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  • Is there a media player that works on HTTPS sites?

    - by Iain Hallam
    I'm currently using Yahoo! Media Player for a site that needs to play MP3 files that are stored on our server. In total, there's quite a bit more than the free limits at Soundcloud, but each file is only a few minutes long. YMP is pretty good, but causes security warnings on HTTPS pages, because it can only be served via HTTP. Is there an equivalent free player I can embed for the HTTPS pages? EDIT: Just to clarify, I'm initially looking for something that will scan the page and turn media links playable.

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  • Logitech Microphone (AK5370) inaudible volume

    - by Iain Lane
    I bought this microphone from Amazon last week. It's detected just fine in 12.10. I can see it in the sound preferences. The problem is that the volume is so low as to be inaudible, even when turned up to maximum in this dialog. It is working, as I can see that the meter responds to noise, but it's just too low. alsamixer's control is the same, so that doesn't help. I tried messing around in pulseaudio too, but to no avail. In lsusb it's Bus 002 Device 004: ID 0556:0001 Asahi Kasei Microsystems Co., Ltd AK5370 I/F A/D Converter.

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  • How do I remove only some values of a URL parameter in Google Analytics?

    - by Iain Hallam
    I'm using Google Analytics on a DokuWiki site, which uses a URL parameter to decide what to do with the current page: /page is equivalent to: /page?do=show 1) I want to see some of these "modes", but mostly I'd like them counted as viewing the bare page URL itself. The following are the only ones I want to see separately: /page?do=login /page?do=backlinks /page?do=revisions /page?do=subscribe How do I collapse the unwanted modes to the page itself (/page)? 2) Some modes do something that should really not have a page attached, such as: /page1?do=sitemap /page2?do=sitemap How do I get these to show up without the page part (/?do=sitemap)? 3) What do I do with the search mode? Can I remove the page part from this too, and still find out which page people used the search function on? /page?do=search&id=query+text

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  • How do I best remove an entity from my game loop when it is dead?

    - by Iain
    Ok so I have a big list of all my entities which I loop through and update. In AS3 I can store this as an Array (dynamic length, untyped), a Vector (typed) or a linked list (not native). At the moment I'm using Array but I plan to change to Vector or linked list if it is faster. Anyway, my question, when an Entity is destroyed, how should I remove it from the list? I could null its position, splice it out or just set a flag on it to say "skip over me, I'm dead." I'm pooling my entities, so an Entity that is dead is quite likely to be alive again at some point. For each type of collection what is my best strategy, and which combination of collection type and removal method will work best?

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  • excel vba moving non-contiguous range selection to an array

    - by Russ Urquhart
    In the situation where the user select two non-contiguous column ranges i wrote the following: Dim count long Dim points variant Dim i long Set user_range = ActiveWindow.RangeSelection count = user_range.count / 2 ReDim points(1 To count, 1 To 2) For i = 1 To count MsgBox "value is" & user_range.Areas.Item(1).Value(i,1) points(i, 1) = user_range.Areas.Item(1).Value(i,1) points(i, 2) = user_range.Areas.Item(2).Value(i,1) Next i But i get an object error when i try this. Am i indexing Value wrong? This should work right? Is there an easier way to do this? Any help is greatly appreciated! Thanks, Russ

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  • introduce a join to this query, possible?

    - by Iain Urquhart
    I'm trying to introduce a join to this query: SELECT `n`.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n`, `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` by adding LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`) after the FROM statement... But when I introduce it, it fails with "Unknown column 'n.entry_id' in 'on clause'" Is it even possible to add a join to this query? Can anybody help, thanks!

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  • merge 2 php arrays which aren't of the same length by value

    - by Iain Urquhart
    Excuse me if this has indeed been asked before, I couldn't see anything that fitted my needs out of the dozens of similar titled posts out there ;) I'm trying to merge 2 php arrays which aren't of the same length, and merge them on a value that exists from identical key = values within both arrays. My first query produces an array from a nested set: array ( 1 => array ( 'node_id' => 1, 'lft' => 1, 'rgt' => 4, 'moved' => 0, 'label' => 'Home', 'entry_id' => 1, 'template_path' => '', 'custom_url' => '/', 'extra' => '', 'childs' => 1, 'level' => 0, 'lower' => 0, 'upper' => 0 ), 2 => array ( 'node_id' => 2, 'lft' => 2, 'rgt' => 3, 'moved' => 0, 'label' => 'Home', 'entry_id' => NULL, 'template_path' => '', 'custom_url' => 'http://google.com/', 'extra' => '', 'childs' => 0, 'level' => 1, 'lower' => 0, 'upper' => 0 ) ); My second array returns some additional key/values I'd like to insert to the above array: array ( 'entry_id' => 1, 'entry_title' => 'This is my title', ); I want to merge both of the arrays inserting the additional information into those that match on the key 'entry_id', as well as keeping the sub arrays which don't match. So, by combining the two arrays, I'd end up with array ( 1 => array ( 'node_id' => 1, 'lft' => 1, 'rgt' => 4, 'moved' => 0, 'label' => 'Home', 'entry_id' => 1, 'template_path' => '', 'custom_url' => '/', 'extra' => '', 'childs' => 1, 'level' => 0, 'lower' => 0, 'upper' => 0, 'entry_title' => 'This is my title' ), 2 => array ( 'node_id' => 2, 'lft' => 2, 'rgt' => 3, 'moved' => 0, 'label' => 'Home', 'entry_id' => NULL, 'template_path' => '', 'custom_url' => 'http://google.com/', 'extra' => '', 'childs' => 0, 'level' => 1, 'lower' => 0, 'upper' => 0, 'entry_title' => NULL ) ); Actually, writing this out makes me think I should do it via sql... Any help/advice greatly appreciated...

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  • Broken count(*) after adding LEFT JOIN

    - by Iain Urquhart
    Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

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  • Software or Photoshop plugins for professional photo album design

    - by Iain Fraser
    I am a graphic designer (among other things) and I'm used to doing magazine advertisements, brochures, posters and that sort of thing. Recently I was approached by a photographer who wants a graphic designer to produce wedding albums for him. I have already done a couple for him but I'm finding it hard to work by just arranging my layouts in Photoshop alone. It's very time consuming, but quite repetitive - especially when you're dealing with common page layouts. I know a lot of photographers use album design software to speed up the process a bit. What's the industry standard in terms of album design software?

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  • Upgrading ATI Catalyst drivers fails

    - by Iain
    I'm trying to upgrade my ATI HD 5770 graphics card drivers, as they keep crashing, but the upgrade keeps failing half way through. I have tried the full driver package and the drivers-only package. 10-5_vista64_win7_64_dd_ccc_enu.exe 10-5_vista64_win7_64_dd.exe I'm on Windows 7 Home Premium 64 bit. How can I upgrade?

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  • setting the PATH for Git (not for me)

    - by Iain
    Hi, I'm running OSX 10.6.5 with Git 1.7.1 I have git installed in a non-standard location (though that really should be the standard on a mac;-) in /Library/Frameworks/Git.framework. My own PATH is set fine, git works fine, until... I set up a pre-commit hook with a Ruby script: $ git commit -m "added some Yard documentation" .git/hooks/pre-commit: line 1: #!/usr/bin/env: No such file or directory The pre-commit.sample runs ok, so it appears that git can't find /usr/bin/env, or much else as I've tried shebanging it directly to ruby etc. Just /bin/sh is ok. So, where does Git get it's PATH? because it's not using mine or this wouldn't be happening. And more to the point, how do I get it to see /usr/bin/env ? I've tested the ruby script already, it works. Just to add: $ cat /etc/paths /usr/bin /bin /usr/sbin /sbin /usr/local/bin $ cat /etc/paths.d/git /Library/Frameworks/Git.framework/Programs The first few lines of the Ruby script (which runs via ./pre-commit or ruby pre-commit) #!/usr/bin/env ruby -wKU class String def expand_path File.expand_path self end def parent_dir File.dirname self.expand_path end end

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  • non-interactive ssh sudo... prompts for the password in plain text

    - by Iain
    I'm running some non-interactive ssh commands. The ssh authentication is taken care of fine through the ssh agent, but if I run a command that requires sudo then the password prompt in my terminal is plain text. For example: ssh remotemachine "sudo -u www mkdir -p /path/to/new/folder" will prompt me for the password in plain text. Does anyone know how I can get it to use the normal secure prompt or that I can pass the password via a switch? (as then I can set up a secure prompt on this side before I send the command) Any help is much appreciated.

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  • All MySQL Databases lost overnight

    - by Iain
    After a call from a customer to say that his website is down, I find that MySQL on our RackSpace Cloud Windows 2008 server was not running. I restarted MySQL but got the 'Access denied for user' error in the browser for all websites with MySQL database. When I look in MySql Server 5.5/data there are no folders other than mysql and performance_schema. It appears all the databases and data have been wiped. Does anyone know what might have happened and where the data has gone? To top that I just found this server is missing from our backup service. ps appears to be after windows update at 4:01 this morning.

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  • Is enemy / bot A.I. part of the model or controller in an MVC game

    - by Iain
    It could be part of the model because it's part of the business logic of the game. It could be part of the controller because it could be seen as simulating player input, which would be considered part of the controller, right? Or would it? What about a normal enemy, like a goomba in Mario? UPDATE: Wow, that's really not the answer I was expecting. As far as I could tell, A.I. is an internal part of the autonomous game system, hence model. I'm still not convinced.

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  • Jquery Uploader not saving to a folder in the site root

    - by Iain Simpson
    im trying to integrate the Jquery Uploader into my website http://blueimp.github.com/jQuery-File-Upload/ The problem I am having is that I cant seem to get it save the folder I want to to save to. In the UploadHander.php I have the following settings 'script_url' => $this->get_full_url().'/', 'upload_dir' => dirname($_SERVER['SCRIPT_FILENAME']).'./images/machinery/', 'upload_url' => $this->get_full_url().'./images/machinery/', This results in an image uploaded url that looks like this http://domain.com/rcsetch/up/server/php/machinery/image.jpg Other than putting my php files in the root of the website, im not sure how to get it to work, as what I want it to do is upload the files to http://domain.com/images/machinery and not to the create a folder in the directory where all the php files for the uploader are located.

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  • jquery date validation on multiple fields

    - by iain
    I am attempting to use jquery to validate a date that is broken up into MM DD YYYY fields. <form name="dateform" id="dateform"> <input type="text" name="month"/> <input type="text" name="day"/> <input type="text" name="year"/> </form> I can only find examples that use a single field, which is not what I want. <form name="dateform" id="dateform"> <input type="text" name="date"/> </form> Any examples I can follow?

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  • IP address numbers in MySQL subquery

    - by Iain Collins
    I have a problem with a subquery involving IPV4 addresses stored in MySQL (MySQL 5.0). The IP addresses are stored in two tables, both in network number format - e.g. the format output by MySQL's INET_ATON(). The first table ('events') contains lots of rows with IP addresses associated with them, the second table ('network_providers') contains a list of provider information for given netblocks. events table (~4,000,000 rows): event_id (int) event_name (varchar) ip_address (unsigned 4 byte int) network_providers table (~60,000 rows): ip_start (unsigned 4 byte int) ip_end (unsigned 4 byte int) provider_name (varchar) Simplified for the purposes of the problem I'm having, the goal is to create an export along the lines of: event_id,event_name,ip_address,provider_name If do a query along the lines of either of the following, I get the result I expect: SELECT provider_name FROM network_providers WHERE INET_ATON('192.168.0.1') >= network_providers.ip_start ORDER BY network_providers.ip_start DESC LIMIT 1 SELECT provider_name FROM network_providers WHERE 3232235521 >= network_providers.ip_start ORDER BY network_providers.ip_start DESC LIMIT 1 That is to say, it returns the correct provider_name for whatever IP I look up (of course I'm not really using 192.168.0.1 in my queries). However, when performing this same query as a subquery, in the following manner, it doesn't yield the result I would expect: SELECT event.id, event.event_name, (SELECT provider_name FROM network_providers WHERE event.ip_address >= network_providers.ip_start ORDER BY network_providers.ip_start DESC LIMIT 1) as provider FROM events Instead the a different (incorrect) value for network_provider is returned - over 90% (but curiously not all) values returned in the provider column contain the wrong provider information for that IP. Using event.ip_address in a subquery just to echo out the value confirms it contains the value I'd expect and that the subquery can parse it. Replacing event.ip_address with an actual network number also works, just using it dynamically in the subquery in this manner that doesn't work for me. I suspect the problem is there is something fundamental and important about subqueries in MySQL that I don't get. I've worked with IP addresses like this in MySQL quite a bit before, but haven't previously done lookups for them using a subquery. The question: I'd really appreciate an example of how I could get the output I want, and if someone here knows, some enlightenment as to why what I'm doing doesn't work so I can avoid making this mistake again. Notes: The actual real-world usage I'm trying to do is considerably more complicated (involving joining two or three tables). This is a simplified version, to avoid overly complicating the question. Additionally, I know I'm not using a between on ip_start & ip_end - that's intentional (the DB's can be out of date, and such cases the owner in the DB is almost always in the next specified range and 'best guess' is fine in this context) however I'm grateful for any suggestions for improvement that relate to the question. Efficiency is always nice, but in this case absolutely not essential - any help appreciated.

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