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  • Shell job control

    - by user1535672
    For my school project I am implementing a shell and I need help with job control. If we type a command, say cat &, then because of the & it should run in background, but it's not working. I have this code: { int pid; int status; pid = fork(); if (pid == 0) { fprintf(stderr, "Child Job pid = %d\n", getpid()); execvp(arg1, arg2); } pid=getpid(); fprintf(stderr, "Child Job pid is = %d\n", getpid()); waitpid(pid, &status, 0); }

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  • Creating a pseudoterminal to make sudo happy

    - by larsks
    I need to automate the provisioning of a cloud instance (running Fedora 17) for which the following initial facts are true: I have ssh-key based access to a remote user (cloud) That user has password-free root access via sudo. Manual configuration is as simple as logging in and running sudo su - and having at it, but I would like to fully automate this process. The trick is that the system defaults to having the requiretty option enabled for sudo, which means that an attempt to do something like this: ssh remotehost sudo yum -y install puppet Will fail: sudo: sorry, you must have a tty to run sudo I am working around this right now by first pushing over a small Python script that will run a command on a pseudoterminal: import os import sys import errno import subprocess pid, master_fd = os.forkpty() if pid == 0: # child process: now that we're attached to a # pty, run the given command. os.execvp(sys.argv[1], sys.argv[1:]) else: while True: try: data = os.read(master_fd, 1024) except OSError, detail: if detail.errno == errno.EIO: break if not data: break sys.stdout.write(data) os.wait() Assuming that this is named pty, I can then run: ssh remotehost ./pty sudo yum -y install puppet This works fine, but I'm wondering if there are solutions already available that I haven't considered. I would normally think about expect, but it's not installed by default on this system. screen can do this in a pinch, but the best I came up with was: screen -dmS sudo somecommand ...which does work but eats the output. Are there any other tools available that will allocate a pseudoterminal for me that are going to be generally available?

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  • not able to use g++ from Fedora

    - by eSKay
    $ yum list | grep gcc arm-gp2x-linux-gcc.i686 4.1.2-11.fc12 @fedora arm-gp2x-linux-gcc-c++.i686 4.1.2-11.fc12 @fedora gcc.i686 4.4.3-4.fc12 @updates libgcc.i686 4.4.3-4.fc12 @updates avr-gcc.i686 4.4.2-2.fc12 updates avr-gcc-c++.i686 4.4.2-2.fc12 updates compat-gcc-34.i686 3.4.6-18 fedora compat-gcc-34-c++.i686 3.4.6-18 fedora compat-gcc-34-g77.i686 3.4.6-18 fedora compat-libgcc-296.i686 2.96-143 fedora gcc-c++.i686 4.4.3-4.fc12 updates gcc-gfortran.i686 4.4.3-4.fc12 updates gcc-gnat.i686 4.4.3-4.fc12 updates gcc-java.i686 4.4.3-4.fc12 updates gcc-objc.i686 4.4.3-4.fc12 updates gcc-objc++.i686 4.4.3-4.fc12 updates mingw32-gcc.i686 4.4.1-3.fc12 fedora mingw32-gcc-c++.i686 4.4.1-3.fc12 fedora mingw32-gcc-gfortran.i686 4.4.1-3.fc12 fedora mingw32-gcc-objc.i686 4.4.1-3.fc12 fedora mingw32-gcc-objc++.i686 4.4.1-3.fc12 fedora msp430-gcc.i686 3.2.3-3.20090210cvs.fc12 $ gcc works fine on .c files but fails on .cpp files saying: $ gcc: error trying to exec 'cc1plus': execvp: No such file or directory g++ fails saying: $ g++: Command not found. What should I do to be able to compile C++ files?

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  • how to implement word count bash shell

    - by codemax
    hey guys. I am trying to write my own code for the word count in bash shell. I did usual way. But i wanna use pipe's output to count the word. So for eg the 1st command is cat and i am redirecting to a file called med. Now i have to use to 'dup2' function to count the words in that file. How can i write the code for my wc? This is the code for my shell pgm : void process( char* cmd[], int arg_count ) { pid_t pid; pid = fork(); char path[81]; getcwd(path,81); strcat(path,"/"); strcat(path,cmd[0]); if(pid < 0) { cout << "Fork Failed" << endl; exit(-1); } else if( pid == 0 ) { int fd; fd =open("med", O_RDONLY); dup2(fd ,0); execvp( path, cmd ); } else { wait(NULL); } } And my wordcount is : int main(int argc, char *argv[]) { char ch; int count = 0; ifstream infile(argv[1]); while(!infile.eof()) { infile.get(ch); if(ch == ' ') { count++; } } return 0; } I dont know how to do input redirection i want my code to do this : When i just type wordcount in my shell implementation, I want it to count the words in the med file by default. Thanks in advance

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  • what does this attempted trojan horse code do?

    - by bstullkid
    It looks like this just sends a ping, but whats the point of that when you can just use ping? /* WARNING: this is someone's attempt at writing a malware trojan. Do not compile and *definitely* don't install. I added an exit as the first line to avoid mishaps - msw */ int main (int argc, char *argv[]) { exit(1); unsigned int pid = 0; char buffer[2]; char *args[] = { "/bin/ping", "-c", "5", NULL, NULL }; if (argc != 2) return 0; args[3] = strdup(argv[1]); for (;;) { gets(buffer); /* FTW */ if (buffer[0] == 0x6e) break; switch (pid = fork()) { case -1: printf("Error Forking\n"); exit(255); case 0: execvp(args[0], args); exit(1); default: break; } } return 255; }

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  • problem with fork()

    - by john
    I'm writing a shell which forks, with the parent reading the input and the child process parsing and executing it with execvp. pseudocode of main method: do{ pid = fork(); print pid; if (p<0) { error; exit; } if (p>0) { wait for child to finish; read input; } else { call function to parse input; exit; } }while condition return; what happens is that i never seem to enter the child process (pid printed is always positive, i never enter the else). however, if i don't call the parse function and just have else exit, i do correctly enter parent and child alternatingly. full code: int main(int argc, char *argv[]){ char input[500]; pid_t p; int firstrun = 1; do{ p = fork(); printf("PID: %d", p); if (p < 0) {printf("Error forking"); exit(-1);} if (p > 0){ wait(NULL); firstrun = 0; printf("\n> "); bzero(input, 500); fflush(stdout); read(0, input, 499); input[strlen(input)-1] = '\0'; } else exit(0); else { if (parse(input) != 0 && firstrun != 1) { printf("Error parsing"); exit(-1); } exit(0); } }while(strcmp(input, "exit") != 0); return 0; }

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  • what is the relation between SIGTSTP and SIGCHLD

    - by Rawhi
    I have tow handlers for each one of them (SIGTSTP, SIGCHLD), the thing is that when I pause a process using SIGTSTP the handler function of SIGCHLD run too. what should I do to prevent this . void ExeExternal(char *args[MAX_ARG], char* cmdString, LIST_ELEMENT** pList, int *Susp_Bg_Pid, int *susp) { int pID, status, w; switch (pID = fork()) { case -1: perror("smash error: >"); break; case 0: // Child Process setpgrp(); execv(args[0], args); execvp(args[0], args); perror("error"); exit(EXIT_FAILURE); break; default: if (cmdString[strlen(cmdString) - 1] != '&') { *Susp_Bg_Pid = pID; *susp = 1; while(*susp); } else { InsertElem(pList, args[0], getpid(), pID, 0); } break; } } signal handlers : void signalHandler(int signal) { int pid, cstatus; if (signal == SIGCHLD) { susp = 0; pid = waitpid(-1, &cstatus, WNOHANG); printf("[[child %d terminated]]\n", pid); DelPID(&JobsList, pid); } } void ctrlZsignal(int signal){ kill(Susp_Bg_Pid, SIGTSTP); susp = 0; printf("\nchild %d suspended\n", Susp_Bg_Pid); } Susp_Bg_Pid used to save the paused process id. susp indicates the state of the "smash" the parent process if it is suspended or not .

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  • C Map String to Function

    - by Scriptonaut
    So, I'm making a Unix minishell, and have come to a roadblock. I need to be able to execute built-in functions, so I made a function: int exec_if_built_in(char **args) It takes an array of strings(the first being the command, and the rest being arguments). For non built-in commands I simply use something like execvp, however I need to find a way to map the first string to a function. I was thinking of making two arrays, one of strings, and another with their corresponding function pointers. However, since many of these functions will be different(return and accept different things), this approach won't work. I also thought of making an array of structs with a name property and a function pointer property, however once again due to the varied nature of the functions I'll be using, this won't work. So, what's the best way to execute a function based on the input of a string? How do I map a string to a certain function? I'm not very familiar with function pointers so I may be missing something. Thank you guys for the help :)

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  • passing pipe to threads

    - by alaamh
    I see it's easy to open pipe between two process using fork, but how we can passing open pipe to threads. Assume we need to pass out of PROGRAM A to PROGRAM B "may by more than one thread", PROGRAM B send his output to PROGRAM C #include <stdio.h> #include <stdlib.h> #include <pthread.h> struct targ_s { int fd_reader; }; void *thread1(void *arg) { struct targ_s *targ = (struct targ_s*) arg; int status, fd[2]; pid_t pid; pipe(fd); pid = fork(); if (pid == 0) { dup2(STDIN_FILENO, targ->fd_reader); close(fd[0]); dup2(fd[1], STDOUT_FILENO); close(fd[1]); execvp ("PROGRAM B", NULL); exit(1); } else { close(fd[1]); dup2(fd[0], STDIN_FILENO); close(fd[0]); execl("PROGRAM C", NULL); wait(&status); return NULL; } } int main(void) { FILE *fpipe; char *command = "PROGRAM A"; char buffer[1024]; if (!(fpipe = (FILE*) popen(command, "r"))) { perror("Problems with pipe"); exit(1); } char* outfile = "out.dat"; FILE* f = fopen (outfile, "wb"); int fd = fileno( f ); struct targ_s targ; targ.fd_reader = fd; pthread_t thid; if (pthread_create(&thid, NULL, thread1, &targ) != 0) { perror("pthread_create() error"); exit(1); } int len; while (read(fpipe, buffer, sizeof (buffer)) != 0) { len = strlen(buffer); write(fd, buffer, len); } pclose(fpipe); return (0); }

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  • Problems with making a simple UNIX shell

    - by Kodemax
    Hai, I am trying to create a simple shell in UNIX. I read a lot and found that everybody uses the strtok a lot. But i want to do without any special functions. So i wrote the code but i cant seem to get it to work. Can anybody point out what i am doing wrong here? void process(char**); int arg_count; char **splitcommand(char* input) { char temp[81][81] ,*cmdptr[40]; int k,done=0,no=0,arg_count=0; for(int i=0 ; input[i] != '\0' ; i++) { k=0; while(1) { if(input[i] == ' ') { arg_count++; break; } if(input[i] == '\0') { arg_count++; done = 1; break; } temp[arg_count][k++] = input[i++]; } temp[arg_count][k++] = '\0'; if(done == 1) { break; } } for(int i=0 ; i<arg_count ; i++) { cmdptr[i] = temp[i]; cout<<endl; } cout<<endl; } void process(char* cmd[]) { int pid = fork(); if(pid < 0) { cout << "Fork Failed" << endl; exit(-1); } else if( pid == 0) { cout<<endl<<"in pid"; execvp(cmd[0], cmd); } else { wait(NULL); cout << "Job's Done" << endl; } } int main() { cout<<"Welcome to shell !!!!!!!!!!!"<<endl; char input[81]; cin.getline(input,81); splitcommand(input); }

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  • Redirecting one file to another using dub2 and strtok

    - by Sergiy Zakharov
    OK, here goes. I have to write a program, in which I need to use strtok and dup2 to redirect one file to another, but I need to also have the user to actually put the command cat < file1 file2, but not from the shell, but instead by using my program. That's why I need strtok. And the reason my program doesn't work is probably because of that, because I don't really understand how strtok works. I found a similar program on the internet, but they just take the ls command and redirect it to the file. That's it. My program is much more complicated. I mean, it would've been easier just to say in shell cat < file1 file2, but for some reason they want us to do it this way. So, anyways, here is what I have so far (here I just combined what I have found on the internet with what I already had from before. We had to do something similar but then the user would just go ls or ls -l. Very simple stuff. This is much harder, for me, at least.) #include <fcntl.h> #include <unistd.h> #include <stdio.h> #include <errno.h> #include <sys/wait.h> #include <string.h> int main() { pid_t pid; char line[256]; char *args[129]; int i; int fd; int status; char *temp; while (1) { printf(">"); if (fgets(line, 256, stdin) == 0) { exit(0); } else { pid = fork(); if (pid == 0) { i = 0; temp = strtok("<",line); while (temp != NULL) { args[i++] = temp; temp = strtok(">",line); args[i] = '\0'; } fd = open("hello", O_RDONLY); dup2(fd, STDIN_FILENO); fd = open("world", O_WRONLY|O_CREAT|O_TRUNC, S_IRWXU); dup2(fd, STDOUT_FILENO ); close(fd); execvp(args[0], args); } else { close(fd); wait(&status); } } } } Any help would be greatly appreciated.

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  • Thread feeding other MultiThreading

    - by alaamh
    I see it's easy to open pipe between two process using fork, but how we can passing open pipe to threads. Assume we need to pass out of PROGRAM A to PROGRAM B "may by more than one thread", PROGRAM B send his output to PROGRAM C #include <stdio.h> #include <stdlib.h> #include <pthread.h> struct targ_s { char* reader; }; void *thread1(void *arg) { struct targ_s *targ = (struct targ_s*) arg; int status, fd[2]; pid_t pid; pipe(fd); pid = fork(); if (pid == 0) { int fd = fileno( targ->fd_reader ); dup2(STDIN_FILENO, fd); close(fd[0]); dup2(fd[1], STDOUT_FILENO); close(fd[1]); execvp ("PROGRAM B", NULL); exit(1); } else { close(fd[1]); dup2(fd[0], STDIN_FILENO); close(fd[0]); execl("PROGRAM C", NULL); wait(&status); return NULL; } } int main(void) { FILE *fpipe; char *command = "PROGRAM A"; char buffer[1024]; if (!(fpipe = (FILE*) popen(command, "r"))) { perror("Problems with pipe"); exit(1); } char* outfile = "out.dat"; FILE* f = fopen (outfile, "wb"); int fd = fileno( f ); struct targ_s targ; targ.fd_reader = outfile; pthread_t thid; if (pthread_create(&thid, NULL, thread1, &targ) != 0) { perror("pthread_create() error"); exit(1); } int len; while (read(fpipe, buffer, sizeof (buffer)) != 0) { len = strlen(buffer); write(fd, buffer, len); } pclose(fpipe); return (0); }

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  • can't read from stream until child exits?

    - by BobTurbo
    OK I have a program that creates two pipes - forks - the child's stdin and stdout are redirected to one end of each pipe - the parent is connected to the other ends of the pipes and tries to read the stream associated with the child's output and print it to the screen (and I will also make it write to the input of the child eventually). The problem is, when the parent tries to fgets the child's output stream, it just stalls and waits until the child dies to fgets and then print the output. If the child doesn't exit, it just waits forever. What is going on? I thought that maybe fgets would block until SOMETHING was in the stream, but not block all the way until the child gives up its file descriptors. Here is the code: #include <stdlib.h> #include <stdio.h> #include <string.h> #include <sys/types.h> #include <unistd.h> int main(int argc, char *argv[]) { FILE* fpin; FILE* fpout; int input_fd[2]; int output_fd[2]; pid_t pid; int status; char input[100]; char output[100]; char *args[] = {"/somepath/someprogram", NULL}; fgets(input, 100, stdin); // the user inputs the program name to exec pipe(input_fd); pipe(output_fd); pid = fork(); if (pid == 0) { close(input_fd[1]); close(output_fd[0]); dup2(input_fd[0], 0); dup2(output_fd[1], 1); input[strlen(input)-1] = '\0'; execvp(input, args); } else { close(input_fd[0]); close(output_fd[1]); fpin = fdopen(input_fd[1], "w"); fpout = fdopen(output_fd[0], "r"); while(!feof(fpout)) { fgets(output, 100, fpout); printf("output: %s\n", output); } } return 0; }

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  • PASS: The Budget Process

    - by Bill Graziano
    Every fiscal year PASS creates a detailed budget.  This helps us set priorities and communicate to our members what we’re going to do in the upcoming year.  You can review the current budget on the PASS Governance page.  That page currently requires you to login but I’m talking with HQ to see if there are any legal issues with opening that up. The Accounting Team The PASS accounting team is two people.  The Executive Vice-President of Finance (“EVP”) and the PASS Accounting Manager.  Sandy Cherry is the accounting manager and works at PASS HQ.  Sandy has been with PASS since we switched management companies in 2007.  Throughout this document when I talk about any actual work related to the budget that’s all Sandy :)  She’s the glue that gets us through this process.  Last year we went through 32 iterations of the budget before the Board approved so it’s a pretty busy time for her us – well, mostly her. Fiscal Year The PASS fiscal year runs from July 1st through June 30th the following year.  Right now we’re in fiscal year 2011.  Our 2010 Summit actually occurred in FY2011.  We switched to this schedule from a calendar year in 2006.  Our goal was to have the Summit occur early in our fiscal year.  That gives us the rest of the year to handle any significant financial impact from the Summit.  If registrations are down we can reduce spending.  If registrations are up we can decide how much to increase our reserves and how much to spend.  Keep in mind that the Summit is budgeted to generate 82% of our revenue this year.  How it performs has a significant impact on our financials.  The other benefit of this fiscal year is that it matches the Microsoft fiscal year.  We sign an annual sponsorship agreement with Microsoft and it’s very helpful that our fiscal years match. This year our budget process will probably start in earnest in March or April.  I’d like to be done in early June so we can publish before July 1st.  I was late publishing it this year and I’m trying not to repeat that. Our Budget Our actual budget is an Excel spreadsheet with 36 sheets.  We remove some of those when we publish it since they include salary information.  The budget is broken up into various portfolios or departments.  We have 20 portfolios.  They include chapters, marketing, virtual chapters, marketing, etc.  Ideally each portfolio is assigned to a Board member.  Each portfolio also typically has a staff person assigned to it.  Portfolios that aren’t assigned to a Board member are monitored by HQ and the ExecVP-Finance (me).  These are typically smaller portfolios such as deferred membership or Summit futures.  (More on those in a later post.)  All portfolios are reviewed by all Board members during the budget approval process, when interim financials are released internally and at year-end. The Process Our first step is to budget revenues.  The Board determines a target attendee number.  We have formulas based on historical performance that convert that to an overall attendee revenue number.  Other revenue projections (such as vendor sponsorships) come from different parts of the organization.  I hope to have another post with more details on how we project revenues. The next step is to budget expenses.  Board members fill out a sample spreadsheet with their budget for the year.  They can add line items and notes describing what the amounts are for.  Each Board portfolio typically has from 10 to 30 line items.  Any new initiatives they want to pursue needs to be budgeted.  The Summit operations budget is managed by HQ.  It includes the cost for food, electrical, internet, etc.  Most of these come from our estimate of attendees and our contract with the convention center.  During this process the Board can ask for more or less to be spent on various line items.  For example, if we weren’t happy with the Internet at the last Summit we can ask them to look into different options and/or increasing the budget.  HQ will also make adjustments to these numbers based on what they see at the events and the feedback we receive on the surveys. After we have all the initial estimates we start reviewing the entire budget.  It is sent out to the Board and we can see what each portfolio requested and what the overall profit and loss number is.  We usually start with too much in expenses and need to cut.  In years past the Board started haggling over these numbers as a group.  This past year they decided I should take a first cut and present them with a reasonable budget and a list of what I changed.  That worked well and I think we’ll continue to do that in the future. We go through a number of iterations on the budget.  If I remember correctly, we went through 32 iterations before we passed the budget.  At each iteration various revenue and expense numbers can change.  Keep in mind that the PASS budget has 200+ line items spread over 20 portfolios.  Many of these depend on other numbers.  For example, if we decide increase the projected attendees that cascades through our budget.  At each iteration we list what changed and the impact.  Ideally these discussions will take place at a face-to-face Board meeting.  Many of them also take place over the phone.  Board members explain any increase they are asking for while performing due diligence on other budget requests.  Eventually a budget emerges and is passed. Publishing After the budget is passed we create a version without the formulas and salaries for posting on the web site.  Sandy also creates some charts to help our members understand the budget.  The EVP writes a nice little letter describing some of the changes from last year’s budget.  You can see my letter and our budget on the PASS Governance page. And then, eight months later, we start all over again.

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  • Help with simple linux shell implementation

    - by nunos
    I am implementing a simple version of a linux shell in c. I have succesfully written the parser, but I am having some trouble forking out the child process. However, I think the problem is due to arrays, pointers and such, because just started C with this project and am not still very knowledgable with them. I am getting a segmentation fault and don't know where from. Any help is greatly appreciated. #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <string.h> #include <sys/wait.h> #include <sys/types.h> #define MAX_COMMAND_LENGTH 250 #define MAX_ARG_LENGTH 250 typedef enum {false, true} bool; typedef struct { char **arg; char *infile; char *outfile; int background; } Command_Info; int parse_cmd(char *cmd_line, Command_Info *cmd_info) { char *arg; char *args[MAX_ARG_LENGTH]; int i = 0; arg = strtok(cmd_line, " "); while (arg != NULL) { args[i] = arg; arg = strtok(NULL, " "); i++; } int num_elems = i; if (num_elems == 0) return -1; cmd_info->infile = NULL; cmd_info->outfile = NULL; cmd_info->background = 0; int iarg = 0; for (i = 0; i < num_elems-1; i++) { if (!strcmp(args[i], "<")) { if (args[i+1] != NULL) cmd_info->infile = args[++i]; else return -1; } else if (!strcmp(args[i], ">")) { if (args[i+1] != NULL) cmd_info->outfile = args[++i]; else return -1; } else cmd_info->arg[iarg++] = args[i]; } if (!strcmp(args[i], "&")) cmd_info->background = true; else cmd_info->arg[iarg++] = args[i]; cmd_info->arg[iarg] = NULL; return 0; } void print_cmd(Command_Info *cmd_info) { int i; for (i = 0; cmd_info->arg[i] != NULL; i++) printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("infile=\"%s\"\n", cmd_info->infile); printf("outfile=\"%s\"\n", cmd_info->outfile); printf("background=\"%d\"\n", cmd_info->background); } void get_cmd(char* str) { fgets(str, MAX_COMMAND_LENGTH, stdin); str[strlen(str)-1] = '\0'; //apaga o '\n' do fim } pid_t exec_simple(Command_Info *cmd_info) { pid_t pid = fork(); if (pid < 0) { perror("Fork Error"); return -1; } if (pid == 0) { execvp(cmd_info->arg[0], cmd_info->arg); perror(cmd_info->arg[0]); exit(1); } return pid; } int main(int argc, char* argv[]) { while (true) { char cmd_line[MAX_COMMAND_LENGTH]; Command_Info cmd_info; printf(">>> "); get_cmd(cmd_line); if ( (parse_cmd(cmd_line, &cmd_info) == -1) ) return -1; parse_cmd(cmd_line, &cmd_info); if (!strcmp(cmd_info.arg[0], "exit")) exit(0); pid_t pid = exec_simple(&cmd_info); waitpid(pid, NULL, 0); } return 0; } Thanks.

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  • how to add a function to that program, and call that function from the command line in the function

    - by user336291
    a#include "smallsh.h" /*include file for example*/ /*program buffers and work pointers*/ static char inpbuf[MAXBUF], tokbuf[2*MAXBUF], *ptr = inpbuf, *tok = tokbuf; userin(p) /*print prompt and read a line*/ char *p; { int c, count; /*initialization for later routines*/ ptr = inpbuf; tok = tokbuf; /*display prompt*/ printf("%s ",p); for(count = 0;;) { if((c = getchar()) == EOF) return(EOF); if(count<MAXBUF) inpbuf[count++] = c; if(c == '\n' && count <MAXBUF) { inpbuf[count] = '\0'; return(count); } /*if line too long restart*/ if(c == '\n') { printf("smallsh:input line too long\n"); count = 0; printf("%s",p); } } } gettok(outptr) /*get token and place into tokbuf*/ char **outptr; { int type; *outptr = tok; /*strip white space*/ for(;*ptr == ' ' || *ptr == '\t'; ptr++) ; *tok++ = *ptr; switch(*ptr++) { case '\n': type = EOL; break; case '&': type = AMPERSAND; break; case ';': type = SEMICOLON; break; case '#': type = POUND; break; default: type = ARG; while(inarg(*ptr)) *tok++ = *ptr++; } *tok++ = '\0'; return(type); } static char special[]= {' ', '\t', '&', ':', '\n', '\0'}; inarg(c) /*are we in an ordinary argument*/ char c; { char *wrk; for(wrk = special;*wrk != '\0';wrk++) if(c == *wrk) return(0); return(1); } #include "smallsh.h" procline() /*process input line*/ { char *arg[MAXARG+1]; /*pointer array for runcommand*/ int toktype; /*type of token in command*/ int narg; /*number of arguments so far*/ int type; /*FOREGROUND or BACKGROUND*/ for(narg = 0;;) { /*loop FOREVER*/ /*take action according to token type*/ switch(toktype = gettok(&arg[narg])) { case ARG: if(narg<MAXARG) narg++; break; case EOL: case SEMICOLON: case AMPERSAND: case POUND: type = (toktype == AMPERSAND) ? BACKGROUND : FOREGROUND; if(narg!=0) { arg[narg] = NULL; runcommand(arg, type); } if((toktype == EOL)||(toktype=POUND)) return; narg = 0; break; } } } #include "smallsh.h" /*execute a command with optional wait*/ runcommand(cline,where) char **cline; int where; { int pid, exitstat, ret; if((pid = fork()) <0) { perror("smallsh"); return(-1); } if(pid == 0) { /*child*/ execvp(*cline, cline); perror(*cline); exit(127); } /*code for parent*/ /*if background process print pid and exit*/ if(where == BACKGROUND) { printf("[Process id %d]\n", pid); return(0); } /*wait until process pid exists*/ while( (ret=wait(&exitstat)) != pid && ret != -1) ; return(ret == -1 ? -1 : exitstat); } #include "smallsh.h" char *prompt = "Command>"; /*prompt*/ main() { while(userin(prompt) != EOF) procline(); }

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  • Help with malloc and free: Glibc detected: free(): invalid pointer

    - by nunos
    I need help with debugging this piece of code. I know the problem is in malloc and free but can't find exactly where, why and how to fix it. Please don't answer: "Use gdb" and that's it. I would use gdb to debug it, but I still don't know much about it and am still learning it, and would like to have, in the meanwhile, another solution. Thanks. #include <stdio.h> #include <stdlib.h> #include <ctype.h> #include <unistd.h> #include <string.h> #include <sys/wait.h> #include <sys/types.h> #define MAX_COMMAND_LENGTH 256 #define MAX_ARGS_NUMBER 128 #define MAX_HISTORY_NUMBER 100 #define PROMPT ">>> " int num_elems; typedef enum {false, true} bool; typedef struct { char **arg; char *infile; char *outfile; int background; } Command_Info; int parse_cmd(char *cmd_line, Command_Info *cmd_info) { char *arg; char *args[MAX_ARGS_NUMBER]; int i = 0; arg = strtok(cmd_line, " "); while (arg != NULL) { args[i] = arg; arg = strtok(NULL, " "); i++; } num_elems = i;precisa em free_mem if (num_elems == 0) return 0; cmd_info->arg = (char **) ( malloc(num_elems * sizeof(char *)) ); cmd_info->infile = NULL; cmd_info->outfile = NULL; cmd_info->background = 0; bool b_infile = false; bool b_outfile = false; int iarg = 0; for (i = 0; i < num_elems; i++) { if ( !strcmp(args[i], "<") ) { if ( b_infile || i == num_elems-1 || !strcmp(args[i+1], "<") || !strcmp(args[i+1], ">") || !strcmp(args[i+1], "&") ) return -1; i++; cmd_info->infile = malloc(strlen(args[i]) * sizeof(char)); strcpy(cmd_info->infile, args[i]); b_infile = true; } else if (!strcmp(args[i], ">")) { if ( b_outfile || i == num_elems-1 || !strcmp(args[i+1], ">") || !strcmp(args[i+1], "<") || !strcmp(args[i+1], "&") ) return -1; i++; cmd_info->outfile = malloc(strlen(args[i]) * sizeof(char)); strcpy(cmd_info->outfile, args[i]); b_outfile = true; } else if (!strcmp(args[i], "&")) { if ( i == 0 || i != num_elems-1 || cmd_info->background ) return -1; cmd_info->background = true; } else { cmd_info->arg[iarg] = malloc(strlen(args[i]) * sizeof(char)); strcpy(cmd_info->arg[iarg], args[i]); iarg++; } } cmd_info->arg[iarg] = NULL; return 0; } void print_cmd(Command_Info *cmd_info) { int i; for (i = 0; cmd_info->arg[i] != NULL; i++) printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("infile=\"%s\"\n", cmd_info->infile); printf("outfile=\"%s\"\n", cmd_info->outfile); printf("background=\"%d\"\n", cmd_info->background); } void get_cmd(char* str) { fgets(str, MAX_COMMAND_LENGTH, stdin); str[strlen(str)-1] = '\0'; } pid_t exec_simple(Command_Info *cmd_info) { pid_t pid = fork(); if (pid < 0) { perror("Fork Error"); return -1; } if (pid == 0) { if ( (execvp(cmd_info->arg[0], cmd_info->arg)) == -1) { perror(cmd_info->arg[0]); exit(1); } } return pid; } void type_prompt(void) { printf("%s", PROMPT); } void syntax_error(void) { printf("msh syntax error\n"); } void free_mem(Command_Info *cmd_info) { int i; for (i = 0; cmd_info->arg[i] != NULL; i++) free(cmd_info->arg[i]); free(cmd_info->arg); free(cmd_info->infile); free(cmd_info->outfile); } int main(int argc, char* argv[]) { char cmd_line[MAX_COMMAND_LENGTH]; Command_Info cmd_info; //char* history[MAX_HISTORY_NUMBER]; while (true) { type_prompt(); get_cmd(cmd_line); if ( parse_cmd(cmd_line, &cmd_info) == -1) { syntax_error(); continue; } if (!strcmp(cmd_line, "")) continue; if (!strcmp(cmd_info.arg[0], "exit")) exit(0); pid_t pid = exec_simple(&cmd_info); waitpid(pid, NULL, 0); free_mem(&cmd_info); } return 0; }

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  • problem with piping in my own implementation of shell

    - by codemax
    Hey guys, i am implementing my own shell. I want to involve piping. i searched here and i got a code. But it is not working.Can any one help me? this is my code #include <sys/types.h> #include <sys/wait.h> #include <sys/ipc.h> #include <fcntl.h> #include <unistd.h> #include <string.h> #include <iostream> #include <cstdlib> using namespace std; char temp1[81][81],temp2[81][81] ,*cmdptr1[40], *cmdptr2[40]; void process(char**,int); int arg_count, count; int arg_cnt[2]; int pip,tok; char input[81]; int fds[2]; void process( char* cmd[])//, int arg_count ) { pid_t pid; pid = fork(); //char path[81]; //getcwd(path,81); //strcat(path,"/"); //strcat(path,cmd[0]); if(pid < 0) { cout << "Fork Failed" << endl; exit(-1); } else if( pid == 0 ) { execvp( cmd[0] , cmd ); } else { wait(NULL); } } void pipe(char **cmd1, char**cmd2) { cout<<endl<<endl<<"in pipe"<<endl; for(int i=0 ; i<arg_cnt[0] ; i++) { cout<<cmdptr1[i]<<" "; } cout<<endl; for(int i=0 ; i<arg_cnt[1] ; i++) { cout<<cmdptr2[i]<<" "; } pipe(fds); if (fork() == 0 ) { dup2(fds[1], 1); close(fds[0]); close(fds[1]); process(cmd1); } if (fork() == 0) { dup2(fds[0], 0); close(fds[0]); close(fds[1]); process(cmd2); } close(fds[0]); close(fds[1]); wait(NULL); } void pipecommand(char** cmd1, char** cmd2) { cout<<endl<<endl; for(int i=0 ; i<arg_cnt[0] ; i++) { cout<<cmd1[i]<<" "; } cout<<endl; for(int i=0 ; i<arg_cnt[1] ; i++) { cout<<cmd2[i]<<" "; } int fds[2]; // file descriptors pipe(fds); // child process #1 if (fork() == 0) { // Reassign stdin to fds[0] end of pipe. dup2(fds[0], STDIN_FILENO); close(fds[1]); close(fds[0]); process(cmd2); // child process #2 if (fork() == 0) { // Reassign stdout to fds[1] end of pipe. dup2(fds[1], STDOUT_FILENO); close(fds[0]); close(fds[1]); // Execute the first command. process(cmd1); } wait(NULL); } close(fds[1]); close(fds[0]); wait(NULL); } void splitcommand1() { tok++; int k,done=0,no=0; arg_count = 0; for(int i=count ; input[i] != '\0' ; i++) { k=0; while(1) { count++; if(input[i] == ' ') { break; } if((input[i] == '\0')) { done = 1; break; } if(input[i] == '|') { pip = 1; done = 1; break; } temp1[arg_count][k++] = input[i++]; } temp1[arg_count][k++] = '\0'; arg_count++; if(done == 1) { break; } } for(int i=0 ; i<arg_count ; i++) { cmdptr1[i] = temp1[i]; } arg_cnt[tok] = arg_count; } void splitcommand2() { tok++; cout<<"count is :"<<count<<endl; int k,done=0,no=0; arg_count = 0; for(int i=count ; input[i] != '\0' ; i++) { k=0; while(1) { count++; if(input[i] == ' ') { break; } if((input[i] == '\0')) { done = 1; break; } if(input[i] == '|') { pip = 1; done = 1; cout<<"PIP"; break; } temp2[arg_count][k++] = input[i++]; } temp2[arg_count][k++] = '\0'; arg_count++; if(done == 1) { break; } } for(int i=0 ; i<arg_count ; i++) { cmdptr2[i] = temp2[i]; } arg_cnt[tok] = arg_count; } int main() { cout<<endl<<endl<<"Welcome to unique shell !!!!!!!!!!!"<<endl; tok=-1; while(1) { cout<<endl<<"***********UNIQUE**********"<<endl; cin.getline(input,81); count = 0,pip=0; splitcommand1(); if(pip == 1) { count++; splitcommand2(); } cout<<endl<<endl; if(strcmp(cmdptr1[0], "exit") == 0 ) { cout<<endl<<"EXITING UNIQUE SHELL"<<endl; exit(0); } //cout<<endl<<"Arg count is :"<<arg_count<<endl; if(pip == 1) { cout<<endl<<endl<<"in main :"; for(int i=0 ; i<arg_cnt[0] ; i++) { cout<<cmdptr1[i]<<" "; } cout<<endl; for(int i=0 ; i<arg_cnt[1] ; i++) { cout<<cmdptr2[i]<<" "; } pipe(cmdptr1, cmdptr2); } else { process (cmdptr1);//,arg_count); } } } I know it is not well coded. But try to help me :(

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