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  • Hide/Show problems on a questionerre application

    - by T. Todd
    I am doing an assignment involving the creation of a simple Quiz type form application. However, whenever I run the program, only the first answer shows for a multiple question and I cannot for the life of me figure out why. This is the contstructor: MultipleChoice dlg = new MultipleChoice( new Question("What is the capital of Zimbabwe?", new Answer("Paris", false), new Answer("Washington D.C.", false), new Answer("Harare", true), new Answer("Cairo", false), new Answer("N'Djamena", false))); if (dlg.ShowDialog() == DialogResult.OK) { if (dlg.Correct) MessageBox.Show("You got something right!"); else MessageBox.Show("You couldn't be more wrong"); } And this is the Question Form Code: private Question Q; public MultipleChoice (Question q) { Q = q; InitializeComponent(); textPrompt.Text = Q.Prompt; if (Q.A != null) { radioA.Text = Q.A.Prompt; } else radioA.Hide(); if (Q.B != null) { radioB.Text = Q.B.Prompt; } radioB.Hide(); if (Q.C != null) { radioC.Text = Q.C.Prompt; } radioC.Hide(); if (Q.D != null) { radioD.Text = Q.D.Prompt; } radioD.Hide(); if (Q.E != null) { radioE.Text = Q.E.Prompt; } radioE.Hide(); } public bool Correct { get { if (Q == null) return false; if (Q.A != null && Q.A.Correct && radioA.Checked) return true; if (Q.B != null && Q.B.Correct && radioB.Checked) return true; if (Q.C != null && Q.C.Correct && radioC.Checked) return true; if (Q.D != null && Q.D.Correct && radioD.Checked) return true; if (Q.E != null && Q.E.Correct && radioE.Checked) return true; return false; } Where have I gone wrong? Thank you, Travis

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  • MODX parse error function implode (is it me or modx?)

    - by Ian
    Hi, I cannot for the life of me figure this out, maybe someone can help. Using MODX a form takes user criteria to create a filter and return a list of documents. The form is one text field and a few checkboxes. If both text field and checkbox data is posted, the function works fine; if just the checkbox data is posted the function works fine; but if just the text field data is posted, modx gives me the following error: Error: implode() [function.implode]: Invalid arguments passed. I've tested this outside of modx with flat files and it all works fine leading me to assume a bug exists within modx. But I'm not convinced. Here's my code: <?php $order = array('price ASC'); //default sort order if(!empty($_POST['tour_finder_duration'])){ //duration submitted $days = htmlentities($_POST['tour_finder_duration']); //clean up post array_unshift($order,"duration DESC"); //add duration sort before default $filter[] = 'duration,'.$days.',4'; //add duration to filter[] (field,criterion,mode) $criteria[] = 'Number of days: <strong>'.$days.'</strong>'; //displayed on results page } if(!empty($_POST['tour_finder_dests'])){ //destination/s submitted $dests = $_POST['tour_finder_dests']; foreach($dests as $value){ //iterate through dests array $filter[] = 'searchDests,'.htmlentities($value).',7'; //add dests to filter[] $params['docid'] = $value; $params['field'] = 'pagetitle'; $pagetitle = $modx->runSnippet('GetField',$params); $dests_array[] = '<a href="[~'.$value.'~]" title="Read more about '.$pagetitle.'" class="tourdestlink">'.$pagetitle.'</a>'; } $dests_array = implode(', ',$dests_array); $criteria[] = 'Destinations: '.$dests_array; //displayed on results page } if(is_array($filter)){ $filter = implode('|',$filter);//pipe-separated string } if(is_array($order)){ $order = implode(',',$order);//comma-separated string } if(is_array($criteria)){ $criteria = implode('<br />',$criteria); } echo '<br />Order: '.$order.'<br /> Filter: '.$filter.'<br /> Criteria: '.$criteria; //next: extract docs using $filter and $order, display user's criteria using $criteria... ?> The echo statement is displayed above the MODX error message and the $filter array is correctly imploded. Any help will save my computer from flying out the window. Thanks

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  • Java: Combination of recursive loops which has different FOR loop inside; Output: FOR loops indexes

    - by vvinjj
    currently recursion is fresh & difficult topic for me, however I need to use it in one of my algorithms. Here is the challenge: I need a method where I specify number of recursions (number of nested FOR loops) and number of iterations for each FOR loop. The result should show me, something simmilar to counter, however each column of counter is limited to specific number. ArrayList<Integer> specs= new ArrayList<Integer>(); specs.add(5); //for(int i=0 to 5; i++) specs.add(7); specs.add(9); specs.add(2); specs.add(8); specs.add(9); public void recursion(ArrayList<Integer> specs){ //number of nested loops will be equal to: specs.size(); //each item in specs, specifies the For loop max count e.g: //First outside loop will be: for(int i=0; i< specs.get(0); i++) //Second loop inside will be: for(int i=0; i< specs.get(1); i++) //... } The the results will be similar to outputs of this manual, nested loop: int[] i; i = new int[7]; for( i[6]=0; i[6]<5; i[6]++){ for( i[5]=0; i[5]<7; i[5]++){ for(i[4] =0; i[4]<9; i[4]++){ for(i[3] =0; i[3]<2; i[3]++){ for(i[2] =0; i[2]<8; i[2]++){ for(i[1] =0; i[1]<9; i[1]++){ //... System.out.println(i[1]+" "+i[2]+" "+i[3]+" "+i[4]+" "+i[5]+" "+i[6]); } } } } } } I already, killed 3 days on this, and still no results, was searching it in internet, however the examples are too different. Therefore, posting the programming question in internet first time in my life. Thank you in advance, you are free to change the code efficiency, I just need the same results.

