Search Results

Search found 2368 results on 95 pages for 'jeff smith'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 2/95 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • VBA/SQL recordsets

    - by intruesiive
    The project I'm asking about is for sending an email to teachers asking what books they're using for the classes they're teaching next semester, so that the books can be ordered. I have a query that compares the course number of this upcoming semester's classes to the course numbers of historical textbook orders, pulling out only those classes that are being taught this semester. That's where I get lost. I have a table that contains the following: -Professor -Course Number -Year -Book -Title The data looks like this: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 12 1111 Pride and Prejudice smith 11 1222 Infinite Jest smith 10 1333 The Bible smith 13 1333 The Bible smith 12 1222 The Alchemist smith 10 1111 Moby Dick johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 10 1333 Everything is Illuminated johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time johnson 10 1333 Great Expectations johnson 9 1222 Proust on the Shore Here's what I need the code to do "on paper": Group the records by professor. Determine every unique course number in that group, and group records by course number. For each unique course number, determine the highest year associated. Then spit out every record with that professor+course number+year combination. With the sample data, the results would be: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 13 1333 The Bible johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time I'm thinking I should make a record set for each teacher, and within that, another record set for each course number. Within the course number record set, I need the system to determine what the highest year number is - maybe store that in a variable? Then pull out every associated record so that if the teacher ordered 3 books the last time they taught that class (whether it was in 2013 or 2012 and so on) all three books display. I'm not sure I'm thinking of record sets in the right way, though. My SQL so far is basic and clearly doesn't work: SELECT [All].Professor, [All].Course, Max([All].Year) FROM [All] GROUP BY [All].Professor, [All].Course; Thanks for your help.

    Read the article

  • SQL: Add counters in select

    - by etarvt
    Hi, I have a table which contains names: Name ---- John Smith John Smith Sam Wood George Wright John Smith Sam Wood I want to create a select statement which shows this: Name 'John Smith 1' 'John Smith 2' 'Sam Wood 1' 'George Wright 1' 'John Smith 3' 'Sam Wood 2' In other words, I want to add separate counters to each name. Is there a way to do it without using cursors?

    Read the article

  • Why are marketing employees, product managers, etc. deserving of their own office, yet programmers are jammed in a room as many as possible?

    - by TheImirOfGroofunkistan
    I don't understand why many (many) companies treat software developers like they are assembly line workers making widgets. Joel Spolsky has a great example of the problems this creates: With programmers, it's especially hard. Productivity depends on being able to juggle a lot of little details in short term memory all at once. Any kind of interruption can cause these details to come crashing down. When you resume work, you can't remember any of the details (like local variable names you were using, or where you were up to in implementing that search algorithm) and you have to keep looking these things up, which slows you down a lot until you get back up to speed. Here's the simple algebra. Let's say (as the evidence seems to suggest) that if we interrupt a programmer, even for a minute, we're really blowing away 15 minutes of productivity. For this example, lets put two programmers, Jeff and Mutt, in open cubicles next to each other in a standard Dilbert veal-fattening farm. Mutt can't remember the name of the Unicode version of the strcpy function. He could look it up, which takes 30 seconds, or he could ask Jeff, which takes 15 seconds. Since he's sitting right next to Jeff, he asks Jeff. Jeff gets distracted and loses 15 minutes of productivity (to save Mutt 15 seconds). Now let's move them into separate offices with walls and doors. Now when Mutt can't remember the name of that function, he could look it up, which still takes 30 seconds, or he could ask Jeff, which now takes 45 seconds and involves standing up (not an easy task given the average physical fitness of programmers!). So he looks it up. So now Mutt loses 30 seconds of productivity, but we save 15 minutes for Jeff. Ahhh! Quote Link More Spolsky on Offices Why don't managers and owner's see this?

    Read the article

  • Why do marketing employees get their own office, yet programmers are jammed in a room as many as possible?

    - by TheImirOfGroofunkistan
    I don't understand why many (many) companies treat software developers like they are assembly line workers making widgets. Joel Spolsky has a great example of the problems this creates: With programmers, it's especially hard. Productivity depends on being able to juggle a lot of little details in short term memory all at once. Any kind of interruption can cause these details to come crashing down. When you resume work, you can't remember any of the details (like local variable names you were using, or where you were up to in implementing that search algorithm) and you have to keep looking these things up, which slows you down a lot until you get back up to speed. Here's the simple algebra. Let's say (as the evidence seems to suggest) that if we interrupt a programmer, even for a minute, we're really blowing away 15 minutes of productivity. For this example, lets put two programmers, Jeff and Mutt, in open cubicles next to each other in a standard Dilbert veal-fattening farm. Mutt can't remember the name of the Unicode version of the strcpy function. He could look it up, which takes 30 seconds, or he could ask Jeff, which takes 15 seconds. Since he's sitting right next to Jeff, he asks Jeff. Jeff gets distracted and loses 15 minutes of productivity (to save Mutt 15 seconds). Now let's move them into separate offices with walls and doors. Now when Mutt can't remember the name of that function, he could look it up, which still takes 30 seconds, or he could ask Jeff, which now takes 45 seconds and involves standing up (not an easy task given the average physical fitness of programmers!). So he looks it up. So now Mutt loses 30 seconds of productivity, but we save 15 minutes for Jeff. Ahhh! Quote Link More Spolsky on Offices Why don't managers and owner's see this?

    Read the article

  • How can I transfer files to a Kindle Fire with a Micro-USB cable?

    - by Jeff
    I'm running Ubuntu 11.10, and when I connect my Kindle Fire to my computer via micro usb, it is not recognized automatically. Other usb devices, such as my ipod and digital camera, are recognized just fine. It does not appear to be a usb power issue, since the Kindle Fire wakes up from sleeping when it is plugged in. I never get the message on the Kindle telling me it is ready to accept files from the computer, though. Here are the last 15 lines of dmesg after plugging the kindle in: jeff@prime:~$ dmesg | tail -n 15 [45918.269671] ieee80211 phy0: wl_ops_bss_info_changed: arp filtering: enabled true, count 1 (implement) [45929.072149] wlan0: no IPv6 routers present [46743.224217] usb 1-1: new high speed USB device number 5 using ehci_hcd [46743.364623] scsi8 : usb-storage 1-1:1.0 [46744.366102] scsi 8:0:0:0: Direct-Access Amazon Kindle 0001 PQ: 0 ANSI: 2 [46744.366356] scsi: killing requests for dead queue [46744.372494] scsi: killing requests for dead queue [46744.384510] scsi: killing requests for dead queue [46744.392348] scsi: killing requests for dead queue [46744.392731] scsi: killing requests for dead queue [46744.396853] scsi: killing requests for dead queue [46744.397214] scsi: killing requests for dead queue [46744.400795] scsi: killing requests for dead queue [46744.401589] sd 8:0:0:0: Attached scsi generic sg2 type 0 [46744.407520] sd 8:0:0:0: [sdb] Attached SCSI removable disk And here are my mounted filesystems: jeff@prime:~$ df Filesystem 1K-blocks Used Available Use% Mounted on /dev/sda1 298594984 174663712 108763480 62% / udev 1407684 4 1407680 1% /dev tmpfs 566924 896 566028 1% /run none 5120 0 5120 0% /run/lock none 1417308 300 1417008 1% /run/shm /home/jeff/.Private 298594984 174663712 108763480 62% /home/jeff I should note that, since I got Dropbox working on my Kindle, the usb is no longer strictly necessary, but as a matter of principle I'd love to get it working.

    Read the article

  • How are views constructed in Josh Smith's MVVM sample?

    - by Wim Coenen
    Being new to both WPF and MVVM, I'm studying Josh Smith's article on the MVVM pattern and the accompanying sample code. I can see that the application is started in app.xaml.cs by constructing a MainWindow object, wiring it to a MainWindowViewModel object and then showing the main window. So far so good. However, I can't find any code which instantiates the AllCustomersView or CustomerView classes. Using "find all references" on the constructors of those views comes up with nothing. What am I missing here?

    Read the article

  • 9 New BizTalk Wencasts in the Light & Easy Series

    - by Alan Smith
    During the MVP summit in February I managed to catch up with a few of the BizTalk MVPs who had recorded new webcasts for the “BizTalk Light & Easy” series. The 9 new webcasts are online now at CloudCasts. ·         BizTalk 2010 and Windows Azure – Paul Somers ·         BizTalk and AppFabric Cache Part 1 – Mike Stephenson ·         BizTalk and AppFabric Cache Part 2 – Mike Stephenson ·         Integration to SharePoint 2010 Part 1 – Mick Badran ·         Integration to SharePoint 2010 Part 2 – Mick Badran ·         Better BizTalk Testing by Taking Advantage of the CAT Logging Framework – Mike Stephenson ·         Calling Business Rules from a .NET Application – Alan Smith ·         Tracking Rules Execution in a .NET Application – Alan Smith ·         Publishing a Business Rules Policy as a Service – Alan Smith The link is here. Big thanks to Paul, Mike and Mick for putting the time in. “BizTalk Light & Easy” is an ongoing project, if you are feeling creative and would like to contribute feel free to contact me via this blog. I can email you some tips on webcasting and the best formats to use.

    Read the article

  • Podcast Show Notes: Evolving Enterprise Architecture

    - by Bob Rhubart
    Back in March Oracle ACE Directors Mike van Alst (IT-Eye) and Jordan Braunstein (Visual Integrator Consulting) and Oracle product manager Jeff Davies participated in an ArchBeat virtual meet-up. The resulting conversation quickly turned to the changing nature of enterprise architecture and the various forces driving that change. All four parts of that wide-ranging conversation are now available. Listen to Part 1 Listen to Part 2 Listen to Part 3 Listen to Part 4 As you’ll hear, Mike, Jordan, and Jeff bring unique perspectives and opinions to this very lively conversation. These are three very sharp, very experienced guys, as and you might expect, they don’t always walk in lock-step when it comes to EA. You can learn more about Mike, Jordan, and Jeff – and share your opinions with them -- through the links below: Mike van Alst Blog | Twitter | LinkedIn | Business |Oracle Mix | Oracle ACE Profile Jordan Braunstein Blog | Twitter | LinkedIn | Business | Oracle Mix | Oracle ACE Profile Jeff Davies Homepage | Blog | LinkedIn | Oracle Mix (Also check out Jeff’s book: The Definitive Guide to SOA: Oracle Service Bus) Up Next Next week’s program features highlights from the panel discussion at the Oracle Technology Architect Day event held in Anaheim, CA on May 19. You’ll hear from Oracle ACE Directors Basheer Khan and Floyd Teter, Oracle virtualization expert and former Sun Microsystems principal engineer Jeff Savit, Oracle security analyst Geri Born, and event MC Ralf Dossman, Director of SOA and Middleware in Oracle’s Enterprise Solutions Group. Stay tuned: RSS

    Read the article

  • SEO impact on subdomain for full name and obscure ccTLD

    - by Dan Christian
    There have been a few questions on subdomains and their impact on SEO, mostly in comparison to subfolders. The closest question I've found is this question but it still doesn't completely answer my query. I'm setting up a blog for 'Sam Smith'. It's imperative the SEO is based around his full name as he is a prominent blogger and his name is his value. All ccTLD variations of 'samsmith' (samsmith.com, samsmith.cc etc) are taken. However there has been the opportunity to register an obscure ccTLD for 'smith'. In regards to SEO value purely from the URL... 1) Will there be any negative SEO implications on searches for 'Sam Smith' when setting up the subdomain as 'sam.smith.' compared to a more regular 'samsmith.' domain? Will a search engine recognise the subdomain as the full name as oppose to just 'smith'? 2) Are there any negative SEO implications with an obscure ccTLD. For instance if Sam Smith was a prominent blogger in Canada with most of his audience based there, would there be any negative SEO if he had, for example, a .co ccTLD.

    Read the article

  • SQL SERVER – Service Broker and CAP_CPU_PERCENT – Limiting SQL Server Instances to CPU Usage

    - by pinaldave
    I have mentioned several times on this blog that the best part of blogging is the questions I receive from readers. They are often very interesting. The questions from readers give me a good idea what other readers might be thinking as well. After reading my earlier article Simple Example to Configure Resource Governor – Introduction to Resource Governor – I received an email from a reader and we exchanged a few emails. After exchanging emails we both figured out what is going on. It was indeed interesting and reader suggested to that I should blog about it.  I asked for permission to publish his name but he does not like the attention so we will just call him Jeff. I have converted our emails into chat for easy consumption. Jeff: Your script does not work at all. I think either there is a bug in SQL Server. Pinal: Would you please explain in detail? Jeff: Your code does not limit the CPU usage? Pinal: How did you measure it? Jeff: Well, we have third party tools for it but let us say I have limited the resources for Reporting Services and used your script described in your blog. After that I ran only reporting service workload the CPU is still used more than 100% and it is not limited to 30% as described in your script. Clearly something is wrong somewhere. Pinal: Did you say you ONLY ran reporting server load? Jeff: Yeah, to validate I ran ONLY reporting server load and CPU did not throttle at 30% as per your script. Pinal: Oh! I get it here is the answer - CAP_CPU_PERCENT = 30. Use it. Jeff: What is that, I think your earlier script says it will throttle the Reporting Service workload and Application/OLTP workload and balance it. Pinal: Exactly, that is correct. Jeff: You need to write more in email buddy! Just like your blogs, your answers do not make sense! No Offense! Pinal: Hmm…feedback well taken. Let me try again. In SQL Server 2012 there are a few enhancements with regards to SQL Server Resource Governor. One of the enhancement is how the resources are allocated. Let me explain you with examples. Configuration: [Read Earlier Post] Reporting Workload: MIN_CPU_PERCENT=0, MAX_CPU_PERCENT=30 Application/OLTP Workload: MIN_CPU_PERCENT=50, MAX_CPU_PERCENT=100 Example 1: If there is only Reporting Workload on the server: SQL Server will not limit usage of CPU to only 30% workload but SQL Server instance will use all available CPU (if needed). In another word in this scenario it will use more than 30% CPU. Example 2: If there is Reproting Workload and heavy Application/OLTP workload: SQL Server will allocate a maximum of 30% CPU resources to Reporting Workload and allocate remaining resources to heavy application/OLTP workload. The reason for this enhancement is for better utilization of the resources. Let us think, if there is only single workload, which we have limited to max CPU usage to 30%. The other unused available CPU resources is now wasted. In this situation SQL Server allows the workload to use more than 30% resources leading to overall improved/optimized performance. However, in the case of multiple workload where lots of resources are needed the limits specified in MAX_CPU_PERCENT are acknowledged. Example 3: If there is a situation where the max CPU workload has to be enforced: This is a very interesting scenario, in the case when the max CPU workload has to be enforced irrespective of the workload and enhanced algorithm, the keyword CAP_CPU_PERCENT is essential. It specifies a hard cap on the CPU bandwidth that all requests in the resource pool will receive. It will never let CPU usage for reporting workload to go over 30% in our case. You can use the key word as follows: -- Creating Resource Pool for Report Server CREATE RESOURCE POOL ReportServerPool WITH ( MIN_CPU_PERCENT=0, MAX_CPU_PERCENT=30, CAP_CPU_PERCENT=40, MIN_MEMORY_PERCENT=0, MAX_MEMORY_PERCENT=30) GO Notice that there is MAX_CPU_PERCENT=30 and CAP_CPU_PERCENT=40, what it means is that when SQL Server Instance is under heavy load under different workload it will use the maximum CPU at 30%. However, when the SQL Server instance is not under workload it will go over the 30% limit. However, as CAP_CPU_PERCENT is set to 40, it will not go over 40% in any case by limiting the usage of CPU. CAP_CPU_PERCENT puts a hard limit on the resources usage by workload. Jeff: Nice Pinal, you should blog about it. [A day passes by] Pinal: Jeff, it is done! Click here to read it. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: Service Broker

    Read the article

  • Filter rows on the basis of "First Name" + "Last Name" in SQL

    - by Raghav Khunger
    Hi, I have a user table in my database which contains two columns FirstName and LastName. Now in my front end there is a textbox to filter out the users from this table. Let's suppose I am taking that input from the front end in the form of a input parameter "@SEARCHKEYWORD". I have created a sample below: DECLARE @Test TABLE ([ID] INT IDENTITY, [FNAME] NVARCHAR(100), [LNAME] NVARCHAR(100) ) INSERT INTO @Test( FNAME, LNAME ) SELECT 'John','Resig' UNION ALL SELECT 'Dave','Ward' UNION ALL SELECT 'Peter','Smith' UNION ALL SELECT 'Dave','Smith' UNION ALL SELECT 'Girija','Acharya' UNION ALL SELECT 'Devendra', 'Gujel' UNION ALL SELECT 'Arjit', 'Gupta' DECLARE @SEARCHKEYWORD NVARCHAR(100) SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD i.e. so far I have thought of this query to filter out the rows but it is not giving the desired results: SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD Here are the desired outputs which I needed for the inputs mentioned below: --WHEN @SEARCHKEYWORD='John Resig' --Desired OUTPUT: the row which contains 'John','Resig' --WHEN @SEARCHKEYWORD='Ac' --Desired OUTPUT: the row which contains 'Girija','Acharya' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith' --WHEN @SEARCHKEYWORD='g' --Desired OUTPUT: the row which contains 'Devendra', 'Gujel' and 'Arjit', 'Gupta' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith'

    Read the article

  • Excel VBA Text To Column

    - by Pat
    This is what I currently have: H101 John Doe Jane Doe Jack Doe H102 John Smith Jane Smith Katie Smith Jack Smith And here is what I want: H101 John Doe H101 Jane Doe H101 Jack Doe H102 John Smith H102 Jane Smith H102 Katie Smith H102 Jack Smith Obviously I want to do this on a bigger scale. The number of columns is between 1 & 6, so I cant limit it that way. I was able to get a script that allows me to put each individual on one row. However, I am having a hard time getting the first column to copy over to each row. Sub ToOneColumn() Dim i As Long, k As Long, j As Integer Application.ScreenUpdating = False Columns(2).Insert i = 0 k = 1 While Not IsEmpty(Cells(k, 3)) j = 3 While Not IsEmpty(Cells(k, j)) i = i + 1 Cells(i, 1) = Cells(k, 1) //CODE IN QUESTION Cells(i, 2) = Cells(k, j) Cells(k, j).Clear j = j + 1 Wend k = k + 1 Wend Application.ScreenUpdating = True End Sub Like I said, it was working fine to get everyone each on their own row, but can't figure out how to get that first column. It seems like it should be so simple, but it's bugging me. Any help is greatly appreciated.

    Read the article

  • Completely remove user account and create another with same name in Windows 7

    - by TeaJay
    Here's my question simply and then the details in case they help to get me an appropriate answer. Question: How can I completely and permanently delete a user account in Windows 7 so that I can create another one with the same user name without the computer name extension added, eg Jane Smith not Jane Smith.computer name? The details: I just did a clean install of Windows 7 Professional 32 bit. (My laptop crashed, I reinstalled Vista and restored backup files but things weren't working so I decided to just get Windows 7 since I had to start over anyway). I used Windows Easy Transfer to save just about everything, even customizing to include a user's appdata from Windows.old which was created when I reinstalled Vista -- not knowing that another windows.old file would be created with the installation of Windows 7. After installing Windows 7, I used Windows Easy Transfer to transfer the user file, appdata, to the new user account which I gave the same name (Jane Smith) in case having a different name would cause problems with reading files or something. Afterwards, I realized that I did not want ALL of that junk. So, I thought no problem, I'll just delete the user account I just created, nothing lost, and create another one this time transferring only the files I wanted (using the customize option in windows easy transfer). I wanted to keep the same user name, e.g. Jane Smith, so after I deleted the user account I checked the files, and I didn't see. It was late so I went to bed and the next morning I created a new user with that same name (Jane Smith). The files looked fine if I remember correctly. Meanwhile, I updated the computer and it restarted a couple times. As I was moving files to the "Jane Smith" user account file, things weren't working as they should. I was actually moving files to the deleted user account and that the current user account was named "Jane Smith.computer name" and that's where the files needed to go. I don't like this. It's too confusing. I want just "Jane Smith". How can I do this without just changing the user name (which doesn't change it in the file path etc)? I want the first one GONE. If I can't do this, is it a problem to create an account with another name and still transfer files to it without path or other problems? I hope this question makes sense and that someone can help me. Thank you in advance!

    Read the article

  • hierachical query to return final row

    - by jeff
    I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

    Read the article

  • Help using left outer joins in SQL...

    - by Waffles
    I'm trying to create a list of people, their friends, and their friends of friends. My table of people is this: People: NAME Jow Smith Sandy Phil Friends LIKER LIKEE jow smith smith jow sandy phil Now, what I want is a table like this: User Friend FriendofFriend Jow smith jow Smith jow smith sandy phil phil I'm trying to create a table using the following: SELECT P.NAME, F.LIKEE, F2.LIKEE FROM PEOPLE P LEFT OUTER JOIN FRIENDS F ON P.NAME = F.LIKER LEFT OUTER JOIN FRIENDS F2 ON F.LIKEE = F2.LIKER But the above isn't working. How can I get a table of people and their friends, regardless of whether or not they actually HAVE any friends?

    Read the article

  • Podcast Show Notes: Evolving Enterprise Architecture

    - by Bob Rhubart
    The latest series of ArchBeat podcast programs grew out of another virtual meet-up, held on March 11. As with previous meet-ups, I sent out a general invitation to the roster of previous ArchBeat panelists to join me on Skype to talk about whatever topic comes up. For this event, Oracle ACE Directors Mike van Alst and Jordan Braunstein  showed up, along with Oracle product manager Jeff Davies.  The result was an impressive and wide-ranging discussion on the evolution of Enterprise Architecture, the role of technology in EA, the impact of social computing, and challenge of having three generations of IT people at work in the enterprise – each with different perspectives on technology. Mike, Jordan, and Jeff talked for more than an hour, and the conversation was so good that slicing and dicing it to meet the time constraints for these podcasts has been a challenge. The first two segments of the conversation are now available. Listen to Part 1 Listen to Part 2 Part 3 will go live next week, and an unprecedented fourth segment will follow. These guys have strong opinions, and while there is common ground, they don’t always agree. But isn’t that what a community is all about? I suspect that you’ll have questions and comments after listening, so I encourage you to reach out to Mike, Jordan, and Jeff  via the following links: Mike van Alst Blog | Twitter | LinkedIn | Business |Oracle Mix | Oracle ACE Profile Jordan Braunstein Blog | Twitter | LinkedIn | Business | Oracle Mix | Oracle ACE Profile Jeff Davies Homepage | Blog | LinkedIn | Oracle Mix (Also check out Jeff’s book: The Definitive Guide to SOA: Oracle Service Bus)   Coming Soon ArchBeat’s microphones were there for the panel discussions at the recent Oracle Technology Network Architect Days in Dallas and Anaheim. Excerpts from those conversations will be available soon. Stay tuned: RSS Technorati Tags: oracle,otn,enterprise architecture,podcast. arch2arch,archbeat del.icio.us Tags: oracle,otn,enterprise architecture,podcast. arch2arch,archbeat

    Read the article

  • A Nondeterministic Engine written in VB.NET 2010

    - by neil chen
    When I'm reading SICP (Structure and Interpretation of Computer Programs) recently, I'm very interested in the concept of an "Nondeterministic Algorithm". According to wikipedia:  In computer science, a nondeterministic algorithm is an algorithm with one or more choice points where multiple different continuations are possible, without any specification of which one will be taken. For example, here is an puzzle came from the SICP: Baker, Cooper, Fletcher, Miller, and Smith live on different floors of an apartment housethat contains only five floors. Baker does not live on the top floor. Cooper does not live onthe bottom floor. Fletcher does not live on either the top or the bottom floor. Miller lives ona higher floor than does Cooper. Smith does not live on a floor adjacent to Fletcher's.Fletcher does not live on a floor adjacent to Cooper's. Where does everyone live? After reading this I decided to build a simple nondeterministic calculation engine with .NET. The rough idea is that we can use an iterator to track each set of possible values of the parameters, and then we implement some logic inside the engine to automate the statemachine, so that we can try one combination of the values, then test it, and then move to the next. We also used a backtracking algorithm to go back when we are running out of choices at some point. Following is the core code of the engine itself: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Public Class NonDeterministicEngine Private _paramDict As New List(Of Tuple(Of String, IEnumerator)) 'Private _predicateDict As New List(Of Tuple(Of Func(Of Object, Boolean), IEnumerable(Of String))) Private _predicateDict As New List(Of Tuple(Of Object, IList(Of String))) Public Sub AddParam(ByVal name As String, ByVal values As IEnumerable) _paramDict.Add(New Tuple(Of String, IEnumerator)(name, values.GetEnumerator())) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(1, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(2, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(3, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(4, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(5, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(6, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(7, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(8, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Sub CheckParamCount(ByVal count As Integer, ByVal paramNames As IList(Of String)) If paramNames.Count <> count Then Throw New Exception("Parameter count does not match.") End If End Sub Public Property IterationOver As Boolean Private _firstTime As Boolean = True Public ReadOnly Property Current As Dictionary(Of String, Object) Get If IterationOver Then Return Nothing Else Dim _nextResult = New Dictionary(Of String, Object) For Each item In _paramDict Dim iter = item.Item2 _nextResult.Add(item.Item1, iter.Current) Next Return _nextResult End If End Get End Property Function MoveNext() As Boolean If IterationOver Then Return False End If If _firstTime Then For Each item In _paramDict Dim iter = item.Item2 iter.MoveNext() Next _firstTime = False Return True Else Dim canMoveNext = False Dim iterIndex = _paramDict.Count - 1 canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then Return True End If Do While Not canMoveNext iterIndex = iterIndex - 1 If iterIndex = -1 Then Return False IterationOver = True End If canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then For i = iterIndex + 1 To _paramDict.Count - 1 Dim iter = _paramDict(i).Item2 iter.Reset() iter.MoveNext() Next Return True End If Loop End If End Function Function GetNextResult() As Dictionary(Of String, Object) While MoveNext() Dim result = Current If Satisfy(result) Then Return result End If End While Return Nothing End Function Function Satisfy(ByVal result As Dictionary(Of String, Object)) As Boolean For Each item In _predicateDict Dim pred = item.Item1 Select Case item.Item2.Count Case 1 Dim p1 = DirectCast(pred, Func(Of Object, Boolean)) Dim v1 = result(item.Item2(0)) If Not p1(v1) Then Return False End If Case 2 Dim p2 = DirectCast(pred, Func(Of Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) If Not p2(v1, v2) Then Return False End If Case 3 Dim p3 = DirectCast(pred, Func(Of Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) If Not p3(v1, v2, v3) Then Return False End If Case 4 Dim p4 = DirectCast(pred, Func(Of Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) If Not p4(v1, v2, v3, v4) Then Return False End If Case 5 Dim p5 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) If Not p5(v1, v2, v3, v4, v5) Then Return False End If Case 6 Dim p6 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) If Not p6(v1, v2, v3, v4, v5, v6) Then Return False End If Case 7 Dim p7 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) If Not p7(v1, v2, v3, v4, v5, v6, v7) Then Return False End If Case 8 Dim p8 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) Dim v8 = result(item.Item2(7)) If Not p8(v1, v2, v3, v4, v5, v6, v7, v8) Then Return False End If Case Else Throw New NotSupportedException End Select Next Return True End FunctionEnd Class    And now we can use the engine to solve the problem we mentioned above:   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test2() Dim engine = New NonDeterministicEngine() engine.AddParam("baker", {1, 2, 3, 4, 5}) engine.AddParam("cooper", {1, 2, 3, 4, 5}) engine.AddParam("fletcher", {1, 2, 3, 4, 5}) engine.AddParam("miller", {1, 2, 3, 4, 5}) engine.AddParam("smith", {1, 2, 3, 4, 5}) engine.AddRequire(Function(baker) As Boolean Return baker <> 5 End Function, {"baker"}) engine.AddRequire(Function(cooper) As Boolean Return cooper <> 1 End Function, {"cooper"}) engine.AddRequire(Function(fletcher) As Boolean Return fletcher <> 1 And fletcher <> 5 End Function, {"fletcher"}) engine.AddRequire(Function(miller, cooper) As Boolean 'Return miller = cooper + 1 Return miller > cooper End Function, {"miller", "cooper"}) engine.AddRequire(Function(smith, fletcher) As Boolean Return smith <> fletcher + 1 And smith <> fletcher - 1 End Function, {"smith", "fletcher"}) engine.AddRequire(Function(fletcher, cooper) As Boolean Return fletcher <> cooper + 1 And fletcher <> cooper - 1 End Function, {"fletcher", "cooper"}) engine.AddRequire(Function(a, b, c, d, e) As Boolean Return a <> b And a <> c And a <> d And a <> e And b <> c And b <> d And b <> e And c <> d And c <> e And d <> e End Function, {"baker", "cooper", "fletcher", "miller", "smith"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine(String.Format("baker: {0}, cooper: {1}, fletcher: {2}, miller: {3}, smith: {4}", result("baker"), result("cooper"), result("fletcher"), result("miller"), result("smith"))) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub   Also, this engine can solve the classic 8 queens puzzle and find out all 92 results for me.   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test3() ' The 8-Queens problem. Dim engine = New NonDeterministicEngine() ' Let's assume that a - h represents the queens in row 1 to 8, then we just need to find out the column number for each of them. engine.AddParam("a", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("b", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("c", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("d", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("e", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("f", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("g", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("h", {1, 2, 3, 4, 5, 6, 7, 8}) Dim NotInTheSameDiagonalLine = Function(cols As IList) As Boolean For i = 0 To cols.Count - 2 For j = i + 1 To cols.Count - 1 If j - i = Math.Abs(cols(j) - cols(i)) Then Return False End If Next Next Return True End Function engine.AddRequire(Function(a, b, c, d, e, f, g, h) As Boolean Return a <> b AndAlso a <> c AndAlso a <> d AndAlso a <> e AndAlso a <> f AndAlso a <> g AndAlso a <> h AndAlso b <> c AndAlso b <> d AndAlso b <> e AndAlso b <> f AndAlso b <> g AndAlso b <> h AndAlso c <> d AndAlso c <> e AndAlso c <> f AndAlso c <> g AndAlso c <> h AndAlso d <> e AndAlso d <> f AndAlso d <> g AndAlso d <> h AndAlso e <> f AndAlso e <> g AndAlso e <> h AndAlso f <> g AndAlso f <> h AndAlso g <> h AndAlso NotInTheSameDiagonalLine({a, b, c, d, e, f, g, h}) End Function, {"a", "b", "c", "d", "e", "f", "g", "h"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine("(1,{0}), (2,{1}), (3,{2}), (4,{3}), (5,{4}), (6,{5}), (7,{6}), (8,{7})", result("a"), result("b"), result("c"), result("d"), result("e"), result("f"), result("g"), result("h")) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub (Chinese version of the post: http://www.cnblogs.com/RChen/archive/2010/05/17/1737587.html) Cheers,  

