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  • A question about the order of pagination

    - by SpawnCxy
    Currently I'm deal with a history message page using Cakephp.And I got a problem about records' order.In the controller,codes about pagination as follows $this->paginate['Msg'] = array('order'=>'Msg.created desc'); $msgs = $this->paginate('Msg'); $this->set('historymsgs',$msgs); Then I got a page of messges like this: tom:I'm eighteen. Jerry:How old are you? tom:Tom. Jerry:what's your name? tom:Hi nice to meet you too! Jerry:Hello,nice to meet you! But what I need is the reversed order of the messages.How can I append a condition of Msg.created asc here? Thanks in advance.

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  • is it possible to combine will_paginate with find_by_sql?

    - by Tam
    In my rails application I want to use will_paginate plugin to paginate on my query. Is that possible? I tried doing something like this but it didn't work: @users = User.find_by_sql(" SELECT u.id, u.first_name, u.last_name, CASE WHEN r.user_accepted =1 AND (r.friend_accepted =0 || r.friend_accepted IS NULL) .........").paginate( :page => @page, :per_page => @per_page, :conditions => conditions_hash, :order => 'first_name ASC') If not, can you recommend a way around this or a way that might work as I don't want to write my own pagination.

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  • How to use will_paginate with a nested resource in Rails?

    - by Sue Petersen
    I'm new to Rails, and I'm having major trouble getting will_paginate to work with a nested resource. I have two models, Statement and Invoice. will_paginate is working on Statement, but I can't get it to work on Invoice. I know I'd doing something silly, but I can't figure it out and the examples I've found on google won't work for me. statement.rb class Statement < ActiveRecord::Base has_many :invoices def self.search(search, page) paginate :per_page => 19, :page => page, :conditions => ['company like ?', "%#{search}%"], :order => 'date_due DESC, company, supplier' end end statements_controller.rb <irrelevant code clipped for readability> def index #taken from the RAILSCAST 51, will_paginate podcast @statements = Statement.search(params[:search], params[:page]) end I call this in the view like so, and it works: <%= will_paginate @statements %> But I can't figure out how to get it to work for Invoices: invoice.rb class Invoice < ActiveRecord::Base belongs_to :statement def self.search(search, page) paginate :per_page => 19, :page => page, :conditions => ['company like ?', "%#{search}%"], :order => 'employee' end end invoices_controller.rb class InvoicesController < ApplicationController before_filter :find_statement #TODO I can't get will_paginate to work w a nested resource def index #taken from the RAILSCAST 51, will_paginate podcast @invoices = Invoice.search(params[:search], params[:page]) end def find_statement @statement_id = params[:statement_id] return(redirect_to(statements_url)) unless @statement_id @statement = Statement.find(@statement_id) end end And I try to call it like this: <%= will_paginate (@invoices) % The most common error message, as I play with this, is: "The @statements variable appears to be empty. Did you forget to pass the collection object for will_paginate?" I don't have a clue what the problem is, or how to fix it. Thanks for any help and guidance!

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  • How to order search results by multiple fields?

    - by JustinRoR
    I am using Sunspot and Will_paginate for search in my application and don't how to have my search results start out with certain ordering conditions. The model I am searching is the UserPrice model and want my :price and :purchase_date in descending order or lowest price to highest and present date to past: class UserPrice < ActiveRecord::Base attr_accessible :price, :product_name, :purchase_date belongs_to :product # Sunspot configuration searchable do text :product_name do product.name end end end class SearchController < ApplicationController def index @search = UserPrice.search do fulltext params[:search] paginate(:per_page => 5, :page => params[:page]) end @user_prices = @search.results end end Even though I don't know how, I'm not sure if I would use Sunspot or Will_paginate to sort by order of price and purchase date. How would I achieve this though? Thank you. UPDATE I try to use the order_by method but not sure how the model would look now. class SearchController < ApplicationController def index @search = UserPrice.search do fulltext params[:search] paginate(:per_page => 5, :page => params[:page]) facet(:business_retail_store_id) facet(:business_online_store_id) order_by :price, :desc order_by :purchase_date, :desc end @user_prices = @search.results end end Not sure why having the following in my controller: order_by :price, :desc order_by :purchase_date, :desc I get the error: Sunspot::UnrecognizedFieldError in SearchController#index No field configured for UserPrice with name 'price' This doesn't make sense to me since I do have these fields inside of my UserPrice model and in my database. How do I fix this?

