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  • Algorithm for parsing a flat tree into a non-flat tree

    - by Chad Johnson
    I have the following flat tree: id name parent_id is_directory =========================================================== 50 app 0 1 31 controllers 50 1 11 application_controller.rb 31 0 46 models 50 1 12 test_controller.rb 31 0 31 test.rb 46 0 and I am trying to figure out an algorithm for getting this into the following tree structuree: [{ id: 50, name: app, is_directory: true children: [{ id: 31, name: controllers, is_directory: true, children: [{ id: 11, name: application_controller.rb is_directory: false },{ id: 12, name: test_controller.rb, is_directory: false }], },{ id: 46, name: models, is_directory: true, children: [{ id: 31, name: test.rb, is_directory: false }] }] }] Can someone point me in the right direction? I'm looking for steps (eg. build an associative array; loop through the array looking for x; etc.).

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  • Implementation of Race Game Tree

    - by Mert Toka
    I build a racing game right in OpenGL using Glut, and I'm a bit lost in all the details. First of all, any suggestions as a road map would be more than great. So far what I thought is this: Tree implementation for transformations. Simulated dynamics.(*) Octree implementation for collusion detection. Actual collusion detection.(*) Modelling in Maya and export them as .OBJs. Polishing the game with GLSL or something like that for graphics quality. (*): I am not sure the order of these two. So I started with the simulated dynamics without tree, and it turned out to be a huge chaos for me. Is there any way you can think of such that could help me to build such tree to use in racing game? I thought something like this but I have no idea how to implement it. Reds are static, yellows are dynamic nodes

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  • How are vector patterns used in syntax-rules?

    - by Jay
    Hi, I have been writing Common Lisp macros, so Scheme's R5Rs macros are a bit unnatural to me. I think I got the idea, except that I don't understand how one would use vector patterns in syntax-rules: (define-syntax mac (syntax-rules () ((mac #(a b c d)) (let () (display a) (newline) (display d) (newline))))) (expand '(mac #(1 2 3 4))) ;; Chicken's expand-full extension shows macroexpansion => (let746 () (display747 1) (newline748) (display747 4) (newline748)) I don't see how I'd use a macro that requires its arguments to be written as a vector: (mac #(1 2 3 4)) => 1 4 Is there some kind of technique that uses those patterns? Thank you!

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  • Programmatically disclosing a node in af:tree and af:treeTable

    - by Frank Nimphius
    A common developer requirement when working with af:tree or af:treeTable components is to programmatically disclose (expand) a specific node in the tree. If the node to disclose is not a top level node, like a location in a LocationsView -> DepartmentsView -> EmployeesView hierarchy, you need to also disclose the node's parent node hierarchy for application users to see the fully expanded tree node structure. Working on ADF Code Corner sample #101, I wrote the following code lines that show a generic option for disclosing a tree node starting from a handle to the node to disclose. The use case in ADF Coder Corner sample #101 is a drag and drop operation from a table component to a tree to relocate employees to a new department. The tree node that receives the drop is a department node contained in a location. In theory the location could be part of a country and so on to indicate the depth the tree may have. Based on this structure, the code below provides a generic solution to parse the current node parent nodes and its child nodes. The drop event provided a rowKey for the tree node that received the drop. Like in af:table, the tree row key is not of type oracle.jbo.domain.Key but an implementation of java.util.List that contains the row keys. The JUCtrlHierBinding class in the ADF Binding layer that represents the ADF tree binding at runtime provides a method named findNodeByKeyPath that allows you to get a handle to the JUCtrlHierNodeBinding instance that represents a tree node in the binding layer. CollectionModel model = (CollectionModel) your_af_tree_reference.getValue(); JUCtrlHierBinding treeBinding = (JUCtrlHierBinding ) model.getWrappedData(); JUCtrlHierNodeBinding treeDropNode = treeBinding.findNodeByKeyPath(dropRowKey); To disclose the tree node, you need to create a RowKeySet, which you do using the RowKeySetImpl class. Because the RowKeySet replaces any existing row key set in the tree, all other nodes are automatically closed. RowKeySetImpl rksImpl = new RowKeySetImpl(); //the first key to add is the node that received the drop //operation (departments).            rksImpl.add(dropRowKey);    Similar, from the tree binding, the root node can be obtained. The root node is the end of all parent node iteration and therefore important. JUCtrlHierNodeBinding rootNode = treeBinding.getRootNodeBinding(); The following code obtains a reference to the hierarchy of parent nodes until the root node is found. JUCtrlHierNodeBinding dropNodeParent = treeDropNode.getParent(); //walk up the tree to expand all parent nodes while(dropNodeParent != null && dropNodeParent != rootNode){    //add the node's keyPath (remember its a List) to the row key set    rksImpl.add(dropNodeParent.getKeyPath());      dropNodeParent = dropNodeParent.getParent(); } Next, you disclose the drop node immediate child nodes as otherwise all you see is the department node. Its not quite exactly "dinner for one", but the procedure is very similar to the one handling the parent node keys ArrayList<JUCtrlHierNodeBinding> childList = (ArrayList<JUCtrlHierNodeBinding>) treeDropNode.getChildren();                     for(JUCtrlHierNodeBinding nb : childList){   rksImpl.add(nb.getKeyPath()); } Next, the row key set is defined as the disclosed row keys on the tree so when you refresh (PPR) the tree, the new disclosed state shows tree.setDisclosedRowKeys(rksImpl); AdfFacesContext.getCurrentInstance().addPartialTarget(tree.getParent()); The refresh in my use case is on the tree parent component (a layout container), which usually shows the best effect for refreshing the tree component. 

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  • Find the minimum gap between two numbers in an AVL tree

    - by user1656647
    I have a data structures homework, that in addition to the regular AVL tree functions, I have to add a function that returns the minimum gap between any two numbers in the AVL tree (the nodes in the AVL actually represent numbers.) Lets say we have the numbers (as nodes) 1 5 12 20 23 21 in the AVL tree, the function should return the minimum gap between any two numbers. In this situation it should return "1" which is |20-21| or |21-20|. It should be done in O(1). Tried to think alot about it, and I know there is a trick but just couldn't find it, I have spent hours on this. There was another task which is to find the maximum gap, which is easy, it is the difference between the minimal and maximal number.

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  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Does syntax really matter in a programming language?

    - by Saif al Harthi
    One of my professors says "the Syntax is the UI of a programming language", languages like ruby have great readability & its growing but we see alot of programmers productive with C\C++, so as programmers does it really matter that the syntax should be acceptable? I would love to know your opinion on that. Disclaimer: I'm not trying to start an argument I thought this is a good topic of discussion. Update : this turns out to be a good topic i'm glad you are all participating it , there will be more good questions to come

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • AVL tree in C language

    - by I_S_W
    Hey all; i am currently doing a project that requires the use of AVL trees , the insert function i wrote for the avl does not seem to be working , it works for 3 or 4 nodes at maximum ; i would really appreciate your help The attempt is below enter code here Tree insert(Tree t,char name[80],int num) { if(t==NULL) { t=(Tree)malloc(sizeof(struct node)); if(t!=NULL) { strcpy(t->name,name); t->num=num; t->left=NULL; t->right=NULL; t->height=0; } } else if(strcmp(name,t->name)<0) { t->left=insert(t->left,name,num); if((height(t->left)-height(t->right))==2) if(strcmp(name,t->left->name)<0) { t=s_rotate_left(t);} else{ t=d_rotate_left(t);} } else if(strcmp(name,t-name)0) { t-right=insert(t-right,name,num); if((height(t-right)-height(t-left))==2) if(strcmp(name,t-right-name)0){ t=s_rotate_right(t); } else{ t=d_rotate_right(t);} } t-height=max(height(t-left),height(t-right))+1; return t; }

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  • Syntax of passing lambda

    - by Astara
    Right now, I'm working on refactoring a program that calls its parts by polling to a more event-driven structure. I've created sched and task classes with the sced to become a base class of the current main loop. The tasks will be created for each meter so they can be called off of that instead of polling. Each of the events main calls are a type of meter that gather info and display it. When the program is coming up, all enabled meters get 'constructed' by a main-sub. In that sub, I want to store off the "this" pointer associated with the meter, as well as the common name for the "action routine. void MeterMaker::Meter_n_Task (Meter * newmeter,) { push(newmeter); // handle non-timed draw events Task t = new Task(now() + 0.5L); t.period={0,1U}; t.work_meter = newmeter; t.work = [&newmeter](){newmeter.checkevent();};<<--attempt at lambda t.flags = T_Repeat; t.enable_task(); _xos->sched_insert(t); } A sample call to it: Meter_n_Task(new CPUMeter(_xos, "CPU ")); 've made the scheduler a base class of the main routine (that handles the loop), and I've tried serveral variations to get the task class to be a base of the meter class, but keep running into roadblocks. It's alot like "whack-a-mole" -- pound in something to fix something one place, and then a new probl pops out elsewhere. Part of the problem, is that the sched.h file that is trying to hold the Task Q, includes the Task header file. The task file Wants to refer to the most "base", Meter class. The meter class pulls in the main class of the parent as it passes a copy of the parent to the children so they can access the draw routines in the parent. Two references in the task file are for the 'this' pointer of the meter and the meter's update sub (to be called via this). void *this_data= NULL; void (*this_func)() = NULL; Note -- I didn't really want to store these in the class, as I wanted to use a lamdba in that meter&task routine above to store a routine+context to be used to call the meter's action routine. Couldn't figure out the syntax. But am running into other syntax problems trying to store the pointers...such as g++: COMPILE lsched.cc In file included from meter.h:13:0, from ltask.h:17, from lsched.h:13, from lsched.cc:13: xosview.h:30:47: error: expected class-name before ‘{’ token class XOSView : public XWin, public Scheduler { Like above where it asks for a class, where the classname "Scheduler" is. !?!? Huh? That IS a class name. I keep going in circles with things that don't make sense... Ideally I'd get the lamba to work right in the Meter_n_Task routine at the top. I wanted to only store 1 pointer in the 'Task' class that was a pointer to my lambda that would have already captured the "this" value ... but couldn't get that syntax to work at all when I tried to start it into a var in the 'Task' class. This project, FWIW, is my teething project on the new C++... (of course it's simple!.. ;-))... I've made quite a bit of progress in other areas in the code, but this lambda syntax has me stumped...its at times like thse that I appreciate the ease of this type of operation in perl. Sigh. Not sure the best way to ask for help here, as this isn't a simple question. But thought I'd try!... ;-) Too bad I can't attach files to this Q.

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  • Syntax of passing lambda causing hair loss (pulling out)

    - by Astara
    Right now, I'm working on refactoring a program that calls its parts by polling to a more event-driven structure. I've created sched and task classes with the sced to become a base class of the current main loop. The tasks will be created for each meter so they can be called off of that instead of polling. Each of the events main calls are a type of meter that gather info and display it. When the program is coming up, all enabled meters get 'constructed' by a main-sub. In that sub, I want to store off the "this" pointer associated with the meter, as well as the common name for the "action routine. void MeterMaker::Meter_n_Task (Meter * newmeter,) { push(newmeter); // handle non-timed draw events Task t = new Task(now() + 0.5L); t.period={0,1U}; t.work_meter = newmeter; t.work = [&newmeter](){newmeter.checkevent();};<<--attempt at lambda t.flags = T_Repeat; t.enable_task(); _xos->sched_insert(t); } A sample call to it: Meter_n_Task(new CPUMeter(_xos, "CPU ")); 've made the scheduler a base class of the main routine (that handles the loop), and I've tried serveral variations to get the task class to be a base of the meter class, but keep running into roadblocks. It's alot like "whack-a-mole" -- pound in something to fix something one place, and then a new probl pops out elsewhere. Part of the problem, is that the sched.h file that is trying to hold the Task Q, includes the Task header file. The task file Wants to refer to the most "base", Meter class. The meter class pulls in the main class of the parent as it passes a copy of the parent to the children so they can access the draw routines in the parent. Two references in the task file are for the 'this' pointer of the meter and the meter's update sub (to be called via this). void *this_data= NULL; void (*this_func)() = NULL; Note -- I didn't really want to store these in the class, as I wanted to use a lamdba in that meter&task routine above to store a routine+context to be used to call the meter's action routine. Couldn't figure out the syntax. But am running into other syntax problems trying to store the pointers...such as g++: COMPILE lsched.cc In file included from meter.h:13:0, from ltask.h:17, from lsched.h:13, from lsched.cc:13: xosview.h:30:47: error: expected class-name before ‘{’ token class XOSView : public XWin, public Scheduler { Like above where it asks for a class, where the classname "Scheduler" is. !?!? Huh? That IS a class name. I keep going in circles with things that don't make sense... Ideally I'd get the lamba to work right in the Meter_n_Task routine at the top. I wanted to only store 1 pointer in the 'Task' class that was a pointer to my lambda that would have already captured the "this" value ... but couldn't get that syntax to work at all when I tried to start it into a var in the 'Task' class. This project, FWIW, is my teething project on the new C++... (of course it's simple!.. ;-))... I've made quite a bit of progress in other areas in the code, but this lambda syntax has me stumped...its at times like thse that I appreciate the ease of this type of operation in perl. Sigh. Not sure the best way to ask for help here, as this isn't a simple question. But thought I'd try!... ;-) Too bad I can't attach files to this Q.

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  • New to AVL tree implementation.

    - by nn
    I am writing a sliding window compression algorithm (LZ77) that searches for phrases in a "moving" dictionary. So far I have written a BST where each node is stored in an array and it's index in the array is also the value of the starting position in the window itself. I am now looking at transforming the BST to an AVL tree. I am a little confused at the sample implementations I have seen. Some only appear to store the balance factors whereas others store the height of each tree. Are there any performance advantage/disadvantages of storing the height and/or balance factor for each node? Apologies if this is a very simple question, but I'm still not visualizing how I want to restructure my BST to implement height balancing. Thanks.

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  • Does syntax really matter in a programming language?

    - by Saif al Harthi
    One of my professors says "the syntax is the UI of a programming language", languages like Ruby have great readability and it's growing, but we see a lot of programmers productive with C\C++, so as programmers does it really matter that the syntax should be acceptable? I would love to know your opinion on that. Disclaimer: I'm not trying to start an argument. I thought this is a good topic of discussion. Update: This turns out to be a good topic. I'm glad you are all participating in it.

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  • Variable declaration versus assignment syntax

    - by rwallace
    Working on a statically typed language with type inference and streamlined syntax, and need to make final decision about syntax for variable declaration versus assignment. Specifically I'm trying to choose between: // Option 1. Create new local variable with :=, assign with = foo := 1 foo = 2 // Option 2. Create new local variable with =, assign with := foo = 1 foo := 2 Creating functions will use = regardless: // Indentation delimits blocks square x = x * x And assignment to compound objects will do likewise: sky.color = blue a[i] = 0 Which of options 1 or 2 would people find most convenient/least surprising/otherwise best?

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  • C syntax or binary optimized syntax?

    - by Dpp
    Let's take an simple example of two lines supposedly doing the same thing: if (value = 96 || value < 0) ... or if (value & ~ 95) ... Say 'If's are costly in a loop of thousands of iterations, is it better to keep with the traditional C syntax or better to find a binary optimized one if possible?

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  • Python invalid syntax with "with" statement

    - by mrlanrat
    Hello all, I am working on writing a simple python application for linux (maemo). However I am getting SyntaxError: invalid syntax on line 23: with open(file,'w') as fileh: The code can be seen here: http://pastebin.com/MPxfrsAp I can not figure out what is wrong with my code, I am new to python and the "with" statement. So, what is causing this code to error, and how can I fix it? Is it something wrong with the "with" statement? Thanks!

