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  • Select row After UIPickerView is loaded

    - by Steve Gibson
    I have an iphone database app that loads a UIPickerView with data from a table. I want to set the selected row to a particular row from the data in another table. for example: Lets say I have a UIPickerView that is loaded with X number of names of the iPhone users friends (the number of names is variable, could be 1 or 1000 and all are entered into the DB by the user). The iPhone user has a preference set that their current best friend is TED. I want the UIPickerView to be position to TED when displayed. Where do I call selectRow? I tried in viewDidAppear but it was never called, in titleForRow which caused all kinds of strange behavior. viewDidLoad and viewWillAppear are out of the question because I don't know what's in the datasource to the picker yet. Thanks in advance.

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  • NULL value when using NSDateFormatter

    - by David A Gibson
    Hello, I am using the following code to try and display in a time in a table cell. TimeSlot *timeSlot = [timeSlots objectAtIndex:indexPath.row]; NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init]; [timeFormat setDateFormat:@"%1m/%1d/%Y"]; NSLog(@"Time: %@", timeSlot.time); NSDate *mydate = timeSlot.time; NSLog(@"Time: %@", mydate); NSString *theTime = [timeFormat stringFromDate:mydate]; NSLog(@"Time: %@", theTime); The log output is this: 2010-04-14 10:23:54.626 MyApp[1080:207] Time: 2010-04-14T10:23:54 2010-04-14 10:23:54.627 MyApp[1080:207] Time: 2010-04-14T10:23:54 2010-04-14 10:23:54.627 MyApp[1080:207] Time: (null) I am new to developing for the iPhone and as it all compiles with no errors or warnings I am at a loss as to why I am getting NULL in the log. Is there anything wrong with this code? Thanks

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  • NULL value when using NSDateFormatter after setting NSDate property via XML parsing

    - by David A Gibson
    Hello, I am using the following code to try and display in a time in a table cell. TimeSlot *timeSlot = [timeSlots objectAtIndex:indexPath.row]; NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init]; [timeFormat setDateFormat:@"HH:mm:ss"]; NSLog(@"Time: %@", timeSlot.time); NSDate *mydate = timeSlot.time; NSLog(@"Time: %@", mydate); NSString *theTime = [timeFormat stringFromDate:mydate]; NSLog(@"Time: %@", theTime); The log output is this: 2010-04-14 10:23:54.626 MyApp[1080:207] Time: 2010-04-14T10:23:54 2010-04-14 10:23:54.627 MyApp[1080:207] Time: 2010-04-14T10:23:54 2010-04-14 10:23:54.627 MyApp[1080:207] Time: (null) I am new to developing for the iPhone and as it all compiles with no errors or warnings I am at a loss as to why I am getting NULL in the log. Is there anything wrong with this code? Thanks Further Info I used the code exactly from your answer lugte098 just to check and I was getting dates which leads me to believe that my TimeSlot class can't have a date correctly set in it's NSDate property. So my question becomes - how from XML do I set a NSDate property? I have this code (abbreviated): -(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *) string { if ([currentElement isEqualToString:@"Time"]) { currentTimeSlot.time = string } } Thanks

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  • How to create Shared VB Array Initialisors for NerdDinner

    - by David A Gibson
    Hello, I am trying to work my way through the NerdDinner tutorial - and as an exercise I'm converting it to VB as I go. I'm not very far in and after having gotten past the C# Yield statement I'm stuck on Shared VB Array Initialisors. static IDictionary<string, Regex> countryRegex = new Dictionary<string, Regex>() { { "USA", new Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$")}, { "UK", new Regex("(^1300\\d{6}$)|(^1800|1900|1902\\d{6}$)|(^0[2|3|7|8]{1}[0- 9]{8}$)|(^13\\d{4}$)|(^04\\d{2,3}\\d{6}$)")}, { "Netherlands", new Regex("(^\\+[0-9]{2}|^\\+[0- 9]{2}\\(0\\)|^\\(\\+[0-9]{2}\\)\\(0\\)|^00[0-9]{2}|^0)([0-9]{9}$|[0-9\\- \\s]{10}$)")}, Can anyone please help me write this in VB? Public Shared countryRegex As IDictionary(Of String, Regex) = New Dictionary(Of String, Regex)() {("USA", New Regex("^[2-9]\\d{2}-\\d{3}-\\d{4}$"))} This code has an error as it does not accept the String and the Regex as an item for the array. Thanks

