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  • No resource type specified (at 'id' with value '@+id\st')

    - by Refaat
    I'm new at android programming, I'm now trying to make some buttons, I configured these buttons using the following code: The MainActivity class : public class MainActivity extends Activity { /** Called when the activity is first created. */ Button st,nd,center; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); st = (Button)findViewById(R.id.st); st = (Button)findViewById(R.id.center); st = (Button)findViewById(R.id.nd); } } and the XML Layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background" > <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello from animation!!" /> <button android:layout_width="100dp" android:layout_height="50dp" android:text="1st half" android:id="@+id\st" /> // and the other two points defined the same way </LinearLayout> And i got that syntax error: error: Error: No resource type specified (at 'id' with value '@+id\st'). // and the same error with the other two buttons HINT: The R class is imported and accessible from the MainActivity class but it can't read R.id.

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  • When someone deletes a shared data source in SSRS

    - by Rob Farley
    SQL Server Reporting Services plays nicely. You can have things in the catalogue that get shared. You can have Reports that have Links, Datasets that can be used across different reports, and Data Sources that can be used in a variety of ways too. So if you find that someone has deleted a shared data source, you potentially have a bit of a horror story going on. And this works for this month’s T-SQL Tuesday theme, hosted by Nick Haslam, who wants to hear about horror stories. I don’t write about LobsterPot client horror stories, so I’m writing about a situation that a fellow MVP friend asked me about recently instead. The best thing to do is to grab a recent backup of the ReportServer database, restore it somewhere, and figure out what’s changed. But of course, this isn’t always possible. And it’s much nicer to help someone with this kind of thing, rather than to be trying to fix it yourself when you’ve just deleted the wrong data source. Unfortunately, it lets you delete data sources, without trying to scream that the data source is shared across over 400 reports in over 100 folders, as was the case for my friend’s colleague. So, suddenly there’s a big problem – lots of reports are failing, and the time to turn it around is small. You probably know which data source has been deleted, but getting the shared data source back isn’t the hard part (that’s just a connection string really). The nasty bit is all the re-mapping, to get those 400 reports working again. I know from exploring this kind of stuff in the past that the ReportServer database (using its default name) has a table called dbo.Catalog to represent the catalogue, and that Reports are stored here. However, the information about what data sources these deployed reports are configured to use is stored in a different table, dbo.DataSource. You could be forgiven for thinking that shared data sources would live in this table, but they don’t – they’re catalogue items just like the reports. Let’s have a look at the structure of these two tables (although if you’re reading this because you have a disaster, feel free to skim past). Frustratingly, there doesn’t seem to be a Books Online page for this information, sorry about that. I’m also not going to look at all the columns, just ones that I find interesting enough to mention, and that are related to the problem at hand. These fields are consistent all the way through to SQL Server 2012 – there doesn’t seem to have been any changes here for quite a while. dbo.Catalog The Primary Key is ItemID. It’s a uniqueidentifier. I’m not going to comment any more on that. A minor nice point about using GUIDs in unfamiliar databases is that you can more easily figure out what’s what. But foreign keys are for that too… Path, Name and ParentID tell you where in the folder structure the item lives. Path isn’t actually required – you could’ve done recursive queries to get there. But as that would be quite painful, I’m more than happy for the Path column to be there. Path contains the Name as well, incidentally. Type tells you what kind of item it is. Some examples are 1 for a folder and 2 a report. 4 is linked reports, 5 is a data source, 6 is a report model. I forget the others for now (but feel free to put a comment giving the full list if you know it). Content is an image field, remembering that image doesn’t necessarily store images – these days we’d rather use varbinary(max), but even in SQL Server 2012, this field is still image. It stores the actual item definition in binary form, whether it’s actually an image, a report, whatever. LinkSourceID is used for Linked Reports, and has a self-referencing foreign key (allowing NULL, of course) back to ItemID. Parameter is an ntext field containing XML for the parameters of the report. Not sure why this couldn’t be a separate table, but I guess that’s just the way it goes. This field gets changed when the default parameters get changed in Report Manager. There is nothing in dbo.Catalog that describes the actual