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• Fighing system in Php & MYSQL

  - by Gully

  I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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• mysql left join

  - by user1019538

  I have two table one is index and another is the price structure as under table : index : column : trandate ,indexcode Table : price : Column: trandate,symbol,price i want to know the missing price. I issue the query select i.trandate,i.indexcode,p.trandate,p.price from index i left join price p on i.trandate = p.trandate where p.symbol='ABC' and indexcode="New" the above query does not show the null date even though various price in missing in price table. Only reason i understand is that the index table does not have the symbol field that's why...but as per theory if you want to show all the rows of one table and only the match value of another table then use the left or right join query...please anybody can help

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• In PHP + MySQL, How do I join many tables with conditions

  - by Moe

  Hi, I'm trying to get the users full activity throughout the website. I need to Join many tables throughout the database, with that condition that it is one user. What I currently have written is: SELECT * FROM comments AS c JOIN rphotos AS r ON c.userID = r.userID AND c.userID = '$defineUserID'; But What it is returning is everything about the user, but it repeats rows. For instance, for one user he has 6 photos and 5 comments So I expect the join to return 11 rows. Instead it returns 30 results like so: PhotoID = 1; CommentID = 1; PhotoID = 1; CommentID = 2; PhotoID = 1; CommentID = 3; and so on... What am i doing wrong?

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• mysql inserts & updates optimized

  - by user271619

  This is an optimization question, mostly. I have many forms on my sites that do simple Inserts and Updates. (Nothing complicated) But, several of the form's input fields are not necessary and may be left empty. (again, nothing complicated) However, my SQL query will have all columns in the Statement. My question, is it best to optimize the Inserts/Update queries appropriately? And only apply the columns that are changed into the query? We all hear that we shouldn't use the "SELECT *" query, unless it's absolutely needed for displaying all columns. But what about Inserts & Updates? Hope this makes sense. I'm sure any amount of optimization is acceptable. But I never really hear about this, specifically, from anyone.

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• Character encoding issues in MySQL

  - by Eric

  In my database we have fields where the data is not readable. I now know why it happened but I don't know how to fix it. I found a way to get the info back from the database: SELECT id, name FROM projects WHERE LENGTH(name) != CHAR_LENGTH(name); One of the rows returned shows: id | name ------------------------- 1008 | Cajón el Diablo This should be: id | name ------------------------- 1008 | Cajón el Diablo Can somebody help me figure out how to fix this problem? How can I convert this using SQL? Is SQL not good? If not, how about Python?

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• Help with MySQL database structure - user notification system

  - by Simon

  Hi, I'd like to send global notifications to my users (1000+ users) and allow them to close the notification box once they have read the message. Basically I may send one notification per week globally ie/ each user get the same message and they are not personal in nature. What is the best way to achieve this? Create 2 tables: **tb_messages** message_id massage_title message_content **tb_read_messages** user_id message_id is-read That way i can just show each user the current notifications that are not read? select * from tb_read_messages WHERE user_id = $user_id AND is-read = no OR is there a more efficient way? Thanks!!!

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• how to get needed data from mysql tables

  - by I Like PHP

  i have 3 tables tbl_faculty(f_id,f_school) tbl_school(s_id,s_city_s_role) tbl_city(c_id,c_name) in one school there may be many teacher(s_role=2) can be appointed, but would be appointed only one principle(s_role=1) first we need to create a school, then we appoint faculty. now i want to appoint principle( where teachers may b already appointed or may b not) so i need all school_id and city name where there is no principle appointed yet references in tables f_school--->s_id s_city---->c_id i used below query but, it show not the exact result i want SELECT s_id,c_name FROM tbl_school LEFT JOIN tbl_city ON c_id=s_city LEFT JOIN tbl_faculty ON f_school=s_id WHERE s_role<>1";

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• MySQL Join Comma Separated Field

  - by neeraj

  I have two tables. First Table is a batch table that contain comma separated student id in field "batch" batch -------------- id batch -------------- 1 1,2 2 3,4 Second Table is marks marks ---------------------- id studentid subject marks 1 1 English 50 2 2 English 40 3 3 English 70 4 1 Math 65 5 4 English 66 6 5 English 75 7 2 Math 55 How we can find those students of first batch id =1 who have scored more than 45 marks in English without using sub query. Problem i found to get this done using a single query is that we can not use IN as an association operator in JOIN statement What changes are required in below query to make it work? SELECT * FROM batch INNER JOIN marks ON marks.studentid IN(batch.batch) where batch.id = 1

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• MySQL range date overlap check

  - by Glide

  This table is used to store sessions CREATE TABLE session ( id int(11) NOT NULL AUTO_INCREMENT , start_date date , end_date date ); INSERT INTO session (start_date, end_date) VALUES ("2010-01-01", "2010-01-10") , ("2010-01-20", "2010-01-30") , ("2010-02-01", "2010-02-15") ; We don't want to have conflict between ranges Let's say we need to insert a new session from 2010-01-05 to 2010-01-25 We would like to know the conflicting session(s). Here is my query: SELECT * FROM session WHERE TRUE AND ("2010-01-05" BETWEEN start_date AND end_date OR "2010-01-25" BETWEEN start_date AND end_date OR "2010-01-05" >= start_date AND "2010-01-25" <= end_date ) ; Here is the result: +----+------------+------------+ | id | start_date | end_date | +----+------------+------------+ | 1 | 2010-01-01 | 2010-01-10 | | 2 | 2010-01-20 | 2010-01-30 | +----+------------+------------+ Is there a better practice way to get that ?

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• Find MySQL entries with same set of column B values for their common column A value

  - by nnsd44g

  I have: +----+------+------+ | id | A | B | +----+------+------+ | 1 | 1 | 1 | < | 2 | 1 | 2 | < | 3 | 2 | 2 | | 4 | 2 | 3 | | 5 | 3 | 1 | < | 6 | 3 | 2 | < | 7 | 4 | 4 | | 8 | 4 | 5 | +----+------+------+ I need to select the entries that have the same set of B values for their common A value. So, in this case, I need ids 1, 2 and 5, 6 because in those cases the sequence of B values is 1, 2. Is this possible? Thanks!

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• MySQL COUNT() multiple columns

  - by liam

  Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

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• php array into mysql

  - by mckenzie

  Hello, $sql_where = ''; $exclude = '30,35,36,122,123,124,125'; if($exclude != '') { $exclude_forums = explode(',', $exclude); foreach ($exclude_forums as $id) { if ($id > 0) { $sql_where = ' AND forum_id <> ' . trim($id); } } } $sql = 'SELECT topic_title, forum_id, topic_id, topic_type, topic_last_poster_id, topic_last_poster_name, topic_last_poster_colour, topic_last_post_time FROM ' . TOPICS_TABLE . ' WHERE topic_status <> 2 AND topic_approved = 1 ' . $sql_where . ' ORDER BY topic_time DESC'; The above code i use to exclude the id of forum to be displayed on sql queries. Why doesn't it work and still display it? Any solution

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• MySQL: Selecting One Record When Others Have Same Data

  - by LoganFrederick

  I have a table of cities that all share the same area code: 367 01451 Harvard Worcester Massachusetts MA 978 Eastern 368 01452 Hubbardston Worcester Massachusetts MA 978 Eastern 369 01453 Leominster Worcester Massachusetts MA 978 Eastern The table has multiple area codes, all with multiple cities. What I'd like to do is only select one city from each area code and delete any extra cities from duplicate area codes. What would be the best query to accomplish this? I believe: http://stackoverflow.com/questions/596629/mysql4-sql-for-selecting-one-or-zero-record Is coming close to what I need but didn't quite get what/how those answers were working. Note The "978" row is the "area_code" row, table name is "zip_code".

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• MySQL LEFT JOIN, GROUP BY and ORDER BY not working as required

  - by Simon

  I have a table 'products' => ('product_id', 'name', 'description') and a table 'product_price' => ('product_price_id', 'product_id', 'price', 'date_updated') I want to perform a query something like SELECT `p`.*, `pp`.`price` FROM `products` `p` LEFT JOIN `product_price` `pp` ON `pp`.`product_id` = `p`.`product_id` GROUP BY `p`.`product_id` ORDER BY `pp`.`date_updated` DESC As you can probably guess the price changes often and I need to pull out the latest one. The trouble is I cannot work out how to order the LEFT JOINed table. I tried using some of the GROUP BY functions like MAX() but that would only pull out the column not the row. Thanks.

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• An array of MySQL results...

  - by Michael Falk

  What am I doing wrong here? I am attempting to return a json object and I can't seem to get past the array... I've built hundreds of regular array and returned them as a json object but I am having a hard time wrapping my head around this one. $rows = array(); $post_array = array(); $i = 0; $result = mysql_query(" SELECT * FROM forum_posts WHERE permalink = '$permalink' AND LOWER(raw_text) LIKE '%$str%' " ); while($row = mysql_fetch_assoc($result)) { $post_array[$i] = $rows[ "id" => htmlentities($row["id"]), "post_content" => htmlentities($row["content"]), "author" => $row["author"], "last_updated" => $row["last_updated"], "author_id" => $row["author_id"], "editing_author" => $row["editing_author"], "date" => $outputQuoteDate ]; $i++; }

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• Preventing entire JOINed MYSQL query from failing when one field is missing within a WHERE clause

  - by filip o

  I am doing a couple of joins with a variable in the WHERE clause. I'm not sure if I am doing everything as efficiently as I could, or even using the best practices but my issue is that half my tables have data for when tableC.type=500, and the other half don't resulting in the entire query failing. SELECT tableA.value1 , tableB.value2, tableC.value3 FROM tableA JOIN tableB ON tableB.id=tableA.id JOIN tableC ON tableC.id=tableB.id WHERE tableA.category=$var && tableC.type=500; What I would like to happen is to still get tableA.value1 and tableB.value2 even if there is no field in tableC with a type=500. any thoughts? i'm totally stumped as how to approach this...

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• How can I update a field in a MySQL database table by addition in MySQL database in a single query

  - by undefined

  I have a table that stores a value that will be added to over time. When I want to add to the value I would like to do so in a single query rather than - Get oldValue from database newValue = oldValue + X update row with newValue $query1 = "SELECT value FROM table WHERE id = thisID"; $result1 = mysql_query($query1); while($row=mysql_fetch_array($result)) { $oldValue = $row['value']; } $newValue = $oldValue + x $query1 = "UPDATE table SET value = $newValue WHERE id = thisID"; Can this be done in a single query?

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• getting rid of repeated customer id's in mysql query

  - by bsandrabr

  I originally started by selecting customers from a group of customers and then for each customer querying the records for the past few days and presenting them in a table row. All working fine but I think I might have got too ambitious as I tried to pull in all the records at once having heard that mutiple queries are a big no no. here is the mysqlquery i came up with to pull in all the records at once SELECT morning, afternoon, date, date2, fname, lname, customers.customerid FROM customers LEFT OUTER JOIN attend ON ( customers.customerid = attend.customerid ) RIGHT OUTER JOIN noattend ON ( noattend.date2 = attend.date ) WHERE noattend.date2 BETWEEN '$date2' AND '$date3' AND DayOfWeek( date2 ) %7 >1 AND group ={$_GET['group']} ORDER BY lname ASC , fname ASC , date2 DESC tables are customer-customerid,fname,lname attend-customerid,morning,afternoon,date noattend-date2 (a table of all the days to fill in the blanks) Now the problem I have is how to start a new row in the table when the customer id changes My query above pulls in customer 1 morning 2 customer 1 morning 1 customer 2 morning 2 customer 2 morning 1 whereas I'm trying to get customer1 morning2 morning1 customer2 morning2 morning1 I dont know whether this is possible in the sql or more likely in the php

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• Average of a Sum in Mysql query

  - by chupeman

  I am having some problems creating a query that gives me the average of a sum. I read a few examples here in stackoverflow and couldn't do it. Can anyone help me to understand how to do this please? This is the data I have: Basically I need the average transaction value by cashier. I can't run a basic avg because it will take all rows but each transaction can have multiple rows. At the end I want to have: Cashier| Average| 131 | 44.31 |(Which comes from the sum divided by 3 transactions not 5 rows) 130 | 33.15 | etc. This is the query I have to SUM the transactions but don't know how or where to include the AVG function. SELECT `products`.`Transaction_x0020_Number`, Sum(`products`.`Sales_x0020_Value`) AS `SUM of Sales_x0020_Value`, `products`.`Cashier` FROM `products` GROUP BY `products`.`Transaction_x0020_Number`, `products`.`Date`, `products`.`Cashier` HAVING (`products`.`Date` ={d'2010-06-04'}) Any help is appreciated.

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• How to display mysql records as preselected checkboxes?

  - by Jennifer

  I have a table column called post_tags within a table called posts where assigned tags are stored separated by the @ symbol. I also have a table called tags where all tag names are stored. I would like to design my database in a more normalized way but for the purpose I am trying to achieve this is the easiest option. Anyway, I want to display on the screen all the entries from the tags table as checkboxes, so I do: $query = mysql_query("SELECT * FROM tags ORDER BY name"); while ($row = mysql_fetch_assoc($query)) { $tag = $row['name']; echo "<input type='checkbox' name='tags[]' value='$tag' />\n"; } Next I want to have the tags that are assigned to a particular post be preselected. For example, if I have a post with the following in it's post_tags column: party@beaches@dolphins@ I want the "party", "beaches" and "dolphin" checkboxes to be checked by default (while the checkboxes for the other options are unchecked). How can this be done?

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• Retrieving specific tuples using Mysql

  - by Narayanan

  Hi, I have some problems retrieving specific tuples. I am actually a student trying to build a Room management system. I have two tables: Room(roomID,hotelname,rate) and Reservation(resID,arriveDate,departDate,roomID). I am not sure how to retrieve the rooms that are available between 2 specific dates. This was the query that i used. SELECT Room.roomID,hotelname,rate FROM Room LEFT JOIN Reservation on ( Room.roomID=Reservation.resID and arriveDate >='2010-02-16' and departDate <='2010-02-20' ) GROUP BY roomID,hotelname,rate HAVING count(*)=0;' but it returns an empty set. Can any1 be kind enough to tell me what mistake i am doing??

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• MySQL customized join query using multiple tables

  - by itgeek

  I am searching one student from each class from one group. There are different class groups and every group has different classes and every class has multiple students. See below: Group1 --> Class1, Class2 etc Class1 --> GreenStudent1, GreenStudent2 etc Class2 --> RedStudent1, RedStudent2 etc ------------------------------------------------------ SELECT table1.id, table1.myname, table1.marks table2.studentid, table2.studentname FROM table1 INNER JOIN table3 ON table1.oldid = table3.id INNER JOIN table2 ON table2.studentid = table3.newid WHERE table1.classgroup = 'SCI79' GROUP BY table1.oldid ORDER BY table1.marks DESC There are different joins applied in the query. Above mentioned query giving me correct results but I need little modification in it. Current query returning me one student from each class. What I need? I need one student from each class but only that student who has MAXIMUM table1.marks So I should have one student from each class who has maximum number in their relevant classes. Can anyone suggest some solution or rewrite this query? Thanks :)

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• MySQL Limiting a query to one consistent value

  - by Lucas Matos

  My current query returns a table like: +------------+ value1 | .... value1 | .... value2 | .... value3 | .... +------------+ I want: +------------+ value1 | .... value1 | .... +------------+ I want to only receive all rows with the first value. Normally I would do a WHERE clause if I knew that value, and I cannot use a LIMIT because each value has a different number of rows. Right now My query looks like "SELECT u.*, n.something, w.* FROM ... AS u, ... AS n, ... AS w WHERE u.id = n.id AND w.val = n.val AND u.desc LIKE '%GET REQUEST VARIABLE%';" This works great, except I get way too many rows and using PHP to do this ruins code portability and is superfluous. Thanks for reading

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• mysql to xls sheet genration problemI(getting html code along with records ,unable get column names)

  - by pmms

  <?php if($_POST['Submit']=='Generatexml') { $tblname=$_GET['genratexml']; //mysql_connect("localhost","root",""); //mysql_select_db("hitnrunf_db"); global $obj_mysql; $result = mysql_query("SELECT * FROM tbl_js_login"); while($row = mysql_fetch_array($result)) { $csv_output .= "$row[fld_id],$row[fld_fname],$row[fld_lname]"; $csv_output .="\015\012"; } header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv; filename= Student_Data_". date("Y-m-d") . ".csv"); print $csv_output; exit; } include_once $path."includes/jobseeker_form.php"; ?> In the above we are getting html code along wtih id, firstname, lastname columns. we are unable to get the heading of the columns also How to remove Html code from xls file also need to get headers

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• Help with MySQL and CASE WHEN with a range of values

  - by kickdaddy

  I have an accounts table and a records table where accounts have multiple records. I would like to break down the account totals by "count of records" range. i.e. show the breakdown of Count of Records | Count 0-25 | 100 25 - 50 | 122 50 - 100 | 300 etc. I am using the following query, but I can't get it to group by "grp" which is what I want, any help on the best way to modify query? Thanks! SELECT count(*) as ct, CASE WHEN COUNT(*) < 25 THEN '1-25' WHEN COUNT(*) >= 25 < 50 THEN '25-50' WHEN COUNT(*) >= 50 < 100 THEN '50-100' WHEN COUNT(*) >= 100 < 250 THEN '100-250' WHEN COUNT(*) >= 250 < 500 THEN '250-500' WHEN COUNT(*) >= 500 < 1000 THEN '500-1000' ELSE '1000+' END AS grp FROM records r,accounts a WHERE r.account_id=a.id ORDER BY ct

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