Search Results

Search found 19992 results on 800 pages for 'font size'.

Page 197/800 | < Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >

  • implementation of a queue using a circular array

    - by matin1234
    Hi I have found these algorithms in the internet but I can not understand that why in the enqueue method we compare size with N-1??? please help me thanks!! Algorithm size(): return (N-f+r)mod N Algorithm enqueue(e): if size()=N-1 then throw a FullQueueException Q[r]<---e r<----(r+1)mod N

    Read the article

  • UIView animation problem

    - by FoJjen
    I try to make a UIImageView open like a hatch, and under the "hatchView" its anoter imageView but when I start the animation its like the view under gets over and cover the animation, When the animation gets over the imageView the its getting visibel. its works fine if a remove the imageView thats under. Here is the code for animation view. - (void) touchesEnded:(NSSet *)touches withEvent:(UIEvent *) event { if (!isHatchOpen) { if (hatchView.layer.anchorPoint.x != 0.0f) { hatchView.layer.anchorPoint = CGPointMake(0.0f, 0.5f); hatchView.center = CGPointMake(hatchView.center.x - hatchView.bounds.size.width/2.0f, hatchView.center.y); } UITouch *touch = [touches anyObject]; CGPoint location = [touch locationInView:hatchView]; [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:1]; [UIView setAnimationCurve:UIViewAnimationCurveEaseInOut]; [UIView setAnimationBeginsFromCurrentState:YES]; float pct = location.x / 320.0f; float rad = acosf(pct); CATransform3D transform = CATransform3DMakeRotation(-rad+5, 0.0f, -1.0f, 0.0f); transform.m14 = (1.0 / -2000) * acosf(pct); hatchView.layer.transform = transform; [UIView commitAnimations]; isHatchOpen = YES; } else { if (hatchView.layer.anchorPoint.x != 0.0f) { hatchView.layer.anchorPoint = CGPointMake(0.0f, 0.5f); hatchView.center = CGPointMake(hatchView.center.x - hatchView.bounds.size.width/2.0f, hatchView.center.y); } [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:1]; [UIView setAnimationCurve:UIViewAnimationCurveLinear]; [UIView setAnimationBeginsFromCurrentState:YES]; CATransform3D transform = CATransform3DMakeRotation(0, 0.0f, -1.0f, 0.0f); transform.m14 = 0; hatchView.layer.transform = transform; // Commit the changes [UIView commitAnimations]; isHatchOpen = NO; } } And here a add the Views hatchView = [[UIImageView alloc] initWithFrame:CGRectMake(0, 1, frame.size.width-1, frame.size.height-2)]; [self addSubview:hatchView]; imageView = [[UIImageView alloc] initWithFrame:CGRectMake(1, 1, frame.size.width-2, frame.size.height-2)]; imageView.contentMode = UIViewContentModeScaleAspectFit; [self insertSubview:imageView belowSubview:hatchView];

    Read the article

  • Java ArrayList remove dupes without sets

    - by Kieran
    I'm having problems removing duplicates from an ArrayList. It's for an assignment for college. Here's the code I have already: public int numberOfDiffWords() { ArrayList<String> list = new ArrayList<>(); for(int i=0; i<words.size()-1; i++) { for(int j=i+1; j<words.size(); j++) { if(words.get(i).equals(words.get(j))) { // do nothing } else { list.add(words.get(i)); } } } return list.size(); } The problem is in the numberOfDiffWords() method. The populate list method is working correctly, as my instructor has given me a sample string (containing 4465 words) to analyse - printing words.size() gives the correct result. I want to return the size of the new ArrayList with all duplicates removed. words is an ArrayList class attribute. UPDATE: I should have mentioned I'm only allowed to use dynamic indexed-based storage for this part of the assignment, which means no hash-based storage.

    Read the article

  • Real Time Sound Captureing J2ME

    - by Abdul jalil
    i am capturing sound in J2me and send these bytes to remote system, i then play these bytes on remote system.five second voice is capture and send to remote system. i get the repeated sound again .i am making a sound messenger please help me where i am doing wrong i am using the follown code . String remoteTimeServerAddress="192.168.137.179"; sc = (SocketConnection) Connector.open("socket://"+remoteTimeServerAddress+":13"); p = Manager.createPlayer("capture://audio?encoding=pcm&rate=11025&bits=16&channels=1"); p.realize(); RecordControl rc = (RecordControl)p.getControl("RecordControl"); ByteArrayOutputStream output = new ByteArrayOutputStream(); OutputStream outstream =sc.openOutputStream(); rc.setRecordStream(output); rc.startRecord(); p.start(); int size=output.size(); int offset=0; while(true) { Thread.currentThread().sleep(5000); rc.commit(); output.flush(); size=output.size(); if(size0) { recordedSoundArray=output.toByteArray(); outstream.write(recordedSoundArray,0,size); } output.reset(); rc.reset(); rc.setRecordStream(output); rc.startRecord(); }

    Read the article

  • Get address using Geocoder in android

    - by user264953
    Hi, I tried to get the address of a particular location by giving static geocordinates. I was not able to fetch the address. Can someone please help. I just need to check whether this function works for me. Here is my snippet. Geocoder geocoder = new Geocoder(AddressSimulator.this, Locale.getDefault()); List<Address> addresses = geocoder.getFromLocation(1.352566007, 103.78921587, 1); System.out.println("Addresses size"+addresses.size()); Address size is obtained as zero. I tried with few other geocordinates also, but address size is always returned as 0. Experts, kindly help me resolve this. Looking forward for your valuable help/suggestions, Best Regards, Rony

    Read the article

  • C/C++ I18N mbstowcs question

    - by bogertron
    I am working on internationalizing the input for a C/C++ application. I have currently hit an issue with converting from a multi-byte string to wide character string. The code needs to be cross platform compatible, so I am using mbstowcs and wcstombs as much as possible. I am currently working on a WIN32 machine and I have set the locale to a non-english locale (Japanese). When I attempt to convert a multibyte character string, I seem to be having some conversion issues. Here is an example of the code: int main(int argc, char** argv) { wchar_t *wcsVal = NULL; char *mbsVal = NULL; /* Get the current code page, in my case 932, runs only on windows */ TCHAR szCodePage[10]; int cch= GetLocaleInfo( GetSystemDefaultLCID(), LOCALE_IDEFAULTANSICODEPAGE, szCodePage, sizeof(szCodePage)); /* verify locale is set */ if (setlocale(LC_CTYPE, "") == 0) { fprintf(stderr, "Failed to set locale\n"); return 1; } mbsVal = argv[1]; /* validate multibyte string and convert to wide character */ int size = mbstowcs(NULL, mbsVal, 0); if (size == -1) { printf("Invalid multibyte\n"); return 1; } wcsVal = (wchar_t*) malloc(sizeof(wchar_t) * (size + 1)); if (wcsVal == NULL) { printf("memory issue \n"); return 1; } mbstowcs(wcsVal, szVal, size + 1); wprintf(L"%ls \n", wcsVal); return 0; } At the end of execution, the wide character string does not contain the converted data. I believe that there is an issue with the code page settings, because when i use MultiByteToWideChar and have the current code page sent in EX: MultiByteToWideChar( CP_ACP, 0, mbsVal, -1, wcsVal, size + 1 ); in place of the mbstowcs calls, the conversion succeeds. My question is, how do I use the generic mbstowcs call instead of teh MuliByteToWideChar call?

    Read the article

  • Initializing a char array through passed pointer segfaults

    - by Bitgarden
    Ie., why does the following work: char* char_array(size_t size){ return new char[size]; } int main(){ const char* foo = "foo"; size_t len = strlen(foo); char* bar=char_array(len); memset(bar, 0, len+1); } But the following segfaults: void char_array(char* out, size_t size){ out= new char[size]; } int main(){ const char* foo = "foo"; size_t len = strlen(foo); char* bar; char_array(bar, len); memset(bar, 0, len+1); }

    Read the article

  • Is there bug in the Matrix.RotateAt method for certain angles? .Net Winforms

    - by Jules
    Here's the code i'm using to rotate: Dim m As New System.Drawing.Drawing2D.Matrix Dim size = image.Size m.RotateAt(degreeAngle, New PointF(CSng(size.Width / 2), CSng(size.Height / 2))) Dim temp As New Bitmap(600, 600, Imaging.PixelFormat.Format32bppPArgb) Dim g As Graphics = Graphics.FromImage(temp) g.Transform = m g.DrawImage(image, 0, 0) (1) Disposals removed for brevity. (2) I test the code with a 200 x 200 rectangle. (3) Size 600,600 it just an arbitrary large value that I know will fit the right and bottom sides of the rotated image for testing purposes. (4) I know, with this code, the top and left edges will be clipped because I'm not transforming the orgin after the rotate. The problem only occurs at certain angles: (1) At 90, the right hand edge disappears completely. (2) At 180, the right and bottom edges are there, but very faded. (3) At 270, the bottom edge disappears completely. Is this a known bug? If I manually rotate the corners an draw the image by specifying an output rectangle, I don't get the same problem - though it is slightly slower than using RotateAt.

    Read the article

  • How to listen to JComboBox's width changes?

    - by agnieszka
    I tried PropertyChangeListener with property set to "width", "Width", "size" and "Size". PropertyChangeListener widthChangeListener = new PropertyChangeListener() { @Override public void propertyChange(PropertyChangeEvent evt) { //code } }; streamsComboBox.addPropertyChangeListener("width", widthChangeListener); projectsComboBox.addPropertyChangeListener("width", widthChangeListener); vobsComboBox.addPropertyChangeListener("width", widthChangeListener); Nothing works - the handler method is never fired. What should I do to handle JComboBox's size change? Where does the property name come from anyway?

    Read the article

  • C++ delete[] operator

    - by Betamoo
    Is this the right way to use delete[] operator? int* a=new int[size]; delete[] a; If yes, Who (compiler or GC or whoever) will determine the size of the newly created array? and where will it store the array size? Thanks

    Read the article

  • C++ vector and segmentation faults

    - by Headspin
    I am working on a simple mathematical parser. Something that just reads number = 1 + 2; I have a vector containing these tokens. They store a type and string value of the character. I am trying to step through the vector to build an AST of these tokens, and I keep getting segmentation faults, even when I am under the impression my code should prevent this from happening. Here is the bit of code that builds the AST: struct ASTGen { const vector<Token> &Tokens; unsigned int size, pointer; ASTGen(const vector<Token> &t) : Tokens(t), pointer(0) { size = Tokens.size() - 1; } unsigned int next() { return pointer + 1; } Node* Statement() { if(next() <= size) { switch(Tokens[next()].type) { case EQUALS : Node* n = Assignment_Expr(); return n; } } advance(); } void advance() { if(next() <= size) ++pointer; } Node* Assignment_Expr() { Node* lnode = new Node(Tokens[pointer], NULL, NULL); advance(); Node* n = new Node(Tokens[pointer], lnode, Expression()); return n; } Node* Expression() { if(next() <= size) { advance(); if(Tokens[next()].type == SEMICOLON) { Node* n = new Node(Tokens[pointer], NULL, NULL); return n; } if(Tokens[next()].type == PLUS) { Node* lnode = new Node(Tokens[pointer], NULL, NULL); advance(); Node* n = new Node(Tokens[pointer], lnode, Expression()); return n; } } } }; ... ASTGen AST(Tokens); Node* Tree = AST.Statement(); cout << Tree->Right->Data.svalue << endl; I can access Tree->Data.svalue and get the = Node's token info, so I know that node is getting spawned, and I can also get Tree->Left->Data.svalue and get the variable to the left of the = I have re-written it many times trying out different methods for stepping through the vector, but I always get a segmentation fault when I try to access the = right node (which should be the + node) Any help would be greatly appreciated.

    Read the article

  • scalabel background image of popup. html, css

    - by Mayur
    Hi All, I M getting porblem in html and css, I used a bg image for my popup window whose size is 500px width and 400px height; having a scrollable text in it. but problem is that if i reduce a size of browser it get distorted please help me if i can make it scalable background and according to that text as per browser size Thanks Mayur Mate

    Read the article

  • Path to background in servlet

    - by kapil chhattani
    //the below line is the element of my HTML form which renders the image sent by the servlet written further below. <img style="margin-left:91px; margin-top:-6px;" class="image" src="http://www.abcd.com/captchaServlet"> I generate a captcha code using the following code in java. public class captchaServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 150; int height = 50; int charsToPrint = 6; String elegibleChars = "ABCDEFGHJKLMPQRSTUVWXYabcdefhjkmnpqrstuvwxy1234567890"; char[] chars = elegibleChars.toCharArray(); StringBuffer finalString = new StringBuffer(); for ( int i = 0; i < charsToPrint; i++ ) { double randomValue = Math.random(); int randomIndex = (int) Math.round(randomValue * (chars.length - 1)); char characterToShow = chars[randomIndex]; finalString.append(characterToShow); } System.out.println(finalString); BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); Graphics2D g2d = bufferedImage.createGraphics(); Font font = new Font("Georgia", Font.BOLD, 18); g2d.setFont(font); RenderingHints rh = new RenderingHints( RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); rh.put(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); g2d.setRenderingHints(rh); GradientPaint gp = new GradientPaint(0, 0, Color.BLUE, 0, height/2, Color.black, true); g2d.setPaint(gp); g2d.fillRect(0, 0, width, height); g2d.setColor(new Color(255, 255, 0)); Random r = new Random(); int index = Math.abs(r.nextInt()) % 5; char[] data=new String(finalString).toCharArray(); String captcha = String.copyValueOf(data); int x = 0; int y = 0; for (int i=0; i<data.length; i++) { x += 10 + (Math.abs(r.nextInt()) % 15); y = 20 + Math.abs(r.nextInt()) % 20; g2d.drawChars(data, i, 1, x, y); } g2d.dispose(); response.setContentType("image/png"); OutputStream os = response.getOutputStream(); ImageIO.write(bufferedImage, "png", os); os.close(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } } But in the above code background is also generated using the setPaint menthod I am guessing. I want the background to be some image from my local machine whoz URL i should be able to mention like URL url=this.getClass().getResource("Desktop/images.jpg"); BufferedImage bufferedImage = ImageIO.read(url); I am just writing the above two lines for making the reader understand better what the issue is. Dont want to use the exact same commands. All I want is the the background of the captcha code generated should be an image of my choice.

    Read the article

  • Hiding iAds when loading?

    - by Jesper Mansa
    I'm trying to make an ios app with an iAd in the bottom but lifted a little bit. It actually woks ok but when the iAd is loading it shows an white area just below where the iAd should be. When its done loading the iAd jumps up in the right position. I think normaly the button is loaded outside the screen and nthen pop ups when done but because mine add is liftet a little I can see the loading area... Is there a way to make the iAd load in the sides instead and then popin from the side? Here is what I have so far: frame.origin.x = ( _screenWidth - frame.size.width ) / 2; if( calculateForBannerOnBottom ) frame.origin.y = _screenHeight - (frame.size.height/1.2); else frame.origin.y = -_adView.frame.size.height+(frame.size.height/2.4); Hoping 4 help and thanks in advance :-)

    Read the article

  • JQuery Onclick display selected info

    - by Emily
    I want to display the selected price, category and size on the dropdown slideingDiv. But what I have done below is not working. I have try to echo out to see if the data have been sent thought but I got nothing. Is anything wrong with my code? Script <script type="text/javascript"> $(document).ready(function () { $(".slidingDiv").hide(); $(".show_hide").show(); $('.show_hide').click(function () { $(".slidingDiv").slideToggle(); }); }); </script> Button <button a href="product.php?ProdID=<?php echo $id; ?>" class="show_hide" id="button" name="button">Add to cart</a></button> PHP <div class="slidingDiv"> <?php dbconnect(); $pid = $_POST['pid']; $length = $_POST["size"]; $qty = $_POST['Qty']; $Category = $_POST['Category']; $stmt4 = $conn->prepare(" SELECT Product.Name as ProductName, Category.Name, size, Price FROM item_Product, Product, Category WHERE Product.ProdID =:pid AND size= :length AND Category.Name = :Category Limit 1"); $stmt4->bindParam('pid',$pid); $stmt4->bindParam('length',$length); $stmt4->bindParam('Category',$Category); $stmt4->execute(); foreach ($stmt4->fetchAll(PDO::FETCH_ASSOC) as $row4 ) { $product_name = $row4["ProductName"]; $price = $row4["Price"]; $length = $row4["size"]; $Category = $row4["Name"]; ?> Item was added shopping bag </br> Name:<?php echo $row4['ProductName']; ?> </br> Length:<?php echo $row4['size']; ?> </br> Category:<?php echo $row4['Name']; ?> </br> Price:<?php echo $row4['Price']; ?> </br> <?php } ?> <a href="cart.php">View Cart</a> </div>

    Read the article

  • simple CATextLayer scaling problem

    - by dersubtile
    I'm having a simple scaling problem with CATextLayer, but i just couldn't figure it out: I want the CATextLayer to proportionally grow in size with it's superlayer: if the superlayer's width is 300 the text size of CATextLayer should be 12 and if the supeview's width is 600 the text size should be 24. I couldn't find a working solution! Can you please give me a clue? Thanks, Julian.

    Read the article

  • why does the array doesn't get initialized by global variable , even though it should not?

    - by ashish yadav
    why does the array a does not get initialized by global variable 'size'. include int size=5; int main() { int a[size]={1,2,3,4,5}; printf("%d",a[0]); return 0; } the compilation error is shown as "variable-sized object may not be initialized". according to me the array should get initialized by 'size'. i apologize if i am not clear but i feel i have expressed myself well enough. thank you!!!!!!!!!!!

    Read the article

  • What is the best way to convert this java code into Objective C code??

    - by LCYSoft
    public byte[] toBytes() { size = 12; ByteBuffer buf = ByteBuffer.allocate(size); buf.putInt(type.ordinal());//type is a enum buf.putInt(id); buf.putInt(size); return buf.array(); } @Override public void fromBytes(byte[] data) { ByteBuffer buf = ByteBuffer.allocate(data.length); buf.put(data); buf.rewind(); type = MessageType.values()[buf.getInt()]; id = buf.getInt(); size = buf.getInt(); } Thanks in advance :)

    Read the article

  • Using xsl param (if exists) to replcae attribute value

    - by Assaf
    I would like an xsl that replaces the value attribute of the data elements only if the relevant param names are passed. Input <applicationVariables applicationServer="tomcat"> <data name="HOST" value="localhost"/> <data name="PORT" value="8080"/> <data name="SIZE" value="1000"/> </applicationVariables> So for example if passing in a param HOST1=myHost and PORT=9080 the output should be: <applicationVariables applicationServer="tomcat"> <data name="HOST" value="myHost"/> <data name="PORT" value="9080"/> <data name="SIZE" value="1000"/> </applicationVariables> Note that HOST and PORT where replaced but SIZE was not replaced because there was no parameter with name SIZE Since the list of data elements is long (and may change), i would like a generic way of doing this with xsl

    Read the article

  • HashMap Memory Leak because of Dynamic Array

    - by Jake M
    I am attempting to create my own HashMap to understand how they work. I am using an array of Linked Lists to store the values(strings) in my hashmap. I am creating the array like this: Node** list; Instead of this: Node* list[nSize]; This is so the array can be any size at runtime. But I think I am getting a memory leak because of how I am doing this. I dont know where the error is but when I run the following simple code the .exe crashes. Why is my application crashing and how can I fix it? Note: I am aware that using a vector would be much better than an array but this is just for learning and I want to challenge myself to create the hashmap using a 'Dynamic' Array. PS: is that the correct term(Dynamic Array) for the kind of array I am using? struct Node { // to implement }; class HashMap { public: HashMap(int dynSize) { *list = new Node[dynSize]; size = dynSize; for (int i=0; i<size; i++) list[i] = NULL; cout << "END\n"; } ~HashMap() { for (int i=0; i<size; i++) delete list[i]; } private: Node** list; // I could use a vector here but I am experimenting with a pointer to an array(pointer), also its more elegant int size; }; int main() { // When I run this application it crashes. Where is my memory leak? HashMap h(5); system("PAUSE"); return 0; }

    Read the article

  • Upgrading to 9.2 - Info You Can Use (part 2 - Get Hands On Experience)

    - by John Webb
    Our guest blogger, Rebekah Jackson, continues with a series of helpful hints on planning your upgrade to PeopleSoft 9.2. Get Hands-On Experience With a an Easy to Install Demo Image Once you have identified the features you believe can add value (see part 1 of this series here), we recommend that you use our Demo Images to quickly create a PeopleSoft environment where you can try out the new features. The Demo Images are virtual machines that run in VirtualBox.   They contain a fully functioning PeopleSoft environment, including the database, PeopleTools, and the application.  These images can be loaded onto nearly any sized machine that meets the specs outlined in the documentation, including a powerful desktop machine.     The image allows you to very quickly deploy a fully functioning PeopleSoft instance that you can use to explore new features and functions or run a conference room pilot. To take advantage these Demo Images: Go to the Demo Images Home Page (Doc id 1552548.1) on My Oracle Support. Use the " Demo Image Quick Start Guide" and additional documentation links on that page to download and install your desired Demo Image. New Demo Images are posted for each product area approximately every 10 weeks, available shortly after the corresponding patching image. When installed, use the Demo Image to explore the desired features and capabilities. Important Notes: - It is not required to use the Demo Images to evaluate features and functions – any 9.2 instance will support this. We recommend use of the Demo Images because the setup and configuration is dramatically faster than doing a traditional PeopleSoft install. - For those looking to explore new features and capabilities on PeopleSoft 9.1 releases, we have provided virtual machine images using the Oracle Virtual Machine technology. Details and links are available in Oracle’s PeopleSoft Virtualization Products page (Doc id 1538142.1). /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";}

    Read the article

  • why my customized marker not showing up in openstreet maps

    - by troy
    I have following java script used for showing the customized marker. But for some reasons its showing up the default marker.. function init() { map = new OpenLayers.Map("basicMap"); var mapnik = new OpenLayers.Layer.OSM(); var fromProjection = new OpenLayers.Projection("EPSG:4326"); var toProjection = new OpenLayers.Projection("EPSG:900913"); var position = new OpenLayers.LonLat(-6.242981,53.331201).transform( fromProjection, toProjection); var zoom = 12; map.addLayer(mapnik); var markers = new OpenLayers.Layer.Markers( "Markers" ); map.addLayer(markers); var size = new OpenLayers.Size(16,28); var offset = new OpenLayers.Pixel(-(size.w*0), -(size.h*1)); var icon = new OpenLayers.Icon('http://m.osmtools.de/images/pin_red.png',size,offset); markers.addMarker(new OpenLayers.Marker(position),icon); map.setCenter(position, zoom ); } And here is my html: <body onload="init();"> <div id="basicMap"></div> </body> I dont understand what wrong with my code .... Please help me.. THank You

    Read the article

  • Display radio buttons in prolog xpce

    - by Ben03
    I created a menu with Radio Buttons in XPCE prolog, but my radio buttons are showing on the same line, and I want to have each one on a separate line. My code is the following: new(D, dialog('title')), send(D, size, size(500,500)), send(D, append, new(Op, menu(options, marked))), send(Op, append, option1), send(Op, append, option2), send(Op, append, option3), send(Op, size, size(300,300)), send(D, display, Op, point(100, 40)), send(D, append(new(B1,button(ok, message(D, return, Op?selection))))), send(D, display, B1, point(100, 100)), send(D, append(button(cancel, message(D, return, @nil)))), send(D, default_button(ok)), get(D, confirm, Rval), free(D). Thanks in advance

    Read the article

  • How to unblend two images from a blend image

    - by gavishna
    I have blended/merged 2 images img1 and img2 with this code which is woking fine.What i want to know is how to obtain the original two images img1 and img2.The code for blending is as under img1=imread('C:\MATLAB7\Picture5.jpg'); img2=imread('C:\MATLAB7\Picture6.jpg'); for i=1:size(img1,1) for j=1:size(img1,2) for k=1:size(img1,3) output(i,j,k)=(img1(i,j,k)+img2(i,j,k))/2; end end end imshow(output,[0 255]);

    Read the article

< Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >