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  • how to remove duplicates but keep the same order?

    - by Ben Fossen
    I have a cell array in Matlab y = { 'd' 'f' 'a' 'g' 'g' 'a' 'w' 'h'} I use unique(y) to get rid of the duplicates but it rearranges the strings in alphabetica order >> unique(y) ans = 'a' 'd' 'f' 'g' 'h' 'w' Like this I want to remove the duplicates but keep the same order. I know I could write a function do do this but was wondering if there was a simpler way using unique to remove duplicates while keeping the same order just with the duplicates removed. I want it to return this >> unique(y) ans = 'd' 'f' 'a' 'g' 'w' 'h'

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  • Does similar Titles considered duplicates relating to SEO

    - by Uri
    I have built a testing service and I wonder if I should be concerned that search engines will consider similar titles as duplicates. For example: Some URLs title can be differed from others by only one word such as "Senior" and "Junior" Title A: C++ Online Test for Juniors Title B: C++ Online Test for Seniors Another example is with the "+" sign: Title A: C Standard Library Online Test for Seniors Title B: C++ Standard Library Online Test for Seniors Should I assume search engines will understand there is a difference in the titles? And the titles are not duplicated?

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  • In SQL / MySQL, can a Left Outer Join be used to find out the duplicates when there is no Primary ID

    - by Jian Lin
    I would like to try using Outer Join to find out duplicates in a table: If a table has Primary Index ID, then the following outer join can find out the duplicate names: mysql> select * from gifts; +--------+------------+-----------------+---------------------+ | giftID | name | filename | effectiveTime | +--------+------------+-----------------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | | 3 | coffee | coffee123.jpg | 2010-04-24 05:10:43 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | | 10 | heart | heart_shape.jpg | 2010-04-24 05:11:29 | | 11 | ice tea | icetea.jpg | 2010-04-24 05:19:53 | | 12 | cash | cash.png | 2010-04-24 05:27:44 | | 13 | chocolate | choco.jpg | 2010-04-25 04:04:31 | | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | +--------+------------+-----------------+---------------------+ 9 rows in set (0.00 sec) mysql> select * from gifts g1 LEFT JOIN (select * from gifts group by name) g2 on g1.giftID = g2.giftID where g2.giftID IS NULL; +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | giftID | name | filename | effectiveTime | giftID | name | filename | effectiveTime | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | NULL | NULL | NULL | NULL | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | NULL | NULL | NULL | NULL | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ 2 rows in set (0.00 sec) But what if the table doesn't have a Primary Index ID, then can an outer join still be used to find out duplicates?

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  • NSArrayController that is sorted and unique (no duplicates) for use in a pop-up in a core-data app

    - by Douglas Weaver
    I have core data app with an entity OBSERVATION that has as one of its attributes DEALNAME. I want to reference through Interface Builder or by making custom modifications to an NSArrayController a list of unique sorted dealnames so that I can use them in a pop-up. I have attempted to use @distinctUnionOfSets (and @distinctUnionOfArrays) but am unable to locate the proper key sequence. I can sort the ArrayController by providing a sort descriptor, but do not know how to eliminate duplicates. Are the @distinct... keys the right methodology? It would seem to provide the easiest way to optimize the use of IB. Is there a predicate form for removing duplicates? Or do I need to use my custom controller to extract an NSSet of the specific dealnames, put them back in an array and sort it and reference the custom array from IB? Any help would be appreciated. I am astounded that other have not tried to create a sorted-unique pop-up in tableviews.

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  • How do I get rid of duplicates in Rhythmbox even though the music in my Home folder is not showing duplicates?

    - by Drake
    I clicked import within Rhythmbox in Ubuntu 12.04 so I could get music to Ubuntu from my windows partition. The music appeared in my Rhythmbox library and I started playing it. However, when I restarted my computer the imported music did not show up. I looked in my music library and it was completely empty. So, I copied all of my music from my Windows partition into my music folder and launched Rhythmbox, but now it shows duplicates of all of the music I have. How can I get rid of the duplicate files if they are not showing in my Home folder?

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  • VBScript and Xpath excluding duplicates [closed]

    - by Malachi
    I am trying to pull names from an XML Document using a vbscript. XML Document structure <Aliases> <Alias PartyType="DF" CaseID="000000" NameType=""> Name Name</Alias> <Alias PartyType="DF" CaseID="000000" NameType=""> Name Name</Alias> <Alias PartyType="DF" CaseID="000000" NameType=""> Name Name</Alias> ... </Aliases> the XML File might have 100 rows with the same name coming from several different CaseID's because for this part of my vbscript I am trying to pull all the different Names from all cases, but here is the issue, I don't want to return duplicates. is there a way to do this with an xPath Expression or should I try to do this with VBScript? EDIT I am pretty sure that I am going to have to do this with VBScript. Would it be Faster and more efficient to solve this issue in VBScript, xPath, or in populating the XML I am retrieving information from ( this might prove more difficult than the other two options ) I am also asking a Similar question on stackoverflow

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  • Detecting Duplicates Using Oracle Business Rules

    - by joeywong-Oracle
    Recently I was involved with a Business Process Management Proof of Concept (BPM PoC) where we wanted to show how customers could use Oracle Business Rules (OBR) to easily define some rules to detect certain conditions, such as duplicate account numbers, duplicate names, high transaction amounts, etc, in a set of transactions. Traditionally you would have to loop through the transactions and compare each transaction with each other to find matching conditions. This is not particularly nice as it relies on more traditional approaches (coding) and is not the most efficient way. OBR is a great place to house these types’ of rules as it allows users/developers to externalise the rules, in a simpler manner, externalising the rules from the message flows and allows users to change them when required. So I went ahead looking for some examples. After quite a bit of time spent Googling, I did not find much out in the blogosphere. In fact the best example was actually from...... wait for it...... Oracle Documentation! (http://docs.oracle.com/cd/E28271_01/user.1111/e10228/rules_start.htm#ASRUG228) However, if you followed the link there was not much explanation provided with the example. So the aim of this article is to provide a little more explanation to the example so that it can be better understood. Note: I won’t be covering the BPM parts in great detail. Use case: Payment instruction file is required to be processed. Before instruction file can be processed it needs to be approved by a business user. Before the approval process, it would be useful to run the payment instruction file through OBR to look for transactions of interest. The output of the OBR can then be used to flag the transactions for the approvers to investigate. Example BPM Process So let’s start defining the Business Rules Dictionary. For the input into our rules, we will be passing in an array of payments which contain some basic information for our demo purposes. Input to Business Rules And for our output we want to have an array of rule output messages. Note that the element I am using for the output is only for one rule message element and not an array. We will configure the Business Rules component later to return an array instead. Output from Business Rules Business Rule – Create Dictionary Fill in all the details and click OK. Open the Business Rules component and select Decision Functions from the side. Modify the Decision Function Configuration Select the decision function and click on the edit button (the pencil), don’t worry that JDeveloper indicates that there is an error with the decision function. Then click the Ouputs tab and make sure the checkbox under the List column is checked, this is to tell the Business Rules component that it should return an array of rule message elements. Updating the Decision Service Next we will define the actual rules. Click on Ruleset1 on the side and then the Create Rule in the IF/THEN Rule section. Creating new rule in ruleset Ok, this is where some detailed explanation is required. Remember that the input to this Business Rules dictionary is a list of payments, each of those payments were of the complex type PaymentType. Each of those payments in the Oracle Business Rules engine is treated as a fact in its working memory. Implemented rule So in the IF/THEN rule, the first task is to grab two PaymentType facts from the working memory and assign them to temporary variable names (payment1 and payment2 in our example). Matching facts Once we have them in the temporary variables, we can then start comparing them to each other. For our demonstration we want to find payments where the account numbers were the same but the account name was different. Suspicious payment instruction And to stop the rule from comparing the same facts to each other, over and over again, we have to include the last test. Stop rule from comparing endlessly And that’s it! No for loops, no need to keep track of what you have or have not compared, OBR handles all that for you because everything is done in its working memory. And once all the tests have been satisfied we need to assert a new fact for the output. Assert the output fact Save your Business Rules. Next step is to complete the data association in the BPM process. Pay extra care to use Copy List instead of the default Copy when doing data association at an array level. Input and output data association Deploy and test. Test data Rule matched Parting words: Ideally you would then use the output of the Business Rules component to then display/flag the transactions which triggered the rule so that the approver can investigate. Link: SOA Project Archive [Download]

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  • Preventing Duplicates on Google

    - by abel
    I am currently using a rewrite rule to enable access to .php pages, without using the php extension. However to prevent old links from breaking, the pages can still be accessed via links containing the .php extension too. For eg. domain.com/page.php can now be accessed at domain.com/page All the links on the website now use domain.com/page type links within the site. However older incoming links will still link to the .php pages, meaning Google will index both pages and mark them as duplicate. I have two plans to remedy the situation. Use a php 301 redirect: When a page is accessed with the .php extension, I can redirect each page individually using a 301 redirect using php Using Canonical: Place a canonical tag on each page, pointing to the ".php" less version My Question: Are both methods equally efficacious in preventing Google from indexing my ".php" pages? Which method should be preferred, by convention or otherwise?

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  • how to handle duplicates in AVL tree

    - by Ahmed Kotb
    I want to make my avl tree support adding duplicates but there is a problem with the default behavior of the binary search tree with duplicates that the rotation could make nodes with equal key be on the left and the right of the parent for example adding A,A,A will cause the tree to do a rotation to be something like that A / \ A A so getting all the entries with that key will be a problem...and searching in both direction is not something good the solution that i have thought of is making each node stores an array of duplicates so when adding a new item that already exists will be just adding a new item to the array , removing item with key will delete the whole node while the find all items with key will return that array. are there are any other methods to handle duplicates ?

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  • Need help to properly remove duplicates in NHibernate

    - by Michael D. Kirkpatrick
    Here is the problem I am having. I have a database with over 100 records in it. I am paging through the data to get 9 results at a time. When I added a check to see if items are active, it caused the results to start doubling up. A little background: "Product" is the actual product line "ProductSkus" are the actual products that exist in the product line When there is more then 1 ProductSku within Product, it causes a duplicate entry to be returned. See the NHibernate Query below: result = this.Session.CreateCriteria<Model.Product>() .Add(Expression.Eq("IsActive", true)) .AddOrder(new Order("Name", true)) .SetFirstResult(indexNumber).SetMaxResults(maxNumber) // This part of the query duplicates the products .CreateAlias("ProductSkus", "ProdSkus", JoinType.InnerJoin) .Add(Expression.Eq("ProdSkus.IsActive", true)) .CreateAlias("ProductToSubcategory", "ProdToSubcat") .CreateAlias("ProdToSubcat.ProductSubcategory", "ProdSubcat") .Add(Expression.Eq("ProdSubcat.ID", subCatId)) // This part takes out the duplicate products - Removes too many items... // Turns out that with .SetFirstResult(indexNumber).SetMaxResults(maxNumber) // it gets 9 records back then the duplicates are removed. // Example: // Total Records over 100 // Max = 9 // 4 Duplicates removed // Yields 5 records when there should be 9 // Why??? This line is ran in NHibernate on the data after it has been extracted from the SQL server. .SetResultTransformer(new NHibernate.Transform.DistinctRootEntityResultTransformer()) .List<Model.Product>(); I added the DistinctRootEntityResultTransformer to clean up the duplicates. The problem is that it pulls 9 records back that contains duplicates. DistinctRootEntityResultTransformer then cleans up the duplicates in the 9 records. I am basically needing a distinct statement to be ran on the SQL server to begin with. However, distinct on SQL is not going to work since NHibernate by default wants to add every field from every table in the select part of the statement. I am only using the fields that belong to the root table to begin with (Model.Product). If I can tell NHibernate to not add the fields to the joined tables into the select part of the statement along with adding Distinct, it would work. I use NHibernare Profiler to see the actual query: SELECT top 9 this_.ID as ID351_3_, this_.Name as Name351_3_, this_.Description as Descript3_351_3_, this_.IsActive as IsActive351_3_, this_.ManufacturerID as Manufact5_351_3_, prodskus1_.ID as ID373_0_, prodskus1_.Description as Descript2_373_0_, prodskus1_.PartNumber as PartNumber373_0_, prodskus1_.Price as Price373_0_, prodskus1_.IsKit as IsKit373_0_, prodskus1_.IsActive as IsActive373_0_, prodskus1_.IsFeaturedProduct as IsFeatur7_373_0_, prodskus1_.DateAdded as DateAdded373_0_, prodskus1_.Weight as Weight373_0_, prodskus1_.TimesViewed as TimesVi10_373_0_, prodskus1_.TimesOrdered as TimesOr11_373_0_, prodskus1_.ProductID as ProductID373_0_, prodskus1_.OverSizedBoxID as OverSiz13_373_0_, prodtosubc2_.ID as ID362_1_, prodtosubc2_.MasterSubcategory as MasterSu2_362_1_, prodtosubc2_.ProductID as ProductID362_1_, prodtosubc2_.ProductSubcategoryID as ProductS4_362_1_, prodsubcat3_.ID as ID352_2_, prodsubcat3_.Name as Name352_2_, prodsubcat3_.ProductCategoryID as ProductC3_352_2_, prodsubcat3_.ImageID as ImageID352_2_, prodsubcat3_.TriggerShow as TriggerS5_352_2_ FROM Product this_ inner join ProductSku prodskus1_ on this_.ID = prodskus1_.ProductID and (prodskus1_.IsActive = 1) inner join ProductToSubcategory prodtosubc2_ on this_.ID = prodtosubc2_.ProductID inner join ProductSubcategory prodsubcat3_ on prodtosubc2_.ProductSubcategoryID = prodsubcat3_.ID WHERE this_.IsActive = 1 /* @p0 */ and prodskus1_.IsActive = 1 /* @p1 */ and prodsubcat3_.ID = 3 /* @p2 */ ORDER BY this_.Name asc If I hand modify the query and run it directly on the SQL server I get the result set I want (I removed all the extra fields in the select section and added DISTINCT): SELECT DISTINCT top 9 this_.ID as ID351_3_, this_.Name as Name351_3_, this_.Description as Descript3_351_3_, this_.IsActive as IsActive351_3_, this_.ManufacturerID as Manufact5_351_3_, FROM Product this_ inner join ProductSku prodskus1_ on this_.ID = prodskus1_.ProductID and (prodskus1_.IsActive = 1) inner join ProductToSubcategory prodtosubc2_ on this_.ID = prodtosubc2_.ProductID inner join ProductSubcategory prodsubcat3_ on prodtosubc2_.ProductSubcategoryID = prodsubcat3_.ID WHERE this_.IsActive = 1 /* @p0 */ and prodskus1_.IsActive = 1 /* @p1 */ and prodsubcat3_.ID = 3 /* @p2 */ ORDER BY this_.Name asc The big question I now must ask is... What must I change in the NHibernate Query to ultimately get the exact same result? Thanks in advance.

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  • Java - Removing duplicates in an ArrayList

    - by Will
    I'm working on a program that uses an ArrayList to store Strings. The program prompts the user with a menu and allows the user to choose an operation to perform. Such operations are adding Strings to the List, printing the entries etc. What I want to be able to do is create a method called removeDuplicates().This method will search the ArrayList and remove any duplicated values. I want to leave one instance of the duplicated value(s) within the list. I also want this method to return the total number of duplicates removed. I've been trying to use nested loops to accomplish this but I've been running into trouble because when entries get deleted, the indexing of the ArrayList gets altered and things don't work as they should. I know conceptually what I need to do but I'm having trouble implementing this idea in code. Here is some pseudo code: start with first entry; check each subsequent entry in the list and see if it matches the first entry; remove each subsequent entry in the list that matches the first entry; after all entries have been examined, move on to the second entry; check each entry in the list and see if it matches the second entry; remove each entry in the list that matches the second entry; repeat for entry in the list Here's the code I have so far: public int removeDuplicates() { int duplicates = 0; for ( int i = 0; i < strings.size(); i++ ) { for ( int j = 0; j < strings.size(); j++ ) { if ( i == j ) { // i & j refer to same entry so do nothing } else if ( strings.get( j ).equals( strings.get( i ) ) ) { strings.remove( j ); duplicates++; } } } return duplicates; }

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  • Select from multiple tables, remove duplicates

    - by staze
    I have two tables in a SQLite DB, and both have the following fields: idnumber, firstname, middlename, lastname, email, login One table has all of these populated, the other doesn't have the idnumber, or middle name populated. I'd LIKE to be able to do something like: select idnumber, firstname, middlename, lastname, email, login from users1,users2 group by login; But I get an "ambiguous" error. Doing something like: select idnumber, firstname, middlename, lastname, email, login from users1 union select idnumber, firstname, middlename, lastname, email, login from users2; LOOKS like it works, but I see duplicates. my understanding is that union shouldn't allow duplicates, but maybe they're not real duplicates since the second user table doesn't have all the fields populated (e.g. "20, bob, alan, smith, [email protected], bob" is not the same as "NULL, bob, NULL, smith, [email protected], bob"). Any ideas? What am I missing? All I want to do is dedupe based on "login". Thanks!

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  • Hard to append a table with many records into another without generating duplicates

    - by Bill Mudry
    I may seem to be a bit wordy at first but for the hope it will be easier for all of you to understand what I am doing in the first place. I have an uncommon but enjoyable activity of collecting as many species of wood from around the world as I can (over 2,900 so far). Ok, that is the real world. Meanwhile I have spent over 8 years compiling over 5.8 meg of text data on all the woods of the world. That got so large that learning some basic PHP and MySQL was most welcome so I could build a new database driven home for all this research. I am still slow at it but getting there. The original premise was to find evidence of as many species of woods in the world I can. The more names identified, the more successful the project. I have named the project TAXA for ease of conversation (short for Taxonomy). You are most welcome to take a look at what I have so far at www.prowebcanada.com/taxa. It is 95% dynamically driven. So far I am reporting about 6,500 botanical wood names and, as said above, the more I can report, the more successful is the project. I have a file of all the woods in the second largest wood collection in the world, the Tervuren wood collection in the Netherlands with over 11,300 wood names even after cleaning out all duplicates. That is almost twice the number I am reporting now so porting all the new wood names from Tervuren to the 'species' table where I keep the reported data would be a major desirable advancement in the project. At one point I was able to add all the Tervuren records to the species table but over 3,000 duplicates also formed. They were not in the Tervuren file in the first place but represent the same wood names common to both files. It is common sense that there would be woods common to both that when merged would create new duplicates. At one point and with the help of others from another forum, I may very well have finally got the proper SQL statement. When I ran it, though, the system said (semi-amusingly at first) ----- that it had gone away! After looking up on the Net what could have have done this, one reason is that the MySQL timeout lapses and probably because of the large size of files I am running. I am running this on a rented account on Godaddy so I cannot go about trying to adjust any config file. For safety, I copied the tervuren.sql file as tervuren_target.sql and the species.sql file as species_master.sql tp use as working files just to make sure I protect the original files from destruction or damage. Later I can name the species_master back to just species.sql once I am happy all worked well. The species file has about 18 columns in it but only 5 columns match the columns in the Tervuren file (name for name and collation also). The rest of the columns are just along for the ride, so to speak. The common key in both is the 'species_name" columns in both. I am not sure it is at all proper to call one a primary key and the other a foreign key since there really is no relational connection to them. One is just more data for the other and can disappear after, never to be referred to the working code in the application. I have been very surprised and flabbergasted on how hard it can be to append records from one large table into another (with same column names plus others) without generating NEW duplicates in the first place. Watch out thinking that a SELECT DISTINCT statement may do the job because absolutely NO records in the species table must get destroyed in the process and there is no way (well, that I know of) to tell the 'DISTINCT" command this. Yes, the original 'species' table has duplicates in it even before all this but, trust me ---- they have to be removed the long hard way manually record by record or I will lose precious information. It is more important to just make sure no NEW duplicates form through bringing in new names in the tervuren_target.species_name into species.species_name. I am hoping and thinking that a straight SQL solution should work --- except for that nasty timeout. How do I get past that? Could it mean that I may have to turn to a PHP plus SQL method?? Or ..... would I have to break up the Tervuren files into a few smaller ones and run them independently (hope not....)" So far, what seems should be easy has proven to be unexpectedly tricky. I appreciate any help you can give but start from the assumption that this may be harder to do right than it may seem on the surface. By the way --- I am running a quad 64 bit system with Windows 7, so at least I have some fairly hefty power on the client end. I have a direct ethernet cable feeding a cable connection to the Internet. Once I get an algorithm and code working for this, I also have many other lists to process that could make the 'species' table grow even more. It could be equivalent to (ahem) lighting a rocket under my project (especially compared to do this record by record manually)! This is my first time in this forum, so I do not know how I can receive any replies. Do I have to to come back here periodically or are replies emailed out also? It would be great if you CC'd copies to me at billmudry at rogers.com :-) Much thanks for your patience and help, Bill Mudry Mississauga, Ontario Canada (next to Toronto).

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  • Virus that duplicates word documents as exe

    - by Bob Rivers
    Hi, We are facing a virus problem on our network, but I'm unable to identify it, so we can't properly deal with it. The symptoms are that the virus duplicates a word document (.doc) generating a new archive with the same name, but with an exe extension, and, after that, the virus hides the original file. So, when the user clicks over the file, it propagates itself. Symantec AV seems to be able to block it: every time that the virus tries to generate the exe, symantec blocks it, but at this point, the original file was already converted to hidden, so the user thinks that the file has been deleted. Symantec identifies it as a simple trojan horse. I already started a full scan, but it didn't found nothing. I'm trying to know the virus name in order to fight it. Does anyone has any kind of information? TIA, Bob

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  • Compress snapshot backups with duplicates

    - by Usavich
    I have a set of backups of mostly photos. The directory looks sort of like this: backup/Day1/photos/1.jpg .../2.jpg backup/Day2/photos/2.jpg .../3.jpg .../4.jpg backup/DayN/photos/2.jpg .../3.jpg .../9.jpg Files with same name are identical. There are many duplicates. Due to the way the backup system works, it's not possible to create incremental backup directly. I always get the entire dump each day. If I want to create a compressed archive for a date range, say Day 5~9, what is the best tool/compression algorithm to do that?

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  • Copy data from different worksheet to a master worksheet but no duplicates

    - by sam
    hi all, i want to clarify my initial question for a possible solutions from any savior out there. Say i have 3 excel sheets one for each user for data entry located in separate workbooks to avoid excel share workbook problems. I also have a master sheet in another workbook where i want individual data enter on those sheets precisely sheets 1 should copy to the next available row of sheet 1 in the master sheet as the users enter them. i need a vba code that can copy each record without copying a duplicate row in the master sheet but highlight the duplicate row and lookup the initial record in a master sheet and return the name of the Imputer looking up the row say column ( I) where each user sign there initials after every row of entry like below. All 4 worksheets are formatted as below: lastname account cardno. type tran amount date location comments initials JAME 65478923 1975 cash 500 4/10/2010 miles st. this acct is resolve MLK BEN 52436745 1880 CHECK 400 4/12/2010 CAREY ST Ongoing investigation MLK JAME 65478923 1975 cash 500 4/10/2010 miles st. this acct is resolve MLK I need the vba to recognize duplicates only if the account number and the card number matches the initial records. So if the duplicates exist a pop up message should be display that a duplicates exist and return the initial Imputer say MLK in COLUMN( I) to any user inputting in the individual worksheets other than warehouse sheets (master). So please any idea will be appreciated.

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  • Finding subsets that can be completed to tuples without duplicates

    - by Jules
    We have a collection of sets A_1,..,A_n. The goal is to find new sets for each of the old sets. newA_i = {a_i in A_i such that there exist (a_1,..,a_n) in (A1,..,An) with no a_k = a_j for all k and j} So in words this says that we remove all the elements from A_i that can't be used to form a tuple (a_1,..a_n) from the sets (A_1,..,A_n) such that the tuple doesn't contain duplicates. My question is how to compute these new sets quickly. If you just implement this definition by generating all possible v's this will take exponential time. Do you know a better algorithm? Edit: here's an example. Take A_1 = {1,2,3,4} A_2 = {2}. Now the new sets look like this: newA_1 = {1,3,4} newA_2 = {2} The 2 has been removed from A_1 because if you choose it the tuple will always be (2,2) which is invalid because it contains duplicates. On the other hand 1,3,4 are valid because (1,2), (3,2) and (4,2) are valid tuples. Another example: A_1 = {1,2,3} A_2 = {1,4,5} A_3 = {2,4,5} A_4 = {1,2,3} A_5 = {1,2,3} Now the new sets are: newA_1 = {1,2,3} newA_2 = {4,5} newA_3 = {4,5} newA_4 = {1,2,3} newA_5 = {1,2,3} The 1 and 2 are removed from sets 2 and 3 because if you choose the 1 or 2 from these sets you'll only have 2 values left for sets 1, 4 and 5, so you will always have duplicates in tuples that look like (_,1,_,_,_) or like (_,_,2,_,_).

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  • Remove Duplicates from LEFT OUTER JOIN

    - by Kaushik Gopal
    Hey folk my question is quite similar to http://stackoverflow.com/questions/757957/restricting-a-left-join I have a variation in that request though and the comment didn't allow too many characters hence posting as a new question. I hope this doesn't go against the posting rules/etiquette. Assuming i have a table SHOP and another table LOCATION. Location is a sort of child table of table SHOP, that has two columns of interest, one is a Division Key (calling it just KEY) and a "SHOP" number. This matches to the Number "NO" in table SHOP. I tried this left outer join: SELECT S.NO, L.KEY FROM SHOP S LEFT OUTER JOIN LOCATN L ON S.NO = L.SHOP But i'm getting a lot of duplicates since there are many locations that belong to a single shop. I want to eliminate them and just get a list of "shop, key" entries without duplicates. any ideas how? (edit: ORACLE 10g Database)

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  • Django : proper way to use model, duplicates!

    - by llazzaro
    Hello, I have a question about the proper, best way to manage the model. I am relative newbie to django, so I think I need to read more docs, tutorials,etc (suggestions for this would be cool!). Anyway, this is my question : I have a python web crawler, that is "connected" with django model. Crawling is done once a day, so its really common to find "duplicates". To avoid duplicates I do this : cars = Car.Objects.filter(name=crawledItem['name']) if len(cars) 0: #object already exists, update it car = cars[0] else: car = Car() #some non-relevant code here car.save() I want to know, if this is the proper/correct way to do it or its any "automatic" way to do it. Its possible to put the logic inside the Car() constructor also, should I do that? Thanks a lot!

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  • Remove Duplicates from List of HashMap Entries

    - by HonorGod
    I have a List<HashMap<String,Object>> which represents a database where each list record is a database row. I have 10 columns in my database. There are several rows where the values of 2 particular columns are equals. I need to remove the duplicates from the list after the list is updated with all the rows from database. What is the efficient way? FYI - I am not able to do distinct while querying the database, because the GroupName is added at a later stage to the Map after the database is loaded. And since Id column is not primary key, once you add GroupName to the Map. You will have duplicates based on Id + GroupName combination! Hope my question makes sense. Let me know if we need more clarification.

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  • Deleting duplicates in Delphi listview

    - by radick
    I am trying to remove duplicates in my listview. This function: procedure RemoveDuplicates(const LV:TbsSkinListView); var i,j: Integer; begin LV.Items.BeginUpdate; LV.SortType := stText; try for i := 0 to LV.Items.Count-1 do begin for j:=i+1 to LV.Items.Count-1 do begin if SameText(LV.Items[i].SubItems[0], LV.Items[j].SubItems[0]) and SameText(LV.Items[i].SubItems[1], LV.Items[j].SubItems[1]) and SameText(LV.Items[i].SubItems[2], LV.Items[j].SubItems[2]) and SameText(LV.Items[i].SubItems[3], LV.Items[j].SubItems[3]) then LV.Items.Delete(j); end; end; finally LV.SortType := stNone; LV.Items.EndUpdate; end; ShowMessage('Deleted'); end; does not delete the duplicates. What is wrong with it?

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  • remove duplicates from object array data java

    - by zahir hussain
    hi i want to know how to remove duplicates in object. for example cat c[] = new cat[10]; c[1].data = "ji"; c[2].data = "pi"; c[3].data = "ji"; c[4].data = "lp"; c[5].data = "ji"; c[6].data = "pi"; c[7].data = "jis"; c[8].data = "lp"; c[9].data = "js"; c[10].data = "psi"; i would like to remove the duplicates value from object array. thanks and advance

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