me: Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Help me plz;(

    Read the article

  • In T-SQL how to display columns for given table name?

    - by salvationishere
    I am trying to list all of the columns from whichever Adventureworks table I choose. What T-sQL statement or stored proc can I execute to see this list of all columns? I want to use my C# web app to input one input parameter = table_name and then get a list of all the column_names as output. Right now I am trying to execute the sp_columns stored proc which works, but I can't get just the one column with select and exec combined. Does anybody know how to do this?

    Read the article

  • Multiple apks, single listing of app for Google TV and Android Phone/Tablet

    - by Yash
    I have an Android phone/tablet apk which is currently in Play store and has these settings in its manifest file: package="com.company.xyz" android:versionCode="0803010008" android:versionName="01.00.08" > <uses-sdk android:minSdkVersion="8" android:targetSdkVersion="8" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> <uses-permission android:name="android.permission.WAKE_LOCK" /> <uses-library android:name="com.adobe.flashplayer" android:required="true" /> <supports-screens android:anyDensity="true" android:largeScreens="true" android:normalScreens="true" android:smallScreens="false" android:xlargeScreens="true" /> <uses-feature android:name="android.hardware.touchscreen" android:required="true" /> I had uploaded another apk for GoogleTV which has the same package name com.company.xyz as the previous apk and has the following settings in its manifest file: package="com.company.xyz" android:versionCode="1203010001" android:versionName="01.00.01" > <uses-sdk android:minSdkVersion="12" android:targetSdkVersion="12" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> <uses-permission android:name="android.permission.WAKE_LOCK" /> <uses-feature android:name="android.hardware.touchscreen" android:required="false" /> <uses-feature android:name="com.google.android.tv" android:required="true" /> <supports-screens android:largeScreens="true"/> <uses-configuration android:reqFiveWayNav="true" /> The Google TV apk never showed up on Play Store on GTV boxes, so I updated its manifest with the settings below and with everything else remaining the same package="com.company.xyz" android:versionCode="1203010002" android:versionName="01.00.02" > <supports-screens android:largeScreens="true" android:normalScreens="false" android:smallScreens="false" android:xlargeScreens="false" /> At this point, I am unable to save the app because of the Play Store error "Error: New APK version is lower than previous APK version" even though the GoogleTV apk has a higher version code than the Phone/Tablet version. Does anyone have a solution for this? Thanks!

    Read the article

  • How does this code break the Law of Demeter?

    - by Dave Jarvis
    The following code breaks the Law of Demeter: public class Student extends Person { private Grades grades; public Student() { } /** Must never return null; throw an appropriately named exception, instead. */ private synchronized Grades getGrades() throws GradesException { if( this.grades == null ) { this.grades = createGrades(); } return this.grades; } /** Create a new instance of grades for this student. */ protected Grades createGrades() throws GradesException { // Reads the grades from the database, if needed. // return new Grades(); } /** Answers if this student was graded by a teacher with the given name. */ public boolean isTeacher( int year, String name ) throws GradesException, TeacherException { // The method only knows about Teacher instances. // return getTeacher( year ).nameEquals( name ); } private Grades getGradesForYear( int year ) throws GradesException { // The method only knows about Grades instances. // return getGrades().getForYear( year ); } private Teacher getTeacher( int year ) throws GradesException, TeacherException { // This method knows about Grades and Teacher instances. A mistake? // return getGradesForYear( year ).getTeacher(); } } public class Teacher extends Person { public Teacher() { } /** * This method will take into consideration first name, * last name, middle initial, case sensitivity, and * eventually it could answer true to wild cards and * regular expressions. */ public boolean nameEquals( String name ) { return getName().equalsIgnoreCase( name ); } /** Never returns null. */ private synchronized String getName() { if( this.name == null ) { this.name == ""; } return this.name; } } Questions How is the LoD broken? Where is the code breaking the LoD? How should the code be written to uphold the LoD?

    Read the article

  • How can I use a value from a session variable as part of the group name in signalR

    - by user1844734
    Hi I am trying to set up signalR to distribute messages to web users the problem is that the one site holds different 'areas' and also 'user types'. The Area is decided when the user visits the site by passing a url parameter, this is then stored in a session variable, The 'user type' is by default not logged in then changed when the user logs in to there user type (returned from a webservice) and stored in a User object. My aim was to connect to the hub using signalR when the user visits the site and add the users connectionId to a groupname, using the 'area id' from the session and the 'user type id' from the User object in the context. The problem I am having is that I can obtain the user id but when it comes to the area id signalR cannot access the session. I understand the reasoning behind not allowing the session available in signalR but does any one know if there is a way to enable this or an alternative way that I can gain access to the users area so that I can create these unique groups.

    Read the article

  • XSLT adding elements on the same path

    - by Stefan
    Consider the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> </catalog> I want to add elements to this XML using XSLT, to get the following result: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> <!-- NEW --> <middlename>???</middlename> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> <!-- NEW --> <comment>great one</comment> </cd> <!-- NEW --> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </catalog> To achieve that, I wrote the following XSLT: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="injectXml"> <xsl:param name="whatToInject"/> <xsl:copy> <xsl:copy-of select="node() | @*"/> <xsl:copy-of select="$whatToInject"/> </xsl:copy> </xsl:template> <xsl:template match="//catalog"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <comment>great one</comment> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]/artist"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <middlename>???</middlename> </xsl:with-param> </xsl:call-template> </xsl:template> </xsl:stylesheet> Why it's not working? How to do it?

    Read the article

  • RESTful design, how to name pages outside CRUD et al?

    - by sscirrus
    Hi all, I'm working on a site that has quite a few pages that fall outside my limited understanding of RESTful design, which is essentially: Create, Read, Update, Delete, Show, List Here's the question: what is a good system for labeling actions/routes when a page doesn't neatly fall into CRUD/show/list? Some of my pages have info about multiple tables at once. I am building a site that gives some customers a 'home base' after they log on. It does NOT give them any information about themselves so it shouldn't be, for example, /customers/show/1. It does have information about companies, but there are other pages on the site that do that differently. What do you do when you have these situations? This 'home-base' is shown to customers and it mainly has info about companies (but not uniquely so). Second case: I have a table called 'Matchings' in between customers and companies. These matchings are accessed in completely different ways on different parts of the site (different layouts, different CSS sheets, different types of users accessing them, etc. They can't ALL be matchings/show. What's the best way to label the others? Thanks very much. =)

    Read the article

  • Ant build classpath jar generates "error in opening zip file"

