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  • Javascript ( jQuery ) Error: SyntaxError: missing ) after argument list

    - by Obmerk Kronen
    I have the simplest function : jQuery(document).ajaxSuccess(function(e, xhr, settings) { var widget_id_base = '099_cf_samurai_widget'; if(settings.data.search('action=save-widget') != -1 && settings.data.search('id_base=' + widget_id_base) != -1) { // alert(\'yay!'\); my_function_chosen_099(); } }); function my_function_chosen_099(){ jQuery(".chzn-select").chosen(); } which works just fine , but When I add the width Parameter like so : function my_function_chosen_k99(){ jQuery(".chzn-select").chosen(width:'95%'); } it gives me an error of: Error: SyntaxError: missing ) after argument list Source File: http://localhost/my-path/js/o99.chosen.init.js?ver=k99 Line: 20, Column: 41 Source Code: jQuery(".chzn-select").chosen(width:"95%"); .............................................| I have tried escaping: jQuery(".chzn-select").chosen(width:\"95%"\); and even double jQuery(".chzn-select").chosen(width:\\"95%"\\); and in my desperation, even jQuery(".chzn-select").chosen( width:"95%" ); I checked and rechecked the closing of brackets , and also tried with single quotes ' - but nothing . There appear to be a lot of similar questions here , but all I saw was escaping problems, ANd I have tried all that I know .. What is wrong here ?? I assume it is not a simple syntax error - or is it ? ( one which I can not find .. )

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  • Heapsort not working in Python for list of strings using heapq module

    - by VSN
    I was reading the python 2.7 documentation when I came across the heapq module. I was interested in the heapify() and the heappop() methods. So, I decided to write a simple heapsort program for integers: from heapq import heapify, heappop user_input = raw_input("Enter numbers to be sorted: ") data = map (int, user_input.split(",")) new_data = [] for i in range(len(data)): heapify(data) new_data.append(heappop(data)) print new_data This worked like a charm. To make it more interesting, I thought I would take away the integer conversion and leave it as a string. Logically, it should make no difference and the code should work as it did for integers: from heapq import heapify, heappop user_input = raw_input("Enter numbers to be sorted: ") data = user_input.split(",") new_data = [] for i in range(len(data)): heapify(data) print data new_data.append(heappop(data)) print new_data Note: I added a print statement in the for loop to see the heapified list. Here's the output when I ran the script: `$ python heapsort.py Enter numbers to be sorted: 4, 3, 1, 9, 6, 2 [' 1', ' 3', ' 2', ' 9', ' 6', '4'] [' 2', ' 3', '4', ' 9', ' 6'] [' 3', ' 6', '4', ' 9'] [' 6', ' 9', '4'] [' 9', '4'] ['4'] [' 1', ' 2', ' 3', ' 6', ' 9', '4']` The reasoning I applied was that since the strings are being compared, the tree should be the same if they were numbers. As is evident, the heapify didn't work correctly after the third iteration. Could someone help me figure out if I am missing something here? I'm running Python 2.4.5 on RedHat 3.4.6-9. Thanks, VSN

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  • list all files from directories and subdirectories in Java

    - by Adnan
    What would be the fastest way to list the names of files from 1000+ directories and sub-directories? EDIT; The current code I use is: import java.io.File; public class DirectoryReader { static int spc_count=-1; static void Process(File aFile) { spc_count++; String spcs = ""; for (int i = 0; i < spc_count; i++) spcs += " "; if(aFile.isFile()) System.out.println(spcs + "[FILE] " + aFile.getName()); else if (aFile.isDirectory()) { System.out.println(spcs + "[DIR] " + aFile.getName()); File[] listOfFiles = aFile.listFiles(); if(listOfFiles!=null) { for (int i = 0; i < listOfFiles.length; i++) Process(listOfFiles[i]); } else { System.out.println(spcs + " [ACCESS DENIED]"); } } spc_count--; } public static void main(String[] args) { String nam = "D:/"; File aFile = new File(nam); Process(aFile); } }

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  • C# Passing objects and list of objects by reference

    - by David Liddle
    I have a delegate that modifies an object. I pass an object to the delegate from a calling method, however the calling method does not pickup these changes. The same code works if I pass a List as the object. I thought all objects were passed by reference so any modifications would be reflected in the calling method? I can modify my code to pass a ref object to the delegate but am wondering why this is necessary? public class Binder { protected delegate int MyBinder<T>(object reader, T myObject); public void BindIt<T>(object reader, T myObject) { //m_binders is a hashtable of binder objects MyBinder<T> binder = m_binders["test"] as MyBinder<T>; int i = binder(reader, myObject); } } public class MyObjectBinder { public MyObjectBinder() { m_delegates["test"] = new MyBinder<MyObject>(BindMyObject); } private int BindMyObject(object reader, MyObject obj) { //make changes to obj in here } } ///calling method in some other class public void CallingMethod() { MyObject obj = new MyObject(); MyBinder binder = new MyBinder(); binder.BindIt(myReader, obj); //don't worry about myReader //obj should show reflected changes }

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  • how to merge two ordered list of objects?

    - by bhavna raghuvanshi
    public class ListMerge { public static void main( String[] args) { Scanner input = new Scanner(System.in); System.out.println ("Input length of arraylist 1:"); int n = input.nextInt(); ArrayList x = new ArrayList(); ArrayList y = new ArrayList(); for (int i = 0; i < n; i++) { System.out.println ("Input x[ " + i +"] :" ); x.add(new Integer(i)); } System.out.println ("Input length of arraylist 2:"); int m = input.nextInt(); for (int i = 0; i < m; i++) { System.out.println ("Input y[ " + i +"] :" ); y.add(new Integer(i)); } List<Integer> all = new ArrayList<Integer>(); all.addAll(x); all.addAll(y); System.out.println(all); } } I did this but its not taking values from user. pls tell me why....

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  • How to center a List(ul)

    - by BlackPearl
    I have a ul List that contain some li elements and I float them to left. It currently looks like below; | A | B | C | D | E < space empty| I want it to be | A | B | C | D | E | that is center on the page and contents should be centered too HTML <div class="profile-content"> <ul class="content-btn"> <li> <div class="digits">83</div>Followers </li> <li> <div class="digits">1507</div>Tweets </li> <li> <div class="digits">234</div>Friends </li> <li> <div class="digits">51</div>Likes </li> <li> <div class="digits">42</div>Gits </li> </ul> <div class="clear"></div> </div> CSS .content-btn { width:100%; margin: 0 auto; } .profile-content ul li { float: left; padding: 5px 8px; text-align: center; border-right: 1px solid #eeeeee; border-left: 1px solid #ffffff; } .profile-content ul li .digits { font-weight: bold; font-size: 16px; }

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  • Best way to add tr element mid-way through a list of table rows - jQuery

    - by soulBit
    Hi all, first post on the site! I'm looking for some help inserting tr elements mid-way through a simple table like the one below: <table id="content"> <tr class="item"> <td><p>header content</p></td> </tr> <tr class="item"> <td><p>footer content</p></td> </tr> </table> I am adding elements using jQuery with the following code: $('<tr class="item" />').insertAfter('#content tr:first'); However after adding an element using this command, I would like to add some more (but after the last added item, not at the top of the list) Im sure there are simple ways of doing this (by assigning an id to the footer element, and using .insertBefore('#footer') for example) but it would be interesting to know some different techniques that could be used. Thanks in advance! :)

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  • List View Array from Database

    - by leenolasco
    I have retrieved data and successfully shown it in text view. What do i modify in my codes to make it look like a list view? And also how do modify my listview programatically(adding size and padding)? Here is my a part of my DBclass in selecting the items that I've displayed getFAData() { // TODO Auto-generated method stub String [] columns = new String[]{Row_Name}; Cursor c = ourDB.query(db_Table, columns, null, null, null, null, null); String res = ""; int iRow = c.getColumnIndex(Row_Name); //int iDesc = c.getColumnIndex(Row_Desc); //int iID = c.getColumnIndex(Row_id); for (c.moveToFirst(); !c.isAfterLast(); c.moveToNext()) { res = res + c.getString(iRow) + "\n"; } return res; } And here is class file: public class FirstAid extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.firstaid); displayresult(); } public void displayresult (){ TextView tvFa = (TextView) findViewById(R.id.tvFA); tvFa.setMovementMethod(new ScrollingMovementMethod()); DbHelper tblFa = new DbHelper(this); tblFa.open(); String result = tblFa.getFAData(); tblFa.close(); tvFa.setText(result); } }

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  • Cannot get list of elements using Linq to XML

    - by Blackator
    Sample XML: <CONFIGURATION> <Files> <File>D:\Test\TestFolder\TestFolder1\TestFile.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile01.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile02.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile03.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile04.txt</File> </Files> <SizeMB>3</SizeMB> <BackupLocation>D:\Log backups\File backups</BackupLocation> </CONFIGURATION> I've been doing some tutorials but I am unable to get all the list of file inside the files element. It only shows the first element and doesn't display the rest. This is my code: var fileFolders = from file in XDocument.Load(@"D:\Hello\backupconfig1.xml").Descendants("Files") select new { File = file.Element("File").Value }; foreach (var fileFolder in fileFolders) { Console.WriteLine("File = " + fileFolder.File); } How do I display all the File in the Files element, the SizeMB and BackupLocation? Thanks

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  • Python: Determine whether list of lists contains a defined sequence

    - by duhaime
    I have a list of sublists, and I want to see if any of the integer values from the first sublist plus one are contained in the second sublist. For all such values, I want to see if that value plus one is contained in the third sublist, and so on, proceeding in this fashion across all sublists. If there is a way of proceeding in this fashion from the first sublist to the last sublist, I wish to return True; otherwise I wish to return False. In other words, for each value in sublist one, for each "step" in a "walk" across all sublists read left to right, if that value + n (where n = number of steps taken) is contained in the current sublist, the function should return True; otherwise it should return False. (Sorry for the clumsy phrasing--I'm not sure how to clean up my language without using many more words.) Here's what I wrote. a = [ [1,3],[2,4],[3,5],[6],[7] ] def find_list_traversing_walk(l): for i in l[0]: index_position = 0 first_pass = 1 walking_current_path = 1 while walking_current_path == 1: if first_pass == 1: first_pass = 0 walking_value = i if walking_value+1 in l[index_position + 1]: index_position += 1 walking_value += 1 if index_position+1 == len(l): print "There is a walk across the sublists for initial value ", walking_value - index_position return True else: walking_current_path = 0 return False print find_list_traversing_walk(a) My question is: Have I overlooked something simple here, or will this function return True for all true positives and False for all true negatives? Are there easier ways to accomplish the intended task? I would be grateful for any feedback others can offer!

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  • Silverlight Tree View with Multiple Levels

    - by psheriff
    There are many examples of the Silverlight Tree View that you will find on the web, however, most of them only show you how to go to two levels. What if you have more than two levels? This is where understanding exactly how the Hierarchical Data Templates works is vital. In this blog post, I am going to break down how these templates work so you can really understand what is going on underneath the hood. To start, let’s look at the typical two-level Silverlight Tree View that has been hard coded with the values shown below: <sdk:TreeView>  <sdk:TreeViewItem Header="Managers">    <TextBlock Text="Michael" />    <TextBlock Text="Paul" />  </sdk:TreeViewItem>  <sdk:TreeViewItem Header="Supervisors">    <TextBlock Text="John" />    <TextBlock Text="Tim" />    <TextBlock Text="David" />  </sdk:TreeViewItem></sdk:TreeView> Figure 1 shows you how this tree view looks when you run the Silverlight application. Figure 1: A hard-coded, two level Tree View. Next, let’s create three classes to mimic the hard-coded Tree View shown above. First, you need an Employee class and an EmployeeType class. The Employee class simply has one property called Name. The constructor is created to accept a “name” argument that you can use to set the Name property when you create an Employee object. public class Employee{  public Employee(string name)  {    Name = name;  }   public string Name { get; set; }} Finally you create an EmployeeType class. This class has one property called EmpType and contains a generic List<> collection of Employee objects. The property that holds the collection is called Employees. public class EmployeeType{  public EmployeeType(string empType)  {    EmpType = empType;    Employees = new List<Employee>();  }   public string EmpType { get; set; }  public List<Employee> Employees { get; set; }} Finally we have a collection class called EmployeeTypes created using the generic List<> class. It is in the constructor for this class where you will build the collection of EmployeeTypes and fill it with Employee objects: public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;            type = new EmployeeType("Manager");    type.Employees.Add(new Employee("Michael"));    type.Employees.Add(new Employee("Paul"));    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} You now have a data hierarchy in memory (Figure 2) which is what the Tree View control expects to receive as its data source. Figure 2: A hierachial data structure of Employee Types containing a collection of Employee objects. To connect up this hierarchy of data to your Tree View you create an instance of the EmployeeTypes class in XAML as shown in line 13 of Figure 3. The key assigned to this object is “empTypes”. This key is used as the source of data to the entire Tree View by setting the ItemsSource property as shown in Figure 3, Callout #1. Figure 3: You need to start from the bottom up when laying out your templates for a Tree View. The ItemsSource property of the Tree View control is used as the data source in the Hierarchical Data Template with the key of employeeTypeTemplate. In this case there is only one Hierarchical Data Template, so any data you wish to display within that template comes from the collection of Employee Types. The TextBlock control in line 20 uses the EmpType property of the EmployeeType class. You specify the name of the Hierarchical Data Template to use in the ItemTemplate property of the Tree View (Callout #2). For the second (and last) level of the Tree View control you use a normal <DataTemplate> with the name of employeeTemplate (line 14). The Hierarchical Data Template in lines 17-21 sets its ItemTemplate property to the key name of employeeTemplate (Line 19 connects to Line 14). The source of the data for the <DataTemplate> needs to be a property of the EmployeeTypes collection used in the Hierarchical Data Template. In this case that is the Employees property. In the Employees property there is a “Name” property of the Employee class that is used to display the employee name in the second level of the Tree View (Line 15). What is important here is that your lowest level in your Tree View is expressed in a <DataTemplate> and should be listed first in your Resources section. The next level up in your Tree View should be a <HierarchicalDataTemplate> which has its ItemTemplate property set to the key name of the <DataTemplate> and the ItemsSource property set to the data you wish to display in the <DataTemplate>. The Tree View control should have its ItemsSource property set to the data you wish to display in the <HierarchicalDataTemplate> and its ItemTemplate property set to the key name of the <HierarchicalDataTemplate> object. It is in this way that you get the Tree View to display all levels of your hierarchical data structure. Three Levels in a Tree View Now let’s expand upon this concept and use three levels in our Tree View (Figure 4). This Tree View shows that you now have EmployeeTypes at the top of the tree, followed by a small set of employees that themselves manage employees. This means that the EmployeeType class has a collection of Employee objects. Each Employee class has a collection of Employee objects as well. Figure 4: When using 3 levels in your TreeView you will have 2 Hierarchical Data Templates and 1 Data Template. The EmployeeType class has not changed at all from our previous example. However, the Employee class now has one additional property as shown below: public class Employee{  public Employee(string name)  {    Name = name;    ManagedEmployees = new List<Employee>();  }   public string Name { get; set; }  public List<Employee> ManagedEmployees { get; set; }} The next thing that changes in our code is the EmployeeTypes class. The constructor now needs additional code to create a list of managed employees. Below is the new code. public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;    Employee emp;    Employee managed;     type = new EmployeeType("Manager");    emp = new Employee("Michael");    managed = new Employee("John");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Tim");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);     emp = new Employee("Paul");    managed = new Employee("Michael");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Sara");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} Now that you have all of the data built in your classes, you are now ready to hook up this three-level structure to your Tree View. Figure 5 shows the complete XAML needed to hook up your three-level Tree View. You can see in the XAML that there are now two Hierarchical Data Templates and one Data Template. Again you list the Data Template first since that is the lowest level in your Tree View. The next Hierarchical Data Template listed is the next level up from the lowest level, and finally you have a Hierarchical Data Template for the first level in your tree. You need to work your way from the bottom up when creating your Tree View hierarchy. XAML is processed from the top down, so if you attempt to reference a XAML key name that is below where you are referencing it from, you will get a runtime error. Figure 5: For three levels in a Tree View you will need two Hierarchical Data Templates and one Data Template. Each Hierarchical Data Template uses the previous template as its ItemTemplate. The ItemsSource of each Hierarchical Data Template is used to feed the data to the previous template. This is probably the most confusing part about working with the Tree View control. You are expecting the content of the current Hierarchical Data Template to use the properties set in the ItemsSource property of that template. But you need to look to the template lower down in the XAML to see the source of the data as shown in Figure 6. Figure 6: The properties you use within the Content of a template come from the ItemsSource of the next template in the resources section. Summary Understanding how to put together your hierarchy in a Tree View is simple once you understand that you need to work from the bottom up. Start with the bottom node in your Tree View and determine what that will look like and where the data will come from. You then build the next Hierarchical Data Template to feed the data to the previous template you created. You keep doing this for each level in your Tree View until you get to the last level. The data for that last Hierarchical Data Template comes from the ItemsSource in the Tree View itself. NOTE: You can download the sample code for this article by visiting my website at http://www.pdsa.com/downloads. Select “Tips & Tricks”, then select “Silverlight TreeView with Multiple Levels” from the drop down list.

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  • How to get my list of rows from database to show while using Zend-Paginator

    - by Matto
    I'm fairly new to the world of Zend-Framework, and have taken over a site that is in zend-framework. There is a bug on one of the pages right now and I can not figure it out. I think it has something to do with Zend Paginator, but not sure. This is the code in the controller for the section I am having a problem with: $currentPage = $this->_getParam('page'); $numWebsitesFullOnline = $websites->getWebsitesFullOnline(); $select = $websites->select(); $select->setIntegrityCheck(false); $select->from(array('w' => 'websites'), array('id', 'online', 'kw_adjective', 'kw_name', 'kw_location', 'url', 'email', 'address', 'ftp_server', 'ftp_username', 'ftp_password', 'ftp_folder', 'phone_number', 'indexed', 'youtube_position', 'twitter_user', 'facebook_id', 'video_made', 'image1_id', 'image2_id', 'image3_id', 'bg_color', 'dark_color', 'light_color', 'links_color', 'text_color', 'google_account', 'ganalytics', 'gmaps_status', 'google_position', 'gmap_position', 'hp1', 'hp2', 'hp3', 'hp4', 'hp5', 'hp6', 'hp7', 'hp8', 'hp9', 'hp10', 'about1_id', 'about2_id', 'about3_id', 'tip1_id', 'tip2_id', 'tip3_id', 'contact_texts_id', 'quote_texts_id', 'demographics_id')) ->join(array('d' => 'demographics'), 'w.demographics_id = d.id', array('total_population')) ->order(array('total_population DESC', 'kw_location')); $paginator = new Zend_Paginator(new Zend_Paginator_Adapter_DbSelect($select)); $paginator->setItemCountPerPage(50); $paginator->setCurrentPageNumber($currentPage); $paginator->setPageRange(($paginator->getTotalItemCount() / 50) + 1); $this->view->paginator = $paginator; $numWebsitesOnline = $websites->getWebsitesOnline(); On the php page I have this code to call the websites that are in the database to a list: <p class="red"> Websites online: <?php echo $this->numOnline; ?> </p> <?php print_r(count($this->paginator)); ?> <?php if(count($this->paginator)): ?> <table class="table-list"> <?php foreach($this->paginator as $item): ?> <tr> <?php if($this->userIsAllowedAction('websites', 'reload')): ?> <td class="center noborder w30"> <img class="hidden" src="<?php echo $this->baseUrl() . '/images/loader.gif' ?>" alt="Loading..."/><a class="reload" title="refresh" href="<?php echo $this->baseUrl(); ?>/utils/ui/refresh-website.php" rel="<?php echo urlencode('http://' . $item['url'] . '/install.php'); ?>,<?php echo urlencode($item['ftp_server']); ?>,<?php echo $item['ftp_username']; ?>,<?php echo $item['ftp_password']; ?>,<?php echo $item['ftp_folder']; ?>,<?php echo $this->baseUrl(); ?>,<?php echo $item['id']; ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-refresh.png" alt="Refresh"/></a> </td> <?php endif; ?> <td class="center noborder w30"> <?php if($this->userIsAllowedAction('websites', 'edit')): ?><a title="Edit" href="<?php echo $this->url(array('controller' => 'websites', 'action' => 'edit', 'id' => $item['id'])); ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-edit.png" alt="Edit"/></a><?php endif; ?> </td> <td class="center noborder w30"> <?php if($this->userIsAllowedAction('websites', 'remove')): ?><a title="Remove" href="<?php echo $this->url(array('controller' => 'websites', 'action' => 'remove', 'id' => $item['id'])); ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-delete.png" alt="Remove"/></a><?php endif; ?> </td> <td> <?php if($item['online']): ?> <span class="hidden"><?php echo trim($this->escape($item['kw_adjective'] . $item['kw_name'])); ?></span><a class="goto-website" href="http://<?php echo $item['url']; ?>" target="_blank"><?php echo $this->escape($item['kw_location']); ?></a> <?php else: ?> <?php echo $this->escape($item['kw_location']); ?> <?php endif; ?> </td> <td class="center population"> <?php if($item['total_population'] >= 0) echo $item['total_population']; ?> </td> <td class="center"> <?php if(!empty($item['url'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['email'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['demographics_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['hp1'] && $item['hp2'] && $item['hp3'] && $item['hp4'] && $item['hp5'] && $item['hp6'] && $item['hp7'] && $item['hp8'] && $item['hp9'] && $item['hp10'] && $item['about1_id'] && $item['about2_id'] && $item['about3_id'] && $item['tip1_id'] && $item['tip2_id'] && $item['tip3_id'] && $item['contact_texts_id'] && $item['quote_texts_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(file_exists($_SERVER['DOCUMENT_ROOT'] . $this->baseUrl() . Zend_Registry::get('assets_base_path') . '/' . $item['id'] . '/header.jpg')): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(($item['bg_color'] != '' && $item['bg_color'] != 'e6e6e6') || ($item['dark_color'] != '' && $item['dark_color'] != '003e75') || ($item['light_color'] != '' && $item['light_color'] != '3073ad') || ($item['links_color'] != '' && $item['links_color'] != '255593') || ($item['text_color'] != '' && $item['text_color'] != '4f4f4f')): ?> <img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/> <?php endif; ?> </td> <td class="center"> <?php if($item['image1_id'] && $item['image2_id'] && $item['image3_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['twitter_user'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['facebook_id'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['phone_number'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['google_account']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['video_made']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['youtube_position']) { echo $item['youtube_position']; }; ?> </td> <td class="center"> <?php if(!empty($item['address'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['gmaps_status'] == 1): ?><img src="<?php echo $this->baseUrl(); ?>/images/icon-gmapspending.png" alt="Pending"/><?php elseif($item['gmaps_status'] == 2): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['ganalytics'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['online']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark_red.png" alt="Online!"/><?php endif; ?> </td> <td class="center"> <?php if($item['indexed']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark_red.png" alt="Online!"/><?php endif; ?> </td> <td class="center"> <?php if($item['gmap_position']) { echo $item['gmap_position']; }; ?> </td> <td class="center"> <?php if($item['google_position']) { echo $item['google_position']; }; ?> </td> </tr> <?php endforeach; ?> </table> <?php endif; ?> The print_r(count($this-paginator)); line is returning "0", and the $this-numOnline; line is returning 1. So it sees that there is one row in the websites table of the database, but it is not returning anything to page and listing out the rows in the websites table. Not sure if this is the paginator that is causing this cause it is returning 0 or something else I don't know about.

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  • How to layout class definition when inheriting from multiple interfaces

    - by gabr
    Given two interface definitions ... IOmniWorkItem = interface ['{3CE2762F-B7A3-4490-BF22-2109C042EAD1}'] function GetData: TOmniValue; function GetResult: TOmniValue; function GetUniqueID: int64; procedure SetResult(const value: TOmniValue); // procedure Cancel; function DetachException: Exception; function FatalException: Exception; function IsCanceled: boolean; function IsExceptional: boolean; property Data: TOmniValue read GetData; property Result: TOmniValue read GetResult write SetResult; property UniqueID: int64 read GetUniqueID; end; IOmniWorkItemEx = interface ['{3B48D012-CF1C-4B47-A4A0-3072A9067A3E}'] function GetOnWorkItemDone: TOmniWorkItemDoneDelegate; function GetOnWorkItemDone_Asy: TOmniWorkItemDoneDelegate; procedure SetOnWorkItemDone(const Value: TOmniWorkItemDoneDelegate); procedure SetOnWorkItemDone_Asy(const Value: TOmniWorkItemDoneDelegate); // property OnWorkItemDone: TOmniWorkItemDoneDelegate read GetOnWorkItemDone write SetOnWorkItemDone; property OnWorkItemDone_Asy: TOmniWorkItemDoneDelegate read GetOnWorkItemDone_Asy write SetOnWorkItemDone_Asy; end; ... what are your ideas of laying out class declaration that inherits from both of them? My current idea (but I don't know if I'm happy with it): TOmniWorkItem = class(TInterfacedObject, IOmniWorkItem, IOmniWorkItemEx) strict private FData : TOmniValue; FOnWorkItemDone : TOmniWorkItemDoneDelegate; FOnWorkItemDone_Asy: TOmniWorkItemDoneDelegate; FResult : TOmniValue; FUniqueID : int64; strict protected procedure FreeException; protected //IOmniWorkItem function GetData: TOmniValue; function GetResult: TOmniValue; function GetUniqueID: int64; procedure SetResult(const value: TOmniValue); protected //IOmniWorkItemEx function GetOnWorkItemDone: TOmniWorkItemDoneDelegate; function GetOnWorkItemDone_Asy: TOmniWorkItemDoneDelegate; procedure SetOnWorkItemDone(const Value: TOmniWorkItemDoneDelegate); procedure SetOnWorkItemDone_Asy(const Value: TOmniWorkItemDoneDelegate); public constructor Create(const data: TOmniValue; uniqueID: int64); destructor Destroy; override; public //IOmniWorkItem procedure Cancel; function DetachException: Exception; function FatalException: Exception; function IsCanceled: boolean; function IsExceptional: boolean; property Data: TOmniValue read GetData; property Result: TOmniValue read GetResult write SetResult; property UniqueID: int64 read GetUniqueID; public //IOmniWorkItemEx property OnWorkItemDone: TOmniWorkItemDoneDelegate read GetOnWorkItemDone write SetOnWorkItemDone; property OnWorkItemDone_Asy: TOmniWorkItemDoneDelegate read GetOnWorkItemDone_Asy write SetOnWorkItemDone_Asy; end; As noted in answers, composition is a good approach for this example but I'm not sure it applies in all cases. Sometimes I'm using multiple inheritance just to split read and write access to some property into public (typically read-only) and private (typically write-only) part. Does composition still apply here? I'm not really sure as I would have to move the property in question out from the main class and I'm not sure that's the correct way to do it. Example: // public part of the interface interface IOmniWorkItemConfig = interface function OnExecute(const aTask: TOmniBackgroundWorkerDelegate): IOmniWorkItemConfig; function OnRequestDone(const aTask: TOmniWorkItemDoneDelegate): IOmniWorkItemConfig; function OnRequestDone_Asy(const aTask: TOmniWorkItemDoneDelegate): IOmniWorkItemConfig; end; // private part of the interface IOmniWorkItemConfigEx = interface ['{42CEC5CB-404F-4868-AE81-6A13AD7E3C6B}'] function GetOnExecute: TOmniBackgroundWorkerDelegate; function GetOnRequestDone: TOmniWorkItemDoneDelegate; function GetOnRequestDone_Asy: TOmniWorkItemDoneDelegate; end; // implementing class TOmniWorkItemConfig = class(TInterfacedObject, IOmniWorkItemConfig, IOmniWorkItemConfigEx) strict private FOnExecute : TOmniBackgroundWorkerDelegate; FOnRequestDone : TOmniWorkItemDoneDelegate; FOnRequestDone_Asy: TOmniWorkItemDoneDelegate; public constructor Create(defaults: IOmniWorkItemConfig = nil); public //IOmniWorkItemConfig function OnExecute(const aTask: TOmniBackgroundWorkerDelegate): IOmniWorkItemConfig; function OnRequestDone(const aTask: TOmniWorkItemDoneDelegate): IOmniWorkItemConfig; function OnRequestDone_Asy(const aTask: TOmniWorkItemDoneDelegate): IOmniWorkItemConfig; public //IOmniWorkItemConfigEx function GetOnExecute: TOmniBackgroundWorkerDelegate; function GetOnRequestDone: TOmniWorkItemDoneDelegate; function GetOnRequestDone_Asy: TOmniWorkItemDoneDelegate; end;

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  • ASP.NET MVC 2 generation of the List/Index view

    - by Klas Mellbourn
    ASP.NET MVC 2 has powerful features for generating the model-dependent content of the Edit view (using EditorForModel) and Details view (using DisplayForModel) that automatically utilizes metadata and editor (or display) templates: <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend><%= Html.LabelForModel() %></legend> <%= Html.EditorForModel() %> <p> <input type="submit" value="Save" /> </p> </fieldset> <% } %> However, I cannot find any comparable tools for the "last" step of generating the Index view (a.k.a. the List view). There I have to hard code the columns first in the row representing the headers and then inside the foreach loop: <h2>Index</h2> <table> <tr> <th></th> <th> ID </th> <th> Foo </th> <th> Bar </th> </tr> <% foreach (var item in Model) { %> <tr> <td> <%= Html.ActionLink("Edit", "Edit", new { id=item.ID }) %> | <%= Html.ActionLink("Details", "Details", new { id=item.ID })%> | <%= Html.ActionLink("Delete", "Delete", new { id=item.ID })%> </td> <td> <%= Html.Encode(item.ID) %> </td> <td> <%= Html.Encode(item.Foo) %> </td> <td> <%= Html.Encode(String.Format("{0:g}", item.Bar)) %> </td> </tr> <% } %> </table> What would be the best way to generate the columns (utlizing metadata such as HiddenInput), with the aim of making the Index view as free of model particulars as Edit and Details?

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  • Linq to XML Read and output XML generated from lookup list

    - by Greg S
    I am trying to use XML created from a lookup list in SharePoint as a datasource for a treeview. It is in the form of : <NewDataSet> <test_data> <ID>1</ID> <Title>MenuItem_1</Title> <child_of /> </test_data> <test_data> <ID>2</ID> <Title>Subitem_1</Title> <Action>http://www.google.com</Action> <child_of>MenuItem_1</child_of> </test_data> <test_data> <ID>3</ID> <Title>Subitem_2</Title> <Action>http://www.google.com</Action> <child_of>MenuItem_1</child_of> </test_data> <test_data> <ID>4</ID> <Title>MenuItem_2</Title> <child_of /> </test_data> <test_data> <ID>5</ID> <Title>Subitem_2_1</Title> <Action>http://www.google.com</Action> <child_of>MenuItem_2</child_of> </test_data> <test_data> <ID>6</ID> <Title>Subitem_2_2</Title> <Action>http://www.google.com</Action> <child_of>MenuItem_2</child_of> </test_data> <test_data> <ID>7</ID> <Title>Subitem_2_2_1</Title> <Action>http://www.google.com</Action> <child_of>Subitem_2_2</child_of> </test_data> </NewDataSet> There may be N tiers, but the items relate to the parent via the <child_of> element. I can't seem to figure out how to write the LINQ in C# to nest the menu items properly. A friend recommended I post here. Any help is greatly appreciated.

