Search Results

Search found 755 results on 31 pages for 'submitting'.

Page 2/31 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Submitting from from Colorbox iframe to parent window

    - by user281867
    I'm pretty new to colorbox and lovin-it. I've been trying to submit a form from Colorbox iframe to parent window but haven't had any luck. Any suggestions would be greatly appreciated! Here's my code. $('#CustomizeBuy').click(function(event){ event.preventDefault(); $(this).attr('action','customize-order.cfm'); parent.location.submit(); parent.$.fn.colorbox.close(); }); or $('#CustomizeBuy').click(function(event){ event.preventDefault(); document.QuickOrderForm.action ="customize-order.cfm"; $('#QuickOrderForm').submit(); parent.$.fn.colorbox.close(); });

    Read the article

  • Submitting a multidimensional array via POST with php

    - by Fireflight
    I have a php form that has a known number of columns (ex. top diameter, bottom diameter, fabric, colour, quantity), but has an unknown number of rows, as users can add rows as they need. I've discovered how to take each of the fields(columns) and place them into an array of their own. <input name="topdiameter['+current+']" type="text" id="topdiameter'+current+'" size="5" /> <input name="bottomdiameter['+current+']" type="text" id="bottomdiameter'+current+'" size="5" /> So what I end up with in the HTML is: <tr> <td><input name="topdiameter[0]" type="text" id="topdiameter0" size="5" /></td> <td><input name="bottomdiameter[0]" type="text" id="bottomdiameter0" size="5" /></td> </tr> <tr> <td><input name="topdiameter[1]" type="text" id="topdiameter0" size="5" /></td> <td><input name="bottomdiameter[1]" type="text" id="bottomdiameter0" size="5" /></td> </tr> ...and so on. What I would like to do now is take all the rows and columns put them into a multidimensional array and email the contents of that to the client (preferably in a nicely formatted table). I haven't been able to really comprehend how to combine all those inputs and selects into a nice array. At this point, I'm going to have to try to use several 1D arrays, although I have the idea that using a single 2D array would be a better practice than using several 1D arrays.

    Read the article

  • gwt/extjs - form not submitting

    - by msaif
    i have form tag received from designer. i need to submit the form from GWT given below. FormPanel form = null; Button submit = null; function onModuleLoad(){ form = FormPanel.wrap(DOM.getElementById("MyForm")); form.setEncoding(FormPanel.ENCODING_MULTIPART); submit = Button.wrap(DOM.getElementById("OK")); submit.addClickHandler(new ClickHandler() { public void onClick(ClickEvent event) { // button clicked confirmed form.submit(); } }); formSubmitHandler = form.addSubmitHandler(new SubmitHandler(){ public void onSubmit(SubmitEvent event) { } }); } but form was not submitted. designer wrote the following lines. form action="./a.cgi" method="post" name="MyForm" id="MyForm" input type="button" value="OK" form

    Read the article

  • Make fancybox jQuery plugin with results from submitting a form on same page

    - by Chase
    I am trying to take form results that are generated from a PHP call and populate them into a div that will then appear in a light box upon click of the submit button. So far I have successfully setup the form and am populating the results on the same page into a hidden div. I can make this div appear no problem in a light box by setting up a href link but cannot make it show up by simply by clicking the submit button. I know my fancybox and jQuery calls are good but not sure where I'm going wrong on the submit button. Here is what I have so far to make it work with a link: <script type="text/javascript"> $(document).ready(function(){ $("#various1").fancybox({ 'transitionIn' : 'none', 'transitionOut' : 'none', 'scrolling' : 'auto', 'overlayOpacity' : '0' }); }); </script> <a id="various1" href="#inline1" >Inline</a> <div style="display: none;"> <div id="inline1" style="width:500px;height:550px;"> Works great here when you click inline after I have submitted the form. Here is what I tried to make it work with the submit button: $(document).ready(function(){ $("#submit").click(function(){ alert('jQTest'); $("#various1").fancybox(); }); }); <input type="submit" name="submit" id="submit" value="--> Find" /> I think it has to be some way I'm calling the jQuery for the fancybox or some identifier for the submit button & div because the submit button click is registering fine. Suggestions?

    Read the article

  • What response Adobe Acrobat/Reader gets back after submitting form to a PHP script

    - by Laszlo
    Hi, PDF experts help needed, I am posting a form from PDF to a PHP script with Adobe Acrobat. I would like to set my PDF to display appropiate messages based upon some returned values. So I am looking for returned values... if there is any returned values after posting the form, how can I access them? Maybe, there is an option to set this in Adobe? Another thing: When the PDF form gets submitted and let's say I echo back a 'thank you' message from my form-handler PHP script, a new PDF gets created and opened displaying my message... is there a way to open that new message in the same window and close the form instead? Thanks, Laz

    Read the article

  • Submitting AjaxForm with jQuery in ASP.NET MVC

    - by Hadi Eskandari
    I have an ajax form in asp.net mvc which is as simple as this: <% using (this.Ajax.BeginForm("LatestBlogPosts", "Blog", null, new AjaxOptions { UpdateTargetId = "blogPostPanel" }, new { id = "BlogPostForm" })) { %> <div class="panel" id="blogPostPanel"> <img src="/images/ajax-loader.gif" alt="ajax-loader" /> </div> <% } %> I want to invoke the form submit when document is loaded. This should supposedly, call the controller's action and return a result that should be replaced with the placeholder DIV. If I add a SUBMIT button to the form, it works perfectly, but when I invoke the submit via jQuery, the whole page is refreshed, and the content returned by the server is displayed in the newly displayed page. Here's my jQuery code: <script type="text/javascript"> $(document).ready(function() { $("#BlogPostForm").submit(); }); </script> Anyway to do this?

    Read the article

  • Java Proxy Servlet for submitting files

    - by KevMo
    I'm attempting to use Panda with my GWT application. I can upload videos directly to my panda server using POST MY_PANDA_SERVER/videos/MY_VIDEO_ID/upload However I would like hide my panda server behind my J2EE (glassfish) server. I would like to achieve this: Start upload to some servlet on my J2EE server Authenticate user POST the file to my panda server while still uploading to servlet Ideally I would like to never store the file on the J2EE server, but just use it as a proxy to get to the panda server.

    Read the article

  • ASP MVC: Submitting a form with nested user controls

    - by Nigel
    I'm fairly new to ASP MVC so go easy :). I have a form that contains a number of user controls (partial views, as in System.Web.Mvc.ViewUserControl), each with their own view models, and some of those user controls have nested user controls within them. I intended to reuse these user controls so I built up the form using a hierarchy in this way and pass the form a parent view model that contains all the user controls' view models within it. For example: Parent Page (with form and ParentViewModel) -->ChildControl1 (uses ViewModel1 which is passed from ParentViewModel.ViewModel1 property) -->ChildControl2 (uses ViewModel2 which is passed from ParentViewModel.ViewModel2 property) -->ChildControl3 (uses ViewModel3 which is passed from ViewModel2.ViewModel3 property) I hope this makes sense... My question is how do I retrieve the view data when the form is submitted? It seems the view data cannot bind to the ParentViewModel: public string Save(ParentViewModel viewData)... as viewData.ViewModel1 and viewData.ViewModel2 are always null. Is there a way I can perform a custom binding? Ultimately I need the form to be able to cope with a dynamic number of user controls and perform an asynchronous submission without postback. I'll cross those bridges when I come to them but I mention it now so any answer won't preclude this functionality. Many thanks.

    Read the article

  • Form is submitting when the page loads

    - by RailAddict
    I have a really simple Rails app. Basically an article with comments. I want the article page to show the article, comments underneath and then a textbox to write a comment and a submit button to submit it. I got it all working except for one (big) problem. When the page loads.. example.com/article/1 a blank comment is submitted to the database. I fixed that by including "validates_presence_of :body" in the Comment model. But that results in the following image when the page loads: This is my code by the way: def show @place = Article.find(params[:id]) @comment = Article.find(params[:id]).comments.create(params[:comment]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @article } end end and <% form_for([@article, @comment]) do |f| %> <p> <%= f.label :commenter %><br /> <%= f.text_field :commenter %> </p> <p> <%= f.label :body %><br /> <%= f.text_area :body %> </p> <p> <%= f.submit "Create" %> </p> <% end %>

    Read the article

  • jQuery / jqGrids / Submitting form data troubles...

    - by Kelso
    Ive been messing with jqgrids alot of the last couple days, and I have nearly everything the way I want it from the display, tabs with different grids, etc. Im wanting to make use of Modal for adding and editing elements on my grid. My problem that Im running into is this. I have my editurl:"editsu.php" set, if that file is renamed, on edit, i get a 404 in the modal.. great! However, with that file in place, nothing at all seems to happen. I even put a die("testing"); line at the top, so it sees the file, it just doesnt do anything with it. Below is the content. ........ the index page jQuery("#landings").jqGrid({ url:'server.php?tid=1', datatype: "json", colNames:['ID','Tower','Sector', 'Client', 'VLAN','IP','DLink','ULink','Service','Lines','Freq','Radio','Serial','Mac'], colModel:[ {name:'id', index:'id', width : 50, align: 'center', sortable:true,editable:true,editoptions:{size:10}}, {name:'tower', index:'tower', width : 85, align: 'center', sortable:true,editable:false,editoptions:{readonly:true,size:30}}, {name:'sector', index:'sector', width : 50, align: 'center',sortable:true,editable:true,editoptions:{readonly:true,size:20}}, {name:'customer',index:'customer', width : 175, align: 'left', editable:true,editoptions:{readonly:true,size:35}}, {name:'vlan', index:'vlan', width : 35, align: 'left',editable:true,editoptions:{size:10}}, {name:'suip', index:'suip', width : 65, align: 'left',editable:true,editoptions:{size:20}}, {name:'datadl',index:'datadl', width:55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'dataul', index:'dataul', width : 55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'servicetype', index:'servicetype', width : 85, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from servicetype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'voicelines', index:'voicelines', width : 35, align: 'center',editable:true,editoptions:{size:30}}, {name:'freqname', index:'freqname', width : 35, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from freqband"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'radioname', index:'radioname', width : 120, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from radiotype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'serial', index:'serial', width : 100, align: 'right',editable:true,editoptions:{size:20}}, {name:'mac', index:'mac', width : 120, align: 'right',editable:true,editoptions:{size:20}} ], rowNum:20, rowList:[30,50,70], pager: '#pagerl', sortname: 'sid', mtype: "GET", viewrecords: true, sortorder: "asc", altRows: true, caption:"Landings", editurl:"editsu.php", height:420 }); jQuery("#landings").jqGrid('navGrid','#pagerl',{edit:true,add:true,del:false,search:false},{height:400,reloadAfterSubmit:false},{height:400,reloadAfterSubmit:false},{reloadAfterSubmit:false},{}); now for the editsu.php file.. $operation = $_REQUEST['oper']; if ($operation == "edit") { qquery("UPDATE customers SET vlan = '".$_POST['vlan']."', datadl = '".$_POST['datadl']."', dataul = '".$_POST['dataul']."', servicetype = '".$_POST['servicetype']."', voicelines = '".$_POST['voicelines']."', freqname = '".$_POST['freqname']."', radioname = '".$_POST['radioname']."', serial = '".$_POST['serial']."', mac = '".$_POST['mac']."' WHERE id = '".$_POST['id']."'") or die(mysql_error()); } Im just having a hard time troubleshooting this to figure out where its getting hung up at. My next question after this would be to see if its possible to make it so when you click "add", that it auto inserts a row into the db with a couple variable predtermined and then bring up the modal window, but ill work on the first problem first. thanks!

    Read the article

  • Ajax.BeginForm is submitting disabled form elements

    - by Fiffe
    Using MVC3 and Ajax.BeginForm I surprisingly discovered that mvc ajax forms submits elements with the attribute disabled="disabled". I have tested both select and text inputs. I was suprised because they should not be submited and they will not when using Html.BeginForm. Is there some hidden option or a workaround for this? [EDIT example] @using (Ajax.BeginForm("Action", "Control", new AjaxOptions() { HttpMethod = "POST" })) { <input type="text" name="_enabled" value="_enabled" /> <input type="text" name="_disabled" value="_disabled" disabled="disabled" /> <input type="submit" value="POST" /> }

    Read the article

  • Javascript : Submitting a form outside the actual form doesn't work

    - by Ben Fransen
    Hello all, I'm trying to achieve a fairly easy triggering mechanism for deleting multiple items from a tablegrid. If a user has enough access he/she is able to delete multiple users from a table. In the table I have set up checkboxes, one per row/user. The name of the checkboxes is UsersToDeletep[], and the value per row is the unique UserID. When a user clicks the button 'Delete selected users' a simple validation takes place to make sure at least one checkbox is selected. After that I call my simple function Submit(form). The function works perfectly when called within the form-tags, where I also use it to delete a single user. The function: function Submit(form) { document.forms[form].submit(); } I've also alerted document.forms[form]. The result is, as expected [object HTMLFormElement]. But for some reason the form just won't submit and a pagereload takes place. I'm a bit confused and can't seem to figure out what I'm doing wrong. Can anyone point me in the right direction? Thanks in advance! Ben

    Read the article

  • not getting a page reload when submitting a form on a page

    - by Bob Walsh
    When showing a project, the user can add a decision via a form_for and its partial. Is there some way of avoiding reloading the page and just creating the record silently? In the controller method (adddecision) I have: respond_to do |format| if @decision.save format.html { redirect_to(@project) } format.xml { head :ok } else format.html { render :action => "show" } format.xml { render :xml => decision.errors, :status => :unprocessable_entity } end I've tried redirect_to(:back) etc - still getting a page reload.

    Read the article

  • Javascript onunload form submit isn't submitting data

    - by Kevin
    I currently have form that checks if a user has unsubmitted changes when they leave the page with a function called through the onunload event. Here's the function: function saveOnExit() { var answer = confirm("You are about to leave the page. All unsaved work will be lost. Would you like to save now?"); if (answer) { document.main_form.submit(); } } And here's the form: <body onunload="saveOnExit()"> <form name="main_form" id="main_form" method="post" action="submit.php" onsubmit="saveScroll()"> <textarea name="comments"></textarea> <input type="submit" name="submit2" value="Submit!"/> </form> I'm not sure what I'm doing wrong here. The data gets submitted and saved in my database if I just press the submit button for the form. However, trying to submit the form through the onunload event doesn't result in anything being stored, from what I can tell. I've tried adding onclick alerts to the submitt button and onsubmit alerts to the form elements and I can verify that the submit button is being triggered and that the form does get submitted. However, nothing gets passed stored in the database. Any ideas as to what I'm doing wrong? Thanks.

    Read the article

  • How to preserve hyperlink when submitting via php form into MySQL

    - by TheTub
    Hi All, I've created a form that stores free text fields into a MySQL database. All works fine and the data is displayed back as intended when viewed. Except for one niggle. In an attempt to prevent malicious attacks I have used mysql_real_escape_string to remove any unwanted code from the input. However, I need to be able to preserve hyperlinks and basic html. For example, I want to store the following: <p align="left">Please follow this <a href="link.html">link</a></p> But the link is being stored as \"link.html\" as the quotes are being escaped. How can I preserve this link and other html? Many thank TT

    Read the article

  • Problem generating APN SSL certificate after submitting to apple store

    - by MikeQ
    I'm having trouble getting Apple to generate an APN SSL certificate for my app ID. I've submitted the application to the Apple store, and it is pending review. I tested the application using an Ad Hoc app ID "${bundle_id}.adHoc" and everything went fine. I submitted to the Apple store with app ID "${bundle_id}.release". Now I want to generate my production APN SSL certificate for use with my release application ID - but the developer portal doesn't want to. When I upload my certificate request, it sits for about a minute before telling me: "We are not able to generate your Profile at this time. Please try again later or try using the Provisioning Portal" Is it impossible to generate your certificate while the application is under review or something? Should I have generated it prior to submission?

    Read the article

  • Calling a method within Portlet when submitting form

    - by Roland
    I have a Portlet that contains a form. Now what I want to achieve is the following. 1) A Porlet containing a form is called within a page via <?php $this->widget('form'); ?> 2) The user fills in this form and clicks on submit "The submit button should be an ajax button" 3) When submit has been pressed the form should call a method within the form portlet class and the form should be replaced with a Thank you message. 4) I only want the current view in the portlet replaced with another view. My portlet class looks like this Yii::import('zii.widgets.CPortlet'); class Polls extends CPortlet{ public $usr_id=''; public function init(){ $cs = Yii::app()->clientScript; $cs->registerCoreScript('jquery'); parent::init(); } protected function renderContent(){ $this->render('form'); } public function update(){ $this->render('thankyou'); } } } Any advise, help would be highly appreciated.

    Read the article

  • jquery validate not submitting after modal close bootstrap

    - by Mariana Hernandez
    I have a modal where i insert some data, but when i open the modal, close it, and the click the modal show button again, it doesnt submit of course because the validate is "acting" in the modal, but i closed it so its not showing... how can i prevent this? thanks it is similar to this jquery functions within modal only work on first open, after close and re-open they stop working but my functions are <script> $(document).ready(function() { $("#myModal").modal('show'); }); </script> and the validation one <script> $(document).ready(function(){ $('#form1').validate( { ignore: "", rules: { usu_login: { required: true }, usu_password: { required: true }, usu_email: { required: true }, usu_nombre1: { required: true }, usu_apellido1: { required: true }, usu_fecha_nac: { required: true }, usu_cedula: { required: true }, usu_telefono1: { required: true }, rol_id: { required: true }, dependencia_id: { required: true }, }, highlight: function(element) { $(element).closest('.grupo').addClass('has-error'); if($(".tab-content").find("div.tab-pane.active:has(div.has-error)").length == 0) { $(".tab-content").find("div.tab-pane:hidden:has(div.has-error)").each(function(index, tab) { var id = $(tab).attr("id"); $('a[href="#' + id + '"]').tab('show'); }); } }, unhighlight: function(element) { $(element).closest('.grupo').removeClass('has-error'); } }); }); </script> So i dont know how to apply the answer of the above =(

    Read the article

  • Deselecting a form input and waiting for a function before submitting

    - by blcArmadillo
    I have a form with an input field where a user enters a unique identifier. I then have some jQuery code that upon the user moving away from the input field (blur) goes out and fetches details about the part and populates some fields on the page. The problem is if the user clicks the submit button before moving out of the input field the jQuery code never has a chance to load in the data and populate the necessary fields. Whats the best way to go about doing this? I thought about maybe setting the focus to body and then having an infinite loop that keeps checking the page until all fields that should be filled in have been filled in but I feel like some sort of event based solution would be better than unpredictable infinite loops. Any ideas?

    Read the article

  • Routing is using ID has action and action has ID after submitting a form

    - by Victor Martins
    I have a model User that has_one user_profile and a User_Profile belongs_to user in the User controller I have: def personal @user = User.find_by_id(params[:id]) @user_profile = @user.user_profile @user_profile ||= @user.build_user_profile end def update_personal @user = User.find_by_id(params[:id]) if @user.user_profile.update_attributes(params[:user_profile]) flash[:notice] = "OK" redirect_to @user else flash[:notice] = "Fail" render :action => 'update_personal' end end In my personal.html.erb view I have: <% semantic_form_for @user_profile, :url => { :action => "update_personal"} do |form| %> <%= form.inputs %> <%= form.buttons %> <%end%> And on the rountes I have: map.resources :users, :member => { :personal => :get, :update_personal => :put } Now the strange thing is that I can do: users/1/personal to see the form but when I submit I get this error: Unknown action No action responded to 1. It's trying to find an action with the name 1. Can anyone point me out on the right direction?

    Read the article

  • Codeigniter: Submitting Forms

    - by Kevin Brown
    How do I submit a form that can do two different things based on the URI? For example, if the URI contains a string "new" the form will submit differently than it would if "new" were not in the URI. I'm having trouble implementing this, as when a form is submitted, it takes the URI of whatever "form_open" says.

    Read the article

  • Submitting a form on 'Enter' with jQuery?

    - by b. e. hollenbeck
    I have a bog-standard login form - an email text field, a password field and a submit button on an AIR project that's using HTML/jQuery. When I hit Enter on the form, the entire form's contents vanish, but the form isn't submitted. Does anyone know if this is a Webkit issue (Adobe AIR uses Webkit for HTML), or if I've bunged things up? I tried: $('.input').keypress(function(e){ if(e.which == 13){ $('form#login').submit(); } }); But that neither stopped the clearing behavior, or submitted the form. There's no action associated with the form - could that be the issue? Can I put a javascript function in the action?

    Read the article

  • Submitting changes to 2 tables with C# linq only one table is changing

    - by Laurence Burke
    SO I am changing the values in 2 different tables and the only table changing is the address table any one know why? protected void btnSubmit_Click(object sender, EventArgs e) { TestDataClassDataContext dc = new TestDataClassDataContext(); var addr = (from a in dc.Addresses where a.AddressID == Convert.ToInt32(ddlAddList.SelectedValue) select a).FirstOrDefault(); var caddr = (from ca in dc.CustomerAddresses where addr.AddressID == ca.AddressID select ca).FirstOrDefault(); if (txtZip.Text != "" && txtAdd1.Text != "" && txtCity.Text != "") { addr.AddressLine1 = txtAdd1.Text; addr.AddressLine2 = txtAdd2.Text; addr.City = txtCity.Text; addr.PostalCode = txtZip.Text; addr.StateProvinceID = Convert.ToInt32(ddlState.SelectedValue); caddr.AddressTypeID = Convert.ToInt32(ddlAddrType.SelectedValue); dc.SubmitChanges(); lblErrMsg.Visible = false; lblSuccess.Visible = true; } else { lblErrMsg.Text = "Invalid Input"; lblErrMsg.Visible = true; } }

    Read the article

  • Referencing object's identity before submitting changes in LINQ

    - by Axarydax
    Hi, is there a way of knowing ID of identity column of record inserted via InsertOnSubmit beforehand, e.g. before calling datasource's SubmitChanges? Imagine I'm populating some kind of hierarchy in the database, but I wouldn't want to submit changes on each recursive call of each child node (e.g. if I had Directories table and Files table and am recreating my filesystem structure in the database). I'd like to do it that way, so I create a Directory object, set its name and attributes, then InsertOnSubmit it into DataContext.Directories collection, then reference Directory.ID in its child Files. Currently I need to call InsertOnSubmit to insert the 'directory' into the database and the database mapping fills its ID column. But this creates a lot of transactions and accesses to database and I imagine that if I did this inserting in a batch, the performance would be better. What I'd like to do is to somehow use Directory.ID before commiting changes, create all my File and Directory objects in advance and then do a big submit that puts all stuff into database. I'm also open to solving this problem via a stored procedure, I assume the performance would be even better if all operations would be done directly in the database.

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >