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  • When Your ASP.NET MVC Custom Error Doesn't Render...

    You've put [HandleError] on your controller and you've set <customErrors mode="On"> in the web.config file. So why do you still see the yellow screen of death? I've heard various wrong explanations for this phenomena, including "it only works under IIS" and "it only works in release mode". But the custom error view does work in debug mode and it does work with the Visual Studio WebDev web server. I think the most common reason for the error view not to display is because the error view throws...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • When Your ASP.NET MVC Custom Error Doesn't Render...

    You've put [HandleError] on your controller and you've set <customErrors mode="On"> in the web.config file. So why do you still see the yellow screen of death? I've heard various wrong explanations for this phenomena, including "it only works under IIS" and "it only works in release mode". But the custom error view does work in debug mode and it does work with the Visual Studio WebDev web server. I think the most common reason for the error view not to display is because the error view throws...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Problem with Ubuntu and UEFI (Problem with any linux OS)

    - by K.T.Sumant
    I have purchased a new Sony Vaio laptop and it is said that the Windows in the recent laptops is installed in the UEFI mode. But all the Linux OS are installed in default in Legacy mode. When I reboot my laptop, Ubuntu is not being detected on boot. Only Windows is detected. To access Ubuntu, whenever I boot the system, I need to: (1) enter the boot menu, (2) change the mode to legacy, and (3) type a bit of scary commands in grub then Ubuntu successfully opens. This is a bit of problem for me. So I wanted to know the solution for this problem. So please kindly look over my problem as soon as possible.

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  • Un modèle économique sans brevets serait-il meilleur pour l'industrie informatique ? Une conférenciè

    Un modèle économique sans brevets serait-il meilleur pour l'industrie informatique ? Une conférencière donne l'exemple de la mode qui fonctionne sans copyrights L'industrie informatique a-t-elle à apprendre de l'industrie de la mode ? C'est en tous cas ce que pense une conférencière américaine. Johanna Blakely dirige une cellule de recherche de l'USC (University of Southern California) qui analyse l'impact de l'entertainment sur la société, la politique et l'industrie. En Avril, elle s'est exprimée au TED à propos des concepts de copyright, trademark, plagiat, etc. Elle explique que dans les secteurs de la mode, l'absence de copyright aide à entretenir le cycle de la création et n'affecte en rien le développement du ...

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  • No GUI after upgrading from 12.04 to 14.04.1

    - by Kalpit
    Yesterday I upgraded Ubuntu version from 12.04 to 14.04 from update manager. After upgrading it, my system got automatically restarted and now I am not able to switch to GUI mode. Its showing me command prompt mode only. I have tried ctrl + alt + f7 & sudo apt-get install Ubuntu-desktop And all but its not responding. I am newbie in Ubuntu so I don't have much idea that what's going wrong with it. How can I switch to GUI mode now.

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  • Is it wrong to use a boolean parameter to determine behavior?

    - by Ray
    I have seen a practice from time to time that "feels" wrong, but I can't quite articulate what is wrong about it. Or maybe it's just my prejudice. Here goes: A developer defines a method with a boolean as one of its parameters, and that method calls another, and so on, and eventually that boolean is used, solely to determine whether or not to take a certain action. This might be used, for example, to allow the action only if the user has certain rights, or perhaps if we are (or aren't) in test mode or batch mode or live mode, or perhaps only when the system is in a certain state. Well there is always another way to do it, whether by querying when it is time to take the action (rather than passing the parameter), or by having multiple versions of the method, or multiple implementations of the class, etc. My question isn't so much how to improve this, but rather whether or not it really is wrong (as I suspect), and if it is, what is wrong about it.

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  • Black screen in kernel 3.8 (not 3.5, 3.11, 3.13)

    - by TheDeeno
    I need to use kernel 3.8 to address some docker compatibility issues. However, after installing this kernel when I attempt to boot my machine I get a black screen. The system appears to boot to the login screen (I hear the drum sounds), but the screen remains black. If I boot into recovery mode the video works, but is buggy/slow. In recover mode it looks like it's using the vesa driver. It'd be great if I can force this in normal mode. My machine has an ivy bridge intel processor with integrated graphics What should I do next to troubleshoot this?