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  • Setting TreeView.DataContext doesn't refresh the tree

    - by dan gibson
    I have a List that I've bound to a TreeView. Setting TreeView.DataContext works - everything displays correctly. I then change the list (add an item to it) and set TreeView.DataContext again (to the same value) but the tree does not refresh with the new items. How do I get the treeview to refresh? This is basically my code: public class xItemCollection : ObservableCollection<xItem> { } public class xItem : INotifyPropertyChanged { xItemCollection _Items; public xItem() { _Items = new xItemCollection(); } public xItemCollection Items {get{return _Items;}} } ... this.RootItem = new xItem(); treeView.DataContext = this; Adding items to the list works until the tree is rendered for the first time. After it is rendered, adding/removing items does not refresh the tree.

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  • JFrame not working correctly

    - by Nick Gibson
    This is making me very angry, I have worked on this for 2 days, have 2 books open and have looked through them, and STILL can't get this program to run the way I want it run. I'm getting to the point where if this doesn't help, I quit. I want a SIMPLE Frame application. It has a JComboBox centered at the top. Next to it is a text field big enough to show numeric digits such as "$49.99" Below it is a spot for a Text area showing terms of service Below that is the checkbox agreeing to the terms of service Below that is 2 buttons "Accept" and "Decline" I Have worked on this for 2 days, here is the coding: public class Bar extends JFrame implements ActionListener { public Bar(final JFrame frame) { String[] tests = { "A+ Certification", "Network+ Certification", "Security+ Certification", "CIT Full Test Package" }; JButton button = new JButton("Click Meh"); add(new JLabel("Welcome to the CIT Test Program ")); add(new JLabel("Please select which Test Package from the list below.")); frame.setVisible(true); frame.setSize(250,250); JPanel pane1 = new JPanel(new FlowLayout()); JPanel pane2 = new JPanel(new FlowLayout()); JMenuBar menuBar = new JMenuBar(); JMenu fileMenu = new JMenu("File"); JMenu editMenu = new JMenu("Edit"); JMenu helpMenu = new JMenu("Help"); menuBar.add(fileMenu); menuBar.add(editMenu); menuBar.add(helpMenu); JMenuItem newMenu = new JMenuItem("New (Ctrl+N)"); JMenuItem openMenu = new JMenuItem("Open (Ctrl+O)"); JMenuItem saveMenu = new JMenuItem("Save (Ctrl+S)"); saveMenu.addActionListener(this); JMenuItem exitMenu = new JMenuItem("Exit (Ctrl+W)"); JMenuItem cutMenu = new JMenuItem("Cut (Ctrl+X)"); JMenuItem copyMenu = new JMenuItem("Copy (Ctrl+C)"); JMenuItem pasteMenu = new JMenuItem("Paste (Ctrl+V)"); JMenuItem infoMenu = new JMenuItem("Help (Ctrl+H)"); fileMenu.add(newMenu); fileMenu.add(openMenu); fileMenu.add(saveMenu); fileMenu.add(exitMenu); editMenu.add(cutMenu); editMenu.add(copyMenu); editMenu.add(pasteMenu); helpMenu.add(infoMenu); frame.setJMenuBar(menuBar); JComboBox packageChoice = new JComboBox(tests); frame.add(packageChoice); } public void actionPerformed(ActionEvent e) { Object source = e.getSource(); { } } EDIT: Forgot to add the second program public class JFrameWithPanel { public static void main(String[] args) { JPanel panel = new Bar(new JFrame("CIT Test Program")); } } How do I get this to have everything where I want it and show up? I'm very confused because of this and now barely even get how Frames work.

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  • How to create database records for a financial year

    - by David A Gibson
    Hello, I need to create entities (specifically contracts) in a database table that are associated with a financial year. These contracts will be applied to projects. Any contract variation will be recorded by creating a new contract record for the same financial year but the original will remain associated with the project as a history. The projects can last several years and so at any one time a project will have a live contract record for each year as well as any number of historic contracts for that year. All of which is incidental but I'm trying to provide some context. If the contracts where for the year - it would be easy and I'd just store the Year either as a date field with the 1st of January or just an Integer. However the contracts run for financial years and I don't know how to approach this. I don't want a separate table containing the financial years as I don't want the users to have to maintain this. I don't want to store the financial year as a string "2009/2010" as this is not ideal for sorting/extracting the data. Any ideas will be helpful, my best so far is to have starting and ending year in 2 columns and just "KNOW" that starting is April of the year etc Thanks

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  • What is the proper way to URL encode Unicode characters?

    - by Josh Gibson
    I know of the non-standard %uxxxx scheme but that doesn't seem like a wise choice since the scheme has been rejected by the W3C. Some interesting examples: The heart character. If I type this into my browser: http://www.google.com/search?q=? Then copy and paste it, I see this URL http://www.google.com/search?q=%E2%99%A5 which makes it seem like Firefox (or Safari) is doing this. urllib.quote_plus(x.encode("latin-1")) '%E2%99%A5' which makes sense, except for things that can't be encoded in Latin-1, like the triple dot character. … If I type the URL http://www.google.com/search?q=… into my browser then copy and paste, I get http://www.google.com/search?q=%E2%80%A6 back. Which seems to be the result of doing urllib.quote_plus(x.encode("utf-8")) which makes sense since … can't be encoded with Latin-1. But then its not clear to me how the browser knows whether to decode with UTF-8 or Latin-1. Since this seems to be ambiguous: In [67]: u"…".encode('utf-8').decode('latin-1') Out[67]: u'\xc3\xa2\xc2\x80\xc2\xa6' works, so I don't know how the browser figures out whether to decode that with UTF-8 or Latin-1. What's the right thing to be doing with the special characters I need to deal with?

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  • Using TextOptions.TextFormattingMode with FormattedText

    - by dan gibson
    With WPF4 you can have non-blurry text by adding TextOptions.TextFormattingMode="Display" and TextOptions.TextRenderingMode="Aliased" to your xaml: <Window TextOptions.TextFormattingMode="Display" TextOptions.TextRenderingMode="Aliased"> This works fine for me except for when I draw text with DrawingContext.DrawText like this: void DrawText(DrawingContext dc) { FormattedText ft = new FormattedText("Hello World", System.Globalization.CultureInfo.CurrentCulture, System.Windows.FlowDirection.LeftToRight, new Typeface(FontFamily, FontStyle, FontWeight, FontStretch), FontSize, brush); dc.DrawText(ft, new Point(rect.Left, rect.Top)); } How can I draw non-blurry text with FormattedText? ie I want TextOptions.TextFormattingMode="Display" and TextOptions.TextRenderingMode="Aliased" to be used.

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  • How to close a JFrame in the middle of a program

    - by Nick Gibson
    public class JFrameWithPanel extends JFrame implements ActionListener, ItemListener { int packageIndex; double price; double[] prices = {49.99, 39.99, 34.99, 99.99}; DecimalFormat money = new DecimalFormat("$0.00"); JLabel priceLabel = new JLabel("Total Price: "+price); JButton button = new JButton("Check Price"); JComboBox packageChoice = new JComboBox(); JPanel pane = new JPanel(); TextField text = new TextField(5); JButton accept = new JButton("Accept"); JButton decline = new JButton("Decline"); JCheckBox serviceTerms = new JCheckBox("I Agree to the Terms of Service.", false); JTextArea termsOfService = new JTextArea("This is a text area", 5, 10); public JFrameWithPanel() { super("JFrame with Panel"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pane.add(packageChoice); setContentPane(pane); setSize(250,250); setVisible(true); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); pane.add(button); button.addActionListener(this); pane.add(text); text.setEditable(false); text.setBackground(Color.WHITE); text.addActionListener(this); pane.add(termsOfService); termsOfService.setEditable(false); termsOfService.setBackground(Color.lightGray); pane.add(serviceTerms); serviceTerms.addItemListener(this); pane.add(accept); accept.addActionListener(this); pane.add(decline); decline.addActionListener(this); } public void actionPerformed(ActionEvent e) { packageIndex = packageChoice.getSelectedIndex(); price = prices[packageIndex]; text.setText("$"+price); Object source = e.getSource(); if(source == accept) { if(serviceTerms.isSelected() == false) { JOptionPane.showMessageDialog(null,"Please accept the terms of service.", "Terms of Service", JOptionPane.ERROR_MESSAGE); } else { JOptionPane.showMessageDialog(null,"Thank you. We will now move on to registering your product."); pane.dispose(); } } else if(source == decline) { System.exit(0); } } public void itemStateChanged(ItemEvent e) { int select = e.getStateChange(); } public static void main(String[] args) { String value1; int constant = 1, invalidNum = 0, answerParse, packNum, packPrice; JOptionPane.showMessageDialog(null,"Hello!"+"\nWelcome to the CIT Test Program."); JOptionPane.showMessageDialog(null,"IT WORKS!"); } }//class How do I get this frame to close so that my JOptionPane Message Dialogs can continue in the program without me exiting the program completely. EDIT: I tried .dispose() but I get this: cannot find symbol symbol : method dispose() location: class javax.swing.JPanel pane.dispose(); ^

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  • string maniupulations, oops, how do I replace parts of a string

    - by Joe Gibson
    I am very new to python. Could someone explain how I can manipulate a string like this? This function receives three inputs: complete_fmla: has a string with digits and symbols but has no hyphens ('-') nor spaces. partial_fmla: has a combination of hyphens and possibly some digits or symbols, where the digits and symbols that are in it (other than hyphens) are in the same position as in the complete_formula. symbol: one character The output that should be returned is: If the symbol is not in the complete formula, or if the symbol is already in the partial formula, the function should return the same formula as the input partial_formula. If the symbol is in the complete_formula and not in the partial formula, the function should return the partial_formula with the symbol substituting the hyphens in the positions where the symbol is, in all the occurrences of symbol in the complete_formula. For example: generate_next_fmla (‘abcdeeaa’, ‘- - - - - - - - ’, ‘d’) should return ‘- - - d - - - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d - - - - ’, ‘e’) should return ‘- - - d e e - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d e e - - ’, ‘a’) should return ‘a - - d e e a a’ Basically, I'm working with the definition: def generate_next_fmla (complete_fmla, partial_fmla, symbol): Do I turn them into lists? and then append? Also, should I find out the index number for the symbol in the complete_fmla so that I know where to append it in the string with hyphens??

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  • assistance required, hangman game.

    - by Phillip Gibson
    I am making a hangman game and am having trouble with part of it. I have selected a random word from a file, but I want to display the word as a series of undersocres __ and then match the letter chosen to a position in the undersocres. Can anyone help me? cout <<"1. Select to play the game\n"; cout <<"2. Ask for help\n"; cout <<"3. Select to quit the game\n"; cout << "Enter a selection: "; int number; cin >> number; while(number < 1 || number > 3 || cin.fail()) { if(cin.fail()) { cin.sync(); cin.clear(); cout << "You have not entered a number, please enter a menu selection between 1 and 3\n"; cin >> number; } else { cout << "Your selection must be between 1 and 3!\n"; cin >> number; } } switch (number) { case 1: { string word; string name; cout << " Whats your name? "; cin >> name; Player player(); ifstream FileReader; FileReader.open("words.txt"); if(!FileReader.is_open()) cout << "Error"; //this is for the random selection of words srand(time(0)); int randnum = rand()%10+1; for(int counter = 0; counter < randnum; counter++) { getline(FileReader, word, '\n'); } cout << "my word: " << word << "\n"; // get length of word int length; //create for loop for(int i = 0; i < length; i++) cout << "_"; //_ _ _ _ _ SetCursorPos(2,10); FileReader.close(); break;

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  • How to check if something is stored in CoreData

    - by Terrel Gibson
    Hi I want to be able to tore some information in core data and but i am unsure of how to check if the file was saved properly. I tried using NSLog but it returns null when its called. I have a dictionary which has a uniqueID and a title which I want to save. I pass this in along with the context of the database. I then sort the database to check if it has any duplicates or not, if not then I add the file. +(VacationPhoto*) photoWithFlickrInfo: (NSDictionary*) flickrInfo inManagedObjectContext: (NSManagedObjectContext*) context{ //returns the dictionary NSLog(@"Photo To Store =%@", flickrInfo); VacationPhoto * photo = nil; NSFetchRequest *request = [NSFetchRequest fetchRequestWithEntityName:@"VacationPhoto"]; request.predicate = [NSPredicate predicateWithFormat:@"uniqueID = %@", [flickrInfo objectForKey:FLICKR_PHOTO_ID]]; NSSortDescriptor * descriptor = [NSSortDescriptor sortDescriptorWithKey:@"title" ascending:YES]; request.sortDescriptors = [NSArray arrayWithObject:descriptor]; NSError *error = nil; NSArray *matches = [context executeFetchRequest:request error:&error]; if (!matches || [matches count] > 1) { // handle error } else if ( [matches count] == 0){ photo.title = [flickrInfo objectForKey:FLICKR_PHOTO_TITLE]; //Returns NULL when called NSLog(@"title = %@", photo.title); photo.uniqueID = [flickrInfo objectForKey:FLICKR_PHOTO_ID]; //Returns NULL when called NSLog(@"ID = %@", photo.uniqueID); } else { //If photo already exists this is called photo = [matches lastObject]; } return photo; }

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  • How do I secure a .NET Web Service for use by an iPhone application?

    - by David A Gibson
    Hello, The title says it all, I have a Web Service written in .NET that provides data for an iPhone application. It will also allow the application make a "reservation." Currently it's all internal to the corporate network but obviously when the iPhone application is published I will need ensure the Web Service is available externally. How would I go about securing the Web Service? There are two aspects I'm looking into: Authentication for accessing the web service Protection for the data being transferred I'm no so bothered about the data being passed back and forth as it will be viewable in the application anyway (which will be free). The key issue for me is preventing users from accessing the Web Service and making reservations themselves. At the moment I am considering encrypting any strings in the XML data passed back and forth so only the client can effectively use the web service sidestepping the need for authentication and providing protection for the data. This is the only model I have seen but I think the overheads on the iPhone and even for the web service make for a poor user experience. Any solutions at all would be most welcome? Thanks

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  • Arrays not matching correctly

    - by Nick Gibson
    userAnswer[] holds the string of the answer the user types in and is comparing it to answers[] to see if they match up and then spits out correct or wrong. j is equal to the question number. So if j was question 6, answers[j] should refer to answers[6] right? Then userAnswer[6] should compare to answers[6] and match if its correct. But its giving me wrong answers and displaying the answer I typed as correct. int abc, loopCount = 100; int j = quesNum, overValue, forLoop = 100; for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; JOptionPane.showMessageDialog(null,abc); if(abc < x) { userAnswer[j] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]); if(userAnswer[j].equals(answers[j])) { JOptionPane.showMessageDialog(null,"Correct. \nThe Correct Answer is "+answers[abc]); } else { JOptionPane.showMessageDialog(null,"Wrong. \n The Correct Answer is "+answers[abc]); }//else }//if }//for

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  • ActionListener isn't Implementing

    - by Nick Gibson
    JFrameWithPanel is not abstract and does not override abstract method actionPerformed(java.awt.event.ActionEvent) in java.awt.event.ActionListener public class JFrameWithPanel extends JFrame implements ActionListener I Don't get this code. Book and Java site tells me this is the syntax for the method, but again this error shows up constantly. import javax.swing.*; import javax.swing.JOptionPane; import java.awt.*; import java.awt.event.*; import java.lang.Math.*; import java.lang.Integer.*; import java.util.*; import java.util.Random; import java.io.*; import java.text.*; import java.text.DecimalFormat.*; public class JFrameWithPanel extends JFrame implements ActionListener { JButton button = new JButton("Exit"); public JFrameWithPanel() { super("JFrame with Panel"); JComboBox packageChoice = new JComboBox(); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); packageChoice.addActionListener(this); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JPanel pane = new JPanel(); pane.add(button); pane.add(packageChoice); setContentPane(pane); setSize(200,100); setVisible(true); } } then later public class CreateJFrameWithPanel { public static void main(String[] args) { JFrameWithPanel panel = new JFrameWithPanel(); } }

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  • In the JSON spec, what does "Since the first two characters of a JSON text will always be ASCII characters" mean?

    - by dan gibson
    The spec is http://www.ietf.org/rfc/rfc4627.txt?number=4627 It contains this: Encoding JSON text SHALL be encoded in Unicode. The default encoding is UTF-8. Since the first two characters of a JSON text will always be ASCII characters [RFC0020], it is possible to determine whether an octet stream is UTF-8, UTF-16 (BE or LE), or UTF-32 (BE or LE) by looking at the pattern of nulls in the first four octets. What does it mean "Since the first two characters of a JSON text will always be ASCII characters [RFC0020]"? I've looked at RFC0020 but couldn't find anything about it. JSON could be {" or { " (ie whitespace before the quote.

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  • How do I automatically delete an Excel file after creating it on a server and returning it to the us

    - by David A Gibson
    Hello, I am creating an Excel file on a web server, using OleDb to connect the the physical (well as physical as it can be) file and appending records. I am then returning a FilePathResult to the user via MVC, and would like to delete the physical file afterwards due to data protection concerns over the appended records. I have tried using a File.Delete in a Finally clause but I get a File Not Found error which must mean the file has gone when MVC is trying to send the file to the user. I thought about creating the File as a MemoryStream but I think OleDb needs a physical file to connect to so this isn't an option. Any suggestions on how to delete the file after returning it in one operation? Thanks

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  • Arrays not counting correctly

    - by Nick Gibson
    I know I was just asking a question earlier facepalm This is in Java coding by the way. Well after everyones VERY VERY helpful advice (thank you guys alot) I managed to get over half of the program running how I wanted. Everything is pointing in the arrays where I want them to go. Now I just need to access the arrays so that It prints the correct information randomly. This is the current code that im using: http://pastebin.org/301483 The specific code giving me problems is this: long aa; int abc; for (int i = 0; i < x; i++) { aa = Math.round(Math.random()*10); String str = Long.toString(aa); abc = Integer.parseInt(str); String[] userAnswer = new String[x]; if(abc > x) { JOptionPane.showMessageDialog(null,"Number is too high. \nNumber Generator will reset."); break; } userAnswer[i] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]); answer = userAnswer[i].compareTo(answers[i]); if(answer == 0) { JOptionPane.showMessageDialog(null,"Correct. \nThe Correct Answer is "+answers[abc]+""+i); } else { JOptionPane.showMessageDialog(null,"Wrong. \n The Correct Answer is "+answers[abc]+""+i); }//else

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  • Unexpected return value

    - by Nicholas Gibson
    Program stopped compiling at this point: What is causing this error? (Error is at the bottom of post) public class JFrameWithPanel extends JFrame implements ActionListener, ItemListener { int packageIndex; double price; double[] prices = {49.99, 39.99, 34.99, 99.99}; DecimalFormat money = new DecimalFormat("$0.00"); JLabel priceLabel = new JLabel("Total Price: "+price); JButton button = new JButton("Check Price"); JComboBox packageChoice = new JComboBox(); JPanel pane = new JPanel(); TextField text = new TextField(5); JButton accept = new JButton("Accept"); JButton decline = new JButton("Decline"); JCheckBox serviceTerms = new JCheckBox("I Agree to the Terms of Service.", false); JTextArea termsOfService = new JTextArea("This is a text area", 5, 10); public JFrameWithPanel() { super("JFrame with Panel"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pane.add(packageChoice); setContentPane(pane); setSize(250,250); setVisible(true); packageChoice.addItem("A+ Certification"); packageChoice.addItem("Network+ Certification "); packageChoice.addItem("Security+ Certifictation"); packageChoice.addItem("CIT Full Test Package"); pane.add(button); button.addActionListener(this); pane.add(text); text.setEditable(false); text.setBackground(Color.WHITE); text.addActionListener(this); pane.add(termsOfService); termsOfService.setEditable(false); termsOfService.setBackground(Color.lightGray); pane.add(serviceTerms); serviceTerms.addItemListener(this); pane.add(accept); accept.addActionListener(this); pane.add(decline); decline.addActionListener(this); } public void actionPerformed(ActionEvent e) { packageIndex = packageChoice.getSelectedIndex(); price = prices[packageIndex]; text.setText("$"+price); Object source = e.getSource(); if(source == accept) { if(serviceTerms.isSelected() = false) // line 79 { JOptionPane.showMessageDialog(null,"Please accept the terms of service."); } else { JOptionPane.showMessageDialog(null,"Thanks."); } } } Error: \Desktop\Java Programming\JFrameWithPanel.java:79: unexpected type required: variable found : value if(serviceTerms.isSelected() = false) ^ 1 error

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  • Setting Frame.Content doesn't always work

    - by dan gibson
    I have a Frame control and I'm setting the Content property. If I set it twice, first to one control then to another, it shows the first control instead of the second. If I display a message box after setting it the first time then it works fine (ie it displays the second control). It's like I can only set Content once until the screen has been repainted. Calling Frame.UpdateLayout also doesn't help. What should I call after setting Content so that I can be sure that Content is actually set to what I specify?

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  • loop prematurely quitting

    - by Nick Gibson
    This loop works fine but prematurely quits at times. I set a piece of code in it so that I can view the random number. It only closes prematurely when the random number is equal to the highest numbered question the user inputs (Example...a user wants 10 questions, if the random number is 10 the program quits.) I have no idea why since i have it set to if(random number <= the number of questions) for ( int loop = 1; loop < loopCount; loop++ ) { aa = r.nextInt ( 10 + 1 ); abc = ( int ) aa; String[] userAnswer = new String[x]; JOptionPane.showMessageDialog ( null, abc ); if ( abc <= x ) { for ( overValue = 1; overValue < forLoop; overValue++ ); { userAnswer[j] = JOptionPane.showInputDialog ( null, "Question " + quesNum + "\n" + questions[abc] + "\n\nA: " + a[abc] + "\nB: " + b[abc] + "\nC: " + c[abc] + "\nD: " + d[abc] ); if ( userAnswer[j].equals ( answers[j] ) ) { JOptionPane.showMessageDialog ( null, "Correct. \nThe Correct Answer is " + answers[abc] ); } else { JOptionPane.showMessageDialog ( null, "Wrong. \n The Correct Answer is " + answers[abc] ); }//else }//for }//if }//for

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