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  • How to avoid open-redirect vulnerability and safely redirect on successful login (HINT: ASP.NET MVC

    - by Brad B.
    Normally, when a site requires that you are logged in before you can access a certain page, you are taken to the login screen and after successfully authenticating yourself, you are redirected back to the originally requested page. This is great for usability - but without careful scrutiny, this feature can easily become an open redirect vulnerability. Sadly, for an example of this vulnerability, look no further than the default LogOn action provided by ASP.NET MVC 2: [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (!String.IsNullOrEmpty(returnUrl)) { return Redirect(returnUrl); // open redirect vulnerability HERE } else { return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "User name or password incorrect..."); } } return View(model); } If a user is successfully authenticated, they are redirected to "returnUrl" (if it was provided via the login form submission). Here is a simple example attack (one of many, actually) that exploits this vulnerability: Attacker, pretending to be victim's bank, sends an email to victim containing a link, like this: http://www.mybank.com/logon?returnUrl=http://www.badsite.com Having been taught to verify the ENTIRE domain name (e.g., google.com = GOOD, google.com.as31x.example.com = BAD), the victim knows the link is OK - there isn't any tricky sub-domain phishing going on. The victim clicks the link, sees their actual familiar banking website and is asked to logon Victim logs on and is subsequently redirected to http://www.badsite.com which is made to look exactly like victim's bank's website, so victim doesn't know he is now on a different site. http://www.badsite.com says something like "We need to update our records - please type in some extremely personal information below: [ssn], [address], [phone number], etc." Victim, still thinking he is on his banking website, falls for the ploy and provides attacker with the information Any ideas on how to maintain this redirect-on-successful-login functionality yet avoid the open-redirect vulnerability? I'm leaning toward the option of splitting the "returnUrl" parameter into controller/action parts and use "RedirectToRouteResult" instead of simply "Redirect". Does this approach open any new vulnerabilities? Side note: I know this open-redirect may not seem to be a big deal compared to the likes of XSS and CSRF, but us developers are the only thing protecting our customers from the bad guys - anything we can do to make the bad guys' job harder is a win in my book. Thanks, Brad

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  • How can you add a UIGestureRecognizer to a UIBarButtonItem as in the common undo/redo UIPopoverContr

    - by SG
    Problem In my iPad app, I cannot attach a popover to a button bar item only after press-and-hold events. But this seems to be standard for undo/redo. How do other apps do this? Background I have an undo button (UIBarButtonSystemItemUndo) in the toolbar of my UIKit (iPad) app. When I press the undo button, it fires it's action which is undo:, and that executes correctly. However, the "standard UE convention" for undo/redo on iPad is that pressing undo executes an undo but pressing and holding the button reveals a popover controller where the user selected either "undo" or "redo" until the controller is dismissed. The normal way to attach a popover controller is with presentPopoverFromBarButtonItem:, and I can configure this easily enough. To get this to show only after press-and-hold we have to set a view to respond to "long press" gesture events as in this snippet: UILongPressGestureRecognizer *longPressOnUndoGesture = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPressOnUndoGesture:)]; //Broken because there is no customView in a UIBarButtonSystemItemUndo item [self.undoButtonItem.customView addGestureRecognizer:longPressOnUndoGesture]; [longPressOnUndoGesture release]; With this, after a press-and-hold on the view the method handleLongPressOnUndoGesture: will get called, and within this method I will configure and display the popover for undo/redo. So far, so good. The problem with this is that there is no view to attach to. self.undoButtonItem is a UIButtonBarItem, not a view. Possible solutions 1) [The ideal] Attach the gesture recognizer to the button bar item. It is possible to attach a gesture recognizer to a view, but UIButtonBarItem is not a view. It does have a property for .customView, but that property is nil when the buttonbaritem is a standard system type (in this case it is). 2) Use another view. I could use the UIToolbar but that would require some weird hit-testing and be an all around hack, if even possible in the first place. There is no other alternative view to use that I can think of. 3) Use the customView property. Standard types like UIBarButtonSystemItemUndo have no customView (it is nil). Setting the customView will erase the standard contents which it needs to have. This would amount to re-implementing all the look and function of UIBarButtonSystemItemUndo, again if even possible to do. Question How can I attach a gesture recognizer to this "button"? More specifically, how can I implement the standard press-and-hold-to-show-redo-popover in an iPad app? Ideas? Thank you very much, especially if someone actually has this working in their app (I'm thinking of you, omni) and wants to share...

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  • Customization for VersionDiff.aspx in sharepoint

    - by Azra
    Hi. I have a Wiki site, and on wiki pages if I select to check history of pages it displays in the Left action panel Version and date as hyperlinks. It uses SharePoint's Diff iterator, I want to do a bit of customization here, along with date I want to display field values too. How can I do that? Thanks, Azra

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  • how create a Controller partial class to override OnAuthorization?

    - by kaijk
    I'm trying to change the method OnAuthorization, so that it is available for any application ... this way: public partial class Controller { protected override void OnAuthorization(AuthorizationContext filterContext) { if ((string)(filterContext.RouteData.Values["action"]) == "test") { filterContext.Result = new HttpUnauthorizedResult(); } } } but is showing the compilation error: ...Controller.OnAuthorization(System.Web.Mvc.AuthorizationContext)': no suitable method found to override can someone help me?

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  • Jquery return multiple values in ajax call

    - by Scarface
    I have a jquery post function that returns a response on success after the click of a div. However, I would like to return multiple variables on success. Do I have to use JSON, and if so, is it possible to integrate it into the $.ajax function after success? $.ajax({ type: "POST", data: "action=favorite&username=" + username + "&topic_id=" + topic_id + "&token=" + token, url: "favorite.php", success: function(response) { } });

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  • Greasemonkey Submit Form

    - by magixx
    I'm trying to autosubmit a form with greasemonkey however I'm not sure how to do it with this button. The button seems to have the following properties a class="blue-button" href="javascript:void(0)" onclick="Form.submit(this);" and the only form I see above is <form xmlns="http://www.w3.org/1999/xhtml" xmlns:s="http://www.blizzard.com/ns/store" action="/account/management/add-game.xml" autocomplete="off" method="post"> The page is here you can use "[email protected]" and "a1a1a1a1" as a login.

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  • Is there a way to add a column with buttons in jqGrid

    - by josh
    I have some data that I'd like to display in jqqgrid. In addition to add, edit, and delete, there are other actions that can be taken on a selected record. I like the flow of having a button/link for that action in that record's row. Is there a way to add a column & buttons/links within jqgrid which isn't bound to data?

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  • How to prevent duplicate records being inserted with SqlBulkCopy when there is no primary key

    - by kscott
    I receive a daily XML file that contains thousands of records, each being a business transaction that I need to store in an internal database for use in reporting and billing. I was under the impression that each day's file contained only unique records, but have discovered that my definition of unique is not exactly the same as the provider's. The current application that imports this data is a C#.Net 3.5 console application, it does so using SqlBulkCopy into a MS SQL Server 2008 database table where the columns exactly match the structure of the XML records. Each record has just over 100 fields, and there is no natural key in the data, or rather the fields I can come up with making sense as a composite key end up also having to allow nulls. Currently the table has several indexes, but no primary key. Basically the entire row needs to be unique. If one field is different, it is valid enough to be inserted. I looked at creating an MD5 hash of the entire row, inserting that into the database and using a constraint to prevent SqlBulkCopy from inserting the row,but I don't see how to get the MD5 Hash into the BulkCopy operation and I'm not sure if the whole operation would fail and roll back if any one record failed, or if it would continue. The file contains a very large number of records, going row by row in the XML, querying the database for a record that matches all fields, and then deciding to insert is really the only way I can see being able to do this. I was just hoping not to have to rewrite the application entirely, and the bulk copy operation is so much faster. Does anyone know of a way to use SqlBulkCopy while preventing duplicate rows, without a primary key? Or any suggestion for a different way to do this?

