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  • Dynamically Delete inline formsets in Django

    - by BenMills
    Is it possible to have Django automatically delete formsets that are not present in the request? So for example if I had three inline formsets represented in HTML when I loaded my edit page and I use javascript to remove two of those when the request is processes Django sees that those two forms are no longer their and deletes them.

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  • Django template can't see CSS files

    - by Technical Bard
    I'm building a django app and I can't get the templates to see the CSS files... My settings.py file looks like: MEDIA_ROOT = os.path.join(os.path.abspath(os.path.dirname(__file__)), 'media') MEDIA_URL = '/media/' I've got the CSS files in /mysite/media/css/ and the template code contains: <link rel="stylesheet" type="text/css" href="/media/css/site_base.css" />` then, in the url.py file I have: # DEVELOPMENT ONLY (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/media'}), but the development server serves the plain html (without styles). What am I doing wrong?

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  • Cookieless Django - Django with no cookies

    - by phoebebright
    As I'm writing a django site from government bodies I'm not going to be able to use cookies. I found this snippet http://djangosnippets.org/snippets/1540/ but it's currently not allowing users to login. Before I start debugging I wondered if anyone else has solved this problem with this snippet or in any other way?

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  • Django OpenID django-openid-auth Login Error.

    - by gramware
    I get the following error when attempting to use django-openid-auth OpenID discovery error: No usable OpenID services found for *******@gmail.com I have followed the instructions that come with it, though it seems there is something I am missing. the installation is on my localhost.

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  • No Module named django.core

    - by Sirish Kumar
    Hi, I have updated to latest Django version 1.0.2 after uninstalling my old Django version.But now when I run django-admin.py I get the following error. How can I resolve this? Traceback (most recent call last): File "C:\Python25\Lib\site-packages\django\bin\django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core

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  • No Module named django.core

    - by Sirish Kumar
    Hi, I have updated to latest Django version 1.0.2 after uninstalling my old Django version.But now when I run django-admin.py I get the following error. How can I resolve this? Traceback (most recent call last): File "C:\Python25\Lib\site-packages\django\bin\django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core

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  • Preventing a confirmation pop-up when updating fields in Word

    - by Gilles
    In Word 2007, an obvious candidate for updating all the fields in a range is myrange.Fields.Update But if the range is the element of ActiveDocument.StoryRanges corresponding to the footnotes, endnotes or comments, this triggers a confirmation pop-up “Word cannot undo this action. Do you want to continue?” What is this pop-up telling me about? How do I get rid of it (if it's not important)? An obvious workaround is to iterate over the fields and call each field's Update method. It doesn't fire up that question. But if I do this, what do I miss? following up to How do I update all fields in a Word document

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  • Why are hidden fields used?

    - by Pavan Reddy
    I have always seen a lot of hidden fields used in web applications. I have worked with code which is written to use a lot of hidden fields and the data values from the visible fields sent back and forth to them. Though I fail to understand why the hidden fields are used. I can almost always think of ways to resolve the same problem without the use of hidden fields. How do hidden fields help in design? Can anyone tell me what exactly is the advantage that hidden fields provide? Why are hidden fields used?

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  • How to create reusable fields in Word

    - by Mystere Man
    I would like to create reusable fields that I can type in, then reuse those fields throughout the document without having to retype them. As an example, I have a cover sheet that contains "Title", "Document ID", "Version Number", and "Published Date". I used the MACROBUTTON trick to create a field that someone can just click on and type, but I don't see how I can re-use what is typed in other parts of the document (such as putting the Document title in the header). I've found something called "fill-in" fields, which don't seem to be what i'm looking for, and "ASK" fields, but that creates a dialog that you have to enter the information into. I'm trying to create a generic template for my documentation needs. Can anyone suggest a method to do what I am looking for?

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  • Django - need to split a table across multiple locations [closed]

    - by MikeRand
    Hi all, I have a Django project to track our company's restructuring projects. Here's the very simple model: class Project(models.Model): code = models.CharField(max_length=30) description = models.CharField(max_length=60) class Employee(models.Model): project = models.ForeignKey(Project) employee_id = models.IntegerField() country_code = models.CharField(max_length=3) severance = models.IntegerField() Due to regulations in some European countries, I'm not allowed to keep employee-level severance information in a database that sits on a box outside of that country. In Django, how do I manage the need to have my Employee table split across multiple databases based on an Employee attribute (i.e. country_code) in a way that doesn't impact anything else in the project (e.g. views, templates, admin)? Thanks, Mike

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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Use the Django ORM in a standalone script (again)

    - by Rishabh Manocha
    I'm trying to use the Django ORM in some standalone screen scraping scripts. I know this question has been asked before, but I'm unable to figure out a good solution for my particular problem. I have a Django project with defined models. What I would like to do is use these models and the ORM in my scraping script. My directory structure is something like this: project scrape #scraping scripts ... test.py web django_project settings.py ... #Django files I tried doing the following in project/scrape/test.py: print os.path.join(os.path.abspath('..'), 'web', 'django_project') sys.path.append(os.path.join(os.path.abspath('..'), 'web', 'django_project')) print sys.path print "-------" os.environ['DJANGO_SETTINGS_MODULE'] = 'django_project.settings' #print os.environ from django_project.myapp.models import MyModel print MyModel.objects.count() However, I get an ImportError when I try to run test.py: Traceback (most recent call last): File "test.py", line 12, in <module> from django_project.myapp.models import MyModel ImportError: No module named django_project.myapp.models One solution I found around this problem is to create a symbolic link to ../web/govcheck in the scrape folder: :scrape rmanocha$ ln -s ../web/govcheck ./govcheck With this, I can then run test.py just fine. However, this seems like a hack, and more importantly, is not very portable (I will have to create this symbolic link everywhere I run this code). So, I was wondering if anyone has any better solutions for my problem?

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  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

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  • Pydev and Django: Shell not finding certain modules?

    - by Rosarch
    I am developing a Django project with PyDev in Eclipse. For a while, PyDev's Django Shell worked great. Now, it doesn't: >>> import sys; print('%s %s' % (sys.executable or sys.platform, sys.version)) C:\Python26\python.exe 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] >>> >>> from django.core import management;import mysite.settings as settings;management.setup_environ(settings) Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.settings >>> The dev server runs just fine. What could I be doing wrong? The models module is also conspicuously absent: >>> import mysite.myapp.models Traceback (most recent call last): File "<console>", line 1, in <module> ImportError: No module named mysite.myapp.models On the normal command line, outside of PyDev, the shell works fine. Why could this be happening?

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  • Django Database design -- Is this a good stragety for overriding defaults

    - by rh0dium
    Hi SO's I have a question on good database design practices and I would like to leverage you guys for pointers. The project started out simple. Hey we have a bunch of questions we want answered for every project (no problem) Which turned into... Hey we have so many questions can we group them into sections (yup we can do that) Which lead into.. Can we weight these questions and I don't really want some of these questions for my project (Yes but we are getting difficult) And then I'm thinking they will want to have each section have it's own weight.. Requirements So there's the requirements - For n number of project Allow a admin member the ability select the questions for a project Allow the admin member to re-weigh or use the default weights for the questions Allow the admin member to re-weight the sections Allow team members to answer the questions. So here is what I came up with. Please feel free to comment and provide better examples models.py from django.db import models from django.contrib.sites.models import Site from django.conf import settings class Section(models.Model): """ This describes the various sections for a checklist: """ name = models.CharField(max_length=64) description = models.TextField() class Question(models.Model): """ This simply provides a simple way to list out the questions. """ question = models.CharField(max_length=255) answer_type = models.CharField(max_length=16) description = models.TextField() section = models.ForeignKey(Section) class ProjectQuestion(models.Model): """ These are the questions relevant to the project """ question = models.ForeignKey(Question) answer = models.CharField(max_length=255) required = models.BooleanField(default=True) weight = models.FloatField(default = XXX) class Project(models.Model): """ Here is where we want to gather our questions """ questions = models.ManyToManyField(ProjectQuestion) Immediate questions: - When I start a project - any ideas on how to "pre-populate" the questions (and ultimately the weights) for the project? - Is there a generally accepted method for doing this process that I am missing? Basically the idea that you refer to the questions overide your own default weight, and store the answer? - It appears that a good chuck of the work will be done in the views and that a lot of checking will need to occur there? Is that OK? Again - feel free to give me better strategies!! Thanks

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  • django-social-auth for Facebook is redirecting home and not logging in

    - by Scott Rogowski
    I have had django-social-auth working for Google for quite some time now but am having problems with Facebook. I am at the point where clicking on the /login/facebook/ link will take me to the Facebook authorization page. I then click "go to app" and it redirects me to my home page but does not log in or create a user but does put some strange "#=" onto the back of my URL. Reading up on that, here https://developers.facebook.com/blog/post/552/, and here https://github.com/omab/django-social-auth/issues/199, it seems that would be happening if the redirect uri was not defined. However, on my facebook app settings, I have the following (replacing my site with example.com): + App Namespace: "example" + Site URL: "http://example.com/complete/facebook/" + Site Domain: "example.com" + Sandbox Mode: "On" + Post-Authorize Redirect URL: "http://apps.facebook.com/example/" + Deauthorize URL: "http://www.example.com/" + Post-Authorize URL: "http://example.com/complete/facebook/" The request that django-social-auth is sending to facebook is (replacing my info again): "https://www.facebook.com/dialog/oauth?scope=email&state=*&redirect_uri=http%3A%2F%2Fexample.com%2Fcomplete%2Ffacebook%2F%3Fredirect_state%3D***&client_id=*" The /complete/facebook/ is what is in the documentation and google works as /complete/google/ What am I missing here?

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  • Using django and django-voting app, how can I order a queryset according to the votes of each item?

    - by snz3
    (I'm new to python and django so please bear with me for a second. I apologise if this has been answered elsewhere and couldn't find it) Let's say I have a Link model and through the django-voting application users can vote on link instances. How can I order those link instances according to their score, eg. display those with the higher score first. I assume I could use the get_top manager of django-voting, but that would only give me the top scoring link instances and wouldn't take into consideration other parameters I would like to add (for example, those links that belong to a specific user or paging or whatever). My guess would be to write a custom manager for my Link model where by I can filter a queryset according to each item's score. If I understand correctly that will require me to loop through each item, check its score, and then place it a list (or dictionary) which will then be sorted according to the score of each item. That wouldn't return a queryset but a dictionary with each item. Am I missing something here?

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  • Django IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • django: results in in_bulk style without IDs

    - by valya
    in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a dictionary of Ints to Places with indexes - primary keys. How to avoid using range in this situation (and avoid using a special query for ids, I just want to get all objects in this dictionary format) >>> Place.objects.in_bulk() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.5/site-packages/Django-1.1.1-py2.5.egg/django/db/models/manager.py", line 144, in in_bulk return self.get_query_set().in_bulk(*args, **kwargs) TypeError: in_bulk() takes exactly 2 arguments (1 given) >>> Place.objects.in_bulk(range(1, 100)) {1L: <Place: "??? ????">, 3L: <Place: "???????????? ?????">, 4L: <Place: "????????? "??????"">, 5L: <Place: "????????? "??????"">, 8L: <Place: "????????? "??????????????"">, 9L: <Place: "??????? ????????">, 10L: <Place: "????????? ???????">, 11L: <Place: "??????????????? ???">, 14L: <Place: "????? ????? ??????">}

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  • Connecting a django application to a drupal database?

    - by Hans
    I have a 3 - 4000 nodes in a drupal 6 installation on mysql and want to access these data through my django application. I have used manage.py inspectdb to get a skeleton of a model structure. I guess that there are good/historical reasons for drupal's database schemes, but find that there are some hard to understand structure and that there are some challenges in applying django models on the database. Some experiences this far are: node and node revision are intertwined and I solved this by using a OneToOneField (don't need the versions). This meens that the node's body gets accessible through node.vid.body, but it works. Foreign keys need to define the proper db_column to sort out the primary keys. Terms need to use an intermediary table with ManyToManyField.through. Drupal stores both the original and the thumbnailed/resized versions of any image as files in the files table. Does anyone have experiences in accessing drupal data in django? Are there better solution to for example the node <- node revision relationship? Drupal stores time/dates as unix-style timestamps in integerfields. Any recommendations? How about time zones?

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  • Django model fields getter / setter

    - by pistacchio
    Hi, is there something like getters and setters for django model's fields? For example, I have a text field in which i need to make a string replace before it get saved (in the admin panel, for both insert and update operations) and make another, different replace each time it is read. Those string replace are dynamic and need to be done at the moment of saving and reading. As I'm using python 2.5, I cannot use python 2.6 getters / setters. Any help?

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