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  • OpenLDAP configuraion in Yast2 - groupOfUniqueNames/uniqueMember

    - by Ales
    hi all, in /etc/openldap/slapd.conf I have this acl and works: access to dn.subtree="ou=users,dc=domain" by group/groupofuniquenames/uniquemember="cn=partner,ou=groups,dc=domain" write by users read When I want to configure it in OpenSuSE 11.1 Yast2 LDAP server configuration it generates me file /etc/openldap/slap.d/cn=config/olcDatabase={1}bdb.ldif whit acl: olcAccess: {3}to dn.subtree="ou=users,dc=domain" by group="cn=partner,ou=groups,dc=domain" manage How can i set it from "by group" to "by group/groupofuniquenames/uniquemember" like in slapd.conf? thanks, Al

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  • Dynamically loading sub-trees into YUI Treeview

    - by user319399
    When you create a YUI TreeView instance, you can pass in an object that represents an entire tree, and it will automatically build up the TextNodes for you. I'd like to send in a partial tree, such that the tree only goes, say, 2 levels deep, and anything deeper than that will invoke dynamic loading. I've got that much working. Now for the interesting part. In the dynamic loading callback I give to my tree instance, I want to again be able to just give YUI a big object representing more of the tree. I want to do something like this: // data is a array of objects organized into a tree, with some nodes requiring dynamic loading when they are navigated to tree = new YAHOO.widget.TreeView("treeDiv1", data); tree.setDynamicLoad(loadDataForNode); function loadDataForNode(node, onCompleteCallback) { if(node.children.length==0) { var subTree = { "label":"Cars", isLeaf:false, children:[ { "label":"Chevy", isLeaf:true }, { "label":"Ford", isLeaf:true }, ] }; // doesn't work, even though it has the required "label" field var tempNode = new YAHOO.widget.TextNode(subTree, node, true); } onCompleteCallback(); } Is this possible? Or do I have to iterate over all the nodes in my subtree and construct individual TextNodes for each one? Thanks much...

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  • How to combine two separate unrelated Git repositories into one with single history timeline

    - by Antony
    I have two unrelated (not sharing any ancestor check in) Git repositories, one is a super repository which consists a number of smaller projects (Lets call it repository A). Another one is just a makeshift local Git repository for a smaller project (lets call it repository B). Graphically, it would look like this A0-B0-C0-D0-E0-F0-G0-HEAD (repo A) A0-B0-C0-D0-E0-F0-G0-HEAD (remote/master bare repo pulled & pushed from repo A) A1-B1-C1-D1-E1-HEAD (repo B) Ideally, I would really like to merge repo B into repo A with a single history timeline. So it would appear that I originally started project in repo A. Graphically, this would be the ideal end result A0-A1-B1-B0-D1-C0-D0-E0-F0-G0-E1-H(from repo B)-HEAD (new repo A) A0-A1-B1-B0-D1-C0-D0-E0-F0-G0-E1-H(from repo B)-HEAD (remote/master bare repo pulled & pushed from repo A) I have been doing some reading with submodules and subtree (Pro Git is a pretty good book by the way), but both of them seem to cater solution towards maintaining two separate branch with sub module being able to pull changes from upstream and subtree being slightly less headache. Both solution require additional and specialized git commands to handle check ins and sync between master and sub tree/module branch. Both solution also result in multiple time-lines (with --squash you even get 3 timelines with subtree). The closest solution from SO seems to talk about "graft", but is that really it? The goal is to have a single unified repository where I can pull/push check-ins, so that there are no more repo B, just repo A in the end.

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  • Powershell - how to set multiple action on get-aduser "dataset"

    - by Patrick Pellegrino
    I'm trying to run a script that modify password for multiple AD user accounts, enable the accounts and force a password change at next logon. I use this code but that's not work : Get-ADUSER -Filter * -SearchScope Subtree -SearchBase "OU=myou,OU=otherou,DC=mydc,DC=local" | Set-ADAccountPassword -Reset -NewPassword (ConvertTo-SecureString -AsPlainText "NewPassord" -Force) | Enable-ADAccount | Set-ADUSER -ChangePasswordAtLogon $true If I run the Get-ADuser line with ONLY one of the other line that's run fine ex : Get-ADUSER -Filter * -SearchScope Subtree -SearchBase "OU=myou,OU=otherou,DC=mydc,DC=local" | Enable-ADAccount Where I'm wrong ? I'm new to PowerShell probably I'm misunderstanding something.

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  • Scripting help - need to get phone number of AD accounts and then add them to contacts in trusted domain

    - by TheCleaner
    I have domain accounts that I have created as contacts in another trusted domain so that they can see them in their Exchange GAL. I need a way to extract the phone number field from UserA (user account) in DomainA and import it into UserA (contact) in DomainB. I get the logic, it's just the code (vbscript/powershell/whatever) that eludes me. The logic as I see it: Connect to source AD (ou/subtree) Extract user accounts from OU and subcontainers including first name, last name, display name, and phone number Connect to target AD (ou/subtree) Verify/match contact with extract in #2 above based on display name Update phone field with phone number in extract Write log of success and failures Anybody able to help?

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  • C# failing LDAP queries

    - by jpkomick
    I'm trying to access an LDAP directory via the SearchRequest object in C#. I can make the same calls via an LDAP library running in and iPhone app, as well as directly via a terminal session. However, the C# queries all seem to fail. var search = new SearchRequest("ou=calendar,dc=ualberta,dc=ca", "term=*,course=094398,class=*", System.DirectoryServices.Protocols.SearchScope.Subtree, attributeLst); This returns a list of terms for the course calendar. However, making the following calls won't return results for specific courses var search = new SearchRequest("ou=calendar,dc=ualberta,dc=ca", "term=1330,course=094398", System.DirectoryServices.Protocols.SearchScope.Subtree, attributeLst); The attributeLst object has proper attribute names included, but the query always returns with zero results. Any suggestions anyone has would be greatly appreciated. Thanks.

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  • Best way to version control a WCF application with Git?

    - by Sam
    Suppose I have the following projects. The format is [ProjectName] : [ProjectDependency1, ProjectDependency2, etc.] // Service CoolLibrary WcfApp.Core WcfApp.Contracts WcfApp.Services : CoolLibrary, WcfApp.Core, WcfApp.Contracts // Clients CustomerX.App : WcfApp.Contracts CustomerY.App : WcfApp.Contracts CustomerZ.App : WcfApp.Contracts (On a side note, WcfApp.Contracts should not depend on WcfApp.Core, right? Else CustomerX.App would also depend on and thus be exposed to the service domain model?) (CoolLibrary is shared with other applications, so I can't just put it inside of WcfApp.Services.) All of this code is in-house. I was thinking of having 6 repositories for this. The format is [repository folder name] : [Projects included in repository.] 1. CoolLibrary.git : CoolLibrary 2. WcfApp.Contracts.git : WcfApp.Contracts 3. WcfApp.git : WcfApp.Core, WcfApp.Services 4. CustomerX.App.git : CustomerX.App 5. CustomerY.App.git : CustomerY.App 6. CustomerZ.App.git : CustomerZ.App How should I manage my project dependencies? I see three options: I could use binaries which I have to manually copy to each dependent repository. This would be easiest at the start, but my repositories would be a little bloated, and it'd become more tedious as I add more client apps for customers. I could import dependent code as submodules. This is what I will probably end up doing, although I keep reading on the web that submodules are a hassle. I also read that I can use something called the subtree merge strategy, but I am not sure how it is different from just cloning the repo into a subdirectory and adding the subdirectory to .gitignore. Is the difference that the subtree is recorded in the master repository, so (for example) cloning it from a different location will also pull the subtree? I know I asked a lot of questions in this post, but the most important two questions I have are: 1. Am I using the right number and layout of repositories? Should I use less or more? 2. Which of the three dependency management strategies would you recommend? Is there another strategy I haven't considered?

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  • How to implement a tiered "selection tree" in Swing? (Or: is there an existing implementation?)

    - by Sbodd
    I need a Swing component that will let me display a tree-structured list of items, and allow the user to select or de-select an arbitrary subset of those items, with the ability to select or deselect an entire subtree's worth of components by picking that subtree's parent. (Basically, something similar to the Eclipse "Export JAR file's" dialog (an image of the relevant dialog is here - I basically want the "Select resources to export" component, but for a Swing application.) I know I can do this by creating a custom TreeCellRenderer, a custom TreeCellEditor, and a custom TreeModel - but that seems like an awful lot of work. Are there any good off-the-shelf implementations that I can use? Thanks!

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  • Constructing a Binary Tree from its traversals

    - by user991710
    I'm trying to construct a binary tree (unbalanced), given its traversals. I'm currently doing preorder + inorder but when I figure this out postorder will be no issue at all. I realize there are some question on the topic already but none of them seemed to answer my question. I've got a recursive method that takes the Preorder and the Inorder of a binary tree to reconstruct it, but is for some reason failing to link the root node with the subsequent children. Note: I don't want a solution. I've been trying to figure this out for a few hours now and even jotted down the recursion on paper and everything seems fine... so I must be missing something subtle. Here's the code: public static <T> BinaryNode<T> prePlusIn( T[] pre, T[] in) { if(pre.length != in.length) throw new IllegalArgumentException(); BinaryNode<T> base = new BinaryNode(); base.element = pre[0]; // * Get root from the preorder traversal. int indexOfRoot = 0; if(pre.length == 0 && in.length == 0) return null; if(pre.length == 1 && in.length == 1 && pre[0].equals(in[0])) return base; // * If both arrays are of size 1, element is a leaf. for(int i = 0; i < in.length -1; i++){ if(in[i].equals(base.element)){ // * Get the index of the root indexOfRoot = i; // in the inorder traversal. break; } // * If we cannot, the tree cannot be constructed as the traversals differ. else throw new IllegalArgumentException(); } // * Now, we recursively set the left and right subtrees of // the above "base" root node to whatever the new preorder // and inorder traversals end up constructing. T[] preleft = Arrays.copyOfRange(pre, 1, indexOfRoot + 1); T[] preright = Arrays.copyOfRange(pre, indexOfRoot + 1, pre.length); T[] inleft = Arrays.copyOfRange(in, 0, indexOfRoot); T[] inright = Arrays.copyOfRange(in, indexOfRoot + 1, in.length); base.left = prePlusIn( preleft, inleft); // * Construct left subtree. base.right = prePlusIn( preright, inright); // * Construc right subtree. return base; // * Return fully constructed tree } Basically, I construct additional arrays that house the pre- and inorder traversals of the left and right subtree (this seems terribly inefficient but I could not think of a better way with no helpers methods). Any ideas would be quite appreciated. Side note: While debugging it seems that the root note never receives the connections to the additional nodes (they remain null). From what I can see though, that should not happen... EDIT: To clarify, the method is throwing the IllegalArgumentException @ line 21 (else branch of the for loop, which should only be thrown if the traversals contain different elements.

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  • PHP XML Strategy: Parsing DOM to fill "Bean"

    - by Mike
    I have a question concerning a good strategy on how to fill a data "bean" with data inside an xml file. The bean might look like this: class Person { var $id; var $forename = ""; var $surname = ""; var $bio = new Biography(); } class Biography { var $url = ""; var $id; } the xml subtree containing the info might look like this: <root> <!-- some more parent elements before node(s) of interest --> <person> <name pre="forename"> Foo </name> <name pre="surname"> Bar </name> <id> 1254 </id> <biography> <url> http://www.someurl.com </url> <id> 5488 </id> </biography> </person> </root> At the moment, I have one approach using DOMDocument. A method iterates over the entries and fills the bean by "remembering" the last node. I think thats not a good approach. What I have in mind is something like preconstructing some xpath expression(s) and then iterate over the subtrees/nodeLists. Return an array containing the beans as defined above eventually. However, it seems not to be possible reusing a subtree /DOMNode as DOMXPath constructor parameter. Has anyone of you encountered such a problem?

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  • Sharepoint Active directory forms authentication

    - by Sushant
    Hi, I am devloping a sharepoint website in Forms authentication mode. I am trying to authenticate myself/ my company users against company's active directory. The ldap path I received from my technical team is LDAP://infinmumcfac.inf.com OU=Infotech,DC=inf,DC=com I got this piece of code from microsoft site. <membership defaultProvider="LdapMembershipProvider"> <providers> <add name="LdapMembership" type="Microsoft.Office.Server.Security.LDAPMembershipProvider, Microsoft.Office.Server, Version=12.0.0.0, Culture=neutral, PublicKeyToken=71E9BCE111E9429C" server="DC" port="389" useSSL="false" userDNAttribute="distinguishedName" userNameAttribute="sAMAccountName" userContainer="CN=Users,DC=userName,DC=local" userObjectClass="person" userFilter="(|(ObjectCategory=group)(ObjectClass=person))" scope="Subtree" otherRequiredUserAttributes="sn,givenname,cn" /> </providers> </membership> The site asked me to change the Server and Usercontainer attribute. I have modified the code to <membership defaultProvider="LdapMembershipProvider"> <providers> <add name="LdapMembership" type="Microsoft.Office.Server.Security.LDAPMembershipProvider, Microsoft.Office.Server, Version=12.0.0.0, Culture=neutral, PublicKeyToken=71E9BCE111E9429C" server=” infinmumcfac.inf.com” port="389" useSSL="false" userDNAttribute="distinguishedName" userNameAttribute="sAMAccountName" userContainer=" OU=Infotech,DC=inf,DC=com " userObjectClass="person" userFilter="(|(ObjectCategory=group)(ObjectClass=person))" scope="Subtree" otherRequiredUserAttributes="sn,givenname,cn" /> </providers> </membership> I placed this code in web.config file of central administration site and my sharepoint website . I am still facing login issues. Any help or insight would be highly grateful.Thanking in anticipation.

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  • LDAP (slapd) ACL issue - can add but not modify entries

    - by Jonas
    I have an issue with the ACL configuration of an LDAP server (slapd). The following ACL entry is active as the first rule that applies: {0}to dn.subtree="ou=some,ou=where,ou=beneath,dc=the,dc=rain,dc=bow" attrs=entry,children by users write Now the strange thing that happens is that given that rule I can add an entry to the respective DN but if I want to modify it with the very same user, then I get 0x32 (LDAP_INSUFFICIENT_ACCESS) Can someone give me a hint what the problem could be?

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  • How do implement a breadth first traversal?

    - by not looking for answer
    //This is what I have. I thought pre-order was the same and mixed it up with depth first! import java.util.LinkedList; import java.util.Queue; public class Exercise25_1 { public static void main(String[] args) { BinaryTree tree = new BinaryTree(new Integer[] {10, 5, 15, 12, 4, 8 }); System.out.print("\nInorder: "); tree.inorder(); System.out.print("\nPreorder: "); tree.preorder(); System.out.print("\nPostorder: "); tree.postorder(); //call the breadth method to test it System.out.print("\nBreadthFirst:"); tree.breadth(); } } class BinaryTree { private TreeNode root; /** Create a default binary tree */ public BinaryTree() { } /** Create a binary tree from an array of objects */ public BinaryTree(Object[] objects) { for (int i = 0; i < objects.length; i++) { insert(objects[i]); } } /** Search element o in this binary tree */ public boolean search(Object o) { return search(o, root); } public boolean search(Object o, TreeNode root) { if (root == null) { return false; } if (root.element.equals(o)) { return true; } else { return search(o, root.left) || search(o, root.right); } } /** Return the number of nodes in this binary tree */ public int size() { return size(root); } public int size(TreeNode root) { if (root == null) { return 0; } else { return 1 + size(root.left) + size(root.right); } } /** Return the depth of this binary tree. Depth is the * number of the nodes in the longest path of the tree */ public int depth() { return depth(root); } public int depth(TreeNode root) { if (root == null) { return 0; } else { return 1 + Math.max(depth(root.left), depth(root.right)); } } /** Insert element o into the binary tree * Return true if the element is inserted successfully */ public boolean insert(Object o) { if (root == null) { root = new TreeNode(o); // Create a new root } else { // Locate the parent node TreeNode parent = null; TreeNode current = root; while (current != null) { if (((Comparable)o).compareTo(current.element) < 0) { parent = current; current = current.left; } else if (((Comparable)o).compareTo(current.element) > 0) { parent = current; current = current.right; } else { return false; // Duplicate node not inserted } } // Create the new node and attach it to the parent node if (((Comparable)o).compareTo(parent.element) < 0) { parent.left = new TreeNode(o); } else { parent.right = new TreeNode(o); } } return true; // Element inserted } public void breadth() { breadth(root); } // Implement this method to produce a breadth first // search traversal public void breadth(TreeNode root){ if (root == null) return; System.out.print(root.element + " "); breadth(root.left); breadth(root.right); } /** Inorder traversal */ public void inorder() { inorder(root); } /** Inorder traversal from a subtree */ private void inorder(TreeNode root) { if (root == null) { return; } inorder(root.left); System.out.print(root.element + " "); inorder(root.right); } /** Postorder traversal */ public void postorder() { postorder(root); } /** Postorder traversal from a subtree */ private void postorder(TreeNode root) { if (root == null) { return; } postorder(root.left); postorder(root.right); System.out.print(root.element + " "); } /** Preorder traversal */ public void preorder() { preorder(root); } /** Preorder traversal from a subtree */ private void preorder(TreeNode root) { if (root == null) { return; } System.out.print(root.element + " "); preorder(root.left); preorder(root.right); } /** Inner class tree node */ private class TreeNode { Object element; TreeNode left; TreeNode right; public TreeNode(Object o) { element = o; } } }

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  • How do I clone over HTTP a repository that has no info/refs?

    - by gbacon
    Given a repository served over HTTP whose owner forgot to chmod +x hooks/post-update, is there a workaround for cloning it? I tried running wget --mirror url, but rather than fetching the subtree only, it tried to mirror the entire site—which I assume happened due to the parent-directory links in the autogenerated index.html resources.

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  • JPA 2 and Hibernate 3.5.1 MEMBER OF query doesnt work.

    - by Ed_Zero
    I'm trying the following JPQL and it fails misserably: Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); I get the following exception: ERROR [main] PARSER.error(454) | <AST>:0:0: unexpected end of subtree java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] ERROR [main] PARSER.error(454) | <AST>:0:0: expecting "from", found '<ASTNULL>' ... ... Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected end of subtree [SELECT u FROM com.online.data.User u WHERE 'admin' MEMBER OF u.roles] I have Spring 3.0.1.RELEASE, Hibernate 3.5.1-Final and maven to glue dependencies. User class: @Entity public class User { @Id @Column(name = "USER_ID") @GeneratedValue(strategy = GenerationType.IDENTITY) private long id; @Column(unique = true, nullable = false) private String username; private boolean enabled; @ElementCollection private Set<String> roles = new HashSet<String>(); ... } Spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/tx/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd"> <!-- Reading annotation driven configuration --> <tx:annotation-driven transaction-manager="transactionManager" /> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" /> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> <property name="maxActive" value="100" /> <property name="maxWait" value="1000" /> <property name="poolPreparedStatements" value="true" /> <property name="defaultAutoCommit" value="true" /> </bean> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="databasePlatform" value="${hibernate.dialect}" /> </bean> </property> <property name="loadTimeWeaver"> <bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" /> </property> <property name="jpaProperties"> <props> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.current_session_context_class">thread</prop> <prop key="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.format_sql">false</prop> <prop key="hibernate.show_comments">true</prop> </props> </property> <property name="persistenceUnitName" value="punit" /> </bean> <bean id="JpaTemplate" class="org.springframework.orm.jpa.JpaTemplate"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> </beans> Persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence"> <persistence-unit name="punit" transaction-type="RESOURCE_LOCAL" /> </persistence> pom.xml maven dependencies. <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate</artifactId> <version>${hibernate.version}</version> <type>pom</type> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-core</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-annotations</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-entitymanager</artifactId> <version>${hibernate.version}</version> </dependency> <dependency> <groupId>commons-dbcp</groupId> <artifactId>commons-dbcp</artifactId> <version>1.2.2</version> <type>jar</type> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-web</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-config</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-taglibs</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework.security</groupId> <artifactId>spring-security-acl</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>javax.annotation</groupId> <artifactId>jsr250-api</artifactId> <version>1.0</version> </dependency> <properties> <!-- Application settings --> <spring.version>3.0.1.RELEASE</spring.version> <hibernate.version>3.5.1-Final</hibernate.version> Im running a unit test to check the configuration and I am able to run other JPQL queries the only ones that I am unable to run are the IS EMPTY, MEMBER OF conditions. The complete unit test is as follows: TestIntegration @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "/spring/dataLayer.xml"}) @Transactional @TransactionConfiguration public class TestUserDaoImplIntegration { @PersistenceContext private EntityManager em; @Test public void shouldTest() throws Exception { try { //WORKS Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' in elements(u.roles)"); List users = query.query.getResultList(); //DOES NOT WORK } catch (Exception e) { e.printStackTrace(); throw e; } try { Query query = em.createQuery("SELECT u FROM User u WHERE 'admin' MEMBER OF u.roles"); List users = query.query.getResultList(); } catch (Exception e) { e.printStackTrace(); throw e; } } }

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  • Problems in Binary Search Tree

    - by user2782324
    This is my first ever trial at implementing the BST, and I am unable to get it done. Please help The problem is that When I delete the node if the node is in the right subtree from the root or if its a right child in the left subtree, then it works fine. But if the node is in the left subtree from root and its any left child, then it does not get deleted. Can someone show me what mistake am I doing?? the markedNode here gets allocated to the parent node of the node to be deleted. the minValueNode here gets allocated to a node whose left value child is the smallest value and it will be used to replace the value to be deleted. package DataStructures; class Node { int value; Node rightNode; Node leftNode; } class BST { Node rootOfTree = null; public void insertintoBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { Node newNode = new Node(); newNode.value = value; rootOfTree = newNode; newNode.rightNode = null; newNode.leftNode = null; } else { while (true) { if (value >= markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.rightNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.leftNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } } } } public void searchBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { System.out.println("Element Not Found"); } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { System.out.println("Element Not Found"); break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { System.out.println("Element Not Found"); break; } } if (value == markedNode.value) { System.out.println("Element Found"); break; } } } } public void deleteFromBST(int value) { Node markedNode = rootOfTree; Node minValueNode = null; if (rootOfTree == null) { System.out.println("Element Not Found"); return; } if (rootOfTree.value == value) { if (rootOfTree.leftNode == null && rootOfTree.rightNode == null) { rootOfTree = null; return; } else if (rootOfTree.leftNode == null ^ rootOfTree.rightNode == null) { if (rootOfTree.rightNode != null) { rootOfTree = rootOfTree.rightNode; return; } else { rootOfTree = rootOfTree.leftNode; return; } } else { minValueNode = rootOfTree.rightNode; if (minValueNode.leftNode == null) { rootOfTree.rightNode.leftNode = rootOfTree.leftNode; rootOfTree = rootOfTree.rightNode; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node rootOfTree.value = minValueNode.leftNode.value; // The value has been swapped if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { break; } else { markedNode = markedNode.rightNode; } } else { System.out.println("Element Not Found"); return; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { break; } else { markedNode = markedNode.leftNode; } } else { System.out.println("Element Not Found"); return; } } } // Parent of the required element found // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { if (markedNode.rightNode.rightNode == null && markedNode.rightNode.leftNode == null) { markedNode.rightNode = null; return; } else if (markedNode.rightNode.rightNode == null ^ markedNode.rightNode.leftNode == null) { if (markedNode.rightNode.rightNode != null) { markedNode.rightNode = markedNode.rightNode.rightNode; return; } else { markedNode.rightNode = markedNode.rightNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.rightNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { if (markedNode.leftNode.rightNode == null && markedNode.leftNode.leftNode == null) { markedNode.leftNode = null; return; } else if (markedNode.leftNode.rightNode == null ^ markedNode.leftNode.leftNode == null) { if (markedNode.leftNode.rightNode != null) { markedNode.leftNode = markedNode.leftNode.rightNode; return; } else { markedNode.leftNode = markedNode.leftNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.leftNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// } } } } } } public class BSTImplementation { public static void main(String[] args) { BST newBst = new BST(); newBst.insertintoBST(19); newBst.insertintoBST(13); newBst.insertintoBST(10); newBst.insertintoBST(20); newBst.insertintoBST(5); newBst.insertintoBST(23); newBst.insertintoBST(28); newBst.insertintoBST(16); newBst.insertintoBST(27); newBst.insertintoBST(9); newBst.insertintoBST(4); newBst.insertintoBST(22); newBst.insertintoBST(17); newBst.insertintoBST(30); newBst.insertintoBST(40); newBst.deleteFromBST(5); newBst.deleteFromBST(4); newBst.deleteFromBST(9); newBst.deleteFromBST(10); newBst.deleteFromBST(13); newBst.deleteFromBST(16); newBst.deleteFromBST(17); newBst.searchBST(5); newBst.searchBST(4); newBst.searchBST(9); newBst.searchBST(10); newBst.searchBST(13); newBst.searchBST(16); newBst.searchBST(17); System.out.println(); newBst.deleteFromBST(20); newBst.deleteFromBST(23); newBst.deleteFromBST(27); newBst.deleteFromBST(28); newBst.deleteFromBST(30); newBst.deleteFromBST(40); newBst.searchBST(20); newBst.searchBST(23); newBst.searchBST(27); newBst.searchBST(28); newBst.searchBST(30); newBst.searchBST(40); } }

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  • Enable basic auth sitewide and disabling it for subpages?

    - by piquadrat
    I have a relatively straight forward config: upstream appserver-1 { server unix:/var/www/example.com/app/tmp/gunicorn.sock fail_timeout=0; } server { listen 80; server_name example.com; location / { proxy_pass http://appserver-1; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; auth_basic "Restricted"; auth_basic_user_file /path/to/htpasswd; } location /api/ { auth_basic off; } } The goal is to use basic auth on the whole website, except on the /api/ subtree. While it does work with respect to basic auth, other directives like proxy_pass are not in effect on /api/ as well. Is it possible to just disable basic auth while retaining the other directives without copy&pasting everything?

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  • Ubuntu 11.04 and OpenLDAP - where is the config?

    - by Tom SKelley
    I've been asked to setup a multimaster LDAP environment on Ubuntu 11.04 - instead of a single master server. I cloned the master server and recreated it into two VMs. I am trying to follow the instructions on the OpenLDAP documentation here: http://www.openldap.org/doc/admin24/replication.html and it talks about modifying the cn=config tree within LDAP. The subdirectory tree appears to be there at: /etc/ldap/slapd.d/ and a slapcat -b cn=config drops out a load of config information. When I try to connect using a browser and the admin bind credentials: ldapsearch -D '<adminDN>' -w <password> -b 'cn=config' I get: # extended LDIF # # LDAPv3 # base <> (default) with scope subtree # filter: (objectclass=*) # requesting: ALL # # search result search: 2 result: 32 No such object I don't see the config context when I connect via an LDAP browser either. I'm sure I'm missing something, but I can't see what it is!

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  • Merging Two Git Repositories with branches

    - by Joel K
    I realize there's a Stack Overflow question: http://stackoverflow.com/questions/277029/combining-multiple-git-repositories But I haven't found git-stitch-repo to be quite the tool I'm looking for. I also consider this more of a sysadmin task. How do I take code from an external repository and combine it with code from a primary repository while maintaining history/diffs and branches. Use case: An outside development team using SVN has ported to git and now wants to 'merge' their code in to the main company's git repo. I've tried subtree merges, but I lose the history. I've tried git-stitch-repo, but that process results in an entirely new repo that's missing branches. I just want to slot in some outside code as a sub-directory in our current main repo with as little disruption as possible and while maintaining the other project's history. Any success stories out there?

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  • Trac permission denied for SVN repo

    - by plesatejvlk
    I'm running Apache2,SVN & Trac on OpenSUSE. SVN works like a charm. I've initialized trac environment for one of my SVN repositories for trac to show source code in it's repo browser and I set the repository up in the Trac web admin. I also ran the trac-admin resync for that repo without problems. Trouble is when I open the Trac repo browser I get: "can't open file: /srv/svn/repos/myrepo/format, access denied)" error. I checked the permissions and: apache runs as wwwrun tracd runs as wwwrun the whole subtree /srv/svn/... belongs to svn group and the group has rw perms all the way down to the "format" file wwwrun is in the svn group I also did the perms check: $ sudo -u wwwrun cat /srv/svn/repos/myrepo/format and got it printed out without trouble. So in my opinion there shoud not be any permission conflict. Any idea what else to check? Thanks in advance!

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  • ldap client cannot contact ldap server

    - by Van
    I have followed these instructions: https://help.ubuntu.com/12.04/serverguide/openldap-server.html#openldap-auth-config The ldap server works fine. I can log into it using an ldap account. However, I configured another Ubuntu 12.04 server as a ldap client for authentication but I cannot contact the server. Here is the error: On the client: # ldapsearch -Q -LLL -Y EXTERNAL -H ldapi://ldap01.domain.local -b cn=config dn ldap_sasl_interactive_bind_s: Can't contact LDAP server (-1) The server can receive requests: On the client: # telnet ldap01.domain.local 389 Trying 10.3.17.10... Connected to sisn01.domain.local. Escape character is '^]'. On the client: # ldapsearch -x -h ldap01.domain.local -b cn=config dn # extended LDIF # # LDAPv3 # base <cn=config> with scope subtree # filter: (objectclass=*) # requesting: dn # # search result search: 2 result: 32 No such object # numResponses: 1 On the server: # ps aux | grep slapd openldap 3759 0.0 0.2 564820 8228 ? Ssl 08:39 0:00 /usr/sbin/slapd -h ldap:/// ldapi:/// -g openldap -u openldap -F /etc/ldap/slapd.d I suspect I am missing a configuration parameter either on the server or on the client. I just cannot figure out what. Any help here would be appreciated.

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  • Boost::Spirit::Qi autorules -- avoiding repeated copying of AST data structures

    - by phooji
    I've been using Qi and Karma to do some processing on several small languages. Most of the grammars are pretty small (20-40 rules). I've been able to use autorules almost exclusively, so my parse trees consist entirely of variants, structs, and std::vectors. This setup works great for the common case: 1) parse something (Qi), 2) make minor manipulations to the parse tree (visitor), and 3) output something (Karma). However, I'm concerned about what will happen if I want to make complex structural changes to a syntax tree, like moving big subtrees around. Consider the following toy example: A grammar for s-expr-style logical expressions that uses autorules... // Inside grammar class; rule names match struct names... pexpr %= pand | por | var | bconst; pand %= lit("(and ") >> (pexpr % lit(" ")) >> ")"; por %= lit("(or ") >> (pexpr % lit(" ")) >> ")"; pnot %= lit("(not ") >> pexpr >> ")"; ... which leads to parse tree representation that looks like this... struct var { std::string name; }; struct bconst { bool val; }; struct pand; struct por; struct pnot; typedef boost::variant<bconst, var, boost::recursive_wrapper<pand>, boost::recursive_wrapper<por>, boost::recursive_wrapper<pnot> > pexpr; struct pand { std::vector<pexpr> operands; }; struct por { std::vector<pexpr> operands; }; struct pnot { pexpr victim; }; // Many Fusion Macros here Suppose I have a parse tree that looks something like this: pand / ... \ por por / \ / \ var var var var (The ellipsis means 'many more children of similar shape for pand.') Now, suppose that I want negate each of the por nodes, so that the end result is: pand / ... \ pnot pnot | | por por / \ / \ var var var var The direct approach would be, for each por subtree: - create pnot node (copies por in construction); - re-assign the appropriate vector slot in the pand node (copies pnot node and its por subtree). Alternatively, I could construct a separate vector, and then replace (swap) the pand vector wholesale, eliminating a second round of copying. All of this seems cumbersome compared to a pointer-based tree representation, which would allow for the pnot nodes to be inserted without any copying of existing nodes. My question: Is there a way to avoid copy-heavy tree manipulations with autorule-compliant data structures? Should I bite the bullet and just use non-autorules to build a pointer-based AST (e.g., http://boost-spirit.com/home/2010/03/11/s-expressions-and-variants/)?