    - by Uberpuppy
    I have a project built in eclipse with a dependencies on 3rd party jars. I'm trying to generate a suitable build file for ant - using eclipses built-in export-ant buildfile feature as a starting block. When I run the build target I get the following error: [javac] error: error reading /base/repo/FabTrace/lib/apache/geronimo/specs/geronimo-j2ee-management_1.0_spec/1.0/geronimo-j2ee-management_1.0_spec-1.0.jar; error in opening zip file And the whole build file (auto-generated by eclipse) looks like this: (NB: the error above always references the first jar listed in the classpath) <project basedir="." default="build" name="FabTrace"> <property environment="env"/> <property name="ECLIPSE_HOME" value="/opt/apps/eclipse"/> <property name="debuglevel" value="source,lines,vars"/> <property name="target" value="1.5"/> <property name="source" value="1.5"/> <path id="JUnit 4.libraryclasspath"> <pathelement location="${ECLIPSE_HOME}/plugins/org.junit4_4.5.0.v20090824/junit.jar"/> <pathelement location="${ECLIPSE_HOME}/plugins/org.hamcrest.core_1.1.0.v20090501071000.jar"/> </path> <path id="FabTrace.classpath"> <pathelement location="bin"/> <pathelement location="lib/apache/geronimo/specs/geronimo-j2ee-management_1.0_spec/1.0/geronimo-j2ee-management_1.0_spec-1.0.jar"/> <pathelement location="lib/apache/geronimo/specs/geronimo-jms_1.1_spec/1.0/geronimo-jms_1.1_spec-1.0.jar"/> <pathelement location="lib/commons-collections/commons-collections/3.2/commons-collections-3.2.jar"/> <pathelement location="lib/commons-io/commons-io/1.4/commons-io-1.4.jar"/> <pathelement location="lib/commons-lang/commons-lang/2.1/commons-lang-2.1.jar"/> <pathelement location="lib/commons-logging/commons-logging/1.1/commons-logging-1.1.jar"/> <pathelement location="lib/commons-logging/commons-logging-api/1.1/commons-logging-api-1.1.jar"/> <pathelement location="lib/javax/activation/activation/1.1/activation-1.1.jar"/> <pathelement location="lib/javax/jms/jms/1.1/jms-1.1.jar"/> <pathelement location="lib/javax/mail/mail/1.4/mail-1.4.jar"/> <pathelement location="lib/javax/xml/bind/jaxb-api/2.1/jaxb-api-2.1.jar"/> <pathelement location="lib/javax/xml/stream/stax-api/1.0-2/stax-api-1.0-2.jar"/> <pathelement location="lib/junit/junit/4.4/junit-4.4.jar"/> <pathelement location="lib/log4j/log4j/1.2.15/log4j-1.2.15.jar"/> <pathelement location="lib/apache/camel/camel-jms-2.0-M1.jar"/> <pathelement location="lib/spring/spring-2.5.6.jar"/> <pathelement location="lib/apache/camel/camel-bundle-2.0-M1.jar"/> <pathelement location="lib/backport-util-concurrent/backport-util-concurrent-3.1.jar"/> <pathelement location="lib/commons-pool/commons-pool-1.4.jar"/> <pathelement location="lib/apache/camel/camel-activemq-1.1.0.jar"/> <pathelement location="lib/apache/activemq/activemq-camel-5.2.0.jar"/> <pathelement location="lib/jencks/jencks-2.2-all.jar"/> <pathelement location="lib/jencks/jencks-amqpool-2.2.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/activemq-all-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/xbean-spring-3.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/activemq-core-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/camel-jetty-2.2.0.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-util-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-xbean-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/activemq-optional-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/geronimo-servlet_2.5_spec-1.2.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-beans-2.5.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-context-2.5.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-core-2.5.6.jar"/> <path refid="JUnit 4.libraryclasspath"/> </path> <target name="init"> <mkdir dir="bin"/> <copy includeemptydirs="false" todir="bin"> <fileset dir="src/main/java"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> <copy includeemptydirs="false" todir="bin"> <fileset dir="src/test/java"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> <copy includeemptydirs="false" todir="bin"> <fileset dir="config"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> </target> <target name="clean"> <delete dir="bin"/> </target> <target depends="clean" name="cleanall"/> <target depends="build-subprojects,build-project" name="build"/> <target name="build-subprojects"/> <target depends="init" name="build-project"> <echo message="${ant.project.name}: ${ant.file}"/> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="src/main/java"/> <classpath refid="FabTrace.classpath"/> </javac> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="src/test/java"/> <classpath refid="FabTrace.classpath"/> </javac> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="config"/> <classpath refid="FabTrace.classpath"/> </javac> </target> </project> (I know there's eclipse specific stuff in here. But I get the same results with or without it.) I've done ye old google search and trawled around without success. I can confirm that all the jars do really exist. I've also tried from the commandline and as sudo - again, same results. Any help would be greatly appreciated. Cheers

    Read the article

  • NHibernate Mapping problem

    - by Bernard Larouche
    My database is being driven by my NHibernate mapping files. I have a Category class that looks like the following : public class Category { public Category() : this("") { } public Category(string name) { Name = name; SubCategories = new List<Category>(); Products = new HashSet<Product>(); } public virtual int ID { get; set; } public virtual string Name { get; set; } public virtual string Description { get; set; } public virtual Category Parent { get; set; } public virtual bool IsDefault { get; set; } public virtual ICollection<Category> SubCategories { get; set; } public virtual ICollection<Product> Products { get; set; } and here is my Mapping file : <property name="Name" column="Name" type="string" not-null="true"/> <property name="IsDefault" column="IsDefault" type="boolean" not-null="true" /> <property name="Description" column="Description" type="string" not-null="true" /> <many-to-one name="Parent" column="ParentID"></many-to-one> <bag name="SubCategories" inverse="true"> <key column="ParentID"></key> <one-to-many class="Category"/> </bag> <set name="Products" table="Categories_Products"> <key column="CategoryId"></key> <many-to-many column="ProductId" class="Product"></many-to-many> </set> when I try to create the database I get the following error : failed: The INSERT statement conflicted with the FOREIGN KEY SAME TABLE constraint "FK9AD976763BF05E2A". The conflict occurred in database "CoderForTraders", table "dbo.Categories", column 'CategoryId'. The statement has been terminated. I looked on the net for some answers but found none. Thanks for your help

    Read the article

  • How can I efficiently group a large list of URLs by their host name in Perl?

