Search Results

Search found 81 results on 4 pages for 'urlpatterns'.

Page 2/4 | < Previous Page | 1 2 3 4  | Next Page >

  • django url - link problem

    - by dana
    i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from my template, using a link like Reply The problem is that i don't know how to use the above url as a link, meaning how can i 'pass the id parameter to a link'? thank you

    Read the article

  • django url from another template than the one associated with the view-function

    - by dana
    Heyy there, i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from another template than the one associated with the def-view that has this url. How should i do that? i have to put two render_to_response to one same function, in order to render the objects from both models? thank you!

    Read the article

  • django file serving issues

    - by tipu
    I have in my url patterns, urlpatterns += patterns('', (r'^(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/home/tipu/Dropbox/dev/workspace/search/images'}) In my template when I do <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}style.css" /> It serves the css just fine. But the file logo.png, that's in the same directory as style.css, doesn't show when I do this: <img src = "{{ MEDIA_URL }}logo.png" id = "logo" /> Any idea why?

    Read the article

  • django url matching with Lighttpd fastcgi

    - by 7seb
    I have a problem with url. I can access the djando app home page ( localhost/djangotest/ ) but can't access the admin section ( localhost/djangotest/admin/ ). I can access it using the django server instead of lighttpd. Lighttp conf : fastcgi.server = ( "/djangotest/" => ( "main" => ( "host" => "127.0.0.1", "port" => 3033, "check-local" => "disable", ) ), ) url.rewrite-once = ( "^(/media.*)$" => "$1", "^/favicon\.ico$" => "/media/favicon.ico", "^/djangotest/[^?](.*)$" => "/djangotest/?$1", ) The django url.py is just : (i just uncommented the good lines) : from django.conf.urls.defaults import patterns, include, url from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^admin/', include(admin.site.urls)), ) I tried many things but without success ... (no need to link to https://docs.djangoproject.com/en/dev/howto/deployment/fastcgi/ ) lighttpd/1.4.28 Python 2.7.2+ Django 1.3.0

    Read the article

  • In Django, what's the best way to handle optional url parameters from the template?

    - by Thierry Lam
    I have the following type of urls which are both valid: hello/ hello/1234/ My urls.py has the following: urlpatterns = patterns('hello.views', url(r'^$', 'index', name='index'), url(r'^(?P<user_id>\d+)/$', 'index', name='index'), ) In my views.py, when I pass user_id to the template, it defaults to 0 if not specified. My template looks like the following, I'm using namespace hello for my hello app: {% url hello:index user_id %} If user_id is not specified, the url defaults to hello/0/. The only way I can think of preventing the default 0 from showing in the url is by an if stmt: {% if user_id %} {% url hello:index user_id %} {% else %} {% url hello:index %} {% endif %} The above will give me hello/ if there are no user_id and hello/1234/ if it's present. Is the above solution the best way to solve this issue?

    Read the article

  • django ignoring admin.py

    - by noam
    I am trying to enable the admin for my app. I managed to get the admin running, but I can't seem to make my models appear on the admin page. I tried following the tutorial (here) which says: (Quote) Just one thing to do: We need to tell the admin that Poll objects have an admin interface. To do this, create a file called admin.py in your polls directory, and edit it to look like this: from polls.models import Poll from django.contrib import admin admin.site.register(Poll) (end quote) I added an admin.py file as instructed, and also added the following lines into urls.py: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', ... (r'^admin/', include(admin.site.urls)), ) but it appears to have no effect. I even added a print 1 at the first line of admin.py and I see that the printout never happens, So I guess django doesn't know about my admin.py. As said, I can enter the admin site, I just don't see anything other than "groups", "users" and "sites". What step am I missing?

    Read the article

  • Django: reverse lookup URL of feeds?

    - by Santa
    I am having trouble doing a reverse URL lookup for Django-generated feeds. I have the following setup in urls.py: feeds = { 'latest': LatestEntries, } urlpatterns = patterns('', # ... # enable feeds (RSS) url(r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed', {'feed_dict': feeds}, name='feeds_view'), ) I have tried using the following template tag: <a href="{% url feeds_view latest %}">RSS feeds</a> But the resulting link is not what want (http://my.domain.com/feeds//). It should be http://my.domain.com/feeds/latest/. For now, I am using a hack to generate the URL for the template: <a href="http://{{ request.META.HTTP_HOST }}/feeds/latest">RSS feeds</a> But, as you can see, it clearly is not DRY. Is there something I am missing?

    Read the article

  • Django/MySQL - __istartswith not producing case-insensitive query.

    - by TheLizardKing
    I make use of generic views and I am attempting to query my MySQL db (utf8_bin collation) in a case insensitive manor to try to find all my song titles that start with a particular letter. view.py def tracks_by_title(request, starts_with): return object_list( request, queryset = Track.objects.filter(title__istartswith=starts_with), template_name = 'tlkmusic_base/titles_list.html', template_object_name = 'tracks', paginate_by = 25, ) and my urls.py urlpatterns = patterns('tlkmusic.apps.tlkmusic_base.views', (r'^titles/(?P<starts_with>\w)/$', tracks_by_title), ) the query it produces according to the django debug toolbar is: SELECT `tracks`.`id`, `tracks`.`url`, `tracks`.`artist`, `tracks`.`album`, `tracks`.`genre`, `tracks`.`year`, `tracks`.`title`, `tracks`.`comment`, `tracks`.`tracknumber`, `tracks`.`discnumber`, `tracks`.`bitrate`, `tracks`.`length`, `tracks`.`samplerate`, `tracks`.`filesize`, `tracks`.`createdate`, `tracks`.`modifydate` FROM `tracks` WHERE `tracks`.`title` LIKE a% LIMIT 1 specifically this line: WHERE `tracks`.`title` LIKE a% LIMIT 1 Why is it not ILIKE which is what I was expecting by using __istartswith? I am using Django 1.1.1 on Ubuntu.

    Read the article

  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

    Read the article

  • Correct way to get absolute url in django

    - by dreamiurg
    A problem that I stumbled upon recently, and, even though I solved it, I would like to hear your opinion of what correct/simple/adopted solution would be. I'm developing website using Django + python. When I run it on local machine with "python manage.py runserver", local address is http://127.0.0.1:8000/ by default. However, on production server my app has other url, with path - like "http://server.name/myproj/" I need to generate and use permanent urls. If I'm using {% url view params %}, I'm getting paths that are relative to / , since my urls.py contains this urlpatterns = patterns('', (r'^(\d+)?$', 'myproj.myapp.views.index'), (r'^img/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/img' }), (r'^css/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/css' }), ) So far, I see 2 solutions: modify urls.py, include '/myproj/' in case of production run use request.build_absolute_uri() for creating link in views.py or pass some variable with 'hostname:port/path' in templates Are there prettier ways to deal with this problem? Thank you.

    Read the article

  • url template tag in django template

    - by user192048
    guys: I was trying to use the url template tag in django, but no lucky, I defined my urls.py like this urlpatterns = patterns('', url(r'^analyse/$', views.home, name="home"), url(r'^analyse/index.html', views.index, name="index"), url(r'^analyse/setup.html', views.setup, name="setup"), url(r'^analyse/show.html', views.show, name="show"), url(r'^analyse/generate.html', views.generate, name="generate"), I defined the url pattern in my view like this {% url 'show'%} then I got this error message Caught an exception while rendering: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. Original Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 155, in render nodelist.append(node.render(context)) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 382, in render raise e NoReverseMatch: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. I am wondering why django failed to render? what is the right way to define it in the tempalte?

    Read the article

  • simply way to add another webapp framework to my project.

    - by zjm1126
    one webapp project has many url and i have to change this: ('/addTopic', AddTopic), ('/delTopic', DeleteTopic), ('/addPost', AddPost), ('/delPost', DeletePost), to this: ('/tribes/addTopic', AddTopic), ('/tribes/delTopic', DeleteTopic), ('/tribes/addPost', AddPost), ('/tribes/delPost', DeletePost), but ,if i add this to my project ,i have to change the url in every py file or html file , in django it can be this : urlpatterns = patterns('', (r'^articles/2003/$', 'news.views.special_case_2003')), ) it is easy to add the url of 'news' to my peoject, but does webapp has this ? thanks updated: (1) my main page url is : ('/', MainPage), ('/sign', Guestbook), (2) the url of a webapp project that i want to add is : ('/', MainPage), ('/logout', LogoutPage), ('/login_response', LoginHandler), and i want to change (1) to this: ('/', MainPage), ('/sign', Guestbook), ('/aa/', p2.MainPage), ('/aa/logout', p2.LogoutPage), ('/aa/login_response', p2.LoginHandler), so i have to change so many url like / to /aa/ , or change /logout to /aa/logout in py file and html file , that is a hard work so any simple way to do this ?

    Read the article

  • django username in url, instead of id

    - by dana
    Hello, in a mini virtual community, i have a profile_view function, so that i can view the profile of any registered user. The profile view function has as a parameter the id of the user wich the profile belongs to, so that when i want to access the profile of user 2 for example, i call it like that: http://127.0.0.1:8000/accounts/profile_view/2/ My problem is that i would like to have the username in the url, and NOT the id. I try to modify my code as follows, but it doesn't work still. Here is my code: view: def profile_view(request, user): u = User.objects.get(pk=user) up = UserProfile.objects.get(created_by = u) cv = UserProfile.objects.filter(created_by = User.objects.get(pk=user)) blog = New.objects.filter(created_by = u) replies = Reply.objects.filter(reply_to = blog) vote = Vote.objects.filter(voted=blog) following = Relations.objects.filter(initiated_by = u) follower = Relations.objects.filter(follow = u) return render_to_response('profile/publicProfile.html', { 'vote': vote, 'u':u, 'up':up, 'cv': cv, 'ing': following.order_by('-date_initiated'), 'er': follower.order_by('-date_follow'), 'list':blog.order_by('-date'), 'replies':replies }, context_instance=RequestContext(request)) and my url: urlpatterns = patterns('', url(r'^profile_view/(?P<user>\d+)/$', profile_view, name='profile_view'), thanks in advance!

    Read the article

  • Pass a captured named regular expression to URL dictionary in generic view

    - by Trent Jurewicz
    I am working with a generic view in Django. I want to capture a named group parameter in the URL and pass the value to the URL pattern dictionary. For example, in the URLConf below, I want to capture the parent_slug value in the URL and pass it to the queryset dictionary value like so: urlpatterns = patterns('django.views.generic.list_detail', (r'^(?P<parent_slugs>[-\w])$', 'object_list', {'queryset':Promotion.objects.filter(category=parent_slug)}, 'promo_promotion_list'), ) Is this possible to do in one URLConf entry, or would it be wiser if I create a custom view to capture the value and pass the queryset directly to the generic view from my overridden view?

    Read the article

  • trying to load css/images in django

    - by tipu
    I looked http://docs.djangoproject.com/en/dev/howto/static-files/ already, but am still confused on how to get css/image files loaded. On my server, the images folder and css file are located at /srv/twingle/search my urls.py 1 from django.conf.urls.defaults import * 2 3 # Uncomment the next two lines to enable the admin: 4 # from django.contrib import admin 5 # admin.autodiscover() 6 7 urlpatterns = patterns('twingle.search.views', 8 url(r'^$', 'index'), 9 url(r'^search/(?P<param>\w+)$', 'index'), 10 ) 11 (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', 12 {'document_root': '/srv/twingle/search'}), 13 I try to access my css as follows, <link rel="stylesheet" type="text/css" href="/site_media/style.css" /> That's exactly how the tutorial says to do it, but it doesn't work. Any suggestions?

    Read the article

  • Django: request object to template context transparancy

    - by anars
    Hi! I want to include an initialized data structure in my request object, making it accessible in the context object from my templates. What I'm doing right now is passing it manually and tiresome within all my views: render_to_response(...., ( {'menu': RequestContext(request)})) The request object contains the key,value pair which is injected using a custom context processor. While this works, I had hoped there was a more generic way of passing selected parts of the request object to the template context. I've tried passing it by generic views, but as it turns out the request object isn't instantiated when parsing the urlpatterns list.

    Read the article

  • Django test client gets 301 redirection when accessing url

    - by Michal Klich
    I am writing unittests for django views. I have observed that one of my views returns redirection code 301, which is not expected. Here is my views.py mentioned earlier. def index(request): return render(request, 'index.html', {'form': QueryForm()}) def query(request): if request.is_ajax(): form = QueryForm(request.POST) return HttpResponse('valid') Below is urls.py. urlpatterns = patterns('', url(r'^$', 'core.views.index'), url(r'^query/$', 'core.views.query') ) And unittest that will fail. def so_test(self): response = self.client.post('/') self.assertEquals(response.status_code, 200) response = self.client.post('/query', {}) self.assertEquals(response.status_code, 200) My question is: why there is status 301 returned?

    Read the article

  • django threadedcomments

    - by Patrick
    Hi folks, I would like to setup a comment systems on my site, using django threadedcomments, and I follow all the steps in the Tutorial, however, I get the following error: No module named newforms.util I am not sure what causing this issue, here is my configuration: #settings.py INSTALLED_APPS = ( 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'myproject.myapp', 'threadedcomments', ) #urls.py from django.conf import settings from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^threadedcomments/', include('threadedcomments.urls')), ) Please let me know if there is another better choice for commenting, as long as the comment system is flexible and able to do lot of customization, as well as threadedcomment, of coz, integrating with Rating, I am happy to use the other one. Thanks guys.

    Read the article

  • Django: url and content creation results in 500 and no apache error log entry

    - by user1684082
    If i try to open a created url i get an 500 error. My procedure was: First python manage.py startapp black I added in project/settings.py under INSTALLED_APPS 'black', I added in project/urls.py url(r'^test/', include('black.urls')), Content of black/urls.py is: from django.conf.urls import patterns, url from black import views urlpatterns = patterns('', url(r'^$', views.index, name='index') ) And content of black/views.py: from django.http import HttpResponse def index(request): return HttpResponse("SHOW ME: BLACK") After all i synced the database. I can't see any error in apache-error-log and also not in my posted django files. What could cause this?

    Read the article

  • How to use external static files with Django (serving external files once again)?

    - by Tomas Novotny
    Hi, even after Googling and reading all relevant posts at StackOverflow, I still can't get static files working in my Django application. Here is how my files look: settings.py MEDIA_ROOT = os.path.join(SITE_ROOT, 'static') MEDIA_URL = '/static/' urs.py from DjangoBandCreatorSite.settings import DEBUG if DEBUG: urlpatterns += patterns('', ( r'^static/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'static'} )) template: <script type="text/javascript" src="/static/jquery.js"></script> <script type="text/javascript"> I am trying to use jquery.js stored in directory "static". I am using: Windows XP Python 2.6.4 Django 1.2.3 Thank you very much for any help

    Read the article

  • Django - The included urlconf doesn't have any patterns in it

    - by unsorted
    My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) Anyone know what's wrong? This is driving me crazy. Thanks,

    Read the article

  • Does Django cache url regex patterns somehow?

    - by Emre Sevinç
    I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

    Read the article

  • django {% tag %} problem

    - by Sevenearths
    I don't know if its me but {% tag ??? %} has bee behaving a bit sporadically round me (django ver 1.2.3). I have the following main.html file: <html> {% include 'main/main_css.html' %} <body> test! <a href="{% url login.views.logout_view %}">logout</a> test! <a href="{% url client.views.client_search_last_name_view %}">logout</a> </body> </html> with the urls.py being: from django.conf.urls.defaults import * import settings from login.views import * from mainapp.views import * from client.views import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^weclaim/', include('weclaim.foo.urls')), (r'^login/$', 'login.views.login_view'), (r'^logout/$', 'login.views.logout_view'), (r'^$', 'mainapp.views.main_view'), (r'^client/search/last_name/(A-Za-z)/$', 'client.views.client_search_last_name_view'), #(r'^client/search/post_code/(A-Za-z)/$', 'client.views.client_search_last_name_view'), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^static/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), ) and the views.py for login being: from django.shortcuts import render_to_response, redirect from django.template import RequestContext from django.contrib import auth import mainapp.views def login_view(request): if request.method == 'POST': uname = request.POST.get('username', '') psword = request.POST.get('password', '') user = auth.authenticate(username=uname, password=psword) # if the user logs in and is active if user is not None and user.is_active: auth.login(request, user) return redirect(mainapp.views.main_view) else: return render_to_response('loginpage.html', {'login_failed': '1',}, context_instance=RequestContext(request)) else: return render_to_response('loginpage.html', {'dave': '1',}, context_instance=RequestContext(request)) def logout_view(request): auth.logout(request) return render_to_response('loginpage.html', {'logged_out': '1',}, context_instance=RequestContext(request)) and the views.py for clients being: from django.shortcuts import render_to_response, redirect from django.template import RequestContext import login.views def client_search_last_name_view(request): if request.user.is_authenticated(): return render_to_response('client/client_search_last_name.html', {}, context_instance=RequestContext(request)) else: return redirect(login.views.login_view) Yet when I login it django raises an 'NoReverseMatch' for {% url client.views.client_search_last_name_view %} but not for {% url login.views.logout_view %} Now why would this be?

    Read the article

  • django+uploadify - don't working

    - by Erico
    Hi, I'm trying to use an example posted on the "github" the link is http://github.com/tstone/django-uploadify. And I'm having trouble getting work. can you help me? I followed step by step, but does not work. Accessing the "URL" / upload / the only thing is that returns "True" part of settings.py import os PROJECT_ROOT_PATH = os.path.dirname(os.path.abspath(file)) MEDIA_ROOT = os.path.join(PROJECT_ROOT_PATH, 'media') TEMPLATE_DIRS = ( os.path.join(PROJECT_ROOT_PATH, 'templates')) urls.py from django.conf.urls.defaults import * from django.conf import settings from teste.uploadify.views import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), url(r'upload/$', upload, name='uploadify_upload'), ) views.py from django.http import HttpResponse import django.dispatch upload_received = django.dispatch.Signal(providing_args=['data']) def upload(request, *args, **kwargs): if request.method == 'POST': if request.FILES: upload_received.send(sender='uploadify', data=request.FILES['Filedata']) return HttpResponse('True') models.py from django.db import models def upload_received_handler(sender, data, **kwargs): if file: new_media = Media.objects.create( file = data, new_upload = True, ) new_media.save() upload_received.connect(upload_received_handler, dispatch_uid='uploadify.media.upload_received') class Media(models.Model): file = models.FileField(upload_to='images/upload/', null=True, blank=True) new_upload = models.BooleanField() uploadify_tags.py from django import template from teste import settings register = template.Library() @register.inclusion_tag('uploadify/multi_file_upload.html', takes_context=True) def multi_file_upload(context, upload_complete_url): """ * filesUploaded - The total number of files uploaded * errors - The total number of errors while uploading * allBytesLoaded - The total number of bytes uploaded * speed - The average speed of all uploaded files """ return { 'upload_complete_url' : upload_complete_url, 'uploadify_path' : settings.UPLOADIFY_PATH, # checar essa linha 'upload_path' : settings.UPLOADIFY_UPLOAD_PATH, } template - uploadify/multi_file_upload.html {% load uploadify_tags }{ multi_file_upload '/media/images/upload/' %} <script type="text/javascript" src="{{ MEDIA_URL }}js/swfobject.js"></script> <script type="text/javascript" src="{{ MEDIA_URL }}js/jquery.uploadify.js"></script> <div id="uploadify" class="multi-file-upload"><input id="fileInput" name="fileInput" type="file" /></div> <script type="text/javascript">// <![CDATA[ $(document).ready(function() { $('#fileInput').uploadify({ 'uploader' : '/media/swf/uploadify.swf', 'script' : '{% url uploadify_upload %}', 'cancelImg' : '/media/images/uploadify-remove.png/', 'auto' : true, 'folder' : '/media/images/upload/', 'multi' : true, 'onAllComplete' : allComplete }); }); function allComplete(event, data) { $('#uploadify').load('{{ upload_complete_url }}', { 'filesUploaded' : data.filesUploaded, 'errorCount' : data.errors, 'allBytesLoaded' : data.allBytesLoaded, 'speed' : data.speed }); // raise custom event $('#uploadify') .trigger('allUploadsComplete', data); } // ]]</script>

    Read the article

  • model not showing up in django admin.

    - by Zayatzz
    Hi. I have ceated several django apps and stuffs for my own fund and so far everything has been working fine. Now i just created new project (django 1.2.1) and have run into trouble from 1st moments. I created new app - game and new model Game. i created admin.py and put related stuff into it. Ran syncdb and went to check into admin. Model did not show up there. I proceeded to check and doublecheck and read through previous similar threads: http://stackoverflow.com/questions/1839927/registered-models-do-not-show-up-in-admin http://stackoverflow.com/questions/1694259/django-app-not-showing-up-in-admin-interface But as far as i can tell, they dont help me either. Perhaps someone else can point this out for me. models.py in game app: # -*- coding: utf-8 -*- from django.db import models class Game(models.Model): type = models.IntegerField(blank=False, null=False, default=1) teamone = models.CharField(max_length=100, blank=False, null=False) teamtwo = models.CharField(max_length=100, blank=False, null=False) gametime = models.DateTimeField(blank=False, null=False) admin.py in game app: # -*- coding: utf-8 -*- from jalka.game.models import Game from django.contrib import admin class GameAdmin(admin.ModelAdmin): list_display = ['type', 'teamone', 'teamtwo', 'gametime'] admin.site.register(Game, GameAdmin) project settings.py: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', ) ROOT_URLCONF = 'jalka.urls' TEMPLATE_DIRS = ( "/home/projects/jalka/templates/" ) INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', 'game', ) urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^jalka/', include('jalka.foo.urls')), (r'^admin/', include(admin.site.urls)), ) Alan.

    Read the article

< Previous Page | 1 2 3 4  | Next Page >