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  • Filter rows on the basis of "First Name" + "Last Name" in SQL

    - by Raghav Khunger
    Hi, I have a user table in my database which contains two columns FirstName and LastName. Now in my front end there is a textbox to filter out the users from this table. Let's suppose I am taking that input from the front end in the form of a input parameter "@SEARCHKEYWORD". I have created a sample below: DECLARE @Test TABLE ([ID] INT IDENTITY, [FNAME] NVARCHAR(100), [LNAME] NVARCHAR(100) ) INSERT INTO @Test( FNAME, LNAME ) SELECT 'John','Resig' UNION ALL SELECT 'Dave','Ward' UNION ALL SELECT 'Peter','Smith' UNION ALL SELECT 'Dave','Smith' UNION ALL SELECT 'Girija','Acharya' UNION ALL SELECT 'Devendra', 'Gujel' UNION ALL SELECT 'Arjit', 'Gupta' DECLARE @SEARCHKEYWORD NVARCHAR(100) SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD i.e. so far I have thought of this query to filter out the rows but it is not giving the desired results: SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD Here are the desired outputs which I needed for the inputs mentioned below: --WHEN @SEARCHKEYWORD='John Resig' --Desired OUTPUT: the row which contains 'John','Resig' --WHEN @SEARCHKEYWORD='Ac' --Desired OUTPUT: the row which contains 'Girija','Acharya' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith' --WHEN @SEARCHKEYWORD='g' --Desired OUTPUT: the row which contains 'Devendra', 'Gujel' and 'Arjit', 'Gupta' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith'

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  • Excel VBA Text To Column

    - by Pat
    This is what I currently have: H101 John Doe Jane Doe Jack Doe H102 John Smith Jane Smith Katie Smith Jack Smith And here is what I want: H101 John Doe H101 Jane Doe H101 Jack Doe H102 John Smith H102 Jane Smith H102 Katie Smith H102 Jack Smith Obviously I want to do this on a bigger scale. The number of columns is between 1 & 6, so I cant limit it that way. I was able to get a script that allows me to put each individual on one row. However, I am having a hard time getting the first column to copy over to each row. Sub ToOneColumn() Dim i As Long, k As Long, j As Integer Application.ScreenUpdating = False Columns(2).Insert i = 0 k = 1 While Not IsEmpty(Cells(k, 3)) j = 3 While Not IsEmpty(Cells(k, j)) i = i + 1 Cells(i, 1) = Cells(k, 1) //CODE IN QUESTION Cells(i, 2) = Cells(k, j) Cells(k, j).Clear j = j + 1 Wend k = k + 1 Wend Application.ScreenUpdating = True End Sub Like I said, it was working fine to get everyone each on their own row, but can't figure out how to get that first column. It seems like it should be so simple, but it's bugging me. Any help is greatly appreciated.

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  • Completely remove user account and create another with same name in Windows 7

    - by TeaJay
    Here's my question simply and then the details in case they help to get me an appropriate answer. Question: How can I completely and permanently delete a user account in Windows 7 so that I can create another one with the same user name without the computer name extension added, eg Jane Smith not Jane Smith.computer name? The details: I just did a clean install of Windows 7 Professional 32 bit. (My laptop crashed, I reinstalled Vista and restored backup files but things weren't working so I decided to just get Windows 7 since I had to start over anyway). I used Windows Easy Transfer to save just about everything, even customizing to include a user's appdata from Windows.old which was created when I reinstalled Vista -- not knowing that another windows.old file would be created with the installation of Windows 7. After installing Windows 7, I used Windows Easy Transfer to transfer the user file, appdata, to the new user account which I gave the same name (Jane Smith) in case having a different name would cause problems with reading files or something. Afterwards, I realized that I did not want ALL of that junk. So, I thought no problem, I'll just delete the user account I just created, nothing lost, and create another one this time transferring only the files I wanted (using the customize option in windows easy transfer). I wanted to keep the same user name, e.g. Jane Smith, so after I deleted the user account I checked the files, and I didn't see. It was late so I went to bed and the next morning I created a new user with that same name (Jane Smith). The files looked fine if I remember correctly. Meanwhile, I updated the computer and it restarted a couple times. As I was moving files to the "Jane Smith" user account file, things weren't working as they should. I was actually moving files to the deleted user account and that the current user account was named "Jane Smith.computer name" and that's where the files needed to go. I don't like this. It's too confusing. I want just "Jane Smith". How can I do this without just changing the user name (which doesn't change it in the file path etc)? I want the first one GONE. If I can't do this, is it a problem to create an account with another name and still transfer files to it without path or other problems? I hope this question makes sense and that someone can help me. Thank you in advance!

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  • Help using left outer joins in SQL...

    - by Waffles
    I'm trying to create a list of people, their friends, and their friends of friends. My table of people is this: People: NAME Jow Smith Sandy Phil Friends LIKER LIKEE jow smith smith jow sandy phil Now, what I want is a table like this: User Friend FriendofFriend Jow smith jow Smith jow smith sandy phil phil I'm trying to create a table using the following: SELECT P.NAME, F.LIKEE, F2.LIKEE FROM PEOPLE P LEFT OUTER JOIN FRIENDS F ON P.NAME = F.LIKER LEFT OUTER JOIN FRIENDS F2 ON F.LIKEE = F2.LIKER But the above isn't working. How can I get a table of people and their friends, regardless of whether or not they actually HAVE any friends?

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  • Is there apt-cacher for Windows?

    - by Ted Kim
    I have two computers. C1: Windows with Internet connection. C2: Ubuntu connected with C1 but not connected with Internet. I'd like to access apt repositories to update or install some packages on Ubuntu. I heard, apt-cacher is one of solutions, but I couldn't find apt-cacher for Windows (It is only one, I have, with Internet connection). Please let me know how to do. Thanks in advance Ted Kim

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  • A Nondeterministic Engine written in VB.NET 2010

    - by neil chen
    When I'm reading SICP (Structure and Interpretation of Computer Programs) recently, I'm very interested in the concept of an "Nondeterministic Algorithm". According to wikipedia:  In computer science, a nondeterministic algorithm is an algorithm with one or more choice points where multiple different continuations are possible, without any specification of which one will be taken. For example, here is an puzzle came from the SICP: Baker, Cooper, Fletcher, Miller, and Smith live on different floors of an apartment housethat contains only five floors. Baker does not live on the top floor. Cooper does not live onthe bottom floor. Fletcher does not live on either the top or the bottom floor. Miller lives ona higher floor than does Cooper. Smith does not live on a floor adjacent to Fletcher's.Fletcher does not live on a floor adjacent to Cooper's. Where does everyone live? After reading this I decided to build a simple nondeterministic calculation engine with .NET. The rough idea is that we can use an iterator to track each set of possible values of the parameters, and then we implement some logic inside the engine to automate the statemachine, so that we can try one combination of the values, then test it, and then move to the next. We also used a backtracking algorithm to go back when we are running out of choices at some point. Following is the core code of the engine itself: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Public Class NonDeterministicEngine Private _paramDict As New List(Of Tuple(Of String, IEnumerator)) 'Private _predicateDict As New List(Of Tuple(Of Func(Of Object, Boolean), IEnumerable(Of String))) Private _predicateDict As New List(Of Tuple(Of Object, IList(Of String))) Public Sub AddParam(ByVal name As String, ByVal values As IEnumerable) _paramDict.Add(New Tuple(Of String, IEnumerator)(name, values.GetEnumerator())) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(1, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(2, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(3, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(4, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(5, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(6, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(7, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(8, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Sub CheckParamCount(ByVal count As Integer, ByVal paramNames As IList(Of String)) If paramNames.Count <> count Then Throw New Exception("Parameter count does not match.") End If End Sub Public Property IterationOver As Boolean Private _firstTime As Boolean = True Public ReadOnly Property Current As Dictionary(Of String, Object) Get If IterationOver Then Return Nothing Else Dim _nextResult = New Dictionary(Of String, Object) For Each item In _paramDict Dim iter = item.Item2 _nextResult.Add(item.Item1, iter.Current) Next Return _nextResult End If End Get End Property Function MoveNext() As Boolean If IterationOver Then Return False End If If _firstTime Then For Each item In _paramDict Dim iter = item.Item2 iter.MoveNext() Next _firstTime = False Return True Else Dim canMoveNext = False Dim iterIndex = _paramDict.Count - 1 canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then Return True End If Do While Not canMoveNext iterIndex = iterIndex - 1 If iterIndex = -1 Then Return False IterationOver = True End If canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then For i = iterIndex + 1 To _paramDict.Count - 1 Dim iter = _paramDict(i).Item2 iter.Reset() iter.MoveNext() Next Return True End If Loop End If End Function Function GetNextResult() As Dictionary(Of String, Object) While MoveNext() Dim result = Current If Satisfy(result) Then Return result End If End While Return Nothing End Function Function Satisfy(ByVal result As Dictionary(Of String, Object)) As Boolean For Each item In _predicateDict Dim pred = item.Item1 Select Case item.Item2.Count Case 1 Dim p1 = DirectCast(pred, Func(Of Object, Boolean)) Dim v1 = result(item.Item2(0)) If Not p1(v1) Then Return False End If Case 2 Dim p2 = DirectCast(pred, Func(Of Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) If Not p2(v1, v2) Then Return False End If Case 3 Dim p3 = DirectCast(pred, Func(Of Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) If Not p3(v1, v2, v3) Then Return False End If Case 4 Dim p4 = DirectCast(pred, Func(Of Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) If Not p4(v1, v2, v3, v4) Then Return False End If Case 5 Dim p5 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) If Not p5(v1, v2, v3, v4, v5) Then Return False End If Case 6 Dim p6 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) If Not p6(v1, v2, v3, v4, v5, v6) Then Return False End If Case 7 Dim p7 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) If Not p7(v1, v2, v3, v4, v5, v6, v7) Then Return False End If Case 8 Dim p8 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) Dim v8 = result(item.Item2(7)) If Not p8(v1, v2, v3, v4, v5, v6, v7, v8) Then Return False End If Case Else Throw New NotSupportedException End Select Next Return True End FunctionEnd Class    And now we can use the engine to solve the problem we mentioned above:   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test2() Dim engine = New NonDeterministicEngine() engine.AddParam("baker", {1, 2, 3, 4, 5}) engine.AddParam("cooper", {1, 2, 3, 4, 5}) engine.AddParam("fletcher", {1, 2, 3, 4, 5}) engine.AddParam("miller", {1, 2, 3, 4, 5}) engine.AddParam("smith", {1, 2, 3, 4, 5}) engine.AddRequire(Function(baker) As Boolean Return baker <> 5 End Function, {"baker"}) engine.AddRequire(Function(cooper) As Boolean Return cooper <> 1 End Function, {"cooper"}) engine.AddRequire(Function(fletcher) As Boolean Return fletcher <> 1 And fletcher <> 5 End Function, {"fletcher"}) engine.AddRequire(Function(miller, cooper) As Boolean 'Return miller = cooper + 1 Return miller > cooper End Function, {"miller", "cooper"}) engine.AddRequire(Function(smith, fletcher) As Boolean Return smith <> fletcher + 1 And smith <> fletcher - 1 End Function, {"smith", "fletcher"}) engine.AddRequire(Function(fletcher, cooper) As Boolean Return fletcher <> cooper + 1 And fletcher <> cooper - 1 End Function, {"fletcher", "cooper"}) engine.AddRequire(Function(a, b, c, d, e) As Boolean Return a <> b And a <> c And a <> d And a <> e And b <> c And b <> d And b <> e And c <> d And c <> e And d <> e End Function, {"baker", "cooper", "fletcher", "miller", "smith"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine(String.Format("baker: {0}, cooper: {1}, fletcher: {2}, miller: {3}, smith: {4}", result("baker"), result("cooper"), result("fletcher"), result("miller"), result("smith"))) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub   Also, this engine can solve the classic 8 queens puzzle and find out all 92 results for me.   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test3() ' The 8-Queens problem. Dim engine = New NonDeterministicEngine() ' Let's assume that a - h represents the queens in row 1 to 8, then we just need to find out the column number for each of them. engine.AddParam("a", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("b", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("c", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("d", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("e", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("f", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("g", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("h", {1, 2, 3, 4, 5, 6, 7, 8}) Dim NotInTheSameDiagonalLine = Function(cols As IList) As Boolean For i = 0 To cols.Count - 2 For j = i + 1 To cols.Count - 1 If j - i = Math.Abs(cols(j) - cols(i)) Then Return False End If Next Next Return True End Function engine.AddRequire(Function(a, b, c, d, e, f, g, h) As Boolean Return a <> b AndAlso a <> c AndAlso a <> d AndAlso a <> e AndAlso a <> f AndAlso a <> g AndAlso a <> h AndAlso b <> c AndAlso b <> d AndAlso b <> e AndAlso b <> f AndAlso b <> g AndAlso b <> h AndAlso c <> d AndAlso c <> e AndAlso c <> f AndAlso c <> g AndAlso c <> h AndAlso d <> e AndAlso d <> f AndAlso d <> g AndAlso d <> h AndAlso e <> f AndAlso e <> g AndAlso e <> h AndAlso f <> g AndAlso f <> h AndAlso g <> h AndAlso NotInTheSameDiagonalLine({a, b, c, d, e, f, g, h}) End Function, {"a", "b", "c", "d", "e", "f", "g", "h"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine("(1,{0}), (2,{1}), (3,{2}), (4,{3}), (5,{4}), (6,{5}), (7,{6}), (8,{7})", result("a"), result("b"), result("c"), result("d"), result("e"), result("f"), result("g"), result("h")) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub (Chinese version of the post: http://www.cnblogs.com/RChen/archive/2010/05/17/1737587.html) Cheers,  

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  • sudo: apache restarting a service on CentOS

    - by WaveyDavey
    I need my web app to restart the dansguardian service (on CentOS) so it needs to run '/sbin/service dansguardian restart' I have a shellscript in /home/topological called apacherestart.sh which does the following: #!/bin/sh id=`id` /sbin/service dansguardian restart r=$? return $r This runs ok (logger statement in script for testing output to syslog, so I know it's running) To make it run, I put this in /etc/sudoers: User_Alias APACHE=www # Cmnd alias specification Cmnd_Alias HTTPRESTART=/home/topological/apacherestart.sh,/sbin/e-smith/db,/etc/rc7.d/S91dansguardian # Defaults specification # User privilege specification root ALL=(ALL) ALL APACHE ALL=(ALL) NOPASSWD: HTTPRESTART So far so good. But the service does not restart. To test this I created a user david, and fudged the uid/gid in /etc/passwd to be the same as www: www:x:102:102:e-smith web server:/home/e-smith:/bin/false david:x:102:102:David:/home/e-smith/files/users/david:/bin/bash then logged in as david and tried to run the apacherestart.sh. The problem I get is: /etc/rc7.d/S91dansguardian: line 51: /sbin/e-smith/db: Permission denied even though S91dansguardian and db are in the sudoers command list. Any ideas?

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  • Multiple 301 redirect and massive loss of ranking

    - by DoesNotCompute
    I just remade from scratch a website for a client, the client ask me to preverve their ranking by making 301 redirect from the original URL to the new URL. For instance: http://plumber-directory.my-website.com/john-smith-city-1.php became http://directory.my-website.com/plumber/city/john-smith.html So i put the website online for few days until the 301 partially kicks in the google results. Then the client call me back to tell me that his boss want to switch back to the ancients URLs _< So i put a new 301 redirect: http://directory.my-website.com/plumber/city/john-smith.html revert to http://plumber-directory.my-website.com/john-smith-city-1.php Because google had just few days to assimilate the new URLs, it have now the two kinds of URLs in it's own result pages. Also the ranking of the website keeps falling down every day, i suspect google to mistaking those redirects for duplicate content. Is there something i can do to avoid a total loss of rankings?

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  • Oracle presentations at the CIPS ICE Conference, November 5 - 7, Edmonton, Alberta, Canada

    - by Darin Pendergraft
    Oracle will be presenting at the CIPS ICE conference the last week of October in Calgary and the first week of November in Edmonton. Here is a list of the presentations for Edmonton: SHAW Conference Centre • Session Title: Identity and Access Management Integrated; Analyzing the Platform vs Point Solution Approach • Speaker: Darin Pendergraft • Monday, November 5th @ 10:45 AM - 12:00 PM • Session Title: Is Your IT Security Strategy Putting Your Institution at Risk? • Speaker: Spiros Angelopoulos • Monday, November 5th @ 1:45 PM - 3:00 PM Three sessions under the TRAIN: Practical Knowledge Track • Monday, November 5th @ 10:45 AM, 1:45 PM, 3:30 PM • Title: What's new in the Java Platform   Presenter: Donald Smith • Title: Java Enterprise Edition 6   Presenter: Shaun Smith • Title: The Road Ahead for Java SE, JavaFX and Java EE    Presenters: Donald Smith and Shaun Smith To learn more about the conference, and to see the other sessions go to the conference website.

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  • First steps into css - aligning data insite one DIV [on hold]

    - by Andrew
    I am trying to move away from tables, and start doing CSS. Here is my HTML code that I currently trying to place into a nice looking container. <div> <div> <h2>ID: 4000 | SSN#: 4545</h2> </div> <div> <img src="./images/tenant/unknown.png"> </div> <div> <h3>Names Used</h3> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> </div> <div> <h3>Phones Used</h3> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> </div> <div> <h3>Addresses Used</h3> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> </div> </div> I now understand now I create classes and assign classes to elements. I have no issues doing colors. But I am very confused with elements alignments. Could you suggest a nice way to pack it together with some CSS which I can analyze and take as a CSS starting learning point?

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  • Linux Router - Share bandwidth per IPs with current active connections

    - by SRoe
    We have a Linux machine running as a custom router, currently utilising Shorewall. This sits between our incoming internet connection and the internal LAN. What we would like to achieve is 'fair use' of the bandwidth on a per IP basis. If only one person currently has an active connection then they get 100% utilisation of the line. However if 20 people have active connections then they should each get 5% utilisation of the line. This should be irrespective of the number of connections held by each user. For example, say we have two users, Bill and Ted, that both have active connections. Bill has a single active connection while Ted has ten active connections. Bill should get 50% utilisation for his single connections whilst Ted should get 5% utilisation for each of his ten connections, giving Ted a total utilisation of 50%.

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  • How to get the second word from a String?

    - by Pentium10
    Take these examples Smith John Smith-Crane John Smith-Crane John-Henry Smith-Crane John Henry I would like to get the John The first word after the space, but it might not be until the end, it can be until a non alpha character. How would this be in Java 1.5?

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  • Algorithm to compare people names to detect identicalness

    - by Pentium10
    I am working on address book synchronization algorithm. I would like to reuse some code if there exists, but couldn't find one yet. Does someone know about an algorithm that will tell me in numbers/float/procent how much two names are identical. Levenstein distance is not good in this approach, as names and our adddress books are matching the begining of each of the name sections. John Smith should match Smith Jon, Jonathan Smith, Johnny Smith

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  • Exchange 2010 OWA - a few questions about using multiple mailboxes

    - by Alexey Smolik
    We have an Exchange 2010 SP2 deployment and we need that our users could access multiple mailboxes in OWA. The problem is that a user (eg John Smith) needs to access not just somebody else's (eg Tom Anderson) mailboxes, but his OWN mailboxes, e.g. in different domains: [email protected], [email protected], [email protected], etc. Of course it is preferable for the user to work with all of his mailboxes from a single window. Such mailboxes can be added as multiple Exchange accounts in Outlook, that works almost fine. But in OWA, there are problems: 1) In the left pane - as I've learned - we can open only Inbox folders from other mailboxes. No way to view all folders like in Outlook? 2) With Send-As permissions set, when trying to send a message from another address, that message is saved in the Sent Items folder of the mailbox that is opened in OWA, and not in the mailbox the message is sent from. The same thing with the trash can. Is there a way to fix that? Also, this problem exists in desktop Outlook when mailboxes are added automatically via the Auto Mapping feature, so that we need to turn it off and add the accounts manually. Is there a simpler workaround? 3) Okay, suppose we only open Inbox folders in the left pane. The problem is that the mailbox names shown there are formed from Display Name attributes. But those names are all identical! All the mailboxes are owned by John Smith, so they should be all named John Smith - so that letter recepient sees "John Smith" in the "from" field, no matter what mailbox it is sent from. Also, the user knows what's his name - no need to tell him. He wants to know what mailbox he works with. So we need a way to either: a) customize OWA to show mailbox email address instead of user Display Name, or b) make Exchange use another attribute to put in the "from" field when sending letters 4) Okay, we can switch between mailboxes using "Open Other Mailbox" in the upper-right corner menu. But: a) To select a mailbox we need to enter its name (or first letters). It there a way to show a list of links to mailboxes the user has full access to? Eg in the page header... b) If we start entering the first letters, we see a popup list with possible mailboxes to be opened. But there are all mailboxes (apparently from GAL), not only mailboxes the user has permission to open! How to filter that popup list? c) The same problem as in (3) with mailbox naming. We can see the opened mailbox email address ONLY in the page URL, which is insufficient for many users. In the left pane we see "John Smith" which is useless. 5) Each mailbox is tied with a separate user in AD. If one has several mailboxes, we need to have additional dummy AD accounts, create additional OUs to store them, etc. That's not very nice, is there any standartized, optimal way to build such a structure? We would really appreciate any answers or additional info for any of these questions. Thank you in advance.

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  • Cloud-Burst 2012&ndash;Windows Azure Developer Conference in Sweden

    - by Alan Smith
    The Sweden Windows Azure Group (SWAG) will running “Cloud-Burst 2012”, a two-day Windows Azure conference hosted at the Microsoft offices in Akalla, near Stockholm on the 27th and 28th September, with an Azure Hands-on Labs Day at AddSkills on the 29th September. The event is free to attend, and will be featuring presentations on the latest Azure technologies from Microsoft MVPs and evangelists. The following presentations will be delivered on the Thursday (27th) and Friday (29th): · Connecting Devices to Windows Azure - Windows Azure Technical Evangelist Brady Gaster · Grid Computing with 256 Windows Azure Worker Roles - Connected System Developer MVP Alan Smith · ‘Warts and all’. The truth about Windows Azure development - BizTalk MVP Charles Young · Using Azure to Integrate Applications - BizTalk MVP Charles Young · Riding the Windows Azure Service Bus: Cross-‘Anything’ Messaging - Windows Azure MVP & Regional Director Christian Weyer · Windows Azure, Identity & Access - and you - Developer Security MVP Dominick Baier · Brewing Beer with Windows Azure - Windows Azure MVP Maarten Balliauw · Architectural patterns for the cloud - Windows Azure MVP Maarten Balliauw · Windows Azure Web Sites and the Power of Continuous Delivery - Windows Azure MVP Magnus Mårtensson · Advanced SQL Azure - Analyze and Optimize Performance - Windows Azure MVP Nuno Godinho · Architect your SQL Azure Databases - Windows Azure MVP Nuno Godinho   There will be a chance to get your hands on the latest Azure bits and an Azure trial account at the Hands-on Labs Day on Saturday (29th) with Brady Gaster, Magnus Mårtensson and Alan Smith there to provide guidance, and some informal and entertaining presentations. Attendance for the conference and Hands-on Labs Day is free, but please only register if you can make it, (and cancel if you cannot). Cloud-Burst 2012 event details and registration is here: http://www.azureug.se/CloudBurst2012/ Registration for Sweden Windows Azure Group Stockholm is here: swagmembership.eventbrite.com The event has been made possible by kind contributions from our sponsors, Knowit, AddSkills and Microsoft Sweden.

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  • SQL Query to retrieve highest item up to a point in a group

    - by James
    The best way of describing this is I have a table of people with their names and ages. Assume that people with the same surname are from the same family. I need a query in oracle which will retrieve a list of the oldest person in each family, but not older than a certain age. Table: person name surname age =============================== James Smith 23 Sarah Powell 17 Barry Smith 31 Mark Smith 35 Mary Smith 18 Bob Powell 30 How do I retrieve the oldest person in each family under 30? Results I'm after name surname age =============================== James Smith 23 Sarah Powell 17

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  • SQL Query that can return intersecting data

    - by Alex
    I have a hard time finding a good question title - let me just show you what I have and what the desired outcome is. I hope this can be done in SQL (I have SQL Server 2008). 1) I have a table called Contacts and in that table I have fields like these: FirstName, LastName, CompanyName 2) Some demo data: FirstName LastName CompanyName John Smith Smith Corp Paul Wade Marc Andrews Microsoft Bill Gates Microsoft Steve Gibbs Smith Corp Diane Rowe ABC Inc. 3) I want to get an intersecting list of people and companies, but companies only once. This would look like this: Name ABC Inc. Bill Gates Diane Rowe John Smith Marc Andrews Microsoft Smith Corp Steve Gibbs Paul Wade Can I do this with SQL? How?

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  • Can this method to convert a name to proper case be improved?

    - by Kelsey
    I am writing a basic function to convert millions of names (one time batch process) from their current form, which is all upper case, to a proper mixed case. I came up with the following so far: public string ConvertToProperNameCase(string input) { TextInfo textInfo = new CultureInfo("en-US", false).TextInfo; char[] chars = textInfo.ToTitleCase(input.ToLower()).ToCharArray(); for (int i = 0; i + 1 < chars.Length; i++) { if ((chars[i].Equals('\'')) || (chars[i].Equals('-'))) { chars[i + 1] = Char.ToUpper(chars[i + 1]); } } return new string(chars);; } It works in most cases such as: JOHN SMITH - John Smith SMITH, JOHN T - Smith, John T JOHN O'BRIAN - John O'Brian JOHN DOE-SMITH - John Doe-Smith There are some edge cases that do no work like: JASON MCDONALD - Jason Mcdonald (Correct: Jason McDonald) OSCAR DE LA HOYA - Oscar De La Hoya (Correct: Oscar de la Hoya) MARIE DIFRANCO - Marie Difranco (Correct: Marie DiFranco) These are not captured and I am not sure if I can handle all these odd edge cases. Can anyone think of anything I could change or add to capture more edge case? I am sure there are tons of edge cases I am not even thinking of as well. All casing should following North American conventions too meaning that if certain countries expect a specific capitalization format, and that differs from the North American format, then the North American format takes precedence.

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  • Parse Text using scanner useDelimiter

    - by Brian
    Looking to parse the following text file: Sample text file: <2008-10-07text entered by user<2008-11-26additional text entered by user I would like to parse the above text so that I can have three variables: v1 = 2008-10-07 v2 = text entered by user v3 = Ted Parlor v1 = 2008-11-26 v2 = additional text entered by user v3 = Ted Parlor I attempted to use scanner and useDelimiter, however, I'm having issue on how to set this up to have the results as stated above. Here's my first attempt: enter code here import java.io.*; import java.util.Scanner; public class ScanNotes { public static void main(String[] args) throws IOException { Scanner s = null; try { //String regex = "(?<=\<)([^\*)(?=\)"; s = new Scanner(new BufferedReader(new FileReader("cur_notes.txt"))); s.useDelimiter("[<]+"); while (s.hasNext()) { String v1 = s.next(); String v2= s.next(); System.out.println("v1= " + v1 + " v2=" + v2); } } finally { if (s != null) { s.close(); } } } } The results is as follows: v1= 2008-10-07text entered by user v2=Ted Parlor What I desire is: v1= 2008-10-07 v2=text entered by user v3=Ted Parlor v1= 2008-11-26 v2=additional text entered by user v3=Ted Parlor Any help that would allow me to extract all three strings separately would be greatly appreciated.

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  • Best way to optimize queries like this in Django

    - by chris
    I am trying to lower the amount of queries that my django app is using, but I am a little confused on how to do it. I would like to get a query set with one hit to the database and then filter items from that set. I have tried a couple of things, but I always get queries for each set. let's say I want to get all names from my DB, but also separate out the people just named Ted. Both the names and the ted set will be used in the template. This will give me two sets, one with all names and one with Ted.. but also hits the database twice: namelist = People.objects.all() tedList = namelist.filter(name='ted') Is there a way to filter the first set without hitting the data base again?

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  • javascript: what does this syntax means?

    - by user1067138
    it is like this: (function () { //codes here })(); here is an example: (function () { var D = TED.EditorCore, E = TED.extend, A = TED.EditorInstanceManager, B = TED.augmentObject; window.TED["SimpleEditor"] = C; function C(F) { C.superclass.call(this, F) } C.defaultConfig = { height: "100px", width: "400px", //blablabla... flashNumLimit: 10, didaDelay: 300, imageWidthLimit: 570 }; E(C, D, { getContentLength: function () { return Math.ceil(this.filteHTML(this.editArea.innerHTML, ["img", "br"]).replace(/<img[^>]*>/gi, "mm").replace(/<br[^>]*>/gi, "m").replace(/&nbsp;/gi, "m").replace(/[^\x00-\xff]/g, "mm").length / 2) }, filteEditHTML: function () { return html = this.editArea.innerHTML.replace(/_moz_dirty=""/gi, "").replace(/\[/g, "[[-").replace(/\]/g, "-]]").replace(new RegExp("<\\/?(?:br[^>]*)>", "gi"), "[$1]").replace(new RegExp('<span([^>]*class="?at"?[^>]*)>', "gi"), "[span$1]").replace(new RegExp('<img([^>]*class="?(?:' + this.config.emptyClassName + "|" + this.config.smileyClassName + ')"?[^>]*)>', "gi"), "[img$1]").replace(/<[^>]*>/g, "").replace(/\[\[\-/g, "[").replace(/\-\]\]/g, "]").replace(new RegExp("\\[(/?(?:br|img|span)[^\\]]*)\\]", "gi"), "<$1>") }, filteSubmitHTML: function () { this.reLayout(); var G = this.editArea.innerHTML.replace(/_moz_dirty=""/gi, "").replace(/\[/g, "[[-").replace(/\]/g, "-]]").replace(new RegExp("<(/?(?:" + this.submitValidHTML.join("|") + ")[^>]*)>", "gi"), "[$1]").replace(new RegExp('<img([^>]*class="?(?:' + this.config.imageClassName + "|" + this.config.smileyClassName + "|" + this.config.flashClassName + "|" + this.config.musicClassName + ')"?[^>]*)>', "gi"), "[img$1]").replace(/<[^>]*>/g, "").replace(/\[\[\-/g, "[").replace(/\-\]\]/g, "]").replace(new RegExp("\\[(/?(?:" + this.submitValidHTML.join("|") + "|img)[^\\]]*)\\]", "gi"), "<$1>"); var F = document.createElement("div"); F.innerHTML = G; this.parseURL(F); return F.innerHTML } }); B(C, A) })(); what exactly does (funtion (){})(); do?

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  • Checking data of all same class elements

    - by Tiffani
    I need the code to check the data-name value of all instances of .account-select. Right now it just checks the first .account-select element and not any subsequent ones. The function right now is on click of an element such as John Smith, it checks the data-name of the .account-select lis. If the data-names are the same, it does not create a new li with the John Smith data. If no data-names are equal to John Smith, then it adds an li with John Smith. This is the JS-Fiddle I made for it so you can see what I am referring to: http://jsfiddle.net/rsxavior/vDCNy/22/ Any help would be greatly appreciated. This is the Jquery Code I am using right now. $('.account').click(function () { var acc = $(this).data("name"); var sel = $('.account-select').data("name"); if (acc === sel) { } else { $('.account-hidden-li').append('<li class="account-select" data-name="'+ $(this).data("name") +'">' + $(this).data("name") + '<a class="close bcn-close" data-dismiss="alert" href="#">&times;</a></li>'); } }); And the HTML: <ul> <li><a class="account" data-name="All" href="#">All</a></li> <li><a class="account" data-name="John Smith" href="#">John Smith</a></li> </ul> <ul class="account-hidden-li"> <ul>

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  • Rewriting from headers in Postfix

    - by inxilpro
    I want to configure Postfix to replace the 'From' header in all forwarded/aliased messages with a custom email address, and the 'Reply-To' header with the original sender's address. Is that something that can be done with a simple configuration change, or am I looking at a more complex problem? For example: Original Message: From: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Would get translated to: From: "My Email Forwarding Service" <[email protected]> Reply-To: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Ideally, I would also have it rewrite the message body (adding something about how the message was forwarded for them), but I know that's much more difficult. We have a number of email aliases, and everytime someone reports spam they received through their alias, our server gets flagged. I'm trying to minimize that damage as much as possible. Any help is greatly appreciated!

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  • Resize Debian in VirtualBox

    - by Poni
    I have a VM with one HD of size 3GB and I'd like to enlarge its HD to 7GB. So I execute this command on the host (while guest is shutdown): VBoxManage modifyhd debian.vdi --resize 7168 Then I run the guest, Debian 6, and then: smith@debian6:~$ df -h Filesystem Size Used Avail Use% Mounted on /dev/sda1 2.8G 2.6G 60M 98% / tmpfs 61M 0 61M 0% /lib/init/rw udev 57M 160K 57M 1% /dev tmpfs 61M 0 61M 0% /dev/shm smith@debian6:~$ sudo parted /dev/sda print Model: ATA VBOX HARDDISK (scsi) Disk /dev/sda: 3221MB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 1049kB 3035MB 3034MB primary ext3 boot 2 3036MB 3220MB 185MB extended 5 3036MB 3220MB 185MB logical linux-swap(v1) smith@debian6:~$ cat /proc/partitions major minor #blocks name 8 0 3145728 sda 8 1 2962432 sda1 8 2 1 sda2 8 5 180224 sda5 So, no automatic resizing (detection) of the HD/partition (while VirtualBox, in the host, shows it's 7GB now). Ok... Then I do: smith@debian6:~$ sudo resize2fs /dev/sda1 resize2fs 1.41.12 (17-May-2010) The filesystem is already 740608 blocks long. Nothing to do! smith@debian6:~$ sudo parted GNU Parted 2.3 Using /dev/sda Welcome to GNU Parted! Type 'help' to view a list of commands. (parted) select /dev/sda1 Using /dev/sda1 (parted) resize WARNING: you are attempting to use parted to operate on (resize) a file system. parted's file system manipulation code is not as robust as what you'll find in dedicated, file-system-specific packages like e2fsprogs. We recommend you use parted only to manipulate partition tables, whenever possible. Support for performing most operations on most types of file systems will be removed in an upcoming release. Partition number? 1 Start? 0 End? [3034MB]? Here I'm stuck. At the above parted it asks me to resize to 3GB. No point in that, right.. What should I do in order to enlarge this partition?

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  • OpenLDAP Authentication UID vs CN issues

    - by user145457
    I'm having trouble authenticating services using uid for authentication, which I thought was the standard method for authentication on the user. So basically, my users are added in ldap like this: # jsmith, Users, example.com dn: uid=jsmith,ou=Users,dc=example,dc=com uidNumber: 10003 loginShell: /bin/bash sn: Smith mail: [email protected] homeDirectory: /home/jsmith displayName: John Smith givenName: John uid: jsmith gecos: John Smith gidNumber: 10000 cn: John Smith title: System Administrator But when I try to authenticate using typical webapps or services like this: jsmith password I get: ldapsearch -x -h ldap.example.com -D "cn=jsmith,ou=Users,dc=example,dc=com" -W -b "dc=example,dc=com" Enter LDAP Password: ldap_bind: Invalid credentials (49) But if I use: ldapsearch -x -h ldap.example.com -D "uid=jsmith,ou=Users,dc=example,dc=com" -W -b "dc=example,dc=com" It works. HOWEVER...most webapps and authentication methods seem to use another method. So on a webapp I'm using, unless I specify the user as: uid=smith,ou=users,dc=example,dc=com Nothing works. In the webapp I just need users to put: jsmith in the user field. Keep in mind my ldap is using the "new" cn=config method of storing settings. So if someone has an obvious ldif I'm missing please provide. Let me know if you need further info. This is openldap on ubuntu 12.04. Thanks, Dave

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