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  • Specifying Android project dependencies (in Eclipse)

    - by Henrik Gustafsson
    I have two Android projects, a 'library project' containing a custom layout, and an 'application project' containing an application which uses the layout. Everything seems to build and execute fine, except that the visual layout editor throws a ClassNotFoundException (which I assume is a bug in the plug-in), but when I try to start to make use of the attributes I defined for the custom layout in the xml, I can no longer build. That is; this works: <?xml version="1.0" encoding="utf-8"?> <se.fnord.android.layout.PredicateLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="asdfasdf" /> </se.fnord.android.layout.PredicateLayout> Whereas this does not: <?xml version="1.0" encoding="utf-8"?> <se.fnord.android.layout.PredicateLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:fnord="http://schemas.android.com/apk/res/se.fnord.android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView fnord:layout_horizontalSpacing="1px" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="asdfasdf" /> </se.fnord.android.layout.PredicateLayout> The build fails with a message from aapt: ERROR No resource identifier found for attribute 'layout_horizontalSpacing' in package 'se.fnord.android' The resource identifier does exist in the R-file and attrs.xml contained the library project, and if I put the layout code and resources directly in the application project everything works fine. The layout_horizontalSpacing attribute (and layout_verticalSpacing) is a custom attribute used in the PredicateLayout.LayoutParam class to specify the distance to the next widget. So far I've tried the standard eclipse ways by specifying project references and build path project dependencies. I was also told to try the tag in the application manifest, which did not help. So, what do I need to do for the references in the xml-file to work? I don't know if it's relevant, but the 'library' manifest looks like this: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="se.fnord.android" android:versionCode="1" android:versionName="1.0.0"> </manifest> The 'application' manifest like this: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="se.fnord.appname" android:versionCode="1" android:versionName="1.0.0"> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".AppName" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> </manifest> (The 'PredicateLayout', btw, is a cleaned-up version of this).

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  • JQuery error: XML filter is applied to non-XML value (function (E, F) {return new (o.fn.init)(E, F);

    - by morpheous
    I am getting this slightly cryptic error message: XML filter is applied to non-XML value (function (E, F) {return new (o.fn.init)(E, F);}) when I run this code snippet function justDoIt(arg){ msg = arg.msg; if(arg.ok) jQuery.(".action-button").each(function(idx,el){jQuery(this).removeClass('enabled');} ); } arg is a JSON format response form the server. Anyone knows how to fix this?

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  • ASP.NET MVC 2.0 JsonRequestBehavior Global Setting

    - by beckelmw
    ASP.NET MVC 2.0 will now, by default, throw an exception when an action attempts to return JSON in response to a GET request. I know this can be overridden on a method by method basis by using JsonRequestBehavior.AllowGet, but is it possible to set on a controller or higher basis (possibly the web.config)? Update: Per Levi's comment, this is what I ended up using- protected override JsonResult Json(object data, string contentType, System.Text.Encoding contentEncoding) { return Json(data, contentType, JsonRequestBehavior.AllowGet); }

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  • Detecting which UIButton was pressed in a UITableView

    - by rein
    Hi, I have a UITableView with 5 UITableViewCells. Each cell contains a UIButton which is set up as follows: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSString *identifier = @"identifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier]; if (cell == nil) { cell = [[UITableView alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier]; [cell autorelelase]; UIButton *button = [[UIButton alloc] initWithFrame:CGRectMake(10, 5, 40, 20)]; [button addTarget:self action:@selector(buttonPressedAction:) forControlEvents:UIControlEventTouchUpInside]; [button setTag:1]; [cell.contentView addSubview:button]; [button release]; } UIButton *button = (UIButton *)[cell viewWithTag:1]; [button setTitle:@"Edit" forState:UIControlStateNormal]; return cell; } My question is this: in the buttonPressedAction: method, how do I know which button has been pressed. I've considered using tags but I'm not sure this is the best route. I'd like to be able to somehow tag the indexPath onto the control. - (void)buttonPressedAction:(id)sender { UIButton *button = (UIButton *)sender; // how do I know which button sent this message? // processing button press for this row requires an indexPath. } What's the standard way of doing this? Edit: I've kinda solved it by doing the following. I would still like to have an opinion whether this is the standard way of doing it or is there a better way? - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSString *identifier = @"identifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier]; if (cell == nil) { cell = [[UITableView alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier]; [cell autorelelase]; UIButton *button = [[UIButton alloc] initWithFrame:CGRectMake(10, 5, 40, 20)]; [button addTarget:self action:@selector(buttonPressedAction:) forControlEvents:UIControlEventTouchUpInside]; [cell.contentView addSubview:button]; [button release]; } UIButton *button = (UIButton *)[cell.contentView.subViews objectAtIndex:0]; [button setTag:indexPath.row]; [button setTitle:@"Edit" forState:UIControlStateNormal]; return cell; } - (void)buttonPressedAction:(id)sender { UIButton *button = (UIButton *)sender; int row = button.tag; } What's important to note is that I can't set the tag in the creation of the cell since the cell might be dequeued instead. It feels very dirty. There must be a better way.

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  • Voice Recognition Connection problem

    - by user244190
    I,m trying to work through and test a Voice Recognition example based on the VoiceRecognition.java example at http://developer.android.com/resources/samples/ApiDemos/src/com/example/android/apis/app/VoiceRecognition.html but when click on the button to create the activity, I get a dialog that says Connection problem. My Manifest file is using the Internet Permission, and I understand it passes the to the Google Servers. Do I need to do anything else to use this. Code below UPDATE: Ok, I was able to replace my emulator image with one from HTC that appears to come with Google Voice Search, however now when I run from the emulator, i'm getting an Audio Problem message with Speak Again or Cancel buttons. It appears to make it back to the onActivityResult(), but the resultCode is 0. Here is the LogCat output: 03-07 20:21:25.396: INFO/ActivityManager(578): Starting activity: Intent { action=android.speech.action.RECOGNIZE_SPEECH comp={com.google.android.voicesearch/com.google.android.voicesearch.RecognitionActivity} (has extras) } 03-07 20:21:25.406: WARN/ActivityManager(578): Activity is launching as a new task, so cancelling activity result. 03-07 20:21:25.968: WARN/ActivityManager(578): Activity pause timeout for HistoryRecord{434f7850 {com.ikonicsoft.mileagegenie/com.ikonicsoft.mileagegenie.MileageGenie}} 03-07 20:21:26.206: WARN/AudioHardwareInterface(554): getInputBufferSize bad sampling rate: 16000 03-07 20:21:26.256: ERROR/AudioRecord(819): Recording parameters are not supported: sampleRate 16000, channelCount 1, format 1 03-07 20:21:26.696: INFO/ActivityManager(578): Displayed activity com.google.android.voicesearch/.RecognitionActivity: 1295 ms 03-07 20:21:29.890: DEBUG/dalvikvm(806): threadid=3: still suspended after undo (s=1 d=1) 03-07 20:21:29.896: INFO/dalvikvm(806): Uncaught exception thrown by finalizer (will be discarded): 03-07 20:21:29.896: INFO/dalvikvm(806): Ljava/lang/IllegalStateException;: Finalizing cursor android.database.sqlite.SQLiteCursor@435d3c50 on ml_trackdata that has not been deactivated or closed 03-07 20:21:29.896: INFO/dalvikvm(806): at android.database.sqlite.SQLiteCursor.finalize(SQLiteCursor.java:596) 03-07 20:21:29.896: INFO/dalvikvm(806): at dalvik.system.NativeStart.run(Native Method) 03-07 20:21:31.468: DEBUG/dalvikvm(806): threadid=5: still suspended after undo (s=1 d=1) 03-07 20:21:32.436: WARN/IInputConnectionWrapper(806): showStatusIcon on inactive InputConnection I,m still not sure why I,m getting the Connect problem on the Droid. I can use Voice Search ok. I also tried clearing the cache, and data as described in some posts, butstill not working?? /** * Fire an intent to start the speech recognition activity. */ private void startVoiceRecognitionActivity() { Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH); intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM); intent.putExtra(RecognizerIntent.EXTRA_PROMPT, "Speech recognition demo"); startActivityForResult(intent, VOICE_RECOGNITION_REQUEST_CODE); } /** * Handle the results from the recognition activity. */ @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { if (requestCode == VOICE_RECOGNITION_REQUEST_CODE && resultCode == RESULT_OK) { // Fill the list view with the strings the recognizer thought it could have heard ArrayList<String> matches = data.getStringArrayListExtra( RecognizerIntent.EXTRA_RESULTS); mList.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, matches)); } super.onActivityResult(requestCode, resultCode, data); }

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  • Rails: foreign_key that is set with a CASE WHEN mysql statement

    - by user305270
    belongs_to :removed_friend, :class_name => 'Profile', :foreign_key => "(CASE WHEN friendships.profile_id = #{self.id} THEN friendships.friend_id ELSE friendships.profile_id END)" The self.id its not working too :s it should be the id of the profile that is triggered the action. Anyway the main problem is that this foreign_key is not working and i got a mysql error. please help.. thanks

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  • Edit links in GridModel (MVCContrib)

    - by DucDigital
    http://stackoverflow.com/questions/1458782/mvccontrib-gridmodel-is-it-possible-to-do-actionsyntax-in-a-gridmodel I've read this article and it's quite useful but I can't apply this. I don't know if in the newest MVCContrib, they removed the ".Action()" because somehow I cannot access this. Is there someway i can put the ActionLink of the edit link into a grid model? Thank you

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  • Apache Commons FileUpload Does not behave like expected

    - by Harry Pham
    I just want to assure you guys that before I post this, I have read couple of similar post but none solved my problem. So here it is. I use Ajax taglib for my form since it wont refresh my screen <%@ taglib uri="WEB-INF/taglib.tld" prefix="a" %> <a:AjaxUpload action="UploadServlet"> <input type="file"> <input type="submit" value="Upload"> </a:AjaxUpload> If this is in any confused you guys, then you can think of the above code will create these form, but send request asynchronously. <form action="UploadServlet" enctype="multipart/form-data" method="post"> <input type="file"> <input type="submit"> </form> My first question is, if I add name="file" inside the <input> to make it become like this, <input type="file" name="file">, my servlet will throw an exception. It wont if I take it out. Here is the exception: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637) My second question is: On the server side, I check the request to see if it is isMultipartContent, and it is. But then when I parseRequest() and store into List<FileItem> items, the items.size() is 0. Here is my Servlet code FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List<FileItem> items = null; if(request.getContentType() != null && request.getContentType().toLowerCase().indexOf("multipart/form-data") > -1){ if(upload.isMultipartContent(request)){ items = upload.parseRequest(request); //It got to here, but items.size is 0. why????????????? } }

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  • Is it necessary to know flash designing for flex3 ?

    - by Srinivas Iyer
    I am from a programming background ,and newbie to flex3 . i would like to learn flex3 and develop some application using rails and flex3 . Is it necessary to know flash in order to learn flex3 or just learning Action script 3 would do ? .Can anybody tell what are the prerequisites to learn flex3 . Thanks in Advance.

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  • How to show quicktime videos in succession

    - by Eric Frank
    How do I have two or more quicktime videos to play one after the other, with no action taken by the user? I've seen an example of the technique here: http://untitled.wiredrive.com//l/p/?presentation=7c79bedbb8b02d2b1da45b033cc20345 I can't seem to boil down their code to the good stuff. Thanks!

