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  • Easy bidirectional communication via P2P NetStream

    - by andsve
    I've been looking into the P2P support in Flash 10, using Adobe Stratus service. I have successfully been able to send data from one user to another, put my problem is that I haven't figured out how to send data back in some easy way (or as some kind of response to the first call). What I'm currently doing; First set up a connection with Stratus service nc = new NetConnection(); nc.addEventListener(NetStatusEvent.NET_STATUS, ncStatusHandler); nc.connect(APPLICATION_URL + DEVELOPER_KEY); On the "server" side I do: sendStream = new NetStream(nc, NetStream.DIRECT_CONNECTIONS); sendStream.addEventListener(NetStatusEvent.NET_STATUS, sendStreamHandler); sendStream.publish("file"); And on the "client" side: // remoteFileID.text is manually copied by the user from the server (which is nc.nearID). recvStream = new NetStream(nc, remoteFileID.text); recvStream.client = this; recvStream.addEventListener(NetStatusEvent.NET_STATUS, recvStreamHandler); recvStream.play("file"); Then I call a remote function on the client: ... sendStream.send("aRemoteFunction", parameterData); ... Now my problem; I want to do the same from the client to the server, to notify that everything went well, or something failed. From what I understand, I will have to setup a new NetStream from the client to the server (i.e publish on the client and play on the server). But to accomplish this, the server need to know the nc.nearID on the client. Is it possible to get that ID without forcing the user to manually copy it from the client to server? Or, is there an easier way for the client to talk back to the server that I am missing?

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  • Hibernate mapping to manage bidirectional relationship using intermediate table

    - by shikarishambu
    I have an object hierarchy that is as follows. Party inherited by Organization and Person Organization inherited by Customer, Vendor Person inherited by Contact In the database I have the following tables Party, Customer, Vendor, Contact. All of them have a corresponding row in Party table. Contact belongs to either Vendor or Customer. I have a field on the Contact table for org_party_id. However, since the organization can be either a Customer or Vendor I need to be able to look at different tables. Is there a way to map this in hibernate? Or, a better way to manage it in DB/ hibernate?

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  • Unit-testing a directive with isolated scope and bidirectional value

    - by unludo
    I want to unit test a directive which looks like this: angular.module('myApp', []) .directive('myTest', function () { return { restrict: 'E', scope: { message: '='}, replace: true, template: '<div ng-if="message"><p>{{message}}</p></div>', link: function (scope, element, attrs) { } }; }); Here is my failing test: describe('myTest directive:', function () { var scope, compile, validHTML; validHTML = '<my-test message="message"></my-test>'; beforeEach(module('myApp')); beforeEach(inject(function($compile, $rootScope){ scope = $rootScope.$new(); compile = $compile; })); function create() { var elem, compiledElem; elem = angular.element(validHTML); compiledElem = compile(elem)(scope); scope.$digest(); return compiledElem; } it('should have a scope on root element', function () { scope.message = 'not empty'; var el = create(); console.log(el.text()); expect(el.text()).toBeDefined(); expect(el.text()).not.toBe(''); }); }); Can you spot why it's failing? The corresponding jsFiddle Thanks :)

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  • JPA Bidirectional OneToMany and ManyToOne?

    - by PhoenixJon
    I'm using Oracle JDeveloper 11g Release 2. I created two tables A and B using SQL developer. Table A has a FK to table B. Using the Entities from Tables function, I created two JPA files from it. A has @ManyToOne annotation on FK. And also B has @OneToMany annotation to A. I don't want this. Can I remove this @OneToMany annotation automatically? public class A implements Serializable { ... @ManyToOne @JoinColumn(name = "FIELD_B") private B b; ... } public class B implements Serializable { ... @OneToMany(mappedBy = "B") private List<A> assetList; ... } I don't need @OneToMany mapping.

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  • Going "behind Hibernate's back" to update foreign key values without an associated entity

    - by Alex Cruise
    Updated: I wound up "solving" the problem by doing the opposite! I now have the entity reference field set as read-only (insertable=false updatable=false), and the foreign key field read-write. This means I need to take special care when saving new entities, but on querying, the entity properties get resolved for me. I have a bidirectional one-to-many association in my domain model, where I'm using JPA annotations and Hibernate as the persistence provider. It's pretty much your bog-standard parent/child configuration, with one difference being that I want to expose the parent's foreign key as a separate property of the child alongside the reference to a parent instance, like so: @Entity public class Child { @Id @GeneratedValue Long id; @Column(name="parent_id", insertable=false, updatable=false) private Long parentId; @ManyToOne(cascade=CascadeType.ALL) @JoinColumn(name="parent_id") private Parent parent; private long timestamp; } @Entity public class Parent { @Id @GeneratedValue Long id; @OrderBy("timestamp") @OneToMany(mappedBy="parent", cascade=CascadeType.ALL, fetch=FetchType.LAZY) private List<Child> children; } This works just fine most of the time, but there are many (legacy) cases when I'd like to put an invalid value in the parent_id column without having to create a bogus Parent first. Unfortunately, Hibernate won't save values assigned to the parentId field due to insertable=false, updatable=false, which it requires when the same column is mapped to multiple properties. Is there any nice way to "go behind Hibernate's back" and sneak values into that field without having to drop down to JDBC or implement an interceptor? Thanks!

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  • Couchdb conflict resolution

    - by Sundar
    How does CouchDB handles conflicts while doing bi-directional replication? For example: Lets say there are two address book databases (in server A and B). There is a document for Jack which contains contact details of Jack. Server A and B are replicated and both have the same version of Jack document. In server A, Jack's mobile no is updated. In server B, Jack's address is updated. Now when we do bi-directional replication there is a conflict. How does couchDB handles it? If we initiate replication in a Java program, is there a way to know whether there were any conflicts from the java program?

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  • Bi-directional WCF Client-Server Communication

    - by Bill
    I have been working for weeks on creating a client/server to control a music-server application located on the server-side that is controlled by several client apps located across the LAN. I've been successful in getting the client-side to communicate with the Server, sending commands to operate the music-server, and through the use of callbacks, reply to the clients so that all of the client UI's can be appropriately updated. My problem is however, that I unable to figure-out how to broadcast other messages that need to be sent from the server app to the clients. I was hoping to utilize the callback method; however I have not been able to access it from the server side. Do I need to modify or create another contract that provides for communication from the server to the clients? Does the binding require modification? As I mentioned earlier, I have truly been working on this for weeks (which is beginning to feel like 'years'), and hope to get this last piece of the application working. Would someone please steer me in the right direction? Client Side SERVICE REFERENCE: <?xml version="1.0" encoding="utf-8"?> <ServiceReference> <ProxyGenerationParameters ServiceReferenceUri="http://localhost:8001/APService/mex" Name="APGateway" NotifyPropertyChange="True" UseObservableCollection="False"> </ProxyGenerationParameters> <EndPoints> <EndPoint Address="net.tcp://localhost:8000/APService/service" BindingConfiguration="TcpBinding" Contract="APClient.APGateway.APUserService" > </EndPoint> <EndPoint Address="http://localhost:8001/APService/service" BindingConfiguration="HttpBinding" Contract="APClient.APGateway.APUserService" > </EndPoint> </EndPoints> </ServiceReference> Client Side AP CONFIG <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <sectionGroup name="applicationSettings" type="System.Configuration.ApplicationSettingsGroup, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" > <section name="APClient.Properties.Settings" type="System.Configuration.ClientSettingsSection, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" requirePermission="false" /> </sectionGroup> </configSections> <system.serviceModel> <client> <endpoint address="net.tcp://localhost:8000/APService/service" binding="netTcpBinding" contract="APClient.APGateway.APUserService" name="TcpBinding" /> <endpoint address="http://localhost:8001/APService/service" binding="wsDualHttpBinding" contract="APClient.APGateway.APUserService" name="HttpBinding" /> </client> </system.serviceModel> <applicationSettings> <APClient.Properties.Settings> <setting name="pathToDatabase" serializeAs="String"> <value>C:\Users\Bill\Documents\APData\</value> </setting> </APClient.Properties.Settings> </applicationSettings> Server Side AP.CONFIG <?xml version="1.0" encoding="utf-8" ?> <configuration> <system.serviceModel> <behaviors> <serviceBehaviors> <behavior name="MetadataBehavior"> <serviceMetadata httpGetEnabled="true" httpGetUrl="http://localhost:8001/APService/mex" /> </behavior> </serviceBehaviors> </behaviors> <services> <service behaviorConfiguration="MetadataBehavior" name="APService.APService"> <endpoint address="service" binding="netTcpBinding" name="TcpBinding" contract="APService.IAPServiceInventory" /> <endpoint address="service" binding="wsDualHttpBinding" name="HttpBinding" contract="APService.IAPServiceInventory" /> <endpoint address="mex" binding="mexHttpBinding" name="MexBinding" contract="IMetadataExchange" /> <host> <baseAddresses> <add baseAddress="net.tcp://localhost:8000/APService/" /> <add baseAddress="http://localhost:8001/APService/" /> </baseAddresses> </host> </service> </services> </system.serviceModel> </configuration> Server Side APSERVICE.CS namespace APService { [ServiceBehavior(ConcurrencyMode=ConcurrencyMode.Single,InstanceContextMode=InstanceContextMode.PerCall)] public class APService : IAPServiceInventory { private static List<IClientCallback> _callbackList = new List<IClientCallback>(); private static int _beerInventory = Convert.ToInt32(System.Configuration.ConfigurationManager.AppSettings["InitialBeerInventory"]); public APService() {} public int SubscribeToServer(string guestName) { IClientCallback guest = OperationContext.Current.GetCallbackChannel<IClientCallback>(); if(!_callbackList.Contains(guest)) { _callbackList.Add(guest); } else { Console.WriteLine(guest + " is already logged onto the Server."); } _callbackList.ForEach(delegate(IClientCallback callback) { callback.NotifyGuestJoinedParty(guestName); }); } public void UpdateClients(string guestName,string UpdateInfo) { _callbackList.ForEach(delegate(IClientCallback callback) { callback.NotifyUpdateClients(guestName,UpdateInfo); }); } public void SendRequestToServer(string guestName, string request) { _callbackList.ForEach(delegate(IClientCallback callback) { callback.NotifyRequestMadeToServer(guestName,request); }); if(request == "Play") { APControl.Play(); } else if(request == "Stop") { APControl.Stop(); } else if(request == "Pause") { APControl.PlayPause(); } else if(request == "Next Track") { APControl.NextTrack(); } else if(request == "Previous Track") { APControl.PreviousTrack(); } else if(request == "Mute") { APControl.Mute(); } else if(request == "Volume Up") { APControl.VolumeUp(5); } else if(request == "Volume Down") { APControl.VolumeDown(5); } } public void CancelServerSubscription(string guestName) { IClientCallback guest = OperationContext.Current.GetCallbackChannel<IClientCallback>(); if(_callbackList.Contains(guest)) { _callbackList.Remove(guest); } _callbackList.ForEach(delegate(IClientCallback callback) { callback.NotifyGuestLeftParty(guestName); }); } } Server Side IAPSERVICE.CS namespace APService { [ServiceContract(Name="APUserService",Namespace="http://AP.com/WCFClientServer/",SessionMode=SessionMode.Required, CallbackContract=typeof(IClientCallback))] public interface IAPServiceInventory { [OperationContract()] int SubscribeToServer(string guestName); [OperationContract(IsOneWay=true)] void SendRequestToServer(string guestName,string request); [OperationContract(IsOneWay=true)] void UpdateClients(string guestName,string UpdateInfo); [OperationContract(IsOneWay=true)] void CancelServerSubscription(string guestName); } } Server side - IAPServiceCallback.cs namespace APService { public interface IClientCallback { [OperationContract(IsOneWay=true)] void NotifyGuestJoinedParty(string guestName); [OperationContract(IsOneWay=true)] void NotifyUpdateClients(string guestName,string UpdateInfo); [OperationContract(IsOneWay=true)] void NotifyRequestMadeToServer(string guestName,string request); [OperationContract(IsOneWay=true)] void NotifyGuestLeftParty(string guestName); }

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  • UIViewScrollviw UITableView subview scrolling. IOS

    - by user1484810
    I have a UIScrollview with a UITableview subview. The UIScrollview scrolls the UITableView horizontally. The UITable view naturally scrolls up and down. If a user places their finger on the UitableView, and moves (swipes) horizontally, The delegate method below is invoked (void)scrollViewDidScroll:(UIScrollView *)scrollView with scrollView isEqual theUIScrollView If the user lifts their finger and places it back down on the UITableView and moves in a vertical direction The delegate method below is invoked (void)scrollViewDidScroll:(UIScrollView *)scrollView with scrollView isEqual = theUITable If however the user places their finger and moves in a horizontally (void)scrollViewDidScroll:(UIScrollView *)scrollView with scrollView isEqual theUIScrollView If the user then moves the finger (without lifting it) in a vertical direction. delegate method scrollViewDidScroll is not invoked at all. (The reverse is true too.) I note that the "Pulse News" app seems to behave in the above manner.. Ultimately I want to figure out how to get the UITableView and UIScrollview moving in a "unidirectional" fashion, with one finger kept on the screen. Thanks...

