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  • blurry lines between web application context layer, service layer and data access layer in spring

    - by thenaglecode
    I Originally asked this question in SO but on advice I have moved the question here... I'll admit I'm a spring newbie, but you can correct me if I'm wrong, this one liner looks kinda fishy in a best practices sort of way: @RepositoryRestResource(collectionResourceRel="people"...) public interface PersonRepository extends PagingAndSortingRepository<Person, Long> For those who are unaware, the following does many things: It is an interface definition that can be registered in an application context as a jpa repository, automagically hooking up all the default CRUD operations within a persistence context (that is externally configured). and also configures default controller/request-mapping/handler functionality at the namespace "/people" relative to your configured dispatcher servlet-mapping. Here's my point. I just crossed 3 conceptual layers with one line of code! this feels against my seperation-of-concern instincts but i wanted to hear your opinion. And for the sake of being on a question and answer site, I would like to know whether there is a better way of seperating these different layers - Service, Data, Controllers - whilst maintaining as minimal configuration as possible

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  • Windows Server 2003 Terminal Server with installed licenses will not go beyond 2 connections

    - by Erwin Blonk
    I installed the Terminal Server role in Windows Server 2003 Standard 64-bits. Still, only 2 connections are allowed. The License Manager says that there are 10 Device CALs available, which is correct, and that none are given out. For good measure I let the server reboot, to no effect. Before this, there was another server (same Windows, except that it is 32 bits) active as a licensing server. I removed the role first and then then added it to the new server. I then removed the Terminal Server Licensing Server component off the old one and added it to the new one. After that, I added to licenses. When that didn't give the required result, I rebooted to new server. Still, the new server, with licenses and all, acts as if it has the 2 license RDP. The server are all stand-alone, there is no active directory been set up. Both servers are in different workgroups.

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  • Spring security request matcher is not working with regex

    - by Felipe Cardoso Martins
    Using Spring MVC + Security I have a business requirement that the users from SEC (Security team) has full access to the application and FRAUD (Anti-fraud team) has only access to the pages that URL not contains the words "block" or "update" with case insensitive. Bellow, all spring dependencies: $ mvn dependency:tree | grep spring [INFO] +- org.springframework:spring-webmvc:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-asm:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-beans:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context-support:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-expression:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-core:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-web:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-core:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-aop:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-web:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-jdbc:jar:3.0.7.RELEASE:compile [INFO] | \- org.springframework:spring-tx:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-config:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-acl:jar:3.1.2.RELEASE:compile Bellow, some examples of mapped URL path from spring log: Mapped URL path [/index] onto handler 'homeController' Mapped URL path [/index.*] onto handler 'homeController' Mapped URL path [/index/] onto handler 'homeController' Mapped URL path [/cellphone/block] onto handler 'cellphoneController' Mapped URL path [/cellphone/block.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/block/] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock/] onto handler 'cellphoneController' Mapped URL path [/user/update] onto handler 'userController' Mapped URL path [/user/update.*] onto handler 'userController' Mapped URL path [/user/update/] onto handler 'userController' Mapped URL path [/user/index] onto handler 'userController' Mapped URL path [/user/index.*] onto handler 'userController' Mapped URL path [/user/index/] onto handler 'userController' Mapped URL path [/search] onto handler 'searchController' Mapped URL path [/search.*] onto handler 'searchController' Mapped URL path [/search/] onto handler 'searchController' Mapped URL path [/doSearch] onto handler 'searchController' Mapped URL path [/doSearch.*] onto handler 'searchController' Mapped URL path [/doSearch/] onto handler 'searchController' Bellow, a test of the regular expressions used in spring-security.xml (I'm not a regex speciality, improvements are welcome =]): import java.util.Arrays; import java.util.List; public class RegexTest { public static void main(String[] args) { List<String> pathSamples = Arrays.asList( "/index", "/index.*", "/index/", "/cellphone/block", "/cellphone/block.*", "/cellphone/block/", "/cellphone/confirmBlock", "/cellphone/confirmBlock.*", "/cellphone/confirmBlock/", "/user/update", "/user/update.*", "/user/update/", "/user/index", "/user/index.*", "/user/index/", "/search", "/search.*", "/search/", "/doSearch", "/doSearch.*", "/doSearch/"); for (String pathSample : pathSamples) { System.out.println("Path sample: " + pathSample + " - SEC: " + pathSample.matches("^.*$") + " | FRAUD: " + pathSample.matches("^(?!.*(?i)(block|update)).*$")); } } } Bellow, the console result of Java class above: Path sample: /index - SEC: true | FRAUD: true Path sample: /index.* - SEC: true | FRAUD: true Path sample: /index/ - SEC: true | FRAUD: true Path sample: /cellphone/block - SEC: true | FRAUD: false Path sample: /cellphone/block.* - SEC: true | FRAUD: false Path sample: /cellphone/block/ - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock.* - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock/ - SEC: true | FRAUD: false Path sample: /user/update - SEC: true | FRAUD: false Path sample: /user/update.* - SEC: true | FRAUD: false Path sample: /user/update/ - SEC: true | FRAUD: false Path sample: /user/index - SEC: true | FRAUD: true Path sample: /user/index.* - SEC: true | FRAUD: true Path sample: /user/index/ - SEC: true | FRAUD: true Path sample: /search - SEC: true | FRAUD: true Path sample: /search.* - SEC: true | FRAUD: true Path sample: /search/ - SEC: true | FRAUD: true Path sample: /doSearch - SEC: true | FRAUD: true Path sample: /doSearch.* - SEC: true | FRAUD: true Path sample: /doSearch/ - SEC: true | FRAUD: true Tests Scenario 1 Bellow, the important part of spring-security.xml: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: FRAUD group **can't" access any page SEC group works fine Scenario 2 NOTE that I only changed the order of intercept-url in spring-security.xml bellow: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: SEC group **can't" access any page FRAUD group works fine Conclusion I did something wrong or spring-security have a bug. The problem already was solved in a very bad way, but I need to fix it quickly. Anyone knows some tricks to debug better it without open the frameworks code? Cheers, Felipe

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  • Spring MVC annotation config problem

    - by Seth
    I'm trying to improve my spring mvc configuration so as to not require a new config file for every servlet I add, but I'm running into problems. I've tried using this tutorial as a starting point, but I'm running into an issue that I can't figure out. The problem is that when I do a GET to my servlet, I get back a 404 error. Here's my config and a representative java snippet from a Controller: web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name>SightLogix Coordination System</display-name> <description>SightLogix Coordination System</description> <servlet> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <url-pattern>/slcs/*</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </context-param> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> </web-app> application-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd" default-init-method="init" default-destroy-method="destroy"> <mvc:annotation-driven /> <context:component-scan base-package="top.level" /> </beans> application-security.xml: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http> <intercept-url pattern="/**" access="ROLE_MANAGER" requires-channel="https" /> <http-basic /> </http> <authentication-manager> <authentication-provider user-service-ref="myUserDetailsService"> <password-encoder hash="sha"/> </authentication-provider> </authentication-manager> <beans:bean id="myUserDetailsService" class="path.to.my.UserDetailsServiceImpl"> </beans:bean> </beans:beans> Snippet of a Controller class (one of many, but they all look essentially like this): @Controller @RequestMapping("/foo.xml") public class FooController { @RequestMapping(method=RequestMethod.GET) public void handleGET(HttpServletRequest request, HttpServletResponse response) throws IOException { ... Can anyone tell me what I'm doing incorrectly? Thanks!

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  • How can I Convert XML to an Object using Spring 3.0 mvc while making RESTful request

    - by brock
    Hi, I'm using the Spring 3.0 RC1 framework and I'm currently testing out Spring mvc. I wanted to use Spring mvc to handle restful requests. I have set up my controller to handle the URI request. I am passing in xml with the request. So on the controller I have a method like follows: public void request(RequestObject request) { doSomething(); } I am having a hard time converting the xml to the RequestObject. I haven't seen much documentation on this and I was wondering if anyone could point me in the right direction. I'm guess that you would have to annotate the RequestObject using JAXB or something in order to tell Spring to convert the xml file to RequestObject but I'm not sure. Thanks for all of your help!!

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  • Migrate database from SQL Server Standard to SQL Server Express for DotNetNuke

    - by Bjørn
    Hello, we have an old server that we want to dedicate fully as a public webserver (hosting a few DotNetNuke sites), and for this purpose we would like to install SQL Server Express (probably 2008) on the server and thus have both the Database server and the Web Server on the machine. But: The databases for the webserver are hosted on a SQL Server 2005 Standard today. So the question is: Is it possible to move a database from a Standard Server to an Express Server?

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  • Windows Server 2003 Terminal Server does not give out all available licenses (solved)

    - by Erwin Blonk
    I installed the Terminal Server role in Windows Server 2003 Standard 64-bits. Still, only 2 connections are allowed. The License Manager says that there are 10 Device CALs available, which is correct, and that none are given out. For good measure I let the server reboot, to no effect. Before this, there was another server (same Windows, except that it is 32 bits) active as a licensing server. I removed the role first and then then added it to the new server. I then removed the Terminal Server Licensing Server component off the old one and added it to the new one. After that, I added to licenses. When that didn't give the required result, I rebooted to new server. Still, the new server, with licenses and all, acts as if it has the 2 license RDP. The server are all stand-alone, there is no active directory been set up. Both servers are in different workgroups. Update (4/12/10): The server has changed the entries in the Terminal Server Licensing a few times. After installing the licenses it added an entry of which the exact phrasing I forgot but it was about temporary Windows 2003 device licenses. Later it added Windows Server 2003 - TS Per Device CAL. The temporary held 2 licenses (standard RDP licenses, I think) and the other 10. At some point, seemingly unrelated from the testing we did, it used a licenses from the new pool. This morning, 2 licenses were used from the pool of 10 and only 1 from the temporary/RDP pool (I wish I had screenshots to show, it changed every few hours oir so it seems). Although I had already activated the server over the internet, and re-activated it, I decided to go through the whole procedure by phone. Update 2 (4/12/10) The problem has been solved. It seems the activation over the web, while it said to have succeeded, did not work correctly. After activating by phone, it did work. What was different from the old setup and what put me on the wrong foot from that moment, was that I now need to create seperate user account because a session with one user account will be taken over by someone else when that account is used by that person. On the previous server, it was possible to open several sesions with the same account. We now use Per Device licenses, I'm not sure what was used before. Thanks all for the replies.

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  • SQL Server Agent was not running on Server Dynamics CRM 2013

    - by No1_Melman
    I'm trying to install Dynamics CRM 2013 on a server. This server is on a VM. There are several other VMs, an ADDS & DNS, a MSSQL and a WebServer VM. Each server is a Windows Server 2012 R2. The SQL Server is 2012 Enterprise. Each VM is part of the main Domain, set by the ADDS & DNS. NSLookup confirms I can see the computer at the right IP address. Each separate VM has its own static IP, the DNS is set to the ADDS & DNS. I use the domain administrator to log into all the servers, and make the that domain administrator a local administrator. I've set up all the domain users for the CRM and gave them appropriate permissions, I have also added the accounts to the appropriate places, such that the CRM Deployment user is in the SQL security. The SQL Agent is running. SQL server configuration manager has SQL server network configuration TCP/IP enabled to allow remote connections. The SQL server has the domain user as a administrator, which is the same user being used to install the CRM. In the CRM setup i point to the [Servername]\[Instance] and I have also tried just the [Servername]. to make this easier I called the server MSSQL and left the instance name to the default. I even install the MSSQL instance as the domain administrator. CRM can find the ReportServer url. I have enable all the ports required, including: 135, 1433, 1434, 2382, 2383, 4022. 1434 UDP. I feel like I have absolutely done everything, I have google many times and tried all the different methods, and for the life of me I cant seem to get the CRM setup to find the SQL server agent. It passes everything else perfectly fine. I can even ping the MSSQL server. What is the problem, why does the CRM still keep giving the error: SQLSERVERAGENT (SQLSERVERAGENT) service is not running on the server MSSQL On the MSSQL server, the name of the sql server agent service is: SQL Server Agent (MSSQLSERVER)

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  • Linked server problem on SQL Server 2005

    - by BradyKelly
    I have a weird issue and I hope someone can steer me in the right direction for resolving this please. When I execute the following query against a linked server, I get the following error. I can connect to the server in SSMS as a separate server, and execute a similar query against its Deposits table. The nn.nn is my own replacement to avoid broadcasting our server addresses. The query: select td.Batch , td.DateTimeDeposited from Deposits cd left join [172.nn.nn.32\sqlexpress].Terminal.dbo.Deposits td on cd.DateTimeDeposited = td.DateTimeDeposited The error: OLE DB provider "SQLNCLI" for linked server "172.nn.nn.11\sqlexpress" returned message "Login timeout expired". OLE DB provider "SQLNCLI" for linked server "172.nn.nn.11\sqlexpress" returned message "An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections.". Msg 65535, Level 16, State 1, Line 0 SQL Network Interfaces: Error Locating Server/Instance Specified [xFFFFFFFF]. Notice how the error is about server 172.nn.nn.11 and not 172.nn.nn.32. SOLVED (STUPID ME): Somebody had added an extra bit to my query that was scrolled off-screen and was querying the 17.nn.nn.11 server.

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  • Can't access SQL Server 2008 from workstations, but can from server

    - by Kev
    We have an app that can use mssql2k or 2k8. We've been using 2k but I decided to try 2k8 to compare. I installed in on our win2k3 server alongside mssql2k. In the ODBC applet on the server, I was able to set up access to 2k8, and it passes the test at the end successfully, whether I tell it to use Windows Authentication or an sql login. The latter is how the app always accessed mssql2k. The app works fine from the server, but when I try it on a workstation (winxpsp3), I get a window titled, "Microsoft SQL Server Login" that says: Connection failed: SQLState: '01000' SQL Server Error: 53 [Microsoft][ODBC SQL Server Driver][DBNETLIB]ConnectionOpen (Connect()). Connection failed: SQLState: '08001' SQL Server ERror: 17 [Microsoft][ODBC SQL Server Driver][DBNETLIB]SQL Server does not exist or access denied. Then I get the ODBC login dialog, which I can't get to login correctly (I just keep getting the same error above), even copying and pasting a password after resetting it on the server, and whether "trusted" is checked or not. "Options" is disabled. The server was straight SERVERNAME for mssql2k, but for mssql2k8 it's called SERVERNAME\mssql2008. That works on the server, why not on the workstation? (Which I'm logged in as the same person on, BTW.)

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  • How to implement login page using Spring Security so that it works with Spring web flow?

    - by simon
    I have a web application using Spring 2.5.6 and Spring Security 2.0.4. I have implemented a working login page, which authenticates the user against a web service. The authentication is done by defining a custom authentincation manager, like this: <beans:bean id="customizedFormLoginFilter" class="org.springframework.security.ui.webapp.AuthenticationProcessingFilter"> <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> <beans:property name="defaultTargetUrl" value="/index.do" /> <beans:property name="authenticationFailureUrl" value="/login.do?error=true" /> <beans:property name="authenticationManager" ref="customAuthenticationManager" /> <beans:property name="allowSessionCreation" value="true" /> </beans:bean> <beans:bean id="customAuthenticationManager" class="com.sevenp.mobile.samplemgmt.web.security.CustomAuthenticationManager"> <beans:property name="authenticateUrlWs" value="${WS_ENDPOINT_ADDRESS}" /> </beans:bean> The authentication manager class: public class CustomAuthenticationManager implements AuthenticationManager, ApplicationContextAware { @Transactional @Override public Authentication authenticate(Authentication authentication) throws AuthenticationException { //authentication logic return new UsernamePasswordAuthenticationToken(principal, authentication.getCredentials(), grantedAuthorityArray); } The essential part of the login jsp looks like this: <c:url value="/j_spring_security_check" var="formUrlSecurityCheck"/> <form method="post" action="${formUrlSecurityCheck}"> <div id="errorArea" class="errorBox"> <c:if test="${not empty param.error}"> ${sessionScope["SPRING_SECURITY_LAST_EXCEPTION"].message} </c:if> </div> <label for="loginName"> Username: <input style="width:125px;" tabindex="1" id="login" name="j_username" /> </label> <label for="password"> Password: <input style="width:125px;" tabindex="2" id="password" name="j_password" type="password" /> </label> <input type="submit" tabindex="3" name="login" class="formButton" value="Login" /> </form> Now the problem is that the application should use Spring Web Flow. After the application was configured to use Spring Web Flow, the login does not work anymore - the form action to "/j_spring_security_check" results in a blank page without error message. What is the best way to adapt the existing login process so that it works with Spring Web Flow?

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  • ACL architechture for a Software As a service in Spring 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • How to read spring-application-context.xml and AnnotationConfigWebApplicationContext both in spring mvc

    - by Suvasis
    In case I want to read bean definitions from spring-application-context.xml, I would do this in web.xml file. <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> In case I want to read bean definitions through Java Configuration Class (AnnotationConfigWebApplicationContext), I would do this in web.xml <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <init-param> <param-name>contextConfigLocation</param-name> <param-value> org.package.MyConfigAnnotatedClass </param-value> </init-param> </servlet> How do I use both in my application. like reading beans from both configuration xml file and annotated class. Is there a way to load spring beans in xml file while we are using AppConfigAnnotatedClass to instantiate/use rest of the beans.

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  • SQL SERVER – Concat Strings in SQL Server using T-SQL – SQL in Sixty Seconds #035 – Video

    - by pinaldave
    Concatenating  string is one of the most common tasks in SQL Server and every developer has to come across it. We have to concat the string when we have to see the display full name of the person by first name and last name. In this video we will see various methods to concatenate the strings. SQL Server 2012 has introduced new function CONCAT which concatenates the strings much efficiently. When we concat values with ‘+’ in SQL Server we have to make sure that values are in string format. However, when we attempt to concat integer we have to convert the integers to a string or else it will throw an error. However, with the newly introduce the function of CONCAT in SQL Server 2012 we do not have to worry about this kind of issue. It concatenates strings and integers without casting or converting them. You can specify various values as a parameter to CONCAT functions and it concatenates them together. Let us see how to concat the values in Sixty Seconds: Here is the script which is used in the video. -- Method 1: Concatenating two strings SELECT 'FirstName' + ' ' + 'LastName' AS FullName -- Method 2: Concatenating two Numbers SELECT CAST(1 AS VARCHAR(10)) + ' ' + CAST(2 AS VARCHAR(10)) -- Method 3: Concatenating values of table columns SELECT FirstName + ' ' + LastName AS FullName FROM AdventureWorks2012.Person.Person -- Method 4: SQL Server 2012 CONCAT function SELECT CONCAT('FirstName' , ' ' , 'LastName') AS FullName -- Method 5: SQL Server 2012 CONCAT function SELECT CONCAT('FirstName' , ' ' , 1) AS FullName Related Tips in SQL in Sixty Seconds: SQL SERVER – Concat Function in SQL Server – SQL Concatenation String Function – CONCAT() – A Quick Introduction 2012 Functions – FORMAT() and CONCAT() – An Interesting Usage A Quick Trick about SQL Server 2012 CONCAT Function – PRINT A Quick Trick about SQL Server 2012 CONCAT function What would you like to see in the next SQL in Sixty Seconds video? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology, Video Tagged: Excel

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  • Howcan I get started with Spring Batch?

    - by C. Ross
    I'm trying to learn Spring Batch, but the startup guide is very confusing. Comments like You can get a pretty good idea about how to set up a job by examining the unit tests in the org.springframework.batch.sample package (in src/main/java) and the configuration in src/main/resources/jobs. aren't exactly helpful. Also I find the Sample project very complicated (17 non-empty Namespaces with 109 classes)! Is there a simpler place to get started with Spring Batch?

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  • RDS installation failure on 2012 R2 Server Core VM in Hyper-V Server

    - by Giles
    I'm currently installing a test-bed for my firms Infrastructure replacement. 10 or so Windows/Linux servers will be replaced by 2 physical servers running Hyper-V server. All services (DC, RDS, SQL) will be on Windows 2012 R2 Server Core VMs, Exchange on Server 2012 R2 GUI, and the rest are things like Elastix, MailArchiver etc, which aren't part of the equation thus far. I have installed Hyper-V server on a test box, and sucessfully got two virtual DC's running, SQL 2014 running, and 8.1 which I use for the RSAT tools. When trying to install RDS (The old fashioned kind, not the newer VDI(?) style), I get a failed installation due to the server not being able to reboot. A couple of articles have said not to do it locally, so I've moved on. Sitting at the Powershell prompt on the Domain Controller or SQL server (Both Server Core), I run the following commands: Import-Module RemoteDesktop New-SessionDeployment -ConnectionBroker "AlstersTS.Alsters.local" -SessionHost "AlstersTS.Alsters.local" The installation begins, carries on for 2 or 3 minutes, then I receive the following error message: New-SessionDeployment : Validation failed for the "RD Connection Broker" parameter. AlstersTS.Alsters.local Unable to connect to the server by using WindowsPowerShell remoting. Verify that you can connect to the server. At line:1 char:1 + NewSessionDeployment -ConnectionBroker "AlstersTS.Alsters.local" -SessionHost " ... + + CategoryInfo : NotSpecified: (:) [Write-Error], WriteErrorException + FullyQualifiedErrorID : Microsoft.PowerShell.Commands.WriteErrorException,New-SessionDeployment So far, I have: Triple, triple checked syntax. Tried various other commands, and a script to accomplish the same task. Checked DNS is functioning as it should. Checked to the best of my knowledge that AD is working as it should. Checked that the Network Service has the needed permissions. Created another VM and placed the two roles on different servers. Deleted all VMs, started again with a new domain name (Lather, rinse, repeat) Performed the whole installation on a second physical box running Hyper-V Server Pleaded with it Interestingly, if I perform the installation via a GUI installation, the thing just works! Now I know I could convert this to a Server Core role after installation, but this wouldn't teach me what was wrong in the first instance. I've probably got 10 pages through various Google searches, each page getting a little less relevant. The closest matches seem to have good information, but it doesn't seem to be the fix for my set-up. As a side note, I expected to be able to "tee" or "out-file" the error message into a text file, but couldn't get that to work either, so I've typed in the error message manually. Chaps, any suggestions, from the glaringly obvious, to the long-winded and complex? Thanks!

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  • What are annotations and how do they actually work for frameworks like Spring?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • What is annotations and how do it actually works for frameworks like Spring ?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • Uninstalling Reporting Server 2008 on Windows Server 2008

    - by Piotr Rodak
    Ha. I had quite disputable pleasure of installing and reinstalling and reinstalling and reinstalling – I think about 5 times before it worked – Reporting Server 2008 on Windows Server with the same year number in name. During my struggle I came across an error which seems to be not quite unfamiliar to some more unfortunate developers and admins who happen to uninstall SSRS 2008 from the server. I had the SSRS 2008 installed as named instance, SQL2008. I wanted to uninstall the server and install it to default instance. And this is when it bit me – not the first time and not the last that day . The setup complained that it couldn’t access a DLL: Error message: TITLE: Microsoft SQL Server 2008 Setup ------------------------------ The following error has occurred: Access to the path 'C:\Windows\SysWOW64\perf-ReportServer$SQL2008-rsctr.dll' is denied. For help, click: http://go.microsoft.com/fwlink?LinkID=20476&ProdName=Microsoft+SQL+Server&EvtSrc=setup.rll&EvtID=50000&ProdVer=10.0.1600.22&EvtType=0x60797DC7%25400x84E8D3C0 ------------------------------ BUTTONS: OK This is a screenshot that shows the above error: This issue seems to have a bit of literature dedicated to it and even seemingly a KB article http://support.microsoft.com/kb/956173 and a similar Connect item: http://connect.microsoft.com/SQLServer/feedback/details/363653/error-messages-when-upgrading-from-sql-2008-rc0-to-rtm The article describes issue as following: When you try to uninstall Microsoft SQL Server 2008 Reporting Services from the server, you may receive the following error message: An error has occurred: Access to the path 'Drive_Letter:\WINDOWS\system32\perf-ReportServer-rsctr.dll' is denied. Note Drive_Letter refers to the disc drive into which the SQL Server installation media is inserted. In my case, the Note was not true; the error pointed to a dll that was located in Windows folder on C:\, not where the installation media were. Despite this difference I tried to identify any processes that might be keeping lock on the dll. I downloaded Sysinternals process explorer and ran it to find any processes I could stop. Unfortunately, there was no such process. I tried to rerun the installation, but it failed at the same step. Eventually I decided to remove the dll before the setup was executed. I changed name of the dll to be able to restore it in case of some issues. Interestingly, Windows let me do it, which means that indeed, it was not locked by any process. I ran the setup and this time it uninstalled the instance without any problems:   To summarize my experience I should say – be very careful, don’t leave any leftovers after uninstallation – remove/rename any folders that are left after setup has finished. For some reason, setup doesn’t remove folders and certain files. Installation on Windows Server 2008 requires more attention than on Windows 2003 because of the changed security model, some actions can be executed only by administrator in elevated execution mode. In general, you have to get used to UAC and a bit different experience than with Windows Server 2003. Technorati Tags: SQL Server 2008,Windows Server 2008,SRS,Reporting Services