    - by jesper
    I have text file that contains over one million URLs. I have to process this file in order to assign URLs to groups, based on host address: { 'http://www.ex1.com' = ['http://www.ex1.com/...', 'http://www.ex1.com/...', ...], 'http://www.ex2.com' = ['http://www.ex2.com/...', 'http://www.ex2.com/...', ...] } My current basic solution takes about 600 MB of RAM to do this (size of file is about 300 MB). Could you provide some more efficient ways? My current solution simply reads line by line, extracts host address by regex and puts the url into a hash. EDIT Here is my implementation (I've cut off irrelevant things): while($line = <STDIN>) { chomp($line); $line =~ /(http:\/\/.+?)(\/|$)/i; $host = "$1"; push @{$urls{$host}}, $line; } store \%urls, 'out.hash';

    Read the article

  • Navigating to nodes using xpath in flat structure

    - by James Berry
    I have an xml file in a flat structure. We do not control the format of this xml file, just have to deal with it. I've renamed the fields because they are highly domain specific and don't really make any difference to the problem. <attribute name="Title">Book A</attribute> <attribute name="Code">1</attribute> <attribute name="Author"> <value>James Berry</value> <value>John Smith</value> </attribute> <attribute name="Title">Book B</attribute> <attribute name="Code">2</attribute> <attribute name="Title">Book C</attribute> <attribute name="Code">3</attribute> <attribute name="Author"> <value>James Berry</value> </attribute> Key things to note: the file is not particularly hierarchical. Books are delimited by an occurance of an attribute element with name='Title'. But the name='Author' attribute node is optional. Is there a simple xpath statement I can use to find the authors of book 'n'? It is easy to identify the title of book 'n', but the authors value is optional. And you can't just take the following author because in the case of book 2, this would give the author for book 3. I have written a state machine to parse this as a series of elements, but I can't help thinking there would have been a way to directly get the results that I want.

    Read the article

  • Unhandled Exception in c#

    - by nightcoder1
    Hello i am currently trying to run a web crawler through the terminal. it compiles fine and the debug does not find any errors, however i get the following error which i do not understand. any ideas on how to get rid of this error would be much appreciated Unhandled Exception: System.ArgumentOutOfRangeException: startIndex + length > this.length Parameter name: length at System.String.Substring (Int32 startIndex, Int32 length) [0x00000] at OpenWebSpiderCS.mysql.executeSQLQuery (System.String SQL) [0x00000] at OpenWebSpiderCS.db.startIndexThisSite (OpenWebSpiderCS.page p) [0x00000] at OpenWebSpiderCS.ows.startCrawling () [0x00000] at OpenWebSpiderCS.mainClass.Main (System.String[] args) [0x00000] thank you

    Read the article

  • Optimizing a Soundex Query for finding similar names

    - by xkingpin
    My application will offer a list of suggestions for English names that "sound like" a given typed name. The query will need to be optimized and return results as quick as possible. Which option would be most optimal for returning results quickly. (Or your own suggestion if you have one) A. Generate the Soundex Hash and store it in the "Names" table then do something like the following: (This saves generating the soundex hash for at least every row in my db per query right?) select name from names where NameSoundex = Soundex('Ann') B. Use the Difference function (This must generate the soundex for every name in the table?) select name from names where Difference(name, 'Ann') = 3 C. Simple comparison select name from names where Soundex(name) = Soundex('Ann') Option A seems like to me it would be the fastest to return results because it only generates the Soundex for one string then compares to an indexed column "NameSoundex" Option B should give more results than option A because the name does not have to be an exact match of the soundex, but could be slower Assuming my table could contain millions of rows, what would yield the best results?