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  • php recursive list help

    - by Jason
    Hi all, I am trying to display a recursive list in PHP for a site I am working on. I am really having trouble trying to get the second level to display. I have a function that displays the contents to the page as follows. function get_menu_entries($content,$which=0) { global $tbl_prefix, $sys_explorer_vars, $sys_config_vars; // INIT LIBRARIES $db = new DB_Tpl(); $curr_time = time(); $db->query("SELECT * FROM ".$tbl_prefix."sys_explorer WHERE preid = '".$which."' && config_id = '".$sys_explorer_vars['config_id']."' && blocked = '0' && startdate < '".$curr_time."' && (enddate > '".$curr_time."' || enddate = '') ORDER BY preid,sorting"); while($db->next_record()){ $indent = $db->f("level") * 10 - 10; $sitemap_vars['break'] = ""; $sitemap_vars['bold'] = ""; if($db->f("level") == 2) { $sitemap_vars['ul_start'] = ""; $sitemap_vars['bold'] = "class='bold'"; $sitemap_vars['ul_end'] = ""; } switch($db->f("link_type")) { case '1': // External Url $sitemap_vars['hyperlink'] = $db->f("link_url"); $sitemap_vars['target'] = ""; if($db->f("link_target") != "") { $sitemap_vars['target'] = "target=\"".$db->f("link_target")."\""; } break; case '2': // Shortcut $sitemap_vars['hyperlink'] = create_url($db->f("link_eid"),$db->f("name"),$sys_config_vars['mod_rewrite']); $sitemap_vars['target'] = ""; break; default: $sitemap_vars['hyperlink'] = create_url($db->f("eid"),$db->f("name"),$sys_config_vars['mod_rewrite']); $sitemap_vars['target'] = ""; break; } if($db->f("level") > 1) { $content .= "<div style=\"text-indent: ".$indent."px;\" ".$sitemap_vars['bold']."><a href=\"".$sitemap_vars['hyperlink']."\" ".$sitemap_vars['target'].">".$db->f("name")."</a></div>\n"; } $content = get_menu_entries($content,$db->f("eid")); } return(''.$content.''); } At the moment the content displays properly, however I want to turn this function into a DHTML dropdown menu. At present what happens with the level 2 elements is that using CSS the contents are indented using CSS. What I need to happen is to place the UL tag at the beginning and /UL tag at the end of the level 2 elements. I hope this makes sense. Any help would be greatly appreciated.

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  • setting ruby hash .default to a list

    - by matpalm
    i thought i understood what the default method does to a hash... give a default value for a key if it doesn't exist irb(main):001:0> a = {} => {} irb(main):002:0> a.default = 4 => 4 irb(main):003:0> a[8] => 4 irb(main):004:0> a[9] += 1 => 5 irb(main):005:0> a => {9=>5} all good. but if i set the default to be a empty list, or empty hash, i dont understand it's behaviour at all.... irb(main):001:0> a = {} => {} irb(main):002:0> a.default = [] => [] irb(main):003:0> a[8] << 9 => [9] # great! irb(main):004:0> a => {} # ?! would have expected {8=>[9]} irb(main):005:0> a[8] => [8] # awesome! irb(main):006:0> a[9] => [9] # unawesome! shouldn't this be [] ?? i was hoping / expecting the same behaviour as if i had used the ||= operator... irb(main):001:0> a = {} => {} irb(main):002:0> a[8] ||= [] => [] irb(main):003:0> a[8] << 9 => [9] irb(main):004:0> a => {8=>[9]} irb(main):005:0> a[9] => nil can anyone explain what is going on ???

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  • Custom Windows Forms Control not exporting functions, not showing in tools list, showing as Text

    - by flavour404
    Hi, I have written a very simple control. C# Visual Studio 2008. Its output should be, and is a dll. I have added a reference to the dll within the project that I intend to use it with. The msdn article about how to write a control states that it should appear in the 'Add reference / projects' list, which it doesn't but I simply navigated to it under the 'browse' tab, went to the /bin folder and added the reference that way. I dragged it over to my toolbox, but it shows up as a 'Text:xhair_tool' and when i try and add it to a form, it won't, so what have I done wrong? It was created as a 'Windows forms control' project. It should export the one method which is 'Target' which return an array, as shown below. using System; using System.Collections.Generic; using System.ComponentModel; using System.Drawing; using System.Data; using System.Text; using System.Windows.Forms; namespace xhair_tool { public partial class xhair : UserControl { public xhair() { InitializeComponent(); } private void xhair_Load(object sender, EventArgs e) { } protected override void OnPaint(PaintEventArgs e) { Graphics g = e.Graphics; Pen pen = new Pen(Color.Black, 1); SolidBrush redBrush = new SolidBrush(Color.Red); g.DrawLine(pen, 8, 0, 8, 7); g.DrawLine(pen, 8, 9, 8, 16); g.DrawLine(pen, 0, 8, 7, 8); g.DrawLine(pen, 9, 8, 16, 8); //ControlPaint.DrawReversibleLine(start, end, backColor) } /// <summary> /// Returns the point at the center of the crosshair /// </summary> /// <returns>int[x,y]</returns> public int[] Target { get { int[] _xy = new int[2]; _xy[0] = this.Left + 8; _xy[1] = this.Top + 8; return _xy; } } } } Thanks, R.

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  • List input and output audio devices in Applet

    - by Jhonny Everson
    I am running a signed applet that needs to provide the ability for the user to select the input and output audio devices ( similar to what skype provides). I borrowed the following code from other thread: import javax.sound.sampled.*; public class SoundAudit { public static void main(String[] args) { try { System.out.println("OS: "+System.getProperty("os.name")+" "+ System.getProperty("os.version")+"/"+ System.getProperty("os.arch")+"\nJava: "+ System.getProperty("java.version")+" ("+ System.getProperty("java.vendor")+")\n"); for (Mixer.Info thisMixerInfo : AudioSystem.getMixerInfo()) { System.out.println("Mixer: "+thisMixerInfo.getDescription()+ " ["+thisMixerInfo.getName()+"]"); Mixer thisMixer = AudioSystem.getMixer(thisMixerInfo); for (Line.Info thisLineInfo:thisMixer.getSourceLineInfo()) { if (thisLineInfo.getLineClass().getName().equals( "javax.sound.sampled.Port")) { Line thisLine = thisMixer.getLine(thisLineInfo); thisLine.open(); System.out.println(" Source Port: " +thisLineInfo.toString()); for (Control thisControl : thisLine.getControls()) { System.out.println(AnalyzeControl(thisControl));} thisLine.close();}} for (Line.Info thisLineInfo:thisMixer.getTargetLineInfo()) { if (thisLineInfo.getLineClass().getName().equals( "javax.sound.sampled.Port")) { Line thisLine = thisMixer.getLine(thisLineInfo); thisLine.open(); System.out.println(" Target Port: " +thisLineInfo.toString()); for (Control thisControl : thisLine.getControls()) { System.out.println(AnalyzeControl(thisControl));} thisLine.close();}}} } catch (Exception e) {e.printStackTrace();}} public static String AnalyzeControl(Control thisControl) { String type = thisControl.getType().toString(); if (thisControl instanceof BooleanControl) { return " Control: "+type+" (boolean)"; } if (thisControl instanceof CompoundControl) { System.out.println(" Control: "+type+ " (compound - values below)"); String toReturn = ""; for (Control children: ((CompoundControl)thisControl).getMemberControls()) { toReturn+=" "+AnalyzeControl(children)+"\n";} return toReturn.substring(0, toReturn.length()-1);} if (thisControl instanceof EnumControl) { return " Control:"+type+" (enum: "+thisControl.toString()+")";} if (thisControl instanceof FloatControl) { return " Control: "+type+" (float: from "+ ((FloatControl) thisControl).getMinimum()+" to "+ ((FloatControl) thisControl).getMaximum()+")";} return " Control: unknown type";} } But what I get: Mixer: Software mixer and synthesizer [Java Sound Audio Engine] Mixer: No details available [Microphone (Pink Front)] I was expecting the get the real list of my devices (My preferences panels shows 3 output devices and 1 Microphone). I am running on Mac OS X 10.6.7. Is there other way to get that info from Java?

