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  • Global "ajax call" notification with asp.net mvc/jquery

    - by Joel Martinez
    I need to be notified any time a largeish asp.net mvc web application makes an ajax call to the server. We're using both jquery, and the built-in Ajax.* methods to do the remote calls, and I would like a global way of knowing when we make a call without having to manually inject some sort of "IsMakingCall" method to every request. The root problem we're trying to solve is session timeout. If the user leaves a page up and goes to lunch (for example), they get errors when they get back because the ajax call is returning the login page instead of the expected json or partial html result. My idea was to have a js timer which would be reset any time we make an ajax call. That way, if the timer runs out (ie. their session has now timed out) I can just auto-log them out. This is how sites like bank of america and mint.com work. Thanks!

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  • How to avoid downtime when resizing virtual machines

    - by Ivan Buttinoni
    Many IaaS provider offer dynamic upgrade/downgrade of RAM and cores. Usually a Linux VM has to be rebooted to apply these changes. Sometimes, things like VMware tools or other guest services are well integrated so the upgrades to resources are immediately available, but the downgrades still need reboot. How can I solve this issue, so that when downgrading resources I do not have to reboot my guests?

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  • [Rails] OAuth with Digg API

    - by Karl
    I'm attempting to get Rails to play nice with the Digg API's OAuth. I'm using the oauth gem (ruby one, not the rails one). My code looks approximately like this: @consumer = OAuth::Consumer.new(API_KEY, API_SECRET, :scheme => :header, :http_method => :post, :oauth_callback => "http://locahost:3000", :request_token_url => 'http://services.digg.com/1.0/endpoint?method=oauth.getRequestToken', :access_token_url => 'http://services.digg.com/1.0/endpoint?method=oauth.getAccessToken', :authorize_url => 'http://digg.com/oauth/authorize') @request_token = @consumer.get_request_token session[:request_token] = @request_token.token session[:request_token_secret] = @request_token.secret redirect_to @request_token.authorize_url Which is by-the-book in terms of what the gem documentation gave me. However, Digg spits a "400 Bad Request" error back at me when @consumer.get_request_token is called. I can't figure out what I'm doing wrong. Any ideas?

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  • where to download Virtual PC addins?

    - by George2
    Hello everyone, I am using Virtual PC 2007 on Windows Vista Enterprise x86. I need Virtual PC addins to enable functions like shared folder between host and guest OS. But I am very surprised I can not find a download URL from search. Could anyone point me to the download URL for my platform please? thanks in advance, George EDIT1: After install the additionals, I still can not set the Folder Sharing option, here is my screen snapshot, any ideas what is wrong? i39.tinypic.com/91h10w.jpg

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  • IOS - Performance Issues with SVProgressHUD

    - by ScottOBot
    I have a section of code that is producing pour performance and not working as expected. it utilizes the SVProgressHUD from the following github repository at https://github.com/samvermette/SVProgressHUD. I have an area of code where I need to use [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]. I want to have a progress hud displayed before the synchronous request and then dismissed after the request has finished. Here is the code in question: //Display the progress HUB [SVProgressHUD showWithStatus:@"Signing Up..." maskType:SVProgressHUDMaskTypeClear]; NSError* error; NSURLResponse *response = nil; [self setUserCredentials]; // create json object for a users session NSDictionary* session = [NSDictionary dictionaryWithObjectsAndKeys: firstName, @"first_name", lastName, @"last_name", email, @"email", password, @"password", nil]; NSData *jsonSession = [NSJSONSerialization dataWithJSONObject:session options:NSJSONWritingPrettyPrinted error:&error]; NSString *url = [NSString stringWithFormat:@"%@api/v1/users.json", CoffeeURL]; NSURL *URL = [NSURL URLWithString:url]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:30.0]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/json" forHTTPHeaderField:@"Accept"]; [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"]; [request setValue:[NSString stringWithFormat:@"%d", [jsonSession length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:jsonSession]; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; NSString *dataString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]; NSDictionary *JSONResponse = [NSJSONSerialization JSONObjectWithData:[dataString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableContainers error:&error]; NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response; NSInteger statusCode = httpResponse.statusCode; NSLog(@"Status: %d", statusCode); if (JSONResponse != nil && statusCode == 200) { //Dismiss progress HUB here [SVProgressHUD dismiss]; return YES; } else { [SVProgressHUD dismiss]; return NO; } For some reason the synchronous request blocks the HUB from being displayed. It displays immediately after the synchronous request happens, unfortunatly this is also when it is dismissed. The behaviour displayed to the user is that the app hangs, waits for the synchronous request to finish, quickly flashes the HUB and then becomes responsive again. How can I fix this issue? I want the SVProgressHUB to be displayed during this hang time, how can I do this?

