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  • How can I validate XML against an XSD with distinct imports and namespaces?

    - by Pedrolopes
    Hi there!! I am trying to validate a few XML files and I'm failing due to various issues with the XSD definition and the namespaces... This is public info, so no problem sharing data: the main XSD is at http://bioinformatics.ua.pt/euadr/euadr_types.xsd and it imports another XSD at the same location name common_types.xsd, I've validated them in W3C validator, and they passed. The XML <?xml version="1.0"?> <relationship xmlns="http://euadr.biosemantic.erasmusmc.org/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://euadr.biosemantic.erasmusmc.org/ http://bioinformatics.ua.pt/euadr/euadr_types.xsd"> <sourceId> <source>SMILE</source> <code>[S]1(=O)(=O)N(C(</code> </sourceId> <targetId> <source>UP</source> <code>P35354</code> </targetId> <creator>http://cgl.imim.es</creator> <observationDateTime>2010-05-12T19:03:40.097+02:00</observationDateTime> <informationSources> <informationSource> <relationshipType>BINDS</relationshipType> <interaction> <type>pIC50</type> <value>6.55</value> </interaction> <evidence> <type>OBSERVATIONAL</type> <value>1.0</value> </evidence> <databaseIds> <databaseId> <source>PDSP</source> <code> P35354</code> </databaseId> </databaseIds> </informationSource> </informationSources> </relationship> is straightforward and well-formed! I've tested a few online validators, and I'm getting the following error cvc-elt.1: Cannot find the declaration of element 'relationship'. Does anyone has any idea of what the problem is? Is it in the declaration of the namespaces? Of the XSD? Thanks in advance for your help! Cheers!

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  • What is your favorite way to read XML files?

    - by stacker
    Let's take this xml structure as example: <?xml version="1.0" encoding="utf-8"?> <Configuration-content> <XFile Name="file name 1" /> <XFile Name="name2" /> <XFile Name="name3" /> <XFile Name="name4" /> </Configuration-content> C# interface to implement: public class Configuration { public XFile[] Files { get; set; } } public interface IConfigurationRipository { Configuration Get(); void Save(Configuration entity); } I wonder what's the best way to do that. The task is to implement IConfigurationRipository using your favorite approach.

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  • What is the correct method to load an XML file and re-write it as a CVS? (C# Only)

    - by codesmack
    Hello, I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named and within the car element I need to process the element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C# Thank you, CodeSmack

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  • What is the correct method to load an XML file and re-write it as a CSV?

    - by codesmack
    I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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  • Do I have to worry about escaping XML reserved characters before I return a DataContract object from

    - by Brett Widmeier
    Hi, I am pretty inexperienced with WCF. I have a DataContract that implements the IExtensibleDataObject interface. Some of the members of this object are populated from freetext input and could contain XML reserved characters ('', for example). I imagine that I get escaping of these characters for free with WCF, but I have been looking around and could not find anything commenting on this one way or another. Is this the case? I have set my service to log the messages that it sends and receives for viewing in the Trace Viewer. Part of a message that my service returns looks like this: <sInstructions>"></sInstructions> Now, I have a couple questions about this. 1) Is it actually transmitting "&gt; and just showing it in a more readable form in the trace viewer? 2) If it is actually is transmitting ">, is this legal XML?

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  • Using variable for tag in getElementsByTagName() for PHP and XML?

    - by Jared
    See my PHP: $file = "routingConfig.xml"; global $doc; $doc = new DOMDocument(); $doc->load( $file ); $ElTag = "Route"; $tag = $doc->getElementsByTagName($ElTag); XML is: <Routes> <Route></Route> <Route></Route> <Routes> Error returned is: Fatal error: Call to a member function getElementsByTagName() on a non-object I'm not sure how to do this?

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  • What is the correct method to load an XML file and re-write it as a CSV? (C# Only)

    - by codesmack
    I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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  • Is it possible to define XML schemata with node names specified via regular expressions?

    - by MartyIX
    Hello, I know it is probably a question against XML philosophy but still is it possible to define schemata for XML like this: <Root> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> </Root> where arbitrary-name-of-node matches regular expression [a-zA-Z0-9]? Thanks for an answer!

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  • SQL SERVER – Understanding XML – Contest Win Joes 2 Pros Combo (USD 198) – Day 5 of 5

    - by pinaldave
    August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Is following XML a well formed XML Document? <?xml version=”1.0″?> <address> <firstname>Pinal</firstname> <lastname>Dave</lastname> <title>Founder</title> <company>SQLAuthority.com</company> </address> a) Yes b) No c) I do not know Query Hints: BIG HINT POST A common observation by people seeing an XML file for the first time is that it looks like just a bunch of data inside a text file. XML files are text-based documents, which makes them easy to read.  All of the data is literally spelled out in the document and relies on a just a few characters (<, >, =) to convey relationships and structure of the data.  XML files can be used by any commonly available text editor, like Notepad. Much like a book’s Table of Contents, your first glance at well-formed XML will tell you the subject matter of the data and its general structure. Hints appearing within the data help you to quickly identify the main theme (similar to book’s subject), its headers (similar to chapter titles or sections of a book), data elements (similar to a book’s characters or chief topics), and so forth. We’ll learn to recognize and use the structural “hints,” which are XML’s markup components (e.g., XML tags, root elements). The XML Raw and Auto modes are great for displaying data as all attributes or all elements – but not both at once. If you want your XML stream to have some of its data shown in attributes and some shown as elements, then you can use the XML Path mode. If you are using an XML Path stream, then by default all values will be shown as elements. However, it is possible to pick one or more elements to be shown with an attribute(s) as well. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 5. SQL Joes 2 Pros Development Series – OpenXML Options SQL Joes 2 Pros Development Series – Preparing XML in Memory SQL Joes 2 Pros Development Series – Shredding XML SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – What is XML? SQL Joes 2 Pros Development Series – What is XML? – 2 Next Step: Answer the Quiz in Contact Form in following format Question - Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • How to convert objects in reflection (Linq to XML)

    - by user829174
    I have the following code which is working fine, the code creates plugins in reflection via run time: using System; using System.Collections.Generic; using System.Linq; using System.IO; using System.Xml.Linq; using System.Reflection; using System.Text; namespace WindowsFormsApplication1 { public abstract class Plugin { public string Type { get; set; } public string Message { get; set; } } public class FilePlugin : Plugin { public string Path { get; set; } } public class RegsitryPlugin : Plugin { public string Key { get; set; } public string Name { get; set; } public string Value { get; set; } } static class MyProgram { [STAThread] static void Main(string[] args) { string xmlstr =@" <Client> <Plugin Type=""FilePlugin""> <Message>i am a file plugin</Message> <Path>c:\</Path> </Plugin> <Plugin Type=""RegsitryPlugin""> <Message>i am a registry plugin</Message> <Key>HKLM\Software\Microsoft</Key> <Name>Version</Name> <Value>3.5</Value> </Plugin> </Client> "; Assembly asm = Assembly.GetExecutingAssembly(); XDocument xDoc = XDocument.Load(new StringReader(xmlstr)); Plugin[] plugins = xDoc.Descendants("Plugin") .Select(plugin => { string typeName = plugin.Attribute("Type").Value; var type = asm.GetTypes().Where(t => t.Name == typeName).First(); Plugin p = Activator.CreateInstance(type) as Plugin; p.Type = typeName; foreach (var prop in plugin.Descendants()) { var pi = type.GetProperty(prop.Name.LocalName); object newVal = Convert.ChangeType(prop.Value, pi.PropertyType); pi.SetValue(p, newVal, null); } return p; }).ToArray(); // //"plugins" ready to use // } } } I am trying to modify the code and adding new class named DetailedPlugin so it will be able to read the following xml: string newXml = @" <Client> <Plugin Type=""FilePlugin""> <Message>i am a file plugin</Message> <Path>c:\</Path> <DetailedPlugin Type=""DetailedFilePlugin""> <Message>I am a detailed file plugin</Message> </DetailedPlugin> </Plugin> <Plugin Type=""RegsitryPlugin""> <Message>i am a registry plugin</Message> <Key>HKLM\Software\Microsoft</Key> <Name>Version</Name> <Value>3.5</Value> <DetailedPlugin Type=""DetailedRegsitryPlugin""> <Message>I am a detailed registry plugin</Message> </DetailedPlugin> </Plugin> </Client> "; for this i modified my classes to the following: public abstract class Plugin { public string Type { get; set; } public string Message { get; set; } public DetailedPlugin DetailedPlugin { get; set; } // new } public class FilePlugin : Plugin { public string Path { get; set; } } public class RegsitryPlugin : Plugin { public string Key { get; set; } public string Name { get; set; } public string Value { get; set; } } // new classes: public abstract class DetailedPlugin { public string Type { get; set; } public string Message { get; set; } } public class DetailedFilePlugin : Plugin { public string ExtraField1 { get; set; } } public class DetailedRegsitryPlugin : Plugin { public string ExtraField2{ get; set; } } from here i need some help to accomplish reading the xml and create the plugins with the nested DetailedPlugin

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  • Java Plugin a huge security risk? How to preseve Java plugin from privilege escalation?

    - by Johannes Weiß
    Installing a regular Java plugin is IMHO a real security risk for non-IT people. Normally Java applets run in a sandbox and the applet cannot do anything harmful to your computer. If an applet, however, needs to do something like read-only accessing your filesystem e.g. uploading an image, you have to give it more privileges. Usually that's ok but I think not everyone knows that you give the applet the same privileges to your computer as your user has! And that's everything Java asks you: That looks as 'harmful' as a self-signed SSL certificate on a random page where no sensitive data is exchanged. The user will click on Run! You can try that at home using JyConsole, that's Jython (Python on Java)! Simply type in python code, e.g. import os os.system('cat /etc/passwd') or worse DON'T TYPE IN THAT CODE ON YOUR COMPUTER!!! import os os.system('rm -rf ~') ... Does anyone know how you can disable the possibily of privilege escalation? And by the way, does anyone know why SUN displays only a dialog as harmless as the one shown above (the self-signed-SSL-certificate-dialog from Firefox 3 and above is much clearer here!)? Live sample from my computer:

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  • activemq-maven-plugin ignore files in classpath?

    - by Oscar Chan
    I have been trying to get activemq-maven-plugin to run activemq with configuration in classpath of the bundle. However, I don't have much luck. It seems that the activemq-maven-plugin just ignore resources (resources/main/conf/activemq.properties) the local bundle. I checked the jar and target/classes and they are built into the right local. I am able to get plugin to run (mvn activemq:run) if I take out the PropertyPlaceholderConfigurer bean in the activemq.xml Did I do anything wrong? Here is the output [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR [INFO] ------------------------------------------------------------------------ [INFO] Failed to start ActiveMQ Broker Embedded error: Could not load properties; nested exception is java.io.FileNotFoundException: class path resource [conf/activemq.properties] cannot be opened because it does not exist [INFO] ------------------------------------------------------------------------ [INFO] For more information, run Maven with the -e switch [INFO] ------------------------------------------------------------------------ [INFO] Total time: 2 seconds [INFO] Finished at: Mon May 03 15:56:05 PDT 2010 [INFO] Final Memory: 11M/79M [INFO] ------------------------------------------------------------------------ Here is the pom.xml, which I specific the plugin to look up activemq.xml via file, that works. However, in the activemq.xml <?xml version="1.0"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>oc.test</groupId> <artifactId>mq</artifactId> <version>0.1</version> <name>mq</name> <url>http://maven.apache.org</url> <dependencies> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> </dependencies> <build> <plugins> <plugin> <groupId>org.apache.activemq.tooling</groupId> <artifactId>maven-activemq-plugin</artifactId> <version>5.3.1</version> <configuration> <configUri>xbean:file:src/main/resources/conf/activemq.xml</configUri> <fork>false</fork> <systemProperties> <property> <name>javax.net.ssl.keyStorePassword</name> <value>password</value> </property> <property> <name>org.apache.activemq.default.directory.prefix</name> <value>./target/</value> </property> </systemProperties> </configuration> <dependencies> <dependency> <groupId>org.springframework</groupId> <artifactId>spring</artifactId> <version>2.5.5</version> </dependency> </dependencies> </plugin> </plugins> </build> </project> Here is the src/main/resources/conf/activemq.xml <?xml version="1.0"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:amq="http://activemq.apache.org/schema/core" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://activemq.apache.org/schema/core http://activemq.apache.org/schema/core/activemq-core.xsd "> <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="locations"> <value>classpath:conf/activemq.properties</value> </property> <property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE"/> </bean> <broker xmlns="http://activemq.apache.org/schema/core" brokerName="localhost" dataDirectory="./data"> <!-- The transport connectors ActiveMQ will listen to --> <transportConnectors> <transportConnector name="openwire" uri="tcp://localhost:61616"/> </transportConnectors> </broker> </beans> Here is the src/main/resources/conf/activemq.properties activemq.port=61616

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  • WordPress plugin for handling User Submitted Posts

    - by Ravish
    User Submitted Posts plugin is a highly useful form, which can be embedded on the desired areas of your WordPress site using a shortcode. User Submitted Posts plugin will allow you to customize the fields in the form like title, or tags. It provides you with useful tools to control uploads. Why you need this? [...] Related posts:Insights WordPress Plugin For Efficient Blogging WordPress User related Plug-ins AddInto Social Bookmarking plugin for WordPress & Blogger

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  • Correct XML serialization and deserialization of "mixed" types in .NET

    - by Stefan
    My current task involves writing a class library for processing HL7 CDA files. These HL7 CDA files are XML files with a defined XML schema, so I used xsd.exe to generate .NET classes for XML serialization and deserialization. The XML Schema contains various types which contain the mixed="true" attribute, specifying that an XML node of this type may contain normal text mixed with other XML nodes. The relevant part of the XML schema for one of these types looks like this: <xs:complexType name="StrucDoc.Paragraph" mixed="true"> <xs:sequence> <xs:element name="caption" type="StrucDoc.Caption" minOccurs="0"/> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="br" type="StrucDoc.Br"/> <xs:element name="sub" type="StrucDoc.Sub"/> <xs:element name="sup" type="StrucDoc.Sup"/> <!-- ...other possible nodes... --> </xs:choice> </xs:sequence> <xs:attribute name="ID" type="xs:ID"/> <!-- ...other attributes... --> </xs:complexType> The generated code for this type looks like this: /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(TypeName="StrucDoc.Paragraph", Namespace="urn:hl7-org:v3")] public partial class StrucDocParagraph { private StrucDocCaption captionField; private object[] itemsField; private string[] textField; private string idField; // ...fields for other attributes... /// <remarks/> public StrucDocCaption caption { get { return this.captionField; } set { this.captionField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("br", typeof(StrucDocBr))] [System.Xml.Serialization.XmlElementAttribute("sub", typeof(StrucDocSub))] [System.Xml.Serialization.XmlElementAttribute("sup", typeof(StrucDocSup))] // ...other possible nodes... public object[] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlTextAttribute()] public string[] Text { get { return this.textField; } set { this.textField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute(DataType="ID")] public string ID { get { return this.idField; } set { this.idField = value; } } // ...properties for other attributes... } If I deserialize an XML element where the paragraph node looks like this: <paragraph>first line<br /><br />third line</paragraph> The result is that the item and text arrays are read like this: itemsField = new object[] { new StrucDocBr(), new StrucDocBr(), }; textField = new string[] { "first line", "third line", }; From this there is no possible way to determine the exact order of the text and the other nodes. If I serialize this again, the result looks exactly like this: <paragraph> <br /> <br />first linethird line </paragraph> The default serializer just serializes the items first and then the text. I tried implementing IXmlSerializable on the StrucDocParagraph class so that I could control the deserialization and serialization of the content, but it's rather complex since there are so many classes involved and I didn't come to a solution yet because I don't know if the effort pays off. Is there some kind of easy workaround to this problem, or is it even possible by doing custom serialization via IXmlSerializable? Or should I just use XmlDocument or XmlReader/XmlWriter to process these documents?

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  • PHP parsing XML file with and without namespaces

    - by Mike
    I need to get a XML File into a Database. Thats not the problem. Cant read it, parse it and create some Objects to map to the DB. Problem is, that sometimes the XML File can contain namespaces and sometimes not. Furtermore sometimes there is no namespace defined at all. So what i first got was something like this: <?xml version="1.0" encoding="UTF-8"?> <struct xmlns:b="http://www.w3schools.com/test/"> <objects> <object> <node_1>value1</node_1> <node_2>value2</node_2> <node_3 iso_land="AFG"/> <coords lat="12.00" long="13.00"/> </object> </objects> </struct> And the parsing: $t = $xml->xpath('/objects/object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } Thats fine as long as there are no namespaces. Here comes the XML File with namespaces: <?xml version="1.0" encoding="UTF-8"?> <b:struct xmlns:b="http://www.w3schools.com/test/"> <b:objects> <b:object> <b:node_1>value1</b:node_1> <b:node_2>value2</b:node_2> <b:node_3 iso_land="AFG"/> <b:coords lat="12.00" long="13.00"/> </b:object> </b:objects> </b:struct> I now came up with something like this: $xml = simplexml_load_file("test.xml"); $namespaces = $xml->getNamespaces(TRUE); $ns = count($namespaces) ? 'a:' : ''; $xml->registerXPathNamespace("a", "http://www.w3schools.com/test/"); $nodes = array('node_1', 'node_2'); $obj = new stdClass(); foreach($nodes AS $node) { $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.$node); if($t[0]) { $obj->$node = (string) $t[0]; } } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'node_3'); if($t[0]) { $obj->iso_land = (string) $t[0]->attributes()->iso_land; } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'coords'); if($t[0]) { $obj->lat = (string) $t[0]->attributes()->lat; $obj->long = (string) $t[0]->attributes()->long; } That works with namespaces and without. But i feel that there must be a better way. Before that i could do something like this: $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } But that just wont work with namespaces.

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  • How to deserialize an element as an XmlNode?

    - by mackenir
    When using Xml serialization in C#, I want to deserialize a part of my input XML to an XmlNode. So, given this XML: <Thing Name="George"> <Document> <subnode1/> <subnode2/> </Document> </Thing> I want to deserialize the Document element to an XmlNode. Below is my attempt which given the XML above, sets Document to the 'subnode1' element rather than the 'Document' element. How would I get the code to set the Document property to the Document element? using System; using System.IO; using System.Xml; using System.Xml.Serialization; [Serializable] public class Thing { [XmlAttribute] public string Name {get;set;} public XmlNode Document { get; set; } } class Program { static void Main() { const string xml = @" <Thing Name=""George""> <Document> <subnode1/> <subnode2/> </Document> </Thing>"; var s = new XmlSerializer(typeof(Thing)); var thing = s.Deserialize(new StringReader(xml)) as Thing; } } However, when I use an XmlSerializer to deserialize the XML above to an instance of Thing, the Document property contains the child element 'subnode1', rather than the 'doc' element. How can I get the XmlSerializer to set Document to an XmlNode containing the 'doc' element.

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  • Cinema4D XML scene not rendering texture

    - by George Profenza
    I was playing with the Cinema 4D command line options and ran into a problem that might not be specific to the command line options. I saved a basic scene(a textured cube) in two formats: the original .c4d(binary) format and .xml(Cinema 4D XML via File Export). the .c4d file renders with the texture applied, while the .xml file renders without the texture applied. I had a look at the xml file, and there is a node that holds a reference to the image used as texture, and there is another node which seems to store the pixels in xml. When I opened the .xml document in Cinema 4D, the document did store the material with the texture, but it was not applied to the object. Am I missing something when I export to XML ? How can I export a Cinema 4D XML that can render with the texture applied ?

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  • How to use the same element name in different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • XML Catalog in Eclipse is not working

    - by svaret
    Where I work we do not have any internet connection. We still want to have validation and code completion when editing xml files. I have tried the instructions here http://www.helmers.nu/?p=276 However, I try the instructions, restarts eclipse, do reload dependencies. I still cannot get any code completion nor validation. Can anyone point me in the right direction? I have tried both with Eclipse Galileo and Helios. My catalog.xml <?xml version="1.0" encoding="UTF-8" standalone="no"?> <catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog"> <uri name="http://www.liquibase.org/xml/ns/dbchangelog/1.9" uri="file:///C:/dev/XMLSchemaDefinition/dbchangelog-1.9.xsd"/> </catalog> My xml-file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <databaseChangeLog xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9 http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd"> </databaseChangeLog>

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  • how can a Win32 App plugin load its DLL in its own directory

    - by Jean-Denis Muys
    My code is a plugin for a specific Application, written in C++ using Visual Studio 8. It uses two DLL from an external provider. Unfortunately, my plugin fails to start because the DLLs are not found (I put them in the same directory as the plugin itself). When I manually move or copy the DLLs to the host application directory, then the plugin loads fine. This moving was deemed unacceptably cumbersome for the end user, and I am looking for a way for my plugin to load its DLLs transparently. What can I do? Relevant details: the host Application plugins are located in a directory mandated by the host application. That directory is not in the DLL search path and I don't control it. The plugin is itself packaged as a subdirectory of the plugin directory, holding the plugin code itself, but also any resource associated with the plugin (eg images, configuration files…). I control what's inside that subdirectory, called a "bundle", but not where it's located. the common plugin installation idiom for that App is for the end user to copy the plugin bundle to the plugin directory. This plugin is a port from the Macintosh version of the plugin. On the Mac there is no issue because each binary contains its own dynamic library search path, which I set as I needed to for my plugin binary. To set that on the Mac simply involves a project setting in the Xcode IDE. This is why I would hope for something similar in Visual Studio, but I could not find anything relevant. Moreover, Visual Studio's help was anything but, and neither was Google. A possible workaround would be for my code to explicitly tell Windows where to find the DLL, but I don't know how, and in any case, since my code is not even started, it hasn't got the opportunity to do so. As a Mac developer, I realize that I may be asking for something very elementary. If such is the case, I apologize, but I have run out of hair to pull out.

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  • How to use the same element name for different purposes ( in XML and DTD ) ?

    - by BugKiller
    Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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  • use multiple xsl files with one xml document

    - by paracaudex
    I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

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  • XML Schema: Can I make some of an attribute's values be required but still allow other values?

    - by scrotty
    (Note: I cannot change structure of the XML I receive, I am only able to change how I validate it.) Let's say I can get XML like this: <Address Field="Street" Value="123 Main"/> <Address Field="StreetPartTwo" Value="Unit B"/> <Address Field="State" Value="CO"/> <Address Field="Zip" Value="80020"/> <Address Field="SomeOtherCrazyValue" Value="Foo"/> I need to create an XSD schema that validates that "Street", "State" and "Zip" must be present. But I don't care if "StreetPartTwo" or "SomeOTherCrazyValue" is present. If I knew that only the three I care about could be included, I could do this: <xs:element name="Address" type="addressType" maxOccurs="unbounded" minOccurs="3"/> <xs:complexType name="addressType"> <xs:attribute name="Field" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="Street"/> <xs:enumeration value="State"/> <xs:enumeration value="Zip"/> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> But this won't work with my case because I may also receive those other Address elements (that also have "Field" attributes) that I don't care about. Any ideas how I can ensure the stuff I care about is present but let the other stuff in too? TIA! Sean

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  • Advance: Parsing XML into another XML page using only javascript or jquery; Can't use PhP, Java or MySQL

    - by UrBestFriend
    Current site: http://cardwall.tk/ Example of intended outcome: http://www.shockwave.com/downloadWall.jsp I have an embeded flash object that uses XML/RSS (Picasa) to feed itself pictures. Now I created my own XML/RSS feed so that I can add additional XML tags and values. Now here's my big problem: enabling search. Since I'm not relying on Picasa's API anymore to return custom RSS/XML for the user's search, how can I create xml from another xml based on the user's search queries using only JavaScript and Jquery? Here is the current code: <script type="text/javascript"> var flashvars = { feed : "http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml", backgroundColor : "#FFFFFF", metadataFont : "Arial", wmode : "opaque", iFrameScrolling: "no", numRows : "3", }; var params = { allowFullScreen: "true", allowscriptaccess : "always", wmode: "opaque" }; swfobject.embedSWF("http://apps.cooliris.com/embed/cooliris.swf", "gamewall", "810", "410", "9.0.0", "", flashvars, params); $(document).ready(function() { $("#cooliris input").keydown(function(e) { if(e.keyCode == 13) { $("#cooliris a#searchCooliris").click(); return false; } }); doCoolIrisSearch = function() { cooliris.embed.setFeedContents( '** JAVA STRING OF PARSED RSS/XML based on http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml and USER'S SEARCH INPUT** ' ) }); <form id="searchForm" name="searchForm" class="shockwave"> <input type="text" name="coolIrisSearch" id="coolIrisSearch" value="Search..." class="field text short" onfocus="this.value='';" /> <a id="searchCooliris" href="#" onclick="doCoolIrisSearch();return false;" class="clearLink">Search Cooliris</a> </form> <div id="gamewall"></div> So basically, I want to replace cooliris.embed.setFeedContents's value with a Javastring based on the parsed RSS/XML and user search input. Any code or ideas would be greatly appreciated.

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  • I have problem loading all items from XML with for each

    - by vaha
    Hi all, I'm low level as3 programmer and I need help whit this code: I have gallery XML file: 1 0 Lokacije 1 1.jpg 2 2 Coaching 1 2.jpg 3 0 0 3.jpg And: var loader: URLLoader = new URLLoader(); loader.load(new URLRequest("gallery.xml"); var xml = new XML(evt.target.data); for each(var item in xml..item) { centralniText.htmlText = item.slika; } only shows last item from XML file: 3.jpg I want all. Please help.

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