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  • HQL join after output of subquery

    - by user350374
    Hey, Say I have 3 classes class foo1 { List prop1;} class foo2 { foo3 prop2;} class foo3{ int Id;} now I want to select distinct foo2's from foo1 and get Id of foo3. I need to write a HQL stmt for the same. I tried the following select c.Id from (select distinct(a.prop1) from foo1.prop1 as a ) as b inner join b.prop2 as c This throws an 'Antlr.Runtime.NoViableAltException How do you suggest I should go about the same. Please note the inner subquery is working fine. So if I have made some mistakes in there please ignore that. I need a method to do the latter. Thanks in Advance.

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  • MySQL Join Question

    - by rbaker86
    Hi i'm struggling to write a particular MySQL Join Query. I have a table containing product data, each product can belong to multiple categories. This m:m relationship is satisfied using a link table. For this particular query I wish to retrieve all products belonging to a given category, but with each product record, I also want to return the other categories that product belongs to. Ideally I would like to achieve this using an Inner Join on the categories table, rather than performing an additional query for each product record, which would be quite inefficient. My simplifed schema is designed roughly as follows: products table: product_id, name, title, description, is_active, date_added, publish_date, etc.... categories table: category_id, name, title, description, etc... product_category table: product_id, category_id I have written the following query, which allows me to retrieve all the products belonging to the specified category_id. However, i'm really struggling to work out how to retrieve the other categories a product belongs to. SELECT p.product_id, p.name, p.title, p.description FROM prod_products AS p LEFT JOIN prod_product_category AS pc ON pc.product_id = p.product_id WHERE pc.category_id = $category_id AND UNIX_TIMESTAMP(p.publish_date) < UNIX_TIMESTAMP() AND p.is_active = 1 ORDER BY p.name ASC I'd be happy just retrieving the category id's releated to each returned product row, as I will have all category data stored in an object, and my application code can take care of the rest. Many thanks, Richard

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  • SQL: Join Parent - Child tables

    - by pray4Mojo
    I'm building a simple review website application and need some help with SQL Query. There are 3 tables (Topics, Comments, Users). I need a SQL query to select the data from all 3 tables. The 'Topics' table is the parent and the 'Comments' table contains the child records (anywhere from zero to 100 records per parent. The third table 'Users' contains the user information for all users. Here are the fields for the 3 tables: Topics (topicID, strTopic, userID) Comments (commentID, topicID, strComment, userID) Users (userID, userName) I tried: SELECT * FROM Topics Inner Join Comments ON Topics.topicID = Comments.topicID Inner Join Users ON Topics.userID = Users.userID But this does not work correctly because there are multiple topics and the User info is not joined to the Comments table. Any help would be appreciated.

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  • Performing Inner Join for Multiple Columns in the Same Table

    - by frankiefrank
    I have a scenario which I'm a bit stuck on. Let's say I have a survey about colors, and I have one table for the color data, and another for people's answers. tbColors color_code , color_name 1 , 'blue' 2 , 'green' 3 , 'yellow' 4 , 'red' tbAnswers answer_id , favorite_color , least_favorite_color , color_im_allergic_to 1 , 1 , 2 3 2 , 3 , 1 4 3 , 1 , 1 2 4 , 2 , 3 4 For display I want to write a SELECT that presents the answers table but using the color_name column from tbColors. I understand the "most stupid" way to do it naming tbColors three times in the FROM section, using a different alias for each column to replace. How would a non-stupid way look?

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  • Remove Duplicates from LEFT OUTER JOIN

    - by Kaushik Gopal
    Hey folk my question is quite similar to http://stackoverflow.com/questions/757957/restricting-a-left-join I have a variation in that request though and the comment didn't allow too many characters hence posting as a new question. I hope this doesn't go against the posting rules/etiquette. Assuming i have a table SHOP and another table LOCATION. Location is a sort of child table of table SHOP, that has two columns of interest, one is a Division Key (calling it just KEY) and a "SHOP" number. This matches to the Number "NO" in table SHOP. I tried this left outer join: SELECT S.NO, L.KEY FROM SHOP S LEFT OUTER JOIN LOCATN L ON S.NO = L.SHOP But i'm getting a lot of duplicates since there are many locations that belong to a single shop. I want to eliminate them and just get a list of "shop, key" entries without duplicates. any ideas how? (edit: ORACLE 10g Database)