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  • how to made one-to-one bidirectional relationships in grails?

    - by user369759
    I have two domain classes and want to have one-to-one BIDIRECTIONAL relation between them. I write: class Person { Book book; String name Integer age Date lastVisit static constraints = { book unique: true // "one-to-one". Without that = "Many-to-one". } } class Book { String title Date releaseDate String ISBN static belongsTo = [person:Person] // it makes relationship bi-directional regarding the grails-docs } So, i want to have bi-directional, i could NOT find link from Book to Person in generated SQL: CREATE TABLE `book` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `version` bigint(20) NOT NULL, `isbn` varchar(255) NOT NULL, `release_date` datetime NOT NULL, `title` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=2 DEFAULT CHARSET=latin1 So then it means it is not bidirectional then? How to make bidirectional?

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  • In a bidirectional JPA OneToMany/ManyToOne association, what is meant by "the inverse side of the as

    - by Bytecode Ninja
    In these examples on TopLink JPA Annotation Reference: Example 1-59 @OneToMany - Customer Class With Generics @Entity public class Customer implements Serializable { ... @OneToMany(cascade=ALL, mappedBy="customer") public Set<Order> getOrders() { return orders; } ... } Example 1-60 @ManyToOne - Order Class With Generics @Entity public class Order implements Serializable { ... @ManyToOne @JoinColumn(name="CUST_ID", nullable=false) public Customer getCustomer() { return customer; } ... } It seams to me that the Customer entity is the owner of the association. However, in the explanation for the mappedBy attribute in the same document, it is written that: if the relationship is bidirectional, then set the mappedBy element on the inverse (non-owning) side of the association to the name of the field or property that owns the relationship as Example 1-60 shows. However, if I am not wrong, looks like in the example the mappedBy is actually specified on the owning side of the association, rather than the non-owning side. So my question is basically: In a bidirectional (one-to-many/many-to-one) association, which of the entities is the owner? How can we designate the One side as the owner? How can we designate the Many side as the owner? What is meant by "the inverse side of the association"? How can we designate the One side as the inverse? How can we designate the Many side as the inverse? Thanks in advance.

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  • What is the difference between Unidirectional and Bidirectional associations?

    - by hguser
    Hi: What is the difference between Unidirectional and Bidirectional associations? Since the table generated in the db are all the same,so the only difference I found is that each side of the bidiretional assocations will have a refer to the other,and the unidirectional not. /////////// This is a Unidirectional association public class User { private int id; private String name; @ManyToOne @JoinColumn( name = "groupId") private Group group; } public class Group { private int id; private String name; } ////////////// The Bidirectional association public class User { private int id; private String name; @ManyToOne @JoinColumn( name = "groupId") private Group group; } public class Group { private int id; private String name; @OneToMany(mappedBy="group") private List<User> users; } The difference is wheather the group hold a refer of the user. So I wonder if this is the only difference? which is recommended?

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  • How to compute a unicode string which bidirectional representation is specified?

    - by valdo
    Hello, fellows. I have a rather pervert question. Please forgive me :) There's an official algorithm that describes how bidirectional unicode text should be presented. http://www.unicode.org/reports/tr9/tr9-15.html I receive a string (from some 3rd-party source), which contains latin/hebrew characters, as well as digits, white-spaces, punctuation symbols and etc. The problem is that the string that I receive is already in the representation form. I.e. - the sequence of characters that I receive should just be presented from left to right. Now, my goal is to find the unicode string which representation is exactly the same. Means - I need to pass that string to another entity; it would then render this string according to the official algorithm, and the result should be the same. Assuming the following: The default text direction (of the rendering entity) is RTL. I don't want to inject "special unicode characters" that explicitly override the text direction (such as RLO, RLE, etc.) I suspect there may exist several solutions. If so - I'd like to preserve the RTL-looking of the string as much as possible. The string usually consists of hebrew words mostly. I'd like to preserve the correct order of those words, and characters inside those words. Whereas other character sequences may (and should) be transposed. One naive way to solve this is just to swap the whole string (this takes care of the hebrew words), and then swap inside it sequences of non-hebrew characters. This however doesn't always produce correct results, because actual rules of representation are rather complex. The only comprehensive algorithm that I see so far is brute-force check. The string can be divided into sequences of same-class characters. Those sequences may be joined in random order, plus any of them may be reversed. I can check all those combinations to obtain the correct result. Plus this technique may be optimized. For instance the order of hebrew words is known, so we only have to check different combinations of their "joining" sequences. Any better ideas? If you have an idea, not necessarily the whole solution - it's ok. I'll appreciate any idea. Thanks in advance.

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  • bidirectional OneToOne Mapping : From Entity to subclass and from superclass to Entity?

    - by Teocali
    I'm trying to establish a tricky bidirectional OneToOne mapping in hibernate. I got the following classes : @Entity @Inheritance(strategy = InheritanceType.JOINED) public class Parent { @OneToOne private AnotherEntity anotherEntity; } @Entity public class Child1 extends Parent{} @Entity public class Child2 extends Parent{} @Entity public class AnotherEntity { @OneToOne(mappedBy = "anotherEntity") private Child1 child1; @OneToOne(mappedBy = "anotherEntity") private Child1 child2; } The problem here is when I'm launching the application : I got the following message : org.hibernate.MappingException: property [anotherEntity] not found on entity [Child1] at org.hibernate.mapping.PersistentClass.getRecursiveProperty(PersistentClass.java:429) at org.hibernate.mapping.PersistentClass.getReferencedProperty(PersistentClass.java:369) at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1614) at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1362) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1727) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1778) at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:189) at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:350) at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:335) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1514) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:294) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:225) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:291) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:193) at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:567) at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:913) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:464) at org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:631) at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:588) at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:645) at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:508) at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:449) at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:133) at javax.servlet.GenericServlet.init(GenericServlet.java:160) at org.apache.catalina.core.StandardWrapper.initServlet(StandardWrapper.java:1266) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1185) at org.apache.catalina.core.StandardWrapper.load(StandardWrapper.java:1080) at org.apache.catalina.core.StandardContext.loadOnStartup(StandardContext.java:5015) at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5302) at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150) at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase.java:895) at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:871) at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:615) at org.apache.catalina.startup.HostConfig.deployWAR(HostConfig.java:962) at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:536) at org.apache.catalina.startup.HostConfig.check(HostConfig.java:1471) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.apache.tomcat.util.modeler.BaseModelMBean.invoke(BaseModelMBean.java:301) at com.sun.jmx.interceptor.DefaultMBeanServerInterceptor.invoke(DefaultMBeanServerInterceptor.java:836) at com.sun.jmx.mbeanserver.JmxMBeanServer.invoke(JmxMBeanServer.java:761) at org.apache.catalina.manager.ManagerServlet.check(ManagerServlet.java:1436) at org.apache.catalina.manager.ManagerServlet.deploy(ManagerServlet.java:673) at org.apache.catalina.manager.ManagerServlet.doPut(ManagerServlet.java:431) at javax.servlet.http.HttpServlet.service(HttpServlet.java:644) at javax.servlet.http.HttpServlet.service(HttpServlet.java:722) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) at org.apache.catalina.filters.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:108) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:225) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:169) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:581) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:168) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:98) at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:927) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407) at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:999) at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:565) at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:307) at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) at java.lang.Thread.run(Thread.java:662) One obvious solution would be to move the anotherEntity field to Child1 and Child2, but it would mean lose the link from Parent to AnotherEntity. Any help welcome.

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  • KODO: how set up fetch plan for bidirectional relationships?

    - by BestPractices
    Running KODO 4.2 and having an issue inefficient queries being generated by KODO. This happens when fetching an object that contains a collection where that collection has a bidrectional relationship back to the first object. Class Classroom { List<Student> _students; } Class Student { Classroom _classroom; } If we create a fetch plan to get a list of Classrooms and their corresponding Students by setting up the following fetch plan: fetchPlan.addField(Classroom.class,”_students”); This will result in two queries (get the classrooms and then get all students that are in those classrooms), which is what we would expect. However, if we include the reference back to the classroom in our fetch plan in order for the _classroom field to get populated by doing fetchPlan.addField(Student.class, “_classroom”), this will result in X number of additional queries where X is the number of students in each classroom. Can anyone explain how to fix this? KODO already has the original Classroom objects at the point that it's executing the queries to retrieve the Classroom objects and set them in each Student object's _classroom field. So I would expect KODO to simply set those objects in the _classroom field on each Student object accordingly and not go back to the database. Once again, the documentation is sorely lacking with Kodo/JDO/OpenJPA but from what I've read it should be able to do this more efficiently. Note-- EAGER_FETCH.PARALLEL is turned on and I have tried this with caching (query and data caches) turned on and off and there is no difference in the resultant queries.

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  • Moses v1.0 multi language ini file

    - by Milan Kocic
    I was working with mosesserver 0.91 and everything works fine but now there is version 1.0 and nothing is same as before. Here is my situation: I want to have multi language translation from arabic to english and from english to arabic. All data and configuration file I have works with 0.91 version of mosesserver. Here is my config file: ------------------------------------------------- ######################### ### MOSES CONFIG FILE ### ######################### # D - decoding path, R - reordering model, L - language model [translation-systems] ar-en D 0 R 0 L 0 en-ar D 1 R 1 L 1 # input factors [input-factors] 0 # mapping steps [mapping] 0 T 0 1 T 1 # translation tables: table type (hierarchical(0), textual (0), binary (1)), source-factors, target-factors, number of scores, file # OLD FORMAT is still handled for back-compatibility # OLD FORMAT translation tables: source-factors, target-factors, number of scores, file # OLD FORMAT a binary table type (1) is assumed [ttable-file] 1 0 0 5 /mnt/models/ar-en/phrase-table/phrase-table 1 0 0 5 /mnt/models/en-ar/phrase-table/phrase-table # no generation models, no generation-file section # language models: type(srilm/irstlm), factors, order, file [lmodel-file] 1 0 5 /mnt/models/ar-en/language-model/en.qblm.mm 1 0 5 /mnt/models/en-ar/language-model/ar.lm.d1.blm.mm # limit on how many phrase translations e for each phrase f are loaded # 0 = all elements loaded [ttable-limit] 20 # distortion (reordering) files [distortion-file] 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/ar-en/reordering-table/reordering-table.wbe-msd-bidirectional-fe.gz 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/en-ar/reordering-model/reordering-table.wbe-msd-bidirectional-fe.gz # distortion (reordering) weight [weight-d] 0.3 0.3 # lexicalised distortion weights [weight-lr] 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 # language model weights [weight-l] 0.5000 0.5000 # translation model weights [weight-t] 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 # no generation models, no weight-generation section # word penalty [weight-w] -1 -1 [distortion-limit] 12 --------------------------------------------------------- So please can someone help me and rewrite this config file so it can work in version 1.0. And i need some python sample code of translation. I am using xmlrpc in python and earler I sent http request with: import xmlrpclib client = xmlrpclib.ServerProxy('http://localhost:8080') client.translate({'text': 'some text', 'system': 'en-ar'}) but now seems there is no more 'system' parameter and moses use always default settings.

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  • How to Make a DVCS Completely Interoperable with Subversion?

    - by David M
    What architectural changes would a DVCS need to be completely interoperable with Subversion? Many DVCSs have some kind of bidirectional interface with Subversion, but there are limitations and caveats. For instance, git-svn can create a repository that mirrors Subversion, and changes to that repo can be sent back to Subversion via 'dcommit'. But the git-svn manpage explicitly cautions against making clones of that repository, so essentially, it's a Subversion working copy that you can use git commands on. Bazaar has a bidirectional Subversion capability too, but its documentation notes that Subversion properties aren't supported at all. Here's the end that I'm pursuing. I want a Subversion repository and a DVCS repository that, in the steady state, have identical content. When something is changed on one, it's automatically mirrored to the other. Subversion users interact with the Subversion repository normally. DVCS users clone the DVCS repository, pull changes from it, and push changes back to it. Most importantly, they don't need to know that this special DVCS repository is associated with a Subversion repository. It would probably be nifty if any clone of the special repository is itself a special repository and could commit directly to Subversion, but it might be sufficient if only the special repository directly interacts with Subversion. I think that's what mostly needed is to improve the bidirectional capability so that changes to Subversion properties are translated to changes in the DVCS repository. Some changes in the DVCS repository would be translated to changes to Subversion properties. Or is the answer to create a new capability in Subversion that interacts with a DVCS repository, using the DVCS repository as just a special storage layer such as fsfs or bdb? If there's not a direct mapping between the things that Subversion and a DVCS regard as having versions, does that imply that there's always going to be some activity that cannot be recorded properly on one or the other?

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  • Common and useful Graph functions?

    - by Nazgulled
    Hi, I'm implementing a simple Graph library for my uni project and since this is the first time I'm dealing with graphs, I would like to know which functions you guys consider to be most common and useful for Graph implementations... So far, I have this: graphInitialize() graphInsertVertex() graphRemoveVertex() graphGetVertex() graphGetVertexValue() (not implemented yet, not sure if I'll need it) graphInsertEdge() graphRemoveEdge() graphLinkVertices() (this calls graphInsertEdge twice for bidirectional graph) graphUnlinkVertices() (this calls graphRemoveEdge twice for bidirectional graph) graphDestroy() I know I'm missing a function do determine the shortest path, but I'm leaving that for last... Do you think I'm missing any common/useful function?

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  • Creating a two-way Forest trust with Powershell

    - by Michel Klomp
    Here is a small Powershell script for creating a two-way forest trust. $localforest = [System.DirectoryServices.ActiveDirectory.Forest]::getCurrentForest() $strRemoteForest = ‘domain.local’ $strRemoteUser = ‘administrator’ $strRemotePassword = ‘P@ssw0rd’ $remoteContext = New-Object System.DirectoryServices.ActiveDirectory.DirectoryContext(‘Forest’, $strRemoteForest,$strRemoteUser,$strRemotePassword) $remoteForest = [System.DirectoryServices.ActiveDirectory.Forest]::getForest($remoteContext) $localForest.CreateTrustRelationship($remoteForest,’Bidirectional’)

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  • Python - pyparsing unicode characters

    - by mgj
    Hi..:) I tried using w = Word(printables), but it isn't working. How should I give the spec for this. 'w' is meant to process Hindi characters (UTF-8) The code specifies the grammar and parses accordingly. 671.assess :: ????? ::2 x=number + "." + src + "::" + w + "::" + number + "." + number If there is only english characters it is working so the code is correct for the ascii format but the code is not working for the unicode format. I mean that the code works when we have something of the form 671.assess :: ahsaas ::2 i.e. it parses words in the english format, but I am not sure how to parse and then print characters in the unicode format. I need this for English Hindi word alignment for purpose. The python code looks like this: # -*- coding: utf-8 -*- from pyparsing import Literal, Word, Optional, nums, alphas, ZeroOrMore, printables , Group , alphas8bit , # grammar src = Word(printables) trans = Word(printables) number = Word(nums) x=number + "." + src + "::" + trans + "::" + number + "." + number #parsing for eng-dict efiledata = open('b1aop_or_not_word.txt').read() eresults = x.parseString(efiledata) edict1 = {} edict2 = {} counter=0 xx=list() for result in eresults: trans=""#translation string ew=""#english word xx=result[0] ew=xx[2] trans=xx[4] edict1 = { ew:trans } edict2.update(edict1) print len(edict2) #no of entries in the english dictionary print "edict2 has been created" print "english dictionary" , edict2 #parsing for hin-dict hfiledata = open('b1aop_or_not_word.txt').read() hresults = x.scanString(hfiledata) hdict1 = {} hdict2 = {} counter=0 for result in hresults: trans=""#translation string hw=""#hin word xx=result[0] hw=xx[2] trans=xx[4] #print trans hdict1 = { trans:hw } hdict2.update(hdict1) print len(hdict2) #no of entries in the hindi dictionary print"hdict2 has been created" print "hindi dictionary" , hdict2 ''' ####################################################################################################################### def translate(d, ow, hinlist): if ow in d.keys():#ow=old word d=dict print ow , "exists in the dictionary keys" transes = d[ow] transes = transes.split() print "possible transes for" , ow , " = ", transes for word in transes: if word in hinlist: print "trans for" , ow , " = ", word return word return None else: print ow , "absent" return None f = open('bidir','w') #lines = ["'\ #5# 10 # and better performance in business in turn benefits consumers . # 0 0 0 0 0 0 0 0 0 0 \ #5# 11 # vHyaapaar mEmn bEhtr kaam upbhOkHtaaomn kE lIe laabhpHrdd hOtaa hAI . # 0 0 0 0 0 0 0 0 0 0 0 \ #'"] data=open('bi_full_2','rb').read() lines = data.split('!@#$%') loc=0 for line in lines: eng, hin = [subline.split(' # ') for subline in line.strip('\n').split('\n')] for transdict, source, dest in [(edict2, eng, hin), (hdict2, hin, eng)]: sourcethings = source[2].split() for word in source[1].split(): tl = dest[1].split() otherword = translate(transdict, word, tl) loc = source[1].split().index(word) if otherword is not None: otherword = otherword.strip() print word, ' <-> ', otherword, 'meaning=good' if otherword in dest[1].split(): print word, ' <-> ', otherword, 'trans=good' sourcethings[loc] = str( dest[1].split().index(otherword) + 1) source[2] = ' '.join(sourcethings) eng = ' # '.join(eng) hin = ' # '.join(hin) f.write(eng+'\n'+hin+'\n\n\n') f.close() ''' if an example input sentence for the source file is: 1# 5 # modern markets : confident consumers # 0 0 0 0 0 1# 6 # AddhUnIk baajaar : AshHvsHt upbhOkHtaa . # 0 0 0 0 0 0 !@#$% the ouptut would look like this :- 1# 5 # modern markets : confident consumers # 1 2 3 4 5 1# 6 # AddhUnIk baajaar : AshHvsHt upbhOkHtaa . # 1 2 3 4 5 0 !@#$% Output Explanation:- This achieves bidirectional alignment. It means the first word of english 'modern' maps to the first word of hindi 'AddhUnIk' and vice versa. Here even characters are take as words as they also are an integral part of bidirectional mapping. Thus if you observe the hindi WORD '.' has a null alignment and it maps to nothing with respect to the English sentence as it doesn't have a full stop. The 3rd line int the output basically represents a delimiter when we are working for a number of sentences for which your trying to achieve bidirectional mapping. What modification should i make for it to work if the I have the hindi sentences in Unicode(UTF-8) format.

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  • Does a router have a receiving range?

    - by Aadit M Shah
    So my dad bought a TP-Link router (Model No. TL-WA7510N) which apparently has a transmitting range of 1km; and he believes that it also has a receiving range of 1km. So he's arguing with me that the router (which is a trans-receiver) can communicate with any device in the range of 1km whether or not that device has a transmitting range of 1km. To put it graphically: +----+ 1km +----+ | |------------------------------------------------->| | | TR | | TR | | | <----| | +----+ 100m+----+ So here's the problem: The two devices are 1km apart. The first device has a transmitting range of 1km. The second device only has a transmitting range of 100m. According to my dad the two devices can talk to each other. He says that the first device has a transmitting and a receiving range of 1km which means that it can both send data to devices 1km away and receive data from devices 1km away. To me this makes no sense. If the second device can only send data to devices 100m away then how can the first device catch the transmission? He further argues that for bidirectional communication both the sender and the reciver should have overlapping areas of transmission: According to him if two devices have an overlapping area of transmission then they can communicate. Here neither device has enough transmission power to reach the other. However they have enough receiving power to capture the transmission. Obviously this makes absolutely no sense to me. How can a device sense a transmission which hasn't even reached it yet and go out, capture it and bring it back it. To me a trans-receiver only has a transmission power. It has zero receiving power. Hence for two devices to be able to communicate bidirectionally, the diagram should look like: Hence, from my point of view, both the devices should have a transmission range far enough to reach the other for bidirectional communication to be possible; but no matter how much I try to explain to my dad he adamantly disagrees. So, to put an end to this debate once and for all, who is correct? Is there even such a thing as a receiving range? Can a device fetch a transmission that would otherwise never reach it? I would like a canonical answer on this.

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  • How to hide a trusted domain in the logon screen?

    - by Massimo
    I need to create a bidirectional trust between two Active Directory domains. But management is worried that users will be puzzled out when seeing another domain name in the drop-down list in the Windows logon screen (many of them use Windows XP), and that help desk calls for failed logins due to having selected the wrong domain will skyrocket. Also, the two domain names are quite similar, adding to the possible user confusion. Is there any way to hide a trusted domain from the drop-down list in the Windows logon screen?

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  • Ubuntu Server VM: copy paste?

    - by bukzor
    I've installed Ubuntu Server under Virtualbox just to get a nice little shell. I've also installed the VirtualBox "Guest Additions" and set "Shared Clipboard: Bidirectional". I still can't seem to get any copy-paste working. Am I missing something here? I've installed gpm which gives mouse support in server mode (no X), and allows copy-paste using the mouse, but still the VirtualBox integration doesn't work.

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  • Ubuntu Server VM: copy paste?

    - by bukzor
    I've installed Ubuntu Server under Virtualbox just to get a nice little shell. I've also installed the VirtualBox "Guest Additions" and set "Shared Clipboard: Bidirectional". I still can't seem to get any copy-paste working. Am I missing something here? I've installed gpm which gives mouse support in server mode (no X), and allows copy-paste using the mouse, but still the VirtualBox integration doesn't work.

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