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  • Convert a binary tree to linked list, breadth first, constant storage/destructive

    - by Merlyn Morgan-Graham
    This is not homework, and I don't need to answer it, but now I have become obsessed :) The problem is: Design an algorithm to destructively flatten a binary tree to a linked list, breadth-first. Okay, easy enough. Just build a queue, and do what you have to. That was the warm-up. Now, implement it with constant storage (recursion, if you can figure out an answer using it, is logarithmic storage, not constant). I found a solution to this problem on the Internet about a year back, but now I've forgotten it, and I want to know :) The trick, as far as I remember, involved using the tree to implement the queue, taking advantage of the destructive nature of the algorithm. When you are linking the list, you are also pushing an item into the queue. Each time I try to solve this, I lose nodes (such as each time I link the next node/add to the queue), I require extra storage, or I can't figure out the convoluted method I need to get back to a node that has the pointer I need. Even the link to that original article/post would be useful to me :) Google is giving me no joy. Edit: Jérémie pointed out that there is a fairly simple (and well known answer) if you have a parent pointer. While I now think he is correct about the original solution containing a parent pointer, I really wanted to solve the problem without it :) The refined requirements use this definition for the node: struct tree_node { int value; tree_node* left; tree_node* right; };

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  • How to functionally generate a tree breadth-first. (With Haskell)

    - by Dennetik
    Say I have the following Haskell tree type, where "State" is a simple wrapper: data Tree a = Branch (State a) [Tree a] | Leaf (State a) deriving (Eq, Show) I also have a function "expand :: Tree a - Tree a" which takes a leaf node, and expands it into a branch, or takes a branch and returns it unaltered. This tree type represents an N-ary search-tree. Searching depth-first is a waste, as the search-space is obviously infinite, as I can easily keep on expanding the search-space with the use of expand on all the tree's leaf nodes, and the chances of accidentally missing the goal-state is huge... thus the only solution is a breadth-first search, implemented pretty decent over here, which will find the solution if it's there. What I want to generate, though, is the tree traversed up to finding the solution. This is a problem because I only know how to do this depth-first, which could be done by simply called the "expand" function again and again upon the first child node... until a goal-state is found. (This would really not generate anything other then a really uncomfortable list.) Could anyone give me any hints on how to do this (or an entire algorithm), or a verdict on whether or not it's possible with a decent complexity? (Or any sources on this, because I found rather few.)

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  • What do you think of this generator syntax?

    - by ChaosPandion
    I've been working on an ECMAScript dialect for quite some time now and have reached a point where I am comfortable adding new language features. I would love to hear some thoughts and suggestions on the syntax. Example generator { yield 1; yield 2; yield 3; if (true) { yield break; } yield continue generator { yield 4; yield 5; yield 6; }; } Syntax GeneratorExpression:     generator  {  GeneratorBody  } GeneratorBody:     GeneratorStatementsopt GeneratorStatements:     StatementListopt GeneratorStatement GeneratorStatementsopt GeneratorStatement:     YieldStatement     YieldBreakStatement     YieldContinueStatement YieldStatement:     yield  Expression  ; YieldBreakStatement:     yield  break  ; YieldContinueStatement:     yield  continue  Expression  ; Semantics The YieldBreakStatement allows you to end iteration early. This helps avoid deeply indented code. You'll be able to write something like this: generator { yield something1(); if (condition1 && condition2) yield break; yield something2(); if (condition3 && condition4) yield break; yield something3(); } instead of: generator { yield something1(); if (!condition1 && !condition2) { yield something2(); if (!condition3 && !condition4) { yield something3(); } } } The YieldContinueStatement allows you to combine generators: function generateNumbers(start) { return generator { yield 1 + start; yield 2 + start; yield 3 + start; if (start < 100) { yield continue generateNumbers(start + 1); } }; }

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  • What do you think of this iterator syntax?

    - by ChaosPandion
    I've been working on an ECMAScript dialect for quite some time now and have reached a point where I am comfortable adding new language features. I would love to hear some thoughts and suggestions on the syntax. Example iterator Numbers { yield 1; yield 2; yield 3; if (true) { yield break; } yield continue iterator { yield 4; yield 5; yield 6; }; } Syntax IteratorDeclaration:     iterator  Identifier  {  IteratorBody  } IteratorExpression:     iterator  Identifieropt  {  IteratorBody  } IteratorBody:     IteratorStatementsopt IteratorStatements:     IteratorStatement IteratorStatementsopt IteratorStatement:     Statement but not one of BreakStatement ContinueStatement ReturnStatement     YieldStatement     YieldBreakStatement     YieldContinueStatement YieldStatement:     yield  Expression  ; YieldBreakStatement:     yield  break  ; YieldContinueStatement:     yield  continue  Expression  ;