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  • Django Formset management-form validation error

    - by gramware
    I have a form and a formset on my template. The problem is that the formset is throwing validation error claiming that the management form is "missing or has been tampered with". Here is my view @login_required def home(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) blogz = list(blog.objects.filter(deleted='0')) delblog = modelformset_factory(blog, exclude=('poster','date' ,'title','content')) if request.user.is_staff== True: staff = 1 else: staff = 0 staffis = 1 if request.method == 'POST': delblogformset = delblog(request.POST) if delblogformset.is_valid(): delblogformset.save() return HttpResponseRedirect('/home') else: delblogformset = delblog(queryset=blog.objects.filter( deleted='0')) blogform = BlogForm(request.POST) if blogform.is_valid(): blogform.save() return HttpResponseRedirect('/home') else: blogform = BlogForm(initial = {'poster':user.id}) blogs= zip(blogz,delblogformset.forms) paginator = Paginator(blogs, 10) # Show 25 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: blogs = paginator.page(page) except (EmptyPage, InvalidPage): blogs = paginator.page(paginator.num_pages) return render_to_response('home.html', {'user':user, 'blogform':blogform, 'staff': staff, 'staffis': staffis, 'blog':blogs, 'delblog':delblogformset}, context_instance = RequestContext( request )) my template {%block content%} <h2>Home</h2> {% ifequal staff staffis %} {% if form.errors %} <ul> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ul> {% endif %} <h3>Post a Blog to the Front Page</h3> <form method="post" id="form2" action="" class="infotabs accfrm"> {{ blogform.as_p }} <input type="submit" value="Submit" /> </form> <br> <br> {% endifequal %} <div class="pagination"> <span class="step-links"> {% if blog.has_previous %} <a href="?page={{ blog.previous_page_number }}">previous</a> {% endif %} <span class="current"> Page {{ blog.number }} of {{ blog.paginator.num_pages }}. </span> {% if blog.has_next %} <a href="?page={{ blog.next_page_number }}">next</a> {% endif %} </span> <form method="post" action="" class="usertabs accfrm"> {{delblog.management_form}} {% for b, form in blog.object_list %} <div class="blog"> <h3>{{b.title}}</h3> <p>{{b.content}}</p> <p>posted by <strong>{{b.poster}}</strong> on {{b.date}}</p> {% ifequal staff staffis %}<p>{{form.as_p}}<input type="submit" value="Delete" /></p>{% endifequal %} </div> {% endfor %} </form> {%endblock%}

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  • how to use spinner

    - by corotana
    I am very new to android. I want to use 2 spinners in my application, one shows the countries list, when any country is selected the other spinner should show the list of cities of that country. when city is selected some action is performed. plz help me with some sample code. thanks in anticipation

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  • Windows Workflow Foundation 4 (WF4) Error Handling

    - by Russ Clark
    What is the best way to get error messages from a WF4 workflow back to a hosting ASP.NET MVC application? I need the workflow to not terminate, but continue to be active, and then pass a message back to the hosting app regarding the error, so the user can take an alternative action, but I'm not sure how to do that.

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  • PHP Warning: Cookie values can not contain any of the following

    - by morpheous
    I am getting this warning whilst using Symfony 1.3.2 on Ubuntu 9.10: HP Warning: Cookie values can not contain any of the following ',; \t\r\n\013\014' in /lib/vendor/symfony/symfony-1.3.2/lib/response/sfWebResponse.class.php on line 368 I am not sure why this warning is being issued, since I am not directly setting any cookies in my action/template. Anyone knows what is causing this?

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  • This Question about how do i learn from basic As3 to advanced as3

    - by user333472
    This Question about how do i learn from basic As3 to advanced as3 , as i want to become professional in as3.And work as freelancer. can anybody guide me how to reach to the peak of Action-Script-3. This question seems to be really funny to many but this is the most basic question in my mind 1) which way to go. 2) what steps i should follow. 3) how should i do my first project professionally. 4) how do i become excellent in as3

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  • routes in rails 3 .. basic routes issue

    - by piemesons
    I m having a controller users in which there are three actions show, update and prepare and there respective views in views/users directory Now when i am trying this:-- http://localhost:3000/users/prepare I am getting an error No route matches "/users/prepare" can anybody explain me how to specify this routes in routes.rb for this.. I am a beginner for rails map.connect '/prepare', :controller => 'users', :action => 'prepare' this is not working..

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