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  • INSERT INTO table doesn't work???

    - by Joann
    I found a tutorial from nettuts and it has a source code in it so tried implementing it in my site.. It is working now. However, it doesn't have a Registration system so I am making one. The thing is, as I have expected, my code is not working... It doesn't seem to know how to INSERT into the database. Here's the function that inserts data into the db. function register_User($un, $email, $pwd) { $query = "INSERT INTO users( username, password, email ) VALUES(:uname, :pwd, :email) LIMIT 1"; if($stmt = $this->conn->prepare($query)) { $stmt->bind_param(':uname', $un); $stmt->bind_param(':pwd', $pwd); $stmt->bind_param(':email', $email); $stmt->execute(); if($stmt->fetch()) { $stmt->close(); return true; } else return "The username or email you entered is already in use..."; } } I have debugged the connection to the database from within the class, it says it's connected. I tried using this method instead: function register($un, $email, $pwd) { $registerquery = $this->conn->query( "INSERT INTO users(uername, password, email) VALUES('".$un."', '".$pwd."', '".$email."')"); if($registerquery) { echo "<h4>Success</h4>"; } else { echo "<h4>Error</h4>"; } } And it echos "Error"... Can you please help me pen point the error in this??? :(

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  • Inserting variables into a query string - it won't work!

    - by Jonesy
    Basically i have a query string that when i hardcode in the catalogue value its fine. when I try adding it via a variable it just doesn't pick it up. This works: Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=WaspTrackAsset_NROI;User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") This doesn't: Public Sub GetWASPAcr() connection.Open() Dim dt As New DataTable() Dim username As String = HttpContext.Current.User.Identity.Name Dim sqlCmd As New SqlCommand("SELECT WASPDatabase FROM dbo.aspnet_Users WHERE UserName = '" & username & "'", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) If dt.Rows.Count > 0 Then For i As Integer = 0 To dt.Rows.Count - 1 If dt.Rows(i)("WASPDatabase") Is DBNull.Value Then WASP = "" Else WASP = "WaspTrackAsset_" + dt.Rows(i)("WASPDatabase") End If Next End If connection.Close() End Sub Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=" & WASP & ";User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") When I debug the catalog is empty in the query string but the WASP variable holds the value "WaspTrackAsset_NROI" Any idea's why? Cheers, jonesy

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • Putting together CSV Cells in Excel with a macro

    - by Eric Kinch
    So, I have a macro to export data into CSV format and it's working great (Code at the bottom). The problem is the data I am putting into it. When I put the data in question in it comes out Firstname,Lastname,username,password,description I'd like to change it so I get Firstname Lastname,Firstname,Lastname,username,password,description What I'd like to do is manipulate my existing macro so to accomplish this. I'm not so good at VBS so any input or a shove in the right direction would be fantastic. Thanks! Sub Make_CSV() Dim sFile As String Dim sPath As String Dim sLine As String Dim r As Integer Dim c As Integer r = 1 'Starting row of data sPath = "C:\CSVout\" sFile = "MyText_" & Format(Now, "YYYYMMDD_HHMMSS") & ".CSV" Close #1 Open sPath & sFile For Output As #1 Do Until IsEmpty(Range("A" & r)) 'You can also Do Until r = 17 (get the first 16 cells) sLine = "" c = 1 Do Until IsEmpty(Cells(1, c)) 'Number of Columns - You could use a FOR / NEXT loop instead sLine = sLine & """" & Replace(Cells(r, c), ";", ":") & """" & "," c = c + 1 Loop Print #1, Left(sLine, Len(sLine) - 1) 'Remove the trailing comma r = r + 1 Loop Close #1 End Sub

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  • CMD Prompt > FTP Size Command

    - by Samuel Baldus
    I'm developing a PHP App on IIS 7.5, which uses PHP FTP commands. These all work, apart from ftp_size(). I've tested: cmd.exe > ftp host > username > password > SIZE filename = Invalid Command However, if I access the FTP site through an Internet Browser, the filesize is displayed. Do I need to install FTP Extensions, and if so, which ones and where do I get them? Here is the PHP Code: <?php // FTP Credentials $ftpServer = "www.domain.com"; $ftpUser = "username"; $ftpPass = "password"; // Unlimited Time set_time_limit(0); // Connect to FTP Server $conn = @ftp_connect($ftpServer) or die("Couldn't connect to FTP server"); // Login to FTP Site $login = @ftp_login($conn, $ftpUser, $ftpPass) or die("Login credentials were rejected"); // Set FTP Passive Mode = True ftp_pasv ($conn, true); // Build the file list $ftp_nlist = ftp_nlist($conn, "."); // Alphabetical sorting sort($ftp_nlist); // Display Output foreach ($ftp_nlist as $raw_file) { // Get the last modified time $mod = ftp_mdtm($conn, $raw_file); // Get the file size $size = ftp_size($conn, $raw_file); // Size is not '-1' => file if (!(ftp_size($conn, $raw_file) == -1)) { //output as file echo "Filename: $raw_file<br />"; echo "FileSize: ".number_format($size, '')."Kb</br>"; echo "Last Modified: ".date("d/m/Y H:i", $mod)."</br>"; } } ?>

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  • Cannot redeploy to remote tomcat 7 with using cargo-maven-plugin

    - by rottmanj
    I am attempting to build and redeploy to a remote tomcat 7 server using the cargo-maven plugin. I have been able to successfully deploy to the remote server, but all other actions fail. Here is the pluging settings in my pom.xml <plugin> <groupId>org.codehaus.cargo</groupId> <artifactId>cargo-maven2-plugin</artifactId> <version>1.1.1</version> <configuration> <!-- Container configuration --> <container> <containerId>tomcat7x</containerId> <type>remote</type> </container> <configuration> <type>runtime</type> <properties> <cargo.remote.username>tomcat</cargo.remote.username> <cargo.remote.password>tomcat</cargo.remote.password> <cargo.remote.uri>http://devserver:8080/manager/html</cargo.remote.uri> </properties> </configuration> </configuration> </plugin> This is the error I am seeing within eclipse, when I attempt to deploy. I posted it to pastebin so it is easier to read. Error link. Any help with this is greatly appreciated.

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • DWR and Spring Security - User is deauthenticated in few seconds

    - by Vojtech
    I am trying to implement user authentication via DWR as follows: public class PublicRemote { @Autowired @Qualifier("authenticationManager") private AuthenticationManager authenticationManager; public Map<String, Object> userLogin(String username, String password, boolean stay) { Map<String, Object> map = new HashMap<>(); UsernamePasswordAuthenticationToken authRequest = new UsernamePasswordAuthenticationToken(username, password); try { Authentication authentication = authenticationManager.authenticate(authRequest); SecurityContextHolder.getContext().setAuthentication(authentication); map.put("success", "true"); } catch (Exception e) { map.put("success", "false"); } return map; } public Map<String, Object> getUserState() { Map<String, Object> map = new HashMap<>(); Authentication authentication = SecurityContextHolder.getContext().getAuthentication(); boolean authenticated = authentication != null && authentication.isAuthenticated(); map.put("authenticated", authenticated); if (authenticated) { map.put("authorities", authentication.getAuthorities()); } return map; } } The authentication works correctly and by calling getUserState() I can see that the user is successfully logged in. The problem is that this state will stay only for few seconds. In probably 5 seconds, the getAuthentication() starts returning null. Is there some problem with session in DWR or is it some misconfiguration of Spring Security?

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  • To OpenID or not to OpenID? Is it worth it?

    - by Eloff
    Does OpenID improve the user experience? Edit Not to detract from the other comments, but I got one really good reply below that outlined 3 advantages of OpenID in a rational bottom line kind of way. I've also heard some whisperings in other comments that you can get access to some details on the user through OpenID (name? email? what?) and that using that it might even be able to simplify the registration process by not needing to gather as much information. Things that definitely need to be gathered in a checkout process: Full name Email (I'm pretty sure I'll have to ask for these myself) Billing address Shipping address Credit card info There may be a few other things that are interesting from a marketing point of view, but I wouldn't ask the user to manually enter anything not absolutely required during the checkout process. So what's possible in this regard? /Edit (You may have noticed stackoverflow uses OpenID) It seems to me it is easier and faster for the user to simply enter a username and password in a signup form they have to go through anyway. I mean you don't avoid entering a username and password either with OpenID. But you avoid the confusion of choosing a OpenID provider, and the trip out to and back from and external site. With Microsoft making Live ID an OpenID provider (More Info), bringing on several hundred million additional accounts to those provided by Google, Yahoo, and others, this question is more important than ever. I have to require new customers to sign up during the checkout process, and it is absolutely critical that the experience be as easy and smooth as possible, every little bit harder it becomes translates into lost sales. No geek factor outweighs cold hard cash at the end of the day :) OpenID seems like a nice idea, but the implementation is of questionable value. What are the advantages of OpenID and is it really worth it in my scenario described above?

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  • How to get Tkinter to input text and submit with button

    - by Rob
    Hi I was wondering if anybody could help me submit code from the test fields to the login fields from Tkinter import * import tkMessageBox if ( __name__ == "__main__" ): import resources.lib.mechanize as mechanize mechanize # Start Browser br = mechanize.Browser(factory=mechanize.RobustFactory()) # User-Agent (Firefox) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://razetheworld.com/wp-login.php?redirect_to=http%3A%2F%2Frazetheworld.com') br.select_form(name="loginform") br['log'] = 'entryWidget_U must enter here' br['pwd'] = 'entryWidget_P must enter here' br.submit(name="wp-submit") print br.geturl() def displayText(): """ Display the Entry text value. """ global entryWidget_U global entryWidget_P if entryWidget_U.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Username") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_U.get().strip()) if entryWidget_P.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Password") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_P.get().strip()) if __name__ == "__main__": root = Tk() root.title("Tkinter Entry Widget") root["padx"] = 40 root["pady"] = 20 # Create a text frame to hold the text Label and the Entry widget textFrame_U = Frame(root) textFrame_P = Frame(root) #Create a Label in textFrame entryLabel = Label(textFrame_U) entryLabel["text"] = "Enter Username:" entryLabel.pack(side=LEFT) entryLabel = Label(textFrame_P) entryLabel["text"] = "Enter Password:" entryLabel.pack(side=LEFT) # Create an Entry Widget in textFrame entryWidget_U = Entry(textFrame_U) entryWidget_U["width"] = 50 entryWidget_U.pack(side=LEFT) entryWidget_P = Entry(textFrame_P) entryWidget_P["width"] = 50 entryWidget_P.pack(side=LEFT) textFrame_U.pack() textFrame_P.pack() button = Button(root, text="Login", command=#Run br.submit(name="wp-submit")) button.pack() root.mainloop()

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  • Remove this URL string when login fails and simply show div error

    - by Anagio
    My developer built our registration page to display a div when logins failed based on a string in the URL. When logins fail this is added to the URL /login?msg=invalid The PHP in my login.phtml which displays the error messages based on the msg= parameter is <?php $msg = ""; $msg = $_GET['msg']; if($msg==""){ $showMsg = ""; } elseif($msg=="invalid"){ $showMsg = ' <div class="alert alert-error"> <a class="close" data-dismiss="alert">×</a> <strong>Error!</strong> Login or password is incorrect! </div>'; } elseif($msg=="disabled"){ $showMsg = "Your account has been disabled."; } elseif($msg==2){ $showMsg = "Your account is not activated. Please check your email."; } ?> In the controller the redirect to that URL is else //email id does not exist in our database { //redirecting back with invalid email(invalid) msg=invalid. $this->_redirect($url."?msg=invalid"); } I know there are a few other validation types for disabled accounts etc. I'm in the process of redesigning the entire interface and would like to get rid of this kind of validation so that the div tags display when logins fail but not show the URL strings. If it matters the new div I want to display is <div class="alert alert-error alert-login"> Email or password incorrect </div> I'd like to replace the php my self in my login.phtml and controller but not a good programmer. What can I replace $this->_redirect($url."?msg=invalid"); with so that no strings are added to the URL and display the appropriate div tags? Thanks

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  • Get Mail with PHP and IMAP in Gmail just loading

    - by Oscar Godson
    I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = '[email protected]'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

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  • Output problem in mysql query in MFC program

    - by D.Gaughan
    Im currently working on a small MFC program that outputs data from a mysql database. I can get output when im using an sql statement that does not contain any variable eg. select album from Artists; but when i try to use a variable the program compiles but i get no output eg. mysql_perform_query(conn,select album from Artists where artists = '"+m_search_edit"'") Here is the function for mysql_perform_query: MYSQL_RES* mysql_perform_query(MYSQL *conn, const char* query) { // send the query to the database if (mysql_query(conn, query)) { // printf("MySQL query error : %s\n", mysql_error(conn)); // exit(1); } return mysql_use_result(conn); } And here is the code block for outputting the data: struct connection_details mysqlD; mysqlD.server = "www.freesqldatabase.com"; // where the mysql database is mysqlD.user = "**********"; // the root user of mysql mysqlD.password = "***********"; // the password of the root user in mysql mysqlD.database = "***************"; // the databse to pick // connect to the mysql database conn = mysql_connection_setup(mysqlD); CStringA query; query.Format("select album from Artists where artist = '%s'", CT2CA(m_search_edit)); res = mysql_perform_query(conn, query); //res = mysql_perform_query (conn, "select distinct artist from Artists"); while((row = mysql_fetch_row(res)) != NULL){ CString str; UpdateData(); str = ("%s\n", row[0]); UpdateData(FALSE); m_list_control.AddString(str); } The m_search_edit variable is the variable for an edit box. I am using Visual Studio 2008 with one copy of this program unicode and one nonunicode, I also have a version built with VC++ 6. Any tips on how I can get output from the databse using the m_search_edit variable??

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  • cannot modify header information puzzler

    - by outofmyleague_lucy
    hi im out of my league i have written what has now become identical code for two sites hosted on different servers. the first worked perfectly and i have therefore used it to compare the second to.from a login for i am directing to a loginaction.php when i include the db_connect.php ie <?php session_start(); include 'db_connect.php'; $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? i am returning cannot modify header information header info already sent, but when i include the content of the db_connect ie <?php session_start(); $connect = mysql_connect("localhost", "user", "pass"); mysql_select_db(db_name, $connection); $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? it works. any ideas? edit - requested error message Warning: Cannot modify header information - headers already sent by (output started at /home/avenncou/public_html/include/db_connect.php:4) in /home/avenncou/public_html/include/loginaction.php on line 14 at line 14 the is a header("Location: {$_SERVER["HTTP_REFERER"]}"); edit - requested db_connect.php <?php $connection = mysql_connect("localhost", "user", "pass");// or die ("Unable to connect!"); mysql_select_db("db", $connection);// or die ("Unable to select database!"); ?> that is all of it (dies commented out in case thats where the error was)!!!

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  • Can i change the identity of the logged in user in ASP.net?

    - by Rising Star
    I have an ASP.net application I'm developing authentication for. I am using an existing cookie-based log on system to log users in to the system. The application runs as an anonymous account and then checks the cookie when the user wants to do something restricted. This is working fine. However, there is one caveat: I've been told that for each page that connects to our SQL server, I need to make it so that the user connects using an Active Directory account. because the system I'm using is cookie based, the user isn't logged in to Active Directory. Therefore, I use impersonation to connect to the server as a specific account. However, the powers that be here don't like impersonation; they say that it clutters up the code. I agree, but I've found no way around this. It seems that the only way that a user can be logged in to an ASP.net application is by either connecting with Internet Explorer from a machine where the user is logged in with their Active Directory account or by typing an Active Directory username and password. Neither of these two are workable in my application. I think it would be nice if I could make it so that when a user logs in and receives the cookie (which actually comes from a separate log on application, by the way), there could be some code run which tells the application to perform all network operations as the user's Active Directory account, just as if they had typed an Active Directory username and password. It seems like this ought to be possible somehow, but the solution evades me. How can I make this work?

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  • CakePHP: Need help using saveField to update a fields in a belongsTo model

    - by afrisch
    I am trying to update a password into two different models/tables in CakePHP. I can update it fine in the parent model, but not the second model. Models: Users (hasOne GameProfile) PK=id Gameprofiles (belongsTo User) FK=user_id Here is a stripped down version of my function in the Users_controller.php: function updatepass() { if (!empty($this->data)) { $this->User->id = $this->Auth->user('id'); $this->User->saveField('sha1password', $this->Auth->password($this->data['User']['newpass'])); $this->User->Gameprofile->saveField('plainpassword', $this->data['User']['newpass']); } } When I execute the function, the users table is updated fine. But the gameprofile table is not updated, rather Cake does an insert. SQL Query Log: 1195 Query UPDATE `users` SET `sha1password` = 'e9443e9f5e1a07832aad1b2f84de1a666daf89b5' WHERE `users`.`id` = 30 1195 Query INSERT INTO `gameprofiles` (`plainpassword`) VALUES ('abc') Is there a way to get CakePHP to do an update using saveField on a model with a belongsTo attribute? I've tried various ways to refer to user_id before executing the second saveField, but just can't seem to find the winning combination. Any help is greatly appreciated!

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  • Kohana Auth Library Deployment

    - by Steve
    My Kohana app runs perfectly on my local machine. When I deployed my app to a server (and adjust the config files appropriately), I can no longer log into the app. I've traced through the app login routine on both my local version and the server version and they both agree with each other all the way through until you get to the auth.php controller logged_in() routine where suddenly, at line 140 - the is_object($this-user) test - the $user object no longer exists!?!?!? The login() function call that calls the logged_in() function successfully passes the following test, which causes a redirect to the logged_in() function. if(Auth::instance()->login($user, $post['password'])) Yes, the password and hash, etc all work perfectly. Here is the offending code: public function logged_in() { if ( ! is_object($this->user)) { // No user is currently logged in url::redirect('auth/login'); } etc... } As the code is the same between my local installation and the server, I reckon it must be some server setting that is messing with me. FYI: All the rest of the code works because I have a temporary backdoor available that allows me to use the application (view pages of tables, etc) without being logged in. Any ideas?

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  • The post->success->data variable is empty..

    - by Asaf
    Hello, I tried sending some data like so: <form action="http://www.someurl.com/something.php" id="login"> <input type="textbox" id="UserName" value="user"> <input type="textbox" id="Password" value="password"> <input type="submit" value="submit"> </form> <div id="result"></div> <script type="text/javascript"> $('form#login').submit(function() { $.post($('form#login').attr('action'), $('form#login').serialize(), function(data) { $('#result').html(data+'222') }); return false; }); </script> Now, the value of #result div change to 222... that is: the post was successful but for some reason there is no data, and when I go directly to something.php and post manually, it does bring back data (am I mistaken or does the post(success(data)) variable returns the whole page returned after you post something? if so, how could it be?) Thank you very much for your help

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  • Create Session Variable from different datasources?

    - by Szafranamn
    Currently I am developing a dynamic website using Dreamweaver cs5 with ColdFusion 9 and using Access to create my databases along with QuickBooks and QODBC to create database. I have established a login session variable stemming from the login page. This session variable is being drawn from one Datasource "Access" Table "Logininfo" Field "FullName" but I wanted to create another session variable either at this point or further into the member's page to use in a query sequence. This session variable would stem from another Datasoucre "QBs" Table "Invoice" Field "CustomerRefFullName" which is generated through Quickbooks and QODBC. I am not sure if this is possible but if it is how do I do it. I want to do this so I can query the Invoice database to upload the customer's Invoices unique to them onto their page. So it would have to be related to their login credentials. If there is another better route to take I would greatly appreciate the advice. Below is the login code if there is additional information needed let me know. This is my current thinking/plan to do what I wish to intend hence the need to create the session variable: I have another Datasource "QBs" with a Table "Invoice" when I create another webpage for the customer to see their invoice I need to create a recordset that accesses that Table. In order to do so I think the best way would some home convert the session.FullName (which came from Access Datasource, Logininfor Table) into a session.CustomerRefFullName (which would have to come from (Datasource: QBs Table: Invoice Field: CustomerRefFullName) that way I could set the query WHERE CustomerRefFullName and have each logged in user see their specific Invoices. So is there a way to turn the session variable off one datasource/table into a different sessionvariable off a new datasource/table even if it is unique just to that page??? <cfif IsDefined("FORM.username")> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username= AND Password=

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  • Am I encrypting my passwords correctly in ASP.NET

    - by Nick
    I have a security class: public class security { private static string createSalt(int size) { //Generate a random cryptographic number RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider(); byte[] b = new byte[size]; rng.GetBytes(b); //Convert to Base64 return Convert.ToBase64String(b); } /// <summary> /// Generate a hashed password for comparison or create a new one /// </summary> /// <param name="pwd">Users password</param> /// <returns></returns> public static string createPasswordHash(string pwd) { string salt = "(removed)"; string saltAndPwd = string.Concat(pwd, salt); string hashedPwd = FormsAuthentication.HashPasswordForStoringInConfigFile( saltAndPwd, "sha1"); return hashedPwd; } } This works fine, but I am wondering if it is sufficient enough. Also, is this next block of code better? Overkill? static byte[] encrInitVector = new byte[] { 0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF }; static string encrKey = "(removed)"; public static string EncryptString(string s) { byte[] key; try { key = Encoding.UTF8.GetBytes(encrKey.Substring(0, 8)); DESCryptoServiceProvider des = new DESCryptoServiceProvider(); byte[] inputByteArray = Encoding.UTF8.GetBytes(s); MemoryStream ms = new MemoryStream(); CryptoStream cs = new CryptoStream(ms, des.CreateEncryptor(key, encrInitVector), CryptoStreamMode.Write); cs.Write(inputByteArray, 0, inputByteArray.Length); cs.FlushFinalBlock(); return Convert.ToBase64String(ms.ToArray()); } catch (Exception e) { throw e; }

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  • How to design authentication in a thick client, to be fail safe?

    - by Jay
    Here's a use case: I have a desktop application (built using Eclipse RCP) which on start, pops open a dialog box with 'UserName' and 'Password' fields in it. Once the end user, inputs his UserName and Password, a server is contacted (a spring remote-servlet, with the client side being a spring httpclient: similar to the approaches here.), and authentication is performed on the server side. A few questions related to the above mentioned scenario: If said this authentication service were to go down, what would be the best way to handle further proceedings? Authentication is something that I cannot do away with. Would running the desktop client in a "limited" mode be a good idea? For instance, important features/menus/views will be disabled, rest of the application will be accessible? Should I have a back up authentication service running on a different machine, working as a backup? What are the general best-practices in this scenario? I remember reading about google gears and how it would let you edit and do stuff offline - should something like this be designed? Please let me know your design/architectural comments/suggestions. Appreciate your help.

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  • jquery can't get the change event on select element

    - by user63898
    i have this code the jquery code never got triggered none of the scripts are triggered : $('select[name=privileges]').change(function(){ alert("id"); var id = $(this).find(':selected')[0].id; alert(id); $('#changevalue').val(id); }) or this: $("#privileges_select").change(function() { alert($('#privileges_select option:selected').html()); }); <form method="GET" action="create_new_user.php"> user:<input type="text" size="40" name="user_name"/> password:<input type="text" size="40" name="password"/> <select name=privileges id="privileges_select"> <option name='opt_1'>admin</option> <option name='opt_2'>ordinary</option> </select> <input type="hidden" name="item_options_id" value="" id="changevalue" /> <input type="submit" value ="create" /> <input type="reset" /> </form> in the end i like to send the selected option id in the form get

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  • Consume a JSON webservice and process data in Android

    - by user1783391
    I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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  • php code in FTP to backup db using URL

    - by Giom
    I fund and inserted this code in my FTP in a backup.php that works great but it copy the file into the root folder (homez/) 1- I would like to put these backup files in a homez/backupDB any idea where to put this path? 2- the db backup files (DB.sql.bz2) have always the same name, is it possible to name each one with the date of creation? (I launch this php with the URL link) <? echo "Votre base est en cours de sauvegarde....... "; $db="nom_de_ma_base"; $status=system("mysqldump --host=mysql5-1.perso --user=$_POST[login] --password=$_POST[password] $db > ../$db.sql"); echo $status; echo "Compression du fichier..... "; system("bzip2 -f ../$db.sql"); echo "C'est fini. Vous pouvez récupérer la base par FTP \n "; ?> Thanks!

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  • Can't post with Perl's Net::Blogger

    - by Ovid
    I'm trying to automatically post to blogger using Perl's Net::Blogger but it keeps returning false and not posting. The main portion of my code looks like this: use Net::Blogger; my $blogger = Net::Blogger->new({ debug => 1, appkey => '0123456789ABCDEF', # doesn't matter? blogid => $blogid, username => $username, password => $password, }); say 'got to here'; my $result = $blogger->newPost({ postbody => \'<p>This is text</p><hr/><p><strong>Whee!</strong></p>', publish => 1, }); say 'done posting'; use Data::Dumper; print Dumper($result); Sure enough, $result is 0 and in checking the blog, nothing has been posted. The error I'm getting when I enable debugging is: Element '' can't be allowed in valid XML message. Died. at /Library/Perl/5.10.1/SOAP/Lite.pm line 1410. What am I doing wrong? If you can suggest an alternative to Net::Blogger, that would be fine.

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