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  • WCF: How to detect new connections to WCF PerSession services ?

    - by Christian Toma
    I have a self-hosted WCF service with the InstanceContextMode set to PerSession. How can I detect new client connections (sessions) to my service from the host application and use that new session context to observe my service trough its events? Something like: [ServiceBehavior(InstanceContextMode = InstanceContextMode.PerSession)] public class MyService : IMyService { public event EventHandler ClientRegistered; public event EventHandler FileUploaded; } and from my host application to be able to do: ServiceHost svc = new ServiceHost(typeof(MyService)); svc.Open(); // something like: svc.NewSession += new EventHandler(...) //... public void SessionHandler(InstanceContext SessionContext) { MySessionHandler NewSessionHandler = new MySessionHandler(SessionContext); // From MySessionHandler I handle the service's events (FileUploaded, ClientRegistered) // for this session and notify the UI of any changes. NewSessionHandler.Handle(); }

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  • internet explorer ashx file problem

    - by vondip
    My problem is a bit complicated: I am writing in c#, asp.net and using jquery I have a page that sends requests to the server using jquery's ajax method. I have a ashx file (handler) to respond to these request. User can perform several changes on several pages, then use some method that will call the ajax method. My ashx file reads some values From the session variables and acts accordingly. This works fine in all browsers but in internet explorer. In internet explorer the session seems to hold old information (old user ids'). It's incredible, the same code works fine in firefox, chrome and safari but fails with ie. What could be causing it? I have no clue where to even start looking for a solution. btw, Sorry for the general title, couldn't figure out how to explain in just few words. Thank You!

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  • Hibernate exception

    - by Mark
    Hi all, im new to hibernate! i have followed the netbeans tutorial on creating a hibernate enabled application. after sucessfully creating a database in mysql workbench i reversed engineered the pojos etc and then tried to run a simple query(from Course) and got the following org.hibernate.MappingException: An association from the table coursemodule refers to an unmapped class: DAL.Module at org.hibernate.cfg.Configuration.secondPassCompileForeignKeys(Configuration.java:1252) at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1170) at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:324) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1286) at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:859) heres the generated class for Course package DAL; // Generated 02-May-2010 16:41:16 by Hibernate Tools 3.2.1.GA import java.util.HashSet; import java.util.Set; /** * Course generated by hbm2java */ public class Course implements java.io.Serializable { private int id; private String name; private Set<Module> modules = new HashSet<Module>(0); public Course() { } public Course(int id, String name) { this.id = id; this.name = name; } public Course(int id, String name, Set<Module> modules) { this.id = id; this.name = name; this.modules = modules; } public int getId() { return this.id; } public void setId(int id) { this.id = id; } public String getName() { return this.name; } public void setName(String name) { this.name = name; } public Set<Module> getModules() { return this.modules; } public void setModules(Set<Module> modules) { this.modules = modules; } } and its config file course.hbm.xml <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated 02-May-2010 16:41:16 by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="DAL.Course" table="course" catalog="walkthrough"> <id name="id" type="int"> <column name="id" /> <generator class="assigned" /> </id> <property name="name" type="string"> <column name="name" not-null="true" /> </property> <set name="modules" inverse="false" table="coursemodule"> <key> <column name="courseId" not-null="true" unique="true" /> </key> <many-to-many entity-name="DAL.Module"> <column name="moduleId" not-null="true" unique="true" /> </many-to-many> </set> </class> </hibernate-mapping> hibernate.reveng.xml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-reverse-engineering PUBLIC "-//Hibernate/Hibernate Reverse Engineering DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-reverse-engineering-3.0.dtd"> <hibernate-reverse-engineering> <schema-selection match-catalog="Walkthrough"/> <table-filter match-name="walkthrough"/> <table-filter match-name="course"/> <table-filter match-name="module"/> <table-filter match-name="studentmodule"/> <table-filter match-name="attendee"/> <table-filter match-name="student"/> <table-filter match-name="coursemodule"/> <table-filter match-name="session"/> <table-filter match-name="test"/> </hibernate-reverse-engineering> hibernate.cfg.xml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.url">jdbc:mysql://localhost:3306/Walkthrough</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.connection.password">password</property> <property name="hibernate.show_sql">true</property> <property name="hibernate.current_session_context_class">thread</property> <mapping resource="DAL/Student.hbm.xml"/> <mapping resource="DAL/Walkthrough.hbm.xml"/> <mapping resource="DAL/Test.hbm.xml"/> <mapping resource="DAL/Module.hbm.xml"/> <mapping resource="DAL/Session.hbm.xml"/> <mapping resource="DAL/Course.hbm.xml"/> </session-factory> </hibernate-configuration> any ideas on why im getting this exception? ps. test is just a table with an id in it and is not related to anything. running "from Test" works

