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  • Use WatiN for automation upload file on the website

    - by MrDuDuDu
    I need upload file on the website. But Have a problem, i can't choose file automatic in code. Always browser show me choose file window. What wrong in my code? IE ie = new IE("https://www.xxxx.com/WFrmlogin.aspx"); FileUploadDialogHandler uploadHandler = new FileUploadDialogHandler(@"D:\065-6405_URGENT.xls"); ie.WaitForComplete(); ie.TextField(Find.ById("txtUser")).TypeText("login"); ie.TextField(Find.ById("txtPassWord")).TypeText("***"); ie.Button(Find.ById("btnok")).Click(); ie.WaitForComplete(); ie.GoTo("https://www.orientspareparts.com/inq/WFrmUpOption.aspx"); ie.WaitForComplete(); ie.DialogWatcher.Clear(); ie.AddDialogHandler(uploadHandler); // This code show choose file dialog ie.FileUpload(Find.ById("FilUpload")).ClickNoWait(); ie.Button(Find.ById("butUpload")).Click(); ie.WaitForComplete();

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  • Large file upload into WSS v3

    - by Rubens Farias
    I'd built an WSSv3 application which upload files in small chunks; when every data piece arrives, I temporarly keep it into a SQL 2005 image data type field for performance reasons**. Problem come when upload ends; I need to move data from my SQL Server to Sharepoint Document Library through WSSv3 object model. Right now, I can think two approaches: SPFileCollection.Add(string, (byte[])reader[0]); // OutOfMemoryException and SPFile file = folder.Files.Add("filename", new byte[]{ }); using(Stream stream = file.OpenBinaryStream()) { // ... init vars and stuff ... while ((bytes = reader.GetBytes(0, offset, buffer, 0, BUFFER_SIZE)) 0) { stream.Write(buffer, 0, (int)bytes); // Timeout issues } file.SaveBinary(stream); } Are there any other way to complete successfully this task? ** Performance reasons: if you tries to write every chunk directly at Sharepoint, you'll note a performance degradation as file grows up (100Mb).

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  • HTTP Upload Problems

    - by jfoster
    We are running a marketplace on ColdFusion8 and IIS with a widely geographically distributed user base and have been receiving complaints of issues with some HTTP uploads. Most of the complaints are coming from geographically distant locations from our main datacenter on the US east coast. I've attempted to upload the same 70MB file from a US West coast test server to both our main site and a backup running the same code on a different network route and I saw the same issues fairly consistently in both places, so I've ruled out the code, route, and internal network errors. I've also tested uploads using both the native cf upload tag and a third party tool called SaFileUp. I saw the same issues with both upload tools, so I also don't think this is necessarily a ColdFusion problem. I don't have any problems uploading the test file from the East coast to other east coast servers, so I'm beginning to think that the distance between our users and our equipment is a factor. I've also found that smaller files are more likely to succeed than large ones (< 10MB) I tried the test upload with both IE and FF and did notice a difference in the way that the browsers seemed to handle packet errors. IE seemed to have a tough time continuing an upload after dropped / bad packets, whereas FF seemed to have the ability to gracefully resume an upload after experiencing packet problems. Has anyone experienced similar issues? Is there anything we can do on our side to make uploads more forgiving to packet loss or resumable after an error? A different upload tool etc… Do we need upload servers in more than one location to shorten the network routes between clients and servers? Does anyone think that switching uploads to SSL will help (no layer7 packet sniffing may lead to a smoother upload). Thanks.

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  • Is it possible to upload only files that have been updated into a server?

    - by kamikaze_pilot
    Hi guys, Suppose I have a server accessible via FTP and it hosts websites Suppose I want to edit the website locally so it wont affect the site live, and suppose I edit a whole bunch of files, and I don't want to deal with the hassle of keeping track of which files I've edited all the time... Once I finished editing I want to upload it to the server via FTP....is there some FTP software that automatically detects which files have been edited and have only those files uploaded and overwritten rather than having me manually choosing the files I've edited (and hence having to keep track of edited files) or have me upload the entire site which is a waste of time thanks in advance

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  • How to queue up Windows 8 file coping to only have one copying at a time

    - by Valamas
    The new windows 8 file explorer copying is great. I can setup multiple copying tasks. They appear in a single window and I am able to pause them. Is there a way to have the copying only occur one at a time and when complete to progress the next one? Currently I have to setup the file copy and pause subsequent ones, then unpause the next one when I notice the current one finishes. I am only asking about a way to queue the file explorer coping and not use alternative tools like robocopy.

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  • File upload permission problem IIS 7

    - by krish
    I am unable to upload files to website hosted under IIS7. I have already given write permissions to "IUSR_websitename" and set the property in web.config also. I am able to upload files with out log in to application at the time of user registration. But once log in to application, if I upload files, it is giving "Access denied" error. Please help me.

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  • Good practices for large scale development/delivery of software

    - by centic
    What practices do you apply when working with large teams on multiple versions of a software or multiple competing projects? What are best practices that can be used to still get the right things done first? Is there information available how big IT companies do development and management of some of their large projects, e.g. things like Oracle Database, WebSphere Application Server, Microsoft Windows, ....?

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  • Calculate total batch upload transfer percent with limited information

    - by GONeale
    Hi there, I have a system which uploads to a server file by file and displays a progress bar on file upload progress, then underneath a second progress bar which I want to indicate percentage of batch complete across all files queued to upload. Information and algorithms I can work out are: Bytes Sent / Total Bytes To Send = First progress bar (eg. 512KB of 1024KB (50%)) That works fine. However supposing I have two other files left to upload, but both file sizes are unknown (as this is only known once the file is about to commence upload, at which point it is compressed and file size is determined) how would I go about making my third progress bar? I didn't think this would be possible as I would need "Total Bytes Sent" / "Total Bytes To Send", to replicate the logic of my first progress bar on a larger scale, however I did get a version working: "Current file number we are on" / "total number of files to send" returning the percentage through the batch, however obviously will not incrementally update and it's pretty crude. So on further thinking I thought if I could incorporate the current file % with this algorithm I could perhaps get the correct progress percentage of my batch's current point. I tried this algorithm, but alas to no such avail (sorry to any math heads, it's probably quite apparent why it won't work) ("Current file number we are on" / "total number of files to send") * ("Bytes Sent" / "Total Bytes To Send") For example I thought I was on the right track when testing with this example: 2/3 (2nd of 3rd file) = 66% (this is right so far) but then when I added * 0.20 (for indicating only 20% of 2nd file has uploaded) we went back to 13%. What I need is only a little over 33%! I did try the inverse at 0.80 and a (2/3 * (2/3 * 0.2)) Can this be done without knowing entire bytes in batch to upload? Please help! Thank you!

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  • PHP upload filename

    - by incrediman
    I'd like to have my PHP script upload a file with a certain filename in a directory of my choosing. However, the catch is that I need it to exist there immediately upon upload so I can moniter it on my server. I don't want to use a PHP extension or something - this should be very easy to transfer to any PHP setup. So basically: Is there a way to guarantee that, from the very beginning of the file upload process, the file has a certain name and location on the server?

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  • PHP Image Upload object won't create directory on windows

    - by ThinkingInBits
    I'm writing a class that excepts a product_id and a $_FILES array as it's constructor. The class saves these variables and uses them to create a new directory named by product_id and attempts to copy the temp file to my specified directory. For some reason my class isn't even getting as far as creating a directory (which should happen in the constructor) Here's a link to my code: http://pastie.org/955454

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  • HTML5 Drag n Drop File Upload

    - by Paris
    I'm running a website, where I'd like yo upload files with Drag 'n Drop, using HTML5's File Api and FileReader API. I have successfully managed to create a new FileReader, but I don't know how to upload the file. My code (javascript) is the following : holder = document.getElementById('uploader'); holder.ondragover = function () { $("#uploader").addClass('dragover'); return false; }; holder.ondragend = function () { $("#uploader").removeClass('dragover'); return false; }; holder.ondrop = function (e) { $("#uploader").removeClass('dragover'); e.preventDefault(); var file = e.dataTransfer.files[0], reader = new FileReader(); reader.onload = function (event) { //I shoud upload the file now... }; reader.readAsDataURL(file); return false; }; I also have a form (id : upload-form) and an input file field (id : upload-input). Do you have any ideas? P.S. I use jQuery, that's why there is $("#uploader") and others..

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  • How to simulate inner join on very large files in java (without running out of memory)

    - by Constantin
    I am trying to simulate SQL joins using java and very large text files (INNER, RIGHT OUTER and LEFT OUTER). The files have already been sorted using an external sort routine. The issue I have is I am trying to find the most efficient way to deal with the INNER join part of the algorithm. Right now I am using two Lists to store the lines that have the same key and iterate through the set of lines in the right file once for every line in the left file (provided the keys still match). In other words, the join key is not unique in each file so would need to account for the Cartesian product situations ... left_01, 1 left_02, 1 right_01, 1 right_02, 1 right_03, 1 left_01 joins to right_01 using key 1 left_01 joins to right_02 using key 1 left_01 joins to right_03 using key 1 left_02 joins to right_01 using key 1 left_02 joins to right_02 using key 1 left_02 joins to right_03 using key 1 My concern is one of memory. I will run out of memory if i use the approach below but still want the inner join part to work fairly quickly. What is the best approach to deal with the INNER join part keeping in mind that these files may potentially be huge public class Joiner { private void join(BufferedReader left, BufferedReader right, BufferedWriter output) throws Throwable { BufferedReader _left = left; BufferedReader _right = right; BufferedWriter _output = output; Record _leftRecord; Record _rightRecord; _leftRecord = read(_left); _rightRecord = read(_right); while( _leftRecord != null && _rightRecord != null ) { if( _leftRecord.getKey() < _rightRecord.getKey() ) { write(_output, _leftRecord, null); _leftRecord = read(_left); } else if( _leftRecord.getKey() > _rightRecord.getKey() ) { write(_output, null, _rightRecord); _rightRecord = read(_right); } else { List<Record> leftList = new ArrayList<Record>(); List<Record> rightList = new ArrayList<Record>(); _leftRecord = readRecords(leftList, _leftRecord, _left); _rightRecord = readRecords(rightList, _rightRecord, _right); for( Record equalKeyLeftRecord : leftList ){ for( Record equalKeyRightRecord : rightList ){ write(_output, equalKeyLeftRecord, equalKeyRightRecord); } } } } if( _leftRecord != null ) { write(_output, _leftRecord, null); _leftRecord = read(_left); while(_leftRecord != null) { write(_output, _leftRecord, null); _leftRecord = read(_left); } } else { if( _rightRecord != null ) { write(_output, null, _rightRecord); _rightRecord = read(_right); while(_rightRecord != null) { write(_output, null, _rightRecord); _rightRecord = read(_right); } } } _left.close(); _right.close(); _output.flush(); _output.close(); } private Record read(BufferedReader reader) throws Throwable { Record record = null; String data = reader.readLine(); if( data != null ) { record = new Record(data.split("\t")); } return record; } private Record readRecords(List<Record> list, Record record, BufferedReader reader) throws Throwable { int key = record.getKey(); list.add(record); record = read(reader); while( record != null && record.getKey() == key) { list.add(record); record = read(reader); } return record; } private void write(BufferedWriter writer, Record left, Record right) throws Throwable { String leftKey = (left == null ? "null" : Integer.toString(left.getKey())); String leftData = (left == null ? "null" : left.getData()); String rightKey = (right == null ? "null" : Integer.toString(right.getKey())); String rightData = (right == null ? "null" : right.getData()); writer.write("[" + leftKey + "][" + leftData + "][" + rightKey + "][" + rightData + "]\n"); } public static void main(String[] args) { try { BufferedReader leftReader = new BufferedReader(new FileReader("LEFT.DAT")); BufferedReader rightReader = new BufferedReader(new FileReader("RIGHT.DAT")); BufferedWriter output = new BufferedWriter(new FileWriter("OUTPUT.DAT")); Joiner joiner = new Joiner(); joiner.join(leftReader, rightReader, output); } catch (Throwable e) { e.printStackTrace(); } } } After applying the ideas from the proposed answer, I changed the loop to this private void join(RandomAccessFile left, RandomAccessFile right, BufferedWriter output) throws Throwable { long _pointer = 0; RandomAccessFile _left = left; RandomAccessFile _right = right; BufferedWriter _output = output; Record _leftRecord; Record _rightRecord; _leftRecord = read(_left); _rightRecord = read(_right); while( _leftRecord != null && _rightRecord != null ) { if( _leftRecord.getKey() < _rightRecord.getKey() ) { write(_output, _leftRecord, null); _leftRecord = read(_left); } else if( _leftRecord.getKey() > _rightRecord.getKey() ) { write(_output, null, _rightRecord); _pointer = _right.getFilePointer(); _rightRecord = read(_right); } else { long _tempPointer = 0; int key = _leftRecord.getKey(); while( _leftRecord != null && _leftRecord.getKey() == key ) { _right.seek(_pointer); _rightRecord = read(_right); while( _rightRecord != null && _rightRecord.getKey() == key ) { write(_output, _leftRecord, _rightRecord ); _tempPointer = _right.getFilePointer(); _rightRecord = read(_right); } _leftRecord = read(_left); } _pointer = _tempPointer; } } if( _leftRecord != null ) { write(_output, _leftRecord, null); _leftRecord = read(_left); while(_leftRecord != null) { write(_output, _leftRecord, null); _leftRecord = read(_left); } } else { if( _rightRecord != null ) { write(_output, null, _rightRecord); _rightRecord = read(_right); while(_rightRecord != null) { write(_output, null, _rightRecord); _rightRecord = read(_right); } } } _left.close(); _right.close(); _output.flush(); _output.close(); } UPDATE While this approach worked, it was terribly slow and so I have modified this to create files as buffers and this works very well. Here is the update ... private long getMaxBufferedLines(File file) throws Throwable { long freeBytes = Runtime.getRuntime().freeMemory() / 2; return (freeBytes / (file.length() / getLineCount(file))); } private void join(File left, File right, File output, JoinType joinType) throws Throwable { BufferedReader leftFile = new BufferedReader(new FileReader(left)); BufferedReader rightFile = new BufferedReader(new FileReader(right)); BufferedWriter outputFile = new BufferedWriter(new FileWriter(output)); long maxBufferedLines = getMaxBufferedLines(right); Record leftRecord; Record rightRecord; leftRecord = read(leftFile); rightRecord = read(rightFile); while( leftRecord != null && rightRecord != null ) { if( leftRecord.getKey().compareTo(rightRecord.getKey()) < 0) { if( joinType == JoinType.LeftOuterJoin || joinType == JoinType.LeftExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, leftRecord, null); } leftRecord = read(leftFile); } else if( leftRecord.getKey().compareTo(rightRecord.getKey()) > 0 ) { if( joinType == JoinType.RightOuterJoin || joinType == JoinType.RightExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, null, rightRecord); } rightRecord = read(rightFile); } else if( leftRecord.getKey().compareTo(rightRecord.getKey()) == 0 ) { String key = leftRecord.getKey(); List<File> rightRecordFileList = new ArrayList<File>(); List<Record> rightRecordList = new ArrayList<Record>(); rightRecordList.add(rightRecord); rightRecord = consume(key, rightFile, rightRecordList, rightRecordFileList, maxBufferedLines); while( leftRecord != null && leftRecord.getKey().compareTo(key) == 0 ) { processRightRecords(outputFile, leftRecord, rightRecordFileList, rightRecordList, joinType); leftRecord = read(leftFile); } // need a dispose for deleting files in list } else { throw new Exception("DATA IS NOT SORTED"); } } if( leftRecord != null ) { if( joinType == JoinType.LeftOuterJoin || joinType == JoinType.LeftExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, leftRecord, null); } leftRecord = read(leftFile); while(leftRecord != null) { if( joinType == JoinType.LeftOuterJoin || joinType == JoinType.LeftExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, leftRecord, null); } leftRecord = read(leftFile); } } else { if( rightRecord != null ) { if( joinType == JoinType.RightOuterJoin || joinType == JoinType.RightExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, null, rightRecord); } rightRecord = read(rightFile); while(rightRecord != null) { if( joinType == JoinType.RightOuterJoin || joinType == JoinType.RightExclusiveJoin || joinType == JoinType.FullExclusiveJoin || joinType == JoinType.FullOuterJoin ) { write(outputFile, null, rightRecord); } rightRecord = read(rightFile); } } } leftFile.close(); rightFile.close(); outputFile.flush(); outputFile.close(); } public void processRightRecords(BufferedWriter outputFile, Record leftRecord, List<File> rightFiles, List<Record> rightRecords, JoinType joinType) throws Throwable { for(File rightFile : rightFiles) { BufferedReader rightReader = new BufferedReader(new FileReader(rightFile)); Record rightRecord = read(rightReader); while(rightRecord != null){ if( joinType == JoinType.LeftOuterJoin || joinType == JoinType.RightOuterJoin || joinType == JoinType.FullOuterJoin || joinType == JoinType.InnerJoin ) { write(outputFile, leftRecord, rightRecord); } rightRecord = read(rightReader); } rightReader.close(); } for(Record rightRecord : rightRecords) { if( joinType == JoinType.LeftOuterJoin || joinType == JoinType.RightOuterJoin || joinType == JoinType.FullOuterJoin || joinType == JoinType.InnerJoin ) { write(outputFile, leftRecord, rightRecord); } } } /** * consume all records having key (either to a single list or multiple files) each file will * store a buffer full of data. The right record returned represents the outside flow (key is * already positioned to next one or null) so we can't use this record in below while loop or * within this block in general when comparing current key. The trick is to keep consuming * from a List. When it becomes empty, re-fill it from the next file until all files have * been consumed (and the last node in the list is read). The next outside iteration will be * ready to be processed (either it will be null or it points to the next biggest key * @throws Throwable * */ private Record consume(String key, BufferedReader reader, List<Record> records, List<File> files, long bufferMaxRecordLines ) throws Throwable { boolean processComplete = false; Record record = records.get(records.size() - 1); while(!processComplete){ long recordCount = records.size(); if( record.getKey().compareTo(key) == 0 ){ record = read(reader); while( record != null && record.getKey().compareTo(key) == 0 && recordCount < bufferMaxRecordLines ) { records.add(record); recordCount++; record = read(reader); } } processComplete = true; // if record is null, we are done if( record != null ) { // if the key has changed, we are done if( record.getKey().compareTo(key) == 0 ) { // Same key means we have exhausted the buffer. // Dump entire buffer into a file. The list of file // pointers will keep track of the files ... processComplete = false; dumpBufferToFile(records, files); records.clear(); records.add(record); } } } return record; } /** * Dump all records in List of Record objects to a file. Then, add that * file to List of File objects * * NEED TO PLACE A LIMIT ON NUMBER OF FILE POINTERS (check size of file list) * * @param records * @param files * @throws Throwable */ private void dumpBufferToFile(List<Record> records, List<File> files) throws Throwable { String prefix = "joiner_" + files.size() + 1; String suffix = ".dat"; File file = File.createTempFile(prefix, suffix, new File("cache")); BufferedWriter writer = new BufferedWriter(new FileWriter(file)); for( Record record : records ) { writer.write( record.dump() ); } files.add(file); writer.flush(); writer.close(); }

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  • Uploading many large files to a remote server

    - by TiernanO
    I am in the process of creating an offsite backup, and need to do a initial load of data. Currently, that's about 400Gb, give or take 10Gb or so... The backup system is producing files which are about 4Gb each, and has some other, smaller related files also. So, i need to transfer all 400ish gigs to a remote server, but how? What is the best method? I have full remote access to the server, so i can install anything i need to install. There are Windows, Linux and a Solaris VM running on the box itself, so any of those can be used there, and i have Windows and Linux at home. I have 2 internet connections in house, 10Mb/s uploading on each, so something that could potentially split the number of connections would be handy (kind of like GetRight, but in reverse... PutRight?).

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  • OpenFilesView Displays All Open and Locked Files to Help Resolve In-Use Errors

    - by Jason Fitzpatrick
    Windows: You go to move a file and Windows throws up an “In Use” error. OpenFilesView shows you what application or system process is locking up the files you’re trying to move. Sometimes the culprit is obvious; if you go to move your media folder and you’ve got your media player open watching South Park then shutting down the media player is the obvious solution. Other times the culprit is less obvious; sometimes Windows processes and less-than-obvious applications are accessing your files in ways that aren’t apparent. The screenshot below showcases the “In Use” error: This is where OpenFilesView comes into play. Fire up the application to see a list of all active files on your system. The master list is a bit overwhelming (on our test system there were over 1200 open files) but you use the find command to drill down to specific file or folder names. Once you’ve found the locked file you can close the file handle, kill the process, or bring the process to the front (so you can examine the program, if possible, before terminating it). It’s much more efficient than rebooting in an attempt to shake the In-Use error. OpenFilesView is freeware and works on Windows XP through Windows 7. HTG Explains: Do You Really Need to Defrag Your PC? Use Amazon’s Barcode Scanner to Easily Buy Anything from Your Phone How To Migrate Windows 7 to a Solid State Drive

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  • MVC 4 Beta with Mobile Project FIle Upload does not work

    - by Jim Shaffer
    I am playing around with the new MVC 4 beta release. I created a new web project using the Mobile Application template. I simply added a controller and a view to upload a file, but the file is always null in the action result. Is this a bug, or am I doing something wrong? Controller Code: using System.IO; using System.Web; using System.Web.Mvc; namespace MobileWebExample.Controllers { public class FileUploadController : Controller { public ActionResult Index() { return View(); } [AllowAnonymous] [HttpPost] [AcceptVerbs(HttpVerbs.Post)] public ActionResult Upload(HttpPostedFileBase file) { int i = Request.Files.Count; if (file != null) { if (file.ContentLength > 0) { var fileName = Path.GetFileName(file.FileName); var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName); file.SaveAs(path); } } return RedirectToAction("Index"); } } } And the view looks like this: @{ ViewBag.Title = "Index"; } <h2>Index</h2> <form action="@Url.Action("Upload")" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <input type="submit" value="Submit" /> </form>

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  • Uploading.to Uploads Files to Multiple File Hosts Simultaneously

    - by Jason Fitzpatrick
    If you’re looking to quickly share a file across a variety of file hosting services, Uploading.to makes it a cinch to share up to 10 files across 14 hosts. The upload process is simple. Visit Uploading.to, select your files, check the hosts you want to share the file across (by default all 14 are checked), add a description to the collection, and hit the Upload button. Uploading.to will upload your file to the various hosts; during the process you’ll see which hosts are confirmed and which have failed. We had 2 failures among the 14 hosts which still left the file mirrored across a sizable 12 host spread–not bad at all. When you’re ready to share the file hit the Copy Link button at the bottom of the screen and share it with your friends. They’ll be directed to Uploading.to and will be able to select from any of the hosts the file was successfully mirrored across. Uploading.to is a free service and requires no registration. Uploading.to [via Addictive Tips] HTG Explains: Do You Really Need to Defrag Your PC? Use Amazon’s Barcode Scanner to Easily Buy Anything from Your Phone How To Migrate Windows 7 to a Solid State Drive

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  • hosting acounts for large uploads

    - by Phil Jackson
    Hi, im wondering if anyone knows of any host providers ( uk preferably ) that deals mostly with accepting large file uploads. Most hosts only let you push something like 1.5mb ( thats taking into account the connection and the max execution time ). What i am looking for is a host specificaly for storing files on. I was going to create an upload script onto my application which posted the file to the external host and then return back ( using headers so the user doen't even know they have left ). Does anyone know of a host for this?

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  • Typing filename in standard open file dialog (Windows 7) - file name suggestion

    - by bybor
    When you use standard windows open file dialog and start typing it puts files whose name starts with what you type to drop down list. But on another pc with same Windows 7 it also puts first of them into input box in which you type - like FF does with URLS, allowing you to immediately press Enter (without pressing 'Down' to select file). I don't know why this behavior is different, but I want suggested file name shown in input box. How could it be achieved? Thanks.

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  • Use a Free Tool to Edit, Delete, or Restore the Default Hosts File in Windows

    - by Lori Kaufman
    The hosts file in Windows contains mappings of IP addresses to host names, like an address book for your computer. Your PC uses IP addresses to find websites, so it needs to translate the host names into IP addresses to access websites. When you enter a host name in a browser to visit a website, that host name is looked up in DNS servers to find the IP address. If you enter IP addresses and host names for websites you visit often, these websites will load faster, because the hosts file is loaded into memory when Windows start and overrides DNS server queries, creating a shortcut to the sites. Because the hosts file is checked first, you can also use it to block websites from tracking your activities on the internet, as well as block ads, banners, third-party cookies, and other intrusive elements on webpages. Your computer has its own host address, known as its “localhost” address. The IP address for localhost is 127.0.0.1. To block sites and website elements, you can enter the host name for the unwanted site in the hosts file and associate it with the localhost address. Blocking ads and other undesirable webpage elements, can also speed up the loading of websites. You don’t have to wait for all those items to load. The default hosts file that comes with Windows does not contain any host name/IP address mappings. You can add mappings manually, such as the IP address 74.125.224.72 for www.google.com. As an example of blocking an ad server website, you can enter the following line in your hosts file to block doubleclick.net from serving you ads. How To Use USB Drives With the Nexus 7 and Other Android Devices Why Does 64-Bit Windows Need a Separate “Program Files (x86)” Folder? Why Your Android Phone Isn’t Getting Operating System Updates and What You Can Do About It

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  • Ajax Upload using valums ajax upload plugin inside a form.

    - by idrish
    Hi , i just came across this ajax upload plugin and i wish to use it inside a form as shown in the demo page example 3. For some reason i am not able to make it work. I am not sure what parameters come into the function. For example here is my sample code. $(document).ready(function(){ var upload = new AjaxUpload('property_i', { action: 'submitproperty.php', autoSubmit: false, onSubmit : function(file , extension){ return false; } }); var upload_data = upload.setData({ 'propertytype':'propertytype' }); }); Now the ID used in the AjaxUpload function should be ID of the or of the Entire form. Also how do i use setData method. Any suggestions or links will be very helpful. Thanks

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  • Large Video Uploads via a website

    - by Andrew
    Some of the problems that can happen are timeouts, disconnections, and not being able to resume a file and having to start from the beginning. Assuming these files are up to around 5gigs in size, what is the best solution for dealing with this problem? I'm using a Drupal 6 install for the website. Some of my constraints due to the server setup I have to deal with: Shared hosting with max 200 connections at a time (unlimited disk space) Shared hosting. Unable to create users through an API (so can't automatically generate ftp accounts) I do have the ability to run cron-type scripts via a Drupal module. My initial thought was to create ftp users based off of Drupal accounts and requiring them to download an ftp client for their OS of choice. But the lack of API to auto-create ftp accounts and the inability to do it from command line kind of hinder that solution. If there's a workaround someone can think of, let me know! Thanks

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  • file upload in ajax by using php

    - by princess123
    hi.... I wud like to use file upload(ajax/javascript with php) in my form that has other controls also. when i uploaded an img it displays on the same form with delete option. if i click on submit it goes into folder as well as database & if i click on delete it deletes an img.... anybody can help me?pls u knw gmail file upload exact like that

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  • PHP Upload file enhance security

    - by mandril
    Hey.. my question is how to prevent someone upload a virus or some malicious code with the extension you pretend for example i have a pdf file uploader, anyone can upload a binary with pdf camouflage there are lots of programs to do that.

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