data sources that the report uses. The default data sources would be part of the Content field, as they are defined in the RDL, but when you deploy reports, you typically choose to NOT replace the data sources. Anyway, they’re not in this table. Maybe it was already considered a bit wide to throw in another ntext field, I’m not sure. They’re in dbo.DataSource instead. dbo.DataSource The Primary key is DSID. Yes it’s a uniqueidentifier... ItemID is a foreign key reference back to dbo.Catalog Fields such as ConnectionString, Prompt, UserName and Password do what they say on the tin, storing information about how to connect to the particular source in question. Link is a uniqueidentifier, which refers back to dbo.Catalog. This is used when a data source within a report refers back to a shared data source, rather than embedding the connection information itself. You’d think this should be enforced by foreign key, but it’s not. It does allow NULLs though. Flags this is an int, and I’ll come back to this. When a Data Source gets deleted out of dbo.Catalog, you might assume that it would be disallowed if there are references to it from dbo.DataSource. Well, you’d be wrong. And not because of the lack of a foreign key either. Deleting anything from the catalogue is done by calling a stored procedure called dbo.DeleteObject. You can look at the definition in there – it feels very much like the kind of Delete stored procedures that many people write, the kind of thing that means they don’t need to worry about allowing cascading deletes with foreign keys – because the stored procedure does the lot. Except that it doesn’t quite do that. If it deleted everything on a cascading delete, we’d’ve lost all the data sources as configured in dbo.DataSource, and that would be bad. This is fine if the ItemID from dbo.DataSource hooks in – if the report is being deleted. But if a shared data source is being deleted, you don’t want to lose the existence of the data source from the report. So it sets it to NULL, and it marks it as invalid. We see this code in that stored procedure. UPDATE [DataSource]    SET       [Flags] = [Flags] & 0x7FFFFFFD, -- broken link       [Link] = NULL FROM    [Catalog] AS C    INNER JOIN [DataSource] AS DS ON C.[ItemID] = DS.[Link] WHERE    (C.Path = @Path OR C.Path LIKE @Prefix ESCAPE '*') Unfortunately there’s no semi-colon on the end (but I’d rather they fix the ntext and image types first), and don’t get me started about using the table name in the UPDATE clause (it should use the alias DS). But there is a nice comment about what’s going on with the Flags field. What I’d LIKE it to do would be to set the connection information to a report-embedded copy of the connection information that’s in the shared data source, the one that’s about to be deleted. I understand that this would cause someone to lose the benefit of having the data sources configured in a central point, but I’d say that’s probably still slightly better than LOSING THE INFORMATION COMPLETELY. Sorry, rant over. I should log a Connect item – I’ll put that on my todo list. So it sets the Link field to NULL, and marks the Flags to tell you they’re broken. So this is your clue to fixing it. A bitwise AND with 0x7FFFFFFD is basically stripping out the ‘2’ bit from a number. So numbers like 2, 3, 6, 7, 10, 11, etc, whose binary representation ends in either 11 or 10 get turned into 0, 1, 4, 5, 8, 9, etc. We can test for it using a WHERE clause that matches the SET clause we’ve just used. I’d also recommend checking for Link being NULL and also having no ConnectionString. And join back to dbo.Catalog to get the path (including the name) of broken reports are – in case you get a surprise from a different data source being broken in the past. SELECT c.Path, ds.Name FROM dbo.[DataSource] AS ds JOIN dbo.[Catalog] AS c ON c.ItemID = ds.ItemID WHERE ds.[Flags] = ds.[Flags] & 0x7FFFFFFD AND ds.[Link] IS NULL AND ds.[ConnectionString] IS NULL; When I just ran this on my own machine, having deleted a data source to check my code, I noticed a Report Model in the list as well – so if you had thought it was just going to be reports that were broken, you’d be forgetting something. So to fix those reports, get your new data source created in the catalogue, and then find its ItemID by querying Catalog, using Path and Name to find it. And then use this value to fix them up. To fix the Flags field, just add 2. I prefer to use bitwise OR which should do the same. Use the OUTPUT clause to get a copy of the DSIDs of the ones you’re changing, just in case you need to revert something later after testing (doing it all in a transaction won’t help, because you’ll just lock out the table, stopping you from testing anything). UPDATE ds SET [Flags] = [Flags] | 2, [Link] = '3AE31CBA-BDB4-4FD1-94F4-580B7FAB939D' /*Insert your own GUID*/ OUTPUT deleted.Name, deleted.DSID, deleted.ItemID, deleted.Flags FROM dbo.[DataSource] AS ds JOIN dbo.[Catalog] AS c ON c.ItemID = ds.ItemID WHERE ds.[Flags] = ds.[Flags] & 0x7FFFFFFD AND ds.[Link] IS NULL AND ds.[ConnectionString] IS NULL; But please be careful. Your mileage may vary. And there’s no reason why 400-odd broken reports needs to be quite the nightmare that it could be. Really, it should be less than five minutes. @rob_farley

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  • ASP.NET object visibility

    - by user181421
    Hello, I have a webform with a button and a textbox. I want to set the textbox, in design time to Visible = false, and then in the onclick event of the button in the client side using javascript, I want to set the visibility of the button back to true. The problem is that I get a message saying that the object does not exist. Any idea how to solve this? TY

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  • Watir question regarding exist on a class for testing purposes.

    - by AJ
    I have a button on my page that changes depending on what radio button is clicked. The button has the same text on it with the same id, but different classes. How do I test if the two different buttons exist depending on the radio. <a id="submit" class="on" href="javascript:submit();">Submit</a> <a id="submit" class="off" href="javascript:submit();">Submit</a> How do i test if the second button appears instead of the first one. I used something like, browser.link(:text, 'Submit').exist? but this doesn't work cause it will return true no matter what. thanks

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  • How to dismiss modal view controller from UITabBarController

    - by user563697
    Currently im developing an iPhone Game...When app loaded a login page is seen...when logged in...from login view controller a welcome screen view controller with tabbar(UITabbarcontroller iVar declared inside and connected to tabbarcontroller with interface builder) is presented(using presentModalViewCotroller)..There the first tab is dealing with account ..loaded from accountController NIb and view controller...inside which there's a logout button...when clicked i need to go to login page under loginview controller... Inside logout button click action method...i had coded like this [self dismissModalViewControllerAnimated:NO]; but on button click nothing happening... first : parent--loginviewcontroller child--welcomescreen view controller Inside welcome screen,in account tab,on logout button click: how could i dismiss the above MVC.... can anyone give me a solution as soon as possible...its urgent...

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  • Android GPS cloud of confusion!

    - by Anthony Forloney
    I am trying to design my first Android application with the use of GPS. As of right now, I have a drawable button that when clicked, alerts a Toast message of the longitude and latitude. I have tried to use the telnet localhost 5554 and then geo fix #number #number to feed in values but no results display just 0 0. I have also tried DDMS way of sending GPS coordinates and I get the same thing. My question is what exactly is the code equivalent to the geo fix and the DDMS way of sending coordinates. I have used Location, LocationManger and LocationListener but I am not sure which is the right choice. Could anyone explain to me what the code-equivalent just so I can get a better understanding of how to fix my application not working. Code is given, just in case if the error exists with the code @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button button = (Button) findViewById(R.id.track); button.setOnClickListener(this); LocationManager location =(LocationManager)getSystemService(Context.LOCATION_SERVICE); Location loc = location.getLastKnownLocation(location.GPS_PROVIDER); updateWithNewLocation(loc); } private final LocationListener locationListener = new LocationListener() { public void onLocationChanged(Location location) { updateWithNewLocation(location); } private void updateWithNewLocation(Location l) { longitude = l.getLongitude(); latitude = l.getLatitude(); provider = l.getProvider(); } public void onClick(View v) { Toast.makeText(this, "Your location is " + longitude + " and " + latitude + " provided by: " + provider, Toast.LENGTH_SHORT).show(); } }

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  • preparing SMS app for Android KitKat

