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  • Modify Django Forms

    - by Ninefingers
    Hi All, I've recently been developing on the django platform and have stumbled upon Django Forms (forms.Form/forms.ModelForm) as ways of creating <form> html. Now, this is brilliant for quick stuff but what I'm trying to do is a little bit more complicated. Consider a DateField - my current form has fields for day, month and year and constructs a python date object from that. However, a django form creates a single textbox in which the correct format (say 2010-06-15) must be entered. As another example, for large fields I need to replace <input> with <textarea>. I'd like to take advantage of Django's forms for simple validation but I need something simpler for my users. So my question is: can I intercept the rendering of one of these objects to write out the html as I like? If so, do I have to do all the writing myself or can I only do those objects I wish to re-write? Thanks in advance.

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  • Django Form Preview

    - by Mark Kecko
    I'm trying to use django's FormPreview and I can't get it to work properly. Here's my code: forms.py class MyForm(forms.ModelForm): status = forms.TypedChoiceField( coerce=int, choices=LIST_STATUS, label="type", widget=forms.RadioSelect ) description = forms.CharField(widget = forms.Textarea) stage = forms.CharField() def __init__(self, useradd=None, *args, **kwargs): super(MyForm, self).__init__(*args, **kwargs) self.fields['firm'].label = "Firm" class Meta: model = MyModel fields = ['status', 'description', 'stage'] class MyFormPreview(FormPreview): form_template = 'templates/post.html' preview_template = 'templates/review.html' def process_preview(self, request, cleaned_data): print "processed" def done(self, request, cleaned_data): print "done" # Do something with the cleaned_data, then redirect # to a "success" page. return HttpResponseRedirect('/') urls.py (r'^post/$', MyFormPreview(MyForm)), post.html <form id = "post_ad" action = "" method = "POST" enctype="multipart/form-data"> <table> {{form.as_table}} </table> <input type="submit" name="save" value="Post" /> </form> When I go to /post/ I get the correct form and I fill it out. When I submit the form it goes right back to /post/ but but there are no errors (I've tried displaying {{errors}}) and the form is empty. None of my print statements execute. I'm not sure what I'm missing. Can anyone help me out? I can't find any documentation besides what's on the django site. Also, what's the "preview" variable called that I should use in my preview.html template? {{preview}} or do I just do {{form}} again? -- Answered below. I tried adding 'django.contrib.formtools' to my installed_apps in settings and I tried using the code from the default form templates from django.contrib as suggested below. Still, when I submit the form I go right back to the post template, none of my print statements execute :(

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  • Error in {% markdown %} filter in Django Nonrel

    - by Robert Smith
    I'm having trouble using Markdown in Django Nonrel. I followed this instructions (added 'django.contrib.markup' to INSTALLED_APPS, include {% load markup %} in the template and use |markdown filter after installing python-markdown) but I get the following error: Error in {% markdown %} filter: The Python markdown library isn't installed. In this line: /path/to/project/django/contrib/markup/templatetags/markup.py in markdown they will be silently ignored. """ try: import markdown except ImportError: if settings.DEBUG: raise template.TemplateSyntaxError("Error in {% markdown %} filter: The Python markdown library isn't installed.") ... return force_unicode(value) else: # markdown.version was first added in 1.6b. The only version of markdown # to fully support extensions before 1.6b was the shortlived 1.6a. if hasattr(markdown, 'version'): extensions = [e for e in arg.split(",") if e] It seems obvious that import markdown is causing the problem but when I run: $ python manage.py shell >>> import elementtree >>> import markdown everthing works alright. Running Markdown 2.0.3, Django 1.3.1, Python 2.7. UPDATE: I thought maybe this was an issue related to permissions, so I changed my project via chmod 777 -R, but it didn't work. Ideas? Thanks!

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  • Django-South introspection rule doesn't work.