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  • Syntax logic suggestions

    - by Anna
    This syntax will be used inside HTML attributes. Here are a few examples of what I have so far: <input name="a" conditions="!b, c" /> <input name="b" /> <input name="c" /> This will make input "a" do something if b is not checked and c is checked (b and c are assumed to be checkboxes if they don't have a :value defined) <input name="a" conditions="!b:foo|bar, c:foo" /> <input name="b" /> <input name="c" /> This will make input "a" do something if bdoesn't have foo or bar values, and if c has the foo value. <input name="a" conditions="!b:EMPTY" /> <input name="b" /> Makes input "a" do something if b has a value assigned. So, essentially , acts as logical AND, : as equals (=), ! as NOT, and | as OR. The | (OR) is only needed between values (at least I think so), and AND is not needed between values for obvious reasons :) EMPTY means empty value, like <input value="" /> Do you have any suggestions on improving this syntax, like making it more human friendly? For example I think the "EMPTY" keyword is not really appropriate and should be replaced with a character, but I don't know which one to choose.

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  • Spanning-tree setup with incompatible switches

    - by wfaulk
    I have a set of eight HP ProCurve 2910al-48G Ethernet switches at my datacenter that are set up in a star topology with no physical loops. I want to partially mesh the switches for redundancy and manage the loops with a spanning-tree protocol. However, our connection to the datacenter is provided by two uplinks, each to a Cisco 3750. The datacenter's switches are handling the redundant connection using PVST spanning-tree, which is a Cisco-proprietary spanning-tree implementation that my HP switches do not support. It appears that my switches are not participating in the datacenter's spanning-tree domain, but are blindly passing the BPDUs between the two switchports on my side, which enables the datacenter's switches to recognize the loop and put one of the uplinks into the Blocking state. This is somewhat supposition, but I can confirm that, while my switches say that both of the uplink ports are forwarding, only one is passing any real quantity of data. (I am assuming that I cannot get the datacenter to move away from PVST. I don't know that I'd want them to make that significant of a change anyway.) The datacenter has also sent me this output from their switches (which I have expurgated of any identifiable info): 3750G-1#sh spanning-tree vlan nnn VLAN0nnn Spanning tree enabled protocol ieee Root ID Priority 10 Address 00d0.0114.xxxx Cost 4 Port 5 (GigabitEthernet1/0/5) Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Bridge ID Priority 32mmm (priority 32768 sys-id-ext nnn) Address 0018.73d3.yyyy Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Aging Time 300 sec Interface Role Sts Cost Prio.Nbr Type ------------------- ---- --- --------- -------- -------------------------------- Gi1/0/5 Root FWD 4 128.5 P2p Gi1/0/6 Altn BLK 4 128.6 P2p Gi1/0/8 Altn BLK 4 128.8 P2p and: 3750G-2#sh spanning-tree vlan nnn VLAN0nnn Spanning tree enabled protocol ieee Root ID Priority 10 Address 00d0.0114.xxxx Cost 4 Port 6 (GigabitEthernet1/0/6) Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Bridge ID Priority 32mmm (priority 32768 sys-id-ext nnn) Address 000f.f71e.zzzz Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Aging Time 300 sec Interface Role Sts Cost Prio.Nbr Type ------------------- ---- --- --------- -------- -------------------------------- Gi1/0/1 Desg FWD 4 128.1 P2p Gi1/0/5 Altn BLK 4 128.5 P2p Gi1/0/6 Root FWD 4 128.6 P2p Gi1/0/8 Desg FWD 4 128.8 P2p The uplinks to my switches are on Gi1/0/8 on both of their switches. The uplink ports are configured with a single tagged VLAN. I am also using a number of other tagged VLANs in my switch infrastructure. And, to be clear, I am passing the tagged VLAN I'm receiving from the datacenter to other ports on other switches in my infrastructure. My question is: how do I configure my switches so that I can use a spanning tree protocol inside my switch infrastructure without breaking the datacenter's spanning tree that I cannot participate in?

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