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  • One table for uploads for multiple resources in CakePHP

    - by Mef
    Hi, I have CakePHP app in which I'd like to attach gallery to multiple resources. Let's say I've got artists, each one has own gallery. I've got articles, every article has some images attached to it and so on. Now I set up tables like this: Artists hasMany Artistimages, fields in artistimages table are: id, artist_id, filename, filetype, filesize etc. Articles hasMany Articleimages, fields in articleimages table are: id, article_id, filename, filetype, filesize etc. ...but this is not how it should be, I think. Is there possibility to have one table called for example uploads which will contain all images with foreign key pointing to resource its reffering to? How to tell CakePHP which image is coming from which resource?

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  • Drupal: How to render a form and table on same page

    - by Aaron
    Can someone help me render a form and table on the same page? I'm sure it's easy, but can't think of how to do it. Here's hook_menu: function ncbi_subsites_menu() { $items = array(); $items['admin/content/ncbi_subsites'] = array( 'title' => 'NCBI Subsites Module', 'description' => 'Informs Drupal about NCBI subsites as defined by the Content Inventory database', 'page callback' => 'ncbi_subsites_show_main_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_NORMAL_ITEM, ); return $items; } Here's the callback: function ncbi_subsites_show_main_page() { $subsites = ncbi_subsites_get_subsites_from_inventory(); // fnc returns associative array from inventory, defined in include return ncbi_subsites_make_table( $subsites ); } In the callback I call some helper functions that return a themed, paged table. What I want is a small form above the table. How would I that?

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  • Find mininum unused value in mysql table

    - by splattru
    I have a MySQL table like this: +--------+-------+ + Server + Port + +--------+-------+ + 1 + 27001 + +--------+-------+ + 2 + 27002 + +--------+-------+ + 4 + 27004 + +--------+-------+ How you can see - here was 27003 port - but it was deleted some time ago (just for example). Is there some way to know the minimum value that is not used (higher than 27000 for example) in mysql table? Or there is no way and I need to make an separate table with all ports and column with "used" or "not used" ? Situation explanation: I am creating game hosting website, and I can use auto-increment for ports, but I will have a lot of deleted/unused ports after some time, and I want to use all of them before increasing port range. Thanks for your answers!

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  • how to sort an existing table in greasemonkey ?

    - by user570512
    i'm writing a greasemonkey user.js for a page with a table in it. (table is 100 rows by 18 columns.) now what i want to do is to make it sortable on column. and also have it run in both chrome and firefox. all searches for answers sofar resulted in suggestions to use jquery/dojo or something alike. can i be done without any external code? after all it's just a matter of replacing the row's in a different order, right? or is that a silly thing to say? the thing is that i'm already using dojo for some query needs but since i want it to run in both firefox and chrome, i just copy paste the whole dojo thing in my script.. also, most of the solutions i found sofar seem to be more for use when building a table. not for altering an existing one. any help is appreciated.

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  • Operations in table data with javascript

    - by Zangrandi
    I'm working with rails and I don't know javascript. I have a table with a select_tag field and I want to have another field that capture the option selected, multiply for the price captured in another field and display the total. Like this <table> <tr> <td>(select_tag)</td> <td>price</td> <td>total</td> </tr> </table

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  • SQL Server dynamic pivot table

    - by user972255
    In SQL Server, I have two tables TableA and TableB, based on these I need to generate a report which is kind of very complex and after doing some research I come to a conclusion that I have to go with SQL Pivot table but I dont have any idea about the SQL Pivot feature so, can anyone please help me on this. Please see the details below: Create table TableA ( ProjectID INT NOT NULL, ControlID INT NOT NULL, ControlCode Varchar(2) NOT NULL, ControlPoint Decimal NULL, ControlScore Decimal NULL, ControlValue Varchar(50) ) Sample Data ------------- ProjectID | ControlID | ControlCode | ControlPoint | ControlScore | ControlValue P001 1 A 30.44 65 Invalid P001 2 C 45.30 85 Valid Create table TableB ( ControlID INT NOT NULL, ControlChildID INT NOT NULL, ControlChildValue Varchar(200) NULL ) Sample Data ------------ ControlID | ControlChildID | ControlChildValue 1 100 Yes 1 101 No 1 102 NA 1 103 Others 2 104 Yes 2 105 SomeValue Output should be in a single row for a given ProjectID with all its Control values first & followed by child control values (based on the ControlCode (i.e.) ControlCode_Child (1, 2, 3...) and it should look like this

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  • Tool to automatically combine many large pivot table in many large Excel sheet ?

    - by Sim
    Hi all, We have several Excel files that contains large pivot data table with the same structure For example File A Pivot table (Field A, B, C) File B Pivot table (Field A, B, C) We want to combine them into 1 pivot table (A, B, C). Just want to know which ways we can do it ? Manual way : open a new empty sheet, copy and paste the pivot there and create the pivot again Automatic way : is there some tool that did this ? Thanks

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  • SQL SERVER – Finding Different ColumnName From Almost Identitical Tables

    - by pinaldave
    I have mentioned earlier on this blog that I love social media – Facebook and Twitter. I receive so many interesting questions that sometimes I wonder how come I never faced them in my real life scenario. Well, let us see one of the similar situation. Here is one of the questions which I received on my social media handle. “Pinal, I have a large database. I did not develop this database but I have inherited this database. In our database we have many tables but all the tables are in pairs. We have one archive table and one current table. Now here is interesting situation. For a while due to some reason our organization has stopped paying attention to archive data. We did not archive anything for a while. If this was not enough we  even changed the schema of current table but did not change the corresponding archive table. This is now becoming a huge huge problem. We know for sure that in current table we have added few column but we do not know which ones. Is there any way we can figure out what are the new column added in the current table and does not exist in the archive tables? We cannot use any third party tool. Would you please guide us?” Well here is the interesting example of how we can use sys.column catalogue views and get the details of the newly added column. I have previously written about EXCEPT over here which is very similar to MINUS of Oracle. In following example we are going to create two tables. One of the tables has extra column. In our resultset we will get the name of the extra column as we are comparing the catalogue view of the column name. USE AdventureWorks2012 GO CREATE TABLE ArchiveTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100)); CREATE TABLE CurrentTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100), ExtraCol INT); GO -- Columns in ArchiveTable but not in CurrentTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' GO -- Columns in CurrentTable but not in ArchiveTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' GO DROP TABLE ArchiveTable; DROP TABLE CurrentTable; GO The above query will return us following result. I hope this solves the problems. It is not the most elegant solution ever possible but it works. Here is the puzzle back to you – what native T-SQL solution would you have provided in this situation? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology

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  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

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  • CSS: Labels in table columns

    - by hello
    Hello. BACKGROUND: I would like to have small labels in columns of a table. I'm using some implemented parts of HTML5/CSS3 in my project, and this section specifically is for mobile devices. While both facts are not necessarily relevant, the bottom line is that I don't have to support Internet Explorer or even Firefox for that matter (just WebKit). THE PROBLEM With my current CSS approach, the vertical padding of the cell comes from the <span element (set to display: block with top/bottom margins), which contains the "value" of the column. As a result there's no padding when the <span> is empty or missing (no value) and the label is not in place. The "full" coulmns should give you the idea of where I want the labels to be, even if there's no value, and the <span> is not there. I realize that I could use "non-breaking-space", but I would really like to avoid it. I wonder if any of you have a fix / better way to do this? current code is below. Thank you for any help. <!DOCTYPE html> <html lang="en"> <head> <title>ah</title> <style> body { width: 320px; } /* TABLE */ table { width: 100%; border-collapse: collapse; font-family: arial; } th, td { border: 1px solid #ccc; border-width: 0px 0px 1px 1px; } th:last-child, td:last-child { border-right-width: 1px; } tr:first-child th { border-top-width: 1px; background: #efefef; } /* RELEVANT STUFF */ td { padding: 3px; } td sup { display: block; } td span { display: block; margin: 3px 0px; text-align: center; } </style> </head> <body> <table> <tr> <th colspan="3">something</th> </tr> <tr> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span></span></td><!-- No content, just a label --> </tr> </table> </body> </html>

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  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

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  • send variable fancybox onclick event

    - by samuel saul
    hi, i want to send href value. but its not working. function display () { $.fancybox({ 'href': 'index.php', 'width' : '75%', 'height' : '75%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' }); } i tryed this : function display (who) { $.fancybox({ 'href': 'index.php'+who, 'width' : '75%', 'height' : '75%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' }); } <a onclick="javascript:display("?id=11");" href="#" >create</a> this onclick event inside the innerhtml so its not working with '' why

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  • Variable Operators in PHP

    - by BenTheDesigner
    Given this example, how would I return the result of the equation rather than the equation itself as a string? $operator = '+'; foreach($resultSet as $item){ $result = $item[$this->orderField] . $operator . 1; echo $result; }

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  • Sinatra Variable Scope

    - by Ethan Turkeltaub
    Take the following code: ### Dependencies require 'rubygems' require 'sinatra' require 'datamapper' ### Configuration config = YAML::load(File.read('config.yml')) name = config['config']['name'] description = config['config']['description'] username = config['config']['username'] password = config['config']['password'] theme = config['config']['theme'] set :public, 'views/themes/#{theme}/static' ### Models DataMapper.setup(:default, "sqlite3://#{Dir.pwd}/marvin.db") class Post include DataMapper::Resource property :id, Serial property :name, String property :body, Text property :created_at, DateTime property :slug, String end class Page include DataMapper::Resource property :id, Serial property :name, String property :body, Text property :slug, String end DataMapper.auto_migrate! ### Controllers get '/' do @posts = Post.get(:order => [ :id_desc ]) haml :"themes/#{theme}/index" end get '/:year/:month/:day/:slug' do year = params[:year] month = params[:month] day = params[:day] slug = params[:slug] haml :"themes/#{theme}/post.haml" end get '/:slug' do haml :"themes/#{theme}/page.haml" end get '/admin' do haml :"admin/index.haml" end I want to make name, and all those variables available to the entire script, as well as the views. I tried making them global variables, but no dice.

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  • How to trim whitespace from bash variable?

    - by too much php
    I have a shell script with this code: var=`hg st -R "$path"` if [ -n "$var" ]; then echo $var fi But the conditional code always executes because hg st always prints at least one newline character. Is there a simple way to strip whitespace from $var (like trim() in php)? or Is there a standard way of dealing with this issue? I could use sed or awk, but I'd like to think there is a more elegant solution to this problem.

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  • How to Navigate Directly From One Table to Another in Word 2013

    - by Lori Kaufman
    Jumping to a specific page in Word is a common task and easy to do using the Find and Replace dialog box. You can also use this same tab to jump from one table directly to the next table in your document. Your cursor does not have to be in a table to jump to the next table. Put the cursor in any paragraph or table and press F5 or use the Ctrl + G keystroke combination to open the Find and Replace dialog box. The Go To tab is automatically selected. Select Table from the Go to what list and click Next. The next table in your document is selected and the Find and Replace dialog box stays open.    

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  • How to declare a variable in MS SQL and use it in the same Stored Procedure

    - by Nicklas
    Im trying to get the Value from BrandID in one tabel and add it to another tabel. But I can't get it to work. Anybody know how to do it right? CREATE PROCEDURE AddBrand AS DECLARE @BrandName nvarchar(50), @CategoryID int, @BrandID int SELECT @BrandID = BrandID FROM tblBrand WHERE BrandName = @BrandName) INSERT INTO tblBrandinCategory (CategoryID, BrandID) VALUES (@CategoryID, @BrandID) RETURN

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  • Dollar ($) sign in password string treated as variable

    - by ncatnow
    Spent some time troubleshooting a problem whereby a PHP/MySQL web application was having problems connecting to the database. The database could be accessed from the shell and phpMyAdmin with the exact same credentials and it didn't make sense. Turns out the password had a $ sign in it: $_DB["password"] = "mypas$word"; The password being sent was "mypas" which is obviously wrong. What's the best way to handle this problem? I escaped the $ with a \ $_DB["password"] = "mypas\$word"; and it worked. I generally use $string = 'test' for strings which is probably how I avoided running into this before. Is this correct behavious? What if this password was stored in a database and PHP pulled it out - would this same problem occur? What am I missing here...

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  • c++ warning: address of local variable

    - by chnet
    int * ref () { int tmp = 100; return &tmp; } int main () { int * a = ref(); cout << *a << endl; } I know the function ref () is allocated stack space. It will get destroyed as soon as the function exits. So the complier will give warning information. But my question is why the returning result is still correct.

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  • vb.net session variable passing "space" from one page to another

    - by iuret
    i have 2 aspx webpages with vb.net code. On the first page, I have a text box, on first page that says "Enter Hobby", but its not a required textbox. So if the user clicks submit, it'll load up the second page. Now in the second page i have textbox "hobby" which has maxlength = 10. and in the vb.net code i have hobby.text = session("hobby"). if the user doesnt fill up hobby in first page, the session comes with 10 "spaces" since maxlength is 10. I tried hobby.text = TRIM(session("hobby"), but nothing happens. Any idea how i can lose the spaces if nothing is inputted?

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  • Question about variable definitions in functions.

    - by Kaan Tekelioglu
    Hi. #include <stdio.h> main() { int a; for(a=1; a<=4 && printf("%d ",a); a++) { int a; static int b=a; printf("%d ",(a++)-b); } getchar(); getchar(); } In this code, the printout is 1 0 2 1 3 2 4 3. I understand why the int a; part works differently then the int a which was defined outside the for function, and why static int b; is only defined once with the primary value of a ; but why does the (a++) part in printf affect proceeding values of a? Don't we redefine int a; each time the for function runs? Thanks in advance.

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  • how can i request a variable in my home.ctp of my cakePHP application?

    - by Simon
    I created a page using the MVC structure called 'sections' ( view is located in the app/views/sections folder, model in the model folder and the controller in the controller folder) when i request the variable $test, it works fine without any errors.. When i want to request this variable in my home.ctp, it provides me with an error, saying that the variable is undefined.. Is there any way in cakePHP to request this variable on any page you want it to? Thnx in advance!

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  • How do I supply a variable to put in a another variable in PHP?

    - by Jared
    I'm not sure if I asked the question correctly. I have some code I am trying to embed. For instance: $menuPopup ='<IMG SRC="' . $someVariable . '">'; Later on, I have the a few product variables: $someProduct1 ='image1.jpg'; $someProduct2 ='image2.jpg'; Later on, want to display the $menuPopup, using a src from $someProduct1, or $someProduct2. //Pseudo Code $menuPopup ( $someProduct1); Anyway to do that?

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