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  • Rails3 - will_paginate plugin strange output

    - by Sam
    I have the will_paginate plugin working in an application, but when I paginate a resource it just spits out the HTML as text, doesn't provide links to the next pages and such. And when I manually type in the URL the plugin is working it just doesn't make <%= will_paginate @products %> into links such as next 1 2 3 ... last Ideas?

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  • Iphone UIScrollView and multiple visible images

    - by joynes
    Hi! Im trying to implement a UIScrollView including multiple images, using paginate. The problem is that I want more then one page to be visible in the UIScrollView, but only one page should be selected. I found several solutions in which you handle touch down/up (touchesBegan and touchesEnded) myself and scrollRectToVisible, but I want to avoid this if possible. A sample solution for that can be found at: http://forums.macrumors.com/showthread.php?t=634462 I dont get why its so easy if you only need to display one page at a time in the UIScrollView , but seems really hard if you want to show more pages. Could you solve it with zooming? /Br Johannes

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  • Undefined method 'total_entries' after upgrading Rails 2.2.2 to 2.3.5

    - by Trevor
    I am upgrading a Rails application from 2.2.2 to 2.3.5. The only remaining error is when I invoke total_entries for creating a jqgrid. Error: NoMethodError (undefined method `total_entries' for #<Array:0xbbe9ab0>) Code snippet: @route = Route.find( :all, :conditions => "id in (#{params[:id]})" ) { if params[:page].present? then paginate :page => params[:page], :per_page => params[:rows] order_by "#{params[:sidx]} #{params[:sord]}" end } respond_to do |format| format.html # show.html.erb format.xml { render :xml => @route } format.json { render :json => @route } format.jgrid { render :json => @route.to_jqgrid_json( [ :id, :name ], params[:page], params[:rows], @route.total_entries ) } end Any ideas? Thanks!

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  • has_many conditions

    - by user305270
    c = "(f.profile_id = #{self.id} OR f.friend_id = #{self.id})" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.friend_id ELSE f.profile_id END = p.id)" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.profile_rejected ELSE f.friend_rejected END = 1)" c += AND + "(p.banned = 0)" I need this to be used in a has_many relationship like this: has_many :removed_friends, :conditions => ??? how do i set there the self.id?, or how do i pass there the id? Then i want to use the will_paginate plugin: @profile.removed_friends.paginate(:page => 1, :per_page => 20) Thanks for your help

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  • Multiple conditions with will_paginate

    - by user363243
    I am using will_paginate for pagination but I can't seem to use more than one condition at a time. For example, if I want to have a sql query that ends in "Where office_id = 5", then it's pretty straight forward, I can do that. but what if I want to do "Where office_id = 5 AND primary_first = 'Mark'"? I can't do that. I have no idea how to enter multiple conditions. Can you help?? Below is an example of my code: def self.search(search, page, office_id) paginate :per_page => 5, :page => page, :conditions => ['office_id', "%#{office_id}"], # + ' and primary_first like ?', "%#{params[:search]}%"], #:conditions => ['primary_first', "%#{search}%"], :order => 'created_at' end Thank you for your help!

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  • CakePHP 3-level-deep model associatons

    - by user357452
    Hi, I am relatively new to CakePHP, I am doing fine with the documentation, but I've been trying to find a way out to this problem for weeks and I don't seem to find the solution, I am sure it is easy and maybe even automagicaly doable, but I just don't know how to find it (maybe I don't know the jargon for these kind of things) My model structure is like this: <?php class Trip extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Start' => array( 'className' => 'Place', 'foreignKey' => 'start_id' ), 'End' => array( 'className' => 'Place', 'foreignKey' => 'end_id' ), 'Transport' => array( 'className' => 'Transport', 'foreignKey' => 'transport_id' ) ); } ?> <?php class Place extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id' ), 'State' => array( 'className' => 'State', 'foreignKey' => 'state_id' ), 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id' ) ); var $hasMany = array( 'PlaceStart' => array( 'className' => 'trip', 'foreignKey' => 'start_id', 'dependent' => false ), 'PlaceEnd' => array( 'className' => 'trip', 'foreignKey' => 'end_id', 'dependent' => false ) ); } ?> <?php class State extends AppModel { var $belongsTo = array( 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id', 'conditions' => '', 'fields' => '', 'order' => '' ) ); var $hasMany = array( 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id', 'dependent' => false ) ); } ?> ... and so forth with User, City, Country, and Transport Models. What I am trying to achieve is to get all the information of the whole tree when I search for a Trip. <?php class TripController extends AppController { function index() { debug($this->Trip->find('first')); } } Outputs Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [user_id] => 4 [start_id] => 2 [end_id] => 1 [title] => My trip [transport_id] => 1 ) [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 1 [direccion] => Lincoln Street ) [End] => Array ( [id] => 1 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 4 [address] => Fifth Avenue ) [Transport] => Array ( [id] => 1 [name] => car ) ) Here is the question: How do I get in one query all the information down the tree? I would like to have something like Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [Country] => Array ( [id] => 1 [name] = Spain ) [State] => Array ( [id] => 1 [name] = Barcelona ) [City] => Array ( [id] => 1 [name] = La Floresta ) [address] => Lincoln Street ) [End] => (same as Start) [title] => My trip [Transport] => Array ( [id] => 1 [name] => car ) ) ) Can CakePHP create this kind of data? Not only for $this->Model->find() but also for $this->paginate() as for example: // filter by start if(isset($this->passedArgs['start'])) { //debug('isset '.$this->passedArgs['start']); $start = $this->passedArgs['start']; $this->paginate['conditions'][] = array( 'OR' => array( 'Start.address LIKE' => "%$start%", 'Start.State.name LIKE' => "%$start%", 'Start.City.name LIKE' => "%$start%", 'Start.Country.name LIKE' => "%$start%" ) ); $this->data['Search']['start'] = $start; } It seems like a rough question but I am sure this is extensively done and documented, I'd really appreciate any help. Thanks Cheers Naoise

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  • Rails has_many conditions

    - by user305270
    c = "(f.profile_id = #{self.id} OR f.friend_id = #{self.id})" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.friend_id ELSE f.profile_id END = p.id)" c += AND + "(CASE WHEN f.profile_id=#{self.id} THEN f.profile_rejected ELSE f.friend_rejected END = 1)" c += AND + "(p.banned = 0)" I need this to be used in a has_many relationship like this: has_many :removed_friends, :conditions => ??? how do i set there the self.id?, or how do i pass there the id? Then i want to use the will_paginate plugin: @profile.removed_friends.paginate(:page => 1, :per_page => 20) Thanks for your help EDIT: class Profile < ActiveRecord::Base has_many :friendships has_many :removed_friends, :class_name => 'Profile', :through => :friendships, :conditions => "(friendships.profile_id = #{self.id} OR friendships.friend_id = #{self.id})" "AND (CASE WHEN friendships.profile_id=#{self.id} THEN friendships.profile_rejected ELSE friendships.friend_rejected END = 1)" + "AND (p.banned = 0)" end class Friendship < ActiveRecord::Base belongs_to :profile belongs_to :removed_friend, :class_name => 'Profile', :foreign_key => "(CASE WHEN friendships.profile_id = #{self.id} THEN friend_id ELSE profile_id END)" end

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  • Rails 3 upgrade will_pagination wrong number of arguments (2 for 1)

    - by user1452541
    I am in the process of upgrading my rails app from 2.3.5 to 3.2.5 on ruby 1.9.3. In the old app I was using the will_paginate plugin, which I have converted to a gem. Now after the upgrade I am getting the following error : wrong number of arguments (2 for 1) A few lines from application trace: Application Trace | Framework Trace | Full Trace will_paginate (3.0.3) lib/will_paginate/active_record.rb:124:in `paginate' app/models/activity.rb:28:in `dashboard_activities' app/controllers/dashboard_controller.rb:10:in `index' actionpack (3.2.5) lib/action_controller/metal/implicit_render.rb:4:in `send_action' actionpack (3.2.5) l I believe the issue is in the old code in the activity Model where I am using pagination. Can anyone help? The code: def dashboard_activities(page, total_records, date_range1 = nil, date_range2 = nil ) unless date_range2.nil? x =[ "is_delete = false AND status = 'open' AND date(due_date) between ? and ?", date_range1, date_range2] else x =[ "is_delete = false AND status = 'open' AND date(due_date) = ? ", date_range1] end paginate(:all, :page =>page, :per_page =>total_records, :conditions => x, :order =>"due_date asc") end

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  • Complex Rails queries across multiple tables, unions, and will_paginate. Solved.

    - by uberllama
    Hi folks. I've been working on a complex "user feed" type of functionality for a while now, and after experimenting with various union plugins, hacking named scopes, and brute force, have arrived at a solution I'm happy with. S.O. has been hugely helpful for me, so I thought I'd post it here in hopes that it might help others and also to get feedback -- it's very possible that I worked on this so long that I walked down an unnecessarily complicated road. For the sake of my example, I'll use users, groups, and articles. A user can follow other users to get a feed of their articles. They can also join groups and get a feed of articles that have been added to those groups. What I needed was a combined, pageable feed of distinct articles from a user's contacts and groups. Let's begin. user.rb has_many :articles has_many :contacts has_many :contacted_users, :through => :contacts has_many :memberships has_many :groups, :through => :memberships contact.rb belongs_to :user belongs_to :contacted_user, :class_name => "User", :foreign_key => "contacted_user_id" article.rb belongs_to :user has_many :submissions has_many :groups, :through => :submissions group.rb has_many :memberships has_many :users, :through => :memberships has_many :submissions has_many :articles, :through => :submissions Those are the basic models that define my relationships. Now, I add two named scopes to the Article model so that I can get separate feeds of both contact articles and group articles should I desire. article.rb # Get all articles by user's contacts named_scope :by_contacts, lambda {|user| {:joins => "inner join contacts on articles.user_id = contacts.contacted_user_id", :conditions => ["articles.published = 1 and contacts.user_id = ?", user.id]} } # Get all articles in user's groups. This does an additional query to get the user's group IDs, then uses those in an IN clause named_scope :by_groups, lambda {|user| {:select => "DISTINCT articles.*", :joins => :submissions, :conditions => {:submissions => {:group_id => user.group_ids}}} } Now I have to create a method that will provide a UNION of these two feeds into one. Since I'm using Rails 2.3.5, I have to use the construct_finder_sql method to render a scope into its base sql. In Rails 3.0, I could use the to_sql method. user.rb def feed "(#{Article.by_groups(self).send(:construct_finder_sql,{})}) UNION (#{Article.by_contacts(self).send(:construct_finder_sql,{})})" end And finally, I can now call this method and paginate it from my controller using will_paginate's paginate_by_sql method. HomeController.rb @articles = Article.paginate_by_sql(current_user.feed, :page => 1) And we're done! It may seem simple now, but it was a lot of work getting there. Feedback is always appreciated. In particular, it would be great to get away from some of the raw sql hacking. Cheers.

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  • Customizing Number of Page Links Rendered With will_paginate?

    - by Moe
    I'm using the will_paginate gem for my Rails project and it's working beautifully. Unfortunately, on paginated result sets with a larger number of pages, the link section is too wide. Instead of: « Previous 1 2 … 5 6 7 8 9 10 11 12 13 … 18 19 Next » I would like to show: « Previous 1 2 … 5 6 7 8 9 … 18 19 Next » How can I reduce the number of page links being rendered? I looked at the will_paginate docs on github but couldn't find a solution. Thanks! Moe

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  • Why did mislav-will_paginate start adding so much garbage to urls between rails 2.3.2 and 2.3.5?

    - by user30997
    I've used will_paginate in a number of projects now, but when I moved one of them to Rails 2.3.5, clicking on any of the pagination links (page number, next, prev, etc.,) went from getting nice URLs like this: http://foo.com/user/1/date/2005_01_31/phone/555-6161 to this: http://foo.com/?options[]=user&options[]=date&options[]=2005_01_31&options[]=phone&options[]=555-6161 I have a route that looks like this that is probably the source of the 'options' keyword: map.connect '/browse/*options', :controller=>'assets', :action=>'browse' It's enough of an annoyance that I'm willing to roll a paginator to get around this if there isn't a way to get back to where I was before. Is there a way to get will_paginate to turn array-style routes into sane urls again? Thanks.

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  • Will_paginate stuck on page 2

    - by Sleepycat
    For some reason my will_paginate collection is stuck on page 2. I have the usual links the view helper provides except every page after page one links to http://localhost:3000/ceo/gr_messages?page=2 I have tried to add the :order option with no luck. I have also ensured that the request is a get as mentioned on this page: http://wiki.github.com/mislav/will_paginate/simple-search Any other thoughts or suggestions would be appreciated.

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  • Doing will_paginate pages calculation around a record

    - by Anderson De Andrade
    I'm displaying a list of events. I wanted displayed the page with the events for today by default. That was easy accomplished by: page = number_of_records_before_RECORD / number_of_pages + 1 Now I want to display the first item of today's events as the first item in that page. Maybe there is a way to generate page numbers around a record with negative values to get back.

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  • Rails (pagination and tags)

    - by Vitaly
    Hey, I stumbled upon a problem of how to mix both acts_as_taggable (on steroids) and will_paginate gems. What I found on this problem is this: http://www.mckinneystation.com/2007/08/20/pagination-with-acts_as_taggable_on_steroids-acts_as_ferret-and-will_paginate/ But it's dated of 2007, may be there's something more recent? And also could you explain in details what should I do to make that fix work?

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  • Ruby on Rails activerecord find average in one sql and Will_Paginate

    - by Darkerstar
    Hi all I have the following model association: a student model and has_many scores. I need to make a list showing their names and average, min, max scores. So far I am using student.scores.average(:score) on each student, and I realise that it is doing one sql per student. How can I make the list with one joined sql? Also how would I use that with Will_Paginate plugin? Thank you

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  • Rails will_paginate custom route

    - by kristian nissen
    How can I use will_paginate with a custom route? I have the following in my routes: map.connect 'human-readable/:name', :controller => :tags, :action => 'show' but will_paginate uses url_for as far as I can tell, but I want to use 'human-readable' instead of url_for, but how?

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  • How can I change the link format in will_paginate for page_cache in Ruby on Rails?

    - by jaehyun
    I want to use page_cache with will_paginate. There are good information on this page below. http://railsenvy.com/2007/2/28/rails-caching-tutorial#pagination http://railslab.newrelic.com/2009/02/05/episode-5-advanced-page-caching I wrote routes.rb looks like: map.connect '/products/page/:page', :controller => 'products', :action => 'index' But, links of url are not changed to '/products/page/:page' which are in will_paginate helper. They are still 'products?page=2' How can i change url format is in will_paginate?

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  • Will_paginate Plugin on two objects on same page

    - by piemesons
    Hello I am using will_paginte plugin on two objects on a same page. Like on stackoverflow. There is a profile page on which there is a pagination on two things QUestions and answers. I am having problem ie:-- when user is clicking on questions pagination page 2. answers page are also updating. The reason is both is sending a post variable ie params[:page] How to change this variable so that only one should be updated. and how to maintain that user should not lose the other page. ie he is on 3rd page of questions and 1st page of answers and now he click on 5th page of the questions the result should be 3rd page of questions and 5th page of answers.

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  • Showing pagination with only single page using will_paginate

    - by James
    I'm using will_paginate as standard, but it only shows the pagination controls (< 1 2 etc) when there's more than one page to display. Normally, this would be what is wanted, but I want to see the pagination controls (for UI consistency and to get round an annoying CSS quirk in the system I'm working on) even when there's only 1 page to display (showing < 1 ). Is this possible?

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