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  • Position:absolute

    - by Andrew
    I have I have a div called logo. I want the logo to be on top of other areas and to overlap into the the preface top of a drupal site, the logo currently sits in the header area. I looked up position absolute and I think that what I need to use but when I use position absolute the logo disappears, I can see it if I use position fixed, relative etc. I thought the logo was being hidden because I was not using a z-index but even with that I cant see the logo. What am I doing wrong? #logo { position: absolute; top: 30px; /* 30 pixels from the top of the page */ left: 80px; /* 80 pixels from the left hand side */ z-index:1099; border: 1px solid red; /* So we can see what is happening */ } Also does anyone know of a really good free online css course? Here is some additional information, namely the CSS and the page.tpl.php: <?php // $Id: page.tpl.php,v 1.1.2.5 2010/04/08 07:02:59 sociotech Exp $ ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="<?php print $language->language; ?>" xml:lang="<?php print $language->language; ?>"> <head> <title><?php print $head_title; ?></title> <?php print $head; ?> <?php print $styles; ?> <?php print $setting_styles; ?> <!--[if IE 8]> <?php print $ie8_styles; ?> <![endif]--> <!--[if IE 7]> <?php print $ie7_styles; ?> <![endif]--> <!--[if lte IE 6]> <?php print $ie6_styles; ?> <![endif]--> <?php print $local_styles; ?> <?php print $scripts; ?> </head> <body id="<?php print $body_id; ?>" class="<?php print $body_classes; ?>"> <div id="page" class="page"> <div id="page-inner" class="page-inner"> <div id="skip"> <a href="#main-content-area"><?php print t('Skip to Main Content Area'); ?></a> </div> <!-- header-top row: width = grid_width --> <?php print theme('grid_row', $header_top, 'header-top', 'full-width', $grid_width); ?> <!-- header-group row: width = grid_width --> <div id="header-group-wrapper" class="header-group-wrapper full-width"> <div id="header-group" class="header-group row <?php print $grid_width; ?>"> <div id="header-group-inner" class="header-group-inner inner clearfix"> <?php print theme('grid_block', theme('links', $secondary_links), 'secondary-menu'); ?> <?php print theme('grid_block', $search_box, 'search-box'); ?> <?php if ($logo || $site_name || $site_slogan): ?> <div id="header-site-info" class="header-site-info block"> <div id="header-site-info-inner" class="header-site-info-inner inner"> <?php if ($logo): ?> <div id="logo"> <a href="<?php print check_url($front_page); ?>" title="<?php print t('Home'); ?>"><img src="<?php print $logo; ?>" alt="<?php print t('Home'); ?>" /></a> </div> <?php endif; ?> <?php if ($site_name || $site_slogan): ?> <div id="site-name-wrapper" class="clearfix"> <?php if ($site_name): ?> <span id="site-name"><a href="<?php print check_url($front_page); ?>" title="<?php print t('Home'); ?>"><?php print $site_name; ?></a></span> <?php endif; ?> <?php if ($site_slogan): ?> <span id="slogan"><?php print $site_slogan; ?></span> <?php endif; ?> </div><!-- /site-name-wrapper --> <?php endif; ?> </div><!-- /header-site-info-inner --> </div><!-- /header-site-info --> <?php endif; ?> <?php print $header; ?> <?php print theme('grid_block', $primary_links_tree, 'primary-menu'); ?> </div><!-- /header-group-inner --> </div><!-- /header-group --> </div><!-- /header-group-wrapper --> <!-- preface-top row: width = grid_width --> <?php print theme('grid_row', $preface_top, 'preface-top', 'full-width', $grid_width); ?> <!-- main row: width = grid_width --> <div id="main-wrapper" class="main-wrapper full-width<?php if ($is_front) { print ' front'; } ?>"> <div id="main" class="main row <?php print $grid_width; ?>"> <div id="main-inner" class="main-inner inner clearfix"> <?php print theme('grid_row', $sidebar_first, 'sidebar-first', 'nested', $sidebar_first_width); ?> <!-- main group: width = grid_width - sidebar_first_width --> <div id="main-group" class="main-group row nested <?php print $main_group_width; ?>"> <div id="main-group-inner" class="main-group-inner inner"> <?php print theme('grid_row', $preface_bottom, 'preface-bottom', 'nested'); ?> <div id="main-content" class="main-content row nested"> <div id="main-content-inner" class="main-content-inner inner"> <!-- content group: width = grid_width - (sidebar_first_width + sidebar_last_width) --> <div id="content-group" class="content-group row nested <?php print $content_group_width; ?>"> <div id="content-group-inner" class="content-group-inner inner"> <?php print theme('grid_block', $breadcrumb, 'breadcrumbs'); ?> <?php if ($content_top || $help || $messages): ?> <div id="content-top" class="content-top row nested"> <div id="content-top-inner" class="content-top-inner inner"> <?php print theme('grid_block', $help, 'content-help'); ?> <?php print theme('grid_block', $messages, 'content-messages'); ?> <?php print $content_top; ?> </div><!-- /content-top-inner --> </div><!-- /content-top --> <?php endif; ?> <div id="content-region" class="content-region row nested"> <div id="content-region-inner" class="content-region-inner inner"> <a name="main-content-area" id="main-content-area"></a> <?php print theme('grid_block', $tabs, 'content-tabs'); ?> <div id="content-inner" class="content-inner block"> <div id="content-inner-inner" class="content-inner-inner inner"> <?php if ($title): ?> <h1 class="title"><?php print $title; ?></h1> <?php endif; ?> <?php if ($content): ?> <div id="content-content" class="content-content"> <?php print $content; ?> <?php print $feed_icons; ?> </div><!-- /content-content --> <?php endif; ?> </div><!-- /content-inner-inner --> </div><!-- /content-inner --> </div><!-- /content-region-inner --> </div><!-- /content-region --> <?php print theme('grid_row', $content_bottom, 'content-bottom', 'nested'); ?> </div><!-- /content-group-inner --> </div><!-- /content-group --> <?php print theme('grid_row', $sidebar_last, 'sidebar-last', 'nested', $sidebar_last_width); ?> </div><!-- /main-content-inner --> </div><!-- /main-content --> <?php print theme('grid_row', $postscript_top, 'postscript-top', 'nested'); ?> </div><!-- /main-group-inner --> </div><!-- /main-group --> </div><!-- /main-inner --> </div><!-- /main --> </div><!-- /main-wrapper --> <!-- postscript-bottom row: width = grid_width --> <?php print theme('grid_row', $postscript_bottom, 'postscript-bottom', 'full-width', $grid_width); ?> <!-- footer row: width = grid_width --> <?php print theme('grid_row', $footer, 'footer', 'full-width', $grid_width); ?> <!-- footer-message row: width = grid_width --> <div id="footer-message-wrapper" class="footer-message-wrapper full-width"> <div id="footer-message" class="footer-message row <?php print $grid_width; ?>"> <div id="footer-message-inner" class="footer-message-inner inner clearfix"> <?php print theme('grid_block', $footer_message, 'footer-message-text'); ?> </div><!-- /footer-message-inner --> </div><!-- /footer-message --> </div><!-- /footer-message-wrapper --> </div><!-- /page-inner --> </div><!-- /page --> <?php print $closure; ?> </body> </html> CSS /* $Id: style.css,v 1.1.2.11 2010/07/02 22:11:04 sociotech Exp $ */ /* Margin, Padding, Border Resets -------------------------------------------------------------- */ html, body, div, span, p, dl, dt, dd, ul, ol, li, h1, h2, h3, h4, h5, h6, form, fieldset, input, textarea { margin: 0; padding: 0; } img, abbr, acronym { border: 0; } /* HTML Elements -------------------------------------------------------------- */ p { margin: 1em 0; } h1, h2, h3, h4, h5, h6 { margin: 0 0 0.5em 0; } h1 { color: white !important; text-shadow: black !important; } ul, ol, dd { margin-bottom: 1.5em; margin-left: 2em; /* LTR */ } li ul, li ol { margin-bottom: 0; } ul { list-style-type: disc; } ol { list-style-type: decimal; } a { margin: 0; padding: 0; text-decoration: none; } a:link, a:visited { } a:hover, a:focus, a:active { text-decoration: underline; } blockquote { } hr { height: 1px; border: 1px solid gray; } /* tables */ table { border-spacing: 0; width: 100%; } tr.even td, tr.odd td { background-color: #FFFFFF; border: 1px solid #dbdbdb; } caption { text-align: left; } th { margin: 0; padding: 0 10px 0 0; } th.active img { display: inline; } thead th { padding-right: 10px; } td { margin: 0; padding: 3px; } /* Remove grid block styles from Drupal's table ".block" class */ td.block { border: none; float: none; margin: 0; } /* Maintain light background/dark text on dragged table rows */ tr.drag td, tr.drag-previous td { background: #FFFFDD; color: #000; } /* Accessibility /-------------------------------------------------------------- */ /* skip-link to main content, hide offscreen */ #skip a, #skip a:hover, #skip a:visited { height: 1px; left: 0px; overflow: hidden; position: absolute; top: -500px; width: 1px; } /* make skip link visible when selected */ #skip a:active, #skip a:focus { background-color: #fff; color: #000; height: auto; padding: 5px 10px; position: absolute; top: 0; width: auto; z-index: 99; } #skip a:hover { text-decoration: none; } /* Helper Classes /-------------------------------------------------------------- */ .hide { display: none; visibility: hidden; } .left { float: left; } .right { float: right; } .clear { clear: both; } /* clear floats after an element */ /* (also in ie6-fixes.css, ie7-fixes.css) */ .clearfix:after, .clearfix .inner:after { clear: both; content: "."; display: block; font-size: 0; height: 0; line-height: 0; overflow: auto; visibility: hidden; } /* Grid Layout Basics (specifics in 'gridnn_x.css') -------------------------------------------------------------- */ /* center page and full rows: override this for left-aligned page */ .page, .row { margin: 0 auto; } /* fix layout/background display on floated elements */ .row, .nested, .block { overflow: hidden; } /* full-width row wrapper */ div.full-width { width: 100%; } /* float, un-center & expand nested rows */ .nested { float: left; /* LTR */ margin: 0; width: 100%; } /* allow Superfish menus to overflow */ #sidebar-first.nested, #sidebar-last.nested, div.superfish { overflow: visible; } /* sidebar layouts */ .sidebars-both-first .content-group { float: right; /* LTR */ } .sidebars-both-last .sidebar-first { float: right; /* LTR */ } /* Grid Mask Overlay -------------------------------------------------------------- */ #grid-mask-overlay { display: none; left: 0; opacity: 0.75; position: absolute; top: 0; width: 100%; z-index: 997; } #grid-mask-overlay .row { margin: 0 auto; } #grid-mask-overlay .block .inner { background-color: #e3fffc; outline: none; } .grid-mask #grid-mask-overlay { display: block; } .grid-mask .block { overflow: visible; } .grid-mask .block .inner { outline: #f00 dashed 1px; } #grid-mask-toggle { background-color: #777; border: 2px outset #fff; color: #fff; cursor: pointer; font-variant: small-caps; font-weight: normal; left: 0; -moz-border-radius: 5px; padding: 0 5px 2px 5px; position: absolute; text-align: center; top: 22px; -webkit-border-radius: 5px; z-index: 998; } #grid-mask-toggle.grid-on { border-style: inset; font-weight: bold; } /* Site Info -------------------------------------------------------------- */ #header-site-info { width: auto; } #site-name-wrapper { float: left; /* LTR */ } #site-name, #slogan { display: block; } #site-name a:link, #site-name a:visited, #site-name a:hover, #site-name a:active { text-decoration: none; } #site-name a { outline: 0; } /* Regions -------------------------------------------------------------- */ /* Header Regions -------------------------------------------------------------- */ #header-group { overflow: visible; } /* Content Regions (Main) -------------------------------------------------------------- */ .node-bottom { margin: 1.5em 0 0 0; } /* Clear floats on regions -------------------------------------------------------------- */ #header-top-wrapper, #header-group-wrapper, #preface-top-wrapper, #main-wrapper, #preface-bottom, #content-top, #content-region, #content-bottom, #postscript-top, #postscript-bottom-wrapper, #footer-wrapper, #footer-message-wrapper { clear: both; } /* Drupal Core /-------------------------------------------------------------- */ /* Lists /-------------------------------------------------------------- */ .item-list ul li { margin: 0; } .block ul, .block ol { margin-left: 2em; /* LTR */ padding: 0; } .content-inner ul, .content-inner ol { margin-bottom: 1.5em; } .content-inner li ul, .content-inner li ol { margin-bottom: 0; } .block ul.links { margin-left: 0; /* LTR */ } /* Menus /-------------------------------------------------------------- */ ul.menu li, ul.links li { margin: 0; padding: 0; } /* Primary Menu /-------------------------------------------------------------- */ /* use ID to override overflow: hidden for .block, dropdowns should always be visible */ #primary-menu { overflow: visible; } /* remove left margin from primary menu list */ #primary-menu.block ul { margin-left: 0; /* LTR */ } /* remove bullets, float left */ .primary-menu ul li { float: left; /* LTR */ list-style: none; position: relative; } /* style links, and unlinked parent items (via Special Menu Items module) */ .primary-menu ul li a, .primary-menu ul li .nolink { display: block; padding: 0.75em 1em; text-decoration: none; } /* Add cursor style for unlinked parent menu items */ .primary-menu ul li .nolink { cursor: default; } /* remove outline */ .primary-menu ul li:hover, .primary-menu ul li.sfHover, .primary-menu ul a:focus, .primary-menu ul a:hover, .primary-menu ul a:active { outline: 0; } /* Secondary Menu /-------------------------------------------------------------- */ .secondary-menu-inner ul.links { margin-left: 0; /* LTR */ } /* Skinr styles /-------------------------------------------------------------- */ /* Skinr selectable helper classes */ .fusion-clear { clear: both; } div.fusion-right { float: right; /* LTR */ } div.fusion-center { float: none; margin-left: auto; margin-right: auto; } .fusion-center-content .inner { text-align: center; } .fusion-center-content .inner ul.menu { display: inline-block; text-align: center; } /* required to override drupal core */ .fusion-center-content #user-login-form { text-align: center; } .fusion-right-content .inner { text-align: right; /* LTR */ } /* required to override drupal core */ .fusion-right-content #user-login-form { text-align: right; /* LTR */ } /* Large, bold callout text style */ .fusion-callout .inner { font-weight: bold; } /* Extra padding on block */ .fusion-padding .inner { padding: 30px; } /* Adds 1px border and padding */ .fusion-border .inner { border-width: 1px; border-style: solid; padding: 10px; } /* Single line menu with separators */ .fusion-inline-menu .inner ul.menu { margin-left: 0; /* LTR */ } .fusion-inline-menu .inner ul.menu li { border-right-style: solid; border-right-width: 1px; display: inline; margin: 0; padding: 0; white-space: nowrap; } .fusion-inline-menu .inner ul.menu li a { padding: 0 8px 0 5px; /* LTR */ } .fusion-inline-menu .inner ul li.last { border: none; } /* Hide second level (and beyond) menu items */ .fusion-inline-menu .inner ul li.expanded ul { display: none; } /* Multi-column menu style with bolded top level menu items */ .fusion-multicol-menu .inner ul { margin-left: 0; /* LTR */ text-align: left; /* LTR */ } .fusion-multicol-menu .inner ul li { border-right: none; display: block; font-weight: bold; } .fusion-multicol-menu .inner ul li.last { border-right: none; } .fusion-multicol-menu .inner ul li.last a { padding-right: 0; /* LTR */ } .fusion-multicol-menu .inner ul li.expanded, .fusion-multicol-menu .inner ul li.leaf { float: left; /* LTR */ list-style-image: none; margin-left: 50px; /* LTR */ } .fusion-multicol-menu .inner ul.menu li.first { margin-left: 0; /* LTR */ } .fusion-multicol-menu .inner ul li.expanded li.leaf { float: none; margin-left: 0; /* LTR */ } .fusion-multicol-menu .inner ul li.expanded ul { display: block; margin-left: 0; /* LTR */ } .fusion-multicol-menu .inner ul li.expanded ul li { border: none; margin-left: 0; /* LTR */ text-align: left; /* LTR */ } .fusion-multicol-menu .inner