    Read the article

  • Spaceship objects

    - by Jam
    I'm trying to make a program which creates a spaceship and I'm using the status() method to display the ship's name and fuel values. However, it doesn't seem to be working. I think I may have messed something up with the status() method. I'm also trying to make it so that I can change the fuel values, but I don't want to create a new method to do so. I think I've taken a horrible wrong turn somewhere in there. Help please! class Ship(object): def __init__(self, name="Enterprise", fuel=0): self.name=name self.fuel=fuel print "The spaceship", name, "has arrived!" def status(): print "Name: ", self.name print "Fuel level: ", self.fuel status=staticmethod(status) def main(): ship1=Ship(raw_input("What would you like to name this ship?")) fuel_level=raw_input("How much fuel does this ship have?") if fuel_level<0: self.fuel=0 else: self.fuel(fuel_level) ship2=Ship(raw_input("What would you like to name this ship?")) fuel_level2=raw_input("How much fuel does this ship have?") if fuel_level2<0: self.fuel=0 else: self.fuel(fuel_level2) ship3=Ship(raw_input("What would you like to name this ship?")) fuel_level3=raw_input("How much fuel does this ship have?") if fuel_level3<0: self.fuel=0 else: self.fuel(fuel_level3) Ship.status() main() raw_input("Press enter to exit.")

    Read the article

  • Write a sql for searching with multiple conditions

    - by Lu Lu
    Hello everyone, I have a table Student with 2 fields: Name: nvarchar(256) Age: int User will use a WinForm application to input a Name and a Age for searching. If inputted Name is empty, sql will not query Name field. If inputted Age is 0, sql will not query Age field. If Name is Null and inputted Name is empty - record is matched. If Name is Null and inputted Name is not empty - record is not matched. And also similar for Age field. My problem is that how to write a sql like this. P/S: I use SQL Server 2005. Please help me. Thanks.

    Read the article

  • How to reference a sql server with a slash (\) in its name?

    - by Bill Paetzke
    Givens: One SQL Server is named: DevServerA Another is named: DevServerB\2K5 Problem: From DevServerA, how can I write a query that references DevServerB\2K5? I tried a sample, dummy query (running it from DevServerA): SELECT TOP 1 * FROM DevServerB\2K5.master.sys.tables And I get the error: Msg 102, Level 15, State 1, Line 2 Incorrect syntax near '\.'. However, I know my syntax is almost correct, since the other way around works (running this query from DevServerB\2K5): SELECT TOP 1 * FROM DevServerA.master.sys.tables Please help me figure out how to reference DevServerB\2K5 from DevServerA. Thanks.

    Read the article

  • jQuery AutoComplete (jQuery UI 1.8rc3) with ASP.NET web service

    - by user296640
    Currently, I have this version of the autocomplete control working when returning XML from a .ashx handler. The xml looks like this: <?xml version="1.0" encoding="UTF-8" standalone="no" ?> <States> <State> <Code>CA</Code> <Name>California</Name> </State> <State> <Code>NC</Code> <Name>North Carolina</Name> </State> <State> <Code>SC</Code> <Name>South Carolina</Name> </State> The autocomplete code looks like this: $('.autocompleteTest').autocomplete( { source: function(request, response) { var list = []; $.ajax({ url: "http://commonservices.qa.kirkland.com/StateLookup.ashx", dataType: "xml", async: false, data: request, success: function(xmlResponse) { list = $("State", xmlResponse).map(function() { return { value: $("Code", this).text(), label: $("Name", this).text() }; }).get(); } }); response(list); }, focus: function(event, ui) { $('.autocompleteTest').val(ui.item.label); return false; }, select: function(event, ui) { $('.autocompleteTest').val(ui.item.label); $('.autocompleteValue').val(ui.item.value); return false; } }); For various reasons, I'd rather be calling an ASP.NET web service, but I can't get it to work. To change over to the service (I'm doing a local service to keep it simple), the start of the autocomplete code is: $('.autocompleteTest').autocomplete( { source: function(request, response) { var list = []; $.ajax({ url: "/Services/GeneralLookup.asmx/StateList", dataType: "xml", This code is on a page at the root of the site and the GeneralLookup.asmx is in a subfolder named Services. But a breakpoint in the web service never gets hit, and no autocomplete list is generated. In case it makes a difference, the XML that comes from the asmx is: <?xml version="1.0" encoding="utf-8" ?> <string xmlns="http://www.kirkland.com/"><State> <Code>CA</Code> <Name>California</Name> </State> <State> <Code>NC</Code> <Name>North Carolina</Name> </State> <State> <Code>SC</Code> <Name>South Carolina</Name> </State></string> Functionally equivalent since I never use the name of the root node in the mapping code. I haven't seen anything in the jQuery docs about calling a .asmx service from this control, but a .ajax call is a .ajax call, right? I've tried various different paths to the .asmx (~/Services/), and I've even moved the service to be in the same path to eliminate these issues. No luck with either. Any ideas?