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  • Layout components Horizontally in Android

    - by xximjasonxx
    Greetings all, I am trying to create a layout in Android for a notification. My goal is to have the following displayed: 1: Icon for the app 2: Vertically stacked LinearLayout with Session title and Room to be held in 3: The start time of the session The problem I am facing is that #2 has a variable width depending on the size of the title. Hardcoding a width would look terrible if the user turns the handset sideways and goes into Landscape mode. Therefore here is my question: How can I layout three components horizontally in Android such that #1 and #3 are left and right aligned respectively, and #2 simply takes the space remaining? Thanks in advance

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  • VMWare Fusion patch to install Snow Leopard client

    - by Michael
    I'm running VMWare Fusion on Snow Leopard. I'm looking for instructions on how to patch the VMWare settings files so it will let me install Snow Leopard client as a guest OS. Please Note: Links to hacks on how to do this is not allowed on SU. Only officially sanctioned Apple or VMWare solutions are allowed. Any other solutions will be deleted.

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  • Using spring:nestedPath tag

    - by Ravi
    Hello All, I have this code, I know I'm missing something but don't know what. It would be great if you help me out. I'm new to Spring MVC. I'm trying out a simple Login application in Spring MVC. This is my web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <servlet> <servlet-name>springapp</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>springapp</servlet-name> <url-pattern>/app/*</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> here is my springapp-servlet.xml file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <bean name="/login" class="springapp.web.LoginController"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> This is my applicationContext.xml file <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"> <beans> <bean id="employee" class="springapp.domain.Employee" /> </beans> Here is my LoginController.java file package springapp.web; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.SimpleFormController; import springapp.domain.Employee; public class LoginController extends SimpleFormController{ public LoginController(){ setCommandName("loginEmployee"); setCommandClass(Employee.class); setFormView("login"); setSuccessView("welcome"); } @Override protected ModelAndView onSubmit(Object command) throws Exception { return super.onSubmit(command); } } And finally my login.jsp file <%@ taglib uri="http://www.springframework.org/tags" prefix="spring" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Timesheet Login</title> </head> <body> <spring:nestedPath path="employee"> <form action="" method="POST"> <table width="200" border="1" align="center" cellpadding="10" cellspacing="0"> <tr> <td>Username:</td> <td> <spring:bind path="userName"> <input type="text" name="${status.expression}" id="${status.value}" /> </spring:bind> </td> </tr> <tr> <td>Password</td> <td> <spring:bind path="password"> <input type="password" name="${status.expression}" id="${status.value}" /> </spring:bind> </td> </tr> <tr> <td colspan="2"><input type="submit" value="Login" /></td> </tr> </table> </form> </spring:nestedPath> </body> </html> But when I try to run the code I get this error javax.servlet.ServletException: javax.servlet.jsp.JspTagException: Neither BindingResult nor plain target object for bean name 'employee' available as request attribute

