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  • ManyToMany Relation does not create the primary key

    - by Javi
    Hello, I have a ManyToMany relationship between two classes: ClassA and ClassB, but when the table for this relationship (table called objectA_objectB) there is no primary key on it. In my ClassA I have the following: @ManyToMany(fetch=FetchType.LAZY) @OrderBy(value="name") @JoinTable(name="objectA_objectB", joinColumns= @JoinColumn(name="idObjectA", referencedColumnName="id"), inverseJoinColumns= @JoinColumn(name="idObjectB", referencedColumnName="id") ) private List<ClassB> objectsB; and in my ClassB I have the reversed relation @ManyToMany List<ClassA> objectsA; I just want to make a primary key of both id's but I need to change the name of the columns as I do. Why is the PK missing? How can I define it? I use JPA 2.0 Hibernate implementation, if this helps. Thanks.

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  • Hibernate triggering constraint violations using orphanRemoval

    - by ptomli
    I'm having trouble with a JPA/Hibernate (3.5.3) setup, where I have an entity, an "Account" class, which has a list of child entities, "Contact" instances. I'm trying to be able to add/remove instances of Contact into a List<Contact> property of Account. Adding a new instance into the set and calling saveOrUpdate(account) persists everything lovely. If I then choose to remove the contact from the list and again call saveOrUpdate, the SQL Hibernate seems to produce involves setting the account_id column to null, which violates a database constraint. What am I doing wrong? The code below is clearly a simplified abstract but I think it covers the problem as I'm seeing the same results in different code, which really is about this simple. SQL: CREATE TABLE account ( INT account_id ); CREATE TABLE contact ( INT contact_id, INT account_id REFERENCES account (account_id) ); Java: @Entity class Account { @Id @Column public Long id; @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true) @JoinColumn(name = "account_id") public List<Contact> contacts; } @Entity class Contact { @Id @Column public Long id; @ManyToOne(optional = false) @JoinColumn(name = "account_id", nullable = false) public Account account; } Account account = new Account(); Contact contact = new Contact(); account.contacts.add(contact); saveOrUpdate(account); // some time later, like another servlet request.... account.contacts.remove(contact); saveOrUpdate(account); Result: UPDATE contact SET account_id = null WHERE contact_id = ? Edit #1: It might be that this is actually a bug http://opensource.atlassian.com/projects/hibernate/browse/HHH-5091

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  • What's a good 2nd level cache for JEE applications?

    - by Hank
    Can anyone recommend a good 2nd level object caching solution for JEE 6 applications, and give background to your recommendation? I'm using JPA 2.0 as persistence provider. I am particularly worried about having to run the cache client as a single-thread / singleton bean. Is that the case? If so, is that an issue? I've good experience using memcached from a PHP webapp, but PHP is of course single-threaded, so that was never an issue...

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  • Seam 2.x and Hibernate 3.5?

    - by user331747
    Does anyone know if Hibernate 3.5 is supported under Seam 2.x (specifically 2.2.x)? I'm very interested in some of the JPA 2 features, particularly query building, but work within the Seam framework. Is this version of the library supported? Thanks in advance!

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  • Programmatically loading Entity classes with JPA 2.0?

    - by Dennetik
    With Hibernate you can load your Entity classes as: sessionFactory = new AnnotationConfiguration() .addPackage("test.animals") .addAnnotatedClass(Flight.class) .addAnnotatedClass(Sky.class) .addAnnotatedClass(Person.class) .addAnnotatedClass(Dog.class); Is there a way to do the same thing - programmatically loading your Entity classes - in a JPA 2.0 compliant way?

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  • JPA Inheritance and Relations - Clarification question

    - by Michael
    Here the scenario: I have a unidirectional 1:N Relation from Person Entity to Address Entity. And a bidirectional 1:N Relation from User Entity to Vehicle Entity. Here is the Address class: @Entity public class Address implements Serializable { private static final long serialVersionUID = 1L; @Id @GeneratedValue(strategy = GenerationType.AUTO) privat Long int ... The Vehicles Class: @Entity public class Vehicle implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne private User owner; ... @PreRemove protected void preRemove() { //this.owner.removeVehicle(this); } public Vehicle(User owner) { this.owner = owner; ... The Person Class: @Entity @Inheritance(strategy = InheritanceType.JOINED) @DiscriminatorColumn(name="PERSON_TYP") public class Person implements Serializable { @Id protected String username; @OneToMany(cascade = CascadeType.ALL, orphanRemoval=true) @JoinTable(name = "USER_ADDRESS", joinColumns = @JoinColumn(name = "USERNAME"), inverseJoinColumns = @JoinColumn(name = "ADDRESS_ID")) protected List<Address> addresses; ... @PreRemove protected void prePersonRemove(){ this.addresses = null; } ... The User Class which is inherited from the Person class: @Entity @Table(name = "Users") @DiscriminatorValue("USER") public class User extends Person { @OneToMany(mappedBy = "owner", cascade = {CascadeType.PERSIST, CascadeType.REMOVE}) private List<Vehicle> vehicles; ... When I try to delete a User who has an address I have to use orphanremoval=true on the corresponding relation (see above) and the preRemove function where the address List is set to null. Otherwise (no orphanremoval and adress list not set to null) a foreign key contraint fails. When i try to delete a user who has an vehicle a concurrent Acces Exception is thrown when do not uncomment the "this.owner.removeVehicle(this);" in the preRemove Function of the vehicle. The thing i do not understand is that before i used this inheritance there was only a User class which had all relations: @Entity @Table(name = "Users") public class User implements Serializable { @Id protected String username; @OneToMany(mappedBy = "owner", cascade = {CascadeType.PERSIST, CascadeType.REMOVE}) private List<Vehicle> vehicles; @OneToMany(cascade = CascadeType.ALL) @JoinTable(name = "USER_ADDRESS", joinColumns = @JoinColumn(name = "USERNAME") inverseJoinColumns = @JoinColumn(name = "ADDRESS_ID")) ptivate List<Address> addresses; ... No orphanremoval, and the vehicle class has used the uncommented statement above in its preRemove function. And - I could delte a user who has an address and i could delte a user who has a vehicle. So why doesn't everything work without changes when i use inheritance? I use JPA 2.0, EclipseLink 2.0.2, MySQL 5.1.x and Netbeans 6.8

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  • Does the JPQL avg aggregate function work with Integers?

    - by Kyle Renfro
    I have a JPA 2 Entity named Surgery. It has a member named transfusionUnits that is an Integer. There are two entries in the database. Executing this JPQL statement: Select s.transfusionUnits from Surgery s produces the expected result: 2 3 The following statement produces the expected answer of 5: Select sum(s.transfusionUnits) from Surgery s I expect the answer of the following statement to be 2.5, but it returns 2.0 instead. Select avg(s.transfusionUnits) from Surgery s If I execute the statement on a different (Float) member, the result is correct. Any ideas on why this is happening? Do I need to do some sort of cast in JPQL? Is this even possible? Surely I am missing something trivial here.

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  • How to handle choice field with JPA 2, Hibernate 3.5

    - by phmr
    I have an entity with Integer attributes that looks like this in proto code: class MyEntity: String name Integer frequency Integer type def getFrequency() def getType() get* accessors return strings according to this table. value(type) HumanReadableString(type) 1 BSD 2 Apache 3 GPL min frequency max frequency HumanReadableString(frequency) 0 1000 rare 1000 2000 frequent 2001 3000 sexy It should be possible to get all possible values that an attribute can take, example: getChoices(MyEntity, "type") returns ("rare", "frequent", "sexy") It should be possible to get the bound value from the string: getValue(MyEntity, "frequency", "sexy") returns (2000,3000)

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  • JPA 2.0 @OrderColumn annotation in Hibernate 3.5

    - by peperg
    I'm trynig to use @OrderColumn annotation with Hibernate 3.5 @OneToMany(mappedBy = "parent",fetch=FetchType.EAGER, cascade=CascadeType.ALL) @OrderColumn(name = "pos") private List<Children> childrenCollection; When retrieving data everyting works fine. But I can't make it to reorded elements in List and save new order to database.

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  • Is this possible: JPA/Hibernate query with list property in result ?

    - by Kdeveloper
    In hibernate I want to run this JPQL / HQL query: select new org.test.userDTO( u.id, u.name, u.securityRoles) FROM User u WHERE u.name = :name userDTO class: public class UserDTO { private Integer id; private String name; private List<SecurityRole> securityRoles; public UserDTO(Integer id, String name, List<SecurityRole> securityRoles) { this.id = id; this.name = name; this.securityRoles = securityRoles; } ...getters and setters... } User Entity: @Entity public class User { @id private Integer id; private String name; @ManyToMany @JoinTable(name = "user_has_role", joinColumns = { @JoinColumn(name = "user_id") }, inverseJoinColumns = {@JoinColumn(name = "security_role_id") } ) private List<SecurityRole> securityRoles; ...getters and setters... } But when Hibernate 3.5 (JPA 2) starts I get this error: org.hibernate.hql.ast.QuerySyntaxException: Unable to locate appropriate constructor on class [org.test.UserDTO] [SELECT NEW org.test.UserDTO (u.id, u.name, u.securityRoles) FROM nl.test.User u WHERE u.name = :name ] Is a select that includes a list as a result not possible? Should I just create 2 seperate queries?

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  • JPA entitylisteners and @embeddable

    - by seanizer
    I have a class hierarchy of JPA entities that all inherit from a BaseEntity class: @MappedSuperclass @EntityListeners( { ValidatorListener.class }) public abstract class BaseEntity implements Serializable { // other stuff } I want all entities that implement a given interface to be validated automatically on persist and/or update. Here's what I've got. My ValidatorListener: public class ValidatorListener { private enum Type { PERSIST, UPDATE } @PrePersist public void checkPersist(final Object entity) { if (entity instanceof Validateable) { this.check((Validateable) entity, Type.PERSIST); } } @PreUpdate public void checkUpdate(final Object entity) { if (entity instanceof Validateable) { this.check((Validateable) entity, Type.UPDATE); } } private void check(final Validateable entity, final Type persist) { switch (persist) { case PERSIST: if (entity instanceof Persist) { ((Persist) entity).persist(); } if (entity instanceof PersistOrUpdate) { ((PersistOrUpdate) entity).persistOrUpdate(); } break; case UPDATE: if (entity instanceof Update) { ((Update) entity).update(); } if (entity instanceof PersistOrUpdate) { ((PersistOrUpdate) entity).persistOrUpdate(); } break; default: break; } } } and here's my Validateable interface that it checks against (the outer interface is just a marker, the inner contain the methods): public interface Validateable { interface Persist extends Validateable { void persist(); } interface PersistOrUpdate extends Validateable { void persistOrUpdate(); } interface Update extends Validateable { void update(); } } All of this works, however I would like to extend this behavior to Embeddable classes. I know two solutions: call the validation method of the embeddable object manually from the entity validation method: public void persistOrUpdate(){ // validate my own properties first // then manually validate the embeddable property: myEmbeddable.persistOrUpdate(); // this works but I'd like something that I don't have to call manually } use reflection, checking all properties to see if their type is of one of their interface types. This would work, but it's not pretty. Is there a more elegant solution?

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  • How to generate JPA 2.0 metamodel?

    - by yamsha
    In the spirit of type safety associated with the CriteriaQuery JPA 2.0 also has an API to support Metamodel representation of entities. Is anyone aware of a fully functional implementation of this API (to generate the Metamodel... as opposed to creating the metamodel classes manually)? It would be awesome if someone also knows the steps for setting this up in Eclipse (I assume it's as simple as setting up an annotation processor, but you never know). EDIT: Just stumbled across Hibernate JPA 2 Metamodel Generator . But the issue remains since I can't find any download links for the jar

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  • Why does Hibernate ignore the JPA2 standardized properties in my persistence.xml?

    - by Ophidian
    I have an extremely simple web application running in Tomcat using Spring 3.0.1, Hibernate 3.5.1, JPA 2, and Derby. I am defining all of my database connectivity in persistence.xml and merely using Spring for dependency injection. I am using embedded Derby as my database. Everything works correctly when I define the driver and url properties in persistence.xml in the classic Hibernate manner as thus: <property name="hibernate.connection.driver_class" value="org.apache.derby.jdbc.EmbeddedDriver"/> <property name="hibernate.connection.url" value="jdbc:derby:webdb;create=true"/> The problems occur when I switch my configuration to the JPA2 standardized properties as thus: <property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/> <property name="javax.persistence.jdbc.url" value="jdbc:derby:webdb;create=true"/> When using the JPA2 property keys, the application bails hard with the following exception: java.lang.UnsupportedOperationException: The user must supply a JDBC connection Does anyone know why this is failing? NOTE: I have copied the javax... property strings straight from the Hibernate reference documentation, so a typo is extremely unlikely.

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  • JTA or LOCAL transactions in JPA2+Hibernate 3.6.0?

    - by Pangea
    We are in the process of re-thinking our tech stack and below are our choices (We can't live without Spring and Hibernate due to the complexity etc of the app). We are also moving from J2EE 1.4 to JEE 5. Tech stack JEE 5 JPA 2.0 (I know JEE 5 only supports JPA 1.0 but we want to use Hibernate as the JPA provider) Hibernate 3.6.0 (We already have lots of hbm files with custom types etc. so we doesn't want to migrate them at this time to JPA. This means we want both jpa/hbm mappings work together and hence the Hibernate as the JPA provider instead of using the default that comes with App Server) Now the problems is that I want to stick with local transactions but other team members want to use JTA. I have been working with J2EE for last 9 years and I've heard time and again people suggesting to stick with local transactions if I doesn't need two phase commits. This is not only for performance reasons but debugging/troubleshooting a local transaction is lot easier than a distributed transaction. My suggestion is to use spring declarative transaction management + local transactions (HibernateTransactionManager) I want to make sure if I am being paranoid or I have a valid point. I'd like to hear what the rest of the JEE world thinks. Thank you.

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  • how openjpa2.0 enhances entities at runtime?

    - by Digambar Daund
    Below is my test code: package jee.jpa2; import java.util.List; import javax.persistence.EntityManager; import javax.persistence.EntityManagerFactory; import javax.persistence.EntityTransaction; import javax.persistence.Persistence; import javax.persistence.Query; import org.testng.annotations.BeforeClass; import org.testng.annotations.Test; @Test public class Tester { EntityManager em; EntityTransaction tx; EntityManagerFactory emf; @BeforeClass public void setup() { emf = Persistence.createEntityManagerFactory("basicPU", System.getProperties()); } @Test public void insert() { Item item = new Item(); for (int i = 0; i < 1000; ++i) { em = emf.createEntityManager(); tx = em.getTransaction(); tx.begin(); item.setId(null); em.persist(item); tx.commit(); em.clear(); em.close(); tx=null; em=null; } } @Test public void read() { em = emf.createEntityManager(); tx = em.getTransaction(); tx.begin(); Query findAll = em.createNamedQuery("findAll"); List<Item> all = findAll.getResultList(); for (Item item : all) { System.out.println(item); } tx.commit(); } } And here is the entity: package jee.jpa2; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.NamedQuery; @Entity @NamedQuery(name="findAll", query="SELECT i FROM Item i") public class Item { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ID", nullable = false, updatable= false) protected Long id; protected String name; public Item() { name = "Digambar"; } public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } @Override public String toString() { return String.format("Item [id=%s, name=%s]", id, name); } } After executing test I get Error: Item [id=1, name=Digambar] Item [id=2, name=Digambar] PASSED: read FAILED: insert <openjpa-2.0.0-r422266:935683 nonfatal store error> org.apache.openjpa.persistence.EntityExistsException: Attempt to persist detached object "jee.jpa2.Item-2". If this is a new instance, make sure any version and/or auto-generated primary key fields are null/default when persisting. FailedObject: jee.jpa2.Item-2 at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2563) at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2423) at org.apache.openjpa.kernel.DelegatingBroker.persist(DelegatingBroker.java:1069) at org.apache.openjpa.persistence.EntityManagerImpl.persist(EntityManagerImpl.java:705) at jee.jpa2.Tester.insert(Tester.java:33) Please Explain whats happening here?

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  • Tab Sweep: Primefaces3, @DataSourceDefinition, JPA Extensions, EclipseLink, Typed Query, Ajax, ...

    - by arungupta
    Recent Tips and News on Java, Java EE 6, GlassFish & more : • JSF2 + Primefaces3 + EJB3 & JPA2 Integration Project (@henk53) • The state of @DataSourceDefinition in Java EE (@henk53) • Java Persistence API (JPA) Extensions Reference for EclipseLink (EclipseLink) • JavaFX 2.2 Pie Chart with JPA 2.0 (John Yeary) • Typed Query RESTful Service Example (John Yeary) • How to set environment variables in GlassFish admin console (Jelastic) • Architect Enterprise Applications with Java EE (Oracle University) • Glassfish – Basic authentication (Marco Ghisellini) • Solving GlassFish 3.1/JSF PWC4011 warning (Rafael Nadal) • PrimeFaces AJAX Enabled (John Yeary)

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  • WebLogic Server???@??:12????????

    - by ???Y
    ??2012?12?14?(?)???31? WebLogic Server???@???????????????2012?WebLogic Server???????????Lightning Talks(+????????)??2????????????2012??WebLogic Server???????????????1???????????????????1????????WebLogic Server??????????????????????WLST?????????JMS?Flight Recorder????????JSF 2.0, EJB3.1, JPA2.0??????????????????????????????!???????????????????????????????????????????????????????????????Lightning Talks?????(+????????)??????????????????????????????????????????????????????????????12/14(?) ???????????????6?30????????????????????? 2012?12?14?(?) 18:30~20:40 (???? 18:00~) ?????????? ?107-0061 ????????2-5-8 ???????? ??? ???

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  • Upgrading in java web development

    - by Vladimir Ivanov
    I'm a java web developer for nearly 3 years. Always trying to learn more and be better but still I feel that the amount of knowledge is not that good as I want. The knowledge in some places still seems to be non-systematic and don't provide a very strong base to solve the problems as good as I want to do it. The example I have is my senior developer, whose solutions are always more efficient and beautiful. So, the question is rather simple and hard the same time. What is the right way to get my knowlege be more systematic and therefore improve it's quality. I understand that there is no practically good answer for the all java programming, so let's focus on the modern java web or nearly web technologies: JSF 2.0 JPA2 and Hibernate as persistence provider Web services and Java SE as a core. What methodologies or books or learning technics lead to the strong knowledge base within the given knowledge area?

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  • Get Ajax4JSF (a4j component) running on Glassfish

    - by yournamehere
    I'm trying to build an JEE6-application on Glassfish V3, using JSF 2.0, Weld, JPA2 and Maven. Now i'm having trouble getting a simple <a4j:support> running. This is the fragment of my little example. When typing something into the inputtext, the outputtext should automatically be updated. But nothing happens (not in Firefox, not in IE8). <ui:composition xmlns:a4j="https://ajax4jsf.dev.java.net/ajax" (...)> <h:inputText value="#{personHome.message}"> <a4j:support event="onkeyup" reRender="repeater"/> </h:inputText> <h:outputText id="repeater" value="#{personHome.message}"/> Beside that my example doesn't work, my problem is also that i don't really understand if i need a JSF implementation (MyFaces, Richfaces, Primefaces etc.) or not to use a4j elements. Is it "built-in" in glassfish? Until now, i only have the following dependencies i think i need in for JSF: <dependency> <groupId>com.sun.faces</groupId> <artifactId>jsf-api</artifactId> <version>2.0.2</version> </dependency> <dependency> <groupId>com.sun.faces</groupId> <artifactId>jsf-impl</artifactId> <version>2.0.2</version> </dependency>I'm trying to build an JEE6-application on Glassfish V3, using JSF 2.0, Weld, JPA2 and Maven. <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> <scope>provided</scope> </dependency> So... what do i have to do to get Ajax4JSF running on a simple JEE-App on Glassfish? Any help is highly appreciated!

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  • JPQL cross tab query

    - by Phil
    Hi can anyone tell me if its possible to write a cross tab query in JPQL? (I'm using eclipse link JPA2) An example of a cross tab query in SQL can found here http://onlamp.com/pub/a/onlamp/2003/12/04/crosstabs.html SELECT dept, COUNT(CASE WHEN gender = 'm' THEN id ELSE NULL END) AS m, COUNT(CASE WHEN gender = 'f' THEN id ELSE NULL END) AS f, COUNT(*) AS total FROM person GROUP BY dept How can I do the same thing as a single query in JPQL? Looking at the spec it doesn't seem to look like CASE is valid in COUNT Is there any other way?

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  • EJB3.1 Remote invocation - is it distributed automatically? is it expensive?

    - by Hank
    I'm building a JEE6 application with performance and scalability in the forefront of my mind. Business logic and JPA2-facade is held in stateless session beans (EJB3.1). As of right now, the SLSBs implement only @Remote-interfaces. When a bean needs to access another bean, it does so via RMI. My reasoning behind this is the assumption that, once the application runs on a bunch of clustered application servers, the RMI-part allows the execution to be distributed across the whole cluster automagically. Is that a correct assumption? I'm fine with dealing with the downsides of that (objects lose entityManager session, pass-by-value), at least I think so. But I am wondering if constant remote invocation isn't adding more load then necessary.

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  • What is the fastest way to learn JPA ?

    - by Jacques René Mesrine
    I'm looking for the best resources (books, frameworks, tutorials) that will help me get up to speed with JPA. I've been happily using iBatis/JDBC for my persistence needs, so I need resources that will hopefully provide comparable functions on how to do things. e.g. how to I set the isolation level for each transaction ? I know there might be 10 books on the topic, so hopefully, your recommendation could narrow down to the best 2 books. Should I start with OpenJPA or are there other opensource JPA frameworks to use ? P.S. Do suggest if I should learn JPA2 or JPA1 ? My goal ultimately is to be able to write a Google App Engine app (which uses JPA1). Thanks Jacque

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  • "Dynamic" java validation framework?

    - by pihentagy
    AFAIK JSR-303 is the standard bean validation system. I don't know whether it could do validations like this (I guess no): if an object has a deleted flag set, you cannot modify the object you cannot change the start date property, after the date is passed you cannot decrease some integer properties in the bean So how can I handle validations, which depend on the previous state of an object? I would like to solve problems like that in hibernate3.5 - spring3 - JPA2 environment. Thanks My solution was to mess with hibernate, reload the object to see the old state (after evicting the new object). This time I need some smarter solution...

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