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  • parse complex xml using Sax xml parsing in android

    - by hardik joshi
    Hello i am new in android and i am currently using SAX parsing in android. Following is my xml file. <response> <peoples> <name>abc</name> <age> 20</age> <info> <address>USA</address> <family>parents</family> </info> </people> <people> <name>abc</name> <age> 20</age> <info> <address>USA</address> <family>parents</family> </info> </people> </response> How to parse this xml using SAX parser. Please help me to find this.Thank you in advance.

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  • TreeView Root Node Style

    - by ScG
    I have a tree view <asp:TreeView ID="TreeView1" runat="server" DataSourceID="SiteMapDataSource1" ShowExpandCollapse="False"> </asp:TreeView> As you can see, root node is hidden. However when the treenode gets rendered, there is a whitespace to the left of each leafnode. This is probably because the root node is hidden but is taking up space. How do i remove that white space.

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  • How to read values from file. tokenizer

    - by user69514
    I have a file in which each line contains two numbers. The problem is that the two number are separated by a space, but the space can be any number of blank spaces. either one, two, or more. I want to read the line and store each of the numbers in a variable, but I'm not sure how to tokenize it. i.e 1 5 3 2 5 6 3 4 83 54 23 23 32 88 8 203

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  • Official names for pointer operators

    - by FredOverflow
    What are the official names for the operators * and & in the context of pointers? They seem to be frequently called dereference operator and address-of operator respectively, but unfortunately, the section on unary operators in the standard does not name them. I really don't want to name & address-of anymore, because & returns a pointer, not an address. (A pointer is a language mechanism, while an address is an implementation detail. Addresses are untyped, while pointers aren't, except for void*.) The standard is very clear about this: The result of the unary & operator is a pointer to its operand. Symmetry suggests to name & reference operator which is a little unfortunate because of the collision with references in C++. The fact that & returns a pointer suggests pointer operator. Are there any official sources that would confirm these (or other) namings?

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  • Modifying a const through a non-const pointer

    - by jasonline
    I'm a bit confused what happened in the following code: const int e = 2; int* w = ( int* ) &e; // (1) cast to remove const-ness *w = 5; // (2) cout << *w << endl; // (3) outputs 5 cout << e << endl; // (4) outputs 2 cout << "w = " << w << endl; // (5) w points to the address of e cout << "&e = " << &e << endl; In (1), w points to the address of e. In (2), that value was changed to 5. However, when the values of *w and e were displayed, their values are different. But if you print value of w pointer and &e, they have the same value/address. How come e still contained 2, even if it was changed to 5? Were they stored in a separate location? Or a temporary? But how come the value pointed by w is still the address of e?

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  • PHP IF condition advise needed

    - by Jose David Garcia Llanos
    I'm using emails as username to login into a site being developed, now if a user updates their email from the profile page, how can i make sure that my email checking statement doesnt catch the user's email as already registered in the database. the page /* Now we will store the values submitted by form in variable */ $fullname=$_POST['fullname']; $dob=$_POST['dob']; $address=$_POST['address']; $myusername=$_POST['myusername']; $telephone=$_POST['telephone']; $queryuser=mysql_query("SELECT * FROM customer WHERE email='$myusername' "); $checkuser=mysql_num_rows($queryuser); if($checkuser != 0) { $Merr[]='&raquo; Sorry this email is already registered!'; } else {$insert_user=mysql_query("UPDATE CUSTOMER SET SYNTAX HERE"); Now these are the fields in question; (name, dob, address, email, telephone) VALUES ('$fullname', '$dob', '$address', '$myusername', '$telephone') As you can see if the user changes the login email then the syntax checks for the email being submitted against the database, however if the user leaves the email unchanged he will get the error because it is found in the database. I was thinking of something like; if($checkuser != 0) { if($myusername == $_POST['myusername']) (...dont show error.) but my php skills are limited. can anyone advise please, thanks

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  • Listener error not connecting

    - by Sham
    I have two database running on Port No : 1521. When i m connecting to ORCL db it get's connected, but when i try to connect to another DB it gives me following error. ORA-12514: TNS:listener does not currently know of service requested in connect descriptor. My Listener: # listener.ora Network Configuration File: C:\app\Administrator\product\11.2.0 \dbhome_1\network\admin\listener.ora # Generated by Oracle configuration tools. ADMIN_RESTRICTIONS_LISTENER = ON LISTENER = (DESCRIPTION_LIST = (DESCRIPTION = (ADDRESS = (PROTOCOL = TCP)(HOST = 127.1.1.1)(PORT = 1521)) ) ) ADR_BASE_LISTENER = C:\app\Administrator TNSNAMES.ora ORCL = (DESCRIPTION = (ADDRESS = (PROTOCOL = TCP)(HOST = 127.1.1.1)(PORT = 1521)) (CONNECT_DATA = (SERVER = DEDICATED) (SERVICE_NAME = orcl) ) ) PARIVARTAN = (DESCRIPTION = (ADDRESS_LIST = (ADDRESS = (PROTOCOL = TCP)(HOST = 127.1.1.1)(PORT = 1521)) ) (CONNECT_DATA = (SERVICE_NAME = Parivartan) ) ) Lsnrctl Result STATUS of the LISTENER ------------------------ Alias LISTENER Version TNSLSNR for 64-bit Windows: Version 11.2.0.1.0 - Production Start Date 14-DEC-2012 14:22:51 Uptime 0 days 0 hr. 19 min. 31 sec Trace Level off Security ON: Local OS Authentication SNMP OFF Listener Parameter File C:\app\Administrator\product\11.2.0\dbhome_1\network\a dmin\listener.ora Listener Log File c:\app\administrator\diag\tnslsnr\127.1.1.1\listener\al ert\log.xml Listening Endpoints Summary... (DESCRIPTION=(ADDRESS=(PROTOCOL=tcp)(HOST=127.1.1.1)(PORT=1521))) Services Summary... Service "orcl" has 1 instance(s). Instance "orcl", status READY, has 1 handler(s) for this service... Service "orclXDB" has 1 instance(s). Instance "orcl", status READY, has 1 handler(s) for this service... The command completed successfully Reply me soon....

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  • MS SQL Error: Primary file group is full

    - by aximili
    I have a very large table in my database and I am starting to get this error Could not allocate a new page for database 'mydatabase' because of insufficient disk space in filegroup 'PRIMARY'. Create the necessary space by dropping objects in the filegroup, adding additional files to the filegroup, or setting autogrowth on for existing files in the filegroup. How do you fix this error? I don't understand the suggestions there.

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  • Why does Email::MIME split up my attachment?

    - by sid_com
    Why does the attachment(ca. 110KiB) split up in 10 parts(ca. 11KiB) when I send it with this script using Email::MIME? #!/usr/bin/env perl use warnings; use strict; use Email::Sender::Transport::SMTP::TLS; my $mailer = Email::Sender::Transport::SMTP::TLS->new( host => 'smtp.my.host', port => 587, username => 'username', password => 'password', ); use Email::MIME::Creator; use IO::All; my @parts = ( Email::MIME->create( attributes => { content_type => 'text/plain', disposition => 'inline', encoding => 'quoted-printable', charset => 'UTF-8', }, body => "Hello there!\n\nHow are you?", ), Email::MIME->create( attributes => { filename => "test.jpg", content_type => "image/jpeg", disposition => 'attachment', encoding => "base64", name => "test.jpg", }, body => io( "test.jpg" )->all, ), ); my $email = Email::MIME->create( header => [ From => 'my@address', To => 'your@address', Subject => 'subject', ], parts => [ @parts ], ); eval { $mailer->send( $email, { from => 'my@address', to => [ 'your@address' ], } ); }; die "Error sending email: $@" if $@;

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  • Dev environment - Cubicles or pods?

    - by jon
    We're reorganizing our workspaces at work, and are individually being given the choice of working in a more open space with a few other developers, or a more closed off space by ourselves. Which should I choose?

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  • Select XML nodes as rows

    - by Bjørn
    I am selecting from a table that has an XML column using T-SQL. I would like to select a certain type of node and have a row created for each one. For instance, suppose I am selecting from a people table. This table has an XML column for addresses. The XML is formated similar to the following: <address> <street>Street 1</street> <city>City 1</city> <state>State 1</state> <zipcode>Zip Code 1</zipcode> </address> <address> <street>Street 2</street> <city>City 2</city> <state>State 2</state> <zipcode>Zip Code 2</zipcode> </address> How can I get results like this: Name         City         State Joe Baker   Seattle      WA Joe Baker   Tacoma     WA Fred Jones  Vancouver BC

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  • Batch file that returns folder size

    - by Paul Wall
    Hi, I'm having space issues on my Vista machine and need to figure out what's taking up so much space. I would like to write a simple batch file that returns all folders under C: and the size of each folder. The dir command doesn't appear to return folder size. Unfortunately we don't have admin rights and can't install a third party application and we have other users in our group that also need this information. Thanks...

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  • java RMI connection to server

    - by user85116
    I have a very simple rmi client / server application. I don't use the "rmiregistry" application though, I use this to create the server: server = new RemoteServer(); registry = LocateRegistry.createRegistry(PORT); registry.bind("RemoteServer", server); The client part is: registry = LocateRegistry.getRegistry(IPADDRESS, PORT); remote = (IRemoteServer) registry.lookup("RemoteServer"); Here is the fascinating problem: The application works perfectly when both server and client are running in my (private) local network. As soon as I put the server on a public server, the application hangs for a minute, then gives me the following error: java.rmi.ServerException: RemoteException occurred in server thread; nested exception is: java.rmi.ConnectException: Connection refused to host: 192.168.x.y; nested exception is: java.net.ConnectException: Connection timed out: connect at sun.rmi.server.UnicastServerRef.dispatch(Unknown Source) at sun.rmi.transport.Transport$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at sun.rmi.transport.Transport.serviceCall(Unknown Source) at sun.rmi.transport.tcp.TCPTransport.handleMessages(Unknown Source) at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run0(Unknown Source ... (the rest is truncated) The key I think is that the client (running on my private network) cannot connect to myself (my address is 192.168.x.y where x.y is some other numbers, but the real error message shows my ip address listed there) If I kill the rmi server on the public internet, then I instantly get a "connection refused to host: a.b.c.d") message, so I know that something at the server end is at least working. Any suggestions? EDIT: just to make this a little more clear: 192.168.x.y is the client address, a.b.c.d is the server address. The stacktrace shows the client cannot connect to the client.

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  • Looking for an algorithm that will show how to fit the most boxes in a container.

    - by Abe Miessler
    I've been interested in writing an application that will show how to fit boxes (of random dimensions) in a container so there is as little space as possible left. A real life example would be something that would tell you how to use the most space in a UPS truck. Does anyone know of a good place to start for something like this? Is there an existing algorithm that does something similar to what I'm talking about?

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  • VB.NET handling data between different forms

    - by niuchu
    Hi, I'm writing a simple application - address book. User enters new addresses and they are added as an entry to a list visible on the main form (frmStart). I use one form to add and edit (AddContForm). Add button on the frmStart works fine, however I experience some problems with the edit button as when I press it and enter new data they are added as new entry however the previous entry is still there. Logic is handled by Contact.vb class. Please let me know how to fix this problem. Here is the code: Contact.vb Public Class Contact Public Contact As String Public Title As String Public Fname As String Public Surname As String Public Address As String Private myCont As String Public Property Cont() Get Return myCont End Get Set(ByVal value) myCont = Value End Set End Property Public Overrides Function ToString() As String Return Me.Cont End Function Public Sub Display() Dim C As New Contact C.Cont = frmAddCont.txtTitle.Text C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text frmStart.lstContact.Items.Add(C) End Sub End Class Here is frmStart.vb Public Class frmStart Public Button As String Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click Button = "" Button = "Add" frmAddCont.ShowDialog() End Sub Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnDel.Click Button = "" Button = "Del" Dim DelCont As Contact DelCont = Me.lstContact.SelectedItem() lstContact.Items.Remove(DelCont) End Sub Private Sub lstContact_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles lstContact.SelectedIndexChanged End Sub Private Sub btnEdit_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnEdit.Click Button = "" Button = "Edit" Dim C As Contact If lstContact.SelectedItem IsNot Nothing Then C = DirectCast(lstContact.SelectedItem, Contact) frmAddCont.ShowDialog() End If End Sub End Class Here is AddContFrm.vb Public Class frmAddCont Public Class ControlObject Dim Title As String Dim FName As String Dim SName As String Dim Address As String Dim TelephoneNumber As Integer Dim emailAddress As String Dim Website As String Dim Photograph As String End Class Private Sub btnConfirmAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnConfirmAdd.Click Dim B As String B = frmStart.Button Dim C As New Contact C.Display() Me.Hide() If B = "Edit" Then C = DirectCast(frmStart.lstContact.SelectedItem, Contact) frmStart.lstContact.SelectedItems.Remove(C) End If End Sub Private Sub frmAddCont_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load End Sub End Class

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  • C# - How do find a string within a string even if it spans across whitespace?

    - by James Heaney
    I want to be able to find and highlight a string within a string BUT I no not want to remove the space. So if my original string is : There are 12 monkeys I want to find '12 mon' and highlight those characters ending up with : There are < font color='red' 12 mon< /font keys BUT I also want the same result if I search for '12mon' (no space this time) This has really bent my mind! I'm sure it can be done with Regex.

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  • Hosting a database?

    - by user296516
    Hi, I was kinda puzzled by seeing that most hosting plans do offer, say, 12.000 MB disk space and 60 MB Database space... what is the difference between this two and what do I do if I need like a few gigs for a database and only some tens of MB for the rest of the site?

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  • Can i upload my apk to SD Card instead of internal storage?

    - by Ahmed Al Khashab
    My APK is big, 70 MB. I don't have any problems when I install it in external storage, but when I upload it to phone before installing, the APK goes to internal storage and my testing phone doesn't have enough space in internal storage and a lot of android phones don't have enough internal space for 70 MB... Can I upload my APK straight to the SD Card instead of internal storage first? upload mean "upload from my eclipse while runnig , or download from market, apk will go to internal storage but i want apk go to external and start install from external"

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  • Make DIV fill remainder of page vertically?

    - by mazin k.
    I have a Google Maps app that takes up most of the page. However, I need to reserve the top-most strip of space for a menu bar. How can make the map div automatically fill its vertical space? height: 100% does not work because the top bar will then push the map past the bottom of the page. +--------------------------------+ | top bar (x% tall) | |================================| | ^ | | | | | div | | (100%-x% tall) | | | | | v | +--------------------------------+

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  • i386 assembly question: why do I need to meddle with the stack pointer?

    - by zneak
    Hello everyone, I decided it would be fun to learn x86 assembly during the summer break. So I started with a very simple hello world program, borrowing on free examples gcc -S could give me. I ended up with this: HELLO: .ascii "Hello, world!\12\0" .text .globl _main _main: pushl %ebp # 1. puts the base stack address on the stack movl %esp, %ebp # 2. puts the base stack address in the stack address register subl $20, %esp # 3. ??? pushl $HELLO # 4. push HELLO's address on the stack call _puts # 5. call puts xorl %eax, %eax # 6. zero %eax, probably not necessary since we didn't do anything with it leave # 7. clean up ret # 8. return # PROFIT! It compiles and even works! And I think I understand most of it. Though, magic happens at step 3. Would I remove this line, my program would die between the call to puts and the xor from a misaligned stack error. And would I change $20 to another value, it'd crash too. So I came to the conclusion that this value is very important. Problem is, I don't know what it does and why it's needed. Can anyone explain me? (I'm on Mac OS, would it ever matter.)

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  • Make part of layout invisible and the other part visible

    - by JonF
    I would like to make a LinearLayout that was created from xml invisible, and another LinearLayout visible to replace it. The replacement layout starts out as invisible. When I make the originally visible layout invisible, it still leaves space for it on the screen. How can I refresh the screen so that space is gone?

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