ul.menu li ul.menu li { font-weight: normal; } /* Split list across multiple columns */ .fusion-2-col-list .inner .item-list ul li, .fusion-2-col-list .inner ul.menu li { float: left; /* LTR */ width: 50%; } .fusion-3-col-list .inner .item-list ul li, .fusion-3-col-list .inner ul.menu li { float: left; /* LTR */ width: 33%; } .fusion-2-col-list .inner .item-list ul.pager li, .fusion-3-col-list .inner .item-list ul.pager li { float: none; width: auto; } /* List with bottom border Fixes a common issue when list items have bottom borders and appear to be doubled when nested lists end and begin. This removes the extra border-bottom */ .fusion-list-bottom-border .inner ul li { list-style: none; list-style-type: none; list-style-image: none; } .fusion-list-bottom-border .inner ul li, .fusion-list-bottom-border .view-content div.views-row { padding: 0 0 0 10px; /* LTR */ border-bottom-style: solid; border-bottom-width: 1px; line-height: 216.7%; /* 26px */ } .fusion-list-bottom-border .inner ul { margin: 0; } .fusion-list-bottom-border .inner ul li ul { border-bottom-style: solid; border-bottom-width: 1px; } .fusion-list-bottom-border .inner ul li ul li.last { border-bottom-style: solid; border-bottom-width: 1px; margin-bottom: -1px; margin-top: -1px; } #views_slideshow_singleframe_pager_slideshow-page_2 .pager-item { display:block; } #views_slideshow_singleframe_pager_slideshow-page_2 { position:absolute; right:0; top:0; } #header-group-wrapper { background: none; } #page { background-color:#F3F3F3; background-image:url('/sites/all/themes/fusion/fusion_core/images/runswithgradient.jpg'); background-repeat:no-repeat; background-attachment: fixed; width: auto; } #views_slideshow_singleframe_pager_slideshow-page_2 div a img { top:0px; height:60px; width:80px; padding-right:10px; padding-bottom:19px; } #mycontent{ width: 720px; } .product-body { -moz-border-radius: 4px 4px 4px 4px; margin: 0 0 20px; overflow: hidden; padding: 20px; background: none repeat scroll 0 0 #F7F7F7; border: 1px solid #000000; border-style:solid; border-width:thin; color:#000000; } #product-details { background: none repeat scroll 0 0 #F7F7F7 !important; border: 1px solid #000000 !important; color: #8E8E8E; } #logo { position: relative; top: 30px; /* 30 pixels from the top of the page */ left: 80px; /* 80 pixels from the left hand side */ z-index:1099; border: 1px solid red; /* So we can see what is happening */ } #breadcrumbs-inner { background: none; border-color: transparent; border-style: none; } #block-views-new_products-block_1{ height:200px; } /* List with no bullet and extra padding This is a common style for menus, which removes the bullet and adds more vertical padding for a simple list style */ .fusion-list-vertical-spacing .inner ul, .fusion-list-vertical-spacing div.views-row-first { margin-left: 0; margin-top: 10px; } .fusion-list-vertical-spacing .inner ul li, .fusion-list-vertical-spacing div.views-row { line-height: 133.3%; /* 16px/12px */ margin-bottom: 10px; padding: 0; } .fusion-list-vertical-spacing .inner ul li { list-style: none; list-style-image: none; list-style-type: none; } .fusion-list-vertical-spacing .inner ul li ul { margin-left: 10px; /* LTR */ } /* Bold all links */ .fusion-bold-links .inner a { font-weight: bold; } /* Float imagefield images left and add margin */ .fusion-float-imagefield-left .field-type-filefield, .fusion-float-imagefield-left .image-insert, .fusion-float-imagefield-left .imagecache { float: left; /* LTR */ margin: 0 15px 15px 0; /* LTR */ } /* Clear float on new Views item so each row drops to a new line */ .fusion-float-imagefield-left .views-row { clear: left; /* LTR */ } /* Float imagefield images right and add margin */ .fusion-float-imagefield-right .field-type-filefield, .fusion-float-imagefield-right .image-insert .fusion-float-imagefield-right .imagecache { float: right; /* LTR */ margin: 0 0 15px 15px; /* LTR */ } /* Clear float on new Views item so each row drops to a new line */ .fusion-float-imagefield-right .views-row { clear: right; /* LTR */ } /* Superfish: all menus */ .sf-menu li { list-style: none; list-style-image: none; list-style-type: none; } /* Superfish: vertical menus */ .superfish-vertical { position: relative; z-index: 9; } ul.sf-vertical { background: #fafafa; margin: 0; width: 100%; } ul.sf-vertical li { border-bottom: 1px solid #ccc; font-weight: bold; line-height: 200%; /* 24px */ padding: 0; width: 100%; } ul.sf-vertical li a:link, ul.sf-vertical li a:visited, ul.sf-vertical li .nolink { margin-left: 10px; padding: 2px; } ul.sf-vertical li a:hover, ul.sf-vertical li a.active { text-decoration: underline; } ul.sf-vertical li ul { background: #fafafa; border-top: 1px solid #ccc; margin-left: 0; width: 150px; } ul.sf-vertical li ul li.last { border-top: 1px solid #ccc; margin-bottom: -1px; margin-top: -1px; } ul.sf-vertical li ul { border-top: none; padding: 4px 0; } ul.sf-vertical li ul li { border-bottom: none; line-height: 150%; /* 24px */ More below but I can't paste that much Thanks for the suggestion I've tried this #header-group { position: relative; z-index: 9; } #logo { position: abosolute; top: 230px; /* 30 pixels from the top of the page */ left: 10px; /* 80 pixels from the left hand side */ z-index: 999; } but it's not working. I've taken a screen shot of the div to show the structure. http://i.stack.imgur.com/ff4DP.png

