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  • Arranging VS2008 generated LinqToSql/EntityFramework data models/contexts in assemblies.

    - by JMSA
    What pattern should I use for data-access in case of VS2008 generated L2s or EF DataModels? Repository-pattern or what? As we know VS2008 generates Data-Models and DataContexts/ObjectContexts in the same file, then, how should I arrange my VS2008 assemblies in my VS2008 solution to achieve a layered design? If I use repository pattern, how should I arrange my assemblies in the VS2008 solution (as Data-Models and Data/Object-Contexts are stored in the same file...)? Any web/example link would be appreciated.

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  • How to get the path of app(without app.exe)?

    - by iPhoney
    I want to get the path of my app like: "\\ProgramFiles\\myApp", I try to use the following code: string path = System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase; But it returns a path which has "\\myapp.exe" at the end. I also tried: string path = System.IO.Directory.GetCurrentDirectory(); But it throws an “NotSupportedException”. Is there any way to get a path without .exe at the end?

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  • convert a sql statement to class?

    - by walter
    Is there a tool or code to convert a sql statement to class? Something like: Dim sqlText = "SELECT CustomerID, Name, Address, City FROM dbo.Customer WHERE CustomerID = 1" Dim obj As New ***SqlStatementTool***(sqlText) obj.GetTables() 'Will Return Tables in sqlText obj.GetWheres() 'Will Return conditions in sqltext obj.GetParameters() 'will return parameters in sqltext

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  • How to extend abstract Entity class in RIA Services

    - by Calanus
    I want to add a bool variable and property to the base Entity class in my RIA services project so that it is available throughout all the entity objects but seem unable to work out how to do this. I know that adding properties to actual entities themselves is easy using .shared.cs and partial classes but adding such properties to the Entity class using similar methods doesn't work. For example, the following code doesn't work namespace System.ServiceModel.DomainServices.Client { public abstract partial class Entity { private bool auditRequired; public bool AuditRequired { get { return auditRequired; } set { auditRequired = value; } } } } All that happens is that the existing Entity class gets totally overriden rather than extending the Entity class. How do I extend the base Entity class so that functionality is available thoughout all derived entity classes?

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  • GUID or int entity key with SQL Compact/EF4?

    - by David Veeneman
    This is a follow-up to an earlier question I posted on EF4 entity keys with SQL Compact. SQL Compact doesn't allow server-generated identity keys, so I am left with creating my own keys as objects are added to the ObjectContext. My first choice would be an integer key, and the previous answer linked to a blog post that shows an extension method that uses the Max operator with a selector expression to find the next available key: public static TResult NextId<TSource, TResult>(this ObjectSet<TSource> table, Expression<Func<TSource, TResult>> selector) where TSource : class { TResult lastId = table.Any() ? table.Max(selector) : default(TResult); if (lastId is int) { lastId = (TResult)(object)(((int)(object)lastId) + 1); } return lastId; } Here's my take on the extension method: It will work fine if the ObjectContext that I am working with has an unfiltered entity set. In that case, the ObjectContext will contain all rows from the data table, and I will get an accurate result. But if the entity set is the result of a query filter, the method will return the last entity key in the filtered entity set, which will not necessarily be the last key in the data table. So I think the extension method won't really work. At this point, the obvious solution seems to be to simply use a GUID as the entity key. That way, I only need to call Guid.NewGuid() method to set the ID property before I add a new entity to my ObjectContext. Here is my question: Is there a simple way of getting the last primary key in the data store from EF4 (without having to create a second ObjectContext for that purpose)? Any other reason not to take the easy way out and simply use a GUID? Thanks for your help.

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  • When transactionManager is not named "transactionManager" ...

