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  • Simulated NAT Traversal on Virtual Box

    - by Sumit Arora
    I have installed virtual box ( with Two virtual Adapters(NAT-type)) - Host (Ubuntu -10.10) - Guest-Opensuse-11.4 . Objective : Trying to simulate all four types of NAT as defined here : https://wiki.asterisk.org/wiki/display/TOP/NAT+Traversal+Testing Simulating the various kinds of NATs can be done using Linux iptables. In these examples, eth0 is the private network and eth1 is the public network. Full-cone iptables -t nat -A POSTROUTING -o eth0 -j SNAT --to-source iptables -t nat -A PREROUTING -i eth0 -j DNAT --to-destination Restricted cone iptables -t nat POSTROUTING -o eth1 -p tcp -j SNAT --to-source iptables -t nat POSTROUTING -o eth1 -p udp -j SNAT --to-source iptables -t nat PREROUTING -i eth1 -p tcp -j DNAT --to-destination iptables -t nat PREROUTING -i eth1 -p udp -j DNAT --to-destination iptables -A INPUT -i eth1 -p tcp -m state --state ESTABLISHED,RELATED -j ACCEPT iptables -A INPUT -i eth1 -p udp -m state --state ESTABLISHED,RELATED -j ACCEPT iptables -A INPUT -i eth1 -p tcp -m state --state NEW -j DROP iptables -A INPUT -i eth1 -p udp -m state --state NEW -j DROP Port-restricted cone iptables -t nat -A POSTROUTING -o eth0 -j SNAT --to-source Symmentric echo "1" /proc/sys/net/ipv4/ip_forward iptables --flush iptables -t nat -A POSTROUTING -o eth1 -j MASQUERADE --random iptables -A FORWARD -i eth1 -o eth0 -m state --state RELATED,ESTABLISHED -j ACCEPT iptables -A FORWARD -i eth0 -o eth1 -j ACCEPT What I did : OpenSuse guest with Two Virtual adapters - eth0 and eth1 -- eth1 with address 10.0.3.15 /eth1:1 as 10.0.3.16 -- eth0 with address 10.0.2.15 now running stund(http://sourceforge.net/projects/stun/) client/server : Server eKimchi@linux-6j9k:~/sw/stun/stund ./server -v -h 10.0.3.15 -a 10.0.3.16 Client eKimchi@linux-6j9k:~/sw/stun/stund ./client -v 10.0.3.15 -i 10.0.2.15 On all Four Cases It is giving same results : test I = 1 test II = 1 test III = 1 test I(2) = 1 is nat = 0 mapped IP same = 1 hairpin = 1 preserver port = 1 Primary: Open Return value is 0x000001 Q-1 :Please let me know If any has ever done, It should behave like NAT as per description but nowhere it working as a NAT. Q-2: How NAT Implemented in Home routers (Usually Port Restricted), but those also pre-configured iptables rules and tuned Linux

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  • Simple list traversal in C++

    - by anni15
    I have a code for simple list traversal. Could you please help me out to do this traversal more efficiently! mylist::traverse() { // this code traverses a list by index order of the elements (for int i=1; i<= thelist.size(); i++ ) /* find index numbers */ { int count=0; /* counter to find index */ Node * cursor; for ( cursor = head_ptr; cursor !=NULL ||count<i; cursor=cursor->link() ) { count++; } if ( cursor != NULL ) cout << “index: “ << i << “ value: “ << cursor->data() << endl; } }

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  • Finding most Important Node(s) in a Directed Graph

    - by Srikar Appal
    I have a large (˜ 20 million nodes) directed Graph with in-edges & out-edges. I want to figure out which parts of of the graph deserve the most attention. Often most of the graph is boring, or at least it is already well understood. The way I am defining "attention" is by the concept of "connectedness" i.e. How can i find the most connected node(s) in the graph? In what follows, One can assume that nodes by themselves have no score, the edges have no weight & they are either connected or not. This website suggest some pretty complicated procedures like n-dimensional space, Eigen Vectors, graph centrality concepts, pageRank etc. Is this problem that complex? Can I not do a simple Breadth-First Traversal of the entire graph where at each node I figure out a way to find the number of in-edges. The node with most in-edges is the most important node in the graph. Am I missing something here?

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  • traversal of multiple separate web services in a ring network

    - by qkrsppopcmpt
    I am facing a design problem, here is some basic requirement: Aggregator 1. Separate service for blog,video,images and associations. 2. Each of the service should be completely separate, that means they run on separate tomcat. 3. And each aggregator must be able to query local database and other aggregators 4. Traversal of services must be asynchronous using a ring network. For example, we have a ring like ws1-ws2-ws3-ws4-ws1. Each node represents one type of one aggregator. The traveral goes in this way: the query from ws1 to ws2, and ws1 is waiting for the response from ws2 asynchronously; ws2 to ws3, also ws2 wait for ws3 asynchronously. If ws3 has the data, reply to ws2 then to ws1, then reply. However if ws3 goes away, the traversal should go back to ws2, then to ws1, then go to ws4, then go to ws3 again. then tells ws4 since ws3 fails. The required technology is axis2 and tomcat 6. Does anybody have any clue about it? If it is clear, I can clarify the question more clearly. Thanks very much.

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  • Recursive breadth first tree traversal

    - by dugogota
    I'm pulling my hair out trying to figure out how to implement breadth first tree traversal in scheme. I've done it in Java and C++. If I had code, I'd post it but I'm not sure how exactly to begin. Given the tree definition below, how to implement breadth first search using recursion? (define tree1 '( A ( B (C () ()) (D () ()) ) (E (F () ()) (G () ())) )) Any help, any, is greatly appreciated.

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  • Allowing directory view/traversal for a specific VirtualHost in Apache 2.2

    - by warren
    I have the following vhost configured: <VirtualHost *:80> DocumentRoot /var/www/myvhost ServerName myv.host.com ServerAlias myv.host.com ErrorLog logs/myvhost-error_log CustomLog logs/myvhost-access_log combined ServerAdmin [email protected] <Directory /var/www/myvhost> AllowOverride All Options +Indexes </Directory> </VirtualHost> The configuration appears to be correct from the apachectl tool's perspective. However, I cannot get a directory listing on that vhost: Forbidden You don't have permission to access / on this server. Additionally, a 403 Forbidden error was encountered while trying to use an ErrorDocument to handle the request. The error log shows the following: [Wed Mar 07 19:23:33 2012] [error] [client 66.6.145.214] Directory index forbidden by Options directive: /var/www/****** update2 More recently, the following is now kicking-into the error.log: [Wed Mar 07 20:16:10 2012] [error] [client 192.152.243.233] Options FollowSymLinks or SymLinksIfOwnerMatch is off which implies that RewriteRule directive is forbidden: /var/www/error/noindex.html update3 Today, the following is getting kicked-out: [Thu Mar 08 14:05:56 2012] [error] [client 66.6.145.214] Directory index forbidden by Options directive: /var/www/<mydir> [Thu Mar 08 14:05:56 2012] [error] [client 66.6.145.214] Options FollowSymLinks or SymLinksIfOwnerMatch is off which implies that RewriteRule directive is forbidden: /var/www/error/noindex.html [Thu Mar 08 14:05:57 2012] [error] [client 66.6.145.214] Request exceeded the limit of 10 internal redirects due to probable configuration error. Use 'LimitInternalRecursion' to increase the limit if necessary. Use 'LogLevel debug' to get a backtrace. This is after modifying the vhosts.conf file thusly: <VirtualHost *:80> DocumentRoot /var/www/<mydir> ServerName myhost ServerAlias myhost ErrorLog logs/myhost-error_log CustomLog logs/myhost-access_log combined ServerAdmin admin@myhost <Directory "/var/www/<mydir>"> Options All +Indexes +FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> </VirtualHost> What is missing? update 4 All subdirectories of the root directory do directory listings properly - it is only the root which cannot.

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  • Removing the obstacle that yields the best path from a map after A* traversal

    - by David Titarenco
    I traverse a 16x16 maze using my own A* implementation. This is exactly what my program does: http://www.screenjelly.com/watch/fDQh98zMP0c?showTab=share All is well. However, after the traversal, I would like to find out what wall would give me the best alternative path. Apart from removing every block and re-running A* on the maze, what's a clever solution? I was thinking give every wall node (ignored by A*), a tentative F-value, and change the node structure to also have a n-sized list of node *tentative_parent where n is the number of walls in the maze. Could this be viable?

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  • BFS traversal of directed graph from a given node

    - by p1
    Hi, My understanding of basic BFS traversal for a graph is: BFS { Start from any node . Add it to que. Add it to visited array While(que is not empty) { remove head from queue. Print node; add all unvisited direct subchilds to que; mark them as visited } } However, if we have to traverse a DIRECTED graph from a given node and not all nodes are accessible from the given node [directly or indirectly] how do we use BFS for the same. Can you please explain in this graph as well: a= b = d = e = d a= c = d Here if the starting node is b , we never print a and c. Am I missing something in the algorithm. P.S: I used "HashMap adj = new HashMap();" to create the adjacencey list to store graph Any pointers are greatly appreciated. Thanks.

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  • Using traversal by pointer to check whether a string is repeated

    - by Bob John
    bool repeat_char(char *s, int n); //R: s is a C-string of at least n non-NUL characters and n > 0 //E: returns true if the first n characters are fully repeated throughout the string s, false // otherwise. I'm having trouble implementing this function using traversal by pointer. I was thinking that I could extract the first n characters from s, then use that in a comparison with s, but I'm not sure how I could do that. If I'm traversing through s one character at a time, how can I check that it matches a block of text, such as the first n characters of s? Thanks!

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  • Linq to XML Document Traversal

    - by Perpetualcoder
    I have an xml document like this: <?xml version="1.0" encoding="utf-8" ?> <demographics> <country id="1" value="USA"> <state id ="1" value="California"> <city>Long Beach</city> <city>Los Angeles</city> <city>San Diego</city> </state> <state id ="2" value="Arizona"> <city>Tucson</city> <city>Phoenix</city> <city>Tempe</city> </state> </country> <country id="2" value="Mexico"> <state id ="1" value="Baja California"> <city>Tijuana</city> <city>Rosarito</city> </state> </country> </demographics> How do I setup LINQ queries for doing things like: 1. Get All Countries 2. Get All States in a Country 3. Get All Cities inside a state of a paricular country ? I gave it a try and I am kind of confused when to use Elements["NodeName"] and Descendants etc. I know I am not the brightest XML guy around. Is the format of the XML file even correct for simple traversal?

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • breadth-first traversal of directory tree is not lazy

    - by user855443
    I try to traverse the diretory tree. A naive depth-first traversal seems not to produce the data in a lazy fashion and runs out of memory. I next tried a breadth first approach, which shows the same problem - it uses all the memory available and then crashes. the code i have is: getFilePathBreadtFirst :: FilePath -> IO [FilePath] getFilePathBreadtFirst fp = do fileinfo <- getInfo fp res :: [FilePath] <- if isReadableDirectory fileinfo then do children <- getChildren fp lower <- mapM getFilePathBreadtFirst children return (children ++ concat lower) return (children ++ concat () else return [fp] -- should only return the files? return res getChildren :: FilePath -> IO [FilePath] getChildren path = do names <- getUsefulContents path let namesfull = map (path </>) names return namesfull testBF fn = do -- crashes for /home/frank, does not go to swap fps <- getFilePathBreadtFirst fn putStrLn $ unlines fps I think all the code is either linear or tail recursive, and I would expect that the listing of filenames starts immediately, but in fact it does not. Where is the error in my code and my thinking? where have I lost lazy evaluation?

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  • Architecture for Social Graph data that has a Time Frame Associated?

    - by Jay Stevens
    I am adding some "social" type features to an existing application. There are a limited # of node & edge types. Overall the data itself is relatively small (50,000 - 70,000 for each type of node) there will be a number of edges (relationships) between them (almost all directional). This, I know, is relatively easy to represent with an SDF store (such as BrightstarDB) or something like Microsoft's Trinity (or really many of the noSQL options). The thing that, I think, makes this a unique use case is that each relationship will have a timeframe associated with it (start and end dates). Right now, I'm thinking of just storing this in a relational structure and dealing with the headaches of "traversing the graph", but I'm looking for suggestions on a better approach (both in terms of data structure and server): Column ================ From_Node_ID Relationship To_Node_ID StartDate EndDate Any suggestions or thoughts are welcomed.

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  • Finding an A* heuristic for a directed graph

    - by Janis Peisenieks
    In a previous question, I asked about finding a route (or path if you will) in a city. That is all dandy. The solution I chose was with the A* algorithm, which really seems to suit my needs. What I find puzzling is heuristic. How do I find one in an environment without constant distance between 2 nodes? Meaning, not every 2 nodes have the same distance between them. What I have is nodes (junctures), streets with weight (which may also be one-way), a start/finish node (since the start and end is always in the same place) and a goal node. In an ordinary case, I would just use the same way I got to goal to go back, but since one of the streets could have been a one-way, that may not be possible. The main question How do I find a heuristic in a directed graph?

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  • Improving the running time of Breadth First Search and Adjacency List creation

    - by user45957
    We are given an array of integers where all elements are between 0-9. have to start from the 1st position and reach end in minimum no of moves such that we can from an index i move 1 position back and forward i.e i-1 and i+1 and jump to any index having the same value as index i. Time Limit : 1 second Max input size : 100000 I have tried to solve this problem use a single source shortest path approach using Breadth First Search and though BFS itself is O(V+E) and runs in time the adjacency list creation takes O(n2) time and therefore overall complexity becomes O(n2). is there any way i can decrease the time complexity of adjacency list creation? or is there a better and more efficient way of solving the problem? int main(){ vector<int> v; string str; vector<int> sets[10]; cin>>str; int in; for(int i=0;i<str.length();i++){ in=str[i]-'0'; v.push_back(in); sets[in].push_back(i); } int n=v.size(); if(n==1){ cout<<"0\n"; return 0; } if(v[0]==v[n-1]){ cout<<"1\n"; return 0; } vector<int> adj[100001]; for(int i=0;i<10;i++){ for(int j=0;j<sets[i].size();j++){ if(sets[i][j]>0) adj[sets[i][j]].push_back(sets[i][j]-1); if(sets[i][j]<n-1) adj[sets[i][j]].push_back(sets[i][j]+1); for(int k=j+1;k<sets[i].size();k++){ if(abs(sets[i][j]-sets[i][k])!=1){ adj[sets[i][j]].push_back(sets[i][k]); adj[sets[i][k]].push_back(sets[i][j]); } } } } queue<int> q; q.push(0); int dist[100001]; bool visited[100001]={false}; dist[0]=0; visited[0]=true; int c=0; while(!q.empty()){ int dq=q.front(); q.pop(); c++; for(int i=0;i<adj[dq].size();i++){ if(visited[adj[dq][i]]==false){ dist[adj[dq][i]]=dist[dq]+1; visited[adj[dq][i]]=true; q.push(adj[dq][i]); } } } cout<<dist[n-1]<<"\n"; return 0; }

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  • Finding the shortest path through a digraph that visits all nodes

    - by Boluc Papuccuoglu
    I am trying to find the shortest possible path that visits every node through a graph (a node may be visited more than once, the solution may pick any node as the starting node.). The graph is directed, meaning that being able to travel from node A to node B does not mean one can travel from node B to node A. All distances between nodes are equal. I was able to code a brute force search that found a path of only 27 nodes when I had 27 nodes and each node had a connection to 2 or 1 other node. However, the actual problem that I am trying to solve consists of 256 nodes, with each node connecting to either 4 or 3 other nodes. The brute force algorithm that solved the 27 node graph can produce a 415 node solution (not optimal) within a few seconds, but using the processing power I have at my disposal takes about 6 hours to arrive at a 402 node solution. What approach should I use to arrive at a solution that I can be certain is the optimal one? For example, use an optimizer algorithm to shorten a non-optimal solution? Or somehow adopt a brute force search that discards paths that are not optimal? EDIT: (Copying a comment to an answer here to better clarify the question) To clarify, I am not saying that there is a Hamiltonian path and I need to find it, I am trying to find the shortest path in the 256 node graph that visits each node AT LEAST once. With the 27 node run, I was able to find a Hamiltonian path, which assured me that it was an optimal solution. I want to find a solution for the 256 node graph which is the shortest.

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  • Looking for an algorithm to connect dots - shortest route

    - by e4ch
    I have written a program to solve a special puzzle, but now I'm kind of stuck at the following problem: I have about 3200 points/nodes/dots. Each of these points is connected to a few other points (usually 2-5, theoretical limit is 1-26). I have exactly one starting point and about 30 exit points (probably all of the exit points are connected to each other). Many of these 3200 points are probably not connected to neither start nor end point in any way, like a separate net, but all points are connected to at least one other point. I need to find the shortest number of hops to go from entry to exit. There is no distance between the points (unlike the road or train routing problem), just the number of hops counts. I need to find all solutions with the shortest number of hops, and not just one solution, but all. And potentially also solutions with one more hop etc. I expect to have a solution with about 30-50 hops to go from start to exit. I already tried: 1) randomly trying possibilities and just starting over when the count was bigger than a previous solution. I got first solution with 3500 hops, then it got down to about 97 after some minutes, but looking at the solutions I saw problems like unnecessary loops and stuff, so I tried to optimize a bit (like not going back where it came from etc.). More optimizations are possible, but this random thing doesn't find all best solutions or takes too long. 2) Recursively run through all ways from start (chess-problem-like) and breaking the try when it reached a previous point. This was looping at about a length of 120 nodes, so it tries chains that are (probably) by far too long. If we calculate 4 possibilities and 120 nodes, we're reaching 1.7E72 possibilities, which is not possible to calculate through. This is called Depth-first search (DFS) as I found out in the meantime. Maybe I should try Breadth-first search by adding some queue? The connections between the points are actually moves you can make in the game and the points are how the game looks like after you made the move. What would be the algorithm to use for this problem? I'm using C#.NET, but the language shouldn't matter.

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  • Ray-Box Intersection during Scene traversal with matrix transforms

    - by Myx
    Hello: There are a few ways that I'm testing my ray-box intersections: Using the ComputeIntersectionBox(...) method, that takes a ray and a box as arguments and computes the closest intersection of the ray and the box. This method works by forming a plane with each of the faces of the box and finding an intersection with each of the planes. Once an intersection is found, a check is made whether or not the point is on the surface of the box by checking that the intersection point is between the corner points. When I look at rays after running this algorithm on two different boxes, I obtain the correct intersections. Using ComputeIntersectionScene(...) method without using the matrix transformations on a scene that has two spheres, a dodecahedron (a triangular mesh), and two boxes. ComputeIntersectionScene(...) recursively traverses all of the nodes of the scene graph and computes the closest intersection with the given ray. This test in particular does not apply any transformations that parent nodes may have that also need to be applied to their children. With this test, I also obtain the correct intersections. Using ComputeIntersectionScene(...) method WITH the matrix transformations. This test works like the one above except that before finding an intersection between the ray and a node in the scene, the ray is transformed into the node's coordinate frame using the inverse of the node's transformation matrix and after the intersection has been computed, this intersection is transformed back into the world coordinates by applying the transformation matrix to the intersection point. When testing with the third method on the same scene file as described in 2, testing with 4 rays (thus one ray intersects the one sphere, one ray the the other sphere, one ray one box, and one ray the other box), only the two spheres get intersected and the two boxes do not get intersections. When I debug looking into my ComputeIntersectionBox(...) method, it actually tells me that the ray intersects every plane on the box but each intersection point does not lie on the box. This seems to be strange behavior, since when using test 2 without transformations, I obtain the correct box intersections (thus, I believe my ray-box intersection to be correct) and when using test 3 WITH transformations, I obtain the correct sphere intersections (thus, I believe my transformed ray should be OK). Any suggestions where I could be going wrong? Thank you in advance.

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  • Simple Fundamental Algorithm Question, binary tree traversal

    - by Ben
    I'm trying to explain to non-computer science major student with many questions. (1)What traverses tree? Is it just logic or actual on off switch generates 1s and 0s traveling the circuit board? where is this tree and node exists CPU/Memory in between? (2)If it is 1s and 0s HOW the circuits understand the line for example p=p.getLeft(); I said search the google or wiki.

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  • Monads and custom traversal functions in Haskell

    - by Bill
    Given the following simple BST definition: data Tree x = Empty | Leaf x | Node x (Tree x) (Tree x) deriving (Show, Eq) inOrder :: Tree x -> [x] inOrder Empty = [] inOrder (Leaf x) = [x] inOrder (Node root left right) = inOrder left ++ [root] ++ inOrder right I'd like to write an in-order function that can have side effects. I achieved that with: inOrderM :: (Show x, Monad m) => (x -> m a) -> Tree x -> m () inOrderM f (Empty) = return () inOrderM f (Leaf y) = f y >> return () inOrderM f (Node root left right) = inOrderM f left >> f root >> inOrderM f right -- print tree in order to stdout inOrderM print tree This works fine, but it seems repetitive - the same logic is already present in inOrder and my experience with Haskell leads me to believe that I'm probably doing something wrong if I'm writing a similar thing twice. Is there any way that I can write a single function inOrder that can take either pure or monadic functions?

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  • Web Application Nat Traversal

    - by pbreault
    We are deploying web applications in java using tomcat on client machines across the country. Once they are installed, we want to allow a remote access to these web applications through a central server, but we do not want our clients to have to open ports on their routers. Is there a way to tunnel the http traffic in a way that the central server can access the web application that is behind the firewall ? The central server has a static ip address and we have full control over it. We don't need to access the filesystem, we only want to access the web application itself through a browser.

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  • XSD traversal in VIM

    - by maayank
    I use VIM as my text editor and I edit a lot of XML and WSDL files. WSDL files have an XSD section. Is there some VIM plugin I can use to traverse the XSD types? i.e., if I have the following line and the caret is where the '|' sign is: <xsd:element minOccurs="0" name="FooName" type="Magic|FooType"/> and I press Ctrl+Alt+Foo (or some other magic combo) it will get me to the definition of MagicFooType, i.e.: <xsd:complexType name="MagicFooType"> I couldn't find how to use ctags for this and all the other plugins that I could find are for imperative languages (i.e. Java). Is there some plugin/script to do the job?

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  • pyramid traversal resource url no attribute __name__

    - by Santana
    So I have: resources.py: def _add(obj, name, parent): obj.__name__ = name obj.__parent__ = parent return obj class Root(object): __parent__ = __name__ = None def __init__(self, request): super(Root, self).__init__() self.request = request self.collection = request.db.post def __getitem__(self, key): if u'profile' in key: return Profile(self.request) class Profile(dict): def __init__(self, request): super(Profile, self).__init__() self.__name__ = u'profile' self.__parent__ = Root self.collection = request.db.posts def __getitem__(self, name): post = Dummy(self.collection.find_one(dict(username=name))) return _add(post, name, self) and I'm using MongoDB and pyramid_mongodb views.py: @view_config(context = Profile, renderer = 'templates/mytemplate.pt') def test_view(request): return {} and in mytemplate.pt: <p tal:repeat='item request.context'> ${item} </p> I can echo what's in the database (I'm using mongodb), but when I provided a URL for each item using resource_url() <p tal:repeat='item request.context'> <a href='${request.resource_url(item)}'>${item}</a> </p> I got an error: 'dict' object has no attribute '__name__', can someone help me?

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  • Namespace Traversal

    - by RikSaunderson
    I am trying to parse the following sample piece of XML: <?xml version="1.0" encoding="UTF-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soapenv:Body> <d2LogicalModel modelBaseVersion="1.0" xmlns="http://datex2.eu/schema/1_0/1_0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://datex2.eu/schema/1_0/1_0 http://datex2.eu/schema/1_0/1_0/DATEXIISchema_1_0_1_0.xsd"> <payloadPublication xsi:type="PredefinedLocationsPublication" lang="en"> <predefinedLocationSet id="GUID-NTCC-VariableMessageSignLocations"> <predefinedLocation id="VMS30082775"> <predefinedLocationName> <value lang="en">VMS M60/9084B</value> </predefinedLocationName> </predefinedLocation> </predefinedLocationSet> </payloadPublication> </d2LogicalModel> </soapenv:Body> </soapenv:Envelope> I specifically need to get at the contents of the top-level predefinedLocation tag. By my calculations, the correct XPath should be /soapenv:Envelope/soapenv:Body/d2LogicalModel/payloadPublication/predefinedLocationSet/predefinedLocation I am using the following C# code to parse the XML: string filename = "content-sample.xml"; XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(filename); XmlNamespaceManager nsmanager = new XmlNamespaceManager(xmlDoc.NameTable); nsmanager.AddNamespace("soapenv", "http://schemas.xmlsoap.org/soap/Envelope"); string xpath ="/soapenv:Envelope/soapenv:Body/d2LogicalModel/payloadPublication/predefinedLocationSet/predefinedLocation"; XmlNodeList itemNodes = xmlDoc.SelectNodes(xpath, nsmanager); However, this keeps coming up with no results. Can anyone shed any light on this, because I feel like I'm banging my head on a brick wall.

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