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  • embedding LEFT OUTER JOIN within INNER JOIN

    - by user3424954
    I am having some problems with one of the question's answered in the book "SQL FOR MERE MORTALS". Here is the problem statement Here is the Database Structure Here is the answer which I am unable to comprehend Here is an answer which looks perfect to me Now the problem with the first answer I am having is: We first use LEFT OUTER JOIN for recipe class and recipes. So it selects all recipe class rows but only matching recipes. Perfecty fine as the question is demanding. Lets call this result set R. Now in the next step when we use INNER JOIN to join RecipieIngridients, it should filter out the rows from R in which Recipie ID doesn't match with the Recipe Id in Recipie Ingredients and hence filtering out the related Recipe class and recipe description also(Since it filters out the entire row of R). So this contradicts with the problem which demands all recipieID and RecipieDescription to be displayed from Recipe_Classes Table in this very step only. How can it be correct. Or Am i Missing some concept.

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  • outer join for parent child chain

    - by dotnetcoder
    Considering below tables and relationships: parent --1:Many-- children --1:Many-- shubchildren Parent may or many not have children records. children always have subchildren records. I wan to write a qiery to select parent names where any if matched parent.name,children.name or subchildren.name Here i understand I have to do a left outer join between parent and children. But what kind of join should I put between children and subchildren ?

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  • Basic join query understanding

    - by OM The Eternity
    I know this very silly, but can anybody help me in understanding what does this join query is doing in elabortive description? SELECT j1.* FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON (j1.trackid = j2.trackid AND j1.field = j2.field AND j1.changedone < j2.changedone) WHERE j1.operation = 'UPDATE' AND j1.trackid=$t_ids[$n] AND j2.id IS NULL I know its very silly, but i need to go ahead with my further need... Pls do help me...