    Read the article

  • Setup mod-rewrite

    - by Publiccert
    I'm trying to setup mod-rewrite for a few servers. The code lives in /home/jeff/www/upload/application/ However, this is what's happening. It appears to be a problem with mod-rewrite since it's appending code.py to the beginning of the directory: The requested URL /code.py/home/jeff/www/upload/application/ was not found on this server. Here are the rules. Which one is the culprit? WSGIScriptAlias / /home/jeff/www/upload/application Alias /static /home/jeff/www/upload/public_html <Directory /home/jeff/www/upload/application> SetHandler wsgi-script Options ExecCGI FollowSymLinks </Directory> AddType text/html .py <Location /> RewriteEngine on RewriteBase / RewriteCond %{REQUEST_URI} !^/static RewriteCond %{REQUEST_URI} !^(/.*)+code.py/ RewriteRule ^(.*)$ code.py/$1 [PT] </Location> </VirtualHost>

    Read the article

  • sudo: apache restarting a service on CentOS

    - by WaveyDavey
    I need my web app to restart the dansguardian service (on CentOS) so it needs to run '/sbin/service dansguardian restart' I have a shellscript in /home/topological called apacherestart.sh which does the following: #!/bin/sh id=`id` /sbin/service dansguardian restart r=$? return $r This runs ok (logger statement in script for testing output to syslog, so I know it's running) To make it run, I put this in /etc/sudoers: User_Alias APACHE=www # Cmnd alias specification Cmnd_Alias HTTPRESTART=/home/topological/apacherestart.sh,/sbin/e-smith/db,/etc/rc7.d/S91dansguardian # Defaults specification # User privilege specification root ALL=(ALL) ALL APACHE ALL=(ALL) NOPASSWD: HTTPRESTART So far so good. But the service does not restart. To test this I created a user david, and fudged the uid/gid in /etc/passwd to be the same as www: www:x:102:102:e-smith web server:/home/e-smith:/bin/false david:x:102:102:David:/home/e-smith/files/users/david:/bin/bash then logged in as david and tried to run the apacherestart.sh. The problem I get is: /etc/rc7.d/S91dansguardian: line 51: /sbin/e-smith/db: Permission denied even though S91dansguardian and db are in the sudoers command list. Any ideas?

    Read the article

  • Multiple 301 redirect and massive loss of ranking

    - by DoesNotCompute
    I just remade from scratch a website for a client, the client ask me to preverve their ranking by making 301 redirect from the original URL to the new URL. For instance: http://plumber-directory.my-website.com/john-smith-city-1.php became http://directory.my-website.com/plumber/city/john-smith.html So i put the website online for few days until the 301 partially kicks in the google results. Then the client call me back to tell me that his boss want to switch back to the ancients URLs _< So i put a new 301 redirect: http://directory.my-website.com/plumber/city/john-smith.html revert to http://plumber-directory.my-website.com/john-smith-city-1.php Because google had just few days to assimilate the new URLs, it have now the two kinds of URLs in it's own result pages. Also the ranking of the website keeps falling down every day, i suspect google to mistaking those redirects for duplicate content. Is there something i can do to avoid a total loss of rankings?

    Read the article

  • Oracle presentations at the CIPS ICE Conference, November 5 - 7, Edmonton, Alberta, Canada

    - by Darin Pendergraft
    Oracle will be presenting at the CIPS ICE conference the last week of October in Calgary and the first week of November in Edmonton. Here is a list of the presentations for Edmonton: SHAW Conference Centre • Session Title: Identity and Access Management Integrated; Analyzing the Platform vs Point Solution Approach • Speaker: Darin Pendergraft • Monday, November 5th @ 10:45 AM - 12:00 PM • Session Title: Is Your IT Security Strategy Putting Your Institution at Risk? • Speaker: Spiros Angelopoulos • Monday, November 5th @ 1:45 PM - 3:00 PM Three sessions under the TRAIN: Practical Knowledge Track • Monday, November 5th @ 10:45 AM, 1:45 PM, 3:30 PM • Title: What's new in the Java Platform   Presenter: Donald Smith • Title: Java Enterprise Edition 6   Presenter: Shaun Smith • Title: The Road Ahead for Java SE, JavaFX and Java EE    Presenters: Donald Smith and Shaun Smith To learn more about the conference, and to see the other sessions go to the conference website.

    Read the article

  • First steps into css - aligning data insite one DIV [on hold]

    - by Andrew
    I am trying to move away from tables, and start doing CSS. Here is my HTML code that I currently trying to place into a nice looking container. <div> <div> <h2>ID: 4000 | SSN#: 4545</h2> </div> <div> <img src="./images/tenant/unknown.png"> </div> <div> <h3>Names Used</h3> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> </div> <div> <h3>Phones Used</h3> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> </div> <div> <h3>Addresses Used</h3> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> </div> </div> I now understand now I create classes and assign classes to elements. I have no issues doing colors. But I am very confused with elements alignments. Could you suggest a nice way to pack it together with some CSS which I can analyze and take as a CSS starting learning point?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >