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  • Limit foreign key choices in select in an inline form in admin

    - by mightyhal
    Edited :-) Hopefully a bit clearer now. The logic is of the model is: A Building has many Rooms A Room may be inside another Room (a closet, for instance--ForeignKey on 'self') A Room can only in inside of another Room in the same building (this is the tricky part) Here's the code I have: #spaces/models.py from django.db import models class Building(models.Model): name=models.CharField(max_length=32) def __unicode__(self): return self.name class Room(models.Model): number=models.CharField(max_length=8) building=models.ForeignKey(Building) inside_room=models.ForeignKey('self',blank=True,null=True) def __unicode__(self): return self.number and: #spaces/admin.py from ex.spaces.models import Building, Room from django.contrib import admin class RoomAdmin(admin.ModelAdmin): pass class RoomInline(admin.TabularInline): model = Room extra = 2 class BuildingAdmin(admin.ModelAdmin): inlines=[RoomInline] admin.site.register(Building, BuildingAdmin) admin.site.register(Room) The inline will display only rooms in the current building (which is what I want). The problem, though, is that for the inside_room drop down, it displays all of the rooms in the Rooms table (including those in other buildings). In the inline of rooms, I need to limit the inside_room choices to only rooms which are in the current building being displayed by the main form. I can't figure out a way to do it with either a limit_choices_to in the model, nor can I figure out how exactly to override the admin's inline formset properly (I feel like I should be somehow create a custom inline form, pass the building_id of the main form to the custom inline, then limit the queryset for the field's choices based on that--but I just can't wrap my head around how to do it). Maybe this is too complex for the admin site, but it seems like something that would be generally useful... Thanks again for your help!

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  • Rails rspec expects Admin::PostsController, which is there.

    - by berkes
    I have a file app/controllers/admin/posts_controller.rb class Admin::PostsController < ApplicationController layout 'admin' # GET /admin/posts def index @pposts = Post.paginate :page => params[:page], :order => 'created_at DESC' end # ...Many more standard CRUD/REST methods... end And an rspec test spec/controllers/admin/posts_controller_spec.rb require 'spec_helper' describe Admin::PostsController do describe "GET 'index'" do it "should be successful" do get 'index' response.should be_success end end #...many more test for all CRUD/REST methods end However, running that spec throws an error. I have no idea what that error means, nor how to start solving it. /home/...../active_support/dependencies.rb:492:in `load_missing_constant': Expected /home/...../app/controllers/admin/posts_controller.rb to define Admin::PostsController (LoadError) I may have it all set up wrong, or may be doing something really silly, but all I want is my CRUD actions on /admin, with separate before filters and a separate layout. And to test these controllers. EDIT ZOMG, made a terrible copy-paste error into this SO posting. The controller was PostsController, not the PagesController that I pasted into there. Problem still stands, as my code is correct, just the SO post, here was wrong.

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  • Django not recognizing django admin urls

    - by colorfulgrayscale
    I just registered my models my models with django admin. I navigate to the django admin at /admin. I log in sucessfully and I can see all my models. great so far. But now if I try to click one of the links, for Ex: 'users', django gives me a 404 saying The current URL, admin/auth/user/, didn't match any of these. Its really weird because in my urls.py I have it mapped correctly (r'^admin/', include(admin.site.urls)), I have all the required middleware enabled and have these in my installed apps 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', anyone have any idea? Thanks.

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  • Cannot Extend Django 1.2.1 Admin Template

    - by jcady
    I am attempting to override/extend the header for the Django admin in version 1.2.1. However when I try to extend the admin template and simply change what I need documented here: http://docs.djangoproject.com/en/dev/ref/contrib/admin/#overriding-vs-replacing-an-admin-template), I run into a recursion problem. I have an index.html file in my project's templates/admin/ directory that starts with {% extends "admin/index.html" %} But it seems that this is referencing the local index file (a.k.a. itself) rather than the default Django copy. I want to extend the default Django template and simply change a few blocks. When I try this file, I get a recursion depth error. How can I extend parts of the admin? Thanks.

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  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

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  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

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  • Error cloning gitosis-admin on new setup

    - by michaelmior
    I have the following in my gitosis.conf. (Created via gitsosis-init < id_rsa.pub with the key from my laptop) [gitosis] loglevel = DEBUG [group gitosis-admin] writable = gitosis-admin members = michael@laptop When I try git clone git@SERVER:gitsos-admin.git, I get the following errors: Initialized empty Git repository in /home/michael/gitsos-admin/.git/ DEBUG:gitosis.serve.main:Got command "git-upload-pack 'gitsos-admin.git'" DEBUG:gitosis.access.haveAccess:Access check for 'michael@laptop' as 'writable' on 'gitsos-admin.git'... DEBUG:gitosis.access.haveAccess:Stripping .git suffix from 'gitsos-admin.git', new value 'gitsos-admin' DEBUG:gitosis.group.getMembership:found 'michael@laptop' in 'gitosis-admin' DEBUG:gitosis.access.haveAccess:Access check for 'michael@laptop' as 'writeable' on 'gitsos-admin.git'... DEBUG:gitosis.access.haveAccess:Stripping .git suffix from 'gitsos-admin.git', new value 'gitsos-admin' DEBUG:gitosis.group.getMembership:found 'michael@laptop' in 'gitosis-admin' DEBUG:gitosis.access.haveAccess:Access check for 'michael@laptop' as 'readonly' on 'gitsos-admin.git'... DEBUG:gitosis.access.haveAccess:Stripping .git suffix from 'gitsos-admin.git', new value 'gitsos-admin' DEBUG:gitosis.group.getMembership:found 'michael@laptop' in 'gitosis-admin' ERROR:gitosis.serve.main:Repository read access denied fatal: The remote end hung up unexpectedly I know my key is being accepted because I have tried logging in via SSH and although a terminal won't be allocated, the authorization works.

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  • Java(standard, non standard) or Non Java based Web developement [closed]

    - by LivingThing
    I am new to web development. Initially i thought i would be learning LAMP or WAMP to acquire web developement skills but recently i came across Standard Java based (JSP, servlets) and Non standard Java based (GWT). My question is related to if and how LAMP can be compared with Java (standarad or non stadard) technologies. Is LAMP even comparable to Java based tech or it does something else or something more or less ? what requirement for a web developement projects require the choice that which of these 'technologies' should be choosen ? Thank YOu

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  • input_formats in django admin has no effect

    - by pablo
    I'm trying to use input_foramts in the admin but it has no effect. What am I doing wrong? # model class Feedback(models.Model): created_at = models.DateTimeField(auto_now_add=True) # admin form class FeedbackAdminForm(forms.ModelForm): created_at = forms.DateTimeField(input_formats=('%d/%m/%Y',)) class Meta: model = Feedback # admin class FeedbackAdmin(admin.ModelAdmin): form = FeedbackAdminForm admin.site.register(Feedback, FeedbackAdmin) Thanks

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  • How to introduce web development to non-programmers?

    - by Gulshan
    Once one of my non-programmer friends asked, "I have a cool website idea that I don't want to share. Rather I want to develop it on my own. So, I want to learn web development. Tell me what to do?" And sometimes many other people asked about how to start with web development as a profession. But they are non-programmers or not from Computer Science background. What should I suggest to them? Learning programming from the scratch? Or using CMS-like tools? Or anything else?

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  • No access to Windows 2003 admin shares

    - by ARomo
    This is the environment: Several Win 2003 SP 2 servers and several Win XP SP2 & SP3 clients. All in the same LAN. Firewall is disabled everywhere. No recent Windows updates or configuration changes. This is the problem: Since last Thursday, I log on to any other server or workstation as any regular (non-admin) user and I fail to be able to open ADMIN SHARES ONLY (namely \\server1\c$, \\server1\e$ and \\server1\admin$). The error message is: "\server1\c$ is not accessible. You might not have permission to use this network resource. Contact the administrator of this server to find out if you have access permissions. Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again." I can, however, open the same shares if I use FQDN or IP address: \\server1.domain.local\c$ \\172.0.0.1\c$ Other shares do not have this issue and I can open them without any issue. Any ideas or suggestion would be truly appreciated. Thank you in advance.

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  • C++: Check istream has non-space, non-tab, non-newline characters left without extracting chars

    - by KRao
    I am reading a std::istream and I need to verify without extracting characters that: 1) The stream is not "empty", i.e. that trying to read a char will not result in an fail state (solved by using peek() member function and checking fail state, then setting back to original state) 2) That among the characters left there is at least one which is not a space, a tab or a newline char. The reason for this is, is that I am reading text files containing say one int per line, and sometimes there may be extra spaces / new-lines at the end of the file and this causes issues when I try get back the data from the file to a vector of int. A peek(int n) would probably do what I need but I am stuck with its implementation. I know I could just read istream like: while (myInt << myIstream) {...} //Will fail when I am at the end but the same check would fail for a number of different conditions (say I have something which is not an int on some line) and being able to differentiate between the two reading errors (unexpected thing, nothing left) would help me to write more robust code, as I could write: while (something_left(myIstream)) { myInt << myIstream; if (myStream.fail()) {...} //Horrible things happened } Thank you!

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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Local User & Local Admin User Server 2008

    - by Ammo
    Hi I had a test recently and one of the questions was to create a file and local user and give the local user write permission to that file. I created the local user successfully however when I went to add permission to the file it would not find the local user when name was entered correctly, and idea what could have prevented this. Secondly I was asked to create a local admin account and give full permissions to the file, to my knowledge server 2008 has a built in admin account, and neither was the server a domain controller. Could you tell me what you would do in this situation? Many Thanks!

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  • Django Admin Actions missing

    - by Andrew C
    One of my Django sites is missing the Django Admin Action bar shown here: http://docs.djangoproject.com/en/dev/ref/contrib/admin/actions/#ref-contrib-admin-actions There is no checkbox next to each row and no Action select box near the top of the page. This is happening on every model. I have several sites running Django 1.1, and they all show the Admin Actions, so it feels like a local configuration issue. Anyone seen this before?

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  • Authlogic admin subsite

    - by MrThomas
    Following this tutorial getting the following errors: NameError in Admin/dashboardsController#show uninitialized constant Admin::DashboardsController NameError in Admin sessionController#new uninitialized constant Admin::AdminHelper not sure how to correct this!

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  • Do we need a non-disclosure agreement (NDA)?

    - by MrEdmundo
    We're going to meet a potential new client today and between ourselves started discussing the need for a non-disclosure agreement (NDA) and whether we need one at this juncture. In this case we don't think we'll be talking about technical specifics as it's an initial meeting about who we are. Is there any precedent on when is the right time for small ISVs to insist on NDAs and when perhaps the insistence might appear over the top and precious. All ideas welcomed, though in our case we're interested in UK law.

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  • Turning my website into a non-profit

    - by GoodbyeWebsite
    I was given an established website about a year ago. It makes some money on ads, but not much (less than 10k/year). I am no longer able to manage the site and am considering turning it over to another person. I don't want them to turn around and sell it. It was suggested that I establish a non-profit of sorts and transfer the assets to that entity. Does anybody have experience or advice on this subject?

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  • Microsoft SQL Server 2008 - 99% fragmentation on non-clustered, non-unique index

    - by user550441
    I have a table with several indexes (defined below). One of the indexes (IX_external_guid_3) has 99% fragmentation regardless of rebuilding/reorganizing the index. Anyone have any idea as to what might cause this, or the best way to fix it? We are using Entity Framework 4.0 to query this, the EF queries on the other indexed fields about 10x faster on average then the external_guid_3 field, however an ADO.Net query is roughly the same speed on both (though 2x slower than the EF Query to indexed fields). Table id(PK, int, not null) guid(uniqueidentifier, null, rowguid) external_guid_1(uniqueidentifier, not null) external_guid_2(uniqueidentifier, null) state(varchar(32), null) value(varchar(max), null) infoset(XML(.), null) -- usually 2-4K created_time(datetime, null) updated_time(datetime, null) external_guid_3(uniqueidentifier, not null) FK_id(FK, int, null) locking_guid(uniqueidentifer, null) locked_time(datetime, null) external_guid_4(uniqueidentifier, null) corrected_time(datetime, null) is_add(bit, not null) score(int, null) row_version(timestamp, null) Indexes PK_table(Clustered) IX_created_time(Non-Unique, Non-Clustered) IX_external_guid_1(Non-Unique, Non-Clustered) IX_guid(Non-Unique, Non-Clustered) IX_external_guid_3(Non-Unique, Non-Clustered) IX_state(Non-Unique, Non-Clustered)

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  • How to customize a many-to-many inline model in django admin

    - by Jonathan
    I'm using the admin interface to view invoices and products. To make things easy, I've set the products as inline to invoices, so I will see the related products in the invoice's form. As you can see I'm using a many-to-many relationship. In models.py: class Product(models.Model): name = models.TextField() price = models.DecimalField(max_digits=10,decimal_places=2) class Invoice(models.Model): company = models.ForeignKey(Company) customer = models.ForeignKey(Customer) products = models.ManyToManyField(Product) In admin.py: class ProductInline(admin.StackedInline): model = Invoice.products.through class InvoiceAdmin(admin.ModelAdmin): inlines = [FilteredApartmentInline,] admin.site.register(Product, ProductAdmin) The problem is that django presents the products as a table of drop down menus (one per associated product). Each drop down contains all the products listed. So if I have 5000 products and 300 are associated with a certain invoice, django actually loads 300x5000 product names. Also the table is not aesthetic. How can I change it so that it'll just display the product's name in the inline table? Which form should I override, and how?

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  • ValueError with multi-table inheritance in Django Admin

    - by jorde
    I created two new classes which inherit model Entry: class Entry(models.Model): LANGUAGE_CHOICES = settings.LANGUAGES language = models.CharField(max_length=2, verbose_name=_('Comment language'), choices=LANGUAGE_CHOICES) user = models.ForeignKey(User) country = models.ForeignKey(Country, null=True, blank=True) created = models.DateTimeField(auto_now=True) class Comment(Entry): comment = models.CharField(max_length=2000, blank=True, verbose_name=_('Comment in English')) class Discount(Entry): discount = models.CharField(max_length=2000, blank=True, verbose_name=_('Comment in English')) coupon = models.CharField(max_length=2000, blank=True, verbose_name=_('Coupon code if needed')) After adding these new models to admin via admin.site.register I'm getting ValueError when trying to create a comment or a discount via admin. Adding entries works fine. Error msg: ValueError at /admin/reviews/discount/add/ Cannot assign "''": "Discount.discount" must be a "Discount" instance. Request Method: GET Request URL: http://127.0.0.1:8000/admin/reviews/discount/add/ Exception Type: ValueError Exception Value: Cannot assign "''": "Discount.discount" must be a "Discount" instance. Exception Location: /Library/Python/2.6/site-packages/django/db/models/fields/related.py in set, line 211 Python Executable: /usr/bin/python Python Version: 2.6.1

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  • Django admin.py missing field error

    - by user782400
    When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

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