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  • http_post_data basic authentication?

    - by kristian nissen
    I have a remote service that I need to access, according to the documentation it's restricted using basic authentication and all requests have to be posted (HTTP POST). The documentation contains this code example - VB script: Private Function SendRequest(ByVal Url, ByVal Username, ByVal Password, ByVal Request) Dim XmlHttp Set XmlHttp = CreateObject("MSXML2.XmlHttp") XmlHttp.Open "POST", Url, False, Username, Password XmlHttp.SetRequestHeader "Content-Type", "text/xml" XmlHttp.Send Request Set SendRequest = XmlHttp End Function how can I accomplish this in PHP? When I post data to the remote server it replies: 401 Unauthorized Access which is fine because I'm not posting my user/pass just the data. Bu when I add my user/pass as it's describe here: http://dk.php.net/manual/en/http.request.options.php like this: $res = http_post_data('https://example.com', $data, array( 'Content-Type: "text/xml"', 'httpauth' => base64_encode('user:pass'), 'httpauthtype' => HTTP_AUTH_BASIC ) ); the protocol is https - I get a runtime error in return (it's a .Net service). I have tried it without the base64_encode but with the same result.

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  • Ios Parse Login

    - by user3806600
    I am programming an IOS app that will use parse to login a user. Using storyboard I have the login button connected to another view controller with the push segue. Whether the username and password are correct the button selection always goes to the new view controller. I might be doing this all wrong. Any help is appreciated. Here is my code: - (IBAction)signIn:(id)sender { [PFUser logInWithUsernameInBackground:self.emailField.text password:self.passwordField.text block:^(PFUser *user, NSError *error) { if (!error) { [self performSegueWithIdentifier:@"signIn" sender:nil]; } else { // The login failed. Check error to see why. } }]; }

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  • Inserting the record into Data Base through JPA

    - by vinay123
    In my code I am using JSF - Front end , EJB-Middile Tier and JPA connect to DB.Calling the EJB using the Webservices.Using MySQL as DAtabase. I have created the Voter table in which I need to insert the record. I ma passing the values from the JSF to EJB, it is working.I have created JPA controller class (which automatcally generates the persistence code based on the data base classes) Ex: getting the entity manager etc., em = getEntityManager(); em.getTransaction().begin(); em.persist(voter); em.getTransaction().commit(); I have created the named query also: @NamedQuery(name = "Voter.insertRecord", query = "INSERT INTO Voter v values v.voterID = :voterID,v.password = :password,v.partSSN = :partSSN,v.address = :address, v.zipCode = :zipCode,v.ssn = :ssn, v.vFirstName = :vFirstName,v.vLastName = :vLastName,v.dob = :dob"),But still not able to insert the record? Can anyone help me in inserting the record into the Data base through JPA.(Persistence object)?

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  • Authenticating wcf service

    - by Muhammad Jamal Shaikh
    hi , i want to implement a web service which is both in java and .net.but i will first create a wcf service and later convert the code to java . for securing the webservice , i have this in my mind. i shall be implementing asp.net form authentication type of stuff . i intent to sent a token to the client on providing valid userID and password to the login method. in return i would send a token. on all other service operations i shall check the token . Now i have a wcf client and a wcf service . what should be the shortest way forward ?should i use soap auth header to send the user ID and password and how should the token be transported ( in which field ? http or soap's ?) . P.S: of course i shall enable ssl later.

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  • Creating keystore for jarsigner programmatically