    - by Pmsc
    in agreement with the recent post from Android Developers http://android-developers.blogspot.pt/2013/10/getting-your-sms-apps-ready-for-kitkat.html ,I was trying to prepare my app to the new android version, but encountered a problem with the part they suggest to create a dialog to let the user set the app as the default application to handle SMS's : Android Developers Post public class ComposeSmsActivity extends Activity { @Override protected void onResume() { super.onResume(); final String myPackageName = getPackageName(); if (!Telephony.Sms.getDefaultSmsPackage(this).equals(myPackageName)) { // App is not default. // Show the "not currently set as the default SMS app" interface View viewGroup = findViewById(R.id.not_default_app); viewGroup.setVisibility(View.VISIBLE); // Set up a button that allows the user to change the default SMS app Button button = (Button) findViewById(R.id.change_default_app); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Intent intent = new Intent(Telephony.Sms.Intents.ACTION_CHANGE_DEFAULT); intent.putExtra(Telephony.Sms.Intents.EXTRA_PACKAGE_NAME, myPackageName); startActivity(intent); } }); } else { // App is the default. // Hide the "not currently set as the default SMS app" interface View viewGroup = findViewById(R.id.not_default_app); viewGroup.setVisibility(View.GONE); } } } the code itself in pretty much straightforward, but I'm unable to access to Telephony.Sms.getDefaultSmsPackage because it says that Telephony cannot be resolved, and I can't find any import or declaration that would fix that. Can anyone please help? Thanks in advanced.

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  • problem in adding image to JFrame

    - by firestruq
    Hi, I'm having problems in adding a picture into JFrame, something is missing probebly or written wrong. here are the classes: main class: public class Tester { public static void main(String args[]) { BorderLayoutFrame borderLayoutFrame = new BorderLayoutFrame(); borderLayoutFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); borderLayoutFrame.setSize(600,600); borderLayoutFrame.setVisible(true); } } public class BorderLayoutFrame extends JFrame implements ActionListener { private JButton buttons[]; // array of buttons to hide portions private final String names[] = { "North", "South", "East", "West", "Center" }; private BorderLayout layout; // borderlayout object private PicPanel picture = new PicPanel(); // set up GUI and event handling public BorderLayoutFrame() { super( "Philosofic Problem" ); layout = new BorderLayout( 5, 5 ); // 5 pixel gaps setLayout( layout ); // set frame layout buttons = new JButton[ names.length ]; // set size of array // create JButtons and register listeners for them for ( int count = 0; count < names.length; count++ ) { buttons[ count ] = new JButton( names[ count ] ); buttons[ count ].addActionListener( this ); } add( buttons[ 0 ], BorderLayout.NORTH ); // add button to north add( buttons[ 1 ], BorderLayout.SOUTH ); // add button to south add( buttons[ 2 ], BorderLayout.EAST ); // add button to east add( buttons[ 3 ], BorderLayout.WEST ); // add button to west add( picture, BorderLayout.CENTER ); // add button to center } // handle button events public void actionPerformed( ActionEvent event ) { } } I'v tried to add the image into the center of layout. here is the image class: public class PicPanel extends JPanel { Image img; private int width = 0; private int height = 0; public PicPanel() { super(); img = Toolkit.getDefaultToolkit().getImage("table.jpg"); } public void paintComponent(Graphics g) { super.paintComponents(g); if ((width <= 0) || (height <= 0)) { width = img.getWidth(this); height = img.getHeight(this); } g.drawImage(img,0,0,width,height,this); } } Please your help, what is the problem? thanks BTW: i'm using eclipse, which directory the image suppose to be in?

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  • Refresh browser???????????????????????????

    - by Ritz
    hello all, I am working with images and changing their sizes dynamically from the input I get from the user. when I change the size of the image first time it doesnot reflect the changes when I click the refresh the page using the browser button the change gets reflected and after that tere is no need to click the refresh button Please tell how shall I do it so that there is no need to click the refresh button of the browser ,the changes but get reflected at one shot. Thanks Ritz

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  • How to put a background image on GridBagLayout

    - by Loligans
    I am trying to work with layout managers for the first time, and they are just kicking me in the teeth. I am trying to make a background image and then put buttons on top, using GridBagLayout, if there is a a better layoutmanager please do tell. As for trying to learn how to use layout managers, its very difficult and any learning references would also be much appreciated. This is what it looks like currently, I can get the frame to show the full image, but when i use gridlayout manager, it does that public void addComponentsToPane(Container pane){ BackgroundImage image = new BackgroundImage(); JButton button1, button2, button3, button4, button5; pane.setLayout(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); if(shouldFill){ c.fill = GridBagConstraints.NONE; } button1 = new JButton("Button 1"); if (shouldWeightX) { c.weightx = 0.5; } c.fill = GridBagConstraints.HORIZONTAL; c.gridx = 1; c.gridy = 0; button1.setOpaque(false); pane.add(button1, c); button2 = new JButton("Button 2"); c.fill = GridBagConstraints.HORIZONTAL; c.weightx = 0.5; c.gridx = 0; c.gridy = 0; button2.setOpaque(false); pane.add(button2, c); button3 = new JButton("Button 3"); c.fill = GridBagConstraints.HORIZONTAL; c.weightx = 0.5; c.gridx = 2; c.gridy = 0; button3.setOpaque(false); pane.add(button3, c); button4 = new JButton("Long-Named Button 4"); c.fill = GridBagConstraints.HORIZONTAL; c.ipady = 40; //make this component tall c.weightx = 0.0; c.gridwidth = 3; c.gridx = 0; c.gridy = 1; pane.add(button4, c); button5 = new JButton("button 1"); c.fill = GridBagConstraints.HORIZONTAL; c.ipady = 0; //reset to default c.weighty = 1.0; //request any extra vertical space c.anchor = GridBagConstraints.PAGE_END; //bottom of space c.insets = new Insets(10,0,0,0); //top padding c.gridx = 1; //aligned with button 2 c.gridwidth = 2; //2 columns wide c.gridy = 2; //third row pane.add(button5, c); c.ipadx = 800; c.ipady = 400; pane.add(image, c); } This is what i'm trying to make it look like

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  • How to instantiate JQuery UI widget by string?

    - by limcheekin
    Hi there, Do you know how to instantiate JQuery UI widget by string? Let's illustrate it with some sample code. Given the html link element below: <a id="testLink" href="#">Test Link</a> Normally, we can make it into button using code below: $('#testLink').button(); What if I want to instantiate the button with string, for example: var widget='button'; $('#testLink').[widget](); Of course the code block above is not working (It is just for illustration purpose only), otherwise you will not see this question. Please advice. Thanks, Chee Kin

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  • Flex 4 animation question

    - by Jerry
    Hello.. I am trying to do the move vertically animation on a button nested in the vertical layout. I am not sure if the Hgroup restricts the button moving vertically. Are there ways to go around it? Thanks for the helps. <s:states> <s:State name="default"/> <s:State name="addRecommend"/> <s:State name="seeOther"/> </s:states> AS: protected function add_clickHandler(event:MouseEvent):void { currentState="addRecommend"; addRecommendMove.play(); } <s:transitions> <s:Transition fromState="default" toState="addRecommend"> <s:Sequence id="addRecommendMove"> <s:Move yTo="50" target="{add}"/> // add button doesn't move at all </s:Sequence> </s:Transition> <s:Transition fromState="addRecommend" toState="seeOther"> <s:Sequence> <s:Move yBy="50" target="{seeOthers}"/> </s:Sequence> </s:Transition> </s:transitions> <s:layout> <s:VerticalLayout paddingTop="15" paddingRight="10" paddingLeft="7"/> </s:layout> <button id="add" click=add_clickHandler(event)/> <button id="seeOthers"/>

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  • User control or custom control for this design?

    - by m0s
    If I want to create a button control like that, is it supposed to be a User Control or a Custom Control? I am not sure maybe something else? Ideally I want to be able style/animate the main button and the inner button separately; also obviously Ill need to process their events separately. These buttons will be created at run-time and Ill need to set the icons dynamically.

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  • problem with dropdown in jsp

    - by Deven
    hello friends i am having three drop downs and button in my web page naming 1st 2nd and 3rd in which the value of 2nd depends on 1st and value of 3rd depends on 2dn its done using ajax now when i click on the button it calls one function of ajax which takes value from database and then select value at 1st dropdown and then fire on change event using fireEvent() function which is used to set values in 2nd dropdown and then the function called at button now select value at 2nd dropdown and then fire on change event using fireEvent() function which is used to set values in 3rd dropdown The main problem is that when i click on button it set value in 1st dropdown but 2nd and 3rd dropdown shows blank values

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  • wxHaskell on OS X

    - by Bill
    I want to use wxHaskell on OS X (Snow Leopard, MacBook Pro). I was able to install the library successfully and the script below: module Main where import Graphics.UI.WX main :: IO () main = start hello hello :: IO () hello = do f <- frame [text := "Hello!"] quit <- button f [text := "Quit", on command := close f] set f [layout := widget quit] does result in a window being displayed with a single button, as specified. However, nothing happens when I click the button - I don't even get the visual response of the button turning blue to indicate that it's been depressed (haha, no pun intended). I've heard that you have to run a package called "macosx-app" on wxHaskell binaries to get them to run, but I can't find this anywhere. It's not on my machine or (as far as I can tell) in the WX or wxHaskell distros. Anyone know what I need to do to get this to work?

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  • Hiding/blocking tabs using windows forms in c#

    - by Audel
    The thing is that i have a 'log in window' and a 'mainwindow' that is called after pressing the log in button or the "VISITANT" button If pressing the log in button, the whole system will come out, and if i press the VISITANT button, one tab should disappear or be blocked or something. private void visitant(object sender, EventArgs e) { mainwindow menu = new mainwindow(); menu.Show(); //mainwindow.tabPage1.Enabled = false; //attempt1 //mainwindow.tabPage1.Visible = false; //attempt1 //System.Windows.Forms.tabPage1.Enabled = false;//attempt2 //System.Windows.Forms.tabPage1.Visible = false;//attempt2 this.Hide(); } the errors i get for using the attempt1 are Error 1 'System.mainwindow.tabPage1' is inaccessible due to its protection level' Error 2 An object reference is required for the non-static field, method, or property 'System.mainwindow.tabPage1' and the one i get for using the attempt2 is Error 1 The type or namespace name 'tabPage1' does not exist in the namespace 'System.Windows.Forms' (are you missing an assembly reference?) as you probably have guessed "tabPage1" is the tab i need to hide when pressing the visitant button. I can't think of any more details, I will be around to provide any extra information Thanks in advance.

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  • icon as an image

    - by Ken
    Hi All, is it possible to use icon file as a image for a button in visual basic? f.e. I have 3 buttons that need to have 3 icons when you click the button the icon of the button needs to be the icon of the form is this posible? btnIcon1 = my.resources.ICO1 btnIcon2 = my.resources.ICO2

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  • Automatic login into asp.net site from flash movie

    - by IrfanRaza
    Hello friends, I have a landing page designed as a flash movie. Please visit http://ivautoinc.com. The movie contains login button. For now when you click on this button I am redirecting to asp.net site login page. What I need is if you click on login button, the login form which is designed within flash will be shown on the same movie. The users will provide username and password. As soon as they press OK button they should see the page from my asp.net site as it is displayed after loggin in. Can anybody help me? Thanks for sharing your valuable time.

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  • How to achieve table like rows within container using CSS

    - by Barry
    I'm helping an artist maintain her website and have inherited some pretty outdated code. Have moved lots of redundant common code to include files and am now working on moving from inline styles to more CSS-driven styles. For the gallery pages, e.g. http://artistsatlaketahoe.com/abstract.html, a lot of inline styling is used to force the current layout. My preference would be to replace this entirely with CSS that presents the following table-like layout within the "content" div: [image] [image descriptives and purchase button] [image] [image descriptives and purchase button] [image] [image descriptives and purchase button] I'd like to middle-align the image descriptives & purchase button relative to the image if possible. And then apply some padding above and below each row to stop using tags for vertical spacing. Any ideas how to create a div that I can use to get this kind of layout? Thanks!

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  • Using Javascript, How do I bring an already existing open window to the front on top of other window

    - by user268249
    The question was fairly descriptive but I'll describe it further. Basically, I have Window1, clicking a button link opens window2. Clicking a button in window2 opens window3, clicking a button in window3 should bring window2 back to the front of the screen on top of window2. I'm not sure how this is exactly done, however I have used and played around with focus(), opener and other various methods and I cannot seem to get it to work properly. Thanks for any help in advance!

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  • Making a login Using JavaScript, Will Incorporate PHP Later

    - by TIMOTHY
    not sure why my code wont work, im teaching myself javascript i know php moderatly and i also know the intelligence of using java to hold a password and username, but at the moment i just want the script to work. <html> <head> <title>34webs</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" media="screen" href="main.css"> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> <script type="javascript" > function logintry (){ var usern = document.logn.username.value; var passw = document.logn.password.value; if(usern == blue && passw == bluee){ alert('password is correct!'); }else{ alert('password is wrong'); } } </script> </head> <body> <div id="bod"> <div id="nav"> <p id="buttonhead">34 web</p> <a href="#" class="button">HOME</a> <a href="#" class="button">NEWS</a> <a href="#" class="button">DOWNLOADS</a> <a href="#" class="button">ERA</a> <a href="#" class="button">IE BROWSER</a> <a href="#" class="button">DRIVERS</a> <form name="logn"> <table style="margin:0 auto; background:#0174DF; color:white;"> <tr> <td> Username<br> <input type="text" name="username" value=""> </td> </tr> <tr> <td> Password<br> <input type="password" name="password" value=""> </td> </tr> <tr> <td style="text-align:center;"> <input type="button" name="Submit" value="submit" onclick= javascript: logintry()> </td> </tr> </table> </form> </div>

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  • Need to have an aspx page with a Feature in SharePoint 2010

    - by camit90
    I have added a custom button to the server ribbon in SharePoint (I have used a feature with Farm scope, so that the button is visible throughout the various site collections). For the elements of the feature, I have added a CustomUIExtension through which I want to load an aspx page on the click of the button. <CommandUIHandler Command="Test_Button" CommandAction="javascript: function demoCallback(dialogResult, returnValue) { SP.UI.Notify.addNotification('Operation Successful!'); SP.UI.ModalDialog.RefreshPage(SP.UI.DialogResult.OK); } var options = { url: '/_layouts/CustomPage.aspx', tite: 'Custom Page', dialogReturnValueCallback: demoCallback }; SP.UI.ModalDialog.showModalDialog(options);" /> I have added the CustomPage.aspx and its corresponding code behind class to the 14 hive (inside 14/TEMPLATE/LAYOUTS). However when I install the feature and click the button, I get an error saying "Cannot load CustomPage". I understand that I haven't deployed the assembly, but shouldn't the aspx page be compiled Just In Time?

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  • WPF Buttons Style

    - by Polaris
    I have WPF Form which has many buttons with the same code. Appearance of all buttons must be the same For example, code for one of these buttons <Button x:Name="btnAddRelative" Width="120" Click="btnAddRelative_Click" > <Button.Content> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" Add Relative" Height="20" VerticalAlignment="Center"/> </StackPanel> </Button.Content> </Button> How can I create one style and use it for all my buttons. All buttons has the same png image, only their text different. How can I do this. I tried to do this with Style object in Resource Section: <UserControl.Resources> <Style TargetType="Button" x:Key="AddStyle"> <Setter Property="Content"> <Setter.Value> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" " Height="20" VerticalAlignment="Center"/> </StackPanel> </Setter.Value> </Setter> </Style> </UserControl.Resources> But this code not work. Can any body know how can I do this?

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  • How to limit the number of the same Activity on the stack for an Android application

    - by johnrock
    Is this possible in an Android app? I want to make it so that no matter how many times a user starts activityA, when they hit the back button they will never get more than one occurence of activityA. What I am finding in my current code is that I have only two options: 1. I can call finish() in activityA which will prevent it from being accessible via the back button completely, or 2. I do not call finish(), and then if the user starts activityA (n) times during their usage, there will be (n) instances when hitting the back button. Again, I want to have activityA accessible by hitting the back button, but there is no reason to keep multiple instances of the same activity on the stack. Is there a way to limit the number of instances of an activity in the queue to only 1?

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