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  • Ruby IRB - Requires and Scope

    - by tyndall
    Trying to understand this problem I'm running into. I create file welcome.rb. The contents of this file: welcome_message = "hi there" I then launch an irb session. And type require 'welcome'. That works fine. Then I type: puts welcome_message I get the error message undefined local variable or method `welcome_message' for main:Object What is the best way to bring in predefined variables and have initialization work done when you require something into your irb session. Global variables didn't seem like the right path.

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  • NHibernate CreateSQLQuery data conversion from bit to boolean error

    - by RemotecUk
    Hi, Im being a bit lazy in NHibernate and using Session.CreateSqlQuery(...) instead of doing the whole thing with Lambda's. Anyway what struct me is that there seems to be a problem converting some of the types returned from (in this case the MySQL) DB into native .Net tyes. The query in question looks like this.... IList<Client> allocatableClients = Session.CreateSQLQuery( "select clients.id as Id, clients.name as Name, clients.customercode as CustomerCode, clients.superclient as SuperClient, clients.clienttypeid as ClientType " + ... ... .SetResultTransformer(new NHibernate.Transform.AliasToBeanResultTransformer(typeof(Client))).List<Client>(); The type in the database of SuperClient is a bit(1) and in the Client object the type is a bool. The error received is: System.ArgumentException: Object of type 'System.UInt64' cannot be converted to type 'System.Boolean'. It seems strange that this conversion cannot be completed. Would be greatful for any ideas. Thanks.

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  • "Integrated" VMs (As opposed to "Sandboxed")

    - by sabof
    It is common for virtual machines to be sandboxes, their interaction with the host OS being limited to the absolutely necessary. Are there any projects that would try to integrate VMs (specifically Virtual Box) with their host OS (specifically Ubuntu on Windows host, but I'd be curious of other combinations as well)? Things like opening all files with a certain extension in either the host or the guest. Possibly other nice things I haven't thought of.

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  • VMware Workstation Easy Install is unable to install Windows 8 with a product key specified

    - by Hippo
    I recently attempted to install Windows 8 Enterprise Edition in VMware Workstation. It specified that Easy Install would be used, and requested for the product key, for which I entered the generated MSDN key. This didn't work - the installation goes into a loop with each iteration of the loop ending with the following screen: The guest reboots and the process repeats after clicking "OK". Has anyone been able to successfully install their MSDN image with Easy Install in Workstation?

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  • get equation from XML, AS3

    - by VideoDnd
    There's an variable in my swf I want to receive XML. It's an integer value in the form of an equation. How do I receive the XML value for 'formatcount'? My Variable //Variable I want to grab XML<br> //formatcount=int('want xml value to go here'); formatcount=int(count*count/100); Path formatcount = myXML.FORMATCOUNT.text() My XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">1000</TIMER> <COUNT TITLE="starting position">10000</COUNT> <FORMATCOUNT TITLE="ramp">count*count/1000</FORMATCOUNT> </SESSION>

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  • Wireless Password

    - by Campo
    I have a security policy question: I want to know how other admins handle the WIFI password in the office. Does everyone know it? Do you enter it in for the user or guest every time and keep it a secret. I am in camp 2. Just want to know what others do and their reasoning behind it.

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  • SSH login with expect(1). How to exit expect and remain in SSH?

    - by Koroviev
    So I wanted to automate my SSH logins. The host I'm with doesn't allow key authentication on this server, so I had to be more inventive. I don't know much about shell scripting, but some research showed me the command 'expect' and some scripts using it for exactly this purpose. I set up a script and ran it, it worked perfectly to login. #!/usr/bin/env expect -f set password "my_password" match_max 1000 spawn ssh -p 2222 "my_username"@11.22.11.22 expect "*?assword:*" send -- "$password\r" send -- "\r" expect eof Initially, it runs as it should. Last login: Wed May 12 21:07:52 on ttys002 esther:~ user$ expect expect-test.exp spawn ssh -p 2222 [email protected] [email protected]'s password: Last login: Wed May 12 15:44:43 2010 from 20.10.20.10 -jailshell-3.2$ But that's where the success ends. Commands do not work, but hitting enter just makes a new line. Arrow keys and other non-alphanumeric keys produce symbols like '^[[C', '^[[A', '^[OQ' etc.[1] No other prompt appears except the two initially created by the expect script. Any ignored commands will be executed by my local shell once expect times out. An example: -jailshell-3.2$ whoami ls pwd hostname (...time passes, expect times out...) esther:~ user$ whoami user esther:~ ciaran$ ls Books Documents Movies Public Code Downloads Music Sites Desktop Library Pictures expect-test.exp esther:~ ciaran$ pwd /Users/ciaran esther:~ ciaran$ hostname esther.local As I said, I have no shell scripting experience, but I think it's being caused because I'm still "inside of" expect, but not "inside of" SSH. Is there any way to terminate expect once I've logged in, and have it hand over the SSH session to me? I've tried commands like 'close' and 'exit', after " send -- "\r" ". Yeah, they do what I want and expect dies, but it vindictively takes the SSH session down with it, leaving me back where I started. What I really need is for expect to do its job and terminate, leaving the SSH session back in my hands as if I did it manually. All help is appreciated, thanks. [1] I know there's a name for this, but I don't know what it is. And this is one of those frightening things which can't be googled, because the punctuation characters are ignored. As a side question, what's the story here?

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  • Creating a Stack Overflow notifier

    - by Trey
    I could not find a Stack Overflow notifier Android app so I am planning on making one. I hope that my app will serve a similar purpose as the Stack Overflow Notifier Chrome extension. This will be my first Android app so I am still unfamiliar with the platform. My main concern when creating this app is, what is the proper way to access the user's Recent Activity page? I thought of two different approaches but I'm not sure how to implement either one: Make the user login to Stack Overflow through the Browser application or an embedded browser and scrape their recent activity page occasionally for updates. Ask the user for their username and password and forward this information to Stack Overflow for authentication, storing cookies somehow to keep the session active. I think Astrid uses something similar to the first approach, but I haven't been able to figure it out yet from skimming their code. What is the correct way to handle a notification application like this that requires session management?

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  • Can't transfer list<T> to web service?

    - by iTayb
    I have the same classes on my server and on my web service. I have the following WebMethod: [WebMethod] public int CreateOrder(List<Purchase> p, string username) { o.Add(new Order(p,username)); return o.Count; } However the following code, run at server: protected void CartRepeater_ItemCommand(object source, RepeaterCommandEventArgs e) { List<Purchase> l = ((List<Purchase>)Session["Cart"]); if (e.CommandName == "Order") { localhost.ValidateService WS = new localhost.ValidateService(); WS.CreateOrder(l, Session["username"].ToString()); } } gives the following error: Argument '1': cannot convert from 'System.Collections.Generic.List<Purchase>' to 'localhost.Purchase[]'. How can I transfer the list<Purchase> object to the web service? Thank you very much.

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  • Is VirtualBox really slow compared to the host OS? (for Ruby development)

    - by dan
    I have VirtualBox running Ubuntu as a guest environment on my Macbook Pro running Leopard OS X 10.5. I timed the same batch of Ruby on Rails unit tests on both systems. The difference seems to be quite big. The same suite of Ruby unit tests that take 13.4 seconds in the native OS X, take 82 seconds to run in VirtualBox Ubuntu. Are other people doing the same kind of development noticing the same differences?

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