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Search found 194 results on 8 pages for 'httpservletresponse'.

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  • Task queue java

    - by user268515
    Hi i'm new to Task queue java API i tried a simple Example for it. My idea is to redirect the queue file to a servlet and to print some statement in the servlet.But it doesn't work. i mapped web.xml and used default queue I didnt get any Error but the file is not redirected to servlet . this is the codee i followed taskq.java public class taskq extends HttpServlet { public void doGet(HttpServletRequest req, HttpServletResponse resp)throwsIOException { Queue queue = QueueFactory.getDefaultQueue(); System.out.println("taskqueue"); queue.add(url("/worker")); } worker.java public class worker extends HttpServlet { private static final long serialVersionUID = 1L; public String s; public void doGet(HttpServletRequest req, HttpServletResponse resp)throws IOException { String s="crimsom"; System.out.println(s); } } Please Help me on this issue. Regards Sharun.

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  • facebook login problem

    - by khoyendra
    This is the code which is use for login in facebook but it is go to the finaly block and show my facebook link in browser. i am show from which it go to the finaly block in program. how to login without open browser this example is yack from http://code.google.com/p/facebook-java-api/wiki/Examples try{ MDC.put(ipAddress, req.getRemoteAddr()); HttpServletRequest request = (HttpServletRequest) req; HttpServletResponse response = (HttpServletResponse) res; HttpSession session = request.getSession(true); IFacebookRestClient<Document> userClient = getUserClient(session); if (userClient == null) { logger.debug("User session doesn't have a Facebook API client setup yet. Creating one and storing it in the user's session."); userClient = new FacebookXmlRestClient(api_key, secret); session.setAttribute(FACEBOOK_USER_CLIENT, userClient); } logger.trace("Creating a FacebookWebappHelper, which copies fb_ request param data into the userClient"); FacebookWebappHelper<Document> facebook = new FacebookWebappHelper<Document>(request, response, api_key, secret, userClient); String nextPage = request.getRequestURI(); nextPage = nextPage.substring(nextPage.indexOf("/", 1) + 1); //cut out the first /, the context path and the 2nd / logger.trace(nextPage); boolean redirectOccurred = facebook.requireLogin(nextPage); if (redirectOccurred) { return; //from this pt. send to finaly block and open my facebook page } redirectOccurred = facebook.requireFrame(nextPage); if (redirectOccurred) { return; } long facebookUserID; try { facebookUserID = userClient.users_getLoggedInUser(); } catch (FacebookException ex) { response.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR, "Error while fetching user's facebook ID"); logger.error("Error while getting cached (supplied by request params) value " + "of the user's facebook ID or while fetching it from the Facebook service " + "if the cached value was not present for some reason. Cached value = {}", userClient.getCacheUserId()); return; } MDC.put(facebookUserId, String.valueOf(facebookUserID)); chain.doFilter(request, response); } finally { MDC.remove(ipAddress); MDC.remove(facebookUserId); }

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  • How to use EJB 3.1 DI in Servlet ? (Could not inject session bean by @EJB from web application)

    - by kislo_metal
    I am tying to merging web application(gwt, jpa) to an separate 2 application(business login in ejb/jpa and web client in gwt). Currently i can`t inject my beans from web application (simple servlet) I am using glassfish v3. module limbo(ejb jar) is in dependency of module lust (war). If I use lust with compiler output of limbo everything work perfect (if ejb in web application and the are deploying together as one application). Have I messed some container configuration ? Here is my steps: I have some limbo.jar (ejb-jar) deployed to ejb container. I do not use any ejb-jar.xml, only annotations. package ua.co.inferno.limbo.persistence.beans; import javax.ejb.Remote; @Remote public interface IPersistentServiceRemote { ArrayList<String> getTerminalACPList(); ArrayList<String> getBoxACPList(); ArrayList<String> getCNPList(); ArrayList<String> getCNSList(); String getProductNamebyID(int boxid); ArrayList<String> getRegionsList(String lang); long getSequence(); void persistEntity (Object ent); } package ua.co.inferno.limbo.persistence.beans; import ua.co.inferno.limbo.persistence.entitis.EsetChSchemaEntity; import ua.co.inferno.limbo.persistence.entitis.EsetKeyActionsEntity; @Local public interface IPersistentService { ArrayList<String> getTerminalACPList(); ArrayList<String> getBoxACPList(); ArrayList<String> getCNPList(); ArrayList<String> getCNSList(); String getProductNamebyID(int boxid); ArrayList<String> getRegionsList(String lang); long getSequence(); long persistPurchaseBox(EsetRegPurchaserEntity rp); void removePurchaseTempBox(EsetRegPurchaserTempEntity rpt); EsetRegionsEntity getRegionsById(long rid); void persistEntity (Object ent); } package ua.co.inferno.limbo.persistence.beans; import ua.co.inferno.limbo.persistence.entitis.EsetChSchemaEntity; import ua.co.inferno.limbo.persistence.entitis.EsetKeyActionsEntity; import ua.co.inferno.limbo.persistence.entitis.EsetRegBoxesEntity; import javax.ejb.Stateless; import javax.persistence.EntityManager; import javax.persistence.PersistenceContext; @Stateless(name = "PersistentService") public class PersistentServiceEJB implements IPersistentService, IPersistentServiceRemote{ @PersistenceContext(unitName = "Limbo") EntityManager em; public PersistentServiceEJB() { } ......... } Than i trying to use PersistentService session bean(included in limbo.jar) from web application in lust.war (the limbo.jar & lust.war is not in ear) package ua.co.lust; import ua.co.inferno.limbo.persistence.beans.IPersistentService; import javax.ejb.EJB; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.IOException; @WebServlet(name = "ServletTest", urlPatterns = {"/"}) public class ServletTest extends HttpServlet { protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { service(request, response); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { service(request, response); } @EJB private IPersistentService pService; public void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String hi = pService.getCNPList().toString(); System.out.println("testBean.hello method returned: " + hi); System.out.println("In MyServlet::init()"); System.out.println("all regions" + pService.getRegionsList("ua")); System.out.println("all regions" + pService.getBoxACPList()); } } web.xm <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> <servlet> <servlet-name>ServletTest</servlet-name> <servlet-class>ua.co.lust.ServletTest</servlet-class> </servlet> </web-app> When servelt is loading i ge 404 eror (The requested resource () is not available.) And errors in logs : global Log Level SEVERE Logger global Name-Value Pairs {_ThreadName=Thread-1, _ThreadID=31} Record Number 1421 Message ID Complete Message Class [ Lua/co/inferno/limbo/persistence/beans/IPersistentService; ] not found. Error while loading [ class ua.co.lust.ServletTest ] javax.enterprise.system.tools.deployment.org.glassfish.deployment.common Log Level WARNING Logger javax.enterprise.system.tools.deployment.org.glassfish.deployment.common Name-Value Pairs {_ThreadName=Thread-1, _ThreadID=31} Record Number 1422 Message ID Error in annotation processing Complete Message java.lang.NoClassDefFoundError: Lua/co/inferno/limbo/persistence/beans/IPersistentService; ejb jar was deployed with this info log : Log Level INFO Logger javax.enterprise.system.container.ejb.com.sun.ejb.containers Name-Value Pairs {_ThreadName=Thread-1, _ThreadID=26} Record Number 1436 Message ID Glassfish-specific (Non-portable) JNDI names for EJB PersistentService Complete Message [ua.co.inferno.limbo.persistence.beans.IPersistentServiceRemote#ua.co.inferno.limbo.persistence.beans.IPersistentServiceRemote, ua.co.inferno.limbo.persistence.beans.IPersistentServiceRemote] Log Level INFO Logger javax.enterprise.system.tools.admin.org.glassfish.deployment.admin Name-Value Pairs {_ThreadName=Thread-1, _ThreadID=26} Record Number 1445 Message ID Complete Message limbo was successfully deployed in 610 milliseconds. Do i nee to add some additional configuration in a case of injections from others application? Some ideas?