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  • ADO program to list members of a large group.

    - by AlexGomez
    Hi everyone, I'm attempting to list all the members in a Active Directory group using ADO. The problem I have is that many of these groups have over 1500 members and ADSI cannot handle more than 1500 items in a multi-valued attribute. Fortunately I came across Richard Muller's wonderful VBScript that handles more than 1500 members at http://www.rlmueller.net/DocumentLargeGroup.htm I modified his code as shown below so that I can list ALL the groups and its memberships in a certain OU. However, I'm keeping getting the exception shown below: "ADODB.Recordset: Item cannot be found in the collection corresponding to the requested name or ordinal." My program appears to get stuck at: strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) All I am doing above is issuing the query to get back a recordset consisting of the ADsPath for each group in the OU. It then walks through the recordset and grabs the ADsPath for the first group and store its in a variable named strPath; we then use the value of that variable to bind to the group account for that group. It really should work! Any idea why the code below doesn't work for me? Any pointers will be great appreciated. Thanks. Option Explicit Dim objRootDSE, strDNSDomain, adoCommand Dim adoConnection, strBase, strAttributes Dim strFilter, strQuery, adoRecordset Dim strDN, intCount, blnLast, intLowRange Dim intHighRange, intRangeStep, objField Dim objGroup, objMember, strName ' Determine DNS domain name. Set objRootDSE = GetObject("LDAP://RootDSE") 'strDNSDomain = objRootDSE.Get("DefaultNamingContext") strDNSDomain = "XXXXXXXX" ' Use ADO to search Active Directory. Set adoCommand = CreateObject("ADODB.Command") Set adoConnection = CreateObject("ADODB.Connection") adoConnection.Provider = "ADsDSOObject" adoConnection.Open = "Active Directory Provider" adoCommand.ActiveConnection = adoConnection adoCommand.Properties("Page Size") = 100 adoCommand.Properties("Timeout") = 30 adoCommand.Properties("Cache Results") = False ' Specify base of search. strBase = "<LDAP://" & strDNSDomain & ">" ' Specify the attribute values to retrieve. strAttributes = "member" ' Filter on objects of class "group" strFilter = "(&(objectClass=group)(samAccountName=*))" ' Enumerate direct group members. ' Use range limits to handle more than 1000/1500 members. ' Setup to retrieve 1000 members at a time. blnLast = False intRangeStep = 999 intLowRange = 0 IntHighRange = intLowRange + intRangeStep Do While True If (blnLast = True) Then ' If last query, retrieve remaining members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange _ & "-*;subtree" Else ' If not last query, retrieve 1000 members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange & "-" _ & intHighRange & ";subtree" End If adoCommand.CommandText = strQuery Set adoRecordset = adoCommand.Execute adoRecordset.MoveFirst intCount = 0 Do Until adoRecordset.EOF strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) For Each objField In adoRecordset.Fields If (VarType(objField) = (vbArray + vbVariant)) _ Then For Each strDN In objField.Value ' Escape any forward slash characters, "/", with the backslash ' escape character. All other characters that should be escaped are. strDN = Replace(strDN, "/", "\/") ' Check dictionary object for duplicates. 'If (objGroupList.Exists(strDN) = False) Then ' Add to dictionary object. 'objGroupList.Add strDN, True ' Bind to each group member, to find member's samAccountName Set objMember = GetObject("LDAP://" & strDN) ' Output group cn, group samaAccountName and group member's samAccountName. Wscript.Echo objMember.samAccountName intCount = intCount + 1 'End if Next End If Next adoRecordset.MoveNext Loop adoRecordset.Close ' If this is the last query, exit the Do While loop. If (blnLast = True) Then Exit Do End If ' If the previous query returned no members, then the previous ' query for the next 1000 members failed. Perform one more ' query to retrieve remaining members (less than 1000). If (intCount = 0) Then blnLast = True Else ' Setup to retrieve next 1000 members. intLowRange = intHighRange + 1 intHighRange = intLowRange + intRangeStep End If Loop

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