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  • Computer won't wake from hibernate

    - by Icoo
    So I have a pretty dumb problem...I accidentaly pressed Hibernate while trying to Restart...since then my computer wont boot into Ubuntu anymore (through normal mode or single user mode - rescue mode that is)...all I get is: mount: mounting /dev on /root/dev failed: No such file or directory mount: mounting /sys/ on root/sys failed: No such file or directory mount: mounting /proc on /root/proc failed: No such file or dirctory Target filesystem doesn't have requested /sbin/init. No init found. Try passing init= boot arg. BusyBox v1.15.3 (Ubuntu 1:1.15.3-1ubuntu5) built-in shell (ash) Enter 'help' for a list of built-in commands. (initramfs) Obviously I tried to fire up the Live CD and run fsck (or e2fsck) from there (or just try to do a Check of /dev/sdb1 my partition via gparted - which is basically the same thing). But it doesn't allow me...both gparted and fsck say that the device is busy (I can't even mount it in the LiveCD to rescue data)...umount /dev/sdb1 says its not mounted...any ideas?

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  • Hangs on Splash Screen after login (auto-login), how can I fix this?

    - by Davious
    Computer: Toshiba Terca A4 OS: Ubuntu Desktop 10.10 After installing 10.10, the splash screen hangs and the mouse pointer appears. Anyone know what I can do to fix this? ~/.xsession-errors has (nautilus:3190): GConf-CRITICAL **: gconf_value_free: assertion `value != NULL' failed btw, Safe-mode works: I do a Ctrl-Alt-F1 into a command prompt session and run ps aux | grep slave then sudo kill [id of gdm-simple-slave] That killed the session and allowed me to login in safe-mode. Safe-mode works. Then I open a terminal and run ps aux | grep nm- sudo kill -9 [id of nm-applet] nm-applet --sm-disable & to get my internet connection up.

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  • How do you ensure consistent experience across multiple graphics cards (or even driver versions)?

    - by Grigory Javadyan
    So I was writing a simple 2D game with OpenGL and SDL and had this problem when there was awful tearing when running in windowed mode (even though I explicitly asked SDL_SetVideoMode to use double buffering). Didn't worry about it all too much because most of the time the game grabs the entire screen, windowed mode is just for debugging. Anyway, yesterday I updated my nVidia drivers and tearing disappeared, the game runs smooth and looks nice in windowed mode too. I can see how the problem may be in the graphics driver, but this leads to a question. Obviously, professional game developers have to deal with a lot of different hardware/software configurations. What are the techniques they use to make sure the game looks the roughly the same on different graphics cards or even the same model of graphics card, but with different driver versions?

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  • Vista missing from grub bootlist after installing ubuntu

    - by tacomensa
    I installed Ubuntu on a logical partition a while ago. When I get to the grub bootlist, Vista is not there. What i get is this: Ubuntu, with linux 2.6.32-26 Ubuntu, with linux 2.6.32-26 (Recovery mode) Ubuntu, with linux 2.6.32-25 Ubuntu, with linux 2.6.32-26 (Recovery mode) Ubuntu, with linux 2.6.32-24 Ubuntu, with linux 2.6.32-26 (Recovery mode) Memory test (memtest86+) Windows vista (loader) (on/dev/sda1) windows recovery environment (loader) (on/dev/sda2) "Windows vista (loader)" is an acer erecovery manager Im guessing that grub installed on my primary partition so it overwrite the vista MBR and i dont have the option to boot vista. Is there some way i can just edit the MBR and add vista to it or how will i have to repair this? here is my boot script http://pastebin.com/7HZFjBT7

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  • configuring separate X screens instead of TwinView

    - by fimre
    My Sony Vaio laptop is connected to an external Samsung monitor and my nVidia driver is configured in TwinView mode. Everything is OK with this, however, I can not adjust my displays individually so at the moment my external display is a little bit darker which disturbs me a lot. I tried the Separate X Screen mode but after restart, my laptop display was white with a black x sign mouse pointer and the external display normal desktop. Is it a bug or something I missed? The idea is that using Separate X Screen mode, I could adjust my displays individually. I would really appreciate someone would guide me out of this situation. Thanx in adv..