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  • Entering and retrieving data from SQLite for an android List View

    - by Infiniti Fizz
    Hi all, I started learning android development a few weeks ago and have gone through the developer.android.com tutorials etc. But now I have a problem. I'm trying to create an app which tracks the usage of each installed app. Therefore I'm pulling the names of all installed apps using the PackageManager and then trying to put them into an SQLite database table. I am using the Notepad Tutorial SQLite implementation but I'm running into some problems that I have tried for days to solve. I have 2 classes, the DBHelper class and the actual ListActivity class. For some reason the app force closes when I try and run my fillDatabase() function which gets all the app names from the PackageManager and tries to put them into the database: private void fillDatabase() { PackageManager manager = this.getPackageManager(); List<ApplicationInfo> appList = manager.getInstalledApplications(0); for(int i = 0; i < appList.size(); i++) { mDbHelper.addApp(manager.getApplicationLabel(appList.get(i)).toString(), 0); } } addApp() is a function defined in my AppsDbHelper class and looks as follows: public long createApp(String name, int usage) { ContentValues initialValues = new ContentValues(); initialValues.put(KEY_NAME, name); initialValues.put(KEY_USAGE, usage); return mDb.insert(DATABASE_TABLE, null, initialValues); } The database create is defined as follows: private static final String DATABASE_CREATE = "create table notes (_id integer primary key autoincrement, " + "title text not null, usage integer not null);"; I have commented out all statements that follow fillDatabase(); in the onCreate() method of the ListActivity and so know that it is definetely the problem but I don't know why. I am taking the appName and putting it into the KEY_NAME field of the row and putting 0 into the KEY_USAGE field of the row (because initially, my app will default the usage of each app to 0 (not used yet)). If my addApp() function doesn't take the usage and just puts KEY_NAME into the ContentValues and into the database, it seems to work fine, but I want a column for usage. Any ideas why it is not working? Have I overlooked something? Thanks for your time, InfinitiFizz

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  • Creating a spam list with a web crawler in python

    - by user313623
    Hey guys, I'm not trying to do anything malicious here, I just need to do some homework. I'm a fairly new programmer, I'm using python 3.0, and I having difficulty using recursion for problem-solving. I've been stuck on this question for quite a while. Here's the assignment: Write a recursive method spam(url, n) that takes a url of a web page as input and a non-negative integer n, collects all the email address contained in the web page and adds them to a global dictionary variable spam_dict, and then recursively calls itself on every http hyperlink contained in the web page. You will use a dictionary so only one copy of every email address is save; your dictionary will store (key,value) pairs (email, email). The recursive call should use the parameter n-1 instead of n. If n = 0, you should collect the email addresses but no recursive calls should be made. The parameter n is used to limit the recursion to at most depth n. You will need to use the solutions of the two above problems; you method spam() will call the methods links2() and emails() and possibly other functions as well. Notes: 1. running spam() directly will produce no output on the screen; to find your spam_dict, you will need to read the value of spam_dict, and you will also need to reset it to the empty dictionary before every run of spam. 2. Recall how global variables are used. Usage: spam_dict = {} spam('http://reed.cs.depaul.edu/lperkovic/csc242/test1.html',0) spam_dict.keys() dict_keys([]) spam_dict = {} spam('http://reed.cs.depaul.edu/lperkovic/csc242/test1.html',1) spam_dict.keys() dict_keys(['[email protected]', '[email protected]']) So far, I've written a function that traverses web pages and puts all the links in a nice little list, and what I wanted to do was call that functions. And why would I use recursion on a dictionary? And how? I don't understand how n ties into all of this. def links2(url): content = str(urlopen(url).read()) myparser = MyHTMLParser() myparser.feed(content) lst = myparser.get() mergelst = [] for link in lst: mergelst.append(urljoin(lst[0],link)) print(mergelst) Any input (except why spam is bad) would be greatly appreciated. Also, I realize that the above function could probably look better, if you have a way to do it, I'm all ears. However, all I need is the point is for the program to produce the proper output.

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  • Sorting a list of colors in one dimension?

    - by Ptah- Opener of the Mouth
    I would like to sort a one-dimensional list of colors so that colors that a typical human would perceive as "like" each other are near each other. Obviously this is a difficult or perhaps impossible problem to get "perfectly", since colors are typically described with three dimensions, but that doesn't mean that there aren't some sorting methods that look obviously more natural than others. For example, sorting by RGB doesn't work very well, as it will sort in the following order, for example: (1) R=254 G=0 B=0 (2) R=254 G=255 B=0 (3) R=255 G=0 B=0 (4) R=255 G=255 B=0 That is, it will alternate those colors red, yellow, red, yellow, with the two "reds" being essentially imperceivably different than each other, and the two yellows also being imperceivably different from each other. But sorting by HLS works much better, generally speaking, and I think HSL even better than that; with either, the reds will be next to each other, and the yellows will be next to each other. But HLS/HSL has some problems, too; things that people would perceive as "black" could be split far apart from each other, as could things that people would perceive as "white". Again, I understand that I pretty much have to accept that there will be some splits like this; I'm just wondering if anyone has found a better way than HLS/HSL. And I'm aware that "better" is somewhat arbitrary; I mean "more natural to a typical human". For example, a vague thought I've had, but have not yet tried, is perhaps "L is the most important thing if it is very high or very low", but otherwise it is the least important. Has anyone tried this? Has it worked well? What specifically did you decide "very low" and "very high" meant? And so on. Or has anyone found anything else that would improve upon HSL? I should also note that I am aware that I can define a space-filling curve through the cube of colors, and order them one-dimensionally as they would be encountered while travelling along that curve. That would eliminate perceived discontinuities. However, it's not really what I want; I want decent overall large-scale groupings more than I want perfect small-scale groupings. Thanks in advance for any help.

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  • Generate a list of file names based on month and year arithmetic

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here? Update: I think, I better upload the entire script for better understanding. #!/usr/bin/env python import os, sys from time import strftime from calendar import month_abbr vGroup = {} vo = "group_lhcb" SI00_fig = float(2.478) months = tuple(month_abbr) print "\n%-12s\t%10s\t%8s\t%10s" % ('VOs','CPU-time','CPU-time','kSI2K-hrs') print "%-12s\t%10s\t%8s\t%10s" % ('','(in Sec)','(in Hrs)','(*2.478)') print "=" * 58 for inFile in os.listdir('.'): if inFile.isdigit(): readFile = open(inFile, 'r') lines = readFile.readlines() readFile.close() month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) for line in lines[2:]: if line.find(vo)==0: g, i = line.split() s = vGroup.get(g, 0) vGroup[g] = s + int(i) sumHrs = ((vGroup[g]/60)/60) sumSi2k = sumHrs*SI00_fig print "%-12s\t%10s\t%8s\t%10.2f" % (mnYear,vGroup[g],sumHrs,sumSi2k) del vGroup[g] When I run the script, I get this: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ================================================== Jan, 2011 211201372 58667 145376.83 Dec, 2010 5064337 1406 3484.07 Feb, 2011 17506049 4862 12048.04 Sep, 2010 210874275 58576 145151.33 As I said in the original post, I like the result to be in this order instead: Sep, 2010 210874275 58576 145151.33 Dec, 2010 5064337 1406 3484.07 Jan, 2011 211201372 58667 145376.83 Feb, 2011 17506049 4862 12048.04 The files in the source directory reads like this: [root@serv07 usage]# ls -l total 3632 -rw-r--r-- 1 root root 1144972 Feb 9 19:23 01 -rw-r--r-- 1 root root 556630 Feb 13 09:11 02 -rw-r--r-- 1 root root 443782 Feb 11 17:23 02.bak -rw-r--r-- 1 root root 1144556 Feb 14 09:30 09 -rw-r--r-- 1 root root 370822 Feb 9 19:24 12 Did I give a better picture now? Sorry for not being very clear in the first place. Cheers!! Update @Mark Ransom This is the result from Mark's suggestion: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ========================================================== Dec, 2010 5064337 1406 3484.07 Sep, 2010 210874275 58576 145151.33 Feb, 2011 17506049 4862 12048.04 Jan, 2011 211201372 58667 145376.83 As I said before, I'm looking for the result to b printed in this order: Sep, 2010 - Dec, 2010 - Jan, 2011 - Feb, 2011 Cheers!!

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  • Absolute Xpath to get list of childnodes?

    - by Googler
    Hi this my xml file, <?xml version="1.0"?> <worldpatentdata xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <meta name="elapsed-time" value="329" xmlns="http://ops.epo.org"/> <exchange-documents xmlns="http://www.epo.org/exchange"> <exchange-document country="AT" doc-number="380509" family-id="38826527" kind="T" system="ops.epo.org"> <bibliographic-data> <publication-reference data-format="docdb"> <document-id> <country>AT</country> <doc-number>380509</doc-number> <kind>T</kind> <date>20071215</date> </document-id> </publication-reference> <parties> <applicants> </applicants> <inventors> </inventors> </parties> </bibliographic-data> </exchange-document> </exchange-documents> </worldpatentdata> For the above xml file, i need the xpath to receive the childnodes below it: Output i need is : <exchange-documents xmlns="http://www.epo.org/exchange"> <exchange-document country="AT" doc-number="380509" family-id="38826527" kind="T" system="ops.epo.org"> <bibliographic-data> <publication-reference data-format="docdb"> <document-id> <country>AT</country> <doc-number>380509</doc-number> <kind>T</kind> <date>20071215</date> </document-id> </publication-reference> <parties> <applicants> </applicants> <inventors> </inventors> </parties> </bibliographic-data> </exchange-document> I using Linq-Xml to get the following data: This is my Xpath and code: var list = doc1.XPathSelectElement("exchange-document"); I couldnt retreive the needed output.It returns null for the above code. Can anyone pls help on this by providing the correct xpath to retieve the child nodes. Else is there any other way to retrieve it.

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  • How to combine a list of choices to determine which select statement

    - by Larry
    I have a mysql db and am using php 5.2 What I am trying to do is offer a list of options for a person to select (only 1). The chosen option will cause a select, update, or delete statement to be ran. The results of the statement do not need to be shown, although, showing the old and then the new would be nice (no problems with that part tho'.). Pseudo-Code: Assign $choice = 0 Check the value of $choice // This way, if it = 100, we do a break Select a Choice:<br> 1. Adjust Status Value (+60) // $choice = 1<br> 2. Show all Ships <br> // $choice = 2 3. Show Ships in Port <br> // $choice = 3 ... 0. $choice="100" // if the value =100, quit this part Use either case (switch) or if/else statements to run the users choice1 If the choice is 1, then run the "Select" statement with the variable of $sql1 -- "SELECT .... If the choice is 2, then run the "Select" statement with the variable of $sql2 --- SELECT * FROM Ships If the choice is 3, then run the "Select" statement with the variable of $sql3 <br> .... If the choice is 0, then we are done. I figured the (3) statements would be assigned in php as: $sql1="...". $sql2="SELECT * FROM Ships" $sql3="SELECT * FROM Ships WHERE nPort="1" My idea was to use the switch statement, but got lost on it. :( I would like the options to be available over and over again, until a variable ($choice) is selected. In which case, this particular page is done and goes back to the "Main Menu"? The coding and display, if I use it, I can do. Just not sure how to write the way to select which one I want. It is possible that I would run all of the queries, and other times, only one, so that is why I would like the choice. An area I get confused in is the proper forms to use such as -- ' ' " " and ...?? Not sure the # of options I will end up with, but it will be more than 5 but less than 20 / page. So if I get the system down for 2-3 choices, I can replicate it for as many as I may need. And, as always, if a better way exists, I am willing to try it. Thanks again... Larry

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