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  • redirect images to php script

    - by Jonathan
    I want to be able to redirect all requests to navigate to an image to a php script which will then show the image but with a nav bar at the top. However using rewrite (im using IIS btw) means that I can't embed those images. Any help will be greatly appreciated.

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  • Android : Connecting to MySQL using PHP

    - by user1771128
    I followed the following article http://blog.sptechnolab.com/2011/02/10/android/android-connecting-to-mysql-using-php/ I am able to execute my php file. I executed it individually and its working fine. The problem is in the android execution part. Am posting the Log Cat for the error am facing. Tried putting in a List View with id "list" but the error stil 10-28 16:08:27.201: E/AndroidRuntime(664): **FATAL EXCEPTION: main** 10-28 16:08:27.201: E/AndroidRuntime(664): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.city/com.example.city.City}: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1956) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1981) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.access$600(ActivityThread.java:123) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1147) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Handler.dispatchMessage(Handler.java:99) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Looper.loop(Looper.java:137) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.main(ActivityThread.java:4424) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invokeNative(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invoke(Method.java:511) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551) 10-28 16:08:27.201: E/AndroidRuntime(664): at dalvik.system.NativeStart.main(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): Caused by: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ListActivity.onContentChanged(ListActivity.java:243) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:254) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.setContentView(Activity.java:1835) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.example.city.City.onCreate(City.java:35) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.performCreate(Activity.java:4465) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1920) 10-28 16:08:27.201: E/AndroidRuntime(664): ... 11 more

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  • Submitting form in php file accessed by Ajax?

    - by dronnoc
    Hi people, I am trying to figure out how to submit a form in a page being accessed by Ajax? here are some code snippets to help demonstrate what i am trying to say. HTML BODY - THIS IS WHAT THE USER WILL SEE. <html> <head> <script language="javascript" src="linktoajaxfile.js"> </head> <body onLoad="gotoPage(0)"> <div id="fillThis"> </div> </body> </html> AJAX FILE var xmlhttp function gotoPage(phase) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Your browser does not support AJAX!"); return; } var url="pageofstuffce.php"; url=url+"?stg="+phase; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("fillThis").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } PAGE OF DATA <?php $stage = $_GET['stg']; if($stage == 0) { echo '<a onClick="gotoPage(1)">click me</a>'; } elseif($stage == 1) { <form> <input type="text" name="name"> <input type="submit" name="submit"> </form> } elseif(somehow can reach here) { show data from form. } ?> Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :) Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc EDIT Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?

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  • seperated mysql statement query in php

    - by stone
    So, I can run the following statements from within mysql itself successfully. SET @fname = 'point1'; SELECT * FROM country WHERE name=@fname;` But when I try to pass the query through php like this and run it, I get an error on the second line $query = "SET @fname = 'point1';"; $query .= "SELECT * FROM country WHERE name=@fname;";

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  • php symantics of setting cookies and redirecting without getting header error

    - by salmane
    I would like to do the following in php : setcookie('name', $value, $Cookie_Expiration,'/'); then some action header("location:http://www.example.com") the problem is that I get : warning: Cannot modify header information - headers already sent by (...etc ) could you please let me know what i am doing wrong and if there is a way to do this? by the way , this code is before any output is made ...the cookie setting part works fine on its own and so does the redirection code....the combination fails thank you

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  • Get values from HTML in a multidimensional array and calculate values using PHP

    - by Frank Nwoko
    I have searched but could not get solution on this issue. I am working on an application which will generate unknown number of items and have users select the quantity from a drop down against each item. Eg. Item(s) | price | Select qty Rice 23 3 Beans 22 4 Eggs 52 5 ... ... ... unknown Please, how can I capture the above in an array and also calculate the total value for all selected items and corresponding fees? I have the following HTML code: <form id='form1' name='form1' method='post' action='item_calc.php'> <?php ..... while($t_row = mysql_fetch_assoc($get_items)) { echo "<p><label>$t_row['$item_name'] <input type='text' READONLY name='item_price[]' value='$t_row['$item_price']' /></label> <input type='text' READONLY name='item_fees[]' value='$t_row['$item_fee']' /> <select name="item_qty"> <option value="1"> <option value="2"> <option value="3"> <option value="4"> <option value="5"> </select> </p><p>"; } echo "<label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; Please, how can I get item_price[] + item_fees[] * item_qty for all selected items? This is what I have tried: for ($i = 0; $i < count($_POST['item_price']); $i++) { // Do something here with $_POST['checkbx'][$i] foreach ($_POST['item_fees'] as $tkey => $tvalue) { //echo "Key: $tkey; Value: $tvalue<br>"; } foreach ($_POST['item_price'] as $pkey => $pvalue) { //echo "Key: $pkey; Value: $pvalue<br>"; } $total = $tvalue + $pvalue; } echo $total;

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  • php extracting complete url with variables

    - by salmane
    Hi there, Using Php I would like to extract the current Url of a page including all variables attached to it. $_SERVER['PHP_SELF'] only return the url without the variable . any idea what function I need. example : www.site.com/?v1=xyz&v2=123 using $_SERVER['PHP_SELF'] I get only : www.site.com as opposed to the whole url. using $_GET[] individually is not an opton since I am not sure what variable are attached to the URL. thank you

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • How do you create domain.com/?stringhere without a .php extension

    - by matt
    I want to create a link like the following: http://www.myurl.com/?IDHERE What i want to be able to do is be able to goto the above link, and then pull whats after the ? (in this case IDHERE) and be able to use that information to perform a MySQL lookup and return a page. Can anyone point me into the right direction? please know this is using PHP not ASP

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  • How do I detect the directory a php file is in

    - by Eric
    I have a PHP file that I need it to detect it's directory it's in. In my case I want it to return C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\ I think that this is pretty straightforward but if there is something you don't understand just comment

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  • [php] call_user_func_array problems

    - by Knarf
    I have a class with this in self::$DB = new PDO("mysql:dbname=$dbname;host:=127.0.0.1" , 'root' , ''); and then this public static function __callStatic($name, $arguments) { return call_user_func_array(array('self::$DB', $name), $arguments); } How does I make it right/work? Warning: call_user_func_array() expects parameter 1 to be a valid callback, class 'self::$DB' not found in D:\Mine Dokumenter\My Dropbox\www\Framework 3\database.class.php on line 19

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  • Return current web path in PHP

    - by BenTheDesigner
    Hi All Currently developing a PHP framework and have ran into my first problem. I need to be able to drop the framework into any folder on a server, no matter how many folders deep, and need to find that directory to use as a base URL. For example, it currently works if I put the framework in the root of the server (http://cms.dev/), but if I were to put it in http://cms.dev/folder/ it does not work. Please advise, any comments welcome. BenTheDesigner

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  • unserialize problem in php

    - by Kurt
    hi i'm using serialize/unserialize functions in php 5.2. the text to be stored is POSTed via a form. btw, no white-space before or after. if text contains " or ' it serializes successfully. the problem is it does not unserialize back. what i'm doing wrong?

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  • php - clean URL

    - by tibin mathew
    Hai I want to create a web site with pure php. I want to hide the url parameters. I.e. I want to make my web site with clean urls. Is there is any way to do this with out using any framework? Is it curl help full to do this? Does any one give me a solution.

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