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  • Hyperlinks within a table - '<a href="">'.$row['username'].'</a>'

    - by Taimur
    Hi, I have made a leaderboard table on my site, which returns the users in the MySQL database with the highest scores (score is a separate field). The fields in the leaderboard table are 'rank' 'username' and 'score'. I would like to link each username in the table to it's own profile page. The profile pages are in the format /profile.php?user=$username. How would I go about adding an <a href> within the table (which is echoed in php): echo '<tr><td>' .$a. '</td><td><a href="profile.php?user=' .$row['username']. '">' .$row['username']. '</a></td><td>'.$row['count'].'</td></tr>'; I've tried the above, but it doesn't seem to work. It shows the usernames, but they don't have any hyperlinks. Thanks

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  • How to UNION ALL two SELECT statements?

    - by Lisa
    I have 2 tables, one looks like this: TABLE ONE id | Last Name | First Name | Username | Password | Secret Question and another that looks like this: TABLE TWO id | Hobby | Country | I want to combine a Select statement that grabs data from both tables and output the results. The following code: $select = mysql_query(" SELECT * FROM table_one WHERE Username = 'Bob' UNION ALL SELECT * FROM table_two WHERE Hobby = 'Baseball' "); while ($return = mysql_fetch_assoc($select)) { $userName = $return['Username']; $hobby = $return['Hobby']; } echo "$userName likes $hobby"; results in a The used SELECT statements have a different number of columns error, what am I doing wrong?

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  • Refreshing <div> and load data from php

    - by forgatn
    I have on my page and there is a tag where is some and values filled from mySQL DB. I need some JavaScript I think. When I select one option, I want to display in this propriate DATAs which are in DB. without refreshing whole page. Can you tell me how to do it, if you know that please?:) <div id="country1" class="tabcontent"> <label>Choose protocol</label> <SELECT name="cisloprot"> <?php $con = mysql_connect("localhost", "root", "123456"); $sql = "SELECT kod FROM prot GROUP BY kod"; $rs = mysql_query($sql,$con); while ($r = mysql_fetch_array($rs)) { echo "<OPTION VALUE=".$r['kod'].">".$r['kod']."</OPTION>"; } ?> </SELECT> </div>

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  • Writing bash script for X-11 forwarding

    - by Bruce
    I was having problem with SSH X-11 forwarding while I used sudo. I found a solution for it. $hostname server4.a.b.edu First I do: $ echo $DISPLAY localhost:10.0 then $ xauth list server1.a.b.edu/unix:12 MIT-MAGIC-COOKIE-1 6026864294a0e081ac452e8740bcd0fe server4.a.b.edu/unix:10 MIT-MAGIC-COOKIE-1 f01fbfe0c0d68e30b45afe3829b27e58 Then I need to do $ sudo xauth add server4.a.b.edu/unix:10 MIT-MAGIC-COOKIE-1 f01fbfe0c0d68e30b45afe3829b27e58 for sudo to work, for the cookie with my server name and display. How do I write a bash script to automate this?

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  • How to evaluate text strings provided by sed/grep/whatever?

    - by T.J.
    This is for UNIX shell programming. It have to be supported by multiple UNIX platforms including Solaris, Linux, and AIX. I have this scenario -- I am to read from a text file a string that may or may not contain an environment variable that may or may not be defined. For example: <foo.bar> This error code was found: $(error_code) I have the following code: statement=$(sed -n $1'p' $messagefile) echo $echo_flag $statement $1 = line number supplied to this particular function/script. $messagefile = filename of log file. $echo_flag = "-e" in Linux, otherwise, empty. $(error_code) = 42. Instead of getting this when running: <foo.bar> This error code was found: 42 I still get this: <foo.bar> This error code was found: $(error_code) How exactly do I tell the shell script that the value of statement should be evaluated further beyond what sed have done?

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  • Logging into SO with curl

    - by Good Person
    I'm working on a project and I want to log into SO via curl. I use an openid via Google which means that I need to log into Google first. Here is the code I have so far #!/usr/bin/env sh . ./params.sh #the file with username and password curl --silent https://www.google.com/accounts/ClientLogin \ -d Email=$username -d Passwd=$password \ -d accountType=GOOGLE \ -d source=localhost-test-1 \ -d service=lh2 \ -o tokens #get $Auth as a variable . ./tokens echo $Auth; How do I use the $Auth token to log into SO? edit: I found http://code.google.com/apis/gdata/articles/using_cURL.html and I'll post the updated code soon.

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  • PHP mysql_real_escape_string() returning `NULL`

    - by DavidYell
    I'm using PHP Version 5.1.6 and trying to escape a query string from my $_GET array. However my script is returning a NULL after it's escaped. It seems that mysql_escape_string() works fine, but it's deprecated, so I don't want to use it. Having checked over the phpinfo() the MySQL lib is all loaded fine from what I can see. Has anyone experienced this kind of thing before? $term = $_GET['q']; var_dump($term); // string(7) "richard" echo "<br />"; $sterm = mysql_real_escape_string($term, $db); var_dump($sterm); // NULL It's very strange to me, I can't imagine why this function wouldn't work.

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  • system() not working in php using windows server 2003

    - by jazzy
    hi i have to extract the cabfile(.cab) on the server. i am Finding such script which extract cab file but i didn't get it yet. So now i am try to extract using cabarc.exe. But i face the problem that when i run command throuw commandline its work fine but when i give same command to system() or exec() function in php it is not work. code is as follow: $command = "c:\\exe\\cabarc X c:\\cab\\data.cab c:\\data\\"; if(($output = system($command,$return) != false) { echo "$return"; } it is not working when i use same string in commandline it works fine. please any body help me to why it not working what to do tomake it work is ther any rights issue. I had give the execute permission to the site. thanks

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  • sending javascript array to external php file using POST

    - by user1472224
    I am trying to send a javascript array to an external php page, but the only thing the php page is picking up is the fact that I am sending array, not the actual data within the array. javascript - var newArray = [1, 2, 3, 4, 5]; $.ajax({ type: 'POST', url: 'array.php', data: {'something': newArray}, success: function(){ alert("sent"); } }); External PHP Page - <?php echo($_POST['something'])); ?> I know this question has been asked before, but for some reason, this isn't working for me. I have spent the last couple days trying to figure this out as well. Can someone please point me in the right direction. current output (from php page) - Array (thats all the page outputs)

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  • MySQL ON DUPLICATE KEY UPDATE issue

    - by user644347
    Hi could some one look at this and tell me where I am going wrong. I have an SQL statement that when I echo using php I get this to screen INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY UPDATE 'GenreName' = 'Drama' WHERE 'GenreID' = '18' INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '16' , 'GenreName' = 'Animation' ON DUPLICATE KEY UPDATE 'GenreName' = 'Animation' WHERE 'GenreID' = '16' And here is the statement $sql="INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '{$genresID[$i]}' , 'GenreName' = '{$genreName[$i]}' ON DUPLICATE KEY UPDATE 'GenreName' = '{$genreName[$i]}' WHERE 'GenreID' = '{$genresID[$i]}'"; This is the error I recieve: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY ' at line 1 Any help would be greatly appreciated, thanks in advance.

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  • Wordpress parses wp_posts.post_content before rendering?

    - by John
    I noticed that when I call the the_post() or the_content() function from my wordpress template, it automatically parses the database data to replace new lines with <br/>, wraps the text with <p> tags etc...There's probably some kind of "format" function within the_post() or the_content(). I wrote a query to directly get posts from the wp_posts. I then print it out like <?php $results = $wp->get_results($sql) foreach($results as $row) echo $row->post_content; ?> Clearly, this data is not parsed by wordpress' "format" function. What is the proper way to output this content such that it undergoes the same "formatting" functions as the_post() or the_content()?

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  • Unknown error when trying to get long lived access token

    - by Marius.Radvan
    I am trying to get a long lived access token for one of my pages, using this code: $page_info = $facebook->api("/page-id?fields=access_token"); $access_token = array( "client_id" => $facebook->getAppId(), "client_secret" => $facebook->getAppSecret(), "grant_type" => "fb_exchange_token", "fb_exchange_token" => $page_info["access_token"] ); $result = $facebook->api("/oauth/access_token", $access_token); echo json_encode($result); ... but I get this response: {"error_code":1,"error_msg":"An unknown error occurred"} I get the same response if I browse to https://graph.facebook.com/oauth/access_token? client_id=APP_ID& client_secret=APP_SECRET& grant_type=fb_exchange_token& fb_exchange_token=EXISTING_ACCESS_TOKEN as stated in https://developers.facebook.com/roadmap/offline-access-removal/#page_access_token

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  • php session_start() warning

    - by Eniasharmila Karunakaran
    I'm new to php.. Im trying to get value from session. Below is my code. Set session in login page session_start(); $_SESSION["username"] = $username ; $_SESSION["password"] = $password ; $_SESSION["companycode"] = $companycode; Get the session if(! isset($_SESSION)) session_start(); $a=$_SESSION["companycode"]; echo $a; But i got the warning in my page: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\lucent\clientlogin.php:216) in C:\xampp\htdocs\lucent\clientlogin.php on line 219 Please help. Thanks

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  • Erroneous Matches with Regular Expression

    - by Ballsacian1
    $regexp = '/(?:<input\stype="hidden"\sname="){1}([a-zA-Z0-9]*)(?:"\svalue="1"\s\/>)/'; $response = '<input type="hidden" name="7d37dddd0eb2c85b8d394ef36b35f54f" value="1" />'; preg_match($regexp, $response, $matches); echo $matches[1]; // Outputs: 7d37dddd0eb2c85b8d394ef36b35f54f So I'm using this regular expression to search for an authentication token on a webpage implementing Joomla in order to preform a scripted login. I've got all this working but am wondering what is wrong with my regular expression as it always returns 2 items. Array ( [0] => [1] => 7d37dddd0eb2c85b8d394ef36b35f54f) Also the name of the input I'm checking for changes every page load both in length and name.

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  • Drupal - Generating forms from the database.

    - by YsoL8
    Hello I'm trying to teach myself Drupal and I've found something I can't find any tutorials for. I am trying to generate a form, with a dynamic number of text fields, to populate and edit the contents of my custom table. In regular PHP I would achieve this with: $count = '0'; while ($row = mysql_fetch_array ($result) { echo "<input type='text' name='title_row".$count."' value='".$row['title']."'>" $count = $count +1; } Can someone point me to something that'll show me how to do that in Drupal (and processing the submited data)? Thanks

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  • Translate This git_parse_function to zsh?

    - by yar
    I am using this function in Bash function parse_git_branch { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^${IFS}]*)" if [[ ! ${git_status}} =~ "working directory clean" ]]; then state="*" fi # add an else if or two here if you want to get more specific if [[ ${git_status} =~ ${pattern} ]]; then branch=${BASH_REMATCH[1]} echo "(${branch}${state})" fi } but I'm determined to use zsh. While I can use this perfectly as a shell script (even without a shebang) in my .zshrc the error is a parse error on this line if [[ ! ${git_status}}... What do I need to do to get it ready for zshell? Note: I realize the answer could be "go learn zsh syntax," but I was hoping for a quick hand with this if it's not too difficult.

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  • relative path not working for images in css

    - by vagu
    Hi, I have the following file structure: C:/wamp/myproject/admin/webroot/images I have an index.php file lying inside the admin folder which calls a header.inc.php file lying in the same folder. header.inc.php has the following code- <td align="left" valign="top" class="header-bg"> <table width="100%" border="0" cellspacing="0" cellpadding="0"> index.php calls a css file (css.css) through the following code: <link href="<?php echo (WS_DIR_CSS); ?>/css.css" rel="stylesheet" type="text/css" /> The css lies in the following location: C:/wamp/myproject/admin/webroot/css The css files has a class which has the following code: .header-bg { background:url(../images/header_bg.jpg) left top repeat-x; height:77px; } The image header_bg.jpg is not being displayed in the browser. Help anyone?

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  • Unbind Events with JQuery: Does it work with events setup in HTML?

    - by Abs
    Hello all, I have a few onclick and on mouseover events in my html generated by PHP, something like this: <div onmouseover="fave('heart_<?php echo $row['id']; ?>';" class="heart"><a href=""></a></div> I wish to make use of unbind on the mouseover but it hasn't worked when I tried this: $('#'+ id).unbind('mouseover'); So I am guessing unbind will only work with events created by JQuery? Is there something else I can try? Btw, I can't move my events to a separate js file as each id is unique and. Thanks all

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  • Linux - Bash Redirect a String to a file

    - by user3502786
    I wrote a simple script that is reading the file content and incrementing a a number inside this file, then i'm holding the change using awk, when i'm trying ro redirect the new String using '' the whole string is redirected in one line and not like the original was which is 4 lines. #!/bin/bash -x # This script is for Incrementing build numbers path=/home/RND/abrodov file=tst.txt tst=`cat $path/$file` printf "this is the content of the file before incrementing: \n $tst" newexpr=`awk '/^Build Number/{$4=$4+1;}1' /home/RND/abrodov/tst.txt` printf "\n the new content \n $newexpr" echo $newexpr > $path/$file This is the original file before running the script: Major Release Number = 4 Minor Release Number = 1 Service Pack Release Number = 2 Build Number = 22 This is the content after i used the script: Major Release Number = 4 Minor Release Number = 1 Service Pack Release Number = 2 Build Number = 23 I'm trying to figure out how can i redirect the text in the original format which is 4 lines.

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  • Modify bash variables with sed

    - by Alexander Cska
    I am trying to modify a number of environmental variables containing predefined compiler flags. To do so, I tried using a bash loop that goes over all environmental variables listed with "env". for i in $(env | grep ipo | awk 'BEGIN {FS="="} ; { print $1 } ' ) do echo $(sed -e "s/-ipo/ / ; s/-axAVX/ /" <<< $i) done This is not working since the loop variable $i contains just the name of the environmental variable stored as a character string. I tried searching a method to convert a string into a variable but things started becoming unnecessary complicated. The basic problem is how to properly supply the environmental variable itself to sed. Any ideas how to properly modify my script are welcome. Thanks, Alex

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  • Accessing a variable passed by jquery using php

    - by celenius
    How does php access a variable passed by JQuery? I have the following code: $.post("getLatLong.php", { latitude: 500000}, function(data){ alert("Data Loaded: " + data); }); but I don't understand how to access this value using php. I've tried $userLat=$_GET["latitude"]; and $userLat=$_GET[latitude]; and then I try to print out the value (to check that it worked) using: echo $userLat; but it does not return anything. I can't figure out how to access what is being passed to it.

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  • problem in displays data in one page

    - by user318068
    hi ,,,,, I have a problem in the following code ... The following code works as follows displays the invites for each member so that if he had five invite from supposed to be displayed all on one page But before you code that does not function Proper image is the only display one invite on the page and until the approval or rejection of the invitation displays the invite the other .... But this is not my want to offer all on one page I wish I could solve the problem and I can view all calls in one page I think that the problem is in the order code I think that the problem is in the order code my code : <?php session_start(); if (!isset($_SESSION['user_id'])) { header("Location: login.php"); } $id=$_SESSION['user_id']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <center> <?php include("connect.php"); $sql =mysql_query("select * from ninvite where recieverMemberID ='$id' and viwed= '0'"); $num =mysql_num_rows($sql); echo $num ; if ($num>0) { while($row=mysql_fetch_array($sql)) { $sender=$row['SenderMemberID']; $room=$row['RoomID']; $sql =mysql_query("select MemberName from members where MemberID ='$sender' "); $sql1 =mysql_query("select RoomName from rooms where RoomID ='$room' "); while($row=mysql_fetch_array($sql)) {$mem =$row['MemberName']; } while($rows=mysql_fetch_array($sql1)) { $Ro =$rows['RoomName']; ?> <form action="join.php" method="post"> <label> </label> <br/> <label> <?php echo " you have invite from $mem to join $Ro"; ?> </label> <br/><br/> <label>accept</label> <input name="radio1" type="radio" value="accpet" /> <label>reject</label> <input name="radio1" type="radio" value="Reject" /><br/> <input type="submit" name="submit" value="done" /> </form> <?php } } } ?> </center> </body> </html> thanks alot. my SQl -- phpMyAdmin SQL Dump -- version 3.2.4 -- http://www.phpmyadmin.net -- Host: localhost -- Generation Time: May 07, 2010 at 12:50 ? -- Server version: 5.1.41 -- PHP Version: 5.3.1 SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; /*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT /; /!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS /; /!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION /; /!40101 SET NAMES utf8 */; -- -- Database: tr -- -- Table structure for table joinroom CREATE TABLE IF NOT EXISTS joinroom ( MemberID int(10) NOT NULL, RoomID int(10) NOT NULL, PRIMARY KEY (MemberID,RoomID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; -- -- Dumping data for table joinroom INSERT INTO joinroom (MemberID, RoomID) VALUES (28, 1); -- -- Table structure for table members CREATE TABLE IF NOT EXISTS members ( MemberID int(10) unsigned NOT NULL AUTO_INCREMENT, MemberName varchar(20) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberPass varchar(10) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberEmail varchar(30) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberLocation text CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberImg text CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, PRIMARY KEY (MemberID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=34 ; -- -- Dumping data for table members INSERT INTO members (MemberID, MemberName, MemberPass, MemberEmail, MemberLocation, MemberImg) VALUES (28, 'marwa', '1234', '[email protected]', 'mmmmmm', 'dddddddddd'), (29, 'nora', '1234', '[email protected]', 'fffffffffffgg', 'gggggggggggggg'), (30, 'soso', '1234', '[email protected]', 'ffffffff', 'kkkkkkkkkkkkkkkkkk'), (31, 'gege', '1234', '[email protected]', 'kkkkkkkkkkkkkkkk', 'uuuuuuuuuuuuuuuuu'), (32, 'nono', '1234', '[email protected]', 'ggggggggggggaaaaa', 'aaaaaaaaaaaaaaa'), (33, 'nda', '1234', '[email protected]', 'kkkkkkkkkkkkkkkk', 'ooooooooooooooo'); -- -- Table structure for table ninvite CREATE TABLE IF NOT EXISTS ninvite ( SenderMemberID int(11) NOT NULL AUTO_INCREMENT, recieverMemberID varchar(30) NOT NULL, RoomID int(11) NOT NULL, viwed int(11) NOT NULL, PRIMARY KEY (SenderMemberID,recieverMemberID,RoomID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=33 ; -- -- Dumping data for table ninvite INSERT INTO ninvite (SenderMemberID, recieverMemberID, RoomID, viwed) VALUES (28, '33', 1, 0), (28, '32', 1, 0), (28, '31', 1, 0); /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT /; /!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS /; /!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;

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  • Is this a correct json format....

    - by chandru_cp
    I want to get a fair idea about json format... I am using php in which i have converted my result array to json like this $result = mysql_query("select dStud_id,dMarkObtained1,dMarkObtained2, dMarkObtained3,dMarkTotal from tbl_internalmarkallot"); $JsonVar = json_encode($res); echo "<input type='text' name='json' id='json' value ='$JsonVar'>"; And the text box shows {"0":"101","dStud_id":"101","1":"60","dMarkObtained1":"60","2":"80", "dMarkObtained2":"80","3":"80","dMarkObtained3":"80","4":"220","dMarkTotal":"220"} Is this a correct json format....

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  • header problem in php refresh

    - by basma
    hello i have this code : <?php session_start(); echo "".$_SESSION['eventnum'].""; $urlRefresh = "testremot.php"; header("Refresh: 5; URL=\"" . $urlRefresh . "\""); ?> but the header doesnt work and this warning appear when i try to run this code : Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\remot\testremot.php:3) in C:\xampp\htdocs\remot\testremot.php on line 5 can you please help me ?

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  • function file_exists not working in php

    - by Rakesh R Nair
    I have been trying to find if a file_exist in the directory. If not i want to use a different image. But as i am using the file_exists function it always returns false. The code i used is while($r=mysql_fetch_row($res)) { if(!file_exists('http://localhost/dropbox/lib/admin/'.$r[5])) { $file='http://localhost/dropbox/lib/admin/images/noimage.gif'; } else $file='http://localhost/dropbox/lib/admin/'.$r[5];} But the function always return false even if the file exits. I checked that by using <img src="<?php echo 'http://localhost/dropbox/lib/admin/'.$r[5]; ?>" /> This displayed the image correctly. Please Someone Help Me

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