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  • Writing to a comet stream using tomcat 6.0

    - by user301247
    Hey I'm new to java servlets and I am trying to write one that uses comet so that I can create a long polling Ajax request. I can successfully start the stream and perform operations but I can't write anything out. Here is my code: public class CometTestServlet extends HttpServlet implements CometProcessor { /** * */ private static final long serialVersionUID = 1070949541963627977L; private MessageSender messageSender = null; protected ArrayList<HttpServletResponse> connections = new ArrayList<HttpServletResponse>(); public void event(CometEvent cometEvent) throws IOException, ServletException { HttpServletRequest request = cometEvent.getHttpServletRequest(); HttpServletResponse response = cometEvent.getHttpServletResponse(); //final PrintWriter out = response.getWriter(); if (cometEvent.getEventType() == CometEvent.EventType.BEGIN) { PrintWriter writer = response.getWriter(); writer.println("<!doctype html public \"-//w3c//dtd html 4.0 transitional//en\">"); writer.println("<head><title>JSP Chat</title></head><body bgcolor=\"#FFFFFF\">"); writer.println("</body></html>"); writer.flush(); cometEvent.setTimeout(10 * 1000); //cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.ERROR) { log("Error for session: " + request.getSession(true).getId()); synchronized(connections) { connections.remove(response); } cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.END) { log("End for session: " + request.getSession(true).getId()); synchronized(connections) { connections.remove(response); } PrintWriter writer = response.getWriter(); writer.println("</body></html>"); cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.READ) { //handleReadEvent(cometEvent); InputStream is = request.getInputStream(); byte[] buf = new byte[512]; do { int n = is.read(buf); //can throw an IOException if (n > 0) { log("Read " + n + " bytes: " + new String(buf, 0, n) + " for session: " + request.getSession(true).getId()); } else if (n < 0) { //error(cometEvent, request, response); return; } } while (is.available() > 0); } } Any help would be appreciated.

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  • How do I execute a sequence of servlets?

    - by Legend
    I have some servlets that act as individual URLs for populating a database for some dummy testing. Something of the form: public class Populate_ServletName extends HttpServlet { public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setContentType("text/plain"); //Insert records //Print confirmation } } I have about 6 such servlets which I want to execute in a sequence. I was thinking of using setLocation to set the next page to be redirected but was not sure if this is the right approach because the redirects should happen after the records have been inserted. Specifically, I am looking for something like this: public class Populate_ALL extends HttpServlet { public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setContentType("text/plain"); //Call Populate_1 //Call Populate_2 //Call Populate_3 //... } } Any suggestions?

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  • How to set response header in JAX-RS so that user sees download popup for Excel?

    - by masato-san
    I wrote code that generate Excel file using REST JAX-RS and I confirmed that the generated Excel file is in GlassFish server directory. But my goal is when user click on the button (which generate Excel .xls), I want download popup to show up asking user whether to save or open the .xls file just like any other web services doing for downloading any type of files. According to my search, the step is: generate Excel .xls (DONE) write the excel to stream in JAX-RS file, set response header to something like, String fileName = "Blah_Report.xls"; response.setHeader("Content-Disposition", "attachment; filename=" + fileName); My question is I'm doing all of this in JAX-RS file and I don't have HttpServletResponse object available. According to the answer from Add Response Header to JAX-RS Webservice He says: You can inject a reference to the actual HttpServletResponse via the @Context annotation in your webservice and use addHeader() etc. to add your header. I can't really figure what exactly that means without sample code..

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  • how to apply filters in jsf

    - by johnbritto
    Hi I have filter code Page not Found error while any client request for Jsf Page in my Jsf application.I dont Know How to Fix this issue This is My Filter Code: HttpServletRequest req =(HttpServletRequest)request; HttpServletResponse res =(HttpServletResponse)response; HttpSession ses = req.getSession(true); String pageRequested =req.getRequestURL().toString(); if (ses.getAttribute("userDetails")!=null) { fc.doFilter(request,response); }else{ RequestDispatcher dis = request.getRequestDispatcher(LOGIN_PAGE); dis.forward(request,response); } This code inside the DoFilter Method I done all The settings in Web.xml deployment Descriptor

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  • How do I redirect to the current page in Servlet Filter?

    - by JeffJak
    I have a page say: /myapp/test.jsp?queryString=Y. The filter needs to redirect to current page. It should go to /myapp/test.jsp (without the query string). The below seems to bring it to to the context root: /myapp. I am running in WAS6.1. public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain) throws IOException, ServletException { HttpServletRequest httpReq = (HttpServletRequest) req; HttpServletResponse httpResp = (HttpServletResponse) resp; { boolean blnNeedToRedirect = true; if (blnNeedToRedirect) { httpResp.sendRedirect("."); return; } chain.doFilter(req, resp); }

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  • Error with connection in my database servlet

    - by Zerobu
    Hello, I am writing a Database servlet, all seems well except that there seems to be an error in my connection import java.io.IOException; import java.sql.Connection; import java.sql.DriverManager; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Statement; import java.util.ArrayList; import javax.servlet.RequestDispatcher; import javax.servlet.ServletContext; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class DBServlet3 extends HttpServlet { private static final long serialVersionUID = 1L; @Override public void init() throws ServletException { super.init(); try { String jdbcDriverClass= getServletContext().getInitParameter( "jdbcDriverClass" ); if (jdbcDriverClass == null) throw new ServletException( "Could not find jdbcDriverClass initialization parameter" ); Class.forName( jdbcDriverClass ); } catch (ClassNotFoundException e) { throw new ServletException( "Could not load JDBC driver class", e ); } } @Override protected void doGet( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { RequestDispatcher dispatcher= request.getRequestDispatcher( "/db.jsp" ); ServletContext application= getServletContext(); ArrayList<String> names= new ArrayList<String>(); try { Connection connection= null; Statement statement= null; ResultSet results= null; try { String jdbcUrl= application.getInitParameter( "jdbcUrl" ); String jdbcUser= application.getInitParameter( "jdbcUser" ); String jdbcPassword= application.getInitParameter( "jdbcPassword" ); connection= DriverManager.getConnection( jdbcUrl, jdbcUser, jdbcPassword ); statement= connection.createStatement(); results= statement.executeQuery( "SELECT * FROM students" ); while (results.next()) { String name= results.getString( "name" ); names.add( name ); } } finally { if (results != null) results.close(); if (statement != null) statement.close(); if (connection != null) connection.close(); } } catch (SQLException e) { throw new ServletException( e ); } request.setAttribute( "names", names ); dispatcher.forward( request, response ); } @Override protected void doPost( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { String sql= "INSERT INTO students VALUES (" + request.getParameter( "id" ) + ", '" + request.getParameter( "name" ) + "')"; sql= "INSERT INTO students VALUES (?, ?, ?, ?)"; PreparedStatement statement= connection.prepareStatement( sql ); //error on this line statement.setString( 1, request.getParameter( "id" ) ); statement.setString( 2, request.getParameter( "name" ) ); } }

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  • How to get the action from the HttpServlet request to dispatch to multiple pages

    - by JFB
    I am using the Page Controller pattern. How could I use the same controller for two different pages by detecting the request action and then dispatching according to the result? Here is my code: account.jsp <form name="input" action="<%=request.getContextPath() %>/edit" method="get"> <input type="submit" value="Modifier" /> </form> Account Servlet public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("received HTTP GET"); String action = request.getParameter("action"); if (action == null) { // the account page dispatch(request, response, "/account"); } else if (action == "/edit") { // the popup edit page dispatch(request, response, "/edit"); } protected void dispatch(HttpServletRequest request, HttpServletResponse response, String page) throws javax.servlet.ServletException, java.io.IOException { RequestDispatcher dispatcher = getServletContext() .getRequestDispatcher(page); dispatcher.forward(request, response); } }

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • Can't run my servlet from tomcat server even though the classes are in package

    - by Mido
    Hi there, i am trying to get my servlet to run, i have been searching for 2 days and trying every possible solution and no luck. The servet class is in the appropriate folder (i.e under the package name). I also added the jar files needed in my servlet into lib folder. the web.xml file maps the url and defines the servlet. So i did everything in the documentation and wt people said in here and still getting this error : type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception javax.servlet.ServletException: Error instantiating servlet class assign1a.RPCServlet org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:108) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:558) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:379) org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:282) org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:357) org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:1687) java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) java.lang.Thread.run(Thread.java:619) root cause java.lang.NoClassDefFoundError: assign1a/RPCServlet (wrong name: server/RPCServlet) java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClassCond(ClassLoader.java:632) java.lang.ClassLoader.defineClass(ClassLoader.java:616) java.security.SecureClassLoader.defineClass(SecureClassLoader.java:141) org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java:2820) org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java:1143) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1638) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:108) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:558) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:379) org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:282) org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:357) org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:1687) java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) java.lang.Thread.run(Thread.java:619) note The full stack trace of the root cause is available in the Apache Tomcat/7.0.5 logs. Also here is my servlet code : package assign1a; import java.io.IOException; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import lib.jsonrpc.RPCService; public class RPCServlet extends HttpServlet { /** * */ private static final long serialVersionUID = -5274024331393844879L; private static final Logger log = Logger.getLogger(RPCServlet.class.getName()); protected RPCService service = new ServiceImpl(); public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); response.getWriter().write("rpc service " + service.getServiceName() + " is running..."); } public void doPost(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { try { service.dispatch(request, response); } catch (Throwable t) { log.log(Level.WARNING, t.getMessage(), t); } } } Please help me :) Thanks. EDIT: here are the contents of my web.xml file <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0" metadata-complete="true"> <servlet> <servlet-name>jsonrpc</servlet-name> <servlet-class>assign1a.RPCServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>jsonrpc</servlet-name> <url-pattern>/rpc</url-pattern> </servlet-mapping> </web-app>

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  • Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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  • Spring Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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  • Path to background in servlet

    - by kapil chhattani
    //the below line is the element of my HTML form which renders the image sent by the servlet written further below. <img style="margin-left:91px; margin-top:-6px;" class="image" src="http://www.abcd.com/captchaServlet"> I generate a captcha code using the following code in java. public class captchaServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 150; int height = 50; int charsToPrint = 6; String elegibleChars = "ABCDEFGHJKLMPQRSTUVWXYabcdefhjkmnpqrstuvwxy1234567890"; char[] chars = elegibleChars.toCharArray(); StringBuffer finalString = new StringBuffer(); for ( int i = 0; i < charsToPrint; i++ ) { double randomValue = Math.random(); int randomIndex = (int) Math.round(randomValue * (chars.length - 1)); char characterToShow = chars[randomIndex]; finalString.append(characterToShow); } System.out.println(finalString); BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); Graphics2D g2d = bufferedImage.createGraphics(); Font font = new Font("Georgia", Font.BOLD, 18); g2d.setFont(font); RenderingHints rh = new RenderingHints( RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); rh.put(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); g2d.setRenderingHints(rh); GradientPaint gp = new GradientPaint(0, 0, Color.BLUE, 0, height/2, Color.black, true); g2d.setPaint(gp); g2d.fillRect(0, 0, width, height); g2d.setColor(new Color(255, 255, 0)); Random r = new Random(); int index = Math.abs(r.nextInt()) % 5; char[] data=new String(finalString).toCharArray(); String captcha = String.copyValueOf(data); int x = 0; int y = 0; for (int i=0; i<data.length; i++) { x += 10 + (Math.abs(r.nextInt()) % 15); y = 20 + Math.abs(r.nextInt()) % 20; g2d.drawChars(data, i, 1, x, y); } g2d.dispose(); response.setContentType("image/png"); OutputStream os = response.getOutputStream(); ImageIO.write(bufferedImage, "png", os); os.close(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } } But in the above code background is also generated using the setPaint menthod I am guessing. I want the background to be some image from my local machine whoz URL i should be able to mention like URL url=this.getClass().getResource("Desktop/images.jpg"); BufferedImage bufferedImage = ImageIO.read(url); I am just writing the above two lines for making the reader understand better what the issue is. Dont want to use the exact same commands. All I want is the the background of the captcha code generated should be an image of my choice.

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  • Scope of Connection Object for a Website using Connection Pooling (Local or Instance)

    - by Danny
    For a web application with connection polling enabled, is it better to work with a locally scoped connection object or instance scoped connection object. I know there is probably not a big performance improvement between the two (because of the pooling) but would you say that one follows a better pattern than the other. Thanks ;) public class MyServlet extends HttpServlet { DataSource ds; public void init() throws ServletException { ds = (DataSource) getServletContext().getAttribute("DBCPool"); } protected void doGet(HttpServletRequest arg0, HttpServletResponse arg1) throws ServletException, IOException { SomeWork("SELECT * FROM A"); SomeWork("SELECT * FROM B"); } void SomeWork(String sql) { Connection conn = null; try { conn = ds.getConnection(); // execute some sql ..... } finally { if(conn != null) { conn.close(); // return to pool } } } } Or public class MyServlet extends HttpServlet { DataSource ds; Connection conn;* public void init() throws ServletException { ds = (DataSource) getServletContext().getAttribute("DBCPool"); } protected void doGet(HttpServletRequest arg0, HttpServletResponse arg1) throws ServletException, IOException { try { conn = ds.getConnection(); SomeWork("SELECT * FROM A"); SomeWork("SELECT * FROM B"); } finally { if(conn != null) { conn.close(); // return to pool } } } void SomeWork(String sql) { // execute some sql ..... } }

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  • Implementing Struts 2 Interceptors using Struts 1

    - by Andriy Zakharchuk
    Hello all, I have a legacy application written with Struts 1. The only feature I was asked to add is to protect some actions. Currently any user can do whatever he/she wants. The idea is to allows all user see the data, but block modification operation, i.e. to modify data a user should log in. I know Struts2 has interceptors, so I could attach them to required actions and forward users to log in page when needed. But how can I do similar thing in Struts 1 application? My first idea was to create my own abstract Action class: public class AuthenticatedAction { public ActionForward execute( ActionMapping mapping, ActionForm form, HttpServletRequest theRequest, HttpServletResponse theResponse) { if (!logged) { // forward to log in form } else { doExecute(mapping, form, request, response); } } public abstract ActionForward doExecute( ActionMapping mapping, ActionForm form, HttpServletRequest theRequest, HttpServletResponse theResponse); } Then change all actions that require authentication from extends Action to extends AuthenticatedAction then add login form, login action (which performs authentications and puts this status into the session) and change JSP header tile to display authentication block, e.g., "You are (not logged in)/", Login/Logout. As I guess this should solve the problem. If this doesn't solve the problem, please explain me why. Is there any better (more elegant like interceptors are) way to do this? Thank you in advance.

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  • Struts ActionError

    - by user287663
    Hi all. Anyone knows why the code below doesn't compile? The reason is that it could not find symbol for ActionError. Thanks in advance. package com.hbs; import javax.servlet.RequestDispatcher; import javax.servlet.ServletException; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpSession; import javax.servlet.http.HttpServletResponse; import org.apache.struts.action.Action; import org.apache.struts.action.ActionError; import org.apache.struts.action.ActionErrors; import org.apache.struts.action.ActionForm; import org.apache.struts.action.ActionMapping; import org.apache.struts.action.ActionForward; import org.apache.struts.util.MessageResources; import org.apache.commons.beanutils.PropertyUtils; public class FeedbackAction extends org.apache.struts.action.Action { private final static String SUCCESS = "success"; public ActionForward execute(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { ActionErrors errors = new ActionErrors(); String fullName = (String)PropertyUtils.getSimpleProperty(form, "fullName"); String fullName1 = ""; if(fullName.equals(fullName1)) { errors.add("fullName", new ActionError("error.fullName", fullName)); saveErrors(request,errors); return (new ActionForward(mapping.getInput())); } return mapping.findForward(SUCCESS); } }

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  • How to get error text in controller from BindingResult

    - by Mike
    I have an controller that returns JSON. It takes a form, which validates itself via spring annotations. I can get FieldError list from BindingResult, but they don't contain the text that a JSP would display in the tag. How can I get the error text to send back in JSON? @RequestMapping(method = RequestMethod.POST) public @ResponseBody JSONResponse submit(@Valid AnswerForm answerForm, BindingResult result, Model model, HttpServletRequest request, HttpServletResponse response) { if (result.hasErrors()) { response.setStatus(HttpServletResponse.SC_BAD_REQUEST); JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.ERROR); //HOW DO I GET ERROR MESSAGES OUT OF BindingResult??? } else { JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.OK); return r; } } JSONREsponse class is just a POJO public class JSONResponse implements Serializable { private JSONResponseStatus status; private String error; private Map<String,String> errors; private Map<String,Object> data; ...getters and setters... } Calling BindingResult.getAllErrors() returns an array of FieldError objects, but it doesn't have the actual errors.