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  • Spring @PostConstruct function in a @Repository called multiple times

    - by Seth
    I have a DAO that I'm trying to inject into a couple different places: @Repository public class FooDAO { @Autowired private HibernateManager sessionFactory; @PostConstruct public void doSomeDatabaseStuff() throws DataAccessException { ... } } And my application-context.xml is a fairly simple context:component-scan: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd" default-init-method="init" default-destroy-method="destroy"> <context:component-scan base-package="top.level"/> </beans> The DAO is accessed from a couple servlets in my application server through @Autowired properties. As far as I understand, anything annotated with @Repository should default to being a singleton and thus doSomeDatabaseStuff() should only be called once (as is my intention). The problem is that I'm seeing doSomeDatabaseStuff() called multiple times. What's going on here? Have I set something up incorrectly? I'm using spring 3.0.0. Thanks for the help.

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  • SQL SERVER – History of SQL Server Database Encryption

    - by pinaldave
    I recently met Michael Coles and Rodeney Landrum the author of one of the kind book Expert SQL Server 2008 Encryption at SQLPASS in Seattle. During the conversation we ended up how Microsoft is evolving encryption technology. The same discussion lead to talking about history of encryption tools in SQL Server. Michale pointed me to page 18 of his book of encryption. He explicitly give me permission to re-produce relevant part of history from his book. Encryption in SQL Server 2000 Built-in cryptographic encryption functionality was nonexistent in SQL Server 2000 and prior versions. In order to get server-side encryption in SQL Server you had to resort to purchasing or creating your own SQL Server XPs. Creating your own cryptographic XPs could be a daunting task owing to the fact that XPs had to be compiled as native DLLs (using a language like C or C++) and the XP application programming interface (API) was poorly documented. In addition there were always concerns around creating wellbehaved XPs that “played nicely” with the SQL Server process. Encryption in SQL Server 2005 Prior to the release of SQL Server 2005 there was a flurry of regulatory activity in response to accounting scandals and attacks on repositories of confidential consumer data. Much of this regulation centered onthe need for protecting and controlling access to sensitive financial and consumer information. With the release of SQL Server 2005 Microsoft responded to the increasing demand for built-in encryption byproviding the necessary tools to encrypt data at the column level. This functionality prominently featured the following: Support for column-level encryption of data using symmetric keys or passphrases. Built-in access to a variety of symmetric and asymmetric encryption algorithms, including AES, DES, Triple DES, RC2, RC4, and RSA. Capability to create and manage symmetric keys. Key creation and management. Ability to generate asymmetric keys and self-signed certificates, or to install external asymmetric keys and certificates. Implementation of hierarchical model for encryption key management, similar to the ANSI X9.17 standard model. SQL functions to generate one-way hash codes and digital signatures, including SHA-1 and MD5 hashes. Additional SQL functions to encrypt and decrypt data. Extensions to the SQL language to support creation, use, and administration of encryption keys and certificates. SQL CLR extensions that provide access to .NET-based encryption functionality. Encryption in SQL Server 2008 Encryption demands have increased over the past few years. For instance, there has been a demand for the ability to store encryption keys “off-the-box,” physically separate from the database and the data it contains. Also there is a recognized requirement for legacy databases and applications to take advantage of encryption without changing the existing code base. To address these needs SQL Server 2008 adds the following features to its encryption arsenal: Transparent Data Encryption (TDE): Allows you to encrypt an entire database, including log files and the tempdb database, in such a way that it is transparent to client applications. Extensible Key Management (EKM): Allows you to store and manage your encryption keys on an external device known as a hardware security module (HSM). Cryptographic random number generation functionality. Additional cryptography-related catalog views and dynamic management views. SQL language extensions to support the new encryption functionality. The encryption book covers all the tools in its various chapter in one simple story. If you are interested how encryption evolved and reached to the stage where it is today, this book is must for everyone. You can read my earlier review of the book over here. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority Book Review, SQLAuthority News, T SQL, Technology Tagged: Encryption, SQL Server Encryption, SQLPASS

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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