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  • Cladogram, tree of life, cladistics, taxonomy in JS or canvas?

    - by boblet
    Good people - I need some help to find a way to create an interactive cladogram or phylogenetic tree (yes, I have read all related posts, and do not find what I am looking for). The thing is, I need the nodes to be name-able. An example would be something like this Most scripts I find are either applets, flash, or simply do not show the node classification, ie it would skip "feliformia" in this example. This is useless to me, as I would then end up with carnivore - anonymous node - anonymous node - anonymous node - tiger, and that is not good. This tree will in theory cover all life, so it could get rather large, and get links and names in english and latin from database. So: no flash, no applets. It must be horizontal, no supertrees (circular). I have gone through this http://bioinfo.unice.fr/biodiv/Tree_editors.html but most of them seems to be either old, not displaying sub-node levels, applets, or way too complex. I imagine this would be a delightful job for canvas/jQuery..? And chances are, someone got there before me? Any pointers much appreciated. Note: if anyone out there would like to do something like this as a project, I will be happy to help, even though it would not benefit me for this project.This type of taxonomy is not as simple as it may seem, and I would be happy see this happen.

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  • How can you get the call tree with python profilers?

    - by Oliver
    I used to use a nice Apple profiler that is built into the System Monitor application. As long as your C++ code was compiled with debug information, you could sample your running application and it would print out an indented tree telling you what percent of the parent function's time was spent in this function (and the body vs. other function calls). For instance, if main called function_1 and function_2, function_2 calls function_3, and then main calls function_3: main (100%, 1% in function body): function_1 (9%, 9% in function body): function_2 (90%, 85% in function body): function_3 (100%, 100% in function body) function_3 (1%, 1% in function body) I would see this and think, "Something is taking a long time in the code in the body of function_2. If I want my program to be faster, that's where I should start." Does anyone know how I can most easily get this exact profiling output for a python program? I've seen people say to do this: import cProfile, pstats prof = cProfile.Profile() prof = prof.runctx("real_main(argv)", globals(), locals()) stats = pstats.Stats(prof) stats.sort_stats("time") # Or cumulative stats.print_stats(80) # 80 = how many to print but it's quite messy compared to that elegant call tree. Please let me know if you can easily do this, it would help quite a bit. Cheers!

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  • A data structure based on the R-Tree: creating new child nodes when a node is full, but what if I ha

    - by Tom
    I realize my title is not very clear, but I am having trouble thinking of a better one. If anyone wants to correct it, please do. I'm developing a data structure for my 2 dimensional game with an infinite universe. The data structure is based on a simple (!) node/leaf system, like the R-Tree. This is the basic concept: you set howmany childs you want a node (a container) to have maximum. If you want to add a leaf, but the node the leaf should be in is full, then it will create a new set of nodes within this node and move all current leafs to their new (more exact) node. This way, very populated areas will have a lot more subdivisions than a very big but rarely visited area. This works for normal objects. The only problem arises when I have more than maxChildsPerNode objects with the exact same X,Y location: because the node is full, it will create more exact subnodes, but the old leafs will all be put in the exact same node again because they have the exact same position -- resulting in an infinite loop of creating more nodes and more nodes. So, what should I do when I want to add more leafs than maxChildsPerNode with the exact same position to my tree? PS. if I failed to explain my problem, please tell me, so I can try to improve the explanation.

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  • Add Zend_Navigation to the View with old legacy bootstrap

    - by Grant Collins
    Hi, I've been struggling with Zend_Navigation all weekend, and now I have another problem, which I believe has been the cause of a lot of my issues. I am trying to add Zend_Navigation to a legacy 1.7.6 Zend Framework application, i've updated the Zend Library to 1.9.0 and updated the bootstrap to allow this library update. The problem is that I don't know how, and the examples show the new bootstrap method of how to add the Navigation object to the view, I've tried this: //initialise the application layouts with the MVC helpers $layout = Zend_Layout::startMvc(array('layoutPath' => '../application/layouts')); $view = $layout->getView(); $configNav = new Zend_Config_Xml('../application/config/navigation.xml', 'navigation'); $navigation = new Zend_Navigation($configNav); $view->navigation($navigation); $viewRenderer = new Zend_Controller_Action_Helper_ViewRenderer(); $viewRenderer->setView($view); This seems to run through fine, but when I go to use the breadcrumb view helper in my layout, it errors with: Strict Standards: Creating default object from empty value in C:\www\moobia\development\website\application\modules\employers\controllers\IndexController.php on line 27 This is caused by the following code in the init() function of my controller. $uri = $this->_request->getPathInfo(); $activeNav = $this->view->navigation()->findByUri($uri); <- this is null when called $activeNav->active = true; I believe it's because the Zend_Navigation object is not in the view. I would look at migrating the bootstrap to the current method, but at present I am running out of time for a release. Thanks, Grant

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  • JSF: Using same jsp page for different outcomes

    - by ComputerPilot
    Would it be possible to use a navigation-case as shown below with the same view-id but different from-outcomes? In the managed bean, I wanted to compare the from-outcome values and decide on the group panel that I would display on the page. How can I get the from-outcome value in my managed bean? <navigation-case> <from-outcome>modifyphone</from-outcome> <to-view-id>/modifytelephone.jsp</to-view-id> </navigation-case> <navigation-case> <from-outcome>confirmmodifyphone</from-outcome> <to-view-id>/modifytelephone.jsp</to-view-id> </navigation-case> <navigation-case> <from-outcome>submitmodifyphone</from-outcome> <to-view-id>/modifytelephone.jsp</to-view-id> </navigation-case>

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  • Keyboard Navigation of File Open Dialog in Windows 7

    - by dkusleika
    In Windows XP standard File - Open dialog, the top has a "Look In" box. I can press Alt+I to drop down a tree of the disks folders and easily navigate to other folders or network shares. In Windows 7, I can't seem to navigate the File - Open dialog as easily. The best I've been able to muster is to tab 5 times (in Excel 2007, but I assume it's a windows standard), then use arrow keys or use Alt+arrow keys like a browser to get around. It's simply not as good because I can't see the whole tree at once. Is there a way to see the whole folder tree? If not, do you have any other tips for keyboard navigation of the file open dialog in Windows 7?

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • How can I force a tree itemrenderer to redraw during a drag and drop operation?

    - by swidnikk
    I have a tree control with a custom item renderer. The item renderer has different states that should be set while an item is being dragged over the item renderer. I understand from reading this post http://forums.adobe.com/message/2091088 that the 'right way' to do this is to override the 'getCurrentState' method and append some text. I do that. Now in my tree control I handle the drag over event and get a reference to the itemrenderer that is being dragged over and I set the boolean 'dragOver' property to true. Now I just need to force my itemRenderer to redraw. I can't figure that out. A workaround, is to just set the currentState of the itemRenderer. My question then, how can I force my itemRenderer to refresh? (and I've tried calling validateNow, invalideDisplayList/Properties/Size, to no avail) <?xml version="1.0" encoding="utf-8"?> <s:MXTreeItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx"> <fx:Script> <![CDATA[ import mx.events.DragEvent; import mx.events.FlexEvent; import spark.layouts.supportClasses.DropLocation; public var dragOver:Boolean = false; override protected function getCurrentRendererState():String { var skinState:String = super.getCurrentRendererState(); if( dragOver ) skinState += "AndDragOver"; trace('getCurrentRendererState', skinState); return skinState; } ]]> </fx:Script> <s:states> <s:State name="normal" /> <s:State name="hovered" /> <s:State name="selected" /> <s:State name="normalAndDragOver" stateGroups="dragOverGroup" /> <s:State name="hoveredAndDragOver" stateGroups="dragOverGroup" /> <s:State name="selectedAndDragOver" stateGroups="dragOverGroup" /> </s:states> ...

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  • How to modify preorder tree traversal algorithm to handle nodes with multiple parents?

    - by poldo
    I've been searching for a while now and can't seem to find an alternative solution. I need the tree traversal algorithm in such a way that a node can have more than 1 parent, if it's possible (found a great article here: Storing Hierarchical Data in a Database). Are there any algorithms so that, starting from a root node, we can determine the sequence and dependencies of nodes (currently reading topological sorting)?

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  • merge sort recursion tree height

    - by Tony
    Hello! I am learning about recursion tree's and trying to figure out how the height of the tree is log b of n where n = 2 and one has 10 elements as input size. I am working with Merge sort. The number of times the split is done is the height of the tree as far as I understood, and the number of levels in the tree is height + 1. But if you take (for merge sort) log2 of 10 you get 1, where if you draw the tree you get at least 2 times that the recursion occurs. Where have I gone wrong? (I hope I am making sense here) NOTE: I am doing a self study, this is not homework!

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  • Tree item edit event listener in flex

    - by Biroka
    I want to catch itemEditEnd in a tree control, but i'm having a little trouble. I call the item editing a bit different: <mx:Tree id="tree" width="100%" height="100%" itemDoubleClick="treeProjects_itemDoubleClickHandler(event)" doubleClickEnabled="true" editable="true" itemEditBeginning="treeProjects_itemEditBeginingHandler(event)" itemEditEnd="treeProjects_itemEditEndHandler(event)" > but: protected function treeProjects_itemEditBeginingHandler(event:ListEvent):void { event.preventDefault(); } i do this, because I want to edit the field just when clicking rename in the context menu. And when I click rename in the context menu, this is what i'm doing (contextParentItem is the event catched on itemRollOver in the tree) : Tree( contextParentItem.target ).editedItemPosition = { columnIndex: 0, rowIndex: contextParentItem.rowIndex }; Thisway I can't catch the itemEditEnd event, but I want to handle some stuff, like: if the new entered value is an empty string, then I don't want to accept the new value if I hit ESC then, the old value should remain.

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  • dojo 1.4: difference in tree html rendering

    - by Fell
    Hi, I have written an application using dojo 1.3 in which i have used the dijit tree. I am loading the tree with json data specified in the store which is in turn used by the tree model. In the 1.3 version the tree elements pick up the id directly from the json data.However in 1.4 the tree elements have their own id which is something like dijit__treenode_4. The id's that I have specified in json are unique and im not able to understand why these are not being used anymore. Please help me understand how this functionality has changed and how I can override the automatic id generation.. Thanks in advance, Fell

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  • Very long tree control inside a <frame>

    - by ryancerium
    I have an tree control inside of a frame. It's quite tall, around 2000 pixels. Right now, we use the frame's scroll bars, which is mostly good. Unfortunately, when you select an item near the bottom of the list, the page reloads and the view goes back to the top of the list. I tried calling the tree control's ScrollNodeIntoView() function, but since we're not using the tree's scroll bars, it just thinks that it's displaying the full 2000 pixels and the control doesn't have its own scroll bar. I'm not much of an HTML guru, so I have two ideas, neither of which I know how to do. 1) Tell the frame to not to let the tree render all 2000 pixels and instead stay inside the viewable area. 2) Tell the tree to not render all 2000 pixels and instead stay within the viewable area. Setting the CSS height property on the within the frame doesn't do anything. Thanks.

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  • Virtual String Tree - Display subnode when parent node is hidden

    - by daemon_x
    Is there a way to show subnode if the parent node is hidden in the Virtual String Tree ? I have some tasks in the tree structure and I wish to display only tasks which belongs to the current user as the list, but from all levels. What I've done is the function to display a list, which hides tree buttons, tree lines, sets the fixed indent and enable toShowHiddenNodes option. Then in this function I iterate through the whole tree (all levels) and hide nodes which doesn't belong to the current user IsVisible[Node] := False and show those which belongs him IsVisible[Node] := True, but the subnodes which should be displayed are invisible when their parent is hidden. VT.TreeOptions.PaintOptions - toShowButtons - toShowTreeLines + toFixedIndent + toShowHiddenNodes

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  • Last element not getting insert in Tree

    - by rdk1992
    So I was asked to make a Binary Tree in Haskell taking as input a list of Integers. Below is my code. My problem is that the last element of the list is not getting inserted in the Tree. For example [1,2,3,4] it only inserts to the tree until "3" and 4 is not inserted in the Tree. data ArbolBinario a = Node a (ArbolBinario a) (ArbolBinario a) | EmptyNode deriving(Show) insert(x) EmptyNode= insert(tail x) (Node (head x) EmptyNode EmptyNode) insert(x) (Node e izq der) |x == [] = EmptyNode --I added this line to fix the Prelude.Head Empty List error, after I added this line the last element started to be ignored and not inserted in the tree |head x == e = (Node e izq der) |head x < e = (Node e (insert x izq) der) |head x > e = (Node e izq (insert x der)) Any ideas on whats going on here? Help is much appreciated

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  • Security Trimmed Cross Site Collection Navigation

    Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). This feed URL has been discontinued. Please update your reader's URL to : http://feeds.feedburner.com/winsmarts Read full article .... ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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