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  • Spring MVC- several parts/views from a controller

    - by leeeroy
    i'm looking into using Spring MVC - how would I structure the fact that a page can be composed of several different views Consider a controller that's basically: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); return new ModelAndView("posts", "posts", posts); } However, I decide that on every page, I'd also want a side "pane" that shows data based on some logic. That "pane" would just be a .jsp that gets included from the above "posts" view, and I could change my controller to: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); List<Items> items= repository.getItems(); return new ModelAndView("model", "model", new MyCommonViewModel(posts,items)); } But then I'd have to change every controller to also do List<Items> items= repository.getItems(); , and change everything again the next time I come up with something new. This seems messy. How do I structure this ? `

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  • Using ControllerClassNameHandlerMapping with @Controller and extending AbstractController

    - by whiskerz
    Hey there, actually I thought I was trying something really simple. ControllerClassNameHandlerMapping sounded great to produce a small spring webapp using a very lean configuration. Just annotate the Controller with @Controller, have it extend AbstractController and the configuration shouldn't need more than this <context:component-scan base-package="test.mypackage.controller" /> <bean id="urlMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" /> to resolve my requests and map them to my controllers. I've mapped the servlet to "*.spring", and calling <approot>/hello.spring All I ever get is an error stating that no mapping was found. If however I extend the MultiActionController, and do something like <approot>/hello/hello.spring it works. Which somehow irritates me, as I would have thought that if that is working, why didn't my first try? Does anyone have any idea? The two controllers I used looked like this @Controller public class HelloController extends AbstractController { @Override protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } } and @Controller public class HelloController extends MultiActionController { public ModelAndView hello(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } }

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Google App Engine how to get an object from the servlet ?

    - by Frank
    I have the following class objects in Google App Engine's dadastore, I can see them from the "Datastore Viewer " : import javax.jdo.annotations.IdGeneratorStrategy; import javax.jdo.annotations.IdentityType; import javax.jdo.annotations.PersistenceCapable; import javax.jdo.annotations.Persistent; import javax.jdo.annotations.PrimaryKey; @PersistenceCapable(identityType=IdentityType.APPLICATION) public class Contact_Info_Entry implements Serializable { @PrimaryKey @Persistent(valueStrategy=IdGeneratorStrategy.IDENTITY) Long Id; public static final long serialVersionUID=26362862L; String Contact_Id="",First_Name="",Last_Name="",Company_Name="",Branch_Name="",Address_1="",Address_2="",City="",State="",Zip="",Country=""; double D_1,D_2; boolean B_1,B_2; Vector<String> A_Vector=new Vector<String>(); public Contact_Info_Entry() { } ...... } How can my java applications get the object from a servlet url ? For instance if have an instance of Contact_Info_Entry who's Contact_Id is "ABC-123", and my App Id is : nm-java When my java program accesses the url : "http://nm-java.appspot.com/Check_Contact_Info?Contact_Id=ABC-123 How will the Check_Contact_Info servlet get the object from datastore and return it to my app ? public class Check_Contact_Info_Servlet extends HttpServlet { static boolean Debug=true; public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException { } ... protected void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException { doGet(request,response); } } Frank

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • Struts 2 discard cache header

    - by Dewfy
    I have strange discarding behavior of struts2 while setting cache option for my image. I'm trying to put image from db to be cached on client side To render image I use ( http://struts.apache.org/2.x/docs/how-can-we-display-dynamic-or-static-images-that-can-be-provided-as-an-array-of-bytes.html ) where special result type render as follow: public void execute(ActionInvocation invocation) throws Exception { ...//some preparation HttpServletResponse response = ServletActionContext.getResponse(); HttpServletRequest request = ServletActionContext.getRequest(); ServletOutputStream os = response.getOutputStream(); try { byte[] imageBytes = action.getImage(); response.setContentType("image/gif"); response.setContentLength(imageBytes.length); //I want cache up to 10 min Date future = new Date(((new Date()).getTime() + 1000 * 10*60l)); ; response.addDateHeader("Expires", future.getTime()); response.setHeader("Cache-Control", "max-age=" + 10*60 + ""); response.addHeader("cache-Control", "public"); response.setHeader("ETag", request.getRequestURI()); os.write(imageBytes); } catch(Exception e) { response.sendError(HttpServletResponse.SC_NOT_FOUND); } os.flush(); os.close(); } But when image is embedded to page it is always reloaded (Firebug shows code 200), and neither Expires, nor max-age are presented in header Host localhost:9090 Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Referer http://localhost:9090/web/result?matchId=1 Cookie JSESSIONID=4156BEED69CAB0B84D950932AB9EA1AC; If-None-Match /web/_srv/teamcolor Cache-Control max-age=0 I have no idea why it is dissapered, may be problem in url? It is forms with parameter: http://localhost:9090/web/_srv/teamcolor?loginId=3

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