    Read the article

  • Java constructor and modify the object properties at runtime

    - by lupin
    Note: This is an assignment Hi, I have the following class/constructor. import java.io.*; class Set { public int numberOfElements = 0; public String[] setElements = new String[5]; public int maxNumberOfElements = 5; // constructor for our Set class public Set(int numberOfE, int setE, int maxNumberOfE) { int numberOfElements = numberOfE; String[] setElements = new String[setE]; int maxNumberOfElements = maxNumberOfE; } // Helper method to shorten/remove element of array since we're using basic array instead of ArrayList or HashSet from collection interface :( static String[] removeAt(int k, String[] arr) { final int L = arr.length; String[] ret = new String[L - 1]; System.arraycopy(arr, 0, ret, 0, k); System.arraycopy(arr, k + 1, ret, k, L - k - 1); return ret; } int findElement(String element) { int retval = 0; for ( int i = 0; i < setElements.length; i++) { if ( setElements[i] != null && setElements[i].equals(element) ) { return retval = i; } retval = -1; } return retval; } void add(String newValue) { int elem = findElement(newValue); if( numberOfElements < maxNumberOfElements && elem == -1 ) { setElements[numberOfElements] = newValue; numberOfElements++; } } int getLength() { if ( setElements != null ) { return setElements.length; } else { return 0; } } String[] emptySet() { setElements = new String[0]; return setElements; } Boolean isFull() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == maxNumberOfElements ){ return True; } else { return False; } } Boolean isEmpty() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == 0 ) { return True; } else { return False; } } void remove(String newValue) { for ( int i = 0; i < setElements.length; i++) { if ( setElements[i].equals(newValue) ) { setElements = removeAt(i,setElements); } } } int isAMember(String element) { int retval = -1; for ( int i = 0; i < setElements.length; i++ ) { if (setElements[i] != null && setElements[i].equals(element)) { return retval = i; } } return retval; } void printSet() { for ( int i = 0; i < setElements.length; i++) { System.out.println("Member elements on index: "+ i +" " + setElements[i]); } } String[] getMember() { String[] tempArray = new String[setElements.length]; for ( int i = 0; i < setElements.length; i++) { if(setElements[i] != null) { tempArray[i] = setElements[i]; } } return tempArray; } Set union(Set x, Set y) { String[] newXtemparray = new String[x.getLength()]; String[] newYtemparray = new String[y.getLength()]; Set temp = new Set(1,20,20); newXtemparray = x.getMember(); newYtemparray = x.getMember(); for(int i = 0; i < newXtemparray.length; i++) { temp.add(newYtemparray[i]); } for(int j = 0; j < newYtemparray.length; j++) { temp.add(newYtemparray[j]); } return temp; } } // This is the SetDemo class that will make use of our Set class class SetDemo { public static void main(String[] args) { //get input from keyboard BufferedReader keyboard; InputStreamReader reader; String temp = ""; reader = new InputStreamReader(System.in); keyboard = new BufferedReader(reader); try { System.out.println("Enter string element to be added" ); temp = keyboard.readLine( ); System.out.println("You entered " + temp ); } catch (IOException IOerr) { System.out.println("There was an error during input"); } /* ************************************************************************** * Test cases for our new created Set class. * ************************************************************************** */ Set setA = new Set(1,10,10); setA.add(temp); setA.add("b"); setA.add("b"); setA.add("hello"); setA.add("world"); setA.add("six"); setA.add("seven"); setA.add("b"); int size = setA.getLength(); System.out.println("Set size is: " + size ); Boolean isempty = setA.isEmpty(); System.out.println("Set is empty? " + isempty ); int ismember = setA.isAMember("sixb"); System.out.println("Element six is member of setA? " + ismember ); Boolean output = setA.isFull(); System.out.println("Set is full? " + output ); setA.printSet(); int index = setA.findElement("world"); System.out.println("Element b located on index: " + index ); setA.remove("b"); setA.emptySet(); int resize = setA.getLength(); System.out.println("Set size is: " + resize ); setA.printSet(); Set setB = new Set(0,10,10); Set SetA = setA.union(setB,setA); SetA.printSet(); } } I have two question here, why I when I change the class property declaration to: class Set { public int numberOfElements; public String[] setElements; public int maxNumberOfElements; // constructor for our Set class public Set(int numberOfE, int setE, int maxNumberOfE) { int numberOfElements = numberOfE; String[] setElements = new String[setE]; int maxNumberOfElements = maxNumberOfE; } I got this error: \ javaprojects>java SetDemo Enter string element to be added a You entered a Exception in thread "main" java.lang.NullPointerException at Set.findElement(Set.java:30) at Set.add(Set.java:43) at SetDemo.main(Set.java:169) Second, on the union method, why the result of SetA.printSet still printing null, isn't it getting back the return value from union method? Thanks in advance for any explaination. lupin

    Read the article

  • XSLT generating attributes if source-Element is in parameterfile

    - by Siegfried
    Hi, i got an xml-file with some elements. For some of these is an aqvivalent in a parameter xml-file along with some other elements. I want to add these other elements from parm-file as parameter to output file if element-names are matching. (the Attributes should only be generated if an element "InvoiceHeader" exists in the source-xml. Here is my code... <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:variable name="rpl" select="document('ParamInvoice.xml')"></xsl:variable> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates></xsl:apply-templates> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:if test="$rpl/StoraInvoice/local-name()"> <xsl:call-template name="AttributeErzeugen"> <xsl:with-param name="attr" select="$rpl/StoraInvoice/local-name()"></xsl:with-param> </xsl:call-template> </xsl:if> <xsl:apply-templates></xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template name="AttributeErzeugen"> <xsl:param name="attr"></xsl:param> <xsl:for-each select="$attr"> <xsl:attribute name="{Attibute/@name}"><xsl:value-of select="."></xsl:value- of></xsl:attribute> </xsl:for-each> </xsl:template> </xsl:stylesheet> and here the param-file <?xml version="1.0" encoding="UTF-8"?> <StoraInvoice> <InvoiceHeader> <Attribute name="Fuehrend">YYY</Attribute> <Attribute name="Feld">FFFF</Attribute> <Attribute name="Format">XYZXYZ</Attribute> </InvoiceHeader> </StoraInvoice> Siegfried

    Read the article

  • what's the C# equivalent of string$ from basic

    - by Preet Sangha
    And is there an elegant linqy way to do it? What I want to do is create string of given length with made of up multiples of another string up to that length So for length - 9 and input string "xxx" I get "xxxxxxxxx" (ie length 9) for a nun integral multiple then I'd like to truncate the line. I can do this using loops and a StringBuilder easily but I'm looking to see if the language can express this idea easily. (FYI I'm making easter maths homework for my son)

    Read the article

  • Ruby Metaprogramming

    - by VP
    I'm trying to write a DSL that allows me to do Policy.name do author "Foo" reviewed_by "Bar" end The following code can almost process it: class Policy include Singleton def self.method_missing(name,&block) puts name puts "#{yield}" end def self.author(name) puts name end def self.reviewed_by(name) puts name end end Defining my method as class methods (self.method_name) i can access it using the following syntax: Policy.name do Policy.author "Foo" Policy.reviewed_by "Bar" end If i remove the "self" from the method names, and try to use my desired syntax, then i receive an error "Method not Found" in the Main so it could not find my function until the module Kernel. Its ok, i understand the error. But how can i fix it? How can i fix my class to make it work with my desired syntax that?

    Read the article

< Previous Page | 186 187 188 189 190 191 192 193 194 195 196 197  | Next Page >