    - by Ory Band
    I'm using Django 1.2.3 and South 0.7.3. I am trying to convert my app (named core) to use Django-South. I have a custom model/field that I'm using, named ImageWithThumbsField. It's basically just the ol' django.db.models.ImageField with some attributes such as height, weight, etc. While trying to ./manage.py convert_to_auth core I receieve South's freezing errors. I have no idea why, I'm Probably missing something... I am using a simple custom Model: from django.db.models import ImageField class ImageWithThumbsField(ImageField): def __init__(self, verbose_name=None, name=None, width_field=None, height_field=None, sizes=None, **kwargs): self.verbose_name=verbose_name self.name=name self.width_field=width_field self.height_field=height_field self.sizes = sizes super(ImageField, self).__init__(**kwargs) And this is my introspection rule, which I add to the top of my models.py: from south.modelsinspector import add_introspection_rules from lib.thumbs import ImageWithThumbsField add_introspection_rules( [ ( (ImageWithThumbsField, ), [], { "verbose_name": ["verbose_name", {"default": None}], "name": ["name", {"default": None}], "width_field": ["width_field", {"default": None}], "height_field": ["height_field", {"default": None}], "sizes": ["sizes", {"default": None}], }, ), ], ["^core/.fields/.ImageWithThumbsField",]) This is the errors I receieve: ! Cannot freeze field 'core.additionalmaterialphoto.photo' ! (this field has class lib.thumbs.ImageWithThumbsField) ! Cannot freeze field 'core.material.photo' ! (this field has class lib.thumbs.ImageWithThumbsField) ! Cannot freeze field 'core.material.formulaimage' ! (this field has class lib.thumbs.ImageWithThumbsField) ! South cannot introspect some fields; this is probably because they are custom ! fields. If they worked in 0.6 or below, this is because we have removed the ! models parser (it often broke things). ! To fix this, read http://south.aeracode.org/wiki/MyFieldsDontWork Does anybody know why? What am I doing wrong?

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  • Complex derived attributes in Django models

    - by rabidpebble
    What I want to do is implement submission scoring for a site with users voting on the content, much like in e.g. reddit (see the 'hot' function in http://code.reddit.com/browser/sql/functions.sql). My submission model currently keeps track of up and down vote totals. Currently, when a user votes I create and save a related Vote object and then use F() expressions to update the Submission object's voting totals. The problem is that I want to update the score for the submission at the same time, but F() expressions are limited to only simple operations (it's missing support for log(), date_part(), sign() etc.) From my limited experience with Django I can see 4 options here: extend F() somehow (haven't looked at the code yet) to support the missing SQL functions; this is my preferred option and seems to fit within the Django framework the best define a scoring function (much like reddit's 'hot' function) in my database, and have Django use the value of that function for the value of the score field; as far as I can tell, #2 is not possible wrap my two step voting process in a suitably isolated transaction so that I can calculate the voting totals in Python and then update the Submission's voting totals without fear that another vote against the submission could be added/changed in the meantime; I'm hesitant to take this route because it seems overly complex - what is a "suitably isolated transaction" in this case anyway? use raw SQL; I would prefer to avoid this entirely -- what's the point of an ORM if I have to revert to SQL for such a common use case as this! (Note that this coming from somebody who loves sprocs, but is using Django for ease of development.) Before I embark on this mission to extend F() (which I'm not sure is even possible), am I about to reinvent the wheel? Is there a more standard way to do this? It seems like such a common use case and yet in an hour of searching I have yet to find a common solution...

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  • Django throws 404 at generic views

    - by x0rg
    I'm trying to get the generic views for a date-based archive working in django. I defined the urls as described in a tutorial, but django returns a 404 error whenever I want to access an url with a variable (such as month or year) in it. It don't even produces a TemplateDoesNotExist-execption. Normal urls without variables work fine. Here's my urlconf: from django.conf.urls.defaults import * from zurichlive.zhl.models import Event info_dict = { 'queryset': Event.objects.all(), 'date_field': 'date', 'allow_future': 'True', } urlpatterns += patterns('django.views.generic.date_based', (r'events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='archive/detail.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/$','archive_day',dict(info_dict,template_name='archive/list.html')), (r'^events/(?P<year>d{4})/(?P<month>[a-z]{3})/$','archive_month', dict(info_dict, template_name='archive/list.html')), (r'^events/(?P<year>)/$','archive_year', dict(info_dict, template_name='archive/list.html')), (r'^events/$','archive_index', dict(info_dict, template_name='archive/list.html')), ) When I access /events/2010/may/12/this-is-a-slug I should get to the detail.html template, but instead I get a 404. What am I doing wrong?

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  • Does a lazy-programmer "document template" with tags exist for Windows?

    - by Anthony Forloney
    I was wondering (if possible) if there was a program/tool/utility that when I create a new file and provide it with an extension that it creates the tags automatically? For example, a new file I create called index.php would have the appropriate tags auto-generated inside: <?php ?> I hope you get the idea. Does one, or could one, exist, preferably Windows based? Any information regarding this would be helpful.