    - by skayred
    I'm trying to generate keystore with certificate to use it with JarSigner. Here is my code: System.out.println("Keystore generation..."); Security.addProvider(new BouncyCastleProvider()); String domainName = "example.org"; KeyPairGenerator keyGen = KeyPairGenerator.getInstance("RSA"); SecureRandom random = SecureRandom.getInstance("SHA1PRNG", "SUN"); keyGen.initialize(1024, random); KeyPair pair = keyGen.generateKeyPair(); X509V3CertificateGenerator v3CertGen = new X509V3CertificateGenerator(); int serial = new SecureRandom().nextInt(); v3CertGen.setSerialNumber(BigInteger.valueOf(serial < 0 ? -1 * serial : serial)); v3CertGen.setIssuerDN(new X509Principal("CN=" + domainName + ", OU=None, O=None L=None, C=None")); v3CertGen.setNotBefore(new Date(System.currentTimeMillis() - 1000L * 60 * 60 * 24 * 30)); v3CertGen.setNotAfter(new Date(System.currentTimeMillis() + (1000L * 60 * 60 * 24 * 365*10))); v3CertGen.setSubjectDN(new X509Principal("CN=" + domainName + ", OU=None, O=None L=None, C=None")); v3CertGen.setPublicKey(pair.getPublic()); v3CertGen.setSignatureAlgorithm("MD5WithRSAEncryption"); X509Certificate PKCertificate = v3CertGen.generateX509Certificate(pair.getPrivate()); FileOutputStream fos = new FileOutputStream("/Users/dmitrysavchenko/testCert.cert"); fos.write(PKCertificate.getEncoded()); fos.close(); KeyStore ks = KeyStore.getInstance(KeyStore.getDefaultType()); char[] password = "123".toCharArray(); ks.load(null, password); ks.setCertificateEntry("hive", PKCertificate); fos = new FileOutputStream("/Users/dmitrysavchenko/hive-keystore.pkcs12"); ks.store(fos, password); fos.close(); It works, but when I'm trying to sign my JAR with this keystore, I get the following error: jarsigner: Certificate chain not found for: hive. hive must reference a valid KeyStore key entry containing a private key and corresponding public key certificate chain. I've discovered that there must be a private key, but I don't know how to add it to certificate. Can you help me?

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  • Disable everything in windows except program c#

    - by rubentjeuh
    Hello, I've got the following question: Is it possible te disable everything in windows except the program it's running? I need to program an application on a touchscreen (fullscreen), where people can fill in a survey. The only thing they should use is this program. (for protection of the survey anwsers and other secret stuff :p ) And the program should be closed when entering the right password. So how can I disable everything else but the program I'm running? Thanks

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  • Why can't Perl's WWW::Machanize find the form by field names?

    - by FRESHTER
    #!/usr/bin/perl use WWW::Mechanize; use Compress::Zlib; my $mech = WWW::Mechanize->new(); my $username = ""; #fill in username here my $keyword = ""; #fill in password here my $mobile = $ARGV[0]; my $text = $ARGV[1]; $deb = 1; print length($text)."\n" if($deb); $text = $text."\n\n\n\n\n" if(length($text) < 135); $mech->get("http://wwwl.way2sms.com/content/index.html"); unless($mech->success()) { exit; } $dest = $mech->response->content; print "Fetching...\n" if($deb); if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $dest =~ s/<form name="loginForm"/<form action='..\/auth.cl' name="loginForm"/g; $mech->update_html($dest); $mech->form_with_fields(("username","password")); $mech->field("username",$username); $mech->field("password",$keyword); print "Loggin...\n" if($deb); $mech->submit_form(); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $mech->get("http://wwwl.way2sms.com//jsp/InstantSMS.jsp?val=0"); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } print "Sending ... \n" if($deb); $mech->form_with_fields(("MobNo","textArea")); $mech->field("MobNo",$mobile); $mech->field("textArea",$text); $mech->submit_form(); if($mech->success()) { print "Done \n" if($deb); } else { print "Failed \n" if($deb); exit; } $dest = $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); #print $dest if($deb); } if($dest =~ m/successfully/sig) { print "Message sent successfully" if($deb); } exit; When run this code halts with an error saying: There is no form with the requested fields at ./sms.pl line 65 Can't call method "value" on an undefined value at /usr/share/perl5/vendor_perl/WWW/Mechanize.pm line 1348.

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  • Can access maven repository from behind proxy, need help.

    - by Digambar Daund
    I am trying to access maven repository from behind proxy. I configured settings.xml correctly (i guess so...) true http username password 12.34.56.78 8080 But still I am error message like... if i dont configure userid/password gets correct error message which is HTTP response code 407 - saying authentication required. But If I configure correct/incorrect proxy authentication it always prints below error message.... Downloading: http://repo1.maven.org/maven2/org/apache/maven/plugins/maven-clean-plugin/2.2/maven-clean-plugin-2.2.pom [WARNING] Unable to get resource 'org.apache.maven.plugins:maven-clean-plugin:pom:2.2' from repository central (http://repo1.maven.org/maven2): Error trans ferring file: Server redirected too many times (20) Downloading: http://repo1.maven.org/maven2/org/apache/maven/plugins/maven-clean-plugin/2.2/maven-clean-plugin-2.2.pom [WARNING] Unable to get resource 'org.apache.maven.plugins:maven-clean-plugin:pom:2.2' from repository central (http://repo1.maven.org/maven2): Error trans ferring file: Server redirected too many times (20) [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR

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  • InternalsVisibleTo attribute ain't workin'!

    - by skb
    I am trying to use the InternalsVisibleTo assembly attribute to make my internal classes in a .NET class library visible to my unit test project. For some reason, I keep getting an error message that says: 'MyClassName' is inaccessible due to its protection level Both assemblies are signed and I have the correct key listed in the attribute declaration. Any ideas?

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  • How can I create a user registration form using datastore - google appengine ??

    - by srivigneshwar
    I am very new to jsp and google appengine , but still I can do something if I get some basic idea , I wanna create an user registration form with fields like name, user id , password, confirm password, etc,. using google appengine datastore feature. and I wanna retrieve user information . Please help me .. Thanks in advance. Thanks for the replies, I need to get some information from user and I want to store it in database, and I will use that information for my application. How can I do that?

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  • how to add a entry to tables with relationships?

    - by siulamvictor
    I have 2 models, Users & Accounts. They are in one-to-many relationship, i.e. each accounts have many users. Accounts company_id company_name company_website Users user_id user_name password company_id email How can I add these entries to database using ActiveRecord? Supposed I don't is the company existed in the database when I add a new entry. Name Email Password Company ----------------------------------------------------------------------------- Albert [email protected] 123456 ABC Company Betty [email protected] 234567 ABC Company Carmen [email protected] 765432 XXX Company David [email protected] 654321 ABC Company

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  • automatic enter login credentials while testing my app (from visual studio 2008)

    - by Michel
    Hi all, this is something that i don't want to program, but i was looking for a handy way of logging on to my web app. i'm building (and testing and running) my webapp over and over again, and here i've been provided a strong password. needless to say it's not so nice to enter my full user name + strong password 30 times a day. is there a nifty tool which lives in the background and when i open page localhost/mytestpage.aspx, it will say: "hey, let me type in michel and sdfs%^%gfhg in these two textboxes"?

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  • How to retrieve the GUID for Yahoo's Contacts API

    - by Jack Marchetti
    I'm attemping to use the Yahoo Contacts API to add an "invite your friends" feature on a site I'm building. I've found the correct web service to call (http://social.yahooapis.com/v1/user/{guid}/contacts) but it is asking for the user's GUID, not their username/password. I've searched, and am unable to find a "lookup" feature through the Yahoo API which lets me get the user's guid from their username/password. Does anyone have any experience with the Contacts API. I've reaad over the documentation, and looked at YQL as well, but I still haven't found how to get the user's guid. Thanks guys.

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  • How to safely store encryption key in a .NET assembly

    - by Alex
    In order to prevent somebody from grabbing my data easily, I cache data from my service as encrypted files (copy protection, basically). However, in order to do this, I must store the encryption key within the .NET assembly so it is able to encrypt and decrypt these files. Being aware of tools like Red Gate's .NET Reflector which can pull my key right out, I get a feeling that this is not a very safe way of doing it... are there any best practices to doing this?

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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  • PHP multiuser login class or script

    - by FFish
    I am looking for a simple but secure login script with mySQL PHP: sessions, MD5 that I can use with my exsisting database. Cookies to store password + password recovery by email. Change login/pass. I do not need registering, I register the user myself with temp login/pass. table agents agent1 agent2 table albums album1, owner: agent1 album2, owner: agent1 album3, owner: agent2 ... login.php agent1 logs in and has access to his albums: - album1 - album2 agent1 can edit his albums: edit.php?ref=album1 but NOT edit.php?ref=album3 by changing the ?ref variable

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  • Google OAuthGetRequestToken returns "signature_invalid"

    - by M Schenkel
    Trying for hours to get a request token using Google OAuthGetRequestToken but it always returns "signature_invalid". For a test I use the oAuth Playground to successfully request the token. Here are the results: Signature base string GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetRequestToken&oauth_callback%3Dhttp%253A%252F%252Fgooglecodesamples.com%252Foauth_playground%252Findex.php%26oauth_consumer_key%3Dwww.embeddedanalytics.com%26oauth_nonce%3D56aa884162ed21815a0406725c79cf79%26oauth_signature_method%3DRSA-SHA1%26oauth_timestamp%3D1321417095%26oauth_version%3D1.0%26scope%3Dhttps%253A%252F%252Fwww.google.com%252Fanalytics%252Ffeeds%252F Request/Response GET /accounts/OAuthGetRequestToken?scope=https%3A%2F%2Fwww.google.com%2Fanalytics%2Ffeeds%2F HTTP/1.1 Host: www.google.com Accept: */* Authorization: OAuth oauth_version="1.0", oauth_nonce="56aa884162ed21815a0406725c79cf79", oauth_timestamp="1321417095", oauth_consumer_key="www.embeddedanalytics.com", oauth_callback="http%3A%2F%2Fgooglecodesamples.com%2Foauth_playground%2Findex.php", oauth_signature_method="RSA-SHA1", oauth_signature="qRtorIaSFaQdOXW1u6eMQlY9LT2j7ThG5kgkcD6rDcW4MIvzluslFgYRNTuRvnaruraNpItjojtgsrK9deYRKoHBGOlU27SsWy6jECxKczcSECl3cVAcjk7dvbywFMDkgi1ZhTZ5Q%2BFoD60HoVQUYnGUbOO0jPXI48LfkiA5ZN4%3D" HTTP/1.1 200 OK Content-Type: text/plain; charset=UTF-8 Date: Wed, 16 Nov 2011 04:18:15 GMT Expires: Wed, 16 Nov 2011 04:18:15 GMT Cache-Control: private, max-age=0 X-Content-Type-Options: nosniff X-XSS-Protection: 1; mode=block Content-Length: 118 Server: GSE oauth_token=4%2FmO86qZzixayI2NoUc-hewC--D53R&oauth_token_secret=r0PReF9D83w1d6uP0nyQQm9c&oauth_callback_confirmed=true I am using Fiddler to trace my calls. It returns the Signature base string: GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetRequestToken&oauth_callback%3Dhttp%253A%252F%252Fgooglecodesamples.com%252Foauth_playground%252Findex.php%26oauth_consumer_key%3Dwww.embeddedanalytics.com%26oauth_nonce%3Dl9Jydzjyzt2fJfM3ltY5yrxxYy2uh1U7%26oauth_signature_method%3DRSA-SHA1%26oauth_timestamp%3D1321417107%26oauth_version%3D1.0%26scope%3Dhttps%253A%252F%252Fwww.google.com%252Fanalytics%252Ffeeds%252F Aside from the oauth_timestamp and oauth_nonce (which should be different), the base string are pretty much identical. Anyone know what I am doing wrong? Update 11/20/2011 Thinking it might be something wrong with my RSA-SHA signing, I have since tried HMAC-SHA. It gives the same results. I thought it might be beneficial to include the Fiddler results (I added carriage returns to have it format better). GET https://www.google.com/accounts/OAuthGetRequestToken? scope=https%3A%2F%2Fwww.google.com%2Fanalytics%2Ffeeds%2F HTTP/1.1 Content-Type: application/x-www-form-urlencoded Authorization: OAuth oauth_version="1.0", oauth_nonce="7C4C900EAACC9C7B62E399A91B81D8DC", oauth_timestamp="1321845418", oauth_consumer_key="www.embeddedanalytics.com", oauth_signature_method="HMAC-SHA1", oauth_signature="ows%2BbFTNSR8jVZo53rGBB8%2BfwFM%3D" Host: www.google.com Accept: */* Accept-Encoding: identity Response HTTP/1.1 400 Bad Request Content-Type: text/plain; charset=UTF-8 Date: Mon, 21 Nov 2011 03:16:57 GMT Expires: Mon, 21 Nov 2011 03:16:57 GMT Cache-Control: private, max-age=0 X-Content-Type-Options: nosniff X-XSS-Protection: 1; mode=block Content-Length: 358 Server: GSE signature_invalid base_string:GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetRequestToken &oauth_consumer_key%3Dwww.embeddedanalytics.com %26oauth_nonce%3D7C4C900EAACC9C7B62E399A91B81D8DC %26oauth_signature_method%3DHMAC-SHA1 %26oauth_timestamp%3D1321845418 %26oauth_version%3D1.0 %26scope%3Dhttps%253A%252F%252Fwww.google.com%252Fanalytics%252Ffeeds%252F

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  • How to get the result for return statement from JSON parsing?

    - by blankon91
    I've follow the code for parsing the value with JSON from here, but I get the problem in my return statement. I want to put the parsing result into my return statement. How to do that? Here is my code: public String MASUK(String user, String password) { SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME); PropertyInfo pi = new PropertyInfo(); pi.setName("ccduser"); pi.setValue(user); pi.setType(String.class); request.addProperty(pi); PropertyInfo pi2 = new PropertyInfo(); pi2.setName("password"); pi2.setValue(password); pi2.setType(String.class); request.addProperty(pi2); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(request); HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS); try { httpTransport.call(SOAP_ACTION, envelope); SoapObject resultSOAP = (SoapObject) envelope.bodyIn; /* gets our result in JSON String */ String ResultObject = resultSOAP.getProperty(0).toString(); resultSOAP = (SoapObject) envelope.bodyIn; ResultObject = resultSOAP.getProperty(0).toString(); if (ResultObject.startsWith("{")) { // if JSON string is an object JSONObj = new JSONObject(ResultObject); Iterator<String> itr = JSONObj.keys(); while (itr.hasNext()) { String Key = (String) itr.next(); String Value = JSONObj.getString(Key); BundleResult.putString(Key, Value); // System.out.println(bundleResult.getString(Key)); } } else if (ResultObject.startsWith("[")) { // if JSON string is an array JSONArr = new JSONArray(ResultObject); System.out.println("length" + JSONArr.length()); for (int i = 0; i < JSONArr.length(); i++) { JSONObj = (JSONObject) JSONArr.get(i); BundleResult.putString(String.valueOf(i), JSONObj.toString()); // System.out.println(bundleResult.getString(i)); } } } catch (Exception exception) { } return null; }

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  • Soap Header Problem

    - by aju982007
    I have a Java Secured Webservice With Soap Header Protection Must Provide Username and Password. My Application is C# Client Application Can i call Java Secured Webservice using C# code what is the code for that ? When i connect this webservice its showing SoapHeader Element Required ..Please Give the Solution

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  • How to read an XML file with Java?

    - by Yatendra Goel
    I don't need to read complex XML files. I just want to read the following configuration file with a simplest XML reader <config> <db-host>localhost</db-host> <db-port>3306</db-port> <db-username>root</db-username> <db-password>root</db-password> <db-name>cash</db-name> </config> How to read the above XML file with a XML reader through Java?

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  • Consume restful webservice through web proxy

    - by Chico
    Hello, I'm trying to consume a restful webservice in java using the Apache Wink framework through my school web proxy requiring authentification ClientConfig clientConfig = new ClientConfig(); clientConfig.proxyHost("proxy.school.com"); clientConfig.proxyPort(3128); //nothing to set username and password :( RestClient client = new RestClient(clientConfig); Resource resource = client.resource("http://vimeo.com/api/v2/artist/videos.xml"); String response = resource.accept("text/plain").get(String.class); I've also tried to use the BasicAuthSecurityHandler but it seems to be used to authenticate directly to a web server, not the web proxy BasicAuthSecurityHandler basicAuthHandler = new BasicAuthSecurityHandler(); basicAuthHandler.setUserName("username"); basicAuthHandler.setPassword("password"); config.handlers(basicAuthHandler); It still fail with a HTTP 407 error code : Proxy Authentication Required. I've googled the best I could, nothing came up better to consume a webservice from a Java client through a web proxy, if someone has another idea, feel free to respond

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  • How to get JSON back from HTTP POST Request (to another domain)

    - by roman m
    I'm trying to use the API on a website, here's the part of the manual: Authenticated Sessions (taken from here) To create an authenticated session, you need to request an authToken from the '/auth' API resource. URL: http://stage.amee.com/auth (this is not my domain) Method: POST Request format: application/x-www-form-urlencoded Response format: application/xml, application/json Response code: 200 OK Response body: Details of the authenticated user, including API version. Extra data: "authToken" cookie and header, containing the authentication token that should be used for subsequent calls. Parameters: username / password Example Request POST /auth HTTP/1.1 Accept: application/xml Content-Type: application/x-www-form-urlencoded username=my_username&password=my_password Response HTTP/1.1 200 OK Set-Cookie: authToken=1KVARbypAjxLGViZ0Cg+UskZEHmqVkhx/Pm...; authToken: 1KVARbypAjxLGViZ0Cg+UskZEHmqVkhx/PmEvzkPGp...== Content-Type: application/xml; charset=UTF-8 QUESTION: How do I get that to work? I tried jQuery, but it seems to have problem with XSS. Actual code snippet would be greatly appreciated. p.s. All I was looking for was WebClient class in C#

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  • Killing Mysql prcoesses staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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