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  • ASP.NET Application Level vs. Session Level and Global.asax...confused

    - by contactmatt
    The following text is from the book I'm reading, 'MCTS Self-Paced Training Kit (Exam 70-515) Web Applications Development with ASP.NET 4". It gives the rundown of the Application Life Cycle. A user first makes a request for a page in your site. The request is routed to the processing pipeline, which forwards it to the ASP.NET runtime. The ASP.NET runtime creates an instance of the ApplicationManager class; this class instance represents the .NET framework domain that will be used to execute requests for your application. An application domain isolates global variables from other applications and allows each application to load and unload separately, as required. After the application domain has been created, an instance of the HostingEnvironment class is created. This class provides access to items inside the hosting environment, such as directory folders. ASP.NET creates instances of the core objects that will be used to process the request. This includes HttpContext, HttpRequest, and HttpResponse objects. ASP.NET creates an instance of the HttpApplication class (or an instance is reused). This class is also the base class for a site’s Global.asax file. You can use this class to trap events that happen when your application starts or stops. When ASP.NET creates an instance of HttpApplication, it also creates the modules configured for the application, such as the SessionStateModule. Finally, ASP.NET processes request through the HttpApplication pipleline. This pipeline also includes a set of events for validating requests, mapping URLs, accessing the cache, and more. The book then demonstrated an example of using the Global.asax file: <script runat="server"> void Application_Start(object sender, EventArgs e) { Application["UsersOnline"] = 0; } void Session_Start(object sender, EventArgs e) { Application.Lock(); Application["UsersOnline"] = (int)Application["UsersOnline"] + 1; Application.UnLock(); } void Session_End(object sender, EventArgs e) { Application.Lock(); Application["UsersOnline"] = (int)Application["UsersOnline"] - 1; Application.UnLock(); } </script> When does an application start? Whats the difference between session and application level? I'm rather confused on how this is managed. I thought that Application level classes "sat on top of" an AppDomain object, and the AppDomain contained information specific to that Session for that user. Could someone please explain how IIS manages Applicaiton level classes, and how an HttpApplication class sits under an AppDomain? Anything is appreciated.

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  • What variable dictates position of non-focused elements in the roundabout plugin?

    - by kristina childs
    Part of the problem here is that i'm not sure what the best language to use in order to find the solution. I search and searched so please forgive if this is already a thread somewhere. I'm using the roundabout plugin to cycle through 3 divs. Each div is 794px wide, which makes the roundabout-in-focus element 794 and the two not in focus 315.218px wide, positioned so half of each is hidden by the in-focus div. This is all well and good, however the total width of the display needs to stay within 1000px (ideally 980px, but i can fudge if need be.) Basically I want to make the non-focused divs be 3/4 hidden by the in-focus div but for the life of me can't figure out what variables i need to edit in order to do it. Unfortunately it's not one of the many easily-changed options like z-index and minScale. i tried minScale but it's clear this isn't going to work. the plugin outputs this code: <li class="roundabout-moveable-item" style="position: absolute; left: -57px; top: 205px; width: 319.982px; height: 149.513px; opacity: 0.7; z-index: 146; font-size: 5.6px;"> i need to find out what changes the left positioning so it's shifted closer to the center of the stage, like this: <li class="roundabout-moveable-item" style="position: absolute; left: 5px; top: 205px; width: 319.982px; height: 149.513px; opacity: 0.7; z-index: 146; font-size: 5.6px;"> i tried playing with the positioning functions of the plugin but all that did was shift everything in tandem left or right. any help is greatly appreciated. this site is going to be awesome once i figure out all this jquery stuff! here is a link to my .js file: http://avalon.eaw.com/scripts/jquery.roundabout2.js i've got an overflow:hidden on the to help guide the positioning of those no-focused items.

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  • PHP - JSON Steam API query

    - by Hunter
    First time using "JSON" and I've just been working away at my dissertation and I'm integrating a few features from the steam API.. now I'm a little bit confused as to how to create arrays. function test_steamAPI() { $api = ('http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key='.get_Steam_api().'&steamids=76561197960435530'); $test = decode_url($api); var_dump($test['response']['players'][0]['personaname']['steamid']); } //Function to decode and return the data. function decode_url($url) { $decodeURL = $url; $data = file_get_contents($url); $data_output = json_decode($data, true); return $data_output; } So ea I've wrote a simple method to decode Json as I'll be doing a fair bit.. But just wondering the best way to print out arrays.. I can't for the life of me get it to print more than 1 element without it retunring an error e.g. Warning: Illegal string offset 'steamid' in /opt/lampp/htdocs/lan/lan-includes/scripts/class.steam.php on line 48 string(1) "R" So I can print one element, and if I add another it returns errors. EDIT -- Thanks for help, So this was my solution: function test_steamAPI() { $api = ('http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key='.get_Steam_api().'&steamids=76561197960435530,76561197960435530'); $data = decode_url($api); foreach($data ['response']['players'] as $player) { echo "Steam id:" . $player['steamid'] . "\n"; echo "Community visibility :" . $player['communityvisibilitystate'] . "\n"; echo "Player profile" . $player['profileurl'] ."\n"; } } //Function to decode and return the data. function decode_url($url) { $decodeURL = $url; $json = file_get_contents($decodeURL); $data_output = json_decode($json, true); return $data_output; } Worked this out by taking a look at the data.. and a couple json examples, this returns an array based on the Steam API URL (It works for multiple queries.... just FYI) and you can insert loops inside for items etc.. (if anyone searches for this).

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  • Using JavaScript to parse an XML file

    - by Chris Clouten
    I am new to Stack OverFlow and coding in general. I am trying to take an XML file and render it in the browser using JavaScript. I have looked around at some sample code of how to do this and came up with the following code: <!DOCTYPE html> <html> <body> <script> if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.open("GET","social.xml",false); xmlhttp.send(); xmlDoc=xmlhttp.responseXML; document.write("<table border='1'>"); var x=xmlDoc.getElementsByTagName("CD"); for (i=0;i<x.length;i++) { document.write("<tr><td>"); document.write(x[i].getElementsByTagName("c_id")[0].childNodes[0].nodeValue); document.write("</td><td>"); document.write(x[i].getElementsByTagName("facebook_id")[0].childNodes[0].nodeValue); document.write("</td></tr>"); } document.write("</table>"); </script> </body> </html> Anyway, when I run this on my local server none of the data that I am trying to display in the table appears. My .html file and .xml file are in the same folder, so I believe I have the correct file pathway. I could just be making a rookie mistake here, but I can't for the life of me figure out why a table listing the c_id and facebook_id values is not being created. I looked around for answers and haven't been able to find any. Any help would be greatly appreciated. Thanks!

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  • How do you unit test the real world?

    - by Kim Sun-wu
    I'm primarily a C++ coder, and thus far, have managed without really writing tests for all of my code. I've decided this is a Bad Idea(tm), after adding new features that subtly broke old features, or, depending on how you wish to look at it, introduced some new "features" of their own. But, unit testing seems to be an extremely brittle mechanism. You can test for something in "perfect" conditions, but you don't get to see how your code performs when stuff breaks. A for instance is a crawler, let's say it crawls a few specific sites, for data X. Do you simply save sample pages, test against those, and hope that the sites never change? This would work fine as regression tests, but, what sort of tests would you write to constantly check those sites live and let you know when the application isn't doing it's job because the site changed something, that now causes your application to crash? Wouldn't you want your test suite to monitor the intent of the code? The above example is a bit contrived, and something I haven't run into (in case you haven't guessed). Let me pick something I have, though. How do you test an application will do its job in the face of a degraded network stack? That is, say you have a moderate amount of packet loss, for one reason or the other, and you have a function DoSomethingOverTheNetwork() which is supposed to degrade gracefully when the stack isn't performing as it's supposed to; but does it? The developer tests it personally by purposely setting up a gateway that drops packets to simulate a bad network when he first writes it. A few months later, someone checks in some code that modifies something subtly, so the degradation isn't detected in time, or, the application doesn't even recognize the degradation, this is never caught, because you can't run real world tests like this using unit tests, can you? Further, how about file corruption? Let's say you're storing a list of servers in a file, and the checksum looks okay, but the data isn't really. You want the code to handle that, you write some code that you think does that. How do you test that it does exactly that for the life of the application? Can you? Hence, brittleness. Unit tests seem to test the code only in perfect conditions(and this is promoted, with mock objects and such), not what they'll face in the wild. Don't get me wrong, I think unit tests are great, but a test suite composed only of them seems to be a smart way to introduce subtle bugs in your code while feeling overconfident about it's reliability. How do I address the above situations? If unit tests aren't the answer, what is? Thanks!

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  • Flex Air HTMLLoader blank pop up window when flash content is loaded

    - by user128938
    I have a flex Air program that loads external content with the HTMLLoader. Now for some reason whenever I load a page that has any flash content a blank system window pops up outside of my program. It's completely blank, all white with min, max and close buttons. If I close it any flash content I loaded stops working. For the life of my I can't figure out what's happening and there's no messages in the console and no title for the window. Does anyone have any ideas? I appreciate any help you can give. Here's the code I'm using: private var webPage:HTMLLoader; private function registerEvents():void { this.addEventListener(gameLoadEvent.GAME_LOAD, gameLoad); //webPage = new HTMLLoader(); } //function called back from Game Command to load correct game private function gameLoad(event:Event):void { var gameEvent:gameLoadEvent = event as gameLoadEvent; loadgame(gameEvent.url, gameEvent.variables); } private function loadgame(url:String, variableString:String):void { DesktopModelLocator.getInstance().scaleX = 1; DesktopModelLocator.getInstance().scaleY = 1; //var url:String = "http://pro-us.sbt-corp.com/aspx/member/LaunchGame.aspx"; var request:URLRequest = new URLRequest(url); //var variables:URLVariables = new URLVariables("gameNum=17&as=as1&t=demo&package=a&btnQuit=0"); if(variableString != null && variableString != ""){ var variables:URLVariables = new URLVariables(variableString); variables.exampleSessionId = new Date().getTime(); variables.exampleUserLabel = "guest"; request.data = variables; } webPage = HTMLLoader.createRootWindow(true, null, true, null); webPage.height = systemManager.stage.nativeWindow.height - 66; webPage.width = systemManager.stage.nativeWindow.width; webPage.load(request); webPage.navigateInSystemBrowser = false; flexBrowser.addChild(webPage); } ]]> </mx:Script> <mx:HTML id="flexBrowser" width="1366" height="658" backgroundAlpha="0.45" creationComplete="registerEvents();" x="0" y="0"> </mx:HTML>

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  • Two collections and a for loop. (Urgent help needed) Checking an object variable against an inputted

    - by Elliott
    Hi there, I'm relatively new to java, I'm certain the error is trivial. But can't for the life of me spot it. I have an end of term exam on monday and currently trying to get to grips with past papers! Anyway heregoes, in another method (ALGO_1) I search over elements of and check the value H_NAME equals a value entered in the main. When I attempt to run the code I get a null pointer exception, also upon trying to print (with System.out.println etc) the H_NAME value after each for loop in the snippet I also get a null statement returned to me. I am fairly certain that the collection is simply not storing the data gathered up by the Scanner. But then again when I check the collection size with size() it is about the right size. Either way I'm pretty lost and would appreciate the help. Main questions I guess to ask are: from the readBackground method is the data.add in the wrong place? is the snippet simply structured wrongly? oh and another point when I use System.out.println to check the Background object values name, starttime, increment etc they print out fine. Thanks in advance.(PS im guessing the formatting is terrible, apologies.) snippet of code: for(Hydro hd: hydros){ System.out.println(hd.H_NAME); for(Background back : backgs){ System.out.println(back.H_NAME); if(back.H_NAME.equals(hydroName)){ //get error here public static Collection<Background> readBackground(String url) throws IOException { URL u = new URL(url); InputStream is = u.openStream(); InputStreamReader isr = new InputStreamReader(is); BufferedReader b = new BufferedReader(isr); String line =""; Vector<Background> data = new Vector<Background>(); while((line = b.readLine())!= null){ Scanner s = new Scanner(line); String name = s.next(); double starttime = Double.parseDouble(s.next()); double increment = Double.parseDouble(s.next()); double sum = 0; double p = 0; double nterms = 0; while((s.hasNextDouble())){ p = Double.parseDouble(s.next()); nterms++; sum += p; } double pbmean = sum/nterms; Background SAMP = new Background(name, starttime, increment, pbmean); data.add(SAMP); } return data; } Edit/Delete Message

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  • PHP Array problems....if anyone can assist!

    - by Homer_J
    First off, the code which brings back my data into an array: function fetch_questions($page) { global $link; $proc = mysqli_prepare($link, "SELECT * FROM tques WHERE page = $page"); mysqli_stmt_bind_param($proc, "i", $page); mysqli_stmt_execute($proc); $rowq = array(); stmt_bind_assoc($proc, $rowq); // loop through all result rows while ($proc->fetch()) { // print_r($rowq); } mysqli_stmt_close($proc); mysqli_clean_connection($link); return($rowq); } Now, when I `print_r($rowq);' I get the following, which is all good: Array ( [questions] => q1 [qnum] => 1 [qtext] => I find my job meaningful [page] => 1 ) Array ( [questions] => q2 [qnum] => 2 [qtext] => I find my job interesting [page] => 1 ) Array ( [questions] => q3 [qnum] => 3 [qtext] => My work supports ABC's objective [page] => 1 ) Array ( [questions] => q4 [qnum] => 4 [qtext] => I am able to balance my work and home life [page] => 1 ) Array ( [questions] => q5 [qnum] => 5 [qtext] => I am clear about what is expected of me in my job [page] => 1 ) Array ( [questions] => q6 [qnum] => 6 [qtext] => My induction helped me to settle into my job [page] => 1 ) Array ( [questions] => q7 [qnum] => 7 [qtext] => I understand the ABC vision [page] => 1 ) Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) Now, in my php page I have the following piece of script: $questions = fetch_questions($page); And when I print_r $questions, as below: print_r($questions); I only get the following back from the array, 1 row: Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) Any ideas why that might be? Thanks in advance, Homer.

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  • Doing XML extracts with XSLT without having to read the whole DOM tree into memory?

    - by Thorbjørn Ravn Andersen
    I have a situation where I want to extract some information from some very large but regular XML files (just had to do it with a 500 Mb file), and where XSLT would be perfect. Unfortunately those XSLT implementations I am aware of (except the most expensive version of Saxon) does not support only having the necessary part of the DOM read in but reads in the whole tree. This cause the computer to swap to death. The XPath in question is //m/e[contains(.,'foobar') so it is essentially just a grep. Is there an XSLT implementation which can do this? Or an XSLT implementation which given suitable "advice" can do this trick of pruning away the parts in memory which will not be needed again? I'd prefer a Java implementation but both Windows and Linux are viable native platforms. EDIT: The input XML looks like: <log> <!-- Fri Jun 26 12:09:27 CEST 2009 --> <e h='12:09:27,284' l='org.apache.catalina.session.ManagerBase' z='1246010967284' t='ContainerBackgroundProcessor[StandardEngine[Catalina]]' v='10000'> <m>Registering Catalina:type=Manager,path=/axsWHSweb-20090626,host=localhost</m></e> <e h='12:09:27,284' l='org.apache.catalina.session.ManagerBase' z='1246010967284' t='ContainerBackgroundProcessor[StandardEngine[Catalina]]' v='10000'> <m>Force random number initialization starting</m></e> <e h='12:09:27,284' l='org.apache.catalina.session.ManagerBase' z='1246010967284' t='ContainerBackgroundProcessor[StandardEngine[Catalina]]' v='10000'> <m>Getting message digest component for algorithm MD5</m></e> <e h='12:09:27,284' l='org.apache.catalina.session.ManagerBase' z='1246010967284' t='ContainerBackgroundProcessor[StandardEngine[Catalina]]' v='10000'> <m>Completed getting message digest component</m></e> <e h='12:09:27,284' l='org.apache.catalina.session.ManagerBase' z='1246010967284' t='ContainerBackgroundProcessor[StandardEngine[Catalina]]' v='10000'> <m>getDigest() 0</m></e> ...... </log> Essentialy I want to select some m-nodes (and I know the XPath is wrong for that, it was just a quick hack), but maintain the XML layout. EDIT: It appears that STX may be what I am looking for (I can live with another transformation language), and that Joost is an implementation hereof. Any experiences? EDIT: I found that Saxon 6.5.4 with -Xmx1500m could load my XML, so this allowed me to use my XPaths right now. This is just a lucky stroke so I'd still like to solve this generically - this means scriptable which in turn means no handcrafted Java filtering first. EDIT: Oh, by the way. This is a log file very similar to what is generated by the log4j XMLLayout. The reason for XML is to be able to do exactly this, namely do queries on the log. This is the initial try, hence the simple question. Later I'd like to be able to ask more complex questions - therefore I'd like the query language to be able to handle the input file.

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  • Create Views for object properties in model in MVC 3 application?

    - by Anders Svensson
    I have an Asp.Net MVC 3 application with a database "Consultants", accessed by EF. Now, the Consultant table in the db has a one-to-many relationship to several other tables for CV type information (work experience, etc). So a user should be able to fill in their name etc once, but should be able to add a number of "work experiences", and so on. But these foreign key tables are complex objects in the model, and when creating the Create View I only get the simple properties as editor fields. How do I go about designing the View or Views so that the complex objects can be filled in as well? I picture a View in my mind where the simple properties are simple fields, and then some sort of control where you can click "add work experience", and as many as needed would be added. But how would I do that and still utilize the model binding? In fact, I don't know how to go about it at all. (BTW, Program and Language stand for things like software experience in general, and natural language competence, not programming languages, in case you're wondering about the relationships there). Any ideas greatly appreciated! Here's the Create View created by the add View command by default: @{ ViewBag.Title = "Create"; } <h2>Create</h2> <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> @using (Html.BeginForm()) { @Html.ValidationSummary(true) <fieldset> <legend>Consultant</legend> <div class="editor-label"> @Html.LabelFor(model => model.FirstName) </div> <div class="editor-field"> @Html.EditorFor(model => model.FirstName) @Html.ValidationMessageFor(model => model.FirstName) </div> <div class="editor-label"> @Html.LabelFor(model => model.LastName) </div> <div class="editor-field"> @Html.EditorFor(model => model.LastName) @Html.ValidationMessageFor(model => model.LastName) </div> <div class="editor-label"> @Html.LabelFor(model => model.UserName) </div> <div class="editor-field"> @Html.EditorFor(model => model.UserName) @Html.ValidationMessageFor(model => model.UserName) </div> <div class="editor-label"> @Html.LabelFor(model => model.Description) </div> <div class="editor-field"> @Html.EditorFor(model => model.Description) @Html.ValidationMessageFor(model => model.Description) </div> <p> <input type="submit" value="Create" /> </p> </fieldset> } <div> @Html.ActionLink("Back to List", "Index") </div> And here's the EF database diagram:

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  • Spring Framework 3.0.5 MVC Issue

    - by user578923
    I know that this may be absolutely dumb but for the life of me I cannot figure out why I'm getting these errors in my Spring Project, it is basically from the MVC tutorial with a few modifications. This is the error I get when running my tomcat server. `Caused by: java.lang.NoClassDefFoundError: org/springframework/web/servlet/mvc/SimpleFormController at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:634) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142) at java.net.URLClassLoader.defineClass(URLClassLoader.java:277) at java.net.URLClassLoader.access$000(URLClassLoader.java:73) at java.net.URLClassLoader$1.run(URLClassLoader.java:212) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1581) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1511) at org.springframework.util.ClassUtils.forName(ClassUtils.java:257) at org.springframework.beans.factory.support.AbstractBeanDefinition.resolveBeanClass(AbstractBeanDefinition.java:408) at org.springframework.beans.factory.support.AbstractBeanFactory.doResolveBeanClass(AbstractBeanFactory.java:1271) at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1242) ... 54 more Caused by: java.lang.ClassNotFoundException: org.springframework.web.servlet.mvc.SimpleFormController at java.net.URLClassLoader$1.run(URLClassLoader.java:217) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) ... 71 more` I just cannot figure out the issue with my classpath...I would appreciate any help. Here are all the jars in my classpath. I know that the class is inside the web-servlet jar but it's not seeing it. Is there a conflict? aopalliance.jar aspectjweaver.jar commons-codec.jar commons-dbcp.jar commons-logging.jar commons-pool.jar jstl.jar org.springframework.aop-3.0.5.RELEASE.jar org.springframework.asm-3.0.5.RELEASE.jar org.springframework.aspects-3.0.5.RELEASE.jar org.springframework.beans-3.0.5.RELEASE.jar org.springframework.context.support-3.0.5.RELEASE.jar org.springframework.context-3.0.5.RELEASE.jar org.springframework.core-3.0.5.RELEASE.jar org.springframework.expression-3.0.5.RELEASE.jar org.springframework.instrument.tomcat-3.0.5.RELEASE.jar org.springframework.instrument-3.0.5.RELEASE.jar org.springframework.jdbc-3.0.5.RELEASE.jar org.springframework.jms-3.0.5.RELEASE.jar org.springframework.orm-3.0.5.RELEASE.jar org.springframework.oxm-3.0.5.RELEASE.jar org.springframework.test-3.0.5.RELEASE.jar org.springframework.transaction-3.0.5.RELEASE.jar org.springframework.web.portlet-3.0.5.RELEASE.jar org.springframework.web.servlet-3.0.5.RELEASE.jar org.springframework.web.struts-3.0.5.RELEASE.jar org.springframework.web-3.0.5.RELEASE.jar postgresql-9.0-801.jdbc3.jar servlet-api.jar spring-security-config-3.0.5.RELEASE.jar spring-security-core-3.0.5.RELEASE.jar spring-security-web-3.0.5.RELEASE.jar standard.jar

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  • current page highlights on child pages

    - by user557318
    Im trying to achieve current page highlights on wordpress similar to this site Alex Soth. I'm very nearly there with my css. At present i have current page highlights on pages, ie. home,calendar, projects. However when it come to current page highlights on child pages i have a problem. the indented child page list appears on hover when selecting a child page, but after page selection the menu reverts back to the standard pages menu with no visible child menus? unlike the link to the Alex Soth site where the extended menu stays and current page is highlighted I know that the answer will be a simple piece of css involving current_page_item and possible position:relative to obtain the menu staying visible after selection. But i can for the life of me work it out. Any ideas Ive attached my relivant pieces of css below?? thanks /* =Link Styles ------------------------------------------------------------------*/ input#submit { cursor: pointer; } input#searchsubmit { background: url(images/search.png) no-repeat center; } input#searchsubmit:hover { background: url(images/search.png) no-repeat center #3399FF !important; cursor: pointer; } .navigation a:hover, input#submit { background: #3399FF; color: #3399FF !important; } a { color: #666; } a:hover, a:hover span { color: #c11501 !important;background-color: #fae100; } .entry sup a, #main_nav .current_page_item a, #main_nav .current_page_ancestor a { color: #666 !important; } #main_nav h1.masthead a { color: #666; } #main_nav h1.masthead a:hover { border-right: none; } h2 a, #main_nav a { color: #3399FF; } img a, img a:hover { text-decoration: none; } .post a, .navigation a { font-weight: bold; color: #000; } .navigation a { background: #EEE; color: #666; font-weight: normal; padding: 3px 0px; border-radius: 0px; -webkit-border-radius: 0px; -moz-border-radius: 0px; } .post sup { font-size: 11px; color: #aaa; } .post sup a { border: 0; margin: 0; font-weight: normal; font-size: 10px; } #supplementary .post_nav ul.about_nav li a, #supplementary .post_nav ul.single_post_meta a, #supplementary ul.contact_key li a { color: #888888; border-bottom: 0; } /* =Main Menu ------------------------------------------------------------------*/ #main_nav ul.menu li { position: relative; } #main_nav ul.menu li:hover ul.sub-menu, #main_nav ul.menu li:hover ul.children { display: block; }

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  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

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  • Calling back a functions value

    - by Jason Kelly
    I need your help, I cannot, for the life of me, figure this out. I've had my head wrapped around it only to no avail. Ideally, i'd like to setup two functions. 1 function: select_date() to interact with the user to select a date from the jQuery Date picker. If the dialog is closed then return as null. Then a second function: test() to check wether or not a date was picked/selected.' Here's my delema, when the function test() is executed, an alert box pops up and says "undefined" which means, I never get to select a date and it always being "undefined" I dont see what I am doing wrong here and everything seems logical to me. <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.21/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.21/jquery-ui.js"></script> <script type="text/javascript"> function select_date() { var sdate $('#dd').dialog({ autoOpen: true, modal: true, overlay: { opacity: 0.5, background: 'black' }, title: "title", height: 265, width: 235, draggable: false, resizable: false }); $('#d1').datepicker({ onSelect: function () { $("#dd").dialog("close"); } }); return sdate } function test() { var x = select_date() alert(x) } </script> <style type="text/css"> #d1 {font-size:64%;} </style> </head> <body> <div id="dd"> <div id="d1"> </div> </div> <a href="javascript:test()">test</a> </body> </html>

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  • iPad web app: Prevent input focus AFTER ajax call

    - by Mike Barwick
    So I've read around and can't for the life of me figure out of to solve my issue effectively. In short, I have a web app built for the iPad - which works as it should. However, I have an Ajax form which also submits as it should. But, after the callback and I clear/reset my form, the "iPad" automatically focuses on an input and opens the keyboard again. This is far from ideal. I managed to hack my way around it, but it's still not perfect. The code below is run on my ajax callback, which works - except there's still a flash of the keyboard quickly opening and closing. Note, my code won't work unless I use setTimeout. Also, from my understanding, document.activeElement.blur(); only works when there's a click event, so I triggered one via js. IN OTHER WORDS, HOW DO I PREVENT THE KEYBOARD FROM REOPENING AFTER AJAX CALL ON WEB APP? PS: Ajax call works fine and doesn't open the keyboard in Safari on the iPad, just web app mode. Here's my code: hideKeyboard: function () { // iOS web app only, iPad IS_IPAD = navigator.userAgent.match(/iPad/i) != null; if (IS_IPAD) { $(window).one('click', function () { document.activeElement.blur(); }); setTimeout(function () { $(window).trigger('click'); }, 500); } } Maybe it's related to how I'm clearing my forms, so here's that code. Note, all inputs have tabindex="-1" as well. clearForm: function () { // text, textarea, etc $('#campaign-form-wrap > form')[0].reset(); // checkboxes $('input[type="checkbox"]').removeAttr('checked'); $('#campaign-form-wrap > form span.custom.checkbox').removeClass('checked'); // radio inputs $('input[type="radio"]').removeAttr('checked'); $('#campaign-form-wrap > form span.custom.radio').removeClass('checked'); // selects $('form.custom .user-generated-field select').each(function () { var selection = $(this).find('option:first').text(), labelFor = $(this).attr('name'), label = $('[for="' + labelFor + '"]'); label.find('.selection-choice').html(selection); }); optin.hideKeyboard(); }

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  • JSON image viewer not working in firefox

    - by jarga
    I have tried to find out why JSON is not working in Firefox all over this forum and the internet. It works on tablets, ie, safari. It works on my desktop in firefox. It only does not work after uploading I've tried a few things (commented out), such as mimeType with no solution. I have tried using the $.ajax with no better luck. Firefox had no javascript errors. I'm using jQuery 1.7. Console.log is printing out the data. $(document).ready(function(){ jQuery.support.cors = true; //$.ajaxSetup({ mimeType: "application/json" }); /*$.ajaxSetup({ scriptCharset: "utf-8" , contentType: "application/json; charset=utf-8"}); */ // loading pictures $.getJSON("intro.json?format=json", function(data){ var links = ''; var imageload = ''; var title = ''; console.log(data) $.each(data, function(key, item){ links += ' <a href=' + item.image + '>' + key + '</a>'; imageload += '<img src="' + item.image + ' " />'; title += item.alt; }); $('.introCon').html(imageload); $('.introCon img').hide(); $('.introCon img:last').fadeIn(500); $('.introCon img').fadeIn(1000); rotatePics(2); }); }); function rotatePics(currentPhoto) { var numberOfPhotos = $('.introCon img').length; currentPhoto = currentPhoto % numberOfPhotos; $('.introCon img').eq(currentPhoto).fadeOut( function() { // re-order the z-index $('.introCon img').each(function(i) { $(this).css( 'zIndex', ((numberOfPhotos - i) + currentPhoto) % numberOfPhotos ); }); $(this).show(); setTimeout(function() {rotatePics(++currentPhoto);}, 3000); }); } Here is the simple JSON from a separate file. { "1" : { "image" : "portfolio/chrpic.png", "alt" : "Blah.", "detail": "Quartz"}, "2" : { "image" : "portfolio/mysspic.png", "alt" : "Landing page.", "detail": "Container"}, "3" : { "image" : "portfolio/decode-pic3.png", "alt" : "Decode this.", "detail": "Landing page 2"}, "4" : { "image" : "portfolio/simple-think-pic.png", "alt" : "Simple Think", "detail": "simpilify your life"} }

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  • Illegal Start of Expression

    - by Kraivyne
    Hello there, I have just started to learn the very basics of Java programming. Using a book entitled "Programming Video Games for the Evil Genius". I have had an Illegal Start of Expression error that I can't for the life of me get rid of. I have checked the sample code from the book and mine is identical. The error is coming from the for(int i = difficulty; i = 0; i- - ) line. Thanks for helping a newbie out. import javax.swing.*; public class S1P4 {public static void main(String[] args) throws Exception { int difficulty; difficulty = Integer.parseInt(JOptionPane.showInputDialog("How good are you?\n"+ "1 = Great\n"+"10 = Terrible")); boolean cont = false; do { cont = false; double num1 = (int)(Math.round(Math.random()*10)); double num2; do { num2 = (int)(Math.round(Math.random()*10)); } while(num2==0.0); int sign = (int)(Math.round(Math.random()*3)); double answer; System.out.println("\n\n*****"); if(sign==0) { System.out.println(num1+" times "+num2); answer = num1*num2; } else if(sign==1) { System.out.println(num1+" divided by"+num2); answer = num1/num2; } else if(sign==1) { System.out.println(num1+" plus "+num2); answer = num1+num2; } else if(sign==1) { System.out.println(num1+" minus "+num2); answer = num1-num2; } else { System.out.println(num1+" % "+num2); answer = num1%num2; } System.out.println("*****\n"); for(int i = difficulty; i >= 0; i- - ) { System.out.println(i+"..."); Thread.sleep(500); } System.out.println("ANSWER: "+answer); String again; again = JOptionPane.showInputDialog("Play again?"); if(again.equals("yes")) cont = true; } while(cont); } }

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  • Javascript problem when setting src for img element in FireFox - string parsing error?

    - by Kevin
    I'm having problems with image's on the page. I'm using Javascript to create the elements, and in FireFox it seems the string that I'm using to set the innerHTML is not being parsed correctly. I'll see this when the server page is requested with invalid GET variables. They look like this (from the PHP script's error handler): GET[] = Array ( [shrink] => true [file_id] => \' file_id \' [refresh] => \' now.getTime() \' ) This only happens for about 5% of requests, which is making it difficult to solve. I have been able to reproduce this myself in FireFox, and Firebug will show that the URL it is trying to fetch is: https://www.domain.com/secure/%27%20+%20image_src%20+%20%27 I read somewhere that it might be related to FireFox prefetching content (can't find it googling now), since it seems to only happen on FireFox. Disabling prefetching in about:config does prevent the problem from occurring, but I'm looking for another solution or workaround that doesn't involve end users changing their configurations. Here's the specifics and code: I have an empty table cell on an HTML page. In JQuery's $(document).ready() function for the page, I used JQuery's $.ajax() method to get some data from the server about what should be in that cell. It returns the file_id variable, which for simplicity I just set below. It then sets the empty table cell to have an image with src that points to a page that will serve the image file depending on what file_id is passed. This part of the code was JQuery originally, so I changed it to straight Javascript but that didn't help anything. //get data about image from server //this is actually done through JQuery's $.ajax() but you get the idea var file_id = 12; //create the src for the img //the refresh is to prevent the image from being cached ever, since the page's //javascript will be it changes //during the course of the page's life var now = new Date(); var image_src = 'serve_image.php?shrink=true&file_id=' + file_id + '&refresh=' + now.getTime(); //create document.getElementById('image_cell').innerHTML = '<A target="_blank" href="serve_image.php?file_id=' + file_id + '">' + '<IMG id=image_element src="' + image_src + '" alt="Loading...">' + '</A>';` Any help would be greatly appreciated. Thanks!

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  • When to use new layouts and when to use new activities?

    - by cmdfrg
    I'm making a game in Android and I'm trying to add a set of menu screens. Each screen takes up the whole display and has various transitions available to other screens. As a rough summary, the menu screens are: Start screen Difficult select screen Game screen. Pause screen. Game over screen. And there are several different ways you can transition between screen: 1 - 2 2 - 3 3 - 4 (pause game) 4 - 1 (exit game) 4 - 3 (resume game) 3 - 5 (game ends) Obviously, I need some stored state when moving between screens, such as the difficulty level select when starting a game and what the player's score is when the game over screen is shown. Can anyone give me some advice for the easiest way to implement the above screens and transitions in Android? All the create/destroy/pause/resume methods make me nervous about writing brittle code if I'm not careful. I'm not fond of using an Activity for each screen. It seems too heavy weight, having to pass data around using intents seems like a real pain and each screen isn't a useful module by itself. As the "back" button doesn't always go back to the previous screen either, my menu layout doesn't seem to fit the activity model well. At the moment, I'm representing each screen as an XML layout file and I have one activity. I set the different buttons on each layout to call setContentView to update the screen the main activity is showing (e.g. the pause button changes the layout to the pause screen). The activity holds onto all the state needed (e.g. the current difficulty level and the game high score), which makes it easy to share data between screens. This seems roughly similar to the LunarLander sample, except I'm using multiple screens. Does what I have at the moment sound OK or am I not doing things the typical Android way? Is there a class I can use (e.g. something like ViewFlipper) that could make my life easier? By the way, my game screen is implemented as a SurfaceView that stores the game state. I need the state in this view to persist between calls to setContentView (e.g. to resume from paused). Is the right idea to create the game view when the activity starts, keep a reference to it and then use this reference with setContentView whenever I want the game screen to appear?

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  • How to get all captures of subgroup matches with preg_match_all()?

    - by hakre
    Update/Note: I think what I'm probably looking for is to get the captures of a group in PHP. Referenced: PCRE regular expressions using named pattern subroutines. (Read carefully:) I have a string that contains a variable number of segments (simplified): $subject = 'AA BB DD '; // could be 'AA BB DD CC EE ' as well I would like now to match the segments and return them via the matches array: $pattern = '/^(([a-z]+) )+$/i'; $result = preg_match_all($pattern, $subject, $matches); This will only return the last match for the capture group 2: DD. Is there a way that I can retrieve all subpattern captures (AA, BB, DD) with one regex execution? Isn't preg_match_all suitable for this? This question is a generalization. Both the $subject and $pattern are simplified. Naturally with such the general list of AA, BB, .. is much more easy to extract with other functions (e.g. explode) or with a variation of the $pattern. But I'm specifically asking how to return all of the subgroup matches with the preg_...-family of functions. For a real life case imagine you have multiple (nested) level of a variant amount of subpattern matches. Example This is an example in pseudo code to describe a bit of the background. Imagine the following: Regular definitions of tokens: CHARS := [a-z]+ PUNCT := [.,!?] WS := [ ] $subject get's tokenized based on these. The tokenization is stored inside an array of tokens (type, offset, ...). That array is then transformed into a string, containing one character per token: CHARS -> "c" PUNCT -> "p" WS -> "s" So that it's now possible to run regular expressions based on tokens (and not character classes etc.) on the token stream string index. E.g. regex: (cs)?cp to express one or more group of chars followed by a punctuation. As I now can express self-defined tokens as regex, the next step was to build the grammar. This is only an example, this is sort of ABNF style: words = word | (word space)+ word word = CHARS+ space = WS punctuation = PUNCT If I now compile the grammar for words into a (token) regex I would like to have naturally all subgroup matches of each word. words = (CHARS+) | ( (CHARS+) WS )+ (CHARS+) # words resolved to tokens words = (c+)|((c+)s)+c+ # words resolved to regex I could code until this point. Then I ran into the problem that the sub-group matches did only contain their last match. So I have the option to either create an automata for the grammar on my own (which I would like to prevent to keep the grammar expressions generic) or to somewhat make preg_match working for me somehow so I can spare that. That's basically all. Probably now it's understandable why I simplified the question. Related: pcrepattern man page Get repeated matches with preg_match_all()

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  • Type casting int into double C++

    - by user1705380
    I am new to programming and this might be an obvious question, though i cannot for life of me figure out why my program is not returning as a double. I am suppose to write a stocks program that takes in shares of stock, whole dollar portion of price and the fraction portion. And the fraction portion is to be inputted as two int values, and include a function definition with 3 int values.The function returns the price as a double. #include <iostream> using namespace std; int price(int, int, int); int main() { int dollars, numerator, denominator, price1, shares; char ans; do { cout<<"Enter the stock price and the number of shares.\n"; cout<<"Enter the price and integers: Dollars, numerator, denominator\n"; cin>>dollars>>numerator>>denominator; cout<<"Enter the number of shares held\n"; cin>>shares; cout<<shares; price1 = price(dollars,numerator,denominator); cout<<" shares of stock with market price of "; cout<< dollars << " " << numerator<<'/'<<denominator<<endl; cout<<"have a value of " << shares * price1<<endl; cout<<"Enter either Y/y to continue"; cin>>ans; }while (ans == 'Y' || ans == 'y'); system("pause"); return 0; } int price(int dollars, int numerator, int denominator) { return dollars + numerator/static_cast<double>(denominator); }

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  • How To Start Your Own Professional Blog with WordPress

    - by Matthew Guay
    Would you like to start your own blog or website?  With a free WordPress  account, it’s free and easy to get started creating your own professional quality blog site. This is the first part in a series on how to create your own professional quality blog site. No, we’re not talking about some cheapo looking blog from Blogger or something on Facebook, but creating a quality blog you can be proud of and present to millions of readers online. WordPress is one of the most popular blogging platforms, powering hundreds of high-profile websites and blogs around the world.  It’s both powerful and easy to use, which makes it great whether you’re just starting out or are a blogging pro.  To start out with your blogging project WordPress is completely free, and you can use the online interface or install the WordPress software on your own server and blog from there. Getting Started You can start a blog in just a few minutes.  Head over to WordPress.com and click Sign up now on the right-hand side of the main page. Enter a username and password, check that you agree with the legal terms, select the “Gimme a blog” bullet, and click Next. WordPress may inform you that your username is already taken, simply choose a new one and try again. Next, choose a domain for your blog.  This will be the address for your site, and cannot be changed, so be sure to choose exactly what you want.  If you’d prefer your address to be yourname.com instead of yourname.wordpress.com, you can add your own domain for a fee after your blog is setup…but we’ll cover that later. Once you click signup, you will be sent a confirmation email.  While you wait for the email to arrive you can go ahead and enter in your name and a short bio about yourself. When you receive your confirmation email, click the link.  Congratulations; you now have your own blog! You can view your new blog immediately, though the default theme isn’t very interesting without your content and pictures. Back on the page you opened from the email, click Login to access your blog’s administration page and to start adding stuff to your blog.  You can also access your blog’s admin page anytime by from yourname.wordpress.com/admin, substituting your own blog name for yourname. Enter your username and password, then click Log in to get started. Adding Content to your WordPress.com Blog When you sign in to your WordPress blog, you’ll first see the WordPress Admin page.  Here you can see recent posts and comments, and you can see stats of how many people have visited your site.  You can also access all of your blog tools and settings right from this page. To add a new post to your blog, click the Posts link on the left, then click “Add New” either on the left menu or on the top of the Edit Posts page.  Or, if you want to edit the default first post, hover over it and select Edit. Or click the New Posts button on the top of the page.  This menu bar is always visible whenever you’re logged in, so it’s an easy way to add a post. The editor lets you easily write anything you want in a Microsoft Word-style editor.  You can format your text, add lists, links, quotes, and more.  When you’re ready to share your content with the world, click Publish on the right side. To add pictures or other files, click the picture icon beside “Upload/Insert”.  Your free blog account can store up to 3Gb of pictures and documents which will definitely give you a good start. Click Select Files, and then choose the pictures or documents you want to add to your post. When the pictures have uploaded, you can add a caption and choose how to position the picture.  When you’re finished, select “Insert into Post”.   Or, if you want to add a video, click the video button.  You have to add a paid upgrade to upload videos directly, but you can add YouTube and other online videos for free. Click the “From URL” tab, and then paste the link to the YouTube video and click Insert into post. If you’re a code geek, click the HTML tab in the editor and edit the HTML of your blog post the geeky way. Once you’ve added all your content and edited it the way you want, click the Publish button on the right of the editor.  Or, you can click Preview to make sure it looks right, and then click Publish. Here’s our blog with the new blog post containing a picture and video.  While you’re getting to know you’re way around the controls in WordPress, the Preview feature will be your best friend while you try to organize the content to your liking.   Conclusion It only takes a couple minutes to get started blogging at WordPress.com. Whether you want to write about your daily life, share pictures of your children, or review the latest books and gadgets, WordPress.com is a great place to get started for free.  But we’ve only covered a small portion of the WordPress features…but this should get you started. Check back for more WordPress and blogging coverage coming up soon! Links Signup for a free WordPress.com account Similar Articles Productive Geek Tips Add Social Bookmarking (Digg This!) Links to your Wordpress BlogHow-To Geek SoftwareProtecting Your WordPress Admin Panel From Hackers With .htaccessMake a Backup Copy of your Production Wordpress Blog on UbuntuLinux QuickTip: Downloading and Un-tarring in One Step TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Awe inspiring, inter-galactic theme (Win 7) Case Study – How to Optimize Popular Wordpress Sites Restore Hidden Updates in Windows 7 & Vista Iceland an Insurance Job? Find Downloads and Add-ins for Outlook Recycle !

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