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  • List display names from django models

    - by Ed
    I have an object: POP_CULTURE_TYPES = ( ('SG','Song'), ('MV', 'Movie'), ('GM', 'Game'), ('TV', 'TV'), ) class Pop_Culture(models.Model): name = models.CharField(max_length=30, unique=True) type = models.CharField(max_length=2, choices = POP_CULTURE_TYPES, blank=True, null=True) Then I have a function: def choice_list(request, modelname, field_name): mdlnm = get.model('mdb', modelname.lower()) mdlnm = mdlnm.objects.values_list(field_name, flat=True).distinct().order_by(field_name) return render_to_response("choice_list.html", { 'model' : modelname, 'field' : field_name, 'field_list' : mdlnm }) This gives me a distinct list of all the "type" entries in the database in the "field_list" variable passed in render_to_response. But I don't want a list that shows: SG MV I want a list that shows: Song Movie I can do this on an individual object basis if I was in the template object.get_type_display But how do I get a list of all of the unique "type" entries in the database as their full names for output into a template? I hope this question was clearly described. . .

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  • Returning form errors for AJAX request in Django

    - by mridang
    Hi Guys, I've been finding my way around Django and jQuery. I've built a basic form in Django. On clicking submit, I'm using jQuey to make an AJAX request to the sever to post my data. This bit seems to work fine and I've managed to save the data. Django returns a ValidatioError when a form is invalid. Could anyone tell me how to return this set of error messages as a response to my AJAX request so i can easily iterate through it using JS and do whatever? I found this snippet. Looking at the JS bit (processJson) you'll see that he seems to get the error messages by extracting them from the response HTML. It seems kinda kludgy to me. Is this a best way to go about it? My apologies for any vagueness. Thanks in advance.

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  • django urlconf or .htaccess trouble

    - by Zayatzz
    Hello I am running my django project from subfolder of a website. Lets say the address where my project is meant to open from is. http://example.com/myproject/ the myproject folder is root folder for my user account. In that folder i have fcgi script that starts my project. The .htaccess file in the folder contains this: RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ mysite.fcgi/$1 [QSA,L] The trouble is, that at some cases, instead of redireting user to page like http://example.com/myproject/social/someurl/ it redirects to http://example.com/social/someurl/ which does not work. What i want to know is how to fix this problem. Is this django problem and i should change it with urconf and add myproject to all urls, or should i do this with .htaccess? I found similar question, which, sadly, remains unanswered: http://stackoverflow.com/questions/2321154/how-to-write-htaccess-if-django-project-is-in-subfolder-and-subdomain Alan.

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  • Django ORM and multiprocessing

    - by Ankur Gupta
    Hi, I am using Django ORM in my python script in a decoupled fashion i.e. it's not running in context of a normal Django Project. I am also using the multi processing module. And different process in turn are making queries. The process ran successfully for an hr and exited with this message "IOError: [Errno 32] Broken pipe" Upon futhur diagnosis and debugging this error pops up when I call save() on the model instance. I am wondering Is Django ORM Process save ? Why would this error arise else ? Cheers Ankur

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  • Django + Postgres: How to specify sequence for a field

    - by Giovanni Di Milia
    I have this model in django: class JournalsGeneral(models.Model): jid = models.AutoField(primary_key=True) code = models.CharField("Code", max_length=50) name = models.CharField("Name", max_length=2000) url = models.URLField("Journal Web Site", max_length=2000, blank=True) online = models.BooleanField("Online?") active = models.BooleanField("Active?") class Meta: db_table = u'journals_general' verbose_name = "Journal General" ordering = ['code'] def __unicode__(self): return self.name My problem is that in the DB (Postgres) the name of the sequence connected to jid is not journals_general_jid_seq as expected by Django but it has a different name. Is there a way to specify which sequence Django has to use for an AutoField? In the documentation I read I was not able to find an answer.

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  • Using Django Admin for a custom database solution

    - by Prashanth Ellina
    A client wants to have a simple intranet application to manage his process. He runs a Quarry and wishes to track number of loads delivered per day and associated activities. Since I knew about Django's excellent Admin interface, I figured I could define the "Schema" in models.py and have Django Admin generate the forms. I did exactly that and the result is not bad at all. I've been able to customize the look and feel to suit the client's taste. Some questions: Is Django Admin the right choice for such a use-case? Will I run to problems in the future due to flexibility of the framework? Is there a better framework out there specifically designed for this use-case (general Database management for small businesses)? I prefer ones written in Python since I can hack it up to customize. Thanks!

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  • Add a prefix do Django comment form

    - by Stefan Manastirliu
    I would like to add a prefix to each django comment form. I'm using multiply comment forms in the same page and depsite it's working well, i don't like having many input fields with the same id attribute like <input type="text" name="honeypot" id="id_honeypot" />. So, is there a way to tell django do add a prefix to each form instance? I know i can do it with other forms when i create a form instance in this waynewform = CustomForm(prefix="a") but using Django's comment system, this part is handled by a comment template tag {% get_comment_form for [object] as [varname] %}. Can I tell to the template tag to add a prefix?

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  • Can I suppress newlines with Django's template engine?

    - by ento
    In Rails ERB, you can suppress newlines by adding a trailing hyphen to tags: <ul> <% for @item in @items -%> <li><%= @item %></li> <% end -%> </ul> becomes: <ul> <li>apple</li> <li>banana</li> <li>cacao</li> </ul> Is there a way to do this in Django? (Disclosure: I'm generating a csv file with Django)

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  • Template error with django-photologue: 'Permission Denied'

    - by Ellie P.
    I'm in the process of re-setting up my Django development environment after reinstalling my OS. We use django-photologue with our project, which I installed using easy_install. However, I'm getting a template error on every template that has a photologue photo: TemplateSyntaxError at /newsroom/news/ Caught an exception while rendering: (13, 'Permission denied') One example of the line where the error is located: <img src="{{ photo.get_list_url }}"> I'm totally stumped--I've used photologue for this project on many different platforms and have never had this problem. Google yields nothing. I'm currently using Jolicloud (based on Ubuntu Jaunty). I'm working with a pre-existing database, so all of the photo sizes and everything have already been set up.

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  • Can I suppress newlines after each template tag with Django's template engine?

    - by ento
    In Rails ERB, you can suppress newlines by adding a trailing hyphen to tags: <ul> <% for @item in @items -%> <li><%= @item %></li> <% end -%> </ul> becomes: <ul> <li>apple</li> <li>banana</li> <li>cacao</li> </ul> Is there a way to do this in Django? (Disclosure: I'm generating a csv file with Django) Edit: Clarified that the newlines I'm hunting down are the ones left behind after the template tags.

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  • Prevent Django from redirecting to add trailing slash

    - by konrad
    UPDATED: Sorry, it looks like it's Apache that's rewriting it for some reason, not Django. I'll investigate further and post my findings. I need to add a /xmlrpc.php to my Byteflow installation to handle an application that is written for PHP blog engines and uses this hardcoded path. For some reason Byteflow appends a slash to this URL using a 301 Moved Permanently redirect, which breaks the application. It does not do so for the /robots.txt that is configured in a similar way. Relevant lines from the project urls.py: url(r'^xmlrpc.php$', 'django_xmlrpc.views.xmlrpc_handler'), url(r'^robots.txt$', include('robots.urls')), I read that the behavior was changed in the Django codebase in commit 6852 (in 2007) to prevent redirects being done for urls that have been explicitly configured not to contain any trailing slashes. I'm using Django 1.1. I assume that once I have fixed this problem, I should be able to use this application with Byteflow, because the application uses the MetaWeblog XML-RPC API. Any clue?

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  • Django: Geocoding an address on form submission?

    - by User
    Trying to wrap my head around django forms and the django way of doing things. I want to create a basic web form that allows a user to input an address and have that address geocoded and saved to a database. I created a Location model: class Location(models.Model): address = models.CharField(max_length=200) city = models.CharField(max_length=100) state = models.CharField(max_length=100, null=True) postal_code = models.CharField(max_length=100, null=True) country = models.CharField(max_length=100) latitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) longitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) And defined a form: class LocationForm(forms.ModelForm): class Meta: model = models.Location exclude = ('latitude','longitude') In my view I'm using form.save() to save the form. This works and saves an address to the database. I created a module to geocode an address. I'm not sure what the django way of doing things is, but I guess in my view, before I save the form, I need to geocode the address and set the lat and long. How do I set the latitude and longitude before saving?

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  • More than one profile in Django?

    - by JPC
    Is it possible to use Django's user authentication features with more than one profile? Currently I have a settings.py file that has this in it: AUTH_PROFILE_MODULE = 'auth.UserProfileA' and a models.py file that has this in it: from django.db import models from django.contrib.auth.models import User class UserProfileA(models.Model): company = models.CharField(max_length=30) user = models.ForeignKey(User, unique=True) that way, if a user logs in, I can easily get the profile because the User has a get_profile() method. However, I would like to add UserProfileB. From looking around a bit, it seems that the starting point is to create a superclass to use as the AUTH_PROFILE_MODULE and have both UserProfileA and UserProfileB inherit from that superclass. The problem is, I don't think the get_profile() method returns the correct profile. It would return an instance of the superclass. I come from a java background (polymorphism) so I'm not sure exactly what I should be doing. Thanks!

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  • Template does not exist: 500.html

    - by xRobot
    I have created a template for 500 http error. I have insert my template 500.html in: 1) /project/ 2) /project/templates/ 3) /python2.5/ 4) /python2.5/templates/ . but I always get this error: TemplateDoesNotExist: 500.html Same problem for Http 404 error. WHY ???

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  • Front-end structure of large scale Django project

    - by Saike
    Few days ago, I started to work in new company. Before me, all front-end and backend code was written by one man (oh my...). As you know, Django app contains two main directories for front-end: /static - for static(public) files and /templates - for django templates Now, we have large application with more than 10 different modules like: home, admin, spanel, mobile etc. This is current structure of files and directories: FIRST - /static directory. As u can see, it is mixed directories with some named like modules, some contains global libs. one more: SECOND - /templates directory. Some directories named like module with mixed templates, some depends on new version =), some used only in module, but placed globally. and more: I think, that this is ugly, non-maintable, put-in-stress structure! After some time spend, i suggest to use this scheme, that based on module-structure. At first, we have version directories, used for save full project backup, includes: /DEPRECATED directory - for old, unused files and /CURRENT (Active) directory, that contains production version of project. I think it's right, because we can access to older or newer version files fast and easy. Also, we are saved from broken or wrong dependencies between different versions. Second, in every version we have standalone modules and global module. Every module contains own /static and /templates directories. This structure used to avoid broken or wrong dependencies between different modules, because every module has own js app, css tables and local images. Global module contains all libraries, main stylesheets and images like logos or favicon. I think, this structure is much better to maintain, update, refactoring etc. My question is: How do you think, is this scheme better than current? Can this scheme live, or it is not possible to implement this in Django app?

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  • Django + gunicorn + virtualenv + Supervisord issue

    - by Florian Le Goff
    Dear all, I have a strange issue with my virtualenv + gunicorn setup, only when gunicorn is launched via supervisord. I do realize that it may very well be an issue with my supervisord and I would appreciate any feedback on a better place to ask for help... In a nutshell : when I run gunicorn from my user shell, inside my virtualenv, everything is working flawlessly. I'm able to access all the views of my Django project. When gunicorn is launched by supervisord at the system startup, everything is OK. But, if I have to kill the gunicorn_django processes, or if I perform a supervisord restart, once that gunicorn_django has relaunched, every request is answered with a weird Traceback : (...) File "/home/hc/prod/venv/lib/python2.6/site-packages/Django-1.2.5-py2.6.egg/django/db/__init__.py", line 77, in connection = connections[DEFAULT_DB_ALIAS] File "/home/hc/prod/venv/lib/python2.6/site-packages/Django-1.2.5-py2.6.egg/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/home/hc/prod/venv/lib/python2.6/site-packages/Django-1.2.5-py2.6.egg/django/db/utils.py", line 50, in load_backend raise ImproperlyConfigured(error_msg) TemplateSyntaxError: Caught ImproperlyConfigured while rendering: 'django.db.backends.postgresql_psycopg2' isn't an available database backend. Try using django.db.backends.XXX, where XXX is one of: 'dummy', 'mysql', 'oracle', 'postgresql', 'postgresql_psycopg2', 'sqlite3' Error was: cannot import name utils Full stack available here : http://pastebin.com/BJ5tNQ2N I'm running... Ubuntu/maverick (up-to-date) Python = 2.6.6 virtualenv = 1.5.1 gunicorn = 0.12.0 Django = 1.2.5 psycopg2 = '2.4-beta2 (dt dec pq3 ext)' gunicorn configuration : backlog = 2048 bind = "127.0.0.1:8000" pidfile = "/tmp/gunicorn-hc.pid" daemon = True debug = True workers = 3 logfile = "/home/hc/prod/log/gunicorn.log" loglevel = "info" supervisord configuration : [program:gunicorn] directory=/home/hc/prod/hc command=/home/hc/prod/venv/bin/gunicorn_django -c /home/hc/prod/hc/gunicorn.conf.py user=hc umask=022 autostart=True autorestart=True redirect_stderr=True Any advice ? I've been stuck on this one for quite a while. It seems like some weird memory limit, as I'm not enforcing anything special : $ ulimit -a core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 20 file size (blocks, -f) unlimited pending signals (-i) 16382 max locked memory (kbytes, -l) 64 max memory size (kbytes, -m) unlimited open files (-n) 1024 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 8192 cpu time (seconds, -t) unlimited max user processes (-u) unlimited virtual memory (kbytes, -v) unlimited file locks (-x) unlimited Thank you.

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