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  • System doesn't boot due to a "[drm: drm_crtc_helper_set_config] * error * "

    - by Albin
    I have a problem with the new Ubuntu 12.10. It finished installing correctly, but when I restart my computer an error message appears: [15.854296] [drm: drm_crtc_helper_set_config] * error * failed to set mode on [CRTC: 10] * checking battery state [17.814209] [drm: drm_crtc_helper_set_config] * error * failed to set mode on [CRTC: 10] and that screen does not advance. I also tried booting from the recovery mode and it starts, but it's too slow loading windows and also shows me a window with an error message: Sorry Ubuntu 12.10 has experienced an internal error More Details: Executable path /usr/bin/xorg I have used Ubuntu since the 2008 version and never had this problem. I hope you can help me. Computer Specs: compaq sr2015la AMD sempron 2Gb. RAM 80Gb Hard Drive Translated from the original Spanish

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  • Error downloading novacom drivers &ndash; WebOS

    - by Ken
    I got sick of the Bing Maps on WebOS not being able to find “coffee” when I’m in St. Paul.  Coffe Pk, TX anyone? – no thanks.  So I finally got around to installing PreWare on my Palm Pre 2.  The WebOS Quick Install doesn’t successfully download the novacom drivers.  You can find them here: http://downloads.help.palm.com/opensource/novacom/novacom-win-32.tgz http://downloads.help.palm.com/opensource/novacom/novacom-win-64-tgz Don’t bother trying the Novacom Universal Installer either. Then put phone in developer mode (by Typing webos20090606 and switch on developer mode), attach phone in “Just Charge” mode, run WebOS Quick Install, select the globe icon, and search for PreWare, install.

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  • nVidia FX5200 Can't set resolution upper than 800x600

    - by Sebastian
    When I install nVidia drivers from terminal with this command: sudo apt-get install nvidia-current ... and I reboot, I get the max. resolution 800x600. I added new mode successfully with xrandr, but my display is 480p. My display is connected to my PC with HDMI and in Windows I was have VGA resolution on HDMI but after I installed in Ubuntu the drivers, the resolution is 480p.How to fix that? And can I change the 420p to 720p or 1080i ? Because my display have option "HDMI Full PC mode" which is good because I can see my display fully, but the Full PC mode is not supported for 480p. Ubuntu: 12.04

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  • Creating a Comment Anchor

    - by John
    Hello, The function below allows a user to insert a comment into a MySQL table called "comment." Then, the file "comments2.php" displays all comments for a given submission. Right after a user submits a comment, I would like the top of the user's browser to be anchored by the comment the user just submitted. How can I do this? Thanks in advance, John The function: function show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl) { echo '<form action="http://www...com/.../comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.stripslashes($submission).'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="checkMax" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; } The file comments2.php contains: $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); $submissionid = mysql_real_escape_string($_POST['submissionid']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented ASC LIMIT 100"; $tzFrom1 = new DateTimeZone('America/New_York'); $tzTo1 = new DateTimeZone('America/Phoenix'); $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; $count = 1; while ($row = mysql_fetch_array($result)) { $dt1 = new DateTime($row["datecommented"], $tzFrom1); $dt1->setTimezone($tzTo1); echo '<tr>'; echo '<td rowspan="3" class="commentnamecount">'.$count++.'.</td>'; echo '<td class="commentname2"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.$row["username"].'</a></td>'; echo '<td rowspan="3" class="commentname1">'.stripslashes($row["comment"]).'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2">'.$dt1->format('F j, Y').'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2a">'.$dt1->format('g:i a').'</td>'; echo '</tr>'; } echo "</table>"; The fields in the MySQL table "comment": commentid loginid submissionid comment datecommented

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  • Image displays when clicked with multiple radio button groups

    - by Jean
    I'm creating a form that has seven different selection groups, most with radio buttons (ie: buns, cheese), a couple with check boxes (toppings). I need jQuery to differentiate the groups and display images when clicked. The value can't be part of the code as I use it as part of the php form in the next page. <html> <head> <script src="js/jquery-1.6.1.min.js" type="text/javascript"></script> </head> <body> <div id="myRadioGroup"> <input type="radio" name="cars" value="American" />Yellow American<br /> <input type="radio" name="cars" value="Swiss" />Jarlsberg Swiss<br /> <input type="radio" name="cars" value="Blue" />Blue<br /> <input type="radio" name="cars" value="Cheddar" />Aged Cheddar<br /> <div id="American" class="desc"><img class="item" src="images/american-cheese-slice.png"></div> <div id="Swiss" class="desc"><img class="item" src="images/swisscheese.png"></div> <div id="Blue" class="desc"><img class="item" src="images/bluecheese.png"></div> <div id="Cheddar" class="desc"><img class="item" src="images/agedcheddar.png"></div> </div> <div id="myBunGroup"> <input type="radio" name="buns" value="Whole Wheat" />Whole Wheat<br /> <input type="radio" name="buns" value="Classic" />Classic<br /> <input type="radio" name="buns" value="Gluten Free" />Gluten Free<br /> <input type="radio" name="buns" value="Wrap" />Wrap<br /> <div id="WholeWheat" class="desc"><img class="item" src="images/wholewheat.png"></div> <div id="Classic" class="desc"><img class="item" src="images/classic.png"></div> <div id="GlutenFree" class="desc"><img class="item" src="images/gf-buns.png"></div> <div id="Wrap" class="desc"><img class="item" src="images/tortilla.png"></div> </div> <div id="myToppingGroup"> </div> <!-- http://stackoverflow.com/questions/5940963/jquery-show-and-hide-divs-based-on-radio-button-click --> <script> $(document).ready(function() { $(".item").hide(); $("input[name$="['cars', 'buns']"]").click(function() { var test = $(this).val(); $(".item").hide(); $("#" + test).show(); }); }); </script> </body> </html>

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  • Invalid assignment left hand side

    - by JoelM
    I'm getting an invalid assignment left hand side. What I'm trying to do is, to use jscolor http://jscolor.com to define the color of polygons im drawing via Mapbender http://mapbender.org. What I do: Select a polygon by clicking on it, then open the options dialog (seperate window) where I have several options including the color. MyCode: if (isTransactional) {str += "\t\t<tr>\n"; var options = ["insert", "update", "delete", "abort", "pick"]; for (var i = 0 ; i < options.length ; i++) { var onClickText = "this.disabled=true;var result = window.opener.formCorrect(document, '"+featureTypeElementFormId+"');"; onClickText += "if (result.isCorrect) {"; onClickText += "window.opener.dbGeom('"+options[i]+"', "+memberIndex+"); "; // onClickText += "window.close();"; onClickText += "}"; onClickText += "else {"; onClickText += "alert(result.errorMessage);this.disabled=false;" onClickText += "}"; if (options[i] == "insert" && hasGeometryColumn && (!fid || showSaveButtonForExistingGeometries)) { str += "\t\t\t<td><input type='button' name='saveButton' value='"+msgObj.buttonLabelSaveGeometry+"' onclick=\""+onClickText+"\" /></td>\n"; } if (!featureTypeMismatch && fid) { if (options[i] == "update" && hasGeometryColumn) { str += "\t\t\t<td><input type='button' name='updateButton' value='"+msgObj.buttonLabelUpdateGeometry+"' onclick=\""+onClickText+"\"/></td>\n"; } if (options[i] == "delete"){ var deleteOnClickText = "var deltrans = confirm('"+msgObj.messageConfirmDeleteGeomFromDb+"');"; deleteOnClickText += "if (deltrans){"; deleteOnClickText += onClickText + "}"; str += "\t\t\t<td><input type='button' name='deleteButton' value='"+msgObj.buttonLabelDeleteGeometry+"' onclick=\""+deleteOnClickText+"\"/></td>\n"; }} if (options[i] == "abort") { str += "\t\t\t<td><input type='button' name='abortButton' value='"+msgObj.buttonLabelAbort+"' onclick=\"window.close();\" /></td>\n"; } if (options[i] == "pick") { var color; str += "<td><input class='color' name='color' id='cPick' onchange="+color+"></td>"; str += "<td><input type='text' id='text' value="+color+"></td>"; //color = document.getElementById('cPick').value; //var color2 = color; //alert(color2); } }str += "\t\t</tr>\n";}str += "\t</table>\n";str += "<input type='hidden' id='fid' value='"+fid+"'>"; //str += "<input type='text' name='mb_wfs_conf'>"; str += "</form>\n";}return str;} The Application: It is a Mapbender application to display maps and draw on it. You can draw points, lines and polygons also merge and split them. You can also select the polygons that you have drawn to alter them. Using: PHP, JavaScript, HTML, CSS, Mapbender, jQuery, Geoserver, PostgreSQL, WMS, WFS-T Sorry guys, but I think I'm wasting your time. Will ask this question in GIS specified Q&A. Thank you for the input. Greetings Joël

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  • Post calls RedirectToAction but view specified in RedirectToAction is not rendered

    - by W4IK
    Here's some of the html <form id="frmSubmit" action="/Viewer" style="display:none;"> <div id="renderSubmit" class="renderReport"> <input type="hidden" name="reportYear" id="reportYear" value="" /> <input type="hidden" name="reportMonth" id="reportMonth" value="" /> <input type="hidden" name="propIds" id="propIds" value="" /> <input type="hidden" name="reportName" id="reportName" value="" /> <input type="hidden" name="reportYearFrom" id="reportYearFrom" value="" /> <input type="hidden" name="reportMonthFrom" id="reportMonthFrom" value="" /> <input type="hidden" name="reportYearTo" id="reportYearTo" value="" /> <input type="hidden" name="reportMonthTo" id="reportMonthTo" value="" /> </div> </form> a little further down the page <div id="reportList" class="renderReport"> <fieldset style="width:105%;"> <legend class="reportStepLegend">Step 3. <br /> Click a report name below to view a report</legend> <br /> <% foreach (ReportMetaData item in (ReportMetaDataContainer)ViewData.Model) { %> <div> <input id=<%=item.SSRSName%> type="button" class="reportLink" value="<%=item.DisplayName%>" /> </div> <%}%> </fieldset> </div> Here's the javascript that gets called when the button is clicked $('.reportLink').click(function() { if (CheckDateAndProps() === true) { $('#reportName').val(this.id); var formData = $("#frmSubmit").serializeArray(); $.post('Home/PostViewer/', formData); } }); Note...i did have the $.post like so earlier...but it didn't seem to make any difference $.post('Home/PostViewer/', formData, function(data) { alert(data.Result); }, "json"); Here's the controller code [AcceptVerbs(HttpVerbs.Post)] public ActionResult PostViewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return RedirectToAction("Viewer"); } All is good in the world up to this point..I'm hitting the above method and all the values are populated. Here's the get ActionResult method [AcceptVerbs(HttpVerbs.Get)] public ActionResult Viewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return View(); } I'm hitting this too...not seeing any values in the parameters...but that's just because I haven't passed them in yet...I don't think that's whats keeping the Viewer page from displaying.? Now...one would one expect the Viewer view to be rendered...right?...well all I see is the page that this was called from...it never displays the Viewer page???!!?!? Here's the routes from global.asax routes.MapRoute( "Viewer", // Route name "Home/Viewer", // URL with parameters new { controller = "Home", action = "Viewer" } // Parameter defaults ); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); I can browse directly to the page http://localhost:50083/Home/Viewer and when I do so I hit the get ActionResult method and the page renders just fine. Any help is greatly appreciated!

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  • validate() > show field after radiobutton selection

    - by RihanU
    hi im saw this jquery script: http://jquery.bassistance.de/validate/demo/ and i want also the posibility to show a field when a button is checked but not with a checkbox. but with two radiobuttons. if radiobutton1 is checked, display field1 and if radiobutton2 is checked display field 2 what do i have to change..? <script type="text/javascript"> $().ready(function() { //code to hide topic selection, disable for demo var foo = $("#foo"); // foo topics are optional, hide first var inital = foo.is(":checked"); var topics = $("#blaat")[inital ? "removeClass" : "addClass"]("gray"); var topicInputs = topics.find("input").attr("disabled", !inital); // show when foo is checked foo.click(function() { topics[this.checked ? "removeClass" : "addClass"]("gray"); topicInputs.attr("disabled", !this.checked); }); }); </script> <form class="cmxform" id="signupForm" method="get" action=""> <fieldset> <p> <label for="foo">De checkbox dus veranderen naar 2 radio buttons</label> <input type="checkbox" class="checkbox" id="foo" name="foo" /> <!-- <input type="radio" value="ding" class="checkbox" id="foo" name="foo" /> <input type="radio" value="dong" class="checkbox" id="foo" name="foo" /> --> </p> <!-- Fieldset 1 --> <fieldset id="blaat"> <label for="topic_marketflash"> <input type="checkbox" id="topic_marketflash" value="marketflash" name="topic" /> Marketflash </label> <label for="topic_fuzz"> <input type="checkbox" id="topic_fuzz" value="fuzz" name="topic" /> Latest fuzz </label> <label for="topic_digester"> <input type="checkbox" id="topic_digester" value="digester" name="topic" /> Mailing list digester </label> </fieldset> <!-- --> <!-- Fieldset 2 --> <fieldset id="andere"> <label for="topic_marketflash"> <input type="checkbox" id="topic_marketflash" value="marketflash" name="topic" /> Voor </label> <label for="topic_fuzz"> <input type="checkbox" id="topic_fuzz" value="fuzz" name="topic" /> Beelden </label> </fieldset> <!-- --> </fieldset> </form>

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  • Javascript: Dynamic Check box (Fieldset with Father/Child Checkboxes)

    - by BoDiE2003
    I have a problem here, when I select any of the 'father' checkboxes all the child checkboxes are getting enabled or disabled. So I need each father checkbox to affect it own child fieldset. Could someone help me with this. Thank you <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <title>toggle disabled</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <style type="text/css"> .cssDisabled { color: #ccc; } </style> <script src="http://prototypejs.org/assets/2009/8/31/prototype.js" type="text/javascript"> </script> <script type="text/javascript"> Event.observe(window, 'load', function(){ // for all items in the group_first class $$('.father').each(function(chk1){ // watch for clicks chk1.observe('click', function(evt){ dynamicCheckbox(); }); dynamicCheckbox(); }); }); function dynamicCheckbox (){ // count how many of group_first are checked, // doEnable true if any are checked var doEnable = ($$('.father:checked').length > 0) ? true : false; // for each in group_second, enable the checkbox, and // remove the cssDisabled class from the parent label $$('.child').each(function(item){ if (doEnable) { item.enable().up('label').removeClassName('cssDisabled'); } else { item.disable().up('label').addClassName('cssDisabled'); } }); }; </script> </head> <body> <fieldset> <legend>First Group</legend> <label><input type="checkbox" value="1" class="father" />Check box 1</label><br /> <label><input type="checkbox" value="2" class="father" checked/>Check box 2</label> </fieldset> <fieldset> <legend>Second Group</legend> <label class="cssDisabled"><input type="checkbox" value="x" class="child" disabled="disabled" />Check box x</label><br /> <label class="cssDisabled"><input type="checkbox" value="y" class="child" disabled="disabled" />Check box y</label><br /> <label class="cssDisabled"><input type="checkbox" value="z" class="child" disabled="disabled" />Check box z</label> </fieldset> <fieldset> <legend>First Group</legend> <label><input type="checkbox" value="3" class="father" />Check box 1</label><br /> </fieldset> <fieldset> <legend>Second Group</legend> <label class="cssDisabled"><input type="checkbox" value="x" class="child" disabled="disabled" />Check box x</label><br /> <label class="cssDisabled"><input type="checkbox" value="y" class="child" disabled="disabled" />Check box y</label><br /> <label class="cssDisabled"><input type="checkbox" value="z" class="child" disabled="disabled" />Check box z</label> </fieldset> </body> </html>

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  • Using label tags in a validation summary error list?

    - by patridge
    I was thinking about making use of <label> tags in my validation error summary on a failed form submit and I can't figure out if it is going to get me in trouble down the line. Can anyone think of a good reason to avoid this approach? Usability, functionality, design, or other issues are all helpful. I really like the idea of clicking a line item in the error list and being jumped to the offending input element, especially in a mobile HTML scenario where vertical orientation is more common and scrolling is a pain. So far the only problem I can find is that labels don't navigate for radio buttons or checkboxes without individual IDs (Clicking a label for a single ID-tagged radio/checkbox element alters its selection). It doesn't make it any worse than no label, though. Here is a stripped down HTML test sample of this idea (CSS omitted for simplicity). <div class="validation-errors"> <p>There was a problem saving your form.</p> <ul> <li><label for="select1">Select 1 is invalid.</label></li> <li><label for="text1">Text 1 is invalid.</label></li> <li><label for="textarea1">TextArea 1 is invalid.</label></li> <li><label for="radio1">Radio 1 is invalid.</label></li> <li><label for="checkbox1">Checkbox 1 is invalid.</label></li> </ul> </div> <form action="/somewhere"> <fieldset><legend>Some Form</legend> <ol> <li><label for="select1">select1</label> <select id="select1" name="select1"> <option value="value1">Value 1</option> <option value="value2">Value 2</option> <option selected="selected" value="value3">Value 3</option> </select></li> <li><label for="text1">text1</label> <input id="text1" name="text1" type="text" value="sometext" /></li> <li><label for="textarea1">textarea1</label> <textarea id="textarea1" name="textarea1" rows="5" cols="25">sometext</textarea></li> <li><ul> <li><label><input type="radio" name="radio1" value="value1" />Value 1</label></li> <li><label><input type="radio" name="radio1" value="value2" checked="checked" />Value 2</label></li> <li><label><input type="radio" name="radio1" value="value3" />Value 3</label></li> </ul></li> <li><ul> <li><label><input type="checkbox" name="checkbox1" value="value1" checked="checked" />Value 1</label></li> <li><label><input type="checkbox" name="checkbox1" value="value2" />Value 2</label></li> <li><label><input type="checkbox" name="checkbox1" value="value3" checked="checked" />Value 3</label></li> </ul></li> <li><input type="submit" value="Save &amp; Continue" /></li> </ol> </fieldset> </form> The only thing I have added to make the click-capable behavior more obvious is to add a CSS rule for the labels. .validation-errors label { text-decoration: underline; cursor: pointer; }