    - by smallufo
    I am trying Spring 3(.0.2.RELEASE) and JPA2 and Hibernate 3.5.1-Final... One thing upsets me is that spring seems only accept a transaction Manager named "transactionManager" If I don't name it "transactionManager" , Spring will throws NoSuchBeanDefinitionException: No bean named 'transactionManager' is defined. Here is my config : <context:component-scan base-package="destiny.data.mining"/> <context:annotation-config/> <bean id="miningEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="mining"/> </bean> <bean id="miningTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" > <property name="entityManagerFactory" ref="miningEntityManagerFactory"/> </bean> <tx:advice id="txAdviceMining" transaction-manager="miningTransactionManager"> <tx:attributes> <tx:method name="get*" read-only="true"/> <tx:method name="save*" propagation="REQUIRED"/> <tx:method name="update*" propagation="REQUIRED"/> <tx:method name="delete*" propagation="REQUIRED"/> <tx:method name="*" propagation="SUPPORTS" read-only="true"/> </tx:attributes> </tx:advice> <aop:config> <aop:pointcut id="methods" expression="execution(* destiny.utils.AbstractDao+.*(..))"/> <aop:advisor advice-ref="txAdviceMining" pointcut-ref="methods"/> </aop:config> <tx:annotation-driven transaction-manager="miningTransactionManager"/> In this config , an Entity Manager Factory is not necessarily named "entityManagerFactory" , and "txAdvice" is not necessarily named "txAdvice" , either. But I don't know why on earth Spring requires a transaction manager named "transactionManager" ? Is there any way not to name a transaction manager "transactionManager" ? (I'm running multiple spring config files , so I try my best to avoid name-conflicting) test code : @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations={"classpath:mining.xml"}) public class MiningPersonDaoTest { @Inject private EntityManagerFactory miningEntityManagerFactory; @Inject private MiningPersonDao miningPersonDao; @Transactional @Test public void testUpdate() { MiningPerson p = miningPersonDao.get(42L); p.setLocationName("OOXX"); miningPersonDao.update(p); System.out.println(p); } } ii

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  • Where should I define custom routes in my ZF 1.10 app?

    - by Ross
    With the new Zend_Application/Zend_Application_Bootstrap classes I'm confused as to where I should be applying my custom routes. For example, at the moment I have one route: protected function _initRouter() { $router = new Zend_Controller_Router_Rewrite; $route = new Zend_Controller_Router_Route('news/:id', array('controller' => 'news', 'action' => 'view')); $router->addRoute('postArchive', $route); } This method is in my Zend_Application_Bootstrap_Bootstrap and is definitely run. The route is also applied in $router. As I see it I could be doing two things wrong - either the wrong place to add these routes, or not adding to the correct router. Can anyone point me in the right direction with this?

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  • EF4 Code-First CTP5 Many-to-one

    - by Kevin McKelvin
    I've been trying to get EF4 CTP5 to play nice with an existing database, but struggling with some basic mapping issues. I have two model classes so far: public class Job { [Key, Column(Order = 0)] public int JobNumber { get; set; } [Key, Column(Order = 1)] public int VersionNumber { get; set; } public virtual User OwnedBy { get; set; } } and [Table("Usernames")] public class User { [Key] public string Username { get; set; } public string EmailAddress { get; set; } public bool IsAdministrator { get; set; } } And I have my DbContext class exposing those as IDbSet I can query my users, but as soon as I added the OwnedBy field to the Job class I began getting this error in all my tests for the Jobs: Invalid column name 'UserUsername'. I want this to behave like NHibernate's many-to-one, whereas I think EF4 is treating it as a complex type. How should this be done?

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  • moving EDMX file System.Data.MetadataException: Unable to load the specified metadata resource.

    - by Dani
    I have a ASP.NET MVC 2 project. I've created edmx file on the class library project that holds the model. now I've created another class library called it shared and moved the edmx file over there. resolved some issues, everything compiles, but it can't find the connection string resource at runtime. I've copied the ConnectionString part of the Web.Config to the main file, the old class library app.config file and the new class library app.config file. Still get this error: System.Data.MetadataException: Unable to load the specified metadata resource. Line 75: public myProjdb() : base("name=myProjdb", "MyProjdb") in the MyProj.Designer.cs file. Any Idea how to resolve this issue ? Is there a better way to store connection string data ?

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  • Eager loading in EF1.0

    - by Dave Swersky
    I have a many-to-many relationship: Application - Applications_Servers - Server This is set up in my Entity Data Model and all is well. My problem is that I'd like to eager-load the whole graph of Applications so that I have an IEnumerable<Applications>, each Application member populated with the Servers collection associated by the many-to-many relationship. Normally this wouldn't be a problem, but according to my research there must be a navigation property between Application and Server. This is not the case for me because my Applications_Servers join table has more in it than just the two keys. Therefore, there is no navigation property directly between Application and Server, and this doesn't work: var apps = (from a in context.Application.Include("Server") select a).ToList(); I get an error saying there is no navigation property on Application called "Server", and that's correct, there is none. How do I write the query to eager-load my Applications with their Servers in this case?

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  • How to Have a Bundled Configurable Product in Magento?

    - by Calua
    I've been searching about this topic on Magento forum and Google but can't find a definite answer for the question. Hope I find it here. Is it possible to have a bundled configurable products in Magento? Take for example I want to sell a set of t-shirt and short on a product page where the customer can choose the number of quantity, the color and the size for the t-shirt and short respectively. Maybe like this : T-Shirt [A configurable Product] Color : [combobox to select color] Size : [combobox to select Size] Qty : [input to enter the qty] Short [Another configurable Product] Color : [combobox to select color] Size : [combobox to select Size] Qty : [input to enter the qty] [Add to Cart Button] Any help and answer will be much appreciated. Thanks!

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  • How do I make this Query against EF Efficient?

    - by dudeNumber4
    Using EF4. Assume I have this: IQueryable<ParentEntity> qry = myRepository.GetParentEntities(); Int32 n = 1; What I want to do is this, but EF can't compare against null. qry.Where( parent => parent.Children.Where( child => child.IntCol == n ) != null ) What works is this, but the SQL it produces (as you would imagine) is pretty inefficient: qry.Where( parent => parent.Children.Where( child => child.IntCol == n ).FirstOrDefault().IntCol == n ) How can I do something like the first comparison to null that won't be generating nested queries and so forth?

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  • ZendX Jquery Decorator

    - by iJD
    How use partial decorator in Jquery Element I use this code for Form Element: $title = new Zend_Form_Element_Text('title'); $title->setRequired(true) ->setAttrib('class', 'inputbox') ->setLabel('Title'); $title->viewScript = 'RegElement.phtml'; $title->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); But when i use Jquery Element i dont know how implement it: $datePicker = new ZendX_JQuery_Form_Element_DatePicker( "datePicker1", array("label" => "Date:") ); $datePicker->viewScript = 'RegElement.phtml'; $datePicker->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); //views/scripts/RegElement.phtml <li class="row <?php echo $this->class ?>"> <div class="cont-error"> <?php echo $this->formErrors($this->element->getMessages()); ?> </div> <div class="rowfields"> <?php echo $this->formLabel($this->element->getName(), $this->element->getLabel()) ?> <?php echo $this->{$this->element->helper}( $this->element->getName(), $this->element->getValue(), $this->element->getAttribs() ) ?> </div> <div class="hint"><?php echo $this->element->getDescription() ?></div> </li> And display this error: Warning: Exception caught by form: Cannot render jQuery form element without at least one decorator implementing the 'ZendX_JQuery_Form_Decorator_UiWidgetElementMarker' interface. I need display datePicker with same format. but idk how implement this interface. thx for your help.

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  • SQL Server Compact Edition - Create Database Tables

    - by Lennie De Villiers
    Hi, I got it right to create a SQL Server CE database table using the code below: string connectionString = "DataSource=\"test.sdf\"; Password=\"mypassword\""; SqlCeEngine en = new SqlCeEngine(connectionString); en.CreateDatabase(); But how do I create my database tables and insert data? I've got the SQL created statements stored in the application Resource location.

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  • Get command object

    - by user198147
    Hi all, I am writing a spring 2.5 application and in my jsp I'm writing my own tags. It's about a list of objects...when I change the number of rows that list shows(a combobox), I am doing a submit on my form returning back to the view(obviosly with the new number of rows returned). When listing with my own tags I need to get the properties from my command object. I have access to the pageContext object but I can't figure where the command object is stored. Could someoane please help me? Thanks in advance, Luisa

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  • Zend Routes conflict

    - by meder
    I have defined 2 custom routes. One for threads/:id/:name and the other for threads/tags/:tagName however the second one conflicts with the first because if I enable both then the first breaks and treats :id literally as an action, not obeying the \d+ requirement ( I also tried using pure regex routes, see bottom ). Action "1" does not exist and was not trapped in __call() I tried re-arranging the order of the routes but if I do that then the threads/tags/:tagName doesnt correctly capture the tagName. I also tried disabling default routes but the routes still don't properly work after that. Here's my route init function: protected function _initRoutes() { $fc = Zend_Controller_Front::getInstance(); $router = $fc->getRouter(); $router->addRoute( 'threads', new Zend_Controller_Router_Route('threads/:id/:name', array( 'controller' => 'threads', 'action' => 'thread', ), array( 'id' => '\d+' ) ) ); $router->addRoute( 'threads', new Zend_Controller_Router_Route('threads/tags/:tagName', array( 'controller' => 'threads', 'action' => 'tags', ), array( 'tagName' => '[a-zA-Z]+' ) ) ); } I also tried using a pure regex route but was unsuccessful, most likely because I did it wrong: $router->addRoute( 'threads', new Zend_Controller_Router_Route_Regex( 'threads/(\d+)/([a-zA-Z]+)', array( 'controller' => 'threads', 'action' => 'thread', ), array( 1 => 'tagName', 2 => 'name' ) ) );

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  • How to write simple Where Clause for dynamic filtering in linq when we use groups in join

    - by malik
    I have simple search page i want to filter the results. var TransactionStats = from trans in context.ProductTransactionSet.Include("SPL") select new { trans.InvoiceNo, ProductGroup = from tranline in trans.ProductTransactionLines group tranline by tranline.ProductTransaction.TransactionID into ProductGroupDetil select new { TransactionDateTime = ProductGroupDetil.Select (Content => Content.TransactionDateTime) } }; I want to use TransactionDateTime in where clause when required. if (_FilterCrieteria.DateFrom.HasValue) { TransactionStats.Where ( a => a.ProductGroup.Where ( dt => dt.DateofTransaction >= _FilterCrieteria.DateFrom && dt.DateofTransaction >= _FilterCrieteria.DateFrom ) ) } Can any one correct the syntax?

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  • EF 4.1 Code First Detaching Entity

    - by Nazaf
    I am trying to add an entity to the DB. Once I have added it, I want to detach it, so I can manipulate the object safely without making any changes to the DB. After calling context.SaveChanges() I do the following to detach the entity: // save context.Stories.Add(story); // attach tags. They already exists in the database foreach(var tag in story.Tags) context.Entry(tag).State = System.Data.EntityState.Unchanged; context.SaveChanges(); context.Entry(story).State = System.Data.EntityState.Detached; However, changing the entity state to DETACHED will remove all related entities associated with the my entity. Is there a way to stop this ? If I don't detach the entity, all my changes are sent to the DB next time I call context.SaveChanges() Thanks!!

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  • Login implementation for windows mobile

    - by pdiddy
    What is a good approach for credential checks for windows mobile app. Knowing that it is an occasionally connected device. Should I keep the user credential into the local database? If the credential doesn't exist in the db, try to see if it has internet access and do the check through a web service? If both fails then display an error message ? If logins is successful then store the credential to the local database store then upon next login go against the database first? Is this a good approach?

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  • Need help converting SQL to EF4 please

    - by Ken Eldridge
    I need help converting this SQL statement, into EF4: Select Posts.PostID, Post, Comment from Posts left join Comments on posts.PostID = Comments.PostID Where CommentID not in ( Select PostID from Votes where VoteTypeID = 4 --4 = flagged comment type ) In my database, the Votes table stores either the PostID of reported posts, or CommentID of reported comments in the column Votes.PostID Thanks in advance!

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  • Create Views for object properties in model in MVC 3 application?

    - by Anders Svensson
    I have an Asp.Net MVC 3 application with a database "Consultants", accessed by EF. Now, the Consultant table in the db has a one-to-many relationship to several other tables for CV type information (work experience, etc). So a user should be able to fill in their name etc once, but should be able to add a number of "work experiences", and so on. But these foreign key tables are complex objects in the model, and when creating the Create View I only get the simple properties as editor fields. How do I go about designing the View or Views so that the complex objects can be filled in as well? I picture a View in my mind where the simple properties are simple fields, and then some sort of control where you can click "add work experience", and as many as needed would be added. But how would I do that and still utilize the model binding? In fact, I don't know how to go about it at all. (BTW, Program and Language stand for things like software experience in general, and natural language competence, not programming languages, in case you're wondering about the relationships there). Any ideas greatly appreciated! Here's the Create View created by the add View command by default: @{ ViewBag.Title = "Create"; } <h2>Create</h2> <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> @using (Html.BeginForm()) { @Html.ValidationSummary(true) <fieldset> <legend>Consultant</legend> <div class="editor-label"> @Html.LabelFor(model => model.FirstName) </div> <div class="editor-field"> @Html.EditorFor(model => model.FirstName) @Html.ValidationMessageFor(model => model.FirstName) </div> <div class="editor-label"> @Html.LabelFor(model => model.LastName) </div> <div class="editor-field"> @Html.EditorFor(model => model.LastName) @Html.ValidationMessageFor(model => model.LastName) </div> <div class="editor-label"> @Html.LabelFor(model => model.UserName) </div> <div class="editor-field"> @Html.EditorFor(model => model.UserName) @Html.ValidationMessageFor(model => model.UserName) </div> <div class="editor-label"> @Html.LabelFor(model => model.Description) </div> <div class="editor-field"> @Html.EditorFor(model => model.Description) @Html.ValidationMessageFor(model => model.Description) </div> <p> <input type="submit" value="Create" /> </p> </fieldset> } <div> @Html.ActionLink("Back to List", "Index") </div> And here's the EF database diagram:

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  • How can I remove a duplicate object from a MongoDB array?

    - by andrewrk
    My data looks like this: foo_list: [ { id: '98aa4987-d812-4aba-ac20-92d1079f87b2', name: 'Foo 1', slug: 'foo-1' }, { id: '98aa4987-d812-4aba-ac20-92d1079f87b2', name: 'Foo 1', slug: 'foo-1' } { id: '157569ec-abab-4bfb-b732-55e9c8f4a57d', name: 'Foo 3', slug: 'foo-3' } ] Where foo_list is a field in a model called Bar. Notice that the first and second objects in the array are complete duplicates. Aside from the obvious solution of switching to PostgresSQL, what MongoDB query can I run to remove duplicate entries from foo_list? Similar answers that do not quite cut it: http://stackoverflow.com/a/16907596/432 http://stackoverflow.com/a/18804460/432 These questions answer the question if the array had bare strings in it. However in my situation the array is filled with objects. I hope it is clear that I am not interested in a query; I want the duplicates to be gone from the database forever.

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  • List<T> paging asp.net

    - by user1397978
    Using a three-tier architecture, I have a list of objects List<object> careerList = new List<object>(); ModuleDTO module = new ModuleDTO(); careerList = module.getDegreeCodeByQualification(qualificationCode); which I then add to a gridview like so: gridViewMaster.DataSource = careerList; gridViewMaster.DataBind(); What I'd like to do is then enable paging on the gridview. My gridview so far is: <asp:GridView ID="gridViewMaster" runat="server" AutoGenerateColumns="False" GridLines="None" BorderWidth="1px" CellPadding="2" DataKeyNames="Grouping" ForeColor="Black" onrowdatabound="gridViewMaster_RowDataBound" CssClass="mGrid" PagerStyle-CssClass="pgr" AlternatingRowStyle-CssClass="alt" OnPageIndexChanging="gridView_PageIndexChanging" AllowPaging="True" > Is it possible to do enable paging on a list's without having to change that list to a Datatable or Dataview? If there is a way, this would help a lot. So far my events are as follows: protected void gridView_PageIndexChanging(object sender, GridViewPageEventArgs e) { gridViewMaster.PageIndex = e.NewPageIndex; List<object> careerList = new List<object>(); ModuleDTO module = new ModuleDTO(); careerList = module.getDegreeCodeByQualification(qualificationCode); ModalProgress.Show(); System.Threading.Thread.Sleep(1000); JobPanel.Visible = true; gridViewMaster.DataSource = careerList.Distinct(); gridViewMaster.DataBind(); } Someone PLEASE HELP ME!!! Thank you

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