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  • Nhibernate Left Outer Join Return First Record of the Join

    - by Touch
    I have the following mappings of which Im trying to bring back 0 - 1 Media Id associated with a Product using a left join (I havnt included my attempt as it confuses the situation) ICriteria productCriteria = Session.CreateCriteria(typeof(Product)); productCriteria .CreateAlias("ProductCategories", "pc", JoinType.InnerJoin) .CreateAlias("pc.ParentCategory", "category") .CreateAlias("category.ParentCategory", "group") .Add(Restrictions.Eq("group.Id", 333)) .SetProjection( Projections.Distinct( Projections.ProjectionList() .Add(Projections.Alias(Projections.Property("Id"), "Id")) .Add(Projections.Alias(Projections.Property("Title"), "Title")) .Add(Projections.Alias(Projections.Property("Price"), "Price")) .Add(Projections.Alias(Projections.Property("media.Id"), "SearchResultMediaId")) // I NEED THIS ) ) .SetResultTransformer(Transformers.AliasToBean<Product>()); IList<Product> products = productCriteria .SetFirstResult(0) .SetMaxResults(10) .List<Product>(); I need the query to populate the SearchResultMediaId with Media.Id, I only want to bring back the first Media in a left outer join, as this is 1 to many association between Product and Media Product is mapped to Media in the following way mapping.HasManyToMany<Media>(x => x.Medias) .Table("ProductMedias") .ParentKeyColumn("ProductId") .ChildKeyColumn("MediaId") .Cascade.AllDeleteOrphan() .LazyLoad() .AsBag(); Any Help would be fantastic.

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  • LINQ, Left Join, Only Get where null in join table

    - by kmehta
    Hi. I am trying to do a left outer join on two tables, but I only want to return the results from the first table where the second table does not have a record (null). var agencies = from a in agencyList join aa in joinTable on a.AgencyId equals aa.AgencyId into joined from aa in joined.DefaultIfEmpty() where aa == null) select a; But this does not exclude the non null values of aa, and returns all the records just the same as if the 'where aa == null' was not there. Any help is appreciated. Thanks.

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  • Unable to log in to ubuntu server 10.04 after trying to join windows domain

    - by nash
    I was trying to join our ubuntu 10.04 server to the windows domain and I ended up editing the pam.d configuration files. My aim was to have domain users log into the ubuntu server with their domain accounts in order to access some applications instead of creating new unix users each time. My system admin says the join was successful to the domain. Now I have no way of logging into the sever. Is there a way I can undo everything and get the server back to the original login using the local account? I will also appreciate if someone pointed me to some configuration that actually worked - I am still willing to try and make it work.

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  • How to JOIN a COUNT from a table, and then effect that COUNT with another JOIN

    - by jakenoble
    Hi I have three tables Post ID Name 1 'Something' 2 'Something else' 3 'One more' Comment ID PostId ProfileID Comment 1 1 1 'Hi my name is' 2 2 2 'I like cakes' 3 3 3 'I hate cakes' Profile ID Approved 1 1 2 0 3 1 I want to count the comments for a post where the profile for the comment is approved I can select the data from Post and then join a count from Comment fine. But this count should be dependent on if the Profile is approved or not. The results I am expecting is CommentCount PostId Count 1 1 2 0 3 1 Thanks for any help.

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  • SQL Join query help

    - by lostInTransit
    Hi I have 2 tables A and B with the following columns Table A - id,bId,aName,aVal Table B - id,bName where A.bId is the same as B.id. I want a result set from a query to get A.id, A.aName, B.bName where A.bId=B.id OR A.id, A.aName, "" when A.bId=0. In both cases, only those records should be considered where A.aVal LIKE "aVal" Can someone please help me with the query? I can use left join but how do I get the blank string if bId=0 and B.bName otherwise? Thanks

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  • Join using combined conditions on one join table

    - by Nathan Wienert
    I have join a table joining songs to genres. The table has a 'source' column that's used to identify where the genre was found. Genres are found from blogs, artists, tags, and posts. So, songs | song_genre | genres id | song_id, source, genre_id | id What I want to build is a song SELECT query that works something like this, given I already have a genre_id: IF exists song_genre with source='artist' AND a song_genre with source='blog' OR exists song_genre with source='artist' AND a song_genre with source='post' OR exists song_genre with source='tag' I'm was going to do it by doing a bunch of joins, but am sure I'm not doing it very well. Using Postgres 9.1.

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  • Mysql JOIN problem

    - by FinalDestiny
    I have 2 mysql tables : Question with the following columns : id, question, nranswers Nranswers must be a number from 1 to 5 And the other table is Answers with the following columns: userid, answer . Now the problem is that I want to get the replies for each answer for one question(id 22 let's say) . P.S. If the nranswers is 3, the result should look like this: (the right number means how many times the reply number was chosen) 1 - 2 2 - 8 3 - 7 If the nranswers is 5, the result should look like this: 1 - 3 2 - 8 3 - 14 4 - 19 5 - 8 Please help me out with the query, atm he's not counting the answers that weren't chosen, only the ones that were chosen at least one time.

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  • Can MySQL / SQL's short hand of "Using" be used without saying "Inner Join" ?

    - by Jian Lin
    The following 2 statements are to join using gifts.giftID = sentgifts.giftID: mysql> select * from gifts, sentgifts using (giftID); ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'using (giftID)' at line 1 and the second one: mysql> select * from gifts INNER JOIN sentgifts using (giftID); +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ | giftID | name | filename | effectiveTime | sentID | whenSent | fromID | toID | trytryWhen | +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | +--------+------------+----------------+---------------------+--------+------------+--------+------+---------------------+ 4 rows in set (0.00 sec) Can the first statement also use the "using" shorthand? It seems that when it is used then the word "Inner Join" must be specified... but the first statement is actually an inner join?

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  • MS SQL 2008, join or no join?

    - by Patrick
    Just a small question regarding joins. I have a table with around 30 fields and i was thinking about making a second table to store 10 of those fields. Then i would just join them in with the main data. The 10 fields that i was planning to store in a second table does not get queried directly, it's just some settings for the data in the first table. Something like: Table 1 Id Data1 Data2 Data3 etc ... Table 2 Id (same id as table one) Settings1 Settings2 Settings3 Is this a bad solution? Should i just use 1 table? How much performance inpact does it have? All entries in table 1 would also then have an entry in table 2. Small update is in order. Most of the Data fields are of the type varchar and 2 of them are of the type text. How is indexing treated? My plan is to index 2 data fields, email (varchar 50) and author (varchar 20). And yes, all records in Table 1 will have a record in Table 2. Most of the settings fields are of the bit type, around 80%. The rest is a mix between int and varchar. The varchars can be null.

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  • SQL Server 2008, join or no join?

    - by Patrick
    Just a small question regarding joins. I have a table with around 30 fields and i was thinking about making a second table to store 10 of those fields. Then i would just join them in with the main data. The 10 fields that i was planning to store in a second table does not get queried directly, it's just some settings for the data in the first table. Something like: Table 1 Id Data1 Data2 Data3 etc ... Table 2 Id (same id as table one) Settings1 Settings2 Settings3 Is this a bad solution? Should i just use 1 table? How much performance inpact does it have? All entries in table 1 would also then have an entry in table 2. Small update is in order. Most of the Data fields are of the type varchar and 2 of them are of the type text. How is indexing treated? My plan is to index 2 data fields, email (varchar 50) and author (varchar 20). And yes, all records in Table 1 will have a record in Table 2. Most of the settings fields are of the bit type, around 80%. The rest is a mix between int and varchar. The varchars can be null.

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  • Basics of Join Factorization

    - by Hong Su
    We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

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  • How sql server evaluates the multiple different joins?

    - by ziang
    Hi, i have a general question about how sql server evaluates the joins.The query is SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id Q1: What tables is the left join based on? I know it will based on the TABLEC but what is the other one? Is it the result of the first inner join or the TABLEB specified in the left join condition? Q2: Is "LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id" equivalent to "LEFT JOIN TABLEC ON TABLEB.id = TABLEC.id" Q3: Is the query equivalent to the following one? (with TABLEB.id replaced by TABLEA.id?) SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEA.id Thank you!

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  • In SQL, can we always write an inner join statement as a main query and subquery if we only want to

    - by Jian Lin
    In SQL, can we always write an inner join statement as a main query and subquery or vice versa if we only want to find the intersection? For example, select * from gifts g where g.giftID in (select giftID from sentGifts); can do a join and show the gifts sent in the sentGifts table, but it won't be able to show the sentTime because that is inside the subquery. But if all we care is to find the intersection, without caring what is being displayed, then we can always convert one to the other?

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  • query for inner join of table 4.

    - by amol kadam
    hi.... I'm facing the problem of inner join of table 4 following is query given plz see & give me solution select INSURED.FNAME + ' ' + INSURED.LNAME AS MNAME ,INSURED.MEMBCODE as MEMBERCODE ,INSURED.POLICYNO AS POLICYNO ,INSURED.POLICYFRMDATE AS POLICYFROMDATE ,INSURED.POLICYTODATE AS POLICYTODATE , MEMBERSHIP.MRKEXTNAME AS MARKETINGEXECUTIVE ,MEMBERSHIP.EMPLOYEECOUNT AS EMPLOYEECOUNT ,INSURED.CLAIMID AS CLAIMID ,POLICY.POLICYTYPE ,POLICY.COVAMTHOSPITAL as SUMINSURED ,ORGANIZATION.ORGANIZATIONNAME from ((INSURED inner join MEMBERSHIP on MEMBERSHIP.MEMBERSHIPID=INSURED.MEMBERSHIPID) inner join POLICY on MEMBERSHIP.POLICYNAME=POLICY.POLICYNAME) inner join ORGANIZATION on ORGANIZATION.ORGANIZATIONID=MEMBERSHIP.ORGANIZATIONID WHERE INSUREDID=427

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