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  • Best way to add an extra (nested) form in the middle of a tabbed form

    - by Scharrels
    I've got a web application, consisting mainly of a big form with information. The form is split into multiple tabs, to make it more readable for the user: <form> <div id="tabs"> <ul> <li><a href="#tab1">Tab1</a></li> <li><a href="#tab2">Tab2</a></li> </ul> <div id="tab1">A big table with a lot of input rows</div> <div id="tab2">A big table with a lot of input rows</div> </div> </form> The form is dynamically extended (extra rows are added to the tables). Every 10 seconds the form is serialized and synchronized with the server. I now want to add an interactive form on one of the tabs: when a user enters a name in a field, this information is sent to the server and an id associated with that name is returned. This id is used as an identifier for some dynamically added form fields. A quick sketchup of such a page would look like this: <form action="bigform.php"> <div id="tabs"> <ul> <li><a href="#tab1">Tab1</a></li> <li><a href="#tab2">Tab2</a></li> </ul> <div id="tab1">A big table with a lot of input rows</div> <div id="tab2"> <div class="associatedinfo"> <p>Information for Joe</p> <ul> <li><input name="associated[26][]" /></li> <li><input name="associated[26][]" /></li> </ul> </div> <div class="associatedinfo"> <p>Information for Jill</p> <ul> <li><input name="associated[12][]" /></li> <li><input name="associated[12][]" /></li> </ul> </div> <div id="newperson"> <form action="newform.php"> <p>Add another person:</p> <input name="extra" /><input type="submit" value="Add" /> </form> </div> </div> </div> </form> The above will not work: nested forms are not allowed in HTML. However, I really need to display the form on that tab: it's part of the functionality of that page. I also want the behaviour of a separate form: when the user hits return in the form field, the "Add" submit button is pressed and a submit action is triggered on the partial form. What is the best way to solve this problem?

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  • I want to use blur function instead mouseup function

    - by yossi
    I have the Demo Table which I can click on the cell(td tag) and I can change the value on it.direct php DataBase. to do that I need to contain two tags.1 - span. 2 - input. like the below. <td class='Name'> <span id="spanName1" class="text" style="display: inline;"> Somevalue </span> <input type="text" value="Somevalue" class="edittd" id="inputName1" style="display: none; "> </td> to control on the data inside the cell I use in jquery .mouseup function. mouseup work but also make truble. I need to replace it with blur function but when I try to replace mouseup with blur the program thas not work becose, when I click on the cell I able to enter the input tag and I can change the value but I can't Successful to Leave the tag/field by clicking out side the table, which alow me to update the DataBase you can see that Demo with blur Here. what you advice me to do? $(".edittd").mouseup(function() { return false; }); //************* $(document).mouseup(function() { $('#span' + COLUME + ROW).show(); $('#input'+ COLUME + ROW ).hide(); VAL = $("#input" + COLUME + ROW).val(); $("#span" + COLUME + ROW).html(VAL); if(STATUS != VAL){ //******ajax code //dataString = $.trim(this.value); $.ajax({ type: "POST", dataType: 'html', url: "./public/php/ajax.php", data: 'COLUME='+COLUME+'&ROW='+ROW+'&VAL='+VAL, //{"dataString": dataString} cache: false, success: function(data) { $("#statuS").html(data); } }); //******end ajax $('#statuS').removeClass('statuSnoChange') .addClass('statuSChange'); $('#statuS').html('THERE IS CHANGE'); $('#tables').load('TableEdit2.php'); } else { //alert(DATASTRING+'status not true'); } });//End mouseup function I change it to: $(document).ready(function() { var COLUMES,COLUME,VALUE,VAL,ROWS,ROW,STATUS,DATASTRING; $('td').click(function() { COLUME = $(this).attr('class'); }); //**************** $('tr').click(function() { ROW = $(this).attr('id'); $('#display_Colume_Raw').html(COLUME+ROW); $('#span' + COLUME + ROW).hide(); $('#input'+ COLUME + ROW ).show(); STATUS = $("#input" + COLUME + ROW).val(); }); //******************** $(document).blur(function() { $('#span' + COLUME + ROW).show(); $('#input'+ COLUME + ROW ).hide(); VAL = $("#input" + COLUME + ROW).val(); $("#span" + COLUME + ROW).html(VAL); if(STATUS != VAL){ //******ajax code //dataString = $.trim(this.value); $.ajax({ type: "POST", dataType: 'html', url: "./public/php/ajax.php", data: 'COLUME='+COLUME+'&ROW='+ROW+'&VAL='+VAL, //{"dataString": dataString} cache: false, success: function(data) { $("#statuS").html(data); } }); //******end ajax $('#statuS').removeClass('statuSnoChange') .addClass('statuSChange'); $('#statuS').html('THERE IS CHANGE'); $('#tables').load('TableEdit2.php'); } else { //alert(DATASTRING+'status not true'); } });//End mouseup function $('#save').click (function(){ var input1,input2,input3,input4=""; input1 = $('#input1').attr('value'); input2 = $('#input2').attr('value'); input3 = $('#input3').attr('value'); input4 = $('#input4').attr('value'); $.ajax({ type: "POST", url: "./public/php/ajax.php", data: "input1="+ input1 +"&input2="+ input2 +"&input3="+ input3 +"&input4="+ input4, success: function(data){ $("#statuS").html(data); $('#tbl').hide(function(){$('div.success').fadeIn();}); $('#tables').load('TableEdit2.php'); } }); }); }); Thx

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  • Problem with Json in Jquery

    - by Davidslv
    Hi everyone, I have a small survey, but when i submit it says that the msg is null, i don't see where is my error. If you could help me i apreciate it. Thank you My Form with Jquery and Ajax Function <!DOCTYPE HTML> <hmtl lang="pt-PT"> <head> <title>Formul&aacute;rio</title> <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script> </head> <body> <hr /> <h3>Formulario</h3> <script type="text/javascript" charset="utf-8"> $(function () { $('#submiter').click( function() { $.ajax({ type: "POST", url: 'validar.php', dataType: 'json', success: function(msg) { alert('Mensagem '+ msg.mensagem); }, error : function () { alert('Ocorreu um erro'); } }); }); }); </script> <form id="formulario" action="" method="post" accept-charset="utf-8"> <p>Pergunta 1</p> <label for="pergunta1">sim</label><input type="radio" id="p1" name="pergunta1" value="1" /><br /> <label for="pergunta1">n&atilde;o</label><input type="radio" id="p1" name="pergunta1" value="0" /> <br /> <p>Pergunta 2</p> <label for="pergunta2">sim</label><input type="radio" name="pergunta2" value="0" /><br /> <label for="pergunta2">n&atilde;o</label><input type="radio" name="pergunta2" value="1" /> <br /> <p>Pergunta 3</p> <label for="pergunta3">sim</label><input type="radio" name="pergunta3" value="0" /><br /> <label for="pergunta3">n&atilde;o</label><input type="radio" name="pergunta3" value="1" /> <br /> <p>Pergunta 4</p> <label for="pergunta4">sim</label><input type="radio" name="pergunta4" value="0" /><br /> <label for="pergunta4">n&atilde;o</label><input type="radio" name="pergunta4" value="1" /> <br /> <p><input type="submit" id="submiter" value="Continue &rarr;"></p> </form> </body> </html> My PHP <?php if($_POST) { $pergunta1 = $_POST['pergunta1']; $pergunta2 = $_POST['pergunta2']; $pergunta3 = $_POST['pergunta3']; $pergunta4 = $_POST['pergunta4']; $calcular = $pergunta1 + $pergunta2 + $pergunta3 + $pergunta4; $var = array ('mensagem' => $calcular); echo json_encode($var); } else { $var2 = array('mensagem' => 'sem resultado'); echo json_encode($var2); } ?>

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