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  • Runtime error of TASM language help!

    - by dominoos
    .model small .stack 400h .data message db "hello. ", 0ah, 0dh, "$" firstdigit db ? seconddigit db ? thirddigit db ? number dw ? newnumber db ? anumber dw 0d bnumber dw 0d Firstn db 0ah, 0dh, "Enter first 3 digit number: ","$" secondn db 0ah, 0dh, "Enter second 3 digit number: ","$" messageB db 0ah, 0dh, "HCF of two number is: ","$" linebreaker db 0ah, 0dh, ' ', 0ah, 0dh, '$' .code Start: mov ax, @data ; establish access to the data segment mov ds, ax ; mov number, 0d mov dx, offset message ; print the string "yob choi 0648293" mov ah, 9h int 21h num: mov dx, offset Firstn ; print the string "put 1st 3 digit" mov ah, 9h int 21h ;run JMP FirstFirst ; jump to FirstFirst FirstFirst: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add anumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add anumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add anumber, ax ; jmp num2 ;go to checks Num2: mov dx, offset secondn ; print the string "put 2nd 3 digits" mov ah, 9h int 21h ;run JMP SecondSecond SecondSecond: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add bnumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add bnumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add bnumber, ax ; jmp compare ;go to compare compare: CMP ax, anumber ;comparing numbB and Number JA comp1 ;go to comp1 if anumber is bigger CMP ax, anumber ; JB comp2 ;go to comp2 if anumber is smaller CMP ax, anumber ; JE equal ;go to equal if two numbers are the same JMP compare ;go to compare (avioding error) comp1: SUB ax, anumber; subtract smaller number from bigger number JMP compare ; comp2: SUB anumber, ax; subtract smaller number from bigger number JMP compare ; equal: mov ah, 9d ;make linkbreak after the 2nd 3 digit number mov dx, offset linebreaker int 21h mov ah, 9d ;print "HCF of two number is:" mov dx, offset messageB int 21h mov ax,anumber ;copying 2nd number into ax add al,30h ; converting to ascii mov newnumber,al ; copying from low part of register into newnumb mov ah, 2d ;bios code for print a character mov dl, newnumber ;we had saved the ascii code here int 21h ;call to bios JMP exit; exit: mov ah, 4ch int 21h ;exit the program End hi, this is a program that finds highest common factor of 2 different 3digit number. if i put 200, 235,312 (low numbers) it works fine. but if i put 500, 550, 654(bigger number) the program crashes after the 2nd 3digit number is entered. can you help me to find out what problem is?

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  • Multiple many-to-many JOINs in a single mysql query without Cartesian Product

    - by VWD
    At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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  • Book Review: &ldquo;Inside Microsoft SQL Server 2008: T-SQL Querying&rdquo; by Itzik Ben-Gan et al

    - by Sam Abraham
    In the past few weeks, I have been reading “Inside Microsoft SQL Server 2008: T-SQL Querying” by Itzik Ben-Gan et al. In the next few lines, I will be providing a quick book review having finished reading this valuable resource on SQL Server 2008. In this book, the authors have targeted most of the common as well as advanced T-SQL Querying scenarios that one would use for development on a SQL Server database. Book content covered sufficient theory and practice to empower its readers to systematically write better performance-tuned queries. Chapter one introduced a quick refresher of the basics of query processing. Chapters 2 and 3 followed with a thorough coverage of applicable relational algebra concepts which set a good stage for chapter 4 to dive deep into query tuning. Chapter 4 has been my favorite chapter of the book as it provided nice illustrations of the internals of indexes, waits, statistics and query plans. I particularly appreciated the thorough explanation of execution plans which helped clarify some areas I may have not paid particular attention to in the past. The book continues to focus on SQL operators tackling a few in each chapter and covering their internal workings and the best practices to follow when used. Figures and illustrations have been particularly helpful in grasping advanced concepts covered therein. In conclusion, Inside Microsoft SQL Server 2008: T-SQL Querying provided me with 750+ pages of focused, advanced and practical knowledge that has added a few tips and tricks to my arsenal of query tuning strategies. Many thanks to the O’Reilly User Group Program and its support of our West Palm Beach Developers’ Group. --Sam Abraham

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  • Can I Specify Strings for MySql Table Values?

    - by afterimagedesign
    I have a MySql table that stores the users state and city from a list of states and cities. I specifically coded each state as their two letter shortened version (like WA for Washington and CA for California) and every city has the two letter abbreviation and the city name formated like this: Boulder Colorado would be CO-boulder and Salt Lake City, Utah would be UT-salt-lake-city as to avoid different states with same city name. The PHP inserts the value (UT-salt-lake-city) under the column City, but when I call the variable through PHP, it displays like this: Your location is: UT-salt-lake-city, Utah. To solve this, I've been making this list of variables if ($city == "AL-auburn") { $city = "Auburn"; } else if ($city == "AL-birmingham") { $city = "Birmingham"; } else if ($city == "GA-columbus") { $city = "Columbus"; $state = "Georgia"; } else if ($city == "AL-dothan") { $city = "Dothan"; } else if ($city == "AL-florence") { $city = "Forence"; } else if ($city == "AL-muscle-shoals") { $city = "Muscle Shoals"; } else if ($city == "AL-gadsden-anniston") { $city = "Gadsden Anniston"; } else if ($city == "AL-huntsville") { $city = "Huntsville"; } else if ($city == "AL-decatur") { $city = "Decatur"; } else if ($city == "AL-mobile") { $city = "Mobile"; } else if ($city == "AL-montgomery") { $city = "Montgomery"; } else if ($city == "AL-tuscaloosa") { $city = "Tuscaloosa"; } Is there a way I can shorten this process or at least call it from a separate file so I don't have to copy/paste every time I want to call the location?

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  • How do I get an Epson al-c 1700 printer working?

    - by Edmond Frants
    I have a brand new epson aculaser c1700 and i'd like to have it working fine on ubuntu 12.04. so i did my homework, kind of, no printer driver comes for this printer in cups ... so i asked epson support who drove me to avasys who no longer handle support since december 2011. This the question that is still in my mind : as this printer comes with an osx driver which uses cups as printer server, how come no driver can be found for cups? I tried to get ppd and filters from osx driver and use them to install the printer on ubuntu but no answer from printer and none printed sheet i have .... i'm so disappointed i could cry ... I'd like to work with someone to get this working fine, please help me!

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  • ASM programming, how to use loop?

    - by chris
    Hello. Im first time here.I am a college student. I've created a simple program by using assembly language. And im wondering if i can use loop method to run it almost samething as what it does below the program i posted. and im also eager to find someome who i can talk through MSN messanger so i can ask you questions right away.(if possible) ok thank you .MODEL small .STACK 400h .data prompt db 10,13,'Please enter a 3 digit number, example 100:',10,13,'$' ;10,13 cause to go to next line first_digit db 0d second_digit db 0d third_digit db 0d Not_prime db 10,13,'This number is not prime!',10,13,'$' prime db 10,13,'This number is prime!',10,13,'$' question db 10,13,'Do you want to contine Y/N $' counter dw 0d number dw 0d half dw ? .code Start: mov ax, @data ;establish access to the data segment mov ds, ax mov number, 0d LetsRoll: mov dx, offset prompt ; print the string (please enter a 3 digit...) mov ah, 9h int 21h ;execute ;read FIRST DIGIT mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov first_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros add number, ax ;save ;variable <number> now contains 1st digit * 10 ;---------------------------------------------------------------------- ;read SECOND DIGIT, multiply by 10 and add in mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov second_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros. Ignore them add number, ax ;save -- nearly finished ;variable <number> now contains 1st digit * 100 + second digit * 10 ;---------------------------------------------------------------------- ;read THIRD DIGIT, add it in (no multiplication this time) mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov third_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer add number, ax ;Both my variable number and ax are 16 bits, so equal size mov ax, number ;copy contents of number to ax mov cx, 2h div cx ;Divide by cx mov half, ax ;copy the contents of ax to half mov cx, 2h; mov ax, number; ;copy numbers to ax xor dx, dx ;flush dx jmp prime_check ;jump to prime check print_question: mov dx, offset question ;print string (do you want to continue Y/N?) mov ah, 9h int 21h ;execute mov ah, 1h int 21h ;execute cmp al, 4eh ;compare je Exit ;jump to exit cmp al, 6eh ;compare je Exit ;jump to exit cmp al, 59h ;compare je Start ;jump to start cmp al, 79h ;compare je Start ;jump to start prime_check: div cx; ;Divide by cx cmp dx, 0h ;reset the value of dx je print_not_prime ;jump to not prime xor dx, dx; ;flush dx mov ax, number ;copy the contents of number to ax cmp cx, half ;compare half with cx je print_prime ;jump to print prime section inc cx; ;increment cx by one jmp prime_check ;repeat the prime check print_prime: mov dx, offset prime ;print string (this number is prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat print_not_prime: mov dx, offset Not_prime ;print string (this number is not prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat Exit: mov ah, 4ch int 21h ;execute exit END Start

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  • What is the difference between these two nloglog(n) sorting algorithms? (Andersson et al., 1995 vs.

    - by Yktula
    Swanepoel's comment here lead me to this paper. Then, searching for an implementation in C, I came across this, which referenced another paper on an algorithm described here. Both papers describe integer sorting algorithms that run in O(nloglog(n)) time. What is the difference between the two? Have there been any more recent findings about this topic? Andersson et al., 1995 Han, 2004

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  • question about merge algorithm

    - by davit-datuashvili
    hi i have question i know that this question is somehow nonsense but let see i have code to merge two sorted array in a one sorted array here is code in java public class Merge { public static void main(String[]args){ int a[]=new int[]{7,14,23,30,35,40}; int b[]=new int[]{5,8,9,11,50,67,81}; int c[]=new int[a.length+b.length]; int al=0; int bl=0; int cl=0; while (al<a.length && bl<b.length) if (a[al]<b[bl]) c[cl++]=a[al++]; else c[cl++]=b[bl++]; while (al<a.length) c[cl++]=a[al++]; while (bl<b.length) c[cl++]=b[bl++]; for (int j=0;j<c.length;j++){ System.out.println(c[j]); } } } question is why does not work if we write here {} brackets while (al } ?

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  • I would like to know if someone has applescript to loop al my stickynotes and put it in a textfile

    - by Richard
    I have been meaning to do this for a while, but I never got around to do it. The problem is that I have to do research how applescript works. Anyway, I have now collected over 200 snippets for my programming, but I need to sort them out Putting them all in a textfile with some obvious breaks inbetween I could sort them and tag them for another snippet programm. This is my first question here, so I hope I am at the right place, maybe stack overflow is also a good place to ask Thanks in advannce, if someone already has done this or knows how to do this Richard

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  • Attempting to convert an if statement to assembly

    - by Malfist
    What am I doing wrong? This is the assmebly I've written: char encode(char plain){ __asm{ mov al, plain ;check for y or z status cmp al, 'y' je YorZ cmp al, 'z' je YorZ cmp al, 'Y' je YorZ cmp al, 'Z' je YorZ ;check to make sure it is in the alphabet now mov cl, al sub cl, 'A' cmp cl, 24 jl Other sub cl, '6' ;there are six characters between 'Z' and 'a' cmp cl, 24 jl Other jmp done ;means it is not in the alphabet YorZ: sub al, 24 jmp done Other: add al, 2 jmp done done: leave ret } } and this is the C code it's supposed to replace, but doesn't char encode(char plain){ char code; if((plain>='a' && plain<='x') || (plain>='A' && plain <='X')){ code = plain+2; }else if(plain == 'y' || plain=='z' || plain=='Y' || plain == 'y'){ code = plain - 24; }else{ code = plain; } return code; } It seems to convert every character that isn't an y,z,Y,Z into a plus 2 equivalent instead of just A-Xa-x. Any ideas why?

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  • Can a sub-procedure procedure lock and modify the same rows FOR UPDATE that its calling procedure al

    - by RenderIn
    Will the following code lead to a deadlock or should it work without any problem? I've got something similar and it's working but I didn't think it would. I thought the parent procedure's lock would have resulted in a deadlock for the child procedure but it doesn't seem to be. If it works, why? My guess is that the nested FOR UPDATE is not running into a deadlock because it's smart enough to realize that it is being called by the same procedure that has the current lock. Would this be a deadlock if FOO_PROC was not a nested procedure? DECLARE FOO_PROC(c_someName VARCHAR2) as cursor c1 is select * from awesome_people where person_name = c_someName FOR UPDATE; BEGIN open c1; update awesome_people set person_name = UPPER(person_name); close c1; END FOO_PROC; cursor my_cur is select * from awesome_people where person_name = 'John Doe' FOR UPDATE; BEGIN for onerow in c1 loop FOO_PROC(onerow.person_name); end loop; END;

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  • What is the relation between database books by Ullman et al.?

    - by macias
    A First Course in Database Systems by Jeffrey D. Ullman, Jennifer Widom (Amazon links) Database System Implementation by Hector Garcia-Molina, Jeffrey D. Ullman, Jennifer D. Widom Database Systems: The Complete Book by Hector Garcia-Molina, Jeffrey D. Ullman, Jennifer Widom As far as I know the second one is the second "part" of the first one. But what about the third one -- is it just first+second published in one volume? I would like to buy them, but I don't want to get redundant reading. Thank you in advance for clarification.

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  • RESTful design, how to name pages outside CRUD et al?

    - by sscirrus
    Hi all, I'm working on a site that has quite a few pages that fall outside my limited understanding of RESTful design, which is essentially: Create, Read, Update, Delete, Show, List Here's the question: what is a good system for labeling actions/routes when a page doesn't neatly fall into CRUD/show/list? Some of my pages have info about multiple tables at once. I am building a site that gives some customers a 'home base' after they log on. It does NOT give them any information about themselves so it shouldn't be, for example, /customers/show/1. It does have information about companies, but there are other pages on the site that do that differently. What do you do when you have these situations? This 'home-base' is shown to customers and it mainly has info about companies (but not uniquely so). Second case: I have a table called 'Matchings' in between customers and companies. These matchings are accessed in completely different ways on different parts of the site (different layouts, different CSS sheets, different types of users accessing them, etc. They can't ALL be matchings/show. What's the best way to label the others? Thanks very much. =)

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  • Zend Framework question (again) Do images, mp3s, scripts, etc, al just go in public folder?

    - by Joel
    I guess these are all questions that everyone must just know, because I'm not seeing this in the documentation :-D I understand that the public folder is the folder that the world has access to. I know it is the case with the css folder, but in migrating a traditional php website over, will my /images folder, /js folder /mp3s, etc Will those all just also be public folders that will be accessed via the layout or view.phtml pages? Thanks!

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  • Catch all DOM events on a page (without Firebug et. al.)

    - by Morten Bergfall
    How would I go about creating a cross-browser script, that would intercept all events firing on a page/browser window/DOM-tree (regardless of browser)? What I'm hoping to accomplish is basically to get a better understanding of the different handling of events in different browsers; I know the basic theory, but need to see to believe...

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  • PPTP VPN connection always connects successfully in Mac OS X/windows but drops after 2 minute in iPad or it doesn't connect al all!

    - by Farshid
    Dear Users, I've a big problem with using iPad's VPN connection. When I use the same VPN connection (PPTP) configuration parameters in my Mac OS X Snow Leopard or my windows XP (Bootcamp), it works flawlessly but when I define the same connection in my iPad, connection drops in about 1 or 2 minutes (some times) and most of the time, it Doesn't Connect at all. I'm using iPad 3G with iOS 4.2.1 and my iPad is not jail-broken. I've tried so hard to make it work in an stable manner but not found any solution yet. (I should have put encryption level to No-Encryption in Mac and Windows otherwise it won't connect in my desktop operating systems. It is a host-related issue and I'm binding to that). I'm sure there is no technical problem in my iPad's hardware and this problem also exists in my friend's iPad too. Our devices work perfectly with 3G and Wifi connections. Your answers are really appreciated.

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  • Best practice -- Content Tracking Remote Data (cURL, file_get_contents, cron, et. al)?

    - by user322787
    I am attempting to build a script that will log data that changes every 1 second. The initial thought was "Just run a php file that does a cURL every second from cron" -- but I have a very strong feeling that this isn't the right way to go about it. Here are my specifications: There are currently 10 sites I need to gather data from and log to a database -- this number will invariably increase over time, so the solution needs to be scalable. Each site has data that it spits out to a URL every second, but only keeps 10 lines on the page, and they can sometimes spit out up to 10 lines each time, so I need to pick up that data every second to ensure I get all the data. As I will also be writing this data to my own DB, there's going to be I/O every second of every day for a considerably long time. Barring magic, what is the most efficient way to achieve this? it might help to know that the data that I am getting every second is very small, under 500bytes.

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  • In FLEX, How can you stop ENTER Key from my Alert being caught by the control that initiated the Al

    - by WeeJavaDude
    I am having an issue where I show an AlertBox message when the user hits ENTER and the focus is in a text area. The pop up works fine, but when the user hits enter the Alert closes as expected, but the TextArea listener receives the ENTER event from the Alert and pops the dialog up again. I have tried a number of ways to catch and eat the event but so far I have not been lucky. Is there way to accomplish this? public function init():void { myTextInput.addEventListener(KeyboardEvent.KEY_UP, handleKeyStrokes); } public function handleKeyStrokes(evt:KeyboardEvent):void { if(evt.keyCode == Keyboard.ENTER) { myAlert = Alert.show("This is a test and only a test", "Title", 4, null, alertCallBack); } } <mx:TextInput id="myTextInput" left="600" top="10"> </mx:TextInput>

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  • TOSM e WPC

    - by Valter Minute
    Per chi ha tempo e voglia di fare quattro chiacchiere sui sistemi embedded microsoft, il sottoscritto parteciperà al TOSM, dal 16 al 18 Novembre a Torino e, in qualità di speaker, a WPC 2011, il principale evento formativo Italiano per le tecnologie Microsoft dal 22 al 24 Novembre a Milano (Assago). Saranno due occasioni per presentare queste tecnologie a un’audience un po’ diversa da quella che di solito frequenta gli eventi embedded e per scambiare idee e opinioni con chi non lavora sui sistemi embedded ma, magari